Answer:
[tex]\sqrt{v^{2} + 2\, g\, y}[/tex].
Explanation:
Apply the SUVAT equation [tex]{v_{1}}^{2} - {v_{0}}^{2} = 2\, a\, x[/tex] to the vertical component of the soccer ball's motion to find the vertical velocity right before the ball lands. In this equation:
[tex]v_{1}[/tex] represents the vertical velocity of the ball right before it lands (needs to be found);[tex]v_{0}[/tex] represents the initial vertical velocity of the soccer ball ([tex]0[/tex] in this question since the ball was initially travelling horizontally); [tex]a[/tex] represents the acceleration (equal to [tex]g[/tex] since air friction is negligible);[tex]x[/tex] represents the vertical displacement of this ball (in this question, this vertical displacement is equal [tex]y[/tex], the height of the cliff.)Rearrange this equation to find an expression for the vertical velocity [tex]v_{1}[/tex] in terms of [tex]y[/tex] and [tex]g[/tex]:
[tex]\begin{aligned}v_{1} &= \sqrt{{v_{0}}^{2} + 2\, a\, x} \\ &= \sqrt{2\, g\, y}\end{aligned}[/tex].
Since air friction is negligible, the horizontal velocity of the ball would stay unchanged. Thus, the horizontal velocity of the ball would still be [tex]v[/tex] right before the ball lands.
Notice that these two components of velocity are perpendicular to one another. Thus, find the combined velocity of the ball right before landing could be found using Pythagorean's Theorem:
[tex]\sqrt{v^{2} + {v_{1}}^{2}} = \sqrt{v^{2} + 2\, g\, y}[/tex].
Phys-1A Horizontal Practice 2
Ground-to-Ground Equations
Horizontal Equations
Vicos
Vertical Equations
sin
ay earth).-9.8 m/s
Horizontal Launch Equations
Horizontal Equations
Vertical Equational
Velocity-as-Hits:
wv * , te
Use. Pythagorean Range
and tan (9)
Show work/use units !!
1. For each problem, solve for "?" and "?", and Velocity-as-it-Mits. Circle your final answers with units.
2.26, 226, 24.3 65.7
Vf, V+ay.t
wh25
V4.0
(Pythag. +
7+17,
tan
Velocity-as-Hits -
2. For each problem, solve for "7" and "?", and Velocity-as-it-Hits Circle your final answers with units.
2.02,742, 21.1 69.5
W.77
VF, VI+ ayt
VF,
Mercede
(Pythag.+ v
tan
Velocity-as-Hits -
What is current of 12 ohm? help me pleasee
1. 0.25 A
2. 0.5 A
3. 1 A
4. 1.5 A
5. 2 A
please show solution.
Answer:
the current is 5.2 Amps
Before beginning an experiment, mrs. wilson warns her science class not to drop the bar magnets on the floor. what is the most likely reason for mrs. wilson’s warning? the magnet might lose its magnetism. the magnet might make a startling noise. the magnet might become stuck to the floor. the magnet might cause the floor to become magnetic.
The most likely reason for Mrs. Wilson's warning will be the magnet might lose its magnetism.
What is magnetism?Magnetism is a component of the larger phenomena of electromagnetic. The most well-known effects occur in ferromagnetic materials,
Which are highly attracted by magnetic fields and maybe magnetized to become permanent magnets, hence creating magnetic fields. It is also feasible to demagnetize a magnet.
We should not drop a magnet on the floor since magnets progressively lose magnetism and grow weak over time if they are not properly preserved.
Hence this is most likely the reason for Mrs. Wilson's warning will be the magnet might lose its magnetism.
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Answer:
The correct answer is A!
Explanation:
~Hope this helps! :)
A car of 15 kg is traveling on a circular track. If the radius of the track is
7. 8 m and the period is 8. 5 seconds, what's the centripetal force on
the car? (Round to the nearest hundredth)
The magnitude of the centripetal force on the car is 69.6 N.
What is centripetal force?This is a force acting on a body in circular path and it is directed to the center around which the body is moving.
To calculate the centripetal force on the car, we use the formula below.
Formula:
F = m(4π²/t²)........ equation 1Where:
F = Magnitude of the centripetal force on the car, m = mass of the cart = timeFrom the question,
Given:
m = 15 kgt = 8.5π = 3.14Substitute these values into equation 1
F = 15(4×3.14²/8.5²)F = 69.6 NHence, the magnitude of the centripetal force on the car is 69.6 N.
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Reagan rides on a playground roundabout with a radius of 2. 5 feet. To the nearest foot, how far does reagan travel over an angle of 4π3radians? ______ ft
Answer:
S = θ R where S is the arc length and θ the arc length in radians
S = 2.5 ft * 4 π^3 rad = 2.5 * 124 = 310 ft (1 radian = 2.5 ft)
Assuming 4π3 means 4π^3
The Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.
What is a circle?It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).
We have Reagan rides on a playground roundabout with a radius of 2.5 feet.
We know the relation between arc length and radius of the circle:
S = R∅
Here R = 2.5 feet, and central angle ∅ = 4π/3
[tex]\rm S = 2.5\times \frac{4\pi}{3}[/tex]
S = 10.47 feet ≈ 10 feet
Thus, the Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.
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A carrot has a mass of 69 grams and a volume of 150 cubic centimeters. Calculate its
density.
Answer:
As Per Provided Information
Mass of carrot 69 grams
Volume of carrot 150 cm³
we have been asked to determine the density of carrot .
Using Formulae
[tex] \bf \: Density = \cfrac{Mass \: of \: carrot}{Volume \: of \: carrot}[/tex]
Substituting the given value and let's solve it to determine the density of carrot.
[tex] \longrightarrow\sf \: Density = \cfrac{69}{150} \\ \\ \\ \longrightarrow\sf \: Density = \cancel\cfrac{69}{150} \\ \\ \\ \longrightarrow\sf \: Density =0.46 \: gm \: {cm}^{ - 3} [/tex]
Therefore,
Density of carrot is 0.46 gm/cm³Which materials are good insulators? Select three options. Glass paper gold plastic silver.
Answer:
Plastic Glass and Paper
Explanation:
i just took the assignment
Glass, paper, and plastic are good insulators. The material that does not allow the flow of current through them is known as the insulators.
What are insulators?An electrical insulator is a substance that prevents electric current from flowing freely. The electrons in the insulator's atoms are closely bonded and cannot travel easily.
Other materials, such as semiconductors and conductors, carry electricity more easily. The characteristic that characterizes an insulator.
Gold and silver are good conductors of electricity. While glass, paper, and plastic are good insulators.
Hence glass, paper, and plastic are good insulators.
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After hearing about an accident on his normal route, mr. gujral checks for alternate routes to get to work. what type of circuit does this traffic situation model? a series circuit because there is more than one path a series circuit because there is only one path a parallel circuit because there is more than one path a parallel circuit because there is only one path
The type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.
What is a parallel circuit?A parallel circuit has branches that split the current such that just a portion of it passes through each branch.
The voltage or potential difference between each branch of a parallel circuit is the same, but the currents might differ.
A parallel circuit is having more than one path in order to reach it on time he has to take a different path.
Hence the type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.
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Answer:
C) a parallel circuit because there is more than one path
Explanation:
C) a parallel circuit because there is more than one path
The electrical loads in _____ circuits each have the same voltage drop, with equals the total applied voltage of the circuit.
Answer:
The electrical loads in parallel circuits each have the same voltage drop, with equals the total applied voltage of the circuit.
Explanation:
I did some research and the voltage drop across any branch of a parallel circuit is the same as the applied voltage.
what other fees are associated with each credit card
Answer:
Finance costs (also known as interest fees) aren't added to your account in a set amount like other fees.
OR
A credit card is a payment card that is issued to users to allow them to pay a merchant for products and services depending on their outstanding debt. The card issuer opens a revolving account for the cardholder and provides a line of credit from which the cardholder can borrow money to pay a merchant or get a cash advance. Consumer credit cards and business credit cards are the two types of credit cards available. The majority of the cards are plastic, however, there are a few metals and gemstone-encrusted metal cards.
Explanation:
Enter an expression, in terms of defined quantities and g, for the force that the scale under left pillar shows
The expression, in terms of defined quantities and g is therefore Fu =((mg/2) +2 mp) g
What is a Scale?This can be defined as a balance or any of various other instruments or devices for weighing.
The expression in terms of defined quantities and g, for the force that the scale under left pillar shows that Fu =((mg/2) +2 mp) g .
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The expression, in terms of defined quantities and g, for the force that the scale under left pillar is (m(b)/2+2m(d))g.
What is the equilibrium state of a system?Equilibrium is the location of the system, in which the system be static does not change its position with respect to time.
The image of the uniform beam which has two pillar is attached below. In this pillar,
The length of the pillar is L and the mass is m(b)Pillars located at L/3 from either end.The system is in equilibrium.A duck is shown has the mass m(d).The expression, in terms of defined quantities and g, for the force that the scale under left pillar has to be find out.
In the equilibrium position torque in left pillar is zero,
[tex]\tau_{right} =0[/tex]
It can be written as,
[tex]F_L\dfrac{L}{3}=m_bg\dfrac{L}{6}+m_dg\dfrac{2L}{3}[/tex]
[tex]F_L=\left(\dfrac{m_b}{2}+2m_d\right)g[/tex]
Thus, the expression, in terms of defined quantities and g, for the force that the scale under left pillar is (m(b)/2+2m(d))g.
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10. Wet-cell and Dry-cell batteries have _______ current.
A. Direct
B. Alternating
C. Series
D. Parallel
Answer:
A
Explanation:
Direct because it's still passes electricity through ir
7. Why are cooking pans made of aluminum? {Explain using the specific heat value of
aluminum} it conducts heat well high thermal energy
A solid sphere is released from the top of a ramp that is at a height
h1 = 2.20 m.
It rolls down the ramp without slipping. The bottom of the ramp is at a height of
h2 = 1.87 m
above the floor. The edge of the ramp is a short horizontal section from which the ball leaves to land on the floor. The diameter of the ball is 0.14 m.
a.) Through what horizontal distance d, in meters, does the ball travel before landing?
b.) How many revolutions does the ball make during its fall?
Hi there!
We can use the work-energy theorem and apply it to this situation.
At the top of the ramp, the ball only has gravitational potential energy, and at the bottom of the ramp, the ball has BOTH translational and rotational kinetic energy.
We must use the following equations:
[tex]GPE = mgh \\KE_T = \frac{1}{2}mv^2\\\\KE_R = \frac{1}{2}I \omega^2[/tex]
m = mass of sphere (kg)
g = acceleration due to gravity (m/s²)
h = height of ramp (m)
v = final velocity (m/s)
I = Moment of Inertia (kgm²)
ω = angular velocity (rad/sec)
Since:
[tex]E_i = E_f\\\\mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega ^2[/tex]
In order to make things easier, since the ball is not slipping, we can relate angular velocity to translational velocity:
[tex]\omega = \frac{v}{r}[/tex]
Also, recall the equation for the moment of inertia for a solid sphere:
[tex]I = \frac{2}{5}mr^2[/tex]
We can use these to simply our equation:
[tex]KE_R = \frac{1}{2}(\frac{2}{5}mr^2)(\frac{v}{r})^2 = \frac{1}{5}mv^2[/tex]
Now, we can rewrite the equation and solve for 'v'.
[tex]mgh = \frac{1}{2}mv^2 + \frac{1}{5}mv^2\\\\mgh = \frac{7}{10}mv^2\\\\v = \sqrt{\frac{10gh}{7}} = \sqrt{\frac{10(9.8)(2.2 - 1.87)}{7}} = 2.149\frac{m}{s}[/tex]
a)
We can begin by solving for the time taken for the ball to land on the ground. The ball only has a horizontal velocity, so this is essentially a free-fall situation. Use the rearranged kinematic equation:
[tex]t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2(1.87)}{9.8}} = .6178 s[/tex]
Now, use the following equation to solve for horizontal distance given horizontal velocity and time:
[tex]d_x = v_x t\\\\d_x = 2.149 * .6178 = \boxed{1.328 m}[/tex]
b)
We can use the previously-stated relationship between translational and angular velocity to solve for the angular velocity.
[tex]\omega = \frac{v}{r}[/tex]
It is given that the diameter is 0.14 m, so the radius is 1/2th the diameter, or 0.07 m.
Solve for the angular velocity:
[tex]\omega = \frac{2.149}{0.07} = 30.706 \frac{rad}{sec}}[/tex]
Using the above fall time and dimensional analysis to convert from rad/sec to revolutions, we can solve for the # of revolutions made by the ball:
[tex]\frac{30.706rad}{sec} * .6178 sec * \frac{1 rev}{2\pi rad} = \boxed{3.019 rev}[/tex]
Please Help Me!
A boy holds a toy soldier in from of a concave mirror. The focal length of the mirror is 0.45 m and the boy holds the toy soldier at a distance of 0.25m from the mirror. Find the image distance.
The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.
What is image distance?This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.
To calculate the image distance, we use the formula below.
Formula:
1/f = 1/u+1/v........... Equation 1Where:
f = Focal length of the mirrorv = Image distanceu = object distanceFrom the question,
Given:
f = 0.45 mu = 0.25 mSubstitute these values into equation 1 and solve for the image distance
1/0.45 = 1/0.25 + 1/v2.22 = 4+1/v1/v = 2.22-41/v = -1.78v = 1/(-1.78)v = -0.56 mHence, The image distance is -0.56 m.
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a car of mass 850kg hits a crash barrier at a speed of 30m/s . the car stops in 0.4s.calculate the force of the car.
During the collision an impulse is created which due to which is equal to change in momentum.
Mathematically,
[tex]\green{ \underline { \boxed{ \sf{Impulse, F\times t = m (v-u) }}}}[/tex]
where
F = forcet = time span m = massv= final speedu = initial speedNow,
[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times (0-30) \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times -30 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf F = -\frac{25500}{0.4} \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf F = -63750 N \\\end{gathered} [/tex]
[tex]\quad\quad\quad\quad\quad\quad[/tex](-ve sign denotes opposite direction)
Therefore, a force of 63750 Newton will act on the car in opposite direction.
With a class 1 lever, does mechanical advantage increase or decrease as the fulcrum is moved closer to the load? Explain why.
Answer:
L1 F1 = L2 F2 explains balancing torques
F1 = load = counterclockwise torque
F2 = applied force - clockwise torque
L represents distances from fulcrum to the applied forces
F2 = F1 * (L1 / L2) (I)
MA mechanical advantage = (L2 / L1) load over applied force
We can rewrite equation (I) as
load force / applied force = applied distance / load distance
As the fulcrum is moved closer to the load L1 decreases and L2 increases which corresponds to an increase in MA
3. Three lightbulbs are connected in a series. A switch is placed between the first lightbulb and the second lightbulb. If that
switch is opened, what happens to each of the three lightbulbs?
Please help explanation
In series connection the current flow remains constant
If switch is placed between first and second lightbulbThen if it's turned on. the three bulbs will be lighted up with same currentConduction is greater in solids .explain in your own words Why?
Explanation:
because conduction takes place in objects whose particles are close/touching each other therefore conduction happens in solid as liquid and gas paricles are not close to each other
name one type of energy the washing machine wastes when spinning the clothes
Answer:
Electrical Energy
The Electricity Rotates the spinning part of Washing machine and It spinns clothes.
Imagine that you are a circus performer riding a uni-cycle (forwards) across the stage. What is the direction of the angular velocity of the single wheel?
The direction of the angular velocity of the single wheel is the clockwise direction
Angular velocityThe angular velocity is the number of revolutions per second of the single wheel. It is given by ω = v/r where
v = linear speed of the wheel and r = radius of the wheel.Direction of the angular velocity of the single wheelSince the wheels moves forward and the velocity of the wheel is always tangential to the wheel causing it to move forward, its angular velocity is in the clockwise direction
So, the direction of the angular velocity of the single wheel is the clockwise direction
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The angular velocity is also known as the rotational velocity. The direction of the angular velocity of the single wheel is clockwise.
What is angular velocity?The angular velocity or rotational velocity, also known as the angular frequency vector, is a vector measure of rotation rate that relates to how fast an item spins or revolves relative to another point, i.e. how quickly the angular position or orientation of an object changes with time.
[tex]\omega = \dfrac vr[/tex]
where v is the velocity and r is the radius.
The Direction of angular velocity is that the wheel goes forward and the velocity of the wheel is always tangential to the wheel, forcing it to move forward, therefore, the angular velocity is clockwise.
Hence, the direction of the angular velocity of the single wheel is clockwise.
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What is the distance a spring is compressed if the spring constant is 10 m/n, and a force
of 25 n is applied?
Answer:
40n
Explanation:
10×25 all over 100 ,25 into hundred 4 times 10×4 =40n
The interior of a refrigerator has a surface area of 2. 6 m2. It is insulated by a 4. 5 cm thick material that has a thermal conductivity of 0. 0098 J/m · s · ◦ C. The ratio of the heat extracted from the interior to the work done by the motor is 4. 4% of the theoretical maximum. The temperature of the room is 37. 7 ◦C, and the temperature inside the refrigerator is 3. 7 ◦C
For an interior of a refrigerator has a surface area of 2. 6 m2, The power is is mathematically given as
P= 71.56W
What is the power?Generally, the equation for the Fourier's law is mathematically given as
H = ∆Q/∆t = k∙A∙∆T/∆x
Therefore
H= 0.0112* 4.2 *(33.3 - 6.8) / 0.022m
H= 58.18J/s
For The coefficient of performance(COP)
COP = Q/W = H/P
Therefore
COP = 279.95K/(306.45K - 279.95K)
COP = 10.564
In conclusion
P = H/COP
P= 58.18W / 0.813
P= 71.56W
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A 5.0-newton force could have perpendicular components of
Answer:
It can have many set of perpendicular component but the most important one is 3 AND 4
Explanation:
PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE
sitting at rest on top of a spring with a spring constant of 10N /m. the spring is compressed 5m
Answer:
50N
Explanation:
this is because 5×10all over 100 ,0 will cancile 0 remaining 10 ,1 into 10 ,10times ,so 5×10 =50N
Which of the following can be used to measure temperature accurately
Celsius
Fahrenheit
Kelvin
All of these are correct
Answer:
Any of those terms can be converted to either of the other terms, so either term is correct. People are accustomed to everyday temperatures in Fahrenheit. The ideal gas law specifies that
P V = N R T where T is in Kelvin which is Celsius + 273 deg.
WILL GIVE BRAINLEST!!! What is the magnification of a virtual image if the image is 10.0 cm from a mirror and the object is 20.0 cm from the mirror?
a. -2.0
b. 0.50
c. 2.0
d. -0.50
option D
hope it helps...!!!
Answer:
B.
Explanation:
You have to divide.
10.0/20.0 = 0.50
I apologize if it is incorrect-
I hope it helps! Have a great day!
Anygays-
A uniform rod of length l and mass m is pivoted around a line perpindicular to the rod at location l/3
Answer:
I for a rod about its center is I = M L^2 / 12
A = L (1/2 - 1/3) = L / 6 distance from middle to location L/3
A^2 = L^2 / 36
I = M L^2 (1/12 + 1/36) = M L^2 (4 / 36) = M L^2 / 9
I about given location by parallel axis theorem
1. How do you describe the path that the light passes through when it travels?
2. What happens during dispersion of light?
3. What are the different colors of light?
4. Similarly, how are rainbows formed up in the sky?
pls help me if u can
A:
The white light is divided into its component hues - red, orange, yellow, green, blue, and violet - as it passes through the prism. Dispersion is the splitting of visible light into its many hues.
===========================================================B:
Dispersion is the splitting of visible light into its many hues. Each hue is associated with a certain wave frequency, as stated in the Light and Color unit, and different frequencies of light waves bend at different rates while passing through a prism.
============================================================C:
The white light is divided into its component hues - red, orange, yellow, green, blue, and violet - as it passes through the prism. Dispersion is the splitting of visible light into its many hues.
===========================================================D:
The sun and the weather combine to create a rainbow. As it passes from air to denser water, light enters a water droplet, slowing and bending. The light bounces off the interior of the droplet, separating the wavelengths—or colors—that make up the droplet. A rainbow is created as light escapes the droplet.
A 1.2-kg hot iron sphere with heat capacity
576 J °C-1 is cooled by immersing it in a tank of
water (Fig g). (See the photo that I uploaded)The mass of the water is 3 kg and
its initial temperature is 12 °C. After 5 minutes,
both the iron sphere and the water reach a final
temperature of 15 °C.
(a) Find the energy gained by the water.
(b) Find the average rate of energy transfer from
the iron sphere to the water.
(c) What is the initial temperature of the iron
sphere?
Given the data from the question, the heat gained by the water, the rate of energy transfer and the initial temperature of the iron are:
A. The energy gained by the water is 37656 J
B. The average rate of energy transfer from
the iron sphere to the water is 125.52 J/s (Watts)
C. The initial temperature of the iron
sphere is 65.4° C
A. How to determine the heat gained Mass of water (M) = 3 Kg = 3 × 1000 = 3000 gInitial temperature (T₁) = 12 °C Final temperature (T₂) = 15 °Change in temperature (ΔT) = 15 – 12 = 3 °C Specific heat capacity (C) = 4.184 J/gºC Heat (Q) =?Q = MCΔT
Q = 3000 × 4.184 × 3
Q = 37656 J
B. How to determine the rate of energy transfer Heat (Q) = 37656 JTime (t) = 5 min = 5 × 60 = 300 sPower (P) =?Power = energy / time
Power = 37656 / 300
Power = 125.52 J/s (Watts)
C. How to determine the initial temperature of the iron Mass of iron (M) = 1.2 Kg = 1.2 × 1000 = 1200 gHeat capacity (C) = 576 J/ºC Heat (Q) = 37656 JTemperature (T) =?Q = CT
37656 = 576 × T
Divide both side by 576
T = 37656 / 576
T = 65.4° C
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