From a hot-air balloon, Guadalupe measures a 31^{\circ} ∘ angle of depression to a landmark that’s 316 feet away, measuring horizontally. What’s the balloon’s vertical distance above the ground?

Answers

Answer 1

Check the picture below.

From A Hot-air Balloon, Guadalupe Measures A 31^{\circ} Angle Of Depression To A Landmark Thats 316 Feet

Related Questions

Find the area of the figure.

7cm

8cm

11cm


Area is ___ square cm?

Answers

Answer:

616cm³

Step-by-step explanation:

you just need to multiply those numbers

7 x 8 x 11= 616

[tex]\text{Perimeter of the triangle,}\\\\ 2s = 7 + 8 +11 =26}\\\\\\\implies s = \dfrac{26}2 = 13\\\\\\\text{Apply Heron's formula to find the area of the triangle,}\\\\A = \sqrt{s(s-8)(s-7)(s-11)}\\\\\implies A = \sqrt{13(13-8)(13-7)(13-11)}\\\\\implies A = \sqrt{780} \\\\\implies A = 27.93~~ \text{cm}^2[/tex]

1 1/5- 1/3
AS FRACTION

Answers

Answer:

-2/15

this should work

Step-by-step explanation:

Answer:

13/15

Step-by-step explanation:

1 1/5 - 1/3 =

= 1 + 1/5 - 1/3

= 5/5 + 1/5 - 1/3

= 6/5 - 1/3

= 18/15 - 5/15

= 13/15

Little help? Ill give 5 stars and brainly (If correct)

Answers

Answer:

C

Step-by-step explanation:

Slope is rise over run. Pick two points and then count the rise and run. The rise in this case is one and the run is 2 and one over 2 is 1/2

[tex]Hiya![/tex]

Sokka is here to help!

ANSWER:

[tex]C.[/tex]

Because, All you need to do is.. Find the slope of proportional graph, by y and x, Which the line is [tex]\frac{4}{2}[/tex].

[tex]And, \frac{4}{2} =\frac{1}{2} .[/tex]

Hopefully, this helps you!!

[tex]Sokka[/tex]

The cost of providing water bottles at a high school football game is $35 for the rental of the coolers and $0.50 per bottle

Answers

The cost function is an illustration of a linear function

The equation of the cost function is C(x) = 35 + 0.5x

The given parameters are:

[tex]Rentals = 35[/tex] -- the cost of renting a cooler

[tex]Rate = 0.5[/tex] --- the rate per bottle

Assume the number of bottles in a cooler is x.

The cost function for the bottles in a cooler would be:

[tex]C(x) = Rentals + Rate \times x[/tex]

So, we have:

[tex]C(x) = 35 + 0.5\times x[/tex]

Evaluate the products

[tex]C(x) = 35 + 0.5x[/tex]

Hence, the equation is [tex]C(x) = 35 + 0.5x[/tex]

Read more about linear functions at:

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two piers, a and b, are located s km away from each other along a river. a motorboat, with a speed of v km/hour in still water, is cruising between the two piers. How much time t (in hours) will the motorboat need to get from pier a to pier b and back, if the speed of the current is 5km/hour? find t if: s=105 v=40

Answers

Answer:

speed in still water is v=40 speed of current

Give an expression for f + g.
A. 12x3 + 16x2 - 6x -8
B. 4x2 + 3x + 2
C. 4x2 + 3x - 8
D. 12x3 + 16x2 - 6x​

Answers

Answer:

A)62x-8

B)11x+2

C)11x-8

D)62x

Step-by-step explanation:

12×3=36

16×2=32

36+32-6=62x-8

Help help help help math math

Answers

Answer:

Yes, it is a function

Step-by-step explanation:

Each x value in the domain has its own output, and it does not have more than 1

Pls help stuck on it

Answers

The ordered pair for the bank is (4, 1)

Answer:

4,-1

Step-by-step explanation:

Please like!♥

For n = 10 and 1 = 0.59, what is P(X = 8)?
P(X = 8) =
(Round to four decimal places as needed.)

Answers

nCx⋅px⋅(1−p)n−x

llllllllllllllllllllllllllllllllllllll

x squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?

Answers

Answer:

[tex]x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}[/tex] and [tex]y=-1,\frac{1}{2}[/tex]

The ordered pair solutions are [tex](-\sqrt{\frac{7}{4}},0.5)[/tex], [tex](\sqrt{\frac{7}{4}},0.5)[/tex], [tex](-1,-1)[/tex], and [tex](1,-1)[/tex].

Step-by-step explanation:

I'm assuming the system is [tex]\left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.[/tex]:

[tex]x^2+y^2=2[/tex]

[tex]x^2+(2x^2-3)^2=2[/tex]

[tex]x^2+(4x^4-12x^2+9)=2[/tex]

[tex]x^2+4x^4-12x^2+9=2[/tex]

[tex]4x^4-11x^2+9=2[/tex]

[tex]4x^4-11x^2+7=0[/tex]

[tex]x^4-11x^2+28=0[/tex]

[tex](x^2-7)(x^2-4)=0[/tex]

[tex](4x^2-7)(x^2-1)=0[/tex]

[tex]4x^2-7=0[/tex]

[tex]4x^2=7[/tex]

[tex]x^2=\frac{7}{4}[/tex]

[tex]x=\pm\sqrt{\frac{7}{4}}[/tex]

[tex]x^2-1=0[/tex]

[tex]x^2=1[/tex]

[tex]x=\pm1[/tex]

[tex]y=2x^2-3[/tex]

[tex]y=2(\pm\sqrt{\frac{7}{4}})^2-3[/tex]

[tex]y=2({\frac{7}{4}})-3[/tex]

[tex]y=\frac{7}{2}-3[/tex]

[tex]y=\frac{1}{2}[/tex]

[tex]y=2x^2-3[/tex]

[tex]y=2(\pm1)^2-3[/tex]

[tex]y=2(1)-3[/tex]

[tex]y=2-3[/tex]

[tex]y=-1[/tex]

Therefore, [tex]x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}}[/tex] and [tex]y=-1,\frac{1}{2}[/tex]

The ordered pair solutions are [tex](-\sqrt{\frac{7}{4}},0.5)[/tex], [tex](\sqrt{\frac{7}{4}},0.5)[/tex], [tex](-1,-1)[/tex], and [tex](1,-1)[/tex].

What is 10% of 75? Use the double number line below to label your work and answer.

Answers

Answer: the answer is 7.5

Step-by-step explanation:

10% of 75 is 7.5 , this is because 75 divided by 10 is 7.5

I don’t understand this please help

Answers

Answer:

i think BC = 8.5

Step-by-step explanation:

19-(2+6.5+2)

19-10.5

8.5

What does Point P on the number line represent? (Use the hyphen for negative numbers, such as −9)

Number line from negative 8 to positive 10 in increments of 1 is shown. Only the even numbers are labeled. A point labeled P is placed at the third tick mark to the left of 0.

(5 points)

Answers

Answer:

P = -3, each line in the negative direction is 1 number

so you would have -1, -2, -3 , -4, etc.

P is on the -3 line.

See attached picture.

Step-by-step explanation:

(2+√3)+(4-√3)
[tex] [/tex]

Answers

Explanation :

________________________________

Given:

(2+√3)+(4-√3)

To Find:

Evaluate the expression

Solution:

Step 1:

Remove the parentheses

(2+√3)+(4-√3)

When there is + or no sign in front of an expression in parentheses, the expression remains the same

= 2 + √3+ 4-√3

Step 2:

Cancel the opposite terms √3 and -√3

"Two numbers are opposites if they have the same absolute value but different signs"

= 2 + 4

Step 3:

Add the numbers

= 6

Hence (2+√3)+(4-√3) = 6.

HELP ASAP Match each division expression to its quotient.

Answers

Answer:

2=-12.2/(-6.1

-2=16/(-8)

-3= -2 2/5/4/5

3= 3 3/7 / 1 1/7

Step-by-step explanation:

Given that f(x) = ax – 5 and f(4) = 15, determine the value of a.

Answers

Given that f(x) = ax – 5 and f(4) = 15, then the value of a is 5

The given function is:

f(x)  =  ax  -  5

If f(4)  =  15, then x = 4

Substitute x = 4 into f(x) = ax - 5

f(4)  =  a(4)  -  5

15   =  4a   -  5

Solve for a by adding 5 to both sides

15  +  5  =  4a  -  5  +  5

20    =  4a

Divide both sides by 4

4a/4   =  20/4

a    =  5

Given that f(x) = ax – 5 and f(4) = 15, then the value of a is 5

Learn more on linear functions here: https://brainly.com/question/15602982

what is the percent change of
30 to 90?
what is what is the percent change of 30 to 90?​

Answers

Answer:

200% increase

Step-by-step explanation:


A bag with 6 marbles has 2 blue marbles, 1 red marble, and 3 yellow marbles. A marble is chosen from the bag at random. What is the probability that it
is not blue?


Answers

There are 2 blue marbles out of 6 total marbles.

6-2 = 4 marbles are not blue.

Probability of not being blue = 4/6 which reduces to 2/3

Answer: 2/3

The constraints of a problem are listed below. What are the vertices of the feasible region?
x+3y<=6
4x+6y>=9
x>=0
y>=0

Answers

The vertices of the feasible region of the constraints is (0,2.5)

How to determine the vertices?

The constraints are given as:

x + 3y ≤ 6

4x + 6y ≥ 9

x ≥ 0,  y ≥ 0

Express the inequalities as equations

x + 3y = 6

4x + 6y = 9

Make x the subject in x + 3y = 6

x = 6 - 3y

Substitute x = 6 - 3y in 4x + 6y = 9

4(6 - 3y) + 6y = 9

Expand

24 - 12y + 6y = 9

Evaluate the like terms

-6y = -15

Divide by 6

y = 2.5

Substitute y = 2.5 in x = 6 - 3y

x = 6 - 3 * 2.5

Evaluate

x = -1.5

So, we have:

(x,y) = (-1.5, 2.5)

Recall that: x ≥ 0,  y ≥ 0

This means that the feasible region must have positive coordinates or zero

So, we set x = 0

(x,y) = (0, 2.5)

Hence, the vertices of the feasible region of the constraints is (0,2.5)

Read more about feasible region at:

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Question
Bill needs to mow his yard which has the dimensions in the shape below. What is the area of yard he needs to mow?
Note: Round your answer to one decimal place.
12 m
5 m
15 m

Answers

Answer:

Step-by-step explanation:

imagine you chop off a right triangle from the left side

now you have a rectangle and a right triangle

the rectangle

height 5

width 12

5 x 12 = 60

triangle

height 5

width 3

3 x 5 = 15

15 / 2 = 7.5

60 + 7.5 = 67.5 m^2

Answer: 67.5 m^2

Step-by-step explanation:

To find out the area of the yard, we split the shape up into a triangle and rectangle. The area of the triangle is,

A = 1 × b × h/2 = 1 × 3 × 5/2 = 7.5 m^2.

And the area of the rectangle is,

A = 12 × 5 = 60 m^2.

We then add the area of the triangle and the area of the rectangle.

A = 7.5 + 60 =67.5 m^2

Rounded to one decimal place, the area of the yard is 67.5 square meters.

The radioactive compound 14CO2 may be used as a tracer to study metabolism in plants. Suppose that a compound isolated from a plant exhibited 28, 32, 27, 39 and 40 counts of radioactive decays per minute. A blank sample used to measure the background counts of the radiation counter gave 28,21, 28 and 20 counts per minute. It appears that the isolated compound gives more counts than those from background. Can we be 95% confident that the compound is indeed radioactive?​

Answers

Using the t-distribution, it is found that since the test statistic is more than the critical value for the right-tailed test, it can be conclude that the isolated compound gives more counts than those from background, and hence, we can be 95% confident that the compound is indeed radioactive.

At the null hypothesis, it is tested if isolated compounds do not give more counts than those from background, that is:

[tex]H_0: \mu_1 - \mu_2 \leq 0[/tex]

At the alternative hypothesis, it is tested if the give more counts, that is:

[tex]H_1: \mu_1 - \mu_2 > 0[/tex]

Using a calculator, the mean and the standard deviation for each sample are given by:

[tex]\mu_1 = 33.2, s_1 = 6.058[/tex]

[tex]\mu_2 = 24.25, s_2 = 4.35[/tex]

Considering the sample sizes of 5 and 4, respectively, the standard errors are given by:

[tex]s_1 = \frac{6.058}{\sqrt{5}} = 2.71[/tex]

[tex]s_2 = \frac{4.35}{\sqrt{4}} = 2.175[/tex]

For the distribution of differences, the mean and standard error are given by:

[tex]\overline{x} = \mu_1 - \mu_2 = 33.2 - 24.25 = 8.95[/tex]

[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{2.71^2 + 2.175^2} = 3.4749[/tex]

The standard error was found from the standard deviation for each sample, hence, the t-distribution is used.

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis, hence:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

[tex]t = \frac{8.95 - 0}{3.4749}[/tex]

[tex]t = 2.58[/tex]

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with 5 + 4 - 2 = 7 df and a 0.05 significance level is of [tex]t^{\ast} = 1.895[/tex]

Since the test statistic is more than the critical value for the right-tailed test, it can be conclude that the isolated compound gives more counts than those from background, and hence, we can be 95% confident that the compound is indeed radioactive.

A similar problem is given at brainly.com/question/24826023

please helppppppppppppp ASAP. please ensure to use step by step explanation. thanks.

Answers

I'll do the first two parts to get you started.

=====================================================

Part (i)

We can show that the operation [tex]\nabla[/tex] is not commutative by picking two random and different real numbers for a,b. In other words, I'm using a counter-example.

Let's say we go for a = 1 and b = 2

[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\1 \nabla 2 = \frac{3*1+2}{5} - 1\\\\1 \nabla 2 = \frac{5}{5} - 1\\\\1 \nabla 2 = 1 - 1\\\\1 \nabla 2 = 0\\\\[/tex]

Now let's swap the values. We'll try a = 2 and b = 1

[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\2 \nabla 1 = \frac{3*2+1}{5} - 1\\\\2 \nabla 1 = \frac{7}{5} - 1\\\\2 \nabla 1 = 1.4 - 1\\\\2 \nabla 1 = 0.4\\\\[/tex]

We can see that [tex]1 \nabla 2[/tex] and [tex]2 \nabla 1[/tex] are not the same value. In general, [tex]a \nabla b \ne b \nabla a[/tex] Therefore, the operation [tex]\nabla[/tex] is not commutative.

The only time [tex]a \nabla b = b \nabla a\\\\[/tex] is true is when [tex]a = b[/tex], since,

[tex]\frac{3a+b}{5}-1 = \frac{3b+a}{5}-1\\\\\frac{3a+a}{5}-1 = \frac{3a+a}{5}-1\\\\\frac{4a}{5}-1 = \frac{4a}{5}-1\\\\[/tex]

It's when [tex]a \ne b[/tex] is where the operation becomes noncommutative.

Another way to arrive at the [tex]a = b[/tex] condition is to solve the original equation for either 'a' or b.

=====================================================

Part (ii)

Using the previous part as inspiration, we'll do a counter-example to show that the operation is not associative. Pick 3 random values for a,b,c. Here are the values I'll pick.

a = 1b = 2c = 3

Then,

[tex]d = b \nabla c = \frac{3b+c}{5}-1 = \frac{3*2+3}{5}-1 = 0.8\\\\a \nabla (b \nabla c) = a \nabla d = \frac{3a+d}{5}-1 = \frac{3*1+0.8}{5}-1 = -0.24\\[/tex]

Next, we can say:

[tex]d = a \nabla b = \frac{3a+b}{5}-1 = \frac{3*1+2}{5}-1 = 0\\\\(a \nabla b) \nabla c = d \ \nabla c = \frac{3d+c}{5}-1 = \frac{3*0+3}{5}-1 = -0.4[/tex]

Let's compare the two outputs:

[tex]a \nabla (b \nabla c) = -0.24\\\\(a \nabla b) \nabla c = -0.4[/tex]

They don't match up, so [tex]a \nabla (b \nabla c) \ne (a \nabla b) \nabla c[/tex] when (a,b,c) = (1,2,3).

In general, the operation is not associative in R.

What are the coordinates of the point (-4, 2) after a translation 2 units left and 2 units up?

A (-2, 0)
B (-6,0)
C (-2, 4)
D (-6, 4)

Answers

Answer:

the answer you're looking for is D. when you move to the left the -4 becomes -6 and when you move up 2 becomes 4.

At a local movie theatre, sodas cost$4.50 and bags of popcorn cost &1.50. Kirk buys three times as many bags of popcorn as sodas and pays a total of $36. Write a system of equations and solve it using any method to determine how many of each item Kirk bought.

Answers

Answer:

this might help

Step-by-step explanation:

this might be kinda similar

Chickens and rabbits

In the yard were chickens and rabbits. Together they had 18 heads and 56 legs. How many chickens and how many rabbits were in the yard?

Correct answer:

chickens:  8

rabbits:  10

Step-by-step explanation:

a+b=18

2a+4b=56

a=8

b=10

a+b = 18

2•a+4•b=56

a+b = 18

2a+4b = 56

a = 8

b = 10

Evaluate the expression when c=4. c^4 + 6

Answers

Answer:

262

Step-by-step explanation:

4x4x4x4+6

256+6

262

Select the interval where g(2) < 0.

(graphed on khan academy)

Answers

Answer:

the number 0 Originally called finding the vertical asymptote.

Research workshop: Generating Research questions and evaluating sources.

Take notes for two sources

Take notes on your second source

Answers

Based on the information, the best research question that Juan should choose will be "How does playing a team sport affect a child's development?"

A research question simply means a question that a researcher wants to answer. It should be noted that choosing a research question is an important element in research.

From the complete question, it should be noted that since Juan is writing a paper about children who play team sports, and he has different research questions, he should choose the one that conveys the research appropriately.

In this case, the best option will be  "How does playing a team sport affect a child's development?"

Learn more about research questions on:

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please answer the file question

Answers

Answer:

  x = 15

Step-by-step explanation:

Corresponding sides have the same ratio:

  UV/PR = TV/QR

  (x +6)/14 = (x -3)/8

  4(x +6) = 7(x -3) . . . . . . multiply by 56

  4x +24 = 7x -21 . . . . . . eliminate parentheses

  45 = 3x . . . . . . . . . . . add 21-4x

  15 = x . . . . . . . . . . . .divide by 3

_____

Alternate solution

The long-side : short-side ratios for the two triangles are ...

  14 : 8 = (x +6) : (x -3)

If we look at the differences between the ratio numbers we see ...

  14 -8 = 6

  (x +6) -(x -3) = 9

That is, the numbers in the second ratio must be 9/6 = 3/2 times the numbers in the first ratio. In other words, ...

  x -3 = (3/2)(8) = 12

  x = 15

Check: x +6 = 3/2(14) ; 15 +6 = 21

Wheel Fun offers rentals of paddle boats that can be enjoyed by 2 or 3 riders. The price for renting a paddle boat is $15 for each hour. Customers must also pay a $20 deposit on the rental. Write an equation that can be used to determine the price, y for renting a paddle boat for x, hours?

Answers

Answer:

15+20=35+15 And then add an additional plus 15 for each hour

Step-by-step explanation:

Evaluate 4x^2 y^-3 for x=3 and y=-2

Answers

Answer:

36   and -1/8

Step-by-step explanation:

x^2 = 3^2 = 9 * 4 = 36

y^-3 = (-2)^-3 = -1/8

Answer:

-4.5.

Step-by-step explanation:

4x^2 y^-3

= 4x^2 / y^3

When x = 3 and y = -2

it is 4(3)^2 / (-2)^3

= 36 / -8

= -4.5.

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