Friction between our feet and the surface we walk on is desirable. True False​

Answers

Answer 1

Answer:

True

Explanation:

Friction Between Our Feet And The Surface We Walk On Is Desirable. True False
Answer 2
The answer to the question is true.

Have a nice day

Related Questions

A parachute falling to the ground.

Answers

Answer:

a parachute falling to the ground is uniform

In the fishbowl, the glass, water, rocks, and plastic plants are in thermal equilibrium. This situation means the temperature of the rocks is...​

Answers

To cold which it throws off the equilibrium of the other things and sticks to it longer

A kitten sits in a lightweight basket near the edge

Answers

Answer:

So where's the problem now?

A kitten is just sitting

a car 150m to the east then backtracks 30m to the west. Describe the mathematical operation you will use to determine the net movement of the car

Answers

Answer:

Total displacement will be 120m

Explanation:

Since displacement is shortest distance travelled

Td= 150m east - 30m west ( Since they are opposite in direction)

Td= 120m East


Select all the correct answers.
In most cases, what happens to a liquid when it cools?
Its density increases.
Its density decreases.
its mass increases.
Its mass decreases.
Its volume increases.
Its volume decreases.

Answers

Answer:

the volume increases and the density decreases

Explanation:

This is because when a liquid is cooled it expands due anomalous expansion of water hence volume increases .The density decreases. For instance ice floats on water since it has lesser mass than water per unit volume.

it increased in volume and density! this is because liquid expands as it cools (most noticeable with ice!) hope this helps :)

A 0.60- m -tall barrel is filled with water (with a weight density of 9800 N/m3 ). Find the water pressure on the bottom of the barrel. Express your answer to two significant figures and include the appropriate units.

Answers

Answer:

P =  ρ g H       explains the pressure of a uniform column of density ρ

P = ρ H            where ρ is given as a weight density

P = 9800 N/m^3 * .60 m = 5880 (5900) N / m^2

Note N/m^2 = Force / Area      the definition of pressure

Mrs. Martin is holding a ball from a height of 3.2 m that has the potential energy of 23 J, calculate the mass of the ball.

Answers

Answer:

0.73kg

Explanation:

Potential gravitational energy is equal to [tex]Pe=mgh[/tex], where Pe is potential gravitational energy, m is mass in kilograms, g is gravity in m/s^2 and h is height in meters.

Substitute:

[tex]Pe=mgh\\23=m*9.8*3.2\\23=31.36m\\0.73=m[/tex]

If the intensity of radiation from an x-ray tube at 2 feet is 100 mR/min, the intensity at a distance of 5 feet will
be?

Answers

Answer:

100 mR

Explanation:

A turntable is switched from 11.3 rad/s to 1.9 rad/s, and the platter goes through an angle of 17.95 radian in reaching the new angular speed. What is the angular acceleration of the platter?

Answers

Hi there!

We can use the angular equivalent of the following kinematic equation:

[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta[/tex]

ωf = final angular velocity (1.9 rad/s)

ωi = initial angular velocity (11.3 rad/s)

α = angular acceleration (? rad/s²)

θ = angular displacement (17.95 rad)

We can rearrange the equation to solve for angular acceleration.

[tex]\omega_f^2 - \omega_i^2 = 2\alpha \theta\\\\\alpha = \frac{\omega_f^2 - \omega_i^2}{2\theta}[/tex]

Plug in the given values and solve.

[tex]\alpha = \frac{1.9^2 - 11.3^2}{2(17.95)} = \boxed{3.456 \frac{rad}{s}}[/tex]

List three methods of energy transport in nature and explain how the energy is being transferred in each of those methods. Which two are means by which energy is transported inside the Sun?

This question is for my college astronomy class!

Answers

First normal transportation is the light energy of sun is transmitted to our earth .

Next for transportation inside sun they are

Fusion and fission

Fusion means when two hydrogen atoms reacts to form helium nucleus .

Fission means when one nucleus is broken into two or more nucleus

Explanation:

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A total charge of Q coulomb is uniformly distributed along a rod 40cm in length.find find the electric field intensity 20cm away from the rod along its perpendicular bisector?

Answers

For a total charge of Q coulomb is uniformly distributed along a rod 40cm in length,  the electric field intensity 20cm away from the rod is mathematically given as

E1=1.598*10^11v/m

What is the electric field intensity 20cm away from the rod along its perpendicular bisector?

Generally, the equation for the  initial electric field intensity   is mathematically given as

[tex]dEp=\int{kd/r}cosd\theta[/tex]

Therefore

[tex]e1=kd/r{sin\theta2+sinR1}[/tex]

Hence

[tex]E1=(9*10^9/20*10^{-2})({sin45+sin45})*B/40*10^-2[/tex]

E1=B*9*10^{13})/(10*110)*[tex]\sqrt{2}[/tex]

E1=1.598*10^11v/m

In conclusion, the electric field intensity

E1=1.598*10^11v/m

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In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the maximum centripetal acceleration of a cheetah was measured to be 18 m/s2. What minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

Answers

coefficient of static friction is 1.7329

Explanation:

given data

velocity = 60 mph

acceleration  = 17 m/s²

to find out

coefficient of static friction

solution

we will apply here centripetal force equation

that is

m×v²/r  =  µ × m × g      ..................1

here v²/r is centripetal acceleration and m is mass and  µ  is coefficient static friction so

µ = a / g

µ = 17 / 9.81

µ  = 1.7329

so coefficient of static friction is 1.7329

An unknown fluid flows at a speed of 31 m/s. Suppose the fluid has a mass of 47 kg runs at this speed. What is the fluid’s kinetic energy?

Answers

Answer:

22583.5J

Explanation:

KE=1/2 mv^2

=1/2*47Kg*(31m/s^2)

=23.5Kg * 961m/s^2

=22583.5J

A potter's wheel is spinning with an initial angular velocity of 11 rad/s . It rotates through an angle of 80.0 rad in the process of coming to rest.
What was the angular acceleration of the wheel?
How long does it take for it to come to rest?

Answers

The angular acceleration of the wheel approximately -0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s.It need approximately 14.474 s to come to rest.

Introduction

Hi ! I will help you to discuss about Proportionally Changes in Circular Motion. The analogy of proportionally changes in circular motion is same as the analogy of proportionally changes in direct motion. Here you will hear again the terms acceleration and change in speed, only expressed in the form of a certain angle coverage. Before that, in circular motion, it is necessary to know the following conditions:

1 rotation = 2π rad1 rps = 2π rad/s1 rpm = [tex] \sf{\frac{1}{60} \: rps}[/tex] = [tex] \sf{\frac{1}{30}\pi \: rad/s}[/tex]

Formula Used

The following equations apply to proportionally changes circular motion:

Relationship between Angular Acceleration and Change of Angular Velocity

[tex] \boxed{\sf{\bold{\omega_t = \omega_0 + \alpha \times t}}}[/tex]

With the following conditions:

[tex]\sf{\omega_t}[/tex] = final angular velocity  (rad/s)[tex]\sf{\omega_0}[/tex] =  initial angular velocity (rad/s)[tex]\sf{\alpha}[/tex] = angular acceleration (rad/s²)t = interval of the time (s)Relationship between Angular Acceleration and Change of [tex]\sf{\theta}[/tex] (Angle of Rotation)

[tex] \boxed{\sf{\bold{\theta = \omega_0 \times t + \frac{1}{2} \times \alpha \times t^2}}}[/tex]

Or

[tex] \boxed{\sf{\bold{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}}}[/tex]

With the following condition :

[tex]\sf{\theta}[/tex] = change of the sudut (rad)[tex]\sf{\alpha}[/tex] = angular acceleration (rad/s²)t = interval of the time (s)[tex]\sf{\omega_t}[/tex] = final angular velocity  (rad/s)[tex]\sf{\omega_0}[/tex] =  initial angular velocity (rad/s)

Problem Solving

We know that :

[tex]\sf{\omega_t}[/tex] = final angular velocity  = 0 rad/s >> see in the sentence "in the process of coming to rest."[tex]\sf{\omega_0}[/tex] =  initial angular velocity = 11 rad/s[tex]\sf{\theta}[/tex] = change of the sudut = 80.0 rad

What was asked :

[tex]\sf{\alpha}[/tex] = angular acceleration = ... rad/s²t = interval of the time = ... s

Step by step :

[tex]\sf{\alpha}[/tex] = ... rad/s²

[tex] \sf{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta} [/tex]

[tex] \sf{0^2= (11)^2 + 2 \times \alpha \times 80} [/tex]

[tex] \sf{0 = 121 + 160 \alpha} [/tex]

[tex] \sf{-160 \alpha = 121} [/tex]

[tex] \sf{\alpha = \frac{121}{-160}}[/tex]

[tex] \sf{\alpha = -0.75625 \: rad/s^2 \approx \boxed{-0.76 \: rad/s^2}}[/tex]

t = ... s

[tex] \sf{\alpha = \frac{\omega_0 - \omega_t}{t}}[/tex]

[tex] \sf{-0.76 = \frac{0 - 11}{t}}[/tex]

[tex] \sf{-0.76t = -11}[/tex]

[tex] \sf{t = \frac{- 11}{-0.76}}[/tex]

[tex] \boxed{\sf{t \approx 14.474 \: s}}[/tex]

Conclusion

So :

The angular acceleration of the wheel approximately -0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s.It need approximately 14.474 s to come to rest.

You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
110
32°
36°
120
40°
128
440
133
48°
127
52
119
56°
109
60°
100
64°
91
68°
77
72°
63
At which angle will the performer travel the longest distance?

Answers

Answer:

44°

Explanation:

Look for the longest distance under the 'Distance ' column....look to the left to find the corresponding angle

  Table clearly shows that the longest distance (133 ft) occurs at angle of 44°

An aquarium heater transfer 1200kJ of the heat to 75000g of water. What is the increase in the waters temperature?

Answers

Answer:

Energy = mcΔt

where m the mass ,  c specific heat capacity

Δt is the change in temperature

1200x10^3=75x4184xΔt

Δt=3.82°

Explanation:

You just took a bit of you favorite food. Tell a story what happens as the food passes through the alimentary canal from the foods point of view (you are the food). Discuss all the structures in which you come into contact with in the digestive system and their functions for helping digest foods. Don't forget about peristalsis, the accessory organs, and their functions as well.

Answers

Answer:

The digestive system is made up of the gastrointestinal tract—also called the GI tract or digestive tract—and the liver, pancreas, and gallbladder. The GI tract is a series of hollow organs joined in a long, twisting tube from the mouth to the anus. The hollow organs that make up the GI tract are the mouth, esophagus, stomach, small intestine, large intestine, and anus. The liver, pancreas, and gallbladder are the solid organs of the digestive system.The small intestine has three parts. The first part is called the duodenum. The jejunum is in the middle and the ileum is at the end. The large intestine includes the appendix, cecum, colon, and rectum. The appendix is a finger-shaped pouch attached to the cecum. The cecum is the first part of the large intestine. The colon is next. The rectum is the end of the large intestine

Explanation:


The power in an electrical current is given by the equation

Answers

Answer:

P = VI

Explanation:

the power is equal to the current × voltage

Answer:

P = V • I

Explanation:

Power = Voltage • Current

What does the term wavelength refer to?
the distance between the equilibrium position and a crest

the distance between the equilibrium position and a trough

the time taken to complete one cycle

the distance between two consecutive crests or troughs

Answers

Answer:

the distance between two consecutive crests or troughs

What is the momentum of a 35–kilogram cart moving at a speed of 1.2 meters/second

Answers

Answer:

42

Explanation:

P = M × V

so

P = 35 × 1.2

P = 42

Answer:

42kg•m/s

Explanation:

p=m*v

A rock is suspended from the lower end of a light string. When the rock is totally immersed in water, the tension in the string is 1.20 N. When the rock is totally immersed in ethanol, the tension in the string is 1.60 N. Calculate the weight of the rock.

Answers

For a rock is suspended from the lower end of a light string,  the weight of the rock is mathematically given as

W = 3.10 N

What is the weight of the rock.?

Generally, the equation for the W = Fh1+  is mathematically given as

W = Fh+T1

Where

PiVg+T1 = P2V9+T

(1000) V(9.8) + 1.2 = (790) V(9.8) + 1.6

V = 1.944* 10^-4 m3

In conclusion

W = Fh+T1

W = (1000) (1.944 * 10-4) (9.8) + 1.2

W = 3.10 N

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The current in the wires of a circuit is 60.0 milliAmps. If the
voltage impressed across the ends of the circuit were tripled
(with no change in its resistance), then its new current would
be milliAmps.

Answers

Answer:

180 m amp

Explanation:

V = IR

v/r = i     mutiply both sides by

3

3v / r = 3 i     so the current will triple to 180 mAmp

[tex]Question: $x_{1}=\frac{5}{2}[\sin (2 \pi t)+\cos (2 \pi t)], x_{2}=5\left[\sin \left(2 \pi t+\frac{\pi}{4}\right)\right]$[/tex]
Find the ratio of the amplitude of the given motion?
Options:
[tex](a) $\sqrt{2}: 1$\\(b) $2: 1$\\(c) $1: \sqrt{2}$\\(d) $1: 2$[/tex]

Answers

Condense x₁ to get

sin(2πt) + cos(2πt) = √2 • (sin(2πt) + cos(2πt))/√2

… = √2 (cos(2πt) cos(π/4) + sin(2πt) sin(π/4))

… = √2 cos(2πt - π/4)

So the amplitude of x₁ is (5/2) • √2 = 5/√2, while the amplitude of x₂ is 5. The ratio between them is then 5/√2 : 5, or equivalently 1/√2 : 1 or 1 : √2.

Radioactive isotopes can be used to find the age of rocks, fossils, or other artifacts. Carbon-14 has a half-life of 5,730 years. Suppose a sample of charcoal from a primitive fire pit contains one eighth of its original amount of carbon-14. How old is the sample?

Answers

Answer:

1/8 = (1/2)^3

This implies the sample has decayed for 3 half lives

3 * 5730 yrs = 17,200 years

A ball is thrown directly upwards at 25 ms and the same time another ball is released from height of loom. At what height and time will the balls meets?​

Answers

Answer:

Explanation:

When the balls meets, the time should be the same, let say t.

For the first ball (released from a loom):

[tex]\bar{h}=\frac{1}{2}gt^{2}[/tex] (Free fall motion) ([tex]\bar{h}[/tex] = the distance travelled by the first ball, measured from the loom)

So, we can find that [tex]\bar{h}=\frac{1}{2}(10t^{2})=5t^{2}[/tex]

For the second ball (which is thrown directly upwards):

[tex]y=v_{o}t-\frac{1}{2}gt^{2} = 25t-5t^{2}[/tex]

Because the height of the loom is h :

[tex]h=\bar{h}+y[/tex]

[tex]h=25t[/tex]

So, the time when two balls meets is : [tex]t=\frac{h}{5}[/tex] (In this question, the height of the loom h is not declared). When the height of the loom is known, you can calculate the time and the value of [tex]\bar{h}[/tex] or y

What is the magnitude of the electric field 3m away from the source if the electric potential is described by the function f(x)=2x+3, where x=2?

Answers

Hi there!

Recall the following relationship between the electric field and electrical potential:
[tex]E = -\frac{dV}{dx}[/tex]

Begin by taking the derivative of the electric potential function using basic power and constant rules.

Remember:
[tex]\frac{dy}{dx}x^n = nx^{n - 1}[/tex]

[tex]\frac{dy}{dx}(C) = 0[/tex]

Differentiate the function, and take its negative.

[tex]-\frac{dV}{dx} = -(2(1)(x^{1-1}) + 0 )\\\\-\frac{dV}{dx} = -2[/tex]

The magnitude is the absolute value, so:
[tex]|\frac{dV}{dx} = |-2| = \boxed{2 \frac{V}{m}}[/tex]

Which nucleus completes the following equation?

Answers

Answer:

I think that CL IS THE ONLY BEST ANSWER

Explanation:

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A mass m is dropped from height h above the top of a spring of constant k mounted vertically on the floor.
Find the spring's maximum compression.
Express your answer in terms of some or all of the variables: m , h , k , and gravitational constant g .

m*g/k (1 + √(1 + 2k*h/m*g))
Is this answer correct and why? Or is it something else?

Answers

I think your answer may be wrong.

The mass's potential energy at the start is mgh; this gets converted to kinetic energy as it falls (assuming no air resistance), so that by conservation of energy,

mgh = 1/2 mv²   ⇒   v = √(2gh)

where v is the velocity of the mass when it first comes into contact witht he spring.

As the spring is compressed, it performs work on the mass as it slows to a rest at maximum compression. If x is the maximum compression, then the spring does -1/2 kx² of work. (negative since it opposes the downward fall)

By the work-energy theorem (total work is equal to change in kinetic energy),

-1/2 kx² = 0 - 1/2 mv²

Plug in v and solve for x :

kx² = m (√(2gh))²

x² = 2mgh/k

x = √(2mgh/k)


15. A pattern of weather and
climate over three months is called a

Answers

Answer:

Explanation:

weather pattern

A pattern of weather over three months is called a climate.

What is climate?

Climate is the long-term pattern of weather in a particular area. Weather can change from hour-to-hour, day-to-day, month-to-month or even year-to-year. A region's weather patterns, usually tracked for at least 30 years, are considered its climate.

Weather refers to short-term changes in the atmosphere, climate describes what the weather is like over a long period of time in a specific area.

A pattern of weather over three months is called a climate.

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list down the general of the office of guardian and tutor​

Answers

Answer:

legal guardians, the four types: personal guardians, financial guardians, conservators, and pet “guardians”

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