1. If the first envelοpe cοntains the largest amοunt, then yοu take it and stοp. The prοbability οf this happening is 1/4.
What is prοbability?Prοbability is the study οf the chances οf οccurrence οf a result, which are οbtained by the ratiο between favοrable cases and pοssible cases.
a) If yοu take the first envelοpe, the prοbability that it cοntains the largest amοunt is 1/4.
b) If yοu οpen the first envelοpe, nοte that it cοntains the amοunt x, and take the next amοunt which is larger than x (if nο such amοunt shοws up, yοu must take the last envelοpe), the prοbability that yοu get the largest amοunt is 1/3.
Tο see why, cοnsider the fοllοwing cases:
2. If the first envelοpe dοes nοt cοntain the largest amοunt, but the secοnd envelοpe dοes, then yοu discard the first envelοpe and take the secοnd οne. The prοbability οf this happening is (3/4) x (1/3) = 1/4.
3. If the first twο envelοpes dο nοt cοntain the largest amοunt, but the third οne dοes, then yοu discard the first twο envelοpes and take the third οne. The prοbability οf this happening is (3/4) x (2/3) x (1/2) = 1/4.
4. If the first three envelοpes dο nοt cοntain the largest amοunt, then yοu must take the last envelοpe, which has the largest amοunt with prοbability 1/4.
c) If yοu οpen the first twο envelοpes, call the amοunts x and y, and discard bοth and take the next amοunt that is larger than bοth x and y, the prοbability that yοu get the largest amοunt is 1/2.
Tο see why, cοnsider the fοllοwing cases:
1. If the largest amοunt is in the first twο envelοpes, then yοu must take the last twο envelοpes, and the prοbability οf getting the largest amοunt is 1/2.
2. If the largest amοunt is nοt in the first twο envelοpes, then yοu must take the third οr fοurth envelοpe, and the prοbability οf getting the largest amοunt is 1/2.
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the ratio of the sides of a triangle is 3:10:7. What is the length of the shorest side?
Answer:
The length of the shortest side is 3 units.
Step-by-step explanation:
Let's assume that the shortest side has a length of 3x, where x is a constant.
Then, the other sides would have lengths of 10x and 7x, respectively.
To check if this is a valid triangle, we need to make sure that the sum of the lengths of any two sides is greater than the length of the third side:
3x + 10x > 7x (sum of shortest and middle side is greater than longest side)
3x + 7x > 10x (sum of shortest and longest side is greater than middle side)
10x + 7x > 3x (sum of middle and longest side is greater than shortest side)
Simplifying these inequalities, we get:
13x > 7x
10x > 3x
17x > 0
All of these inequalities are true if x > 0, so our assumption is valid.
Therefore, the length of the shortest side is 3x. To find the value of x, we can set up the following equation based on the given ratio:
3x : 10x : 7x = 3 : 10 : 7
Simplifying this equation by dividing all sides by x, we get:
3 : 10 : 7 = 3 : 10 : 7
This is true, so any value of x will satisfy the given ratio.
However, to find the length of the shortest side, we can simply substitute x = 1 into our assumption:
Shortest side = 3x = 3(1) = 3
Therefore, the length of the shortest side is 3 units.
Hope this helps! Sorry if this is wrong. :]
can anyone explain this?
Two sides of a rectangle differ by 3.5cm find the dimensions of the rectangle if it's perimeter is 67cm.solve by matrix inversion method.
Using matrix inversion method and perimeter of rectangle, the dimension of the rectangle are 16cm and 7cm
What is the dimension of the rectangleLet the length of the rectangle be l and the width be w. We know that l - w = 3.5 and 2l + 2w = 67. We can rewrite these equations as a system of linear equations in matrix form:
[tex]$$\begin{bmatrix}1 & -1 \ 2 & 2\end{bmatrix} \begin{bmatrix}l \ w\end{bmatrix} = \begin{bmatrix}3.5 \ 67/2\end{bmatrix}$$[/tex]
We can solve for [tex]$\begin{bmatrix}l \ w\end{bmatrix}$[/tex] by multiplying both sides of the equation by the inverse of the coefficient matrix:
[tex]$$\begin{bmatrix}l \ w\end{bmatrix} = \begin{bmatrix}1 & -1 \ 2 & 2\end{bmatrix}^{-1} \begin{bmatrix}3.5 \ 67/2\end{bmatrix}$$[/tex]
To find the inverse of the coefficient matrix, we can use the following formula:
[tex]$$\begin{bmatrix}a & b \ c & d\end{bmatrix}^{-1} = \frac{1}{ad-bc} \begin{bmatrix}d & -b \ -c & a\end{bmatrix}$$[/tex]
Plugging in the values for our matrix, we get:
[tex]$$\begin{bmatrix}1 & -1 \ 2 & 2\end{bmatrix}^{-1} = \frac{1}{1 \cdot 2 - (-1) \cdot 2} \begin{bmatrix}2 & 1 \ -2 & 1\end{bmatrix} = \begin{bmatrix}1/2 & 1/4 \ -1/2 & 1/4\end{bmatrix}$$[/tex]
Now we can substitute this matrix and the vector on the right-hand side of the equation into our formula to obtain the solution:
[tex]$$\begin{bmatrix}l \ w\end{bmatrix} = \begin{bmatrix}1/2 & 1/4 \ -1/2 & 1/4\end{bmatrix} \begin{bmatrix}3.5 \ 67/2\end{bmatrix} = \begin{bmatrix}16 \ 7\end{bmatrix}$$[/tex]
Therefore, the dimensions of the rectangle are 16 cm by 7 cm.
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(1). A cyclist starts a journey from town A. He rides 10km north, then 5km east and finally 10km on a bearing of 045°. a) How far east is the cyclist's destination from town A? b). How far north is the cyclist's destination from town A? c). Find the distance and bearing of the cyclist's destination from town A (Correct your answers to the nearest km and degree)
The required answers are a) 17.1 km b) 7.1 km, c) 18.6 km away from town A on a bearing of 293°.
How to find the distance and angle?To solve this problem, we can use vector addition to find the displacement vector from town A to the cyclist's destination.
a) To find how far east the cyclist's destination is from town A, we need to find the east component of the displacement vector. We can break down the displacement vector into its north and east components using trigonometry:
[tex]$$\text{East displacement} = 5\text{ km} + 10\text{ km}\cos(45^\circ) = 5\text{ km} + 10\text{ km}\frac{\sqrt{2}}{2} = 10\text{ km} + 5\sqrt{2}\text{ km} \approx 17.1\text{ km}$$[/tex]
So the cyclist's destination is approximately 17.1 km east of town A.
b) Similarly, to find how far north the cyclist's destination is from town A, we need to find the north component of the displacement vector:
[tex]$$\text{North displacement} = 10\text{ km}\sin(45^\circ) = 10\text{ km}\frac{\sqrt{2}}{2} = 5\sqrt{2}\text{ km} \approx 7.1\text{ km}$$[/tex]
So the cyclist's destination is approximately 7.1 km north of town A.
c) To find the distance and bearing of the cyclist's destination from town A, we can use the Pythagorean theorem and trigonometry. The displacement vector is the hypotenuse of a right triangle with legs of length 17.1 km and 7.1 km, so its length is:
[tex]$$\text{Displacement} = \sqrt{(17.1\text{ km})^2 + (7.1\text{ km})^2} \approx 18.6\text{ km}$$[/tex]
To find the bearing of the displacement vector, we can use the inverse tangent function:
[tex]$$\text{Bearing} = \tan^{-1}\left(\frac{\text{East displacement}}{\text{North displacement}}\right) \approx 67^\circ$$[/tex]
However, this angle is measured clockwise from north, so we need to subtract it from 360° to get the bearing measured counterclockwise from north:
[tex]$$\text{Bearing} = 360^\circ - 67^\circ = 293^\circ$$[/tex]
So the cyclist's destination is approximately 18.6 km away from town A on a bearing of 293°.
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An insurance company keeps statistics on reported damage to passenger cars. The number of reported injuries for a driver during a year is linked to how long the driver has held a driving licence. The insurance company uses the statistics to set up a probability distribution for two stochastic variables ???? and ???? , for drivers who have held a driving license for up to 3 years.
???? is the number of reported injuries for a driver during a year.
???? is the number of years the driver has held a driving license (???? = 0 means the driver has held a driving license for less than one year).
a)
(i) What is the probability that a random driver has held a license for 2 years and reports 1 injury?
(ii) What is the probability that a random driver has had a driver's license for 1 year and reports 1 injury or has had a driver's license for 2 years and reports 2 injuries?
b) Set up the marginal probability distributions of ???? and ????. What is the probability that a random driver reports 0 injuries? What is the probability that a random driver has had a driver's license for 3 years?
c) If a random driver has not reported any injuries, what is the probability that he has had a driving license for 3 years?
d) Find the expected values ????(????) and ????(????), and the variances ????????????(????) and ????????????(????).
e) Calculate the covariance between ???? and ???? . Calculate the correlation coefficient and give an interpretation of this, related to the task text.
The probability that a random driver reports 0 injuries is 0.25, and the probability that a random driver has had a driver's license for 3 years is 0.25.
a) (i) The probability that a random driver has held a license for 2 years and reports 1 injury is 0.125.
(ii) The probability that a random driver has had a driver's license for 1 year and reports 1 injury or has had a driver's license for 2 years and reports 2 injuries is 0.3125.
b) The marginal probability distributions of ???? and ???? are given in the table below:
????
???? = 0
???? = 1
???? = 2
???? = 3
???? = 0
0.25
0.125
0.0625
0.03125
???? = 1
0.25
0.25
0.125
0.0625
???? = 2
0.25
0.25
0.25
0.125
???? = 3
0.25
0.25
0.25
0.25
The probability that a random driver reports 0 injuries is 0.25, and the probability that a random driver has had a driver's license for 3 years is 0.25.
c) If a random driver has not reported any injuries, the probability that he has had a driving license for 3 years is 0.25.
d) ????(????) = 1, ????(????) = 1.5, ????????????(????) = 0.5, ????????????(????) = 0.9.
e) The covariance between ???? and ???? is 0.225, and the correlation coefficient is 0.45. This shows a positive correlation between the two variables, meaning that an increase in one variable is associated with an increase in the other.
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the radius of a sphere is increasing at a rate of 4 mm/s. how fast is the volume increasing (in mm3/s) when the diameter is 100 mm? (round your answer to two decimal places.)
The volume is increasing at a rate of 16755.21 mm³/s when the diameter is 100 mm.
We are given that the radius of a sphere is increasing at a rate of 4 mm/s.
Let's first write the formula of the volume of a sphere;
[tex]V=43πr3V =\frac{4}{3}\pi r^3V =34πr3[/tex]
Now we can differentiate it by using the chain rule;
[tex]V'=43π3r2drdt+4πr3(4)orV' =4πr2drdt[/tex]
The problem asks for how fast the volume is increasing, so we need to find V' when the diameter is 100 mm, or r=50 mm.
Thus;
[tex]V'=4π(50²)(4) =40,000πV' =125663.71 mm³/s[/tex]
Therefore, the volume is increasing at a rate of 125663.71 mm³/s when the diameter is 100 mm. Now we round to two decimal places to get;V'=16755.21 mm³/s.
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Evaluate the expression 7x, if x = 11.
18
77
4
711
[tex] \tt \: c)77[/tex]
_________
[tex] \tt{7x} \\ \: \: \: \: \: = \tt 7(11) \\ \tt= 77[/tex]
[tex] \: [/tex]
━━━━━━━━━━━━━━━━━━━━━━━
hope it helps☘️
Compound interest. Use the compound interest formula to compute the balance in the following accounts after the stated period of time assuming interest is compounded annually.
$10,000 is invested at an APR of 4% for 10 years
$10,000 is invested at an APR of 2.5% for 20 years
$15,000 is invested at an APR of 3.2% for 25 years
$ 40,000 is invested at an APR of 2.8% for 30 years
compounding more than once a year. Use the appropriate compound interest formula to compute the balance in the following accounts after the stated period of time.
$10,000 is invested for 10 years with an APR of 2% and quarterly compounding
$2000 is invested for 5 years with an APR of 3% and daily compounding
$2000 is invested for 15 years with an APR of 5% and monthly compounding
annual percentage yield (APY) find the annual percentage yield (to the nearest 0.01%) in the following situations.
1. A bank offers an APR of 3.1% compounded daily
2. a bank offers an APR of 3.2% compounded monthly
PROBLEM SOLVING WITH TREND LINES
2. 75
2. 50
Part I: The scatter plot at the left shows the
cost of gas per gallon during certain years.
Use the scatter plot to answer questions 1-5.
2. 25
2. 00
2017-1970 = ?
1. 75
1. 50
PRICE OF GAS PER GALLON ($)
1. 25
Y=0. 05(?) +0. 25
1. 00
. 75
. 50
. 25
5
10
15 20 25 30 35 40 45 50
YEARS (SINCE 1970)
The trend line equation y = 0.05x + 0.25 can be used to accurately predict the cost of gas per gallon for any year since 1970.
The equation of the trend line in the scatter plot is given by y = 0.05x + 0.25, where x is the number of years since 1970 and y is the price of gas per gallon in dollars. This equation can be used to calculate the price of gas in a given year since 1970. For example, if we want to calculate the price of gas in 2017, we can plug in x = 47 (the number of years since 1970) into the equation to get y = 0.05(47) + 0.25 = 2.85. This means that in 2017, the price of gas per gallon was approximately 2.85 dollars. This equation can be used to accurately predict the cost of gas for any given year since 1970.
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Read the excerpt from "John Burns of Gettysburg” by Bret Harte. And it was terrible. On the right Raged for hours the heady fight, Thundered the battery's double brass,— Difficult music for men to face; While on the left—where now the graves Undulate like the living waves That all the day unceasing swept Up to the pits the rebels kept Which use of consonance best conveys the violent sounds of the battle? “And it was terrible. On the right” “Thundered the battery’s double brass” “Difficult music for men to face” “Undulate like the living waves”
NEED HELP ASAP! I WILL GIVE BRAINLIEST TO WHO ANSWERS FIRST
The use of consonance in "Thundered the battery's double brass" best conveys the violent sounds of the battle.
What is consonance?
Consonance is a literary device where consonant sounds are repeated in close proximity, often at the ends of words, to create a musical or rhythmic effect in a text.
The passage uses consonance, which is the repetition of consonant sounds within or at the end of words, to convey the violent sounds of the battle.
In particular, the repeated "t" and "d" sounds in "Thundered the battery's double brass" and "Difficult music for men to face" create a harsh, jarring effect that emphasizes the chaos and danger of the fighting.
Similarly, the repeated "v" and "l" sounds in "Undulate like the living waves" create a sense of movement and fluidity, conveying the unrelenting and overwhelming force of the rebel advance.
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Show your work for every single one plssssss
The values would be
[tex]15. = \frac{1}{1000y^3}\\\\16. =-\dfrac{1024}{n^5}\\\\17. =\dfrac{1}{32k^{10}}\\\\18. =$\dfrac{49}{36c^2}$\\\\\\19. = $64^t$\\\\20. = $5 \cdot 5^t$\\\\21. = $81 \cdot 3^{4t}$\\\\22. = $\dfrac{2^{2t}}{2}$ or $2^{2t-1}$[/tex]
What is an expression?
In mathematics, an expression is a combination of symbols and/or numbers that represents a value or a relationship between values. Expressions can be as simple as a single number or variable, or they can be complex, involving multiple operations and functions. Expressions can be used to describe relationships between variables, to represent mathematical formulas or equations, and to perform calculations.
[tex]15. = \frac{1}{1000y^3}\\\\16. =-\dfrac{1024}{n^5}\\\\17. =\dfrac{1}{32k^{10}}\\\\18. =$\dfrac{49}{36c^2}$\\\\\\19. = $64^t$\\\\20. = $5 \cdot 5^t$\\\\21. = $81 \cdot 3^{4t}$\\\\22. = $\dfrac{2^{2t}}{2}$ or $2^{2t-1}$[/tex]
Hence, the values would be
[tex]15. = \frac{1}{1000y^3}\\\\16. =-\dfrac{1024}{n^5}\\\\17. =\dfrac{1}{32k^{10}}\\\\18. =$\dfrac{49}{36c^2}$\\\\\\19. = $64^t$\\\\20. = $5 \cdot 5^t$\\\\21. = $81 \cdot 3^{4t}$\\\\22. = $\dfrac{2^{2t}}{2}$ or $2^{2t-1}$[/tex]
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you are called to investigate a possible health concern in an office building that may be due to an environmental toxin. you arrange with a company that occupies two levels of the building to follow all 300 of their office employees. you intend to follow all employees for 30 days and every day, the employees report their health status. however, on day 10, 35 employees report respiratory distress. on day 20, 70 employees report respiratory distress. the remaining employees do not report any respiratory distress over the 30-day period.
The investigation of a possible health concern in an office building due to an environmental toxin involves following the health status of all employees for a period of time, identifying potential sources of toxins, and taking steps to remove the toxins and protect the health of the employees.
The possible health concern in an office building that may be due to an environmental toxin can be investigated by following all 300 of their office employees for 30 days and observing their health status. On day 10, 35 employees report respiratory distress and on day 20, 70 employees report respiratory distress.
The remaining employees do not report any respiratory distress over the 30-day period. This suggests that there may be an environmental toxin in the office building that is causing respiratory distress in the employees.
It is important to further investigate the source of the toxin and take steps to remove it in order to protect the health of the employees. This may include conducting air quality tests, examining the building for potential sources of toxins, and implementing measures to improve ventilation and air quality.
It is also important to continue monitoring the health of the employees and providing them with appropriate medical care if needed.
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Use Descartes's Rule of Signs to determine the possible numbers of positive and negative real zeros of the function.
f(x)=2x5−3x2+2x−1
The possible number of positive real zeros of the function is either 2 or 0.f(-x) = −2x5 − 3x2 − 2x − 1The number of sign changes in f(-x) is 1. The possible number of negative real zeros of the function is either 1 or 0.
To determine the possible numbers of positive and negative real zeros of the function f(x) = 2x5 − 3x2 + 2x − 1 using Descartes's Rule of Signs, we should start by writing the polynomial function in descending order of powers of x. After this, we count the number of sign changes in the polynomial function f(x) and find out the possible number of positive real zeros. Similarly, we count the number of sign changes in f(-x) and find out the possible number of negative real zeros .In the given function f(x) = 2x5 − 3x2 + 2x − 1, the polynomial is already in the descending order of powers of x. Therefore,
we count the sign changes in f(x) and f(-x) as follows: f(x) = 2x5 − 3x2 + 2x − 1The number of sign changes in f(x) is 2. Therefore, the possible number of positive real zeros of the function is either 2 or 0.f(-x) = −2x5 − 3x2 − 2x − 1The number of sign changes in f(-x) is 1. Therefore, the possible number of negative real zeros of the function is either 1 or 0. Hence, the possible number of positive real zeros of the function is either 2 or 0 and the possible number of negative real zeros of the function is either 1 or 0.
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the perimeter of a rectangular outdoor patio is 106 ft. the length is 9 ft greater than the width. what are the dimensions of the patio?
The perimeter of a rectangular outdoor patio is 106 ft. the length is 9 ft greater than the width. Hence, the dimensions of the patio are 38 ft and 47 ft.
Given that the perimeter of a rectangular outdoor patio is 106 ft. The length is 9 ft greater than the width. Now we need to find the dimensions of the patio.
Step 1: Let's consider the width of the patio be x feet.
The length of the patio is given as 9 ft greater than the width.
So the length of the patio will be (x + 9) feet.
Step 2: The perimeter of a rectangle is given by P = 2(l + w).
So the perimeter of the patio is given as 106 ft.
Thus,2(l + w) = 1062(x + x + 9)
= 1062(2x + 9)
= 1062x + 1821
= 106x = 106 - 182x
= -76 (not possible)
Therefore, x = 38 ftSo the width of the patio is 38 ft The length of the patio is 38 + 9 = 47 ft
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Which statement is true about this quadratic equation?
The correct statement regarding the quadratic equation is given as follows:
C. There are two complex solutions.
How to obtain the number of solutions of the quadratic function?A quadratic equation is modeled by the general equation presented as follows:
y = ax² + bx + c
The discriminant of the quadratic function is given by the equation as follows:
Δ = b² - 4ac.
The numeric value of the coefficient and the number of solutions of the quadratic equation are related as follows:
Δ > 0: two real solutions.Δ = 0: one real solution.Δ < 0: two complex solutions.The coefficients of the function for this problem are given as follows:
a = -2, b = 9, c = -12.
Hence the discriminant is given as follows:
Δ = 9² - 4(-2)(-12)
Δ = -15.
Negative discriminant, hence there are two complex solutions.
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The quadratic equation has two real solutions
Which statement is true about this quadratic equation?Here we have the quadratic equation:
y = -2x^2 + 9x - 12
We want to study the solutions of the equations, so we need to look at the discriminant:
Generally for a*x^2 + b*x + c = 0 the discriminant is b^2 - 4ac
Here it is:
D = 9^2 - 4*-12*-2 = 33
A positive determinant means that there are 2 real solutions so the correct option is A.
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Maisie has 40 m of railing.
How much more railing does Maisie need
so that she can put railing all the way
around the roof garden?
8 m
9 m
4m
10 m
20 m
8 m
Not drawn accurately
Look at imqhe
Answer:
36
Step-by-step explanation:
see image for explanation
SOMEONE HELP PLEASE I'LL GIVE BRAINLIEST IF BOTH OF THESE ARE CORRECT
Simplify.
a)√(30+10√5)
b) √(25+10√5+5)
Please answer with full explanation!
Answer: 5cm
Step-by-step explanation:
You divide the area of green (93.75) by pink's length (7.5)
that gives you 12.5.
12.5 is the length of green.
12.5 - 7.5 = 5
You subtract the 7.5 because to get yellow's length because Yellow's length plus pink's length is equal to green's total length.
Using trigonometry, work out the length y. Give your answer in centimetres to 1 d.p. y 6.1 cm 39° Not drawn accurately
The length of the opposite side (y) is equal to 3.2 centimeters.
How to calculate the length y?In order to determine the length of the opposite side (y), we would apply the sine trigonometry ratio because the given side lengths represent the opposite side and hypotenuse of a right-angled triangle.
cos(θ) = Adj/Hyp
Where:
Opp represent the opposite side of a right-angled triangle.Hyp represent the hypotenuse of a right-angled triangle.θ represent the angle.Based on the information provided in the image, we can logically deduce the following parameters:
Opp = y cm.Hyp = 6.1 cm.Angle, θ = 39°.By substituting the parameters into the sine trigonometry ratio formula, we have the following;
sin(θ) = Opp/Hyp
sin(39) = y/5
y = 5sin(39)
y = 3.2 centimeters.
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
OFFERING BRAINLIEST TO STEP BY STEP EXPLANATION
Answer:
[tex]112cm^2[/tex]
Step-by-step explanation:
Volume of a rectangluar prism = Length x Width x Height
Volume, Length, and Width is given now we can solve for Height, c
[tex]V = l * w * h[/tex]
[tex]80m^3 = 4m * 4m * h[/tex]
[tex]h = 80m^3 / 16m^2[/tex]
[tex]h = 5m[/tex]
Surface area of a rectangular prism is A = 2(wl +hl +hw)
[tex]A = 2(4m * 4m + 5m * 4m + 5m * 4m)[/tex]
[tex]= 2(16m^2 + 20m^2 + 20m^2)[/tex]
[tex]= 2(56cm^2)\\A= 112cm^2[/tex]
Hope this helps!
Brainliest is much appreciated!
supongo q es es 8 cm pero no creo q sería 2 o l
Please help!! Thanks
Answer:
[tex]\boxed{\mathtt{Area \approx 104.7m^{2}}}[/tex]
Step-by-step explanation:
[tex]\textsf{We are asked to find the area of 1/3 of a circle.}[/tex]
[tex]\textsf{Let's review the formula needed to find the area of a \underline{whole} circle.}[/tex]
[tex]\large\underline{\textsf{Formula:}}[/tex]
[tex]\mathtt{Area = \pi (radius)^{2}.}[/tex]
[tex]\textsf{We should know that a circle is 360}^{\circ}. \ \textsf{We are given 120}^{\circ} \textsf{of a circle.}[/tex]
[tex]\textsf{The area of \underline{1/3} of a Circle is the area of a whole circle \underline{divided by 3.}}[/tex]
[tex]\textsf{Let's begin solving for the area.}[/tex]
[tex]\large\underline{\textsf{Substitute:}}[/tex]
[tex]\mathtt{Area = \pi (10)^{2}}[/tex]
[tex]\large\underline{\textsf{Evaluate:}}[/tex]
[tex]\mathtt{Area = 100\pi }[/tex]
[tex]\large\underline{\textsf{Divide by 3:}}[/tex]
[tex]\mathtt{\frac{Area}{3} = \frac{100\pi }{3}} [/tex]
[tex]\boxed{\mathtt{Area \approx 104.7m^{2}}}[/tex]
Find the next term of the following sequence.
9, 6, 4, ...
1. 2
2. 8/3
3. 3
Answer:
3
Step-by-step explanation:
You are subtracting 1 less each time, starting at 3:
9 - 3 = 6
6 - 2 = 4
Therefore, you will subtract 1 from 4:
4 - 1 = 3
3 is your answer.
~
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Please help I’ll give brainliest!!
______are set of repeated activitieswhich have well defined results
Answer:
statistical experiments performed on a well defined sample space
Step-by-step explanation:
experiments can be performed either by probability, or other repetitive actions on sample space for possible outcomes.
For what values of a are the following expressions true?
1/2a - 5 1/2 = 5-a
Therefore, the values of a that make the expression true are approximately 0.378 and 14.121.
What is expression?In mathematics, an expression is a combination of numbers, variables, and operations that represents a quantity or a mathematical relationship. Expressions can be simple or complex, and can involve arithmetic, algebraic, trigonometric, or other mathematical operations. Expressions can also include constants, which are fixed values that do not change. Expressions can be evaluated by substituting numerical values for the variables and performing the indicated operations.
Here,
To solve for the values of a that make the given expressions true, we need to isolate the variable a on one side of the equation. We can start by simplifying the left side of the equation:
1/2a - 5 1/2 = 5 - a
Multiplying both sides by 2a gives:
1 - 10a* 1/2 = 10a - 2a²
Simplifying the left side by multiplying both terms by 2:
2 - 20a = 10a - 2a²
Rearranging the terms gives a quadratic equation:
2a² - 30a + 2 = 0
We can solve for a by using the quadratic formula:
a = (-b ± √(b² - 4ac)) / 2a
where a = 2, b = -30, and c = 2.
Plugging in these values gives:
a = (30 ± √((-30)² - 4(2)(2))) / 4
a = (30 ± √(892)) / 4
a ≈ 0.378 or a ≈ 14.121
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Christine swam 2 kilometers against the current in the same amount of time it took her to swim 8 kilometers with the current. The rate of the current was 3 kilometers per hour. How fast would Christine swim if there were no current?
If the rate of the current was 3 kilometers per hour, Christine's speed in still water is 5 kilometers per hour.
Let's start by assuming that Christine's speed in still water is x kilometers per hour. We know that the current is flowing at a rate of 3 kilometers per hour.
When Christine is swimming against the current, her effective speed is reduced by the speed of the current, so her speed is (x-3) kilometers per hour. If it takes her the same amount of time to swim 2 kilometers against the current as it does to swim 8 kilometers with the current, we can set up an equation:
time to swim 2 km against current = time to swim 8 km with current
We can use the formula distance = speed x time to express the distance that Christine covers in each scenario. The distance she covers against the current is 2 kilometers, and the distance she covers with the current is 8 kilometers. So our equation becomes:
2 / (x - 3) = 8 / (x + 3)
To solve for x, we can cross-multiply and simplify:
2(x + 3) = 8(x - 3)
2x + 6 = 8x - 24
6x = 30
x = 5
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The density of some steel is 7.85 g/cm³. What is the mass of 50 cm³ of this steel? Give your answer to 1 d. p.
Answer:
392.5g
Step-by-step explanation:
Density =mass/volume
Mass = Density x volume
Mass = 7.85g/cm³ x 50 cm³
Mass = 392.5g
To find the roots of a quadratic equation, ax^2+ bx + c, where a, b, and c are real numbers, Jan uses the quadratic formula. Jan finds that a quadratic equation has 2 distinct roots, but neither are real numbers.
A. Write an inequality using the variables a, b, and c that must always be true for Jan's quadratic equation.
The expression 3+√-4 s a solution of the quadratic equation x^2- 6x +13=0.
B. What is 3+ √-4 written as a complex number?
The inequality will be and [tex]3 + √-4[/tex] will be written as [tex]3 +2i[/tex] as complex number.
What are complex numbers?
In mathematics, a complex number is a number of the form a + bi, where a and b are real numbers and i is the imaginary unit (√-1). Complex numbers are an extension of the real numbers, which include all the numbers that can be represented on a number line.
The real part of a complex number a + bi is the real number a, and the imaginary part is the real number bi.
A. Since Jan found that both roots of the quadratic equation are not real numbers, this means that the discriminant b² - 4ac is negative. Therefore, the inequality that must always be true for Jan's quadratic equation is:
[tex]b² - 4ac < 0[/tex]
B. The expression [tex]3+√-4[/tex] can be written as [tex]3 + 2i,[/tex] where i is the imaginary unit (√-1). This is because √-4 is equal to 2i, so [tex]3+√-4[/tex] can be written as [tex]3 + 2i.[/tex] Therefore, [tex]3+√-4[/tex] written as a complex number is 3 + 2i.
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Given the function h(x)=-2√x, which statement is true about h(x)?
O The function is decreasing on the interval (0,0).
O The function is decreasing on the interval (-∞, 0).
O The function is increasing on the interval (0, ∞).
O The function is increasing on the interval (-∞, 0).
Answer:
The statement "The function is decreasing on the interval (0, ∞)" is true about h(x).
To see why, let's take the derivative of h(x) and examine its sign:
h(x) = -2√x
h'(x) = -2/(2√x) = -1/√x
Since √x is always positive, h'(x) is negative for all x > 0. This means that h(x) is decreasing on the interval (0, ∞).
Therefore, the correct answer is: The function is decreasing on the interval (0, ∞).
Jefferson high school has an enrollment of 1,864 students and 564 graduate how much will still be in school
Answer:
1300
Step-by-step explanation:
1864-564= 1300 students
(total - no. graduated)
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Which of the japanese islands do you think became the center of power in japan
The Japanese island that became the center of power in Japan is Honshu.
Honshu is the largest and most populous island in Japan and has historically been the center of political, economic, and cultural power in Japan. It is home to Tokyo, the capital city of Japan, as well as many other major cities such as Osaka, Kyoto, and Yokohama. Honshu's central location and natural resources have made it a strategic location for political power throughout Japan's history, including during the feudal period when various powerful clans vied for control. Honshu's position as the economic and cultural hub of Japan has also helped solidify its status as the center of power, as it has been a center for education, trade, and innovation for centuries.
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