Answer: We need to find the doubling time for population growth:
Population growth is given by
[tex]P=P_oe^{(0.2)t}[/tex]Where:
[tex]\begin{gathered} P\rightarrow\text{final} \\ P_o\rightarrow I\text{nitial} \end{gathered}[/tex]For the population to double, it implies that:
[tex]P=2P_o[/tex]Therefore:
[tex]\frac{P}{P_o}=\frac{2P_o}{P_o}=2=e^{(0.2)t}[/tex]Solving for time "t" gives:
[tex]2=e^{(0.2)t}\rightarrow\ln (2)=(0.2)t\rightarrow t=\frac{\ln (2)}{(0.2)}=3.46u[/tex]15= x/6-1 help me with this im just using it to study so show step by step because i forgot
The value of x after solving the expression, 15 = (x/6)-1, step by step is 96.
According to the question,
We have the following expression:
15 = (x/6)-1
Now, we can change the sides because it will not make any difference to the overall answer.
(x/6)-1 = 15
Now, we will move 1 from the left hand side to the right hand side. So, the sign will change from minus to plus.
x/6 = 15+1
x/6 = 16
Now, we will move 6 from the left hand side to right hand side. 6 is in the division on the left hand side then it will be in multiplication on the right hand side.
x = 16*6
x = 96
Hence, the value of x after solving the expression step by step is 96.
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A polynomial function is given.
Q(x) = −x2(x2 − 9)
(a) Describe the end behavior of the polynomial function.
End behavior: y → as x → ∞
y → as x → −∞
The end behavior of the polynomial is:
y → −∞ as x → ∞
y → −∞ as x → −∞
How is the end behavior?Here we have the polynomial:
Q(x) = -x²*(x² - 9)
Remember that polynomials with even degrees have the same behavior for the negative values of x than for the positive, in this case if we expand the polynomial we get:
Q(x) = -x⁴ + 9x²
The leading coefficient is negative, then the end behavior will tend to negative infinity in both ends, then we get:
y → −∞ as x → ∞
y → −∞ as x → −∞
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The length of a rectangular pool is 6 meters less than twice the width. If the pools perimeter is 84 meters, what is the width? A) Write Equation to model the problem (Use X to represent the width of the pool) B) Solve the equation to find the width of the pool (include the units)
I have a problem with the perimeter of a pool expressed in an unknown which corresponds to "x"
The first thing to do is to pose the corresponding equation, this corresponds to section A of the question
For the length, we have a representation of twice the width minus 6, i.e. 2x-6
For the width we simply have x
Remember that the sum of all the sides is equal to the perimeter which is 84, However, we must remember that in a rectangle we have 4 sides where there are two pairs of parallel sides, so we must multiply the length and width by 2
Now we can represent this as an equation
[tex]2(2x-6)+2x=84[/tex]This is the answer A
Now let's solve the equation for part B.
[tex]\begin{gathered} 2(2x-6)+2x=84 \\ 4x-12+2x=84 \\ 6x=84+12 \\ x=\frac{96}{6} \end{gathered}[/tex][tex]x=16[/tex]In conclusion, the width of the pool is 16
Since January 1, 1960, the population of Slim Chance has been described by the formula P = 27000(0.95)^t, where P is the population of the city t years after the start of 1960. At what rate was the population changingon January 1, 19702?numerical rate of change= ___ people per year
We have to calculate the rate of change of the population P(t) at January 1, 1970 (t = 10).
The expression for P(t) is:
[tex]P(t)=27000\cdot0.95^t[/tex]The rate of change will be given by the first derivative of P(t):
[tex]\frac{dP}{dt}=27000\cdot\ln (0.95)\cdot0.95^t[/tex]Then, we can calculate the value of the rate of change when t = 10, by replacing t with 10 in the last expression. We then will get:
[tex]\begin{gathered} \frac{dP}{dt}(100)=27000\cdot\ln (0.95)\cdot0.95^{10} \\ \frac{dP}{dt}(100)\approx27000\cdot(-0.0513)\cdot0.5987 \\ \frac{dP}{dt}(100)\approx-829 \end{gathered}[/tex]The population, on January 1st 1970, is decreasing at a rate of 829 people per year.
Answer: numerical rate of change= -829 people per year
tell whether the fractions are equivalent
Step 1:
Equivalent fractions are fraction that are equal in ratio.
1/3 is equivalent to 4/12
4/12 can be simplify to 1/3 because 4 is a highest common factor of 4 and 12
When you divide by numerator ( 4) and denominator (12) by 4, the fraction result to 1/3.
Hence, 1/3 is equivalent to 4/12.
Final answer
[tex]\frac{1}{3}\text{ = }\frac{4}{12}[/tex]
Madeline is a salesperson who sells computers at an electronics store. She makes a base pay of $80 each day and then is paid a $20 commission for every computer sale she makes. Make a table of values and then write an equation for P, in terms of x, representing Madeline's total pay on a day on which she sells x computers.
I need the equation.
Answer:
I don’t know if I can send it answer
Step-by-step explanation:
A taxi service charges $3 for the first mile and then $2.25 for every mile after that. The farthest the taxi will travel is 35 miles. If X represents the number of miles traveled, and Y represents the total cost of the taxi ride, what is the most appropriate domain for the solutions?
Solution:
Given:
[tex]\begin{gathered} A\text{ taxi service charges \$3 for the first mile} \\ \text{ \$2.25 for every mile after that.} \\ \text{The farthest the taxi will travel is 35 miles.} \end{gathered}[/tex]Since x represents the number of miles traveled
y represents the total cost of the taxi ride
From the description, the number of miles the taxi will travel is between 0 and 35miles since 35 miles is the farthest it could go.
This means the domain which refers to the set of possible input values will be;
[tex]\begin{gathered} x>0\text{ because the service is charged once a certain distance is covered.} \\ \text{when no distance is covered, no charge is made.} \\ \text{Also,} \\ x\le35\text{ because the farthest is 35miles. This means the ta}\xi\text{ can not travel beyond 35miles.} \\ \\ \text{From the descriptions made, the domain will be:} \\ 0Therefore, the most appropriate domain for the solutions is;
[tex]0 The correct answer is OPTION B.Find the measure of each angle in the triangle. F R 6x 15x 15x O 02
Answer:
R = 75
O = 75
F = 30
Step-by-step explanation:
15x + 15x + 6x = 180
add like terms
36x = 180
divide
x = 5
The measure of angle P is 30°, angle R is 75° and angle O is 75° in triangle POR.
What is angle sum property of a triangle?Angle sum property of triangle states that the sum of interior angles of a triangle is 180°.
From the given triangle POR, ∠R=15x, ∠O=15x and ∠P=6x.
By using angle sum property, we get
∠P+∠O+∠R=180°
6x+15x+15x=180
36x=180
x=180/36
x=5
So, ∠R=15x=75°, ∠O=15x=75° and ∠P=6x=30°
Therefore, the measure of angle P is 30°, angle R is 75° and angle O is 75° in triangle POR.
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Given 5x + 2y=22 and that y=1, find x
In a linear equation both variables are dependent on each other
Then to find x
first reorder and put x as one term only
x = (22- 2y)/5
now replace y by its given value y= 1
then x= (22- 2•1)/5 = 20/5= 4
If TRAP is an isosceles trapezoid, what is the value of x?A. 1B. 22C. 12D. 23E. 11F. Cannot be determined
In an Isosceles trapezoid, it is known that the base angles have equal measures, and non-congruent angles are supplementary.
The non-congruent angles ∠RAP and ∠APTfrom the figure have measures 6x° and (2x+4)°, respectively.
Since they must be supplementary, it follows that their sum is 180°:
[tex]\begin{gathered} 6x+2x+4=180 \\ \Rightarrow8x+4=180\Rightarrow8x=180-4 \\ \Rightarrow8x=176\Rightarrow\frac{8x}{8}=\frac{176}{8} \\ \Rightarrow x=22 \end{gathered}[/tex]Hence, the value of x is 22. The correct option is B.
Answer:B
Step-by-step explanation:just took the test
In a class of 30 students, 14 take tea and 20 take coffee. How many take both tea
and coffee?
Answer:
4
Step-by-step explanation:
[tex]20 + 14 = 34[/tex]
[tex]34 - 30 = 4[/tex]
Date: t rates to determine the better buy? b. Stop and Shop: 6 packages of Oreos cost $15.00 Key Food: 5 packages of Oreos cost $13.25
To determine the better buy you have to calculate how much one package costs in each shop.
1) 6 packages cost $15.00
If you use cross multiplication you can determine how much 1 package costs:
6 packs ______$15.00
1 pack _______$x
[tex]\begin{gathered} \frac{15.00}{6}=\frac{x}{1} \\ x=\frac{15}{6}=\frac{5}{2}=2.5 \end{gathered}[/tex]Each package costs $2.5
2) 5 packages cost $13.25
5packs_____$13.25
1 pack______$x
[tex]\begin{gathered} \frac{13.25}{5}=\frac{x}{1} \\ x=\frac{13.25}{5}=2.65 \end{gathered}[/tex]Each package costs $2.65
For the second purchase each package cost $0.15 more than in the first purchase.
Is best to buy the 6 packages at $15.00
Find slope and y-intercept of the line. Compare the values to equation y=3x-8
The slope of a line graph, we need to pick two point on the line.
It is better to pick points that meet the grids, so we can have its exactly coordinates.
Also, since we will need the y-intercept, one of the points can be this.
The y-intercept is the point where the line intercepts the y-axis, its x value is always 0, and we can see that it happens, in this case, at y = -8, so the point is (0, -8), and the y-intercept is -8.
Now, we can look at any other point. We can see that one point that meets the grids is the point at x = 3 and y = 1, so at point (3, 1).
The slope, m, can be, then, calculated as:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{1-(-8)}{3-0}=\frac{1+8}{3}=\frac{9}{3}=3 \end{gathered}[/tex]So, the slope is 3.
Answers:
Slope: 3
y-intercept: (0, -8)
The line in the slope-intercept form is:
[tex]y=mx+b[/tex]where m is the slope and b is the y value of the y-intercept.
So, in this case, we have:
[tex]\begin{gathered} m=3 \\ b=-8 \\ y=3x-8 \end{gathered}[/tex]Which is exactly the same as the equation given, y = 3x - 8, so the equation given corresponds to the graph given.
Use the slope and y-intercept to graph the line whose equation is given. 2 y = -x + 5x+1
ok
y = -2/5 + 1
This is the graph
Find the coordinates of the other endpoint of a segment with the given endpoint and Midpoint M.T(-8,-1)M(0,3)
If we have 2 endpoints (x1, y1) and (x2, y2), the coordinates of the midpoint will be:
[tex]\begin{gathered} x=\frac{x_1+x_2}{2} \\ y=\frac{y_1+y_2}{2} \end{gathered}[/tex]Now, we know the coordinates of one endpoint (x1, y1) equal to (-8, -1) and the midpoint (x, y) equal to (0,3), so we can replace those values and solve for x2 and y2.
Then, for the x-coordinate, we get:
[tex]\begin{gathered} 0=\frac{-8+x_2}{2} \\ 0\cdot2=-8+x_2 \\ 0=-8+x_2 \\ 0+8=-8+x_2+8 \\ 8=x_2 \end{gathered}[/tex]At the same way, for the y-coordinate, we get:
[tex]\begin{gathered} 3=\frac{-1+y_2}{2} \\ 3\cdot2=-1+y_2 \\ 6=-1+y_2 \\ 6+1=-1+y_2+1 \\ 7=y_2 \end{gathered}[/tex]Therefore, the coordinates of the other endpoint are (8, 7)
Answer: (8, 7)
Aaquib can buy 25 liters of regular gasoline for $58.98 or 25 liters of permimum gasoline for 69.73. How much greater is the cost for 1 liter of premimum gasolinz? Round your quotient to nearest hundredth. show your work :)
YOU WILL GET 70 POINTS!
The cost for 1 liter of premium gasoline is $0.43 greater than the regular gasoline.
What is Cost?This is referred to as the total amount of money and resources which are used by companies in other to produce a good or service.
In this scenario, we were given 25 liters of regular gasoline for $58.98 or 25 liters of premium gasoline for $69.73.
Cost per litre of premium gasoline is = $69.73 / 25 = $2.79.
Cost per litre of regular gasoline is = $58.98/ 25 = $2.36.
The difference is however $2.79 - $2.36 = $0.43.
Therefore the cost for 1 liter of premimum gasoline is $0.43 greater than the regular gasoline.
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find the simple interest earned, to the nearest cent, for each principal interest rate, and time.
Answer:
$8.40
Explanation:
From the given statement:
Principal = $840
Time = 6 Months
Rate = 2%
Note that Time must be in Years, therefore:
Time = 6 Months = 6/12 = 0.5 Years
[tex]\begin{gathered} \text{Simple Interest }=P\times R\times T \\ =840\times2\%\times0.5 \\ =840\times0.02\times0.5 \\ =\$8.40 \end{gathered}[/tex]The simple interest earned is $8.40
The cost to mail a package is 5.00. Noah has postcard stamps that are worth 0.34 and first-class stamps that are worth 0.49 each. An equation that represents this is 0.49f + 0.34p = 5.00Solve for f and p.If Noah puts 7 first-class stamps, how many postcard stamps will he need?
ANSWER
[tex]\begin{gathered} f=\frac{5.00-0.34p}{0.49} \\ p=\frac{5.00-0.49f}{0.34} \\ p=4.618\approx5\text{ postcard stamps} \end{gathered}[/tex]EXPLANATION
The equation that represents the situation is:
[tex]0.49f+0.34p=5.00[/tex]To solve for f, make f the subject of the formula from the equation:
[tex]\begin{gathered} 0.49f=5.00-0.34p \\ \Rightarrow f=\frac{5.00-0.34p}{0.49} \end{gathered}[/tex]To solve for p, make p the subject of the formula from the equation:
[tex]\begin{gathered} 0.34p=5.00-0.49f \\ \Rightarrow p=\frac{5.00-0.49f}{0.34} \end{gathered}[/tex]To find how many postcard stamps Noah will need if he puts 7 first-class stamps, solve for p when f is equal to 7.
That is:
[tex]\begin{gathered} p=\frac{5.00-(0.49\cdot7)}{0.34} \\ p=\frac{5.00-3.43}{0.34}=\frac{1.57}{0.34} \\ p=4.618\approx5\text{ postcard stamps} \end{gathered}[/tex]solve the following system of equations-5x-3y=-16-3x+2y=-21x=y=
-5x - 3y = -16
-3x + 2y = -21
Solving for y the first equation:
-5x + 16 = 3y
y = (-5/3)x + (16/3)
Using this value of y into the second equation:
-3x + 2(-5/3)x + 2(16/3) = -21
-3x - (10/3)x + 32/3 = -21
Multiplying all by 3:
-9x - 10x + 32 = -63
-19x = -63 - 32 = -95
x = 95/19
Using this value of x into the y we found with the first equation:
y = (-5/3)x + 16/3
y = (-5/3)(95/19) + 16/3 = -475/57+ 304/57 = -171/57
y = -171/57
x = -31/19 = -1.6315
y = -171/57 = -3
Answer:
x = -1.6315
y = -3
18. Yvonne paid $18.72 for 8 gallons of gas. How much would she have spent on gas if she had only needed 5 gallons of gas?
As given by the question
There are given that $18.72 for 8 gallons of gas.
Now,
Since, $18.72 for 8 gallons of gas;
Then,
First calculate the price of one-gallon gas
So,
[tex]\frac{18.72}{8}=2.34[/tex]The price og one g
Use Vocabulary in Writing 9. Explain how you can find the product 4 X 2 and the product 8 X 2 Use at least 3 terms from the Word List in your explanation.
Okay, here we have this:
help me please.......
Let
x -----> the larger room
y -----> the smaller room
we have that
x=2y
we have
y=25 3/4 ft
Convert to an improper fraction
25 3/4=25+3/4=103/4 ft
Find the value of x
x=2y
x=2(103/4)
x=103/2 ft
Convert to mixed number
103/2=51.5=51+0.5=51 1/2 ft
the answer is51 1/2 fthe larger roomhe larger room
what's the answer for proportions 4/n+2=7/n
Explanation
[tex]\frac{4}{n+2}=\frac{7}{n}[/tex]we need to solve for n
Step 1
cross multiply
[tex]\begin{gathered} \frac{4}{n+2}=\frac{7}{n} \\ 4\cdot n=7(n+2) \\ 4n=7n+14 \\ \end{gathered}[/tex]Step 2
subtract 4n in both sides
[tex]\begin{gathered} 4n=7n+14 \\ 4n-4n=7n+14-4n \\ 0=3n+14 \end{gathered}[/tex]Step 3
subtract 14 in both sides,
[tex]\begin{gathered} 0=3n+14 \\ 0-14=3n+14-14 \\ -14=3n \end{gathered}[/tex]Step 4
Finally, divide both sides by 3
[tex]\begin{gathered} \frac{-14}{3}=\frac{3n}{3} \\ n=-\frac{14}{3} \end{gathered}[/tex]I hope this helps you
Find an expression equivalent to the one shown below.913 x 9-6OA. 79OB.919OC. 97OD. 9-78
Answer:
C. 9⁷
Explanation:
We will use the following property of the exponents:
[tex]x^a\times x^b=x^{a+b}[/tex]It means that when we have the same base, we can simplify the expression by adding the exponents. So, in this case, the equivalent expression is:
[tex]9^{13}\times9^{-6}=9^{13-6}=9^7[/tex]Therefore, the answer is C. 9⁷
Write an equation of the line that passes through (4, 3) and is parallel to the line defined by 5x-2y-3. Write the answer in slope-intercept form (if possible)
and in standard form (Ax+By-C) with smallest integer coefficients. Use the "Cannot be written" button, if applicable.
The final answer to the question is highlighted in the box
which property justifies the following statement if 3x=9,then x=3.
Answer:
Multiplication Property
Division Property
This can be justified using multiplication property and division property:
Multiplication property:
If both sides of equation:
3x = 9
are multiplied by 1/3, we have:
x = 3
Division property
Divide both sides of the equation:
3x = 9 by 3, we have:
x = 3
An advertising company plans to market a product to low-income families. A study states that for a particular area the mean income per family is $25,174 and the standard deviation is $8,700. If the company plans to target the bottom 18% of the families based on income, find the cutoff income. Assume the variable is normally distributed.
Suppose that the distribution for total amounts spent by students vacationing for a week in Florida is normally distributed with a mean of 650 and a standard deviation of 120. Suppose you take a simple random sample (SRS) of 35 students from this distribution.
What is the probability that an SRS of 35 students will spend an average o between 600 and 700 dollars? Round to five decimal places
The probability that an SRS of 35 students will spend an average o between 600 and 700 dollars is 98.61%
Given,
The mean of the normal distribution, μ = 650
Standard deviation of the distribution, σ = 120
n = 35
By using central limit theorem, standard deviation for SRS of n, δ = σ/√n = 120/√35
The z score = (x - μ) / σ
By using central limit theorem,
z score = (x - μ) / δ
Here,
We have to find the probability that an SRS of 35 students will spend an average o between 600 and 700 dollars:
(p value of z score of x = 700) - (p value of z score of x = 600)
z score of x = 700
z = (x - μ) / δ = (700 - 650) /( 120/√35) = (50 × √35) / 120 = 2.46
p value of z score 2.46 is 0.99305
z score of x = 600
z = (x - μ) / δ = (600 - 650) /( 120/√35) = (-50 × √35) / 120 = -2.46
p value of z score -2.46 is 0.0069469
Now,
0.99305 - 0.0069469 = 0.9861031 = 98.61%
That is, the probability that an SRS of 35 students will spend an average o between 600 and 700 dollars is 98.61%
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A game fair requires that you draw a queen from a deck of 52 ards to win. The cards are put back into the deck after each draw, and the deck is shuffled. That is the probability that it takes you less than four turns to win?
The probability (P) is winning in less than four turns can be decomposed as the following sum:
The probability of winning in one turn is
[tex]P(\text{Winning in turn 1})=\frac{\#Queens}{\#Cards}=\frac{4}{52}.[/tex]The probability of winning in the second turn is
[tex]\begin{gathered} P(\text{ Winning in the second turn})=P(\text{ Lossing (in turn 1)})\cdot P(\text{ Winning (in turn 2)}), \\ \\ P(\text{ Winning in the second turn})=\frac{\#NoQueens}{\#Cards}\cdot\frac{\#Queens}{\#Cards}, \\ \\ P(\text{ Winning in the second turn})=\frac{48}{52}\cdot\frac{4}{52}\text{.} \end{gathered}[/tex]The probability of winning in the third turn is
[tex]\begin{gathered} P(\text{ Winning in the third turn})=P(\text{ Lossing (in turn 1)})\cdot P(\text{ Lossing (in turn 2)})\cdot P(\text{ winning (in turn 3)}), \\ \\ P(\text{ Winning in the third turn})=\frac{\#NoQueens}{\#Cards}\cdot\frac{\#NoQueens}{\#Cards}\cdot\frac{\#Queens}{\#Cards}, \\ \\ P(\text{ Winning in the third turn})=\frac{48}{52}\cdot\frac{48}{52}\cdot\frac{4}{52}\text{.} \end{gathered}[/tex]Adding all together, we get
[tex]\begin{gathered} P(\text{ Winning in less than four turns})=\frac{4}{52}+\frac{48}{52}\cdot\frac{4}{52}+\frac{48}{52}\cdot\frac{48}{52}\cdot\frac{4}{52}, \\ \\ P(\text{ Winning in less than four turns})=\frac{469}{2197}, \\ \\ P(\text{ Winning in less than four turns})\approx0.2135, \\ \\ P(\text{ Winning in less than four turns})\approx21.35\% \end{gathered}[/tex]AnswerThe probability of winning in less than four turns is (approximately) 21.35%.
School: Practice & Problem Solving 7.1.PS-18 Question Help A rectangle and a parallelogram have the same base and the same height. How are their areas related? Provide an example to justify your answer The areas equal. A rectangle has dimensions 5 m by 7 m, so its area is m² A parallelogram with a base of 5 m and a height of 7 m has an area of (Type whole numbers.)
The image shown below shows the relationship between areas of rectangle and parallelogram
It can be seen that the areas are equal when they have the same sides or dimension
A rectangle has dimensions 5 m by 7 m, so its area is 5m x 7m = 35m²
A parallelogram with a base of 5 m and a height of 7 m has an area of 5m x 7m = 35m²