Finding Slope

HELP ME PLS

Finding Slope HELP ME PLS

Answers

Answer 1

The slope of the line that passes through the points (-5,6) and (-9,-6) is m = 3

The first point = (-5,6)

The second point = (-9,-6)

The slope of the line defined as the change in y coordinates with respect to the change in x coordinates.

The slope of the line m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Where m is the slope of the line

[tex](x_1,y_1)[/tex]  is the coordinates of the first point

[tex](x_2,y_2)[/tex] is the coordinates of the second point

Substitute the values in the equation

The slope of the line m = [tex]\frac{-6-6}{-9-(-5)}[/tex]

= -12/-4

= 3

Hence, the slope of the line that passes through the points (-5,6) and (-9,-6) is m = 3

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Related Questions

I would like to know how to solve this answer.

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

k > 0

k * v

Step 02:

Scalars and Vectors:

k = scalar

v = vector

Scalar multiplication of a real vector by a positive real number multiplies the vector's magnitude, without changing its direction.

k * v

The answer is:

k v is parallel and has same direction as v

What is the slope of a line perpendicular to the line whose equation is15x + 12y = -108. Fully reduce your answer.Answer:Submit Answer

Answers

GIven:

The equation of a line is 15x+12y=-108.

The objective is to find the slope of the perpencidular line.

It is known that the equation of straight line is,

[tex]y=mx+c[/tex]

Here, m represents the slope of the equation and c represents the y intercept of the equation.

Let's find the slope of the given equation by rearranging the eqation.

[tex]\begin{gathered} 15x+12y=-108 \\ 12y=-108-15x \\ y=-\frac{15x}{12}-\frac{108}{12} \\ y=-\frac{5}{4}x-9 \end{gathered}[/tex]

By comparing the obtained equation with equation of striaght line, the value of slope is,

[tex]m_1=-\frac{5}{4}[/tex]

THe relationship between slopes of a perpendicular lines is,

[tex]\begin{gathered} m_1\cdot m_2=-1 \\ -\frac{5}{4}\cdot m_2=-1 \\ m_2=-1\cdot(-\frac{4}{5}) \\ m_2=\frac{4}{5}^{} \end{gathered}[/tex]

Hence, the value of slope of perpendicular line to the given line is 4/5.

What is (are) the solution(s) to the system of equations y = -x + 4 and y = -x^2 + 4 ?

Answers

Given:

[tex]\begin{gathered} y=-x+4----(1) \\ y=-x^2+4----(2) \end{gathered}[/tex]

Required:

To find the solutions to the given equations.

Explanation:

Put equation 1 in 2, we get

[tex]\begin{gathered} -x+4=-x^2+4 \\ \\ -x+4+x^2-4=0 \\ \\ x^2-x=0 \\ \\ x(x-1)=0 \\ \\ x=0,1 \end{gathered}[/tex]

When x=0,

[tex]\begin{gathered} y=-0+4 \\ y=4 \end{gathered}[/tex]

When x=1,

[tex]\begin{gathered} y=-1+4 \\ =3 \end{gathered}[/tex]

Final Answer:

The solution are

[tex]x=0,1[/tex]

The solution sets are

[tex]\begin{gathered} (0,4)\text{ and} \\ (1,3) \end{gathered}[/tex]

A machine that makes
toy spinners operates for 8 hours each
day. The machine makes 7,829 toy
spinners in
day. About how
many toy
spinners does the machine make each
hour?

Answers

Using the unitary method, the number of toy spinners the machines will make in an hour is 2069.

The unitary approach is a strategy for problem-solving that involves first determining the value of a single unit, then multiplying that value to determine the required value.

A machine makes 7829 toy spinners in a day.

The machines operate for 8 hours each day to make the toy spinners.

So,

8 hours = 7829

Then by using the unitary method the number of toy spinners the machines will make each hour will be:

8 hours = 7829

24 hours = x toy spinner

Toys in one hour = ( 7829/ 24 ) × 8

Toys in one hour = 326.20833 × 8

Toys in one hour = 2609.6667

Toys in one hour = 2069

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I need to find out what sine cosine and cotangent is, if this is my reference angle in the picture

Answers

We will use the following trigonometric identities

[tex]\begin{gathered} \tan \Theta=\frac{sin\Theta}{\cos \Theta} \\ \cot \Theta=\frac{1}{\tan \Theta} \end{gathered}[/tex]

Using these identities we can identify

[tex]\begin{gathered} \tan \Theta=\frac{12}{5} \\ \sin \Theta=12 \\ \cos \Theta=5 \\ \cot \Theta=\frac{1}{\frac{12}{5}}=\frac{5}{12} \end{gathered}[/tex][tex]\begin{gathered} \Theta=\tan ^{-1}(2.4) \\ \Theta=67.38º \\ \sin \Theta=0.92 \\ \cos \Theta=0.38 \end{gathered}[/tex][tex]\begin{gathered} \tan \Theta=\frac{opposite}{\text{adjacent}}^{} \\ \text{opposite}=12 \\ \text{adjacent}=5 \\ \text{hippotenuse=}\sqrt[\square]{12^2+5^2} \\ \text{hippotenuse=}13 \end{gathered}[/tex][tex]\begin{gathered} \sin \Theta=\frac{12}{13} \\ \cos \Theta=\frac{5}{13} \end{gathered}[/tex]

A randomly generated list of integers from 0 to 7 is being used to simulate an event, with the numbers 0, 1, 2, and 3 representing a success. What is the estimated probability of a success? O A. 25% OB. 50% O C. 80% O D. 43%

Answers

The total numbers of integers used is 7 + 1 = 8 (since we are using ubtewgers from 0 to 7).

If 0, 1, 2 and 3 represents succes, we have 4 integers of the 8 total that are success, thus, the theoretical probability is:

[tex]P=\frac{4}{8}=0.5[/tex]

So the probability os success is 0.50 = 50%.

reduce the square root of -360

Answers

reduce the square root of

[tex]\begin{gathered} \sqrt[]{-360} \\ 360=36\cdot10=6^2\cdot10 \\ \end{gathered}[/tex]

There is no square root for the negative number

so, this is represent a complex number

So,

[tex]\begin{gathered} \sqrt[]{-360}=\sqrt[]{-1}\cdot\sqrt[]{360} \\ =i\cdot\sqrt[]{6^2\cdot10} \\ =i\cdot6\sqrt[]{10} \\ =6\sqrt[]{10}\cdot i \end{gathered}[/tex]

help meeeeeeeeee pleaseee !!!!!

Answers

The solution to the composite function is as follows;

(f + g)(x) = x² + 3x + 5(f - g)(x) = x² - 3x + 5(f. g)(x) = 3x³ + 15x(f / g)(x) = x² + 5 / 3x

How to solve composite function?

The composition of a function is an operation where two functions say f and g generate a new function say h in such a way that h(x) = g(f(x)).

If we are given two functions, it is possible to create or generate a “new” function by composing one into the other.

Composite functions are when the output of one function is used as the input of another.

In other words, a composite function is generally a function that is written inside another function.

Therefore,

f(x) = x² + 5

g(x) = 3x

Hence, the composite function can be solved as follows:

(f + g)(x) = f(x) + g(x)  = x² + 5 + 3x = x² + 3x + 5

(f - g)(x) = f(x) - g(x)  = x² + 5 - 3x = x² - 3x + 5

(f. g)(x) = f(x) . g(x) = (x² + 5)(3x) = 3x³ + 15x

(f / g)(x) = f(x) / g(x) = x² + 5 / 3x

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The volume of a right circular cylinder with a radius of 4 in. and a height of 12 in. is ___ π in^3.

Answers

For the given right cylinder:

Radius = r = 4 in

Height = h = 12 in

The volume of the cylinder =

[tex]\pi\cdot r^2\cdot h=\pi\cdot4^2\cdot12=192\pi[/tex]

So, the answer will be the volume is 192π in^3

Does the point (3,-1) lie on the circle (x + 1)2 + (y - 1)1)2 = 16?no; the point is not represented by (h, k) in the equationyes; when you plug the point in for x and y you get a true statementno; when you plug in the point for x and y in the equation, you do not get a trueyes; the point is represented by (h, k) in the equation

Answers

We are given an equation of a circle and a point. We are then asked to find if the point lies on the circle. The equation of the circle and the point is given below

[tex]\begin{gathered} \text{Equation of the circle} \\ (x+1)^2+(y-1)^2=16 \\ \text{Given point =(3,-1)} \end{gathered}[/tex]

To find if the point lies in the circle, we can use the simple method of substituting the coordinates into the equation of the circle.

This can be seen below:

[tex]\begin{gathered} (3+1)^2+(-1-1)^2=16 \\ 4^2+(-2)^2=16 \\ 16+4=16 \\ \therefore20\ne16 \end{gathered}[/tex]

Since 20 cannot be equal to 16, this implies that the point does not lie on the circle.

ANSWER: Option 3

2. The Venn diagram shows the sets U, X and Y.UXY.34 246..9.512:31List the elements of the following sets:(a) X(b) Y(c) U(d) XUY(e) XnY(g) X\Y(h) Y\X(f) X'(1) (XY)2:31

Answers

Given the Venn diagram in the question, we can proceed to answer the questions as follow

[tex]\begin{gathered} X=\text{members of the subset X} \\ This\text{ gives: 1,2,3,4, and 5} \end{gathered}[/tex][tex]\begin{gathered} QuestionA\text{ } \\ X=1,2,3,4,and\text{ 5} \\ \end{gathered}[/tex]

Question B

Y= members of subset Y

Y =2,4,6, and 8

Question C

U means that we should list all elements in the universal set

U = ALL members of the set

U = 1,2,3,4,5,6,7,8, and 9

Question D

This is the union of both sets X and Y. This means we will list all the members that are found in the 2 subsets

[tex]\text{XUY}=1,2,3,4,5,6,\text{ and 8}[/tex]

Question E

[tex]\begin{gathered} \text{XnY means we are to find the elements that are common to both X and Y} \\ \text{XnY}=2\text{ and 4} \end{gathered}[/tex]

Question F

X' means that we should find all members of the set except that of X

[tex]X^{\prime}=6,7,8,\text{ and 9}[/tex]

Question G

X\Y means that we should list the elements of X that are not found in Y

X\Y= 1,3, and 5

Question H

Y\X means that we should list the elements of Y that are not found in X

Y\X= 6, and 7

Question I

To solve (XnY)' we will follow the steps below

Step 1: Find (XnY)

[tex]\text{XnY}=2\text{ and 4}[/tex]

Step 2: Find (XnY)'

[tex]We\text{ will list all elements aside (XnY)}[/tex][tex](XnY)^{^{\prime}}\Rightarrow1,3,5,6,7,8,\text{and 9}[/tex]

In the equation y = 2x, y represents the perimeter of a square.What does x represent?Ahalf the length of each sideBthe length of each sideСtwice the length of each sideDtwice the number of sides

Answers

Given:

An equation that represents the perimeter of a square:

[tex]y=2x[/tex]

To find:

What x represents.

Solution:

It is known that the perimeter of the square is equal to four times the side of the square.

Let the side of the square be s. So,

[tex]\begin{gathered} y=P \\ 2x=4s \\ x=\frac{4s}{2} \\ x=2s \end{gathered}[/tex]

Therefore, x represents twice the length of each side.

Determine whether point (4, -3) lies on the line with equation y = -2x + 5 by using substitution and by graphing.

Answers

The equation of the line is:

[tex]y=-2x+5[/tex]

And we need to find if the point (4,-3) lies on the line.

To solve by using substitution, we need to remember that an ordered pair always has the form (x, y) --> the first number is the x-value, and the second number is the y-value.

In this case (4,-3):

x=4

and

y=-3

So now, we substitute the x value into the equation, and if the y-value we get in return is -3 --> the point lies on the line. If not, the point does not lie on the line.

[tex]\begin{gathered} y=-2x+5 \\ \text{Substituting x=4} \\ y=-2(4)+5 \\ y=-8+5 \\ y=-3 \end{gathered}[/tex]

We do get -3 as the y-value which matches with the indicated y value of the point.

Thus, by substitution, we confirm that the point lies on the line.

To check the result by graphing, we need to graph the line. The graph of the line is shown in the following image:

In the image, we can see that the marked point on the line is the point we were looking for (4,-3). So we confirm by the graphing method that the point lies on the line.

Answer: It is confirmed by substitution and graphing that the point (4,-3) lies on the line.

Business Mathematics question ​

Answers

Number system depends on two basic concepts are Binary and Decimal.

Given the statement is :
Number System depends on two basic concept.

Let's know the definition of number system:

What is Number System?

A number system is defined as a system of writing to express numbers. It is the mathematical notation for representing numbers of a given set by using digits or other symbols in a consistent manner. It provides a unique representation of every number and represents the arithmetic and algebraic structure of the figures. It also allows us to operate arithmetic operations like addition, subtraction, multiplication and division.

Hence, Number system depends on two basic concepts are Binary and Decimal.

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You are given the equation 12 = 3x + 4 with no solution set. Part A: Determine two values that make the equation false. Part B: Explain why your integer solutions are false. Show all work.

Answers

[tex]12=3x+4 \\ \\ 8=3x \\ \\ x=8/3[/tex]

So, two integer values are 1 and 2 since they are not the solution to the equation.

Today's high temperature is 72°F. If yesterday's high temperature was 87"F, what was the change in high temperatures?

Answers

To find the change in temperature we have to do a subtraction:

Highest temperature-lowest temperature-

87-72= 15F

The change in high temperatures was 15 F .

Subtract the following polynomial. Once simplified, name the resulting polynomial. 5.) (10x² + 8x - 7) - (6x^2 + 4x + 5)

Answers

The given polynomial expression: (10x² + 8x - 7) - (6x^2 + 4x + 5)

[tex]\begin{gathered} (10x^2+8x-7)-(6x^2+4x+5) \\ \text{Open the brackets:} \\ (10x^2+8x-7)-(6x^2+4x+5)=10x^2+8x-7-6x^2-4x-5 \\ \text{Arrange the like term together:} \\ (10x^2+8x-7)-(6x^2+4x+5)=10x^2-6x^2+8x-4x-7-5 \\ \text{Simplify the like terms together:} \\ (10x^2+8x-7)-(6x^2+4x+5)=4x^2+4x-12 \end{gathered}[/tex]

The resulting polynomial be:

[tex](10x^2+8x-7)-(6x^2+4x+5)=4x^2+4x-12[/tex]

The highest degree of the polynomial is 2 so, the polynomial is Quadratic polynomial

Answer: 4x^2 + 4x - 12, Quadratic polynomial

A student council president wants to learn about the preferred theme for the upcoming spring dance. Select all the samples that are representative of the population.

Answers

The idea of being representative of the population is actually reflecting the characteristics (features) we want to study of the whole population.

In this case, the samples that better represent the whole population are B and D. Why? Because they give us the possibility of taking a student of every grade. The other options, excluding the "bus option" and the first option, fail doing that. Finally, these options (bus option and lunch option) are related to the council president.

There are 10 males and 18 females in the Data Management class. How many different committees of 5 students can be formed if there must be 3 males and 2 femalesA: 18360B: 2600C: 98280D: 15630

Answers

Answer:

A: 18360

Explanation:

The number of ways of combinations to select x people from a group of n people is calculated as

[tex]\text{nCx}=\frac{n!}{x!(n-x)!}[/tex]

Since we need to form committees with 3 males and 2 females, we need to select 3 people from the 10 males and 2 people from the 18 females, so

[tex]10C3\times18C2=\frac{10!}{3!(10-3)!}\times\frac{18!}{2!(18-2)!}=120\times153=18360[/tex]

Therefore, there are 18360 ways to form a committee.

So, the answer is

A: 18360

Find the coordinates of the circumcenter of triangle PQR with vertices P(-2,5) Q(4,1) and R(-2,-3)

Answers

The given triangle has vertices at:

[tex]\begin{gathered} P(-2,5) \\ Q(4,1) \\ R(-2,-3) \end{gathered}[/tex]

In the coordinate plane, the triangle looks like this:

There are different forms to find the circumcenter, we are going to use the midpoint formula:

[tex]M(x,y)=(\frac{x1+x2}{2},\frac{y1+y2}{2})[/tex]

Apply this formula for each vertice and find the midpoint:

[tex]M_{P,Q}=(\frac{-2+4}{2},\frac{5+1}{2})=(1,3)[/tex]

For QR:

[tex]M_{Q,R}=(\frac{4+(-2)}{2},\frac{1+(-3)}{2})=(1,-1)[/tex]

For PR:

[tex]M_{P,R}=(\frac{-2+(-2)}{2},\frac{5+(-3)}{2})=(-2,1)[/tex]

Now, we need to find the slope for any of the line segments, for example, PQ:

We can apply the slope formula:

[tex]m=\frac{y2-y1}{x2-x1}=\frac{1-5}{4-(-2)}=\frac{-4}{6}=-\frac{2}{3}[/tex]

By using the midpoint and the slope of the perpendicular line, find out the equation of the perpendicular bisector line, The slope of the perpendicular line is given by the formula:

[tex]\begin{gathered} m1\cdot m2=-1 \\ m2=-\frac{1}{m1} \\ m2=-\frac{1}{-\frac{2}{3}}=\frac{3}{2}_{} \end{gathered}[/tex]

The slope-intercept form of the equation is y=mx+b. Replace the slope of the perpendicular bisector and the coordinates of the midpoint to find b:

[tex]\begin{gathered} 3=\frac{3}{2}\cdot1+b \\ 3-\frac{3}{2}=b \\ b=\frac{3\cdot2-1\cdot3}{2}=\frac{6-3}{2} \\ b=\frac{3}{2} \end{gathered}[/tex]

Thus, the equation of the perpendicular bisector of PQ is:

[tex]y=\frac{3}{2}x+\frac{3}{2}[/tex]

If we graph this bisector over the triangle we obtain:

Now, let's find the slope of the line segment QR:

[tex]m=\frac{-3-1}{-2-4}=\frac{-4}{-6}=\frac{2}{3}[/tex]

The slope of the perpendicular bisector is:

[tex]m2=-\frac{1}{m1}=-\frac{1}{\frac{2}{3}}=-\frac{3}{2}[/tex]

Let's find the slope-intercept equation of this bisector:

[tex]\begin{gathered} -1=-\frac{3}{2}\cdot1+b \\ -1+\frac{3}{2}=b \\ b=\frac{-1\cdot2+1\cdot3}{2}=\frac{-2+3}{2} \\ b=\frac{1}{2} \end{gathered}[/tex]

Thus, the equation is:

[tex]y=-\frac{3}{2}x+\frac{1}{2}[/tex]

This bisector in the graph looks like this:

Now, to find the circumcenter we have to equal both equations, and solve for x:

[tex]\begin{gathered} \frac{3}{2}x+\frac{3}{2}=-\frac{3}{2}x+\frac{1}{2} \\ \text{Add 3/2x to both sides} \\ \frac{3}{2}x+\frac{3}{2}+\frac{3}{2}x=-\frac{3}{2}x+\frac{1}{2}+\frac{3}{2}x \\ \frac{6}{2}x+\frac{3}{2}=\frac{1}{2} \\ \text{Subtract 3/2 from both sides} \\ \frac{6}{2}x+\frac{3}{2}-\frac{3}{2}=\frac{1}{2}-\frac{3}{2} \\ \frac{6}{2}x=-\frac{2}{2} \\ 3x=-1 \\ x=-\frac{1}{3} \end{gathered}[/tex]

Now replace x in one of the equations and solve for y:

[tex]\begin{gathered} y=-\frac{3}{2}\cdot(-\frac{1}{3})+\frac{1}{2} \\ y=\frac{1}{2}+\frac{1}{2} \\ y=1 \end{gathered}[/tex]

The coordinates of the circumcenter are: (-1/3,1).

In the graph it is:

The following relation defines y as a one-to-one function of x x y3.0 7.45-8.4 -8.072.4 -9.16-1.5 7.45TrueFalse

Answers

One-to-one functions are the ones that each value of "y" is related to only one value of "x". So we need to check in the provided values if that applies.

We have a group of 4 different values of "y". For these the value y = 7.45 is related to the x values of 3 and -1.5, therefore it is not a one-to-one function.

Each of 6 students reported the number of movies they saw in the past year. This is what they reported:20, 16, 9, 9, 11, 20Find the mean and median number of movies that the students saw.If necessary, round your answers to the nearest tenth.

Answers

Solution:

The number of movies 6 students reported they saw in the past year is;

[tex]20,16,9,9,11,20[/tex]

The mean number of movies that the students saw is;

[tex]\begin{gathered} \bar{x}=\frac{\Sigma x}{n} \\ n=6 \\ \bar{x}=\frac{20+16+9+9+11+20}{6} \\ \bar{x}=\frac{85}{6} \\ \bar{x}=14.2 \end{gathered}[/tex]

The mean round to the nearest tenth is 14.2

Also, the median is the middle number of the data set after arranging either in ascending or descending order.

[tex]9,9,11,16,20,20[/tex]

The median number of movies the students saw is the average or mean of the third and fourth.

[tex]\begin{gathered} \text{Median}=\frac{11+16}{2} \\ \text{Median}=\frac{27}{2} \\ \text{Median}=13.5 \end{gathered}[/tex]

The median round to the nearest tenth is 13.5

Find the equation of the line connecting the points (2,0) and (3,15). Write your final answer in slope-intercept form.

Answers

The first step to find the equation of the line is to find its slope. To do it, we need to use the following formula:

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

Where y2 and y1 are the y coordinates of 2 given points on the line, and x2 and x1 are the x coordinates of the same points. m is the slope.

Replace for the given values and find the slope:

[tex]m=\frac{15-0}{3-2}=\frac{15}{1}=15[/tex]

Now, use one of the given points and the slope in the point slope formula:

[tex]y-y1=m(x-x1)[/tex]

Replace for the known values:

[tex]\begin{gathered} y-0=15(x-2) \\ y=15x-30 \end{gathered}[/tex]

The equation of the line is y=15x-30

I really need help solving this practice from my prep guide in trigonometry

Answers

Given: Different angles in degrees and in terms of pi. The different angles are:

[tex]\begin{gathered} a)714^0 \\ b)\frac{23\pi}{5} \\ c)120^0 \\ d)\frac{31\pi}{6} \end{gathered}[/tex]

To Determine: The equivalence of the given angles

The equivalent of degree and pi is given as

[tex]\begin{gathered} 2\pi=360^0 \\ \pi=\frac{360^0}{2} \\ \pi=180^0 \\ 360^0=2\pi \\ 1^0=\frac{2\pi}{360^0} \\ 1^0=\frac{1}{180}\pi \end{gathered}[/tex][tex]\begin{gathered} a)714^0 \\ 1^0=\frac{1}{180}\pi \\ 714^0=\frac{714^0}{180^0}\pi \\ 714^0=3\frac{29}{30}\pi \\ 714^0=\frac{119\pi^{}}{30} \end{gathered}[/tex][tex]\begin{gathered} b)\frac{23\pi}{5} \\ 1\pi=180^0 \\ \frac{23\pi}{5}=\frac{23}{5}\times180^0 \\ \frac{23\pi}{5}=828^0 \end{gathered}[/tex][tex]\begin{gathered} c)120^0 \\ 1^0=\frac{\pi}{180} \\ 120^0=120\times\frac{\pi}{180} \\ 120^0=\frac{2\pi}{3} \end{gathered}[/tex][tex]\begin{gathered} d)\frac{31\pi}{6} \\ 1\pi=180^0 \\ \frac{31\pi}{6}=\frac{31}{6}\times180^0 \\ \frac{31\pi}{6}=930^0 \end{gathered}[/tex]

ALTERNATIVELY

A revolution is 360 degree

[tex]\begin{gathered} a)714^0 \\ \text{Multiples of 360 degre}e \\ 2\times360^0=720^0 \\ \text{equivalent of 714 degre}e\text{ would be} \\ 720^0-714^0=6^0 \end{gathered}[/tex]

[tex]undefined[/tex]

[tex]\begin{gathered} a)714^0=\frac{119\pi}{30} \\ b)\frac{23\pi}{5}=828^0 \\ c)120^0=\frac{2\pi}{3} \\ d)\frac{31\pi}{6}=930^0 \end{gathered}[/tex]

) - At a farming supply store 7 pounds of seed cost $141.96. If a farmer needed 4 pounds ofseeds, how much would it cost him?

Answers

Hello

From the question, we know that 7 pounds of the seeds cost $141.96.

4 pounds would be assumed to be x and we can solve for x.

[tex]\begin{gathered} 7\text{ pounds = 141.96} \\ 4\text{ pounds = x} \end{gathered}[/tex]

Cross multiply both sides.

[tex]\begin{gathered} 7\times x=4\times141.96 \\ 7x=567.84 \end{gathered}[/tex]

Divide both sides by the coefficient of x

[tex]\begin{gathered} 7x=567.84 \\ \frac{7x}{7}=\frac{567.84}{7} \\ x=81.12 \end{gathered}[/tex]

From the calculation above, the cost of 4 pounds of the seeds is equal to $81.12

A rectangle has a diagonal of length 10 cm and a base of length 8 cm . Find its height

Answers

Given:

The length of diagonal of rectangle is d = 10 cm.

The length of base is b = 8 cm.

Explanation:

The relation between length, height and diagonal of rectangle is given by pythagoras theorem. So

[tex]d^2=l^2+h^2[/tex]

Substitute the values in the equation to obtain the value of h.

[tex]\begin{gathered} (10)^2=(8)^2+h^2 \\ 100=64+h^2 \\ h=\sqrt[]{100-64} \\ =\sqrt[]{36} \\ =6 \end{gathered}[/tex]

So the height of rectangle is 6 cm.

Answer: 6 cm

What is the measure of the angle at the bottom of home plate?

Answers

We will ave the following:

*First: We will determine the sum of all internal angles of the polygon:

[tex](n-2)\cdot180\Rightarrow(5-2)\cdot180=3\cdot180[/tex][tex]=540[/tex]

*Second: Now, that we know that the sum of all internal angles will be 540°, the following is true:

[tex]90+90+135+135+\alpha=540[/tex]

Now, we solve for alpha [The angle]:

[tex]\Rightarrow\alpha=540-135-135-90-90\Rightarrow\alpha=90[/tex]

So, the measure of the angle at the bottom is 90°.

Write the equation of a line, in slope-intercept form, that has a slope of m= -2 and y-interceptof b = -8.Y=

Answers

Explanation

We are given the following:

[tex]\begin{gathered} slope(m)=-2 \\ y\text{ }intercept(b)=-8 \end{gathered}[/tex]

We are required to determine the equation of the line in the slope-intercept form.

We know that the equation of a line in slope-intercept form is given as:

[tex]\begin{gathered} y=mx+b \\ where \\ m=slope \\ b=y\text{ }intercept \end{gathered}[/tex]

Therefore, we have:

[tex]\begin{gathered} y=mx+b \\ where \\ m=-2\text{ }and\text{ }b=-8 \\ y=-2x+(-8) \\ y=-2x-8 \end{gathered}[/tex]

Hence, the answer is:

[tex]y=-2x-8[/tex]

Given a family with four children, find the probability of the event. All are boys. The probability that all are boys

Answers

Answer:

0.0625

Explanation:

The number of children in the family = 4

The possible combination of genders:

[tex]|\Omega|=2^4=16[/tex]

The event that all are boys, |A|=1

Therefore, the probability that all are boys:

[tex]\begin{gathered} P(A)=\frac{1}{16} \\ =0.0625 \end{gathered}[/tex]

Find the equation of the line. Use exortumbers. st V = 2+ 9 8- 6+ 5+ -4 3+ 2+ 1+ T + -9-8-7-65 2 3 5 6 7 8 9 4 -3 -2 -2 + -3+ -4+ -5* -6+ -7+ -8+

Answers

We can see that the line passes by the points (0, -5) & (5, 0), using this information we proceed as follows:

1st: We find the slope(m):

[tex]m=\frac{0+5}{5-0}\Rightarrow m=1[/tex]

2nd: We use one of the points from the line and the slope to replace in the following expression:

[tex]y-y_1=m(x-x_1)[/tex]

That is (Using point (0, -5):

[tex]y+5=1(x-0)[/tex]

Now, we solve for y:

[tex]\Rightarrow y=x-5[/tex]

And that is the equation of the line shown.

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