Find the value of n x 5 when n=8

Answer:

~Lord

The magnitude of the degree in a circle is. there are 5 angels in a circle

measure of each angle:

so measure of each angle is 72°

Step-by-step explanation:

As Per Provided Information

Number of sector in given circle is 5

As we know sum of all angles in a circle at centre is 360° .

Since number of sector is given and we are asked to find the measure of each angle in given circle .

[tex] \huge{ \boxed{\sf \: Angle_{(Circle)} = \cfrac{360}{ \: number \: of \: sector}}}[/tex]

Now put the value in above equation and we obtain

[tex] \longrightarrow\sf \: Angle_{(Circle)} = \cfrac{360}{5} \\ \\ \\ \longrightarrow\sf \: Angle_{(Circle)} = \cancel \dfrac{360}{5} \\ \\ \\ \longrightarrow\sf \: Angle_{(Circle)} = {72}^{ \circ} [/tex]

Therefore,

Answer: Below

Step-by-step explanation:

We know that water must be three times flour, so our end goal is 12 cups of water, since 4 * 3 = 12.

We already have 2.5 and 4, so we make the equation:

2.5 + x = 12

Simplify.

x = 7.5

Our answer is 7.5

Using the normal distribution and the central limit theorem, it is found that there is a 0.5934 = 59.34% probability that there is an error of at most $1000.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Researching the problem on the internet, it is found that the population has mean and standard deviation given, respectively, by [tex]\mu = 57300, \sigma = 9600[/tex].

For samples of 64, the standard error is given by:

[tex]s = \frac{9600}{\sqrt{64}} = 1200[/tex]

The probability of an error of at most $1000 is the probability of a sample mean between $56,300 and $58,300, which is the p-value of Z when X = 58300 subtracted by the p-value of Z when X = 56300, hence:

X = 58300:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{58300 - 57300}{1200}[/tex]

Z = 0.83

Z = 0.83 has a p-value of 0.7967.

X = 56300:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{56300 - 57300}{1200}[/tex]

Z = -0.83

Z = -0.83 has a p-value of 0.2033.

0.7967 - 0.2033 = 0.5934.

0.5934 = 59.34% probability that there is an error of at most $1000.

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Using the uniform distribution, it is found that there is a 0.9 probability that the tree's angle, from the vertical, will be greater than 4 degrees.

It is a distribution with two bounds, a and b, in which each outcome is equally as likely.

The probability of finding a value above x is:

[tex]P(X > x) = \frac{b - x}{b - a}[/tex]

In this problem, the bounds are a = 3 and b = 13, hence:

[tex]P(X > 4) = \frac{13 - 4}{13 - 3} = 0.9[/tex]

There is a 0.9 probability that the tree's angle, from the vertical, will be greater than 4 degrees.

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Answer:

There is a 0.9 probability that the tree's angle, from the vertical, will be greater than 4 degrees.

Step-by-step explanation:

just took the test :D

Answer: 10 cars

Step-by-step explanation:

We know that:

A railroad car is 6 inches long and the railroad track is 5 feet long

Start by converting feet to inches. You can do that by multplying the amount of feet by 12.

5 feet x 12 = 60 inches

Now we can divide the length of the railroad track by the length of the railroad cars to see how many we can fit.

60 ÷ 6 = 10

Answer: 76 meters

Step-by-step explanation:

top side left blank = 18 because it is congruent to the bottom

left side blank is 4 + 4 + 4 (right side lengths added)

left side blank is 12

add all side lengths together for perimeter

12 + 18 + 4 + 8 + 4 + 8 + 4 + 18 = 76

76 meters

Answer:

4

Step-by-step explanation:

[tex]slope = \frac{5 - 1}{5 - 4} \\ = \frac{4}{1} \\ = 4[/tex]

Answer: 4

Step-by-step explanation:

Slope is rise over run, which is the change in the y-values divided by the change in the x-values. Each point is given as a coordinate pair: (x,y).

For point Q (4,1) the y-value is 1 and the x-value is 4.

For point X (5,5), the y-value is 5 and the x-value is 5.

To find the slope, take the y-value for point X minus the y-value for point Q. That is the numerator of your slope. Then take the x-value for point X minus the x-value for point Q. That is the denominator of your slope.

The numerator divided by the denominator equals the slope.

(5-1)/(5-4) = (4)/(1) = 4

Semi perimeter:-

[tex]\\ \rm\rightarrowtail s=\dfrac{a+b+c}{2}[/tex]

[tex]\\ \rm\rightarrowtail s=\dfrac{1.8+2.4+3}{2}[/tex]

[tex]\\ \rm\rightarrowtail s=\dfrac{7.2}{2}=3.6cm[/tex]

Apply heron s formula

Area:-

[tex]\\ \rm\rightarrowtail \sqrt{s(s-a)(s-b)(s-c)}[/tex]

[tex]\\ \rm\rightarrowtail \sqrt{3.6(3.6-1.8)(3.6-3)(3.6-2.4)}[/tex]

[tex]\\ \rm\rightarrowtail \sqrt{3.6(1.8)(0.6)(1.2)}[/tex]

[tex]\\ \rm\rightarrowtail \sqrt{4.6656}[/tex]

[tex]\\ \rm\rightarrowtail 2.16cm^2[/tex]

Answer:

[tex]\sf Area \ of \ a \ Triangle=\dfrac12bh[/tex]

(where b is the base of the triangle and h is the height)

Given:

Substitute the given values into the formula:

[tex]\sf \implies Area=\dfrac12 \cdot 2.4 \cdot 1.8[/tex]

               [tex]\sf =2.16 \ cm^2[/tex]

Answer:

I think the modes are: 20 ,18 and 19

The system of equations that describes the situation is given by these two following equations:

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are c and x.

Carlos has 10 more friends than Xavier when they start the competition, hence:

c = 10 + x.

Carlos doubles his amount of friends and Xavier triples his. In the end they have a total of 160 friends, hence:

2c + 3x = 160.

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Step-by-step explanation:

x is the angle.

complementary angles are adding up to 90°.

supplementary angles are adding up to 180°.

so,

90 - x = (180 - x) - 40 = 140 - x

0 = 50 ? no

there is something wrong here. this cannot work out, there is no solution. there cannot be a solution.

because due to the definitions, the supplementary measure of an angle must always be 90° larger than the complementary measure of the same angle. that is by default the difference in their definition.

so, if an angle is only 40° less than the supplementary angle, then it cannot be the complementary angle.

so, either there was a mistake in the question, or this is a trick question.

under the given circumstances, there is no solution possible.

Answer:

Corral 4

Step-by-step explanation:

we need to divide  the area of the corral by the Number of animals In order To know the dedicated  space for each animal

Corral 1 :

(50×40)÷110 = 18.181818181818 < 20

Then it doesn’t meet the requirements.

Corral 2 :

(60×35)÷115 = 18.260869565217 < 20

Then it doesn’t meet the requirements

Corral 3 :

(55×45)÷125 = 19.8 < 20

Then it doesn’t meet the requirements

Corral 4 :

(65×40)÷130 = 20

Then It meets the requirements

Answer:

[tex]\frac{198}{7} \ \text{feet}^{2}[/tex]

Given:

To find the area of the rug, we need to use the formula "πr² or π(D/2)²"

Where:

Since we do not have the radius, we need to substitute the diameter in the formula "π(D/2)²" to determine the area of the rug.

⇒ [tex]\pi (\frac{D}{2} )^{2}[/tex]

⇒ [tex]\pi (\frac{6}{2} )^{2}[/tex]

⇒ [tex]\pi (3 )^{2}[/tex]

⇒ [tex]\pi (3 )(3)[/tex]

⇒ [tex]9\pi[/tex]

Substituting "22/7" as π:

⇒ [tex]9(\frac{22}{7} )[/tex]

⇒ [tex](\frac{198}{7} )[/tex]

When finding the area of ANY shape, do not forget to include the units.

⇒ [tex]\frac{198}{7} \ \text{feet}^{2}[/tex]

Answer:

28.26 ft²

Step-by-step explanation:

Formula:

[tex]\text{Area of circular rug:} = \pi r^{2}[/tex]

Determining the radius of the circular rug:

To determine the radius, we need to divide the diameter by 2.

Given diameter: 6 feet

[tex]\implies {\dfrac{\text{Diameter}}{2} = \text{Radius}[/tex]

[tex]\implies {\dfrac{\text{6}}{2} = \text{Radius}[/tex]

[tex]\implies 3\ \text{feet} = \text{Radius}[/tex]

Replacing the radius in the formula:

[tex]\implies \text{Area of circular rug:} = \pi (3)^{2}[/tex]

Determining the area of the circular rug:

[tex]\implies \text{Area of circular rug:} = \pi (3)^{2}[/tex]

[tex]\implies \text{Area of circular rug:} = 9\pi[/tex]

Replacing π as 3.14 (Approx. measure of π):

[tex]\implies \text{Area of circular rug:} = 9(3.14)[/tex]

[tex]\implies \text{Area of circular rug:} = 28.26 \ \text{ft}^{2}[/tex]

Answer: 36 degrees

Step-by-step explanation:

Answer:

377 square centimeters

Step-by-step explanation:

Formula: h(2×pi×radius) I know there's a second part but I'm doing this first.

First find the radius, in the problem it says a diameter of 10cm

Divide 10 by 2 to find the radius = 5

I'm going to use 3.14 as Pi

7(2×3.14×5)

7(31.4) = 219.8

Next part, solving for the 2 circles

Formula: 2×pi×radius²

2×3.14×5²

solve 5² first (5×5) = 25

2×3.14×25 is 157

add 219.8 and 157 = 376.8 round to 377

Answer: 377 square centimeters

Answer:

I belive that will be a trapazoid

Step-by-step explanation:

Both sides on the top and bottom are parallel
Please tell me if im wrong!

Answer:

Trapezium

Step-by-step explanation:

It has exactly one pair of parallel sides

A) System doesn't have a solution.

x-y=4

2x-2y=1

x=4+y

2(4+y)-2y=1

8+2y-2y=1

8≠1

B) System has one solution.

x-4y=0

2x+4y=3

x=4y

2(4y)+4y=3

8y+4y=3

12y=3

y=1/4

C) Every solution is right for the system.

x-2y=1

4x-8y=4

x=1+2y

4(1+2y)-8y=4

4+8y-8y=4

4=4

Answer:

Step-by-step explanation:

The height of the tree to the nearest hundredth of a meter is 1.875 meters.

Given that:

Khalil is 1.65 meters tall. At 3 p.m., he measures the length of a tree's shadow to be 34.55 meters. He stands 30.4 meters away from the tree, so that the tip of his shadow meets the tip of the tree's shadow.

Let h be the height of khalil h = 1.65 , H be the tree height , L be the length of the tree's shadow L = 34.55 and l be the length of khalil shadow l = 30.4

Using equivalent ratios of heights:

h : H = l : L

H : 1.65 = 34.55 : 30.4

H/1.65 = 34.55/30.4

H = 34.55/30.4 * 1.65

on solving

H = 1.875 meters which is tree height

Therefore the height of the tree to the nearest hundredth of a meter is 1.875 meters.

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Answer:

A. a transformation that either reduces or enlarges an object in the coordinate plane

Step-by-step explanation:

The definition of dilation is the size of an object/shape by increasing/ decreasing its dimensions by scaling factors.

Dialtions do not flip and object, spin it, or slide it. It's dimensions are either enlarged, or reduced. Therefore, option A makes the most sense.

The left out number is 12 if the  average (mean) of five numbers is 8. If one of the numbers is left out, the average of the remaining numbers is 7 option (D) is correct.

It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.

Let's suppose the number of sum is x when mean is 8

[tex]\rm \dfrac{x}{5} = 8[/tex]

x = 40

Now one number is left out, mean become 7 let's suppose the sum is y.

[tex]\rm \dfrac{y}{4} = 7[/tex]

y = 28

So, the number = 40 - 28 = 12

Thus, the left out number is 12 if the  average (mean) of five numbers is 8. If one of the numbers is left out, the average of the remaining numbers is 7 option (D) is correct.

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Answer:

70 degrees

Step-by-step explanation:

rectange angle total = 360

1 corner = 90

90-20 = 70

Answer:

1- 34,000 Millimeters in 34 meters

2- 50 Millimeters in 5 Cm

3- 6mm is already in milimeter form

Step-by-step explanation:

1000 Millimeters are in 1 meter so 34,000 millimeters are in 34 meters

10 millimeters are in 1 CM, so 50 millimeters make up 5 cm

Answer:

34m=34x10³mm=34000mm

5cm=5x10mm=50mm

6mm=6mm

Answer:

-9,4

Step-by-step explanation:

Using the given function, it is found that the snowball traveled 4 feet when the height is 20 feet.

The height when x feet are traveled is given by:

h(x) = -0.5x² + 6x + 4.

When the height is of 20 meters, we have that h(x) = 20, hence:

20 = -0.5x² + 6x + 4.

0.5x² - 6x + 16 = 0

x² - 12x + 32 = 0

(x - 8)(x - 4) = 0

For the first time: x - 4 = 0 -> x = 4.

The snowball traveled 4 feet when the height is 20 feet.

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Answer:

(x+2)^2 + (y-4)^2 = 4^2

Step-by-step explanation:

A circle is x^2 + y^2 = 1 , where r = 1

The radius of that circle looks to appear to be r = 4.

x^2 + y^2 = 4^2

Transition that circle origin from (0,0) to (-2,4)

The origin is (-2,4) which mean h = -2 left and k = 4 up.

(x-h)^2 + (y-k)^2 = 4^2

(x-(-2))^2 + (y-4)^2 =4^2

Answer:

12 days

Step-by-step explanation:

Answer:

Step-by-step explanation:

The hour hand is 20 mm and the minute hand is

The tip of the hour hand travels 1/12 of the circle and the tip of the minute hand travels full circle in one hour.

Find each length and their difference using circumference formula.

Hour hand

Minute hand

The difference between the two above

Answer:

230.38 mm

Step-by-step explanation:

The distance traveled by the tip of the hands is (part of) the circumference of the circle with radius of the lengths of the hands.

[tex]\textsf{Circumference of a circle}=\sf 2 \pi r\quad\textsf{(where r is the radius)}[/tex]

Radii

Larger circle (minute hand):  

Smaller circle (hour hand):

Minute Hand

The minute hand does a full rotation of the circle in one hour.

Therefore, the distance it travels in one hour is the complete circumference of a circle with radius 40 mm:

[tex]\begin{aligned} \implies \textsf{Distance minute hand travels} & = \sf 2 \pi (40)\\ & = \sf 80 \pi \: mm\end{aligned}[/tex]

Hour Hand

There are 12 numbers on a clock.

The hour hand travels from one number to the next in one hour.

Therefore, the distance it travels in one hour is 1/12th of the circumference of the circle:

[tex]\begin{aligned}\implies \sf \textsf{Distance hour hand travels} & =\left(\dfrac{1}{12}\right)2 \pi r\\ & = \sf \left(\dfrac{1}{12}\right)2 \pi (40)\\& = \sf \dfrac{20}{3}\pi \: mm \end{aligned}[/tex]

To find how much farther the tip of the minute hand moves than the tip of the hour hand, subtract the latter from the former:

[tex]\begin{aligned}\implies \textsf{distance} & = \textsf{minute hand distance}-\textsf{hour hand distance}\\& = \sf 80 \pi - \dfrac{20}{3} \pi \\& = \sf \dfrac{220}{3} \pi \\& = \sf 230.38\: mm \:(nearest\:hundredth) \end{aligned}[/tex]