find the solution to the linear system of differential equations {x′y′==19x 20y−15x−16y satisfying the initial conditions x(0)=9 and y(0)=−6.

The percent changes that we need to write in the table are, in order from top to bottom:

To find the percent change, we need to use the formula:

P = 100%*(final population - initial population)/initial population.

For the first case, we have:

initial population = 111

final population = 128

Then:

P = 100%*(128 - 111)/111 = 15.32%

For the second case we have:

initial population = 128

final population = 117

P = 100%*(117 - 128)/128 = -8.6%

For the last case:

initial population = 117

final population = 147

then:

P = 100%*(147 - 117)/117 = 25.64%

These are the percent changes.

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The [tex]125^{8x-6}[/tex], can be expressed in the form 5y,  as  5^{(24x-18)} .

An expression, often known as a mathematical expression, is a finite collection of symbols that are well-formed in accordance with context-dependent principles.

Given that

[tex]125^{8x-6}[/tex]

then we can express 125 inform of a power of 5  which can be expressed as [tex]125 = 5^{5}[/tex]

Then the expression becomes

[tex]5^{3(8x-6)}[/tex]

=[tex]5^{(24x-18)}[/tex]

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The problem asks us to use a change of variables to find the indefinite integral of the given expression, and then verify our result by differentiation. The original integral is[tex]\int\limits(1/\sqrt(4 - 25x^2)) dx[/tex], and we need to find a suitable change of variables to simplify the integral.

To find a suitable change of variables, we notice that the expression inside the square root resembles the standard form of a trigonometric identity. In this case, we can use the substitution x = (2/5)sin(u).

First, we find the derivative [tex]dx/dt: dx/dt = (2/5)cos(u).[/tex]

Next, we substitute x and dx in terms of u into the original integral:

[tex]\int\limits(1/\sqrt (4 - 25x^2)) dx = \int\limit(1/\sqrt(4 - 25((2/5)sin(u))^2))((2/5)cos(u)) du.[/tex]

Simplifying further, we get[tex]: \int\limits(1/\sqrt(4 - 4sin^2(u)))((2/5)cos(u)) du = \int\limits(1/\sqrt(4cos^2(u)))((2/5)cos(u)) du = \int\limits(1/2) du = (1/2)u + c[/tex]

To verify our result, we differentiate (1/2)u + C with respect to u:

d/dt((1/2)u + C) = 1/2, which matches the integrand[tex]1/\sqrt(4 - 25x^2)[/tex]in the original expression.

Therefore, the indefinite integral of[tex]\sqrt(4 - 25x^2)[/tex] with respect to x is (1/2)arcsin(2x/5) + C, where C is the constant of integration.

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To determine the absolute extremes of the function f(x) = 2x^3 - 6x^2 - 180 over the interval 1 < x < 4, we need to find the critical points and evaluate the function at these points as well as the endpoints of the interval. Answer :  the absolute minimum occurs at x = 2, and the minimum value is -208

1. Find the derivative of f(x):

f'(x) = 6x^2 - 12x

2. Set f'(x) equal to zero to find the critical points:

6x^2 - 12x = 0

Factor out 6x: 6x(x - 2) = 0

Set each factor equal to zero:

6x = 0, which gives x = 0

x - 2 = 0, which gives x = 2

So, the critical points are x = 0 and x = 2.

3. Evaluate the function at the critical points and the endpoints of the interval:

f(1) = 2(1)^3 - 6(1)^2 - 180 = -184

f(4) = 2(4)^3 - 6(4)^2 - 180 = -128

4. Compare the function values at the critical points and endpoints to find the absolute extremes:

The minimum value occurs at x = 2, where f(2) = 2(2)^3 - 6(2)^2 - 180 = -208.

The maximum value occurs at x = 4 (endpoint), where f(4) = -128.

Therefore, the absolute minimum occurs at x = 2, and the minimum value is -208.

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The three derivative rules used to find the derivative of the given function f(x) = (4e* In-e") [C5] are product rule, chain rule and quotient rule.

The given function is f(x) = (4e* In-e") [C5].

We can find its derivative using the following derivative rules:

Product Rule: If u(x) and v(x) are two functions of x, then the derivative of their product is given by d/dx(uv) = u(dv/dx) + v(du/dx)

Quotient Rule: If u(x) and v(x) are two functions of x, then the derivative of their quotient is given by d/dx(u/v) = (v(du/dx) - u(dv/dx))/(v²)

Chain Rule: If f(x) is a composite function, then its derivative can be calculated using the chain rule as d/dx(f(g(x))) = f'(g(x))g'(x)

Now, let's find the derivative of the given function using the above rules:Let u(x) = 4e, v(x) = ln(e⁻ˣ) = -x

Using the product rule, we have:f'(x) = u'(x)v(x) + u(x)v'(x)f(x) = 4e⁻ˣ + (-4e) * (-1) = -4eˣ⁺¹

Therefore, f'(x) = d/dx(-4eˣ⁺¹) = -4e

Using the chain rule, we have:g(x) = -xu(g(x))

Using the chain rule, we have:f'(x) = d/dx(u(g(x)))

= u'(g(x))g'(x)f'(x)

= 4e⁻ˣ * (-1)

= -4e⁻ˣ

Finally, using the quotient rule, we have:f(x) = (4e* In-e") [C5] = 4e¹⁻ˣ

Using the power rule, we have:f'(x) = d/dx(4e¹⁻ˣ) = -4e¹⁻ˣ

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The function given is [tex]\(f(x,y) = \sqrt{x^2 + y^2}\)[/tex]. The partial derivative with respect to[tex]\(x\) (\(f_x\)) is \(\frac{x}{\sqrt{x^2 + y^2}}\)[/tex].  The partial derivative with respect to [tex]\(y\) (\(f_y\)) is \(\frac{y}{\sqrt{x^2 + y^2}}\)[/tex].

[tex]\(f_x(3,5)\) is \(\frac{3}{\sqrt{3^2 + 5^2}}\)[/tex] .

- [tex]\(f_y(-6,1)\)[/tex] is [tex]\(\frac{1}{\sqrt{(-6)^2 + 1^2}}\)[/tex].

To find the partial derivative [tex]\(f_x\)[/tex], we differentiate [tex]\(f(x,y)\)[/tex] with respect to x while treating y as a constant. Using the chain rule, we get:

[tex]\[f_x = \frac{d}{dx}(\sqrt{x^2 + y^2}) = \frac{1}{2\sqrt{x^2 + y^2}} \cdot 2x = \frac{x}{\sqrt{x^2 + y^2}}.\][/tex]

Similarly, to find [tex]\(f_y\)[/tex], we differentiate [tex]\(f(x,y)\)[/tex] with respect to y while treating x as a constant:

[tex]\[f_y = \frac{d}{dy}(\sqrt{x^2 + y^2}) = \frac{1}{2\sqrt{x^2 + y^2}} \cdot 2y = \frac{y}{\sqrt{x^2 + y^2}}.\][/tex]

Substituting the given values, we find [tex]\(f_x(3,5) = \frac{3}{\sqrt{3^2 + 5^2}}\) and \(f_y(-6,1) = \frac{1}{\sqrt{(-6)^2 + 1^2}}\)[/tex].

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To find the new area of Suzy's frame after upgrading with a scale factor of 12/5, we need to multiply the area of the original frame by the square of the scale factor.

Hence , Given that the original area of the frame is 19 in², we can calculate the new area as follows: New Area = (Scale Factor)^2 * Original Area

Scale Factor = 12/5. New Area = (12/5)^2 * 19 in² = (144/25) * 19 in²

= 6.912 in² (rounded to three decimal places). Therefore, the new area of Suzy's frame after upgrading will be approximately 6.912 square inches.

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We are able to deduce from the information that has been supplied that the total number of squared products that the variables m and f contribute to add up to 3,892 in total.

To determine the value of m2f, first each value of m is multiplied by the value of "f" that corresponds to it, then the result is squared, and finally all of the squared products are put together. This process is repeated until the desired value is determined. Let's analyse the calculation by breaking it down into the following components:

For m = 2, f = 82: (2 * 82)² = 27,664.

For m = 3, f = 278: (3 * 278)² = 231,288.

For m = 4, f = 432: (4 * 432)² = 373,248.

For m = 5, f = 16: (5 * 16)² = 2,560.

For m = 6, f = 6: (6 * 6)² equals 216.

For m = 7, f = 3: (7 * 3)² = 441.

For m = 8, f = 1: (8 * 1)² equals 64.

After tallying up all of the squared products, we have come to the conclusion that the total number we have is 635,481: 27,664 + 231,288 plus 373,248 plus 2,560 plus 216 plus 441 plus 64.

The total number of squared products that contain both m and f comes to 635,481 as a direct result of this.

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The slope of the tangent line to the given polar curve at the point where `θ = 7π/4` and `r = 5 - 7cosθ` is `0`.

To find the slope of the tangent line to the given polar curve at the point where `θ = 7π/4` and `r = 5 - 7cosθ`, we first need to find the derivative of `r` with respect to `θ`.

We can use the following formula to do this: `r' = dr/dθ = (dr/dt) / (dθ/dt) = (5 + 7sinθ) / sinθ`, where `t` is the parameter and `r = r(θ)`.

Now, to find the slope of the tangent line, we use the following formula: `dy/dx = (dy/dθ) / (dx/dθ)`, where `y = r sinθ` and `x = r cosθ`.

Differentiating `y` and `x` with respect to `θ`, we get `dy/dθ = r' sinθ + r cosθ` and `dx/dθ = r' cosθ - r sinθ`.

Plugging in `θ = 7π/4` and `r = 5 - 7cosθ`, we get

`r' = (5 + 7sinθ) / sinθ = (5 - 7/√2) / (-1/√2) = -7√2 - 5√2 = -12√2` and

`x = r cosθ = (5 - 7cosθ) cosθ = (5√2 + 7)/2` and

`y = r sinθ = (5 - 7cosθ) sinθ = (-5√2 - 7)/2`.

Therefore, `dy/dx = (dy/dθ) / (dx/dθ) = (r' sinθ + r cosθ) / (r' cosθ - r sinθ) = (-12√2 + (-5√2)(-1/√2)) / (-12√2(-1/√2) - (-5√2)(-√2)) = 7/12 - 7/12 = 0`.Thus, the slope of the tangent line to the given polar curve at the point where `θ = 7π/4` and `r = 5 - 7cosθ` is `0`.

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The equation describes the rate of change of the amount of the substance, which decreases by 6.8% per day.

The equation dN/dt = -0.068N represents the rate of change of the amount of the chemical substance, where N represents the amount of the substance and t represents the number of days. The negative sign indicates that the amount of the substance is decreasing over time.

By solving this differential equation, we can determine the behavior of the substance's decay. Integrating both sides of the equation gives:

∫ dN/N = ∫ -0.068 dt

Applying the integral to both sides, we get:

ln|N| = -0.068t + C

Here, C is the constant of integration. By exponentiating both sides, we find:

|N| = e^(-0.068t + C)

Since the absolute value of N is used, both positive and negative values are possible for N. The constant C represents the initial condition, or the amount of the substance at t = 0 (N₀). Therefore, the general solution for the decay of the substance is:

N = ±e^(-0.068t + C)

This equation provides the general behavior of the amount of the chemical substance as it decays over time, with the constant C and the initial condition determining the specific values for N at different time points.

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The polynomial (f-g)(x) is equal to x^2 + 2x - 35.

To find (f-g)(x), we need to subtract g(x) from f(x).

Step 1: Find f(x) - g(x)

f(x) - g(x) = (x^2 + 3x - 28) - (x + 7)

Step 2: Distribute the negative sign to the terms inside the parentheses:

= x^2 + 3x - 28 - x - 7

Step 3: Combine like terms:

= x^2 + 3x - x - 28 - 7

= x^2 + 2x - 35

Therefore, (f-g)(x) = x^2 + 2x - 35.

The result is a polynomial in simplest form.

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Prospective Cohort Study, Cross-sectional survey, Retrospective cohort study . Researchers would analyze data from individuals who have already undergone diagnostic testing to evaluate the impact of various strategies on identifying cases and guiding public health interventions.

The study on the transmission risk of a novel coronavirus causing severe acute respiratory syndrome would best be suited for a prospective cohort study. This design involves following a group of individuals over time to observe their exposure to the virus and the development of the disease, allowing researchers to assess the risk factors and outcomes associated with transmission.

The study on COVID-19 vaccine confidence among parents of Filipino children in Manila would be best conducted using a cross-sectional survey design. This design involves collecting data at a single point in time to assess the attitudes, beliefs, and behaviors of a specific population regarding vaccine confidence.

It provides a snapshot of the participants' views and allows for the examination of factors associated with vaccine acceptance or hesitancy.

The study on diagnostic testing strategies to manage the COVID-19 pandemic would be most suitable for a retrospective cohort study design. This design involves looking back at historical data to assess the effectiveness and outcomes of different diagnostic testing strategies in managing the pandemic.

Researchers would analyze data from individuals who have already undergone diagnostic testing to evaluate the impact of various strategies on identifying cases and guiding public health interventions.

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The value of the Wronskian [tex]at x = 2 is 480[/tex]. The correct answer is (e) 480.  three functions and calculate their Wronskian at x = 2.

To find the Wronskian of the given functions at x = 2, we need to calculate the determinant of the matrix formed by their derivatives. The Wronskian is defined as:

[tex]W = |Y1 Y2 Y3||Y1' Y2' Y3'||Y1'' Y2'' Y3''|[/tex]

First, let's find the derivatives of the given functions:

[tex]Y1' = 0 (since Y1 = 5, a constant)Y2' = 2Y3' = 4x^3[/tex]

Next, let's find the second derivatives:

[tex]Y1'' = 0 (since Y1' = 0)Y2'' = 0 (since Y2' = 2, a constant)Y3'' = 12x^2[/tex]

Now, we can form the matrix and calculate its determinant:

[tex]| 5 2x x^4 || 0 2 4x^3 || 0 0 12x^2|[/tex]

Substituting x = 2 into the matrix, we have:

[tex]| 5 2(2) (2)^4 || 0 2 4(2)^3 || 0 0 12(2)^2 |[/tex]

Simplifying the matrix:

[tex]| 5 4 16 || 0 2 32 || 0 0 48 |[/tex]

The determinant of this matrix is:

[tex]Det = (5 * 2 * 48) - (16 * 2 * 0) - (4 * 0 * 0) - (5 * 32 * 0) - (2 * 16 * 0) - (48 * 0 * 0)= 480[/tex]

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To find the value of angle θ (e) given that sin θ = 0.67, we need to take the inverse sine of 0.67. Using a calculator, we can determine the approximate value of e.

Using the inverse sine function (sin^(-1)), we find:

e ≈ sin^(-1)(0.67) ≈ 42.067°.

Therefore, the approximate value of angle e, rounded to three decimal places, is 42.067°.

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(a) The relation R is reflexive. (b) The relation R is symmetric but not antisymmetric. (c) The relation R is transitive. (d) The relation R is not an equivalence relation. (e) The set (A, R) does not form a partially ordered set.

(a) The relation R is reflexive because every positive integer a has all its prime factors in common with itself.

Therefore, aRa is true for all positive integers a.

(b) The relation R is symmetric because if a is a positive integer and b is another positive integer with the same prime factors as a, then b also has the same prime factors as a.

However, R is not antisymmetric because there can be positive integers a and b such that aRb and bRa but a is not equal to b.

(c) The relation R is transitive because if aRb and bRc, it means that all the prime factors of a are also prime factors of b, and all the prime factors of b are also prime factors of c.

Therefore, all the prime factors of a are also prime factors of c, satisfying the transitive property.

(d) The relation R is not an equivalence relation because it is not reflexive, symmetric, and transitive.

It is only reflexive and transitive but not symmetric. An equivalence relation must satisfy all three properties.

(e) (A, R) does not form a partially ordered set because a partially ordered set requires that the relation is reflexive, antisymmetric, and transitive.

In this case, R is not antisymmetric, so it does not meet the requirements of a partially ordered set.

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The volume of the solid generated by revolving the region bounded by the equations y = 16 - x² and y = 0, between x = -2 and x = 2, around the x-axis is 256π/3 cubic units.

To find the volume, we can use the method of cylindrical shells. Consider an infinitesimally thin vertical strip of width dx at a distance x from the y-axis. The height of this strip is given by the difference between the two curves: y = 16 - x² and y = 0. Thus, the height of the strip is (16 - x²) - 0 = 16 - x². The circumference of the shell is 2πx, and the thickness is dx.

The volume of this cylindrical shell is given by the formula V = 2πx(16 - x²)dx. Integrating this expression over the interval [-2, 2] will give us the total volume. Therefore, we have:

V = ∫[from -2 to 2] 2πx(16 - x²)dx

Evaluating this integral gives us V = 256π/3 cubic units. Hence, the volume of the solid generated by revolving the region bounded by the given equations around the x-axis is 256π/3 cubic units.

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There are 55 counters in a box.

We have to given that;

There are C counters in a box, 11 of the counters are green

And, Benedict takes 20 counters at random from the box 4 of these counters are green.

Since, Any relationship that is always in the same ratio and quantity which vary directly with each other is called the proportional.

Hence, By definition of proportion we get;

⇒ c / 11 = 20 / 4

Solve for c,

⇒ c = 11 × 20 / 4

⇒ c = 11 × 5

⇒ c = 55

Therefore, The value of counters in a box is,

⇒ c = 55

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To find the volume of the solid obtained by rotating the region enclosed by the curves y = ln(x) + 2, y = 0, y = 7, and x = 0 about the y-axis, we can use the method of cylindrical shells to set up an integral and evaluate it.

The volume of the solid obtained by rotating the region about the y-axis can be found by integrating the cross-sectional area of each cylindrical shell from y = 0 to y = 7.

For each value of y within this range, we need to find the corresponding x-values. From the equation y = ln(x) + 2, we can rewrite it as[tex]x = e^(y - 2).[/tex]

The radius of each cylindrical shell is the x-value corresponding to the given y-value, which is x = e^(y - 2).

The height of each cylindrical shell is given by the differential dy.

Therefore, the volume of the solid can be calculated as follows: [tex]V = ∫[0 to 7] 2πx dy[/tex]

Substituting the value of x = e^(y - 2), we have: V = ∫[0 to 7] 2π(e^(y - 2)) dy

Simplifying the integral, we get: [tex]V = 2π ∫[0 to 7] e^(y - 2) dy[/tex]

To evaluate this integral, we can use the property of exponential functions:

[tex]∫ e^(kx) dx = (1/k) e^(kx) + C[/tex]

In our case, k = 1, so the integral becomes[tex]: V = 2π [e^(y - 2)][/tex]from 0 to 7

Evaluating this integral, we have: [tex]V = 2π [(e^5) - (e^-2)][/tex]

This gives us the volume of the solid obtained by rotating the region about the y-axis.

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In betweenness and incidence geometry, the point D lies in the interior of angle CAB if and only if it is between points B and C on line BC.

In betweenness and incidence geometry, we have the following axioms:

Proof:

Conversely,

Thus, we have proved that D is in the interior of angle CAB if and only if B * D * C.

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To find the absolute extrema of the function g(x) = 4x^2 - 8x on the closed interval [0, 4], we need to evaluate the function at its critical points and endpoints. The general solution of a differential equation typically involves finding an antiderivative of the given equation and including a constant of integration.

To find the critical points of g(x), we take the derivative and set it equal to zero: g'(x) = 8x - 8. Solving for x, we get x = 1, which is the only critical point within the interval [0, 4]. Next, we evaluate g(x) at the critical point and endpoints: g(0) = 0, g(1) = -4, and g(4) = 16. Therefore, the absolute minimum occurs at (1, -4) and the absolute maximum occurs at (4, 16). Moving on to the differential equation, without a specific equation given, it is not possible to find the general solution. The general solution of a differential equation typically involves finding an antiderivative of the equation and including a constant of integration denoted by C.

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(A) To find the antiderivative of the function f(x, y) = 6ln(x)xy with respect to y, we treat x as a constant and integrate: ∫ 6ln(x)xy dy = 6ln(x)(1/2)y^2 + C,

where C is the constant of integration.

(B) Using the antiderivative we found in part (A), we can evaluate the definite integral: ∫[a, b] 6ln(x) dy = [6ln(x)(1/2)y^2]∣[a, b].

Substituting the upper and lower limits of integration into the antiderivative, we have: [6ln(x)(1/2)b^2] - [6ln(x)(1/2)a^2] = 3ln(x)(b^2 - a^2).

Therefore, the value of the definite integral is 3ln(x)(b^2 - a^2).

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The pipeline with a length of 1 kilometer will require approximately 314,159,265 cubic centimeters of oil to fill.

To find the volume of the pipeline, we need to calculate the volume of a cylinder. The formula for the volume of a cylinder is V = πr^2h, where V is the volume, r is the radius, and h is the height (or length) of the cylinder.

Inside diameter of the pipeline = 20 centimeters

Radius (r) = diameter / 2 = 20 cm / 2 = 10 cm

To convert the length of the pipeline from kilometers to centimeters, we multiply by 100,000:

Length of the pipeline = 1 kilometer * 100,000 = 100,000 centimeters

Now, we can calculate the volume of the pipeline:

V = πr^2h = π * 10^2 * 100,000 = 3.14159 * 100 * 100,000 = 314,159,265 cubic centimeters

Therefore, it will take approximately 314,159,265 cubic centimeters of oil to fill 1 kilometer of the pipeline.

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Therefore, the points on the graph where the tangent line is vertical are:

(x, y) = (6, 3)

(x, y) = (-6, 3)

(x, y) = (12, -3)

(x, y) = (-12, -3)

To find the points on the graph where the tangent line is vertical, we need to identify the values of (x, y) that make the derivative of y with respect to x undefined. A vertical tangent line corresponds to an undefined slope.

Given the equation y^3 - 27y = x^2 - 90, we can differentiate both sides of the equation implicitly to find the slope of the tangent line:

Differentiating y^3 - 27y = x^2 - 90 with respect to x:

3y^2 * dy/dx - 27 * dy/dx = 2x.

To find the values where the slope is undefined, we set the derivative dy/dx equal to infinity or does not exist:

3y^2 * dy/dx - 27 * dy/dx = 2x.

(3y^2 - 27) * dy/dx = 2x.

For a vertical tangent line, dy/dx must be undefined, which occurs when (3y^2 - 27) = 0. Solving this equation:

3y^2 - 27 = 0,

3y^2 = 27,

y^2 = 9,

y = ±3.

So, the points where the tangent line is vertical are when y = 3 and y = -3.

Substituting these values of y back into the original equation to find the corresponding x values:

For y = 3:

y^3 - 27y = x^2 - 90,

3^3 - 27(3) = x^2 - 90,

27 - 81 = x^2 - 90,

-54 = x^2 - 90,

x^2 = 36,

x = ±6.

For y = -3:

y^3 - 27y = x^2 - 90,

(-3)^3 - 27(-3) = x^2 - 90,

-27 + 81 = x^2 - 90,

54 = x^2 - 90,

x^2 = 144,

x = ±12.

Ordered from smallest to largest x and then from smallest to largest y:

(x, y) = (-12, -3)

(x, y) = (-6, 3)

(x, y) = (6, 3)

(x, y) = (12, -3)

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Events a and b are not independent. The probability of both events occurring is 0.2, which is less than the product of their individual probabilities (0.7 x 0.4 = 0.28).

If events a and b were independent, the probability of both events occurring would be the product of their individual probabilities (P(a) x P(b)). However, in this scenario, the probability of both events occurring is 0.2, which is less than the product of their individual probabilities (0.7 x 0.4 = 0.28). This suggests that the occurrence of one event affects the occurrence of the other, indicating that they are dependent events.

Independence between events a and b refers to the idea that the occurrence of one event does not affect the probability of the other event occurring. In other words, if events a and b are independent, the probability of both events occurring is equal to the product of their individual probabilities. However, in this scenario, we are given that the probability of event a occurring is 0.7, the probability of event b occurring is 0.4, and the probability of both events occurring is 0.2. To determine whether events a and b are independent, we can compare the probability of both events occurring to the product of their individual probabilities. If the probability of both events occurring is equal to the product of their individual probabilities, then events a and b are independent. However, if the probability of both events occurring is less than the product of their individual probabilities, then events a and b are dependent.

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The equation of the ellipse satisfying the given conditions, with foci (*6, 0) and vertices (#10, 0), in standard form is (x/5)^2 + y^2 = 1. In the form Ax^2 + By^2 = C, the equation is 25x^2 + y^2 = 25.



An ellipse is a conic section defined as the locus of points where the sum of the distances to two fixed points (foci) is constant. The distance between the foci is 2c, where c is a positive constant. In this case, the foci are given as (*6, 0), so the distance between them is 2c = 12, which means c = 6.

The distance between the center and each vertex of an ellipse is a, which represents the semi-major axis. In this case, the vertices are given as (#10, 0). The distance from the center to a vertex is a = 10.To write the equation in standard form, we need to determine the values of a and c. We know that a = 10 and c = 6. The equation of an ellipse in standard form is (x-h)^2/a^2 + (y-k)^2/b^2 = 1, where (h, k) represents the center of the ellipse.

Since the center of the ellipse lies on the x-axis and is equidistant from the foci and vertices, the center is at (h, k) = (0, 0). Plugging in the values, we have (x/10)^2 + y^2/36 = 1. Multiplying both sides by 36 gives us the equation in standard form: 36(x/10)^2 + y^2 = 36.To convert the equation to the form Ax^2 + By^2 = C, we multiply each term by 100, resulting in 100(x/10)^2 + 100y^2 = 3600. Simplifying further, we obtain 10x^2 + y^2 = 3600. Dividing both sides by 36 gives us the final equation in the desired form: 25x^2 + y^2 = 100.

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The result for the given series is 2/([tex]2^{4}[/tex] + 2 * 27 * x + 2 * k * x) will be a sum of two terms, each of which can be evaluated using geometric series or other known series representations.

The given series is 2/([tex]2^{4}[/tex] + 2 * 27 * x + 2 * k * x). To determine the interval of convergence, we need to find the values of x for which the denominator of the fraction does not equal zero.

Setting the denominator equal to zero, we get [tex]2^{4}[/tex] + 2 * 27 * x + 2 * k * x = 0. Simplifying, we get 16 + 54x + kx = 0. Solving for x, we get x = -16/(54+k).

Since the series is a rational function with a polynomial in the denominator, it will converge for all values of x that are not equal to the value we just found, i.e. x ≠ -16/(54+k). Therefore, the interval of convergence is (-∞, -16/(54+k)) U (-16/(54+k), ∞), where U represents the union of two intervals.

To evaluate the series within the interval of convergence, we can use partial fraction decomposition to write 2/([tex]2^{4}[/tex] + 2 * 27 * x + 2 * k * x) as A/(x - r) + B/(x - s), where r and s are the roots of the denominator polynomial.

Using the quadratic formula, we can solve for the roots as r = (-27 + sqrt(27² - 2 * [tex]2^{4}[/tex] * k))/k and s = (-27 - sqrt(27² - 2 * [tex]2^{4}[/tex] * k))/k. Then, we can solve for A and B by equating the coefficients of x in the numerator of the partial fraction decomposition to the numerator of the original fraction.

Once we have A and B, we can substitute the expression for the partial fraction decomposition into the series and simplify. The result will be a sum of two terms, each of which can be evaluated using geometric series or other known series representations.

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The value of slant height of cone is,

⇒ l = 4.2 feet

We have to given that,

The slant height of a cone with a volume of approximately 28.2 ft and a height of 2 ft.

Now, We know that,

Volume of cone is,

⇒ V = πr²h / 3

Here, We have;

⇒ V = 28.2 feet

⇒ h = 2 feet

Substitute all the values, we get;

⇒ V = πr²h / 3

⇒ 28.2 = 3.14 × r² × 2 / 3

⇒ 28.2 × 3 = 6.28r²

⇒ 84.6 = 6.28 × r²

⇒ 13.5 = r²

⇒ r = √13.5

⇒ r = 3.7 feet

Since, We know that,

⇒ l² = h² + r²

Where, 'l' is slant height and 'r' is radius.

⇒ l² = 2² + 3.7²

⇒ l² = 4 + 13.5

⇒ l² = 17.5

⇒ l = √17.5

⇒ l = 4.2 feet

Thus, The value of slant height of cone is,

⇒ l = 4.2 feet

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To find a formula for h(x) = (f∘g)(x), we need to substitute the expression for g(x) into f(x) and simplify.

Given:

f(x) = √(x² - 9²)

g(x) = √(9 - x)

Substituting g(x) into f(x):

h(x) = f(g(x)) = f(√(9 - x))

Simplifying:

h(x) = √((√(9 - x))² - 9²)

    = √(9 - x - 81)

    = √(-x - 72)

Therefore, the formula for h(x) is h(x) = √(-x - 72).

Now, let's determine the domain of h(x). Since h(x) involves taking the square root of a quantity, the radicand (-x - 72) must be greater than or equal to zero.

-x - 72 ≥ 0

Solving for x:

-x ≥ 72

x ≤ -72

Therefore, the domain of h(x) is x ≤ -72, expressed in interval notation as (-∞, -72].

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Given equation is ln(4x + 5) + 4x = 25. We are required to find an integer n so that the interval (n, n+1) contains a solution to this equation.

To solve this equation, we have to use numerical methods. We can use the trial and error method or use graphical methods to find the solution.Let's consider the graphical method:First, let's plot the graphs of y = ln(4x + 5) + 4x and y = 25 and see where they intersect. We can use the Desmos graphing calculator for this.Step 1: Visit the Desmos Graphing Calculator website.Step 2: Enter the equations y = ln(4x + 5) + 4x and y = 25 in the given field.Step 3: Adjust the window of the graph to see the intersection points, which are shown in the image below.Image of the graph shown on Desmos calculator.The graph of y = ln(4x + 5) + 4x intersects the graph of y = 25 in the interval (4, 5).Thus, n = 4.Therefore, the solution is as follows:n = 4.

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The length g for the triangle in this problem is given as follows:

3.

The three trigonometric ratios are the sine, the cosine and the tangent of an angle, and they are obtained according to the rules presented as follows:

For the angle of 60º, we have that:

Hence we apply the sine ratio to obtain the length g as follows:

[tex]\sin{60^\circ} = \frac{g}{2\sqrt{3}}[/tex]

[tex]\frac{\sqrt{3}}{2} = \frac{g}{2\sqrt{3}}[/tex]

2g = 6

g = 3.

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