Find the point on the line 2x + 7y - 4 = 0 which is closest to the point (-3, 4)

Answer: it would be 15

Step-by-step explanation:

to do this add 15 five times and you will get 75

just tell the teacher that you started at ten and then when you got to 15 it worked. orrrr...  you know there is 60 minutes in an hour and you know that it can be divided by 4 to equal 15 so you added 15 one more time and got 75

6 The probabilities of both questions are a.1/20, and b.9/20.

(a) To find the probability that both David and Mary hit the target, we can use the formula for independent events: P(A and B) = P(A) x P(B).

So, P(David hits the target) = 1/5, and P(Mary hits the target) = 1/4.

Therefore, P(both hit the target) = (1/5) x (1/4) = 1/20.

(b) To find the probability that the target will be hit at least once, we can use the formula P(A or B) = P(A) + P(B) - P(A and B).

So, P(David hits the target) = 1/5, and P(Mary hits the target) = 1/4.

Therefore, P(at least one hits the target) = P(David hits the target) + P(Mary hits the target) - P(both hit the target) = (1/5) + (1/4) - (1/20) = 9/20.

7. The probabilities of both questions are a.0.0625, and b.0.0588.

(a) If the first card is replaced, the probability of drawing a Heart on the first card is 13/52 (since there are 13 Hearts in a deck of 52 cards). After the first card is drawn and replaced, there are still 52 cards in the deck, with 13 of them being Hearts.

So, the probability of drawing a Heart on the second card is also 13/52.

Therefore, the probability of drawing two Hearts with replacement is (13/52) x (13/52) = 169/2704, which simplifies to 0.0625 (correct to 4 decimal places).

(b) If the first card is not replaced, the probability of drawing a Heart on the first card is 13/52 (since there are 13 Hearts in a deck of 52 cards). After the first card is drawn and not replaced, there are now only 51 cards left in the deck, with 12 of them being Hearts.

So, the probability of drawing a Heart on the second card is 12/51.

Therefore, the probability of drawing two Hearts without replacement is (13/52) x (12/51) = 156/2652, which simplifies to 0.0588 (correct to 4 decimal places).

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This expression represents the change in the function values (f (x) - f (2)) divided by the change in the x-values (x - 2), which gives us the slope of the secant line between points P and Q.

The slope of the secant line through the points P (2, f (2)) and Q (x, f(x)) can be found using the slope formula:

slope = (f (x) - f (2))/ (x - 2)

This expression represents the change in y (f(x) - f (2)) divided by the change in x (x - 2) between the two points. It gives the average rate of change of the function over that interval.

Alternatively, we could use the point-slope form of a line to find the equation of the secant line through P and Q:

y - f(2) = slope(x - 2)

where slope is given by the expression above. This equation represents a line that passes through P and Q, and it can be used to approximate the behavior of the function between those points. As x gets closer to 2, the secant line becomes a better approximation of the tangent line to the curve at that point.

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First, let me explain some key terms related to the question.

- Discrete: This refers to mathematics that deals with countable or finite sets of numbers, rather than continuous sets. In other words, we're dealing with specific, separate values rather than a continuous range.
- Recurrence: This refers to a mathematical sequence where each term depends on one or more previous terms. In other words, we can use a formula to generate the next term based on previous terms.
- Relation: This refers to a mathematical expression that relates one or more variables. In this case, our recurrence relation relates the sequence An to its previous terms.

With that in mind, let's tackle the question!

We're given a recurrence relation: An = 6An-1 – 9An-2. This means that each term in the sequence An depends on the two previous terms, An-1 and An-2.

We're also given initial conditions: a0 = 2 and a1 = 3. This gives us a starting point for the sequence.

To solve the recurrence relation and find the values of An, we'll use a technique called iteration. Essentially, we'll use the recurrence relation to generate the next term in the sequence, then use that term to generate the next one, and so on.

Here's how it works:

- First, we use the initial conditions to find the first two terms of the sequence: a0 = 2 and a1 = 3.
- Next, we use the recurrence relation to generate the third term: a2 = 6a1 - 9a0 = 6(3) - 9(2) = 0.
- We continue this process, using the recurrence relation to generate each subsequent term. For example, to find a3, we use the formula An = 6An-1 – 9An-2 with n = 3: a3 = 6a2 - 9a1 = 6(0) - 9(3) = -27.
- We can keep going like this to find as many terms as we need.

Here's what the first few terms of the sequence look like:

a0 = 2
a1 = 3
a2 = 0
a3 = -27
a4 = -54
a5 = -162
a6 = -270
...
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The equation that find the values of the table is y = 2x - 2.

Mrs Sanchez writes the following table of x and y values on the chalkboard. Therefore, let's find the equation that fits the values of the table.

using slope intercept form for linear equation,

y = mx + b

where

Hence,

m = -2 + 6 / 0 + 2

m = 4 / 2

m = 2

Therefore, lets' find the value of b, y intercepts using (0, -2)

Hence,

y = 2x + b

-2 = 2(0) + b

b = -2

Therefore, the equation is y = 2x -2

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Answer: The cooling of a body can be modeled using Newton's Law of Cooling, which states that the rate of cooling of an object is proportional to the temperature difference between the object and its surroundings. The equation for Newton's Law of Cooling is:

T(t) = T_0 + (T_s - T_0) * e^(-kt)

where T(t) is the temperature of the body at time t, T_0 is the initial temperature of the body, T_s is the temperature of the surroundings, k is the cooling constant, and e is the base of the natural logarithm.

Assuming that the temperature of the surroundings is constant at 68°F, we can use the given information to solve for t:

76.5°F = 68°F + (T_0 - 68°F) * e^(-kt)

Simplifying this equation, we get:

8.5°F = (T_0 - 68°F) * e^(-kt)

Taking the natural logarithm of both sides, we get:

ln(8.5°F / (T_0 - 68°F)) = -kt

Solving for t, we get:

t = -ln(8.5°F / (T_0 - 68°F)) / k

The cooling constant k depends on various factors such as the body's mass, the body's surface area, and the body's initial temperature. For a human body, k is typically estimated to be around 0.00087 per minute.

Assuming that the initial temperature of the body was 98.6°F (the average temperature of a living human body), we can plug in the values and solve for t:

t = -ln(8.5°F / (98.6°F - 68°F)) / 0.00087

t ≈ 16.5 hours

Therefore, it has been approximately 16.5 hours since the person died.

Step-by-step explanation:

The answer is (d) none of these.

For the differential equation (2D^2 + 12D + 2)y = 0,

The characteristic equation is: 2r^2 + 12r + 2 = 0

Solving this quadratic equation using the quadratic formula, we get:

r = (-12 ± sqrt(12^2 - 4(2)(2))) / (2(2))

r = (-6 ± sqrt(32)) / 2

r = -3 ± sqrt(8)

The roots of the characteristic equation are complex conjugates, which means that the solution to the differential equation will be of the form:

y = e^(-3x) (c1 cos(sqrt(8)x) + c2 sin(sqrt(8)x))

The damping ratio is given by:

ζ = (c * n) / (2 * sqrt(a))

where c is the damping coefficient, n is the natural frequency, and a is the coefficient of the second derivative term.

In this case, c = 12, n = sqrt(8), and a = 2. Substituting these values into the above formula, we get:

ζ = (12 * sqrt(8)) / (2 * sqrt(2))

ζ = 6

Since the damping ratio ζ is greater than 1, the system is overdamped.

Therefore, the answer is (a) Overdamping.

For the differential equation (3D^2 + 6D + 7)y = sin(x),

The characteristic equation is: 3r^2 + 6r + 7 = 0

Using the quadratic formula, we can see that the roots of the characteristic equation are complex conjugates, which means that the solution to the differential equation will be of the form:

y = e^(-3x) (c1 cos(sqrt(2)x) + c2 sin(sqrt(2)x))

Since the real part of the roots of the characteristic equation is negative, the system is stable

However, the right-hand side of the differential equation is not of the form that matches with the solution, which means that the system is not able to respond to the input sin(x).

Therefore, the answer is (d) none of these.

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The steady-state solutions of y'(t) =

[tex] y^2 - 15y + 56[/tex]

are y = 7 and y = 8, with y = 7 being a stable equilibrium point and y = 8 being an unstable equilibrium point.

The steady-state solutions of a differential equation are the values of the function that remain constant over time. To find the steady-state solutions of the given differential equation, we need to set y'(t) = 0 and solve for y.

[tex]y^2 - 15y + 56 = 0[/tex]

We can factor this quadratic equation as (y-7)(y-8) = 0, so the steady-state solutions are y = 7 and y = 8. These values are called equilibrium points or fixed points because if y(t) starts at one of these values, it will remain there as time goes on.

To understand the behavior of the system around these steady-state solutions, we can use the first derivative test. If y'(t) > 0 for y < 7 or y > 8, then y(t) is increasing and moving away from the steady-state solution. If y'(t) < 0 for 7 < y < 8, then y(t) is decreasing and moving towards the steady-state solution. Hence, y = 7 is a stable equilibrium point, and y = 8 is an unstable equilibrium point.

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You asked to sketch the function f(t) and find its Fourier Transform, where f(t) = 1 for 0 ≤ t < 1, and f(t) = 0 otherwise.

(i) To sketch the function f(t), follow these steps:
1. Set up a coordinate system with the horizontal axis representing time (t) and the vertical axis representing the amplitude of the function (f(t)).
2. For the time interval 0 ≤ t < 1, draw a horizontal line at f(t) = 1.
3. For any other time intervals (t < 0 or t ≥ 1), draw a horizontal line at f(t) = 0.

(ii) To find the Fourier Transform of the function f(t), use the following formula:
F(ω) = ∫[f(t) * e^(-jωt)] dt, where ω is the angular frequency and the integral is evaluated over the entire domain of the function.

Since f(t) is non-zero only in the interval 0 ≤ t < 1, we can limit the integration to that interval:
F(ω) = ∫[e^(-jωt)] dt from 0 to 1.

Now, integrate the function with respect to t:
F(ω) = [-1/jω * e^(-jωt)] evaluated from 0 to 1.

Evaluate the limits of the integral:
F(ω) = [-1/jω * e^(-jω)] - [-1/jω * e^(0)].
F(ω) = (-1/jω * e^(-jω)) + (1/jω).

So, the Fourier Transform of the function f(t) is given by:
F(ω) = (1/jω) * (1 - e^(-jω)).

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The joint distribution for (X,Y) is given by the table below, and the marginal distributions for X and Y are given by the tables below.

Y P(Y)

0 0

1 0.3686

2 0.0588

To determine the joint distribution for (X,Y), we need to calculate the probability of each possible outcome. There are 4 kings in the deck and 13 diamonds. We can use the formula for calculating probabilities of combinations to find the probabilities of each possible combination of kings and diamonds:

P(X = 0, Y = 0) = 36/52 * 35/51 = 0.5098

P(X = 0, Y = 1) = 36/52 * 16/51 = 0.2353

P(X = 0, Y = 2) = 36/52 * 1/51 = 0.0055

P(X = 1, Y = 0) = 16/52 * 36/51 = 0.2353

P(X = 1, Y = 1) = 16/52 * 15/51 = 0.0588

P(X = 1, Y = 2) = 16/52 * 0 = 0

P(X = 2, Y = 0) = 1/52 * 36/51 = 0.0055

P(X = 2, Y = 1) = 1/52 * 15/51 = 0.0007

P(X = 2, Y = 2) = 1/52 * 0 = 0

Therefore, the joint distribution for (X,Y) is:

To find the marginal distribution for X, we can sum the probabilities for each possible value of X:

P(X = 0) = 0.5098 + 0.2353 + 0.0055 = 0.7506

P(X = 1) = 0.2353 + 0.0588 + 0 = 0.2941

P(X = 2) = 0.0055 + 0.0007 + 0 = 0.0062

Therefore, the marginal distribution for X is:

To find the marginal distribution for Y, we can sum the probabilities for each possible value of Y:

P(Y = 0) = 0.5098 + 0.2353 + 0.0055 = 0.7506

P(Y = 1) = 0.2353 + 0.0588 + 0.0007 = 0.2948

P(Y = 2) = 0.0055 + 0 + 0 = 0.0055

Therefore, the marginal distribution for Y is:

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The value of system of equations are,

⇒ x = - 1 and y = 1

We have to given that;

The system of equations are,

x + 2y = 1  .. (i)

x = y - 2  .. (ii)

Now, We can plug the value of x in (i);

x + 2y = 1

(y - 2) + 2y = 1

3y - 2 = 1

3y = 3

y = 1

And, From (ii);

x = y - 2

x = 1 - 2

x = - 1

Thus, The value of system of equations are,

⇒ x = - 1 and y = 1

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To begin, let's recall that synthetic division is a method used to divide a polynomial by a linear factor (i.e. a binomial of the form x-a, where a is a constant). The result of synthetic division is the quotient of the division, which is a polynomial of one degree less than the original polynomial.

In this case, we are given that x is a solution of a third-degree polynomial equation. This means that the polynomial can be factored as (x-r)(ax^2+bx+c), where r is the given solution and a, b, and c are constants that we need to determine.

To use synthetic division, we will divide the polynomial by x-r, where r is the given solution. The result of the division will give us the coefficients of the quadratic factor ax^2+bx+c.

Here's an example of how to do this using synthetic division:

Suppose we are given the polynomial P(x) = x^3 + 2x^2 - 5x - 6 and we know that x=2 is a solution.

1. Write the polynomial in descending order of powers of x:

P(x) = x^3 + 2x^2 - 5x - 6

2. Set up the synthetic division table with the given solution r=2:

2 | 1  2  -5  -6

3. Bring down the leading coefficient:

2 | 1  2  -5  -6
  ---
   1

4. Multiply the divisor (2) by the result in the first row, and write the product in the second row:

2 | 1  2  -5  -6
  ---
   1  2

5. Add the second row to the next coefficient in the first row, and write the sum in the third row:

2 | 1  2  -5  -6
  ---
   1  2 -3

6. Multiply the divisor by the result in the third row, and write the product in the fourth row:

2 | 1  2  -5  -6
  ---
   1  2 -3
       4

7. Add the fourth row to the next coefficient in the first row, and write the sum in the fifth row:

2 | 1  2  -5  -6
  ---
   1  2 -3
       4 -2

The final row gives us the coefficients of the quadratic factor: ax^2+bx+c = x^2 + 2x - 3. Therefore, the factorization of P(x) is

P(x) = (x-2)(x^2+2x-3).

To find the real solutions of the equation, we can use the quadratic formula or factor the quadratic further:

x^2 + 2x - 3 = (x+3)(x-1).

Therefore, the real solutions of the equation are x=2, x=-3, and x=1.

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The approximated value of the volume of the cone cup is 18.5 cubic cm

From the question, we have the following parameters that can be used in our computation:

Diameter = 2.8 cm

Height = 9 cm

The volume of the cone cup is calculated as

Volume = 1/3 * 3.14 * r^2h

substitute the known values in the above equation, so, we have the following representation

Volume = 1/3 * 3.14 * (2.8/2)^2 * 9

Evaluate the products

So, we have

Volume = 18.4632

Approximate

Volume = 18.5

Hence, the volume is 18.5

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Answer:

Step-by-step explanation:

Stem leaf plots are read from top to bottom

The center columned number is the first digit in the number, your 10's place (stem)

The other numbers to right and left are the leaves. and will be your ones place.

So the list of numbers for seaside would be

05, 08

10, 11, 12, 15, 16, 18

25, 25, 27, 27, 28

30 and 36

Put them in a line and find the middle number  I counted,  on the chart to 7.  I counted the (5, 8, 0, 1, 2, 5, 6)   6 was my 7th number with a one in front making it 16

Numbers for Bayside (reads somewhat backwards) since leaves go towards left

05, 06, 08

10, 12, 14, 15, 16, 18

20, 20, 22, 23, 25

42

no leaves in front of 3 on this side so no numbers for 30's

Count 7 and that's 15

Since there are 15 for each school, count 7 numbers and that's your middle number for each

Bayside 15

Seaside 16

Variability is range of numbers

Bayside goes from 5 to 42 so 42-5=38

Seaside 36-5=31

Answer:

31

Step-by-step explanation:

Since there are 15 for each school, count 7 numbers and that's your middle number for each

Bayside 15

Seaside 16

Variability is range of numbers

Bayside goes from 5 to 42 so 42-5=38

Seaside 36-5=31

Answer:

the median is D) 12

Step-by-step explanation:

First of all what it median

median is the value in the middle of a data set.

For example:- The median of 2,3,4 is 3. In Maths, the median is also a type of average, which is used to find the centre value.

The original price of the ticket was $210 and the new price is $310.

To find the percentage increase, we can use the formula:

percentage increase = (new price - old price) / old price * 100%

So, the percentage increase in the ticket price is:

percentage increase = (310 - 210) / 210 * 100% = 47.62%

Therefore, the ticket price has increased by 47.62%.

If the airline charges an additional $50 baggage fee with the new ticket price of $310, then the new price will be $360.

To find the new percentage increase, we can use the same formula:

percentage increase = (new price - old price) / old price * 100%

So, the percentage increase in the ticket price with the additional $50 baggage fee is:

percentage increase = (360 - 210) / 210 * 100% = 71.43%

Therefore, the ticket price has increased by 71.43% with the additional $50 baggage fee.

Answer:

Percent Increase= 47.619% increase, With $50 baggage fee= 71.4286% increase

Step-by-step explanation:

The mean of the data set is 9.33 minutes.

To find mean of the data set, we will add all the values and divide by the total number of values.

In this case, the sum of the values is:

= 0 + 2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 + 22

= 112

There are 12 values in the data set, so the mean is:

= Sum of values / Total number of values

= 112 / 12

= 9.3333

= 9.33 minutes.

Therefore, the mean of the data set is 9.33 minutes.

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there are 1365 possible committees that can be formed from this group of 15 people, regardless of gender.

To form a committee of 4 people from a group of 9 women and 6 men, we need to consider all possible combinations of 4 people, regardless of gender.

The number of ways to choose 4 people from a group of 15 (9 women and 6 men) is given by the combination formula:

C(15,4) = 15! / (4! * (15-4)!) = 15! / (4! * 11!) = (15 * 14 * 13 * 12) / (4 * 3 * 2 * 1) = 1365

Therefore, there are 1365 possible committees that can be formed from this group of 15 people, regardless of gender.

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The probability of rolling an odd number on a die and getting a head on a coin toss is 1/4. Therefore, the correct answer is (c) 1/4.

The probability of two independent events occurring simultaneously: rolling an odd number on a die and getting a head on a coin toss. To find the probability, we'll multiply the probabilities of each event.

1. Probability of rolling an odd number on a die:
There are 3 odd numbers (1, 3, 5) and 6 possible outcomes (1, 2, 3, 4, 5, 6). So the probability is 3/6, which simplifies to 1/2.

2. Probability of getting a head on a coin toss:
There are 2 possible outcomes (heads or tails), and 1 of them is heads. So the probability is 1/2.

Now, we'll multiply the probabilities: (1/2) * (1/2) = 1/4.

So the probability of rolling an odd number on a die and getting a head on a coin toss is 1/4. Therefore, the correct answer is (c) 1/4.

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If the money had been shared after Sarah's 7th birthday instead of now, she would have received an additional $12.95 because her share would have been increased from $54 to $66.95 based on the new age ratio of 8:7:4.

At present, James, Sarah, and Lucy have received $72, $54, and $36 respectively based on their age ratios of 8:6:4. If Sarah's birthday is in three weeks, then she would have turned 7 by then. So, the new age ratio would be 8:7:4. The total amount of money to be shared remains $180.

Therefore, the total parts for the new ratio are 8+7+4 = 19 parts.

The new share for Sarah is

(7/19) * $180 = $66.95 (rounded to the nearest cent)

So, if the money had been shared after Sarah's birthday, she would have received an additional $66.95 - $54 = $12.95.

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The surface area of the pyramid is 186 cm².

Given that the net diagram of a square pyramid, we need to find the surface area of the same,

SA = a² + 2al

a = side length, l = height

SA = 6² + 2×6×12.5

= 186 cm²

Hence, the surface area of the pyramid is 186 cm².

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Yes, given the conditions provided, a, b, and c are conditionally independent given d. Conditional independence means that the probability distribution of any one of the variables is independent of the others when the conditioning variable is known.

In this case, you have the following conditional independence relationships:

1. a and b are conditionally independent given d.
2. a and c are conditionally independent given d.
3. b and c are conditionally independent given d.

To show that a, b, and c are conditionally independent given d, we need to demonstrate that the joint probability distribution of a, b, and c given d can be factored into the product of their individual conditional probability distributions.

P(a, b, c | d) = P(a | d) * P(b | d) * P(c | d)

From the given relationships, we can infer the following:

P(a, b | d) = P(a | d) * P(b | d)
P(a, c | d) = P(a | d) * P(c | d)
P(b, c | d) = P(b | d) * P(c | d)

Now, we can substitute the individual conditional probabilities from the given relationships into the expression for the joint probability distribution:

P(a, b, c | d) = P(a | d) * P(b | d) * P(c | d)

Since the joint probability distribution of a, b, and c given d can be factored into the product of their individual conditional probability distributions, a, b, and c are conditionally independent given d.

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Answer: 9.2

Step-by-step explanation:

Pythagorean theorem = A^2+B^2=C^2

x^2+6^2=11^2…. Putting the equation into math-way. com

x=9.2159444

Rounded 9.2

Answer:

Assuming that the distribution of section scores is still approximately normal with a mean of 500 and a standard deviation of 100, we can use the empirical rule (also known as the 68-95-99.7 rule) to estimate the probability that a randomly-selected student gets a section score of 700 or better.

According to the empirical rule, approximately 68% of the scores fall within one standard deviation of the mean, approximately 95% of the scores fall within two standard deviations of the mean, and approximately 99.7% of the scores fall within three standard deviations of the mean.

To estimate the probability of getting a section score of 700 or better, we need to find the proportion of scores that are more than two standard deviations above the mean.

Z-score = (X - μ) / σ = (700 - 500) / 100 = 2

From the standard normal distribution table, we find that the proportion of scores that are more than 2 standard deviations above the mean is approximately 0.0228.

Therefore, the estimated probability that a randomly-selected student gets a section score of 700 or better is about 0.0228, or 2.28%.

Step-by-step explanation:

The equation of the line that passes through the points (-7,5) and (0,7) is equals to [tex] y = \frac{2}{7} x + 7 [/tex] and in point-slope form 7( y - 5) = 2( x +7).

The equation of a straight line is y = mx+ c, where, m is slope of line

Point-slope form of equation of line is written as y – y₁ = m(x – x₁), where

We have a line that passes through the points say A(-7,5) and B(0,7). We have to write an equation of line in point-slope form. Now, slope of line, [tex]m = \frac{ y_2 - y_1}{x_2- x_1}[/tex]

here, x₁ = -7, y₁ = 5, x₂ = 0, y₂ = 7

=> [tex]m = \frac{ 7 - 5}{0 + 7}[/tex]

[tex]= \frac{2}{7}[/tex]

Using the point slope equation of a line passes through A(-7,5) and B(0,7) is y – y₁ = m(x – x₁).

Substitute all known values, [tex]y - 5 = \frac{2}{7}( x + 7) [/tex]

Cross multiplication, 7( y - 5) = 2( x +7)

=> 7y - 35 = 2x + 14

=> 7y = 2x + 14 + 35

=> 7y = 2x + 49

=> [tex] y = \frac{2}{7} x + 7 [/tex]

Hence, required equation is [tex] y = \frac{2}{7} x + 7 [/tex] but in point slope form 7( y - 5) = 2( x +7).

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80% of the time it takes more than 7.52 minutes to find a parking space at 9 A.M.

We can solve this problem by using the inverse normal distribution. We want to find the value of x such that P(X > x) = 0.8, where X is the time it takes to find a parking space.

First, we standardize the distribution: Z = (X - μ) / σ, where μ = 5 and σ = 3. Thus, we want to find the value of z such that P(Z > z) = 0.8.

Using a standard normal distribution table or a calculator, we can find that the z-value corresponding to a cumulative probability of 0.8 is approximately 0.84.

So, we have:

0.84 = (X - 5) / 3

Solving for X, we get:

X = 0.84(3) + 5 = 7.52

Therefore, 80% of the time it takes more than 7.52 minutes to find a parking space at 9 A.M.

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Answer:

--------------------------

Area of a trapezoid formula:

We have the following values as per picture:

Substitute the given values into formula to get the area:

Hence the area of the trapezoid is 15h cm².

Answer:

15h cm²

Step-by-step explanation:

<3

From the side limits of function, f(x), [tex]\lim_{x→ 6^{+}} f(x)= \lim_{ x→6^{- }} f(x) = 2, the limit value of function f(x) when x approaches to 6, [tex] \lim_{x →6} f(x) \\ [/tex] is equals to 2. So, option (d) is right one.

In Calculus a part of mathematics, a limit is the value that a function approaches when its input approaches some other value. That f(x) be approaches L when x approaches 0 then L is called limit of f(x).

Also, limit of a function f(x) if and only if the one sided limits of the function are equal, [tex] \lim_{ x → c} f(x) = L \\ [/tex] iff

[tex] \lim_{ x → c^- } f(x) = \lim_{ x → c^+} f(x) = L \\ [/tex]. We have a limit function f(x) the right hand and left hand limits are defined as, [tex] \lim_{x → 6^{-}} f(x) = 2 \\ [/tex], [tex] \lim_{ x → 6^{+}} f(x) = 2\\ [/tex]

but f( 6) does not exist.

We have to determine the value [tex] \lim_{ x → 6} f(x) \\ [/tex]. From above definition of limit of a function exist, if and only if RHS and LHS limits exist and equal. Here, both RHS and LHS limits are exist and equal so, [tex]\lim_{x→ 6} f(x) = lim_{x→ 6 ^{+}}f(x) = \lim_{x → 6^{-}} f(x) = 2.\\ [/tex] Hence, required value is equals to 2.

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Complete question:

[tex] \lim_{ x -> 6^{ - } } f(x) = 2 \\ [/tex]

and

[tex]\lim_{x --> 6 ^{ + } } f(x) = 2, \\ [/tex]

but f(6) does not exist. What can you say about

[tex] \lim_{x--> 6} f(x) \\ [/tex]

?

A. Is - 2

B. Does not exist

C. Is oo

D. Is 2

C is open and neither closed nor open. C is not compact.

a. A = [-1, 1]

int(A) = (-1, 1), bd(A) = {-1, 1}, A' = [-1, 1], cl(A) = [-1, 1]

A is closed and neither open nor closed. A is compact.

b. B = {(-1)^n + h : n ∈ N}

int(B) = ∅, bd(B) = B, B' = {-1, 1}, cl(B) = B ∪ {-1, 1}

B is closed and neither open nor closed. B is not compact.

c. C = {r ∈ Q+ : r^2 < 4}

int(C) = {r ∈ Q+ : r^2 < 4}, bd(C) = {r ∈ Q+ : r^2 = 4}, C' = {r ∈ R+ : r^2 ≤ 4}, cl(C) = {r ∈ R+ : r^2 ≤ 4}

C is open and neither closed nor open. C is not compact.

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The value of equation 7x² + 9x - 3 for x= 3 is 87.

We have the equation

7x² + 9x - 3.

Now, put the value of x = 3 in the given equation we get

7x² + 9x - 3.

= 7(3)² + 9(3) - 3.

=7(9) + 27- 3

= 63 - 3 + 27

= 60 + 27

= 87

Thus, the required value is 87.

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87 will be the value of the given expression when x= 3.

To find the value of the expression 7x^2 + 9x - 3 when x=3, we substitute x=3 into the expression and simplify:

7(3)^2 + 9(3) - 3

= 7(9) + 27 - 3

= 63 + 24

= 87

Therefore, the value of the expression 7x^2 + 9x - 3 when x=3 is 87.

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