Find the measure of the arc or central angle indicated. Assume that lines which appear to bediameters are actual diameters.

Find The Measure Of The Arc Or Central Angle Indicated. Assume That Lines Which Appear To Bediameters

Answers

Answer 1

From the given circle, the measure of the arc or the central angle indicated is as shown at the center of the circle is subtended by the arc

Hence, the measure of the arc or central angle indicated is 65° ,Option B


Related Questions

I need help with this practice Having trouble solving it The subject is trigonometry

Answers

To solve the problem, we will make use of the identity:

[tex]\cos (\alpha-\beta)=\cos (\alpha)\cos (\beta)+\sin (\alpha)\sin (\beta)_{}[/tex]

ANGLE α

The angle lies in the second quadrant. The only positive ratio is the sine.

If we have that:

[tex]\tan \alpha=-\frac{12}{5}[/tex]

Displaying this on a triangle for ease of working, we have:

Therefore, the length of the hypotenuse will be:

[tex]\begin{gathered} x=\sqrt[]{12^2+5^2}=\sqrt[]{144+25}=\sqrt[]{169} \\ x=13 \end{gathered}[/tex]

Therefore, we have that:

[tex]\begin{gathered} \sin \alpha=\frac{12}{13} \\ \cos \alpha=-\frac{5}{13} \end{gathered}[/tex]

ANGLE β

This angle lies in the fourth quadrant. Only the cosine ratio is positive in this quadrant.

We are given in the question:

[tex]\cos \beta=\frac{3}{5}[/tex]

Displaying this on a triangle for ease of working, we have:

Therefore, using the Pythagorean Triplets, we have that:

[tex]y=4[/tex]

Therefore, we have that:

[tex]\sin \beta=-\frac{4}{5}[/tex]

SOLVING THE IDENTITY

Applying the identity quoted earlier, we have:

[tex]\begin{gathered} \cos (\alpha-\beta)=\cos (\alpha)\cos (\beta)+\sin (\alpha)\sin (\beta)_{} \\ \cos (\alpha-\beta)=(-\frac{5}{13})(\frac{3}{5})+(\frac{12}{13})(-\frac{4}{5}) \\ \cos (\alpha-\beta)=-\frac{63}{65} \end{gathered}[/tex]

Fine all the missing side lengths and angle measured of each triangle.

Answers

Answer:

[tex]\begin{gathered} AT=8\sqrt[]{3} \\ AC=8 \\ mStep-by-step explanation:

To find the missing lengths of the triangle, use trigonometric ratios for right triangles, which are represented by the following equations:

[tex]\begin{gathered} \sin (\text{angle)=}\frac{\text{ opposite}}{\text{ hypotenuse}}_{} \\ \cos (\text{angle)}=\frac{\text{adjacent}}{\text{hypotenuse}} \\ \tan (\text{angle)}=\frac{\text{ opposite}}{\text{ adjacent}} \end{gathered}[/tex]

Then, find the opposite and adjacent side given the 60 degrees angle:

[tex]\begin{gathered} \sin (60)=\frac{AT}{16} \\ AT=16\cdot\sin (60) \\ AT=8\sqrt[]{3} \\ \\ \cos (60)=\frac{AC}{16} \\ AC=16\cdot\cos (60) \\ AC=8 \end{gathered}[/tex]

Now, since the intern angles of a triangle must add up to 180 degrees, given two of the angles find the missing angle:

[tex]\begin{gathered} m

Please help. Find value of p

Answers

The value of p from the given diagram using the similarity theorem is -13.

Similarity theorem of triangle

You can use three triangle-specific theorems to quickly distinguish similar triangles. These three theorems, known as Angle - Angle (AA), Side - Angle - Side (SAS), and Side - Side - Side (SSS), are proof methods for determining similarity in triangles.

In order to determine the value of p from the given expression, we will use the expression below;

2p-5+3p/14+26 = 3p/26

5p+5/40 = 3p/26

Cross multiply

40 * 3p = 26(5p +5)

120p = 130p + 130

120-130p = 130

-10p = 130

Divide both sides by -10 to have:

-10p/-10 = 130/-10
p = -13

This gives the required value of p from the figure.

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In gym class, a student can do 40 sit-ups in 60 seconds and 100 sit-ups in 150 seconds.

Graph the proportional relationship.

graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 60
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 60 comma 30
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 60 comma 50
graph with x axis labeled time seconds and y axis labeled sit ups, with a line from 0 comma 0 going through 90 comma 30
Question 6 (Essay Worth 4 points)

Answers

By using the linear equation y=3x we draw the graph for proportional relationship.

What is Graph?

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

A proportional relationship graph between two variables is a relationship where the ratio between the two variables is always the same

the graph of any proportional relationship is characterized by a straight line with data points passing through the origin (0, 0).

By the definition of proportional relationship of graph, we can reduce relationship between the values on the x-coordinate and y-coordinate of the given graph

As they are  proportional and represented by euation

y = 3x

Where, x represent the time and y represent the number of sit-ups.

Hence by using the linear equation y=3x we draw the graph for proportional relationship.

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What is the equation of the line that passes through the origin and is perpendicular to the line 4x+3y=6

Answers

The Equation of a Line

The slope-intercept form of a line can be written as:

y = mx + b

Where m is the slope of the graph of the line and b is the y-intercept.

In the specific case where the line passes through the origin (0,0), we can find the value of b by substituting x=0 and y=0:

0 = m(0) + b

Solving for b:

b = 0.

Thus, the equation of the line reduces to:

y = mx

We only need to find the value of the slope.

That is where we need the second data. Our line is perpendicular to the line of equation 4x + 3y = 6.

Solving for y:

[tex]y=-\frac{4}{3}x+2[/tex]

The slope of the second line is -4/3.

We must recall that if two lines of slopes m1 and m2 are perpendicular, then:

[tex]m_1\cdot m_2=-1[/tex]

Substituting the value of m1 and solving for m2:

[tex]\begin{gathered} -\frac{4}{3}\cdot m_2=-1 \\ m_2=\frac{3}{4} \end{gathered}[/tex]

The slope of our line is 3/4 and the required equation is:

[tex]y=\frac{3}{4}x[/tex]

From this last equation, we need to find the general form of the line.

Multiply both sides of the equation by 4:

4y = 3x

Subtract 3x on both sides:

4y - 3x = 0

Reorder:

-3x + 4y = 0

The graph of f(a) = > has been transformed to create the graph of g(s) =

Answers

EXPLANATION

The graph of the parent function: f(x) = 1/x has the following form:

Translating the function two units to the left, give us the Image function:

This function is obtained by adding two units to the denominator.

In conclusion, the solution is -2

9. A researcher gathered data on hours of video games played by school-aged children and young adults. She collected the following data:601241215171711409914110131015163915121698131016651717129(a) Complete the frequency distribution for the data.HoursFrequencyRelative Frequency0-23-56-89-1112-1415-17(b) Which of the following is the correct histogram for this data?246810Hours0369121518Frequency[Graphs generated by this script: setBorder(54,40,20,15); initPicture(0,18,0,10);axes(34,2,1,null,2); fill="blue"; textabs([165,0],"Hours","above");line([0,-0.2],[0,0.2]); text([0,0],"0","below");line([3,-0.2],[3,0.2]); text([3,0],"3","below");line([6,-0.2],[6,0.2]); text([6,0],"6","below");line([9,-0.2],[9,0.2]); text([9,0],"9","below");line([12,-0.2],[12,0.2]); text([12,0],"12","below");line([15,-0.2],[15,0.2]); text([15,0],"15","below");line([18,-0.2],[18,0.2]); text([18,0],"18","below");textabs([0,115],"Frequency","right",90);rect([0,0],[3,6]);rect([3,0],[6,4]);rect([6,0],[9,5]);rect([9,0],[12,7]);rect([12,0],[15,6]);rect([15,0],[18,10]);]246810121416Hours061218Frequency[Graphs generated by this script: setBorder(54,40,20,15); initPicture(0,18,0,16);axes(34,2,1,null,2); fill="blue"; textabs([165,0],"Hours","above");line([0,-0.32],[0,0.32]); text([0,0],"0","below");line([6,-0.32],[6,0.32]); text([6,0],"6","below");line([12,-0.32],[12,0.32]); text([12,0],"12","below");line([18,-0.32],[18,0.32]); text([18,0],"18","below");textabs([0,115],"Frequency","right",90);rect([0,0],[6,10]);rect([6,0],[12,12]);rect([12,0],[18,16]);]2468101214Hours061218Frequency[Graphs generated by this script: setBorder(54,40,20,15); initPicture(0,18,0,14);axes(34,2,1,null,2); fill="blue"; textabs([165,0],"Hours","above");line([0,-0.28],[0,0.28]); text([0,0],"0","below");line([6,-0.28],[6,0.28]); text([6,0],"6","below");line([12,-0.28],[12,0.28]); text([12,0],"12","below");line([18,-0.28],[18,0.28]); text([18,0],"18","below");textabs([0,115],"Frequency","right",90);rect([0,0],[6,12]);rect([6,0],[12,14]);rect([12,0],[18,12]);]2468Hours0369121518

Answers

(a)

Remember that the frequency refers to the number of times a data shows up. In this case, the frequency is the number of data that falls into each interval.la

To find the relative frequency is calculated by dividing each frequency by 38 (the total number of data).

[tex]\begin{gathered} \frac{6}{38}=0.1579 \\ \frac{4}{38}=0.1053 \\ \frac{4}{38}=0.1053 \\ \frac{8}{38}=0.2105 \\ \frac{7}{38}=0.1842 \\ \frac{9}{38}=0.2368 \end{gathered}[/tex]

Let's include the relative frequencies in the table.

On the other hand, the correct histogram has to show the frequencies in the same order. The following histogram shows the correct frequency distribution.

Timothy ran a lemonade stand for 6 days. on the first day he made $5. Each day after that he made $2 more than the previous day. How much money did Marcus make, , after the 6 days?A) $60B) $15C) $12D) $30

Answers

Step `1;

Total number of days = 6

Step 2:

First day = $5

Second day = $5 + $2 = $7

Third day = $7 + $2 = $9

Fourth day + $9 + $2 = $11

Fifth day = $11 + $2 = $13

Sixth day = $13 + $2 = $15

Step 3:

Marcus made = $5 + $7 + $9 + $11 + $13 + $15

= $60

Second method

Use the sum of nth terms of arithmetic progression.

first term a = $5

Common difference = 2

n = 6

[tex]\begin{gathered} S\text{um of the 6 terms = }\frac{n}{2}(\text{ 2a + (n-1)d)} \\ =\text{ }\frac{6}{2}\text{ ( 2}\times5\text{ + (6 -1) }\times\text{ 2)} \\ =\text{ 3( 10 + 5}\times2\text{ )} \\ =\text{ 3( 10 + 10 )} \\ =\text{ 3 }\times\text{ 20} \\ =\text{ \$60} \end{gathered}[/tex]

Final answer

Marcus made = $60 Option A

Find the 1st term, last term and the sum for the finite arithmetic series.

Answers

Answer:

Given that,

[tex]\sum ^{30}_{n\mathop=2}(3n-1)[/tex]

Simplifying we get,

[tex]\sum ^{30}_{n\mathop{=}2}(3n-1)=\sum ^{30}_{n\mathop{=}2}3n+\sum ^{30}_{n\mathop{=}2}1[/tex][tex]=3\sum ^{30}_{n\mathop{=}2}n+\sum ^{30}_{n\mathop{=}2}1[/tex]

we have that,

[tex]\sum ^n_{n\mathop=1}1=n[/tex]

If n is from 2 to n we get,

[tex]\sum ^n_{n\mathop{=}2}1=n-1[/tex]

Also,

[tex]\sum ^k_{n\mathop=1}n=\frac{k(k+1)}{2}[/tex]

If n is from 2 to n we get,

[tex]\sum ^k_{n\mathop=2}n=\frac{k(k+1)}{2}-1[/tex]

Using this and substituting in the required expression we get,

[tex]=3\lbrack\frac{30\times31}{2}-1\rbrack+30-1[/tex][tex]=3(464)+29[/tex][tex]=1421[/tex]

Answer is: 1421

Find the interval in the line below. Use correct symbols to indicate in interval notation. If number is no an integer then round to the nearest hundredth.

Answers

we can see the interval is between -2 and 1. but the -2 isn't included (you can notice by the white circle) and the 1 is included, so in interval notation you get:

(-2,1]

A cake is cut into 12 equal slices. After 3 days Jake has eaten 5 slices. What is his weekly rate of eating the cake?
5
36
35
36
cakes/week
cakes/week
1 cakes/week
35
01 cakes/week

Answers

The cake is divided into 12 equal slices. Jake had eaten 5 slices after 3 days. The weekly cake consumption rate is 11.6

What is algebraic expression?An algebraic expression is one that is composed of integer constants, variables, and algebraic operations. 3x2 2xy + c, for example, is an algebraic expression. Algebraic expressions have at least one variable and one operation (addition, subtraction, multiplication, division). 2(x + 8y) is an algebraic expression, for example. An algebraic expression is one that contains constants, variables, and algebraic operations. 3x2 2xy + d, for example, is an algebraic expression. Thus, an algebraic expression is composed of three types of fundamental elements: Coefficient (i.e. numbers) (i.e. numbers)

Therefore,

The weekly cake consumption rate is 11.6

we have 7 days.

7days-3days =4

in 3 days he has eaten 5 slices

again 4-3 days=1

so in 6 days, he has eaten 10 slices

we have 1 day left.so if he eats 5 slices in 3 days, how many does he eat slices in 1 day?

5/3=1.6

10+1.6= 11.6

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All changes saved16. Suppose you invest $7500 at an annual Interest rate of 4.2% compounded continuously. How much will you have in the account after 2 years? Round the solution to the nearest dollar.$8158$17,372$17,373$8157

Answers

We have to use the continuous compound interest formula

[tex]A=P\cdot e^{rt}[/tex]

Where P = 7500, r = 0.042, t = 2. Let's replace and solve

[tex]\begin{gathered} A=7500\cdot e^{0.042\cdot2} \\ A\approx8,157 \end{gathered}[/tex]Hence, the answer is $8,157.

Lesson 6.07: In a random sample of 74 homeowners in a city, 22 homeowners said they wouldsupport a ban on nonnatural lawn fertilizers to protect fish in the local waterways. The samplingmethod had a margin of error of +3.1%. SHOW ALL WORK!A) Find the point estimate.B) Find the lower and upper limits and state the interval.

Answers

Confidence interval is written in the form,

(point estimate +/- margin of error)

The given scenario involves population proportion

The formula for the point estimate is

p' = x/n

where

p' = estimated proportion of success. p' is a point estimate for p which is the true proportion

x represents the number of success

n represents the number of samples

From the information given,

n = 74

x = 22

p' = 22/74 = 0.297

The formula for finding margin of error is expressed as

[tex]\begin{gathered} \text{margin of error = z}_{\frac{\alpha}{2}}(\sqrt[]{\frac{p^{\prime}q^{\prime}}{n}} \\ q^{\prime}\text{ = 1 - p'} \\ q^{\prime}\text{ = 1 - 0.297 = 0.703} \end{gathered}[/tex]

A) The point estimate is 0.297

B) margin of error = +/-3.1% = 3.1/100 = +/- 0.031

Thus,

the lower limit would be 0.297 - 0.031 = 0.266

Expressing in percentage, it is 0.266 x 100 = 26.6%

the upper limit would be 0.297 + 0.031 = 0.328

Expressing in percentage, it is 0.328 x 100 = 32.8%

Thus, the confidence interval is between 26.6% and 32.8%

Through (1,-2) parallel to y=-2x+5

Answers

Answer:

Step-by-step explanation:The line parallel to y = -2x + 5 that passes through the point(1,1)

Has the same slope, m but a different y intercept (0,b)

So lets start by using the given point (1, 1) and the slope intercept form of the line to calculate b

y = mx + b

m = -2

1 = -2(1) + b

1 = -2 + b

Add 2 to both sides of the equation to solve for b

1 + 2 = b

3 = b

The line is

y = -2x + 3

If I am in San Juan, then
I am in Puerto Rico.
State whether the following
statement is inverse, converse,
contrapositive.
If I am not in San Juan,
then I am not in Puerto
Rico.

Answers

The statement "If I am not in San Juan, then I am not in Puerto Rico." is the inverse and contrapositive statement because it is inverse of "If I am in San Juan, then I am in Puerto Rico."

What is inverse?

The inverse function of a function f in mathematics is a function that reverses the operation of f. If and only if f is bijective, then the inverse of f is true. A function that "undoes" another function is called an inverse. In other words, if f(x) produces y, then y entered into the inverse of f produces x. An invertible function is one that has an inverse, and the inverse is represented by the symbol f⁻¹.

What is contrapositive?

When you reverse the hypothesis and the conclusion in a statement and reject both of them, you have a contrapositive statement. When the hypothesis and the conclusion are switched in this example and both are negated, the outcome is: If it is not a triangle, then it is not a polygon.

Here,

The statement is "If I am in San Juan, then I am in Puerto Rico."

So the contrapositive and inverse will be:

"If I am not in San Juan, then I am not in Puerto Rico."

Because it is the opposite of "If I am in San Juan, then I am in Puerto Rico," the statement "If I am not in San Juan, then I am not in Puerto Rico" is the inverse and contrapositive statement.

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Using this formula and other formulas, find Q1,Q2, Q3 the midquartile, and the interquartile range for the data set.51, 62, 73, 92, 97, 100, 104

Answers

Given:

The given set of data is 51, 62, 73, 92, 97, 100, 104.

The objective is to find Q1,Q2, Q3 the midquartile, and the interquartile range.

Explanation:

The given set of data is already arranged in increasing oder.

To find Q2:

The quartile Q2 represents the middle term of the set of data arranged in increasing order.

The number of terms in the set of data is N = 7.

Then, the middle term of the set of data is 92, which is Q2.

To find Q1:

The quartile 1 represents the middle term of the left side of the Q2.

The left side of Q2 contains 51, 62, 73.

Thus, the middle term of the left side of Q2 is 62, which is Q1.

To find Q3:

The quartile 3 represents the middle temr of the right side of the Q2.

The right side of Q2 contains 97, 100, 104.

Thus, the middle term of the right side of Q2 is 100, which is Q3.

To find midquartile:

The midquartile is termed as the average of highest and lowest value of the set of data.

The highest value in the given set of data is 104 and the lowest value in the given set of data is 51.

Then, the midquartile can be calculated as,

[tex]\begin{gathered} \text{Midquartile}=\frac{104+51}{2} \\ =77.5 \end{gathered}[/tex]

To find interquartile:

The

D is the midpoint of AC, BA ≅BC and ∠EDA ≅ ∠FDC. Prove ΔAED ≅ ΔCFD

Answers

We are asked to prove that triangles AED and CFD are congruent. To do that we will prove that we can use the ASA (Angle Side Angle) rule of congruency.

First, we are given that D is a midpoint of segment AC, therefore:

[tex]\bar{AD}=\bar{AC}[/tex]

Also, we are given that:

[tex]\bar{BA}=\bar{BC}[/tex]

This means that triangle ABC is an isosceles triangle and therefore, its base angles are equal. This means that:

[tex]\angle BAC=\angle BCA[/tex]

And, since we are given that angles EDA and FDC are equal, then by ASA we can conclude that:

[tex]\Delta AED\cong\Delta CFD[/tex]

A function can have miltiple x intercepts A function can have multiple y intercepts To find the y intercept you must find the zeros The notation of the Zeros of the function is f(0)

Answers

The statements which are true regarding a function among the given answer choices are;

A function can have multiple x-intercepts.The notation of the zeroes of the function is; f(0).

Which statements among the answer choices are true for functions?

It follows from the complete task content that the statements which are true be identified from the given answer choices.

From the definition of a function; A function is a relation which assigns to every input value one single output value. Hence, it follows that no single input value has more than one output value assigned to it.

It therefore follows from the definition above that; a function can have multiple x-intercepts, but can only have one y-intercept.

Also, the zeroes of the function are represented by the function instance; f(0) at which point the input, x = 0.

Remarks;

The complete task content is such that; The statements which are correct about functions are to.be identified.

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l show how the distributive property can make the arithmetic simpler in the following problems5(108)

Answers

Firstly Example of Distributive property can be shown below.

GIiven: 6(9 - 4)

6 x 9 - 6 x 4

54 - 24 = 30

a) 3(50.15)

3(50 + 0.15)

3x50 + 3 x0.15

150 + 0.45 = 150.45

(b) 5(108)

5(100 + 8)

5x100 + 5x8

500 + 40 = 540

If sin A = 3/5 and cos B = 20/29 and angles A and B are in Quadrant 1, find the valueof tan(A + B).

Answers

Our approach is to use SOHCAHTOA to derive values for sine and cosines of both A and B.

[tex]\begin{gathered} \sin A=\frac{3}{5},\text{ cosA=}\frac{\sqrt[]{5^2-3^2}}{5}=\frac{4}{5} \\ \cos B=\frac{20}{29},\text{ sinB=}\frac{\sqrt[]{29^2-20^2}}{29}=\frac{21}{29} \end{gathered}[/tex][tex]\begin{gathered} \tan (A+B)=\frac{\tan A+\tan B}{1-\text{tanAtanB}}\text{ WHERE} \\ \tan A=\frac{\sin A}{\cos A},\tan B=\frac{\sin B}{\cos B} \end{gathered}[/tex][tex]\begin{gathered} \tan (A+B)=\frac{\frac{\frac{3}{5}}{\frac{4}{5}}+\frac{\frac{21}{29}}{\frac{20}{29}}}{1-\frac{\frac{3}{5}}{\frac{4}{5}}\times\frac{\frac{21}{29}}{\frac{20}{29}}}=\frac{\frac{3}{4}+\frac{21}{20}}{1-\frac{3}{4}\times\frac{21}{20}}=\frac{\frac{9}{5}}{1-\frac{63}{80}}=\frac{\frac{9}{5}}{\frac{17}{80}} \\ \tan (A+B)=8.47 \end{gathered}[/tex]

tan (A+B) = 8.47

find the intercepts and graph the equation by plotting points. 13^2 + 4y = 52

Answers

ANSWER

[tex]y-intercept:(0,-\frac{117}{4})[/tex]

Graph:

EXPLANATION

Given:

[tex]13^2+4y=52[/tex]

Desired Results:

Intercepts and graph the equation

Solve for y

[tex][/tex]

Help me due is tomorrow

Answers

Step-by-step explanation:

5.3g+9=2.3g+15

5.3g-2.3g=15-9

3g=6

3g/3=6/3

g=2

B,5.3(2)+9=2.3(2)+15

10.6+9=4.6+15

19.6=19.6

Answer:

g = 2

Step-by-step explanation:

5.3g + 9 = 2.3g + 15

Subtract 9 from both sides.

5.3g + 9 - 9 = 2.3g + 15 - 9

5.3g = 2.3g + 6

Subtract 2.3g from both sides

5.3g - 2.3g = 2.3g - 2.3g + 6

3g = 6

Divide both sides by 3

g = 2

To check if the value of g is correct, substitute the value of g in the equation above and remember that the both sides should be equal because of the equal sign (=) in the equation.

5.3g + 9 = 2.3g + 15

5.3(2) + 9 = 2.3(2) + 15

10.6 + 9 = 4.6 + 15

19.6 = 19.6

11 gallons Blue Car 2 of gas 35.4 miles A gallons 27 miles Silver Car 5 14. You are running a fuel economy study. You want to find out which car can travel a greater distance on 1'gallon of gas. a. What is the gas mileage, in miles per gallon, for the blue car? b. What is the gas mileage, in miles per gallon, for the silver car? c. Which car could travel the greater distance on 1 gallon of gas?

Answers

Answer:

a) 23.67 miles per gallon

b) 34 miles per gallon

c) The silver car could travel a greater distance.

Step-by-step explanation:

a)

Conversion of the mixed numbers to fractions:

[tex]1\frac{1}{2}=\frac{1\ast2+1}{2}=\frac{2+1}{2}=\frac{3}{2}[/tex][tex]35\frac{1}{2}=\frac{35\ast2+1}{2}=\frac{70+1}{2}=\frac{71}{2}[/tex]

Gas mileage:

3/2 gallons - 71/2 miles

1 gallons - x miles

Simplifying the top line by 2.

3 gallons - 71 miles

1 gallon - x miles

3x = 71

x = 71/3

x = 23.67 miles per gallon

b)

Conversion of the mixed number to fraction:

[tex]27\frac{1}{5}=\frac{27\ast5+1}{5}=\frac{135+1}{5}=\frac{136}{5}[/tex]

Mileage:

4/5 gallons - 136/5 miles

1 gallon - x miles

Simplifying the top line by 5

4 gallons - 136 miles

1 gallon - x miles

4x = 136

x = 136/4

x = 34 miles per gallon

c)

Blue car: 23.67 miles per gallon

Silver car: 34 miles per gallon

Silver car could travel a greater distance.

Identify the range of the function shown in the graph. 10 8 4 -10-8-4-2 8 10 O A. -2< y < 2 O B. {-2, 2) O C. y is all real numbers OD. Y > 0

Answers

Answer

Option B is correct.

Range: y is all real numbers.

Explanation

The range of a function refers to the region of values where the function can exist. It refers to the values that the dependent variable [y or f(x)] can take on. It is the region around the y-axis that the graph of the function spans.

For this question, we can see that the graph spans over the entire y-axis.

Hence, the range of this function shown in the graph is all real number.

Hope this Helps!!!

The probability that John recieves junk mail is 11 percent. If he receives 94 pieces of mail in a week, about how many of them can he expect to be junk mail.a. 5 b. 15 c. 10 d.20

Answers

10 (option C)

Explanation:

The probability of getting a junk mail = 11%

Number of mails received = 94

Amount that will be junk mail = The probability of getting a junk mail × Number of mails received

Amount that will be junk mail = 11% × 94

= 0.11 × 94 = 10.34

Since we can't have decimal number of mails, we would approximate to the nearest whole number

10.34 to the nearest whole number is 10

Hence, 10 junk mails are expected

The table gives a set of outcomes and their probabilities. Let A be the event the outcome is divisible by 3". Find P(A). 12 Outcome Probability Tim elaps 1 0.14 PAUS 2 0.02 3 0.19 Smart out of 4 0.01 5 0.04 7 6 0.17 7 0.15 8 0.28

Answers

Here, we want to get the probability that a selected outcome is divisible by 3

What we have to do here is ti select numbers that are multiples of 3 and add their probabilities

From the given table, the outcomes that are multiples of 3 are;

3 and 6 only

So, we proceed to add the probabilities of these outcomes

Mathematically, we have this as;

[tex]P(A)\text{ = 0.19 + 0.17 = 0.36}[/tex]

Which choice is equivalent to the quotient shown here for acceptablevalues of x?25(x - 1) = 5(x - 1)?A.5(x - 1)B. 125(x - 1)C. V25(x - 1) -5(x - 1)?D. V5(x - 1)SUBMIT

Answers

Given the expression:

[tex]\sqrt[]{28(x-1)}\div\sqrt[]{8x^2}[/tex]

[tex]\frac{\sqrt[]{28(x-1)}}{\sqrt[]{8x^2}}[/tex]

Let's determine the inequality that represents all the values of x.

Here, we are to find the domain.

Let's solve for x.

Set the radicand in the numerator and denominator to be greater or equal to zero.

We have:

[tex]\frac{28(x-1)\ge0}{8x^2\ge0}[/tex]

For the numerator, we have:

[tex]\begin{gathered} 28(x-1)\ge0 \\ \text{Divide both sides by 28:} \\ \frac{28(x-1)}{28}\ge\frac{0}{28} \\ \\ x-1\ge0 \\ \text{Add 1 to both sides:} \\ x-1+1\ge0+1 \\ x\ge1 \end{gathered}[/tex]

For the denominator, we have:

[tex]\begin{gathered} 8x\ge0 \\ x\ge\frac{0}{8} \\ x\ge0 \end{gathered}[/tex]

Therefore, the possible x-values for which the quotient is defined is all positive integers greater or equal to 1.

Thus, we have:

[tex]x\ge1[/tex]

ANSWER:

[tex]C.x\ge1[/tex]

Determine a third pair of congruent parts to establish congruence between the triangles. Give the congruence postulate involved

Answers

In this problem, we have that

mYO ≅ XO

The third pair of congruent parts is

m by vertical angles

therefore

triangle YOT ≅ triangle XOB ----> by ASA congruence postulate

please help me ASAP!!!

Answers

[tex]f(x)=\sqrt[]{2x^2-3x+\text{ 1}}[/tex]

substitute x = 5 in the above function

[tex]f(5)=\sqrt[]{2(5)^2-3(5)+1}[/tex][tex]=\sqrt[]{2(25)-15+1}[/tex][tex]=\sqrt[]{50-15+1}[/tex][tex]=\sqrt[]{36}=\text{ 6}[/tex]

f(5) = 6

What is the driving distance from the police station to an animal shelter

Answers

The coordinates of the Police station is (0, -4)

The coordinates of Animal shelter is (6,- 2)

The distance between the Police station and the Animal shelter is given by the formoula;

[tex]\begin{gathered} \text{Distance}=\sqrt[]{(x_2-x_1)^2+(y}_2_{}-y_1)^2_{} \\ \text{Distance}=\sqrt[]{(6-0)^2+(-2--4)^2}=\text{ }\sqrt[]{6^2+2^2} \end{gathered}[/tex][tex]\text{Distance}=\sqrt[]{36+4}\text{ = }\sqrt[]{40}=\text{ 6.325}\approx6.33[/tex]

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