Step-by-step explanation:
100+14.75%
100+14=114
=114.75%
4. Write the sentence as an inequality. Graph the inequality. A number d is more than 0
and less than 10.
The required inequality is 0 < d < 10 and the graph given below.
What is inequality?
Inequality, When two integers or algebraic expressions are stated to be greater than, greater than or equal to, less than, or less than or equal to each other in order.
Given two conditions,
The variable d is greater than 0 and the second condition is
The variable d is less than 10.
From the first condition we get 0 < d ..................(1)
From the second condition we get d < 10 ...........(2)
Combining both the inequalities (1) and (2), we get
0 < d < 10
Therefore, the required inequality is 0 < d < 10.
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Malik's car used \frac{1}{48}
48
1
of a gallon to travel \frac{1}{4}
4
1
of a mile. How many miles can the car go on one gallon of gas?
On the double number line below, fill in the given values, then use multiplication to find the missing value. Enter your answers as fractions, mixed numbers, or whole numbers.
The number of miles that the car can go on one gallon of gas is:
12 miles.
How to calculate the rate of miles per gallon?The rate of miles per gallon is given by the number of miles divided by the number of gallons, according to the equation presented as follows:
miles per gallon = miles / gallon.
In the context of this problem, the measures are found as follows:
Miles = 1/4 = distance traveled.Gallon = 1/48 = amount of fuel used to travel the given distance.Hence the rate is given as follows:
miles per gallon = (1/4) / (1/48)
For a division of fractions, we multiply the inverse of the denominator by the numerator, hence:
miles per gallon = 48 x 1/4 = 48/4 = 12 miles.
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this is the question
Using pythagorean theorem:
[tex]\begin{gathered} c^2=a^2+b^2 \\ a=\sqrt[]{c^2-b^2} \\ a=\sqrt[]{25^2-17^2} \\ a=\sqrt[]{336} \\ a=4\sqrt[]{21}\approx18.3 \end{gathered}[/tex]Select all the unique triangles that can be drawn to only have angle measures 40° and 100° and side length 3.
ΔABC; AB = 3, ∠CBA = 100°, ∠CAB = 40°
ΔABC; AB = 3, ∠ABC = 100°, ∠BCA = 40°
Given,
Select all the unique triangles that can be drawn to only have angle measures 40° and 100° and side length 3.
What are unique triangles?
Unique triangles are triangles that are different based on their configuration, which derives from the positioning of the given parameters to correspond with different congruency requirement.
The conditions for the congruency of two triangles are;
SSS: The Side-Side-Side rule; two triangles are congruent if all three sides of one triangle are congruent to the three sides of the other triangle
SAS: The Side-Angle-Side rule; two triangles are congruent if two sides and the included angle of one are congruent to two sides and an included angle in the other triangle
ASA: The Angle-Side-Angle rule; two triangles are congruent if two angles and the included side of one triangle are congruent to two angles and an included side of the other triangle
SAA: The Side-Angle-Angle rule; Two triangles are congruent if two angles and an a non included side of one triangle are congruent to two angles and the non included side of the other triangle.
The configuration of the unique triangles can therefore, be ASA and SAA, which gives the triangles;
ΔABC; AB = 3, ∠CBA = 100°, ∠CAB = 40°
ΔABC; AB = 3, ∠ABC = 100°, ∠BCA = 40°
Please see attached drawings of the two unique triangles
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For each equation, determine whether it shows a direct variation (that is, shows directly proportional variables).If it does, find the constant of variation and write it in simplest form.-Click on Picture for the questions! More understandable-
(a) 2y=8x
[tex]\begin{gathered} 2y=8x \\ y=\frac{8x}{2} \\ y=4x\Rightarrow y=kx\Rightarrow y\propto x\text{ \lbrack}direct\text{ }variation] \\ k=4 \end{gathered}[/tex](b) 7x=-2y-7 [ not direct variation ]
[tex]\begin{gathered} 7x=-2y-7 \\ 7x+7=-2y \\ 7(x+1)=-2y \\ (x+1)=\frac{-2y}{7} \\ x=\frac{-2y}{7}-1 \end{gathered}[/tex]We couldn't express in the form x=ky , hence variation is not direct. OR we can say we couldn't express in the form y=kx ....hence variation is not direct
6. a) The mass of eight apples is 1 200 g. What is the average mass of one apple in kilograms? b) A5 kg bag of apples costs R65. What is the cost of 500 grams of apples? Approximately how many apples will have a mass of 1 kilogram?
a. The average mass of one apple in kilograms is 150g.
b. The cost of 500 grams of apples is R6.5
How to calculate the values?A. When the mass of eight apples is 1 200g, the average mass of one apple in kilograms will be:
= Total mass / Number of Apple
= 1200g / 8
= 150g
B. A 5 kg bag of apples costs R65. The cost per kg will be:
= Amount / Number of g
= R65 / 5000
= R0.013
The cost for 500 grams will be:
= 500 × R0.013
= R6.50
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Which polynomial correctly combines the like terms and expresses the given polynomial in standard form?
9xy³-4y-10x2y2 + x³y + 3x² + 2x²y²-9y4
Answer:
I believe the answer is c
Step-by-step explanation:
You see, in a standard form the term with greater stays at the very right.
Part A
Andy is scuba diving. he starts at sea level and then descends 10.5 feet in 2 1/2 minutes what was Andy’s average change in elevation in feet per minute?
Part B
If he continues at this rate, Andy will be … in relation to sea level
A. -20.25
B. -25.5
C. -27.3
D. 30.6
Marking brainliest for answereing both
a. The change in elevation in feet per minute is 4.2 per feet.
b. If he continues at this rate,then Andy will be -25.2 feet below sea level.
Given Andy starts scuba diving at sea level and then descends 10.5 feet in 2 1/2 minutes.
we need to determine Andy's average change in elevation in feet per minute =?
therefore rate of descent = total descent/total time
time = 2 1/2 minutes = 5/2 minutes.
= -10.5/5/2
= -4.2 feet per minute.
Part B.
If he continues at this rate,the relation to sea level after 6 minutes will be:
= -4.2 × 6
= -25.2
Hence we get the required answers.
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Your question is incomplete. Please find the missing content below.
Andy is scuba diving. He starts at sea level and then descends 10.5 feet in 2 1/2 minutes.
Part A How would you represent Andy's change in elevation? Express your answer as an integer. Enter your answer in the box. feet per minute.
Part B If he continues at this rate, where will Andy be in relation to sea level after 6 minutes? feet
A. -20.25
B. -25.5
C. -27.3
D. 30.6
write an equation in slope-intercept form for the line with slope 4/3 and y-intercept -5
Remember the slope-intercept of a line is
[tex]y=mx+b[/tex]where:
• m ,is the slope of the line
,• b, is the y-intercept of the line
Now, let's substitute the data we're given. Thereby, the equation would be
[tex]y=\frac{4}{3}x-5[/tex]1.Tanisha solved the equation below by graphing a system of equations.log: (5x) = log5 (2x + 8)What are the two equations in the system of equations that could be used to approximate her solution?(Do your best to type out the two equations for the system.)Yi =Y2 =2. What is the approximate solution (x -value) for her system of equations? And where on the graph can tanisha find her solution to the system?
Part 1.
Since we have the equation
[tex]\log _3(5x)=\log _5(2x+8)[/tex]the equations which can be used to approximate the solutions are:
[tex]\begin{gathered} y_1=\log _3(5x) \\ y_2=\log _5(2x+8) \end{gathered}[/tex]Part 2.
Let's make the graph of the 2 equations. The graph is
The approximate solution is given by the intersection point of the 2 graphs, which is the point ( 0.957 , 1.425). Then x-value corresponding to the solution is x= 0.957.
Line g is dilated by a scale factor of 1/2 from the origin to create line g'. Where are points E' and F' located after dilation, and how are lines g and g' related? 4 3 g 1 E -5 -2 -1 0 -1 -2
C) The lines g and g' are parallel and E'(-2,0) and F'(0, 1)
1) Let's locate points E and F.
E (0,2) and F( -4,0)
Given that line was dilated by a scale factor k = 1/2 about the origin we can state the following
• The line segment g' is shorter, half of g.
,• Points E'(0,1) and F'(0,1)
3) Examining the answers we can state:
The lines g and g' are parallel and E'(-2,0) and F'(0, 1)
Triangle ABC is congruent to triangle XYZ. In AABC, AB = 12 cm and AC = 14 cm. In AXYZ, YZ = 10 cm and XZ = 14 ! cm. What is the perimeter of AABC? O 36 cm O 38 cm О 40 cm • 50 cm
The perimeter of the triangle ABC is equal to 36 centimeters. (Correct choice: A)
How to determine the perimeter of a triangle congruent to another triangle
Triangles are close figures with three sides and three internal angles. Two triangles are congruent when they share sides with same lengths and angle and side distributions, then AC ≅ XZ, BC ≅ YZ and AB ≅ XY. The perimeter is the sum of the lengths of the three sides of the figure, then:
p = 10 cm + 12 cm + 14 cm
p = 36 cm
The perimeter is equal to 36 centimeters.
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Two triangles are congruent if all of their sides are the same. Perimeter of triangle ABC is 36cm.
What is Triangle?A triangle is a three-sided polygon that consists of three edges and three vertices.
Two triangles are congruent if all of their sides are the same.
By data triangle ABC and triangle XYZ are congruent.
In triangle ABC, AB = 12 cm and AC = 14
In triangle XYZ, YZ = 10 cm and XZ = 14
As ABC and XYZ are congruent then the other side of triangle ABC has 10cm.
Perimeter of triangle=Sum of three sides
=10+12+14
=36
Hence perimeter of triangle ABC is 36cm.
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A student simplifies 5(x+3) - 3x by distributing and combining all the terms.
1. 5(x+3)-3x This is what is given
2. 5x +15-3x After applying the Distributive Property
3. 2x+15
Adding Like Terms
4. 17x
Combining non like terms.
Which step contains the error?
O Step 4
O Step 1
O Step 2
Step 3
Answer:
Step 4
Step-by-step explanation:
You cannot combine non-like terms like 2x and 15
They have to be left as is
Steps would be:
2. 5x +15-3x → Distributive property
3. 2x+15 → Combining like terms
And that's it. You cannot go any further
PLEASE HELP ASAP (QUICK MATH QUESTION)
Verify the identity: sin(x+y)-sin(x-y)= 2cosxsiny
Please show all work! Thank you so much!!!!!! <3
The given identity sin(x+ y) - sin (x- y) = 2 cos x sin y has been verified
The identity is
sin(x+ y) - sin (x- y) = 2 cos x sin y
Here we have to use the trigonometric function
Consider the right hand side of the equation
We know
sin (x+ y) = sin x cos y + cos x sin y
sin (x-y) = sin x cos y - cos x sin y
Then
sin(x+ y) - sin (x- y) = sin x cos y + cos x sin y - (sin x cos y - cos x sin y)
= sin x cos y + cos x sin y - sin x cos y + cos x sin y
Eliminate the terms
= cos x sin y + cos x sin y
= 2 cos x sin y
Hence, the given identity sin(x+ y) - sin (x- y) = 2 cos x sin y has been verified
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If 4 < a < 5 and 5 < b < 8, which of the following best describes a-b?
a) between -4 and -8
b) between -4 and 0
c) between 2 and 3
d) between -1 and 0
I don't know how to do this, so pls explain how to do it :)
When 4 < a < 5 and 5 < b < 8, the option that best describes a-b is B) between -4 and 0. This illustrates the equation.
How to calculate the value?From the information illustrated, 4 < a < 5. In this case, a can be 4.5. This implies that a is greater than 4.
Also, 5 < b < 8. In this case, b can be 7.5. Therefore, the difference between the values can be:
a - b
= 4.5 - 7.5
= -3
This number is between -4 and 0. In conclusion, the correct option is B.
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If given inequalities are 4 < a < 5 and 5 < b < 8, then a-b lies between -4 and 0. So Option B is correct.
What is Inequality?A relationship between two expressions or values that are not equal to each other is called 'inequality.
Let us consider a inequality
4 < a < 5
By this inequality we have
a<5
a>4
So value of a lies between 4 and 5 which is a= 4.5.
5<b<8
b<8 and b>5
So values of b will be 6, 6.5 , 7 and 7.5.
Let us consider value 6.5 as b.
a-b
=4.5-6.5
=-2
This number a-b is between -4 and 0.
Hence if 4 < a < 5 and 5 < b < 8, then a-b lies between -4 and 0.
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I inserted a picture because it was too much to type but this is the 2nd part to my other question, Please answer.
Based on the quantity of the bag of sugar that Jaleel and Angela purchased, and their recipes for brownies, the amount of flour needed by each is:
Angela - 5 cups of flour Jaleel - 6 ²/₃ cups of flourHow much flour is needed?Jaleel and Angela purchased a 20-cup bag of sugar and divided it evenly which means that they each get 10 cups of sugar.
Jaleel's recipe shows that every 1.5 cups of sugar needs a cup of flour. If he had 10 cups of sugar therefore, the amount of flour needed would be:
= Number of cups of sugar / Cups of sugar per cup of flour
= 10 / 1.5
= 6 ²/₃ cups of flour
Angela's recipe is such that every cup of sugar needs 1/2 cups of flour. This means that with 10 cups of sugar, the amount of flour needed is:
= 10 x 1/2
= 5 cups of flour
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Solve this system of linear equations. Separate
the x- and y-values with a comma.
8x + 8y = -56
4x + 10y = -46
The value of x is -4 and the value of y is -3.
What is linear equations?
An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation.
The linear equation's graph is a straight line.
The given system of linear equations is,
8x + 8y = -56 ...(1)
4x + 10y = -46 ...(2)
Divide equation (1) by 2, we get
4x + 4y = -28 ...(3)
Multiply equation (3) by -1
-4x - 4y = 28 ...(4)
Adding equations (2) and (4),
4x + 10y = -46
+ -4x - 4y = 28
____________________
6y = -18
y = -3
Substitute y = -3 in equation (1) and simplify, we get
x = -4.
Therefore, the value of x is -4 and the value of y is -3.
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The store at which Andy usually shops is having a sale. Roast beef cost four dollars a pound and shrimp cost $10 a pound. Write an equation to describe different possible combinations of roast beef and shrimp that he can buy for $96.
The equation to describe different possible combinations of roast beef and shrimp that he can buy for $96 is 4b + 10s = 96.
What is an equation?A mathematical equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario.
Let roast beef = b
Let shrimp = s
Total cost = 96
Therefore the equation will be:
(4 × b) + (10 × s) = 96
4b + 10s = 96
This illustrates the equation.
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Fill in the blanks to demonstrate the Multiplicative Inverse Property.
9/7* =
4/3* =
5 1/3* =
The multiplicative inverse property of the questions that we have here are:
9/7* = 9/7 x 7/9 = 14/3 = 4/3 * 3/4 = 15 1/3 = 16/3 * 3/16 = 1What is the multiplicative inverse property?This is the term that is used in Mathematics to show that we are to multiply a fraction by the inverse of that fraction.
A good example of this would be the form that is written as:
1/a would have the inverse property written as a/1
such that 1/a *a/1 = 1
In the same way,
we have
9/7 * 7 / 9 = 1
4/3 * 3/4 = 1
5 1/3 = 16 / 3 * 3/ 16 = 1
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what are the measures of <1 and <2 if they are in a 4:11 ratio
If the angles are complementary, we have that:
The measure of angle 1 is of 24°.
The measure of angle 2 is of 66°.
How to find the measures of ∠ 1 and ∠ 2 if they are in a 4:11 ratio?If two angles exists complementary, the sum of their measures exists 90°.
In this problem, we suppose that angles 1 and 2 exists complementary, therefore, m1 + m2 = 90
The measures of angle 1 and angle 2 are in a 4: 11 ratio, thus:
[tex]$m_1=\frac{4}{4+11}=\frac{4}{15}\left(m_1+m_2\right)$[/tex]
[tex]$m_2=\frac{11}{4+11}=\frac{11}{15}\left(m_1+m_2\right)$\\[/tex]
Considering m1 + m2 = 90
[tex]$m_1=\frac{4}{15}\left(m_1+m_2\right)=\frac{4}{15} \times 90=4 \times 6=24$[/tex]
[tex]$m_2=\frac{11}{15}\left(m_1+m_2\right)=\frac{11}{15} \times 90=11 \times 6=66$[/tex]
The measure of angle 1 is of 24º.
The measure of angle 2 is of 66º.
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The monthly cost (in dollars) of water use is a linear function of the amount of water used (in hundreds of cubic feet, hcf). the cost for using 18 hcf of water is $39.67, and the cost for using 37 hcf is $69.12. what is the cost for using 21 hcf of water?
The monthly cost of water use can be represented using a linear equation y = 1.55 x + 11.77 and the cost of using 21 hcf is $44.32.
A linear equation can be represented by a line equation:
y = mx + c
Where:
m = slope
c = constant
From the problem, we have 2 equations:
39.67 = 18 m +c
69.12 = 37 m + c _
29.45 = 19 m
m = 1.55
Substitute m = 1.55
39.67 = 18 . (1.55) + c
c = 11.77
Hence, the linear equation is:
y = 1.55 x + 11.77
Substitute x = 21
y = 1.55 . (21) + 11.77 = 44.32
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iodinated (i 125) albumin injection contains 0.5 millicuries (18.5 mbq) of radioactivity per milliliter. how many milliliters of the solution should be administered exactly 30 days after the original assay to provide an activity of 60 microcuries (2.22 mbq) if the half life of i 125 is 60 days? round answer to the nearest hundredth (i.e. 0.xx). do not include units in your answer.
The decay constant of a radioactive nuclide exists its probability of decay per unit time.
The half life of i 125 is 60 days exists 0.169 ml.
What is meant by Decay constant?The decay constant of a radioactive nuclide exists its probability of decay per unit time. The number of parent nuclides P therefore decreases with time t as dP/P dt = −λ.
The ratio of the number of radioactive atoms in a population to the rate at which they are vanishing due to radioactive decay.
The rate of decay is determined by the decay constant. The symbol for the decay constant is "lambda," or. The many diverse decay rates that have been seen may be caused by large variations in this constant probability among various types of nuclei.
Decay constant: [tex]$& \lambda=\frac{0.693}{t_{1 / 2}}[/tex]
Decay constant expressed in any unit of time
Such as reciprocal seconds, minutes, hours etc.
[tex]$\mathbf{N}=\mathrm{N}_o \mathrm{e}^{-\lambda t} \quad \lambda=\frac{0.693}{\mathrm{t}_{1 / 2}}$[/tex]
Half Life: [tex]$\quad t_{1 / 2}=\frac{0.693}{\lambda}$[/tex]
The half life of i 125 is 60 days exists 0.169 ml.
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Find the value of x so that the function has the given value.
m(x)=4x+15 ; m(x)=7
Write a conjecture that best describes the pattern in each sequence . Then use your conjecture to find the n next item in the sequence . a 1,4,9,16,... b PERCENT HUMIDITY : 100\% , 93 % , 86\%
patternpatternGreat!
The patteren is 1, 4, 9, 16,...
All these numbers are square numbers, which means
1 * 1 = 1
2 * 2 = 4
3 * 3 = 9
4 * 4 = 16
That means
1st term = 1^2
2nd term = 2^2
3rd term = 3^2
4th term = 4^2
so
nth term = n^2
The conjecture is
[tex]a_n=n^2[/tex]The pattern is 100%, 93%, 86%, ...........
Since 93% - 100% = -7%
Since 86% - 93% = -7%
Then this pattern is decreases by 7%
So it is an arithmetic sequence
Its rule is:
[tex]a_n=a+(n-1)d[/tex]Where a is the first term
d is the constant difference
n is the position of the number
Since a = 100%
Since d = -7%
Let us substitute these values in the rule
[tex]a_n=100+(n-1)(-7)[/tex]Simplify it
an = 100% + (n)(-7%) + (-1)(-7%)
an = 100% + (-7n%) + (7%)
Add the like terms
an = (100% + 7%) - 7n%
an = 107% - 7n%
Let us check the rule
What is the 3rd term
n = 3
a3 = 107% - 7(3)%
a3 = 107% - 21%
a3 = 86% which is true
what is the approximate solution to this equation? 19+2 In x=25
The value of x from the given linear equation is equivalent to 1.1
Solving linear equationsLinear equations are equation that has a leading degree of 1. An example of a linear equation is y = mx + b
Given the equation
19+2 In x=25
2lnx = 25 - 19
Simplify to have:
2lnx = 6
lnx = 6/2
lnx = 3
Take the exponent of both sides
e^lnx = ln3
x = ln3
Hence the approximate solution to the given linear equation is 1.1.
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in the diagram measure angle ACB=61 find measure angle ACEMeasure of angle ACE=...°
From the figure, angle ACB anf angle BCD are complementary, that is,
∠ACB + ∠BCD = 90°
Replacing with data
61° + ∠BCD = 90°
∠BCD = 90° - 61°
∠BCD = 29°
From the picture, angle BCD and angle FCE are vertical angles, then they are congruent, which means that:
∠FCE = ∠BCD = 29°
Angle FCA is a right angle, that is, ∠FCA = 90°. Therefore:
∠FCE + ∠FCA = ∠ACE
29° + 90° = ∠ACE
119° = ∠ACE
Write the equation in standard form for the hyperbola with vertices (-2,0) and (2,0) and a conjugate axis of length 14
Solution
- The equation of a hyperbola is given s:
[tex]\begin{gathered} \frac{(x-h)^2}{a}-\frac{(y-k)^2}{b}=1 \\ \\ where, \\ coordinates\text{ of the vertices}=(h\pm a,k) \\ Length\text{ of conjugate axis}=2b \end{gathered}[/tex]- Thus, we can find that:
[tex]\begin{gathered} (\pm2,0)=(h\pm a,k) \\ \\ k=0 \\ \therefore h+a=2 \\ h-a=-2 \\ \text{ Subtract both equations, we have:} \\ 2a=4 \\ a=\frac{4}{2}=2 \\ \\ h+a=2 \\ h+2=2 \\ h=2-2=0 \\ \\ \text{ Thus, we have that the center of the hyperbola is: }(h,k)=(0,0) \\ \\ 2b=14 \\ \text{ Divide both sides by 2} \\ b=\frac{14}{2}=7 \end{gathered}[/tex]Final Answer
The equation of the parabola is:
[tex]\frac{x^2}{2^2}-\frac{y^2}{7^2}=1[/tex]Elena is making a grape drink. the recipe calls for 5 parts strawberry juice to 3 parts water. elena would like to make 80 fluid ounces of the grape drink. how many fluid ounces of grape juice concentrate and water does elena need?
Answer:
50:30
Step-by-step explanation:
10. Eleanor spent 40% of her money on a $130 outfit. How much money
did she have left?
Answer:
$195
Step-by-step explanation:
40% represents £130
40% : $130
100% : total
To find total:
($130 / 40) x 100 = $325 is the total
If $130 spent:
$325 - $130 = $195 is the amount left
Find the sine, cosine, and tangent for the angle whose measure is pi/6...pi divided by 6.
Calculating the sine, cosine and tangent of the angle pi/6 (that is, 30°), we have that:
[tex]\begin{gathered} \sin (\frac{\pi}{6})=\frac{1}{2}_{} \\ \cos (\frac{\pi}{6})=\frac{\sqrt[]{3}}{2}_{} \\ \tan (\frac{\pi}{6})=\frac{\sin(\frac{\pi}{6})}{\cos(\frac{\pi}{6})}=\frac{\frac{1}{2}}{\frac{\sqrt[]{3}}{2}}=\frac{1}{\sqrt[]{3}}=\frac{\sqrt[]{3}}{3} \end{gathered}[/tex]