Find the gradients of lines A and B.​

Find The Gradients Of Lines A And B.

Answers

Answer 1

Answer:

A=4

B=-2

Step-by-step explanation:

the gradient to B is a negative coz the line is sloping downwards

Answer 2

Answer:

m (A) = 4

m (B) = - 2

Step-by-step explanation:

choose any 2 coordinates on line A to use it in the formulae

no need to do so for line B because the y-int and x-int both are clear.

Find The Gradients Of Lines A And B.

Related Questions

Gabrielle is saving money for a vacation. Each week she save $40. Let a represent the total amount of money Gabrielle saves, and let w represent the number of weeks. How much money would she save from 1 to 7 weeks?

Answers

Step-by-step explanation:

A = 40w

To Calculate how much she would get in 7 weeks

Substitute w = 7 into A = 40w

⇒ A = 40(7)

⇒ A = 280

Gabrielle would save $280 in 7 weeks

What is the simplified form of the following expression? 2 startroot 18 endroot 3 startroot 2 endroot startroot 162 endroot

Answers

The simplified form of the provided expression of 2 startroot 18 endroot +3 startroot 2 endroot startroot +162 endroot is 18√2.

What is the simplified form of an equation?

The simplified form of an equation is the simplest way of expressing the equation, by applying the required operations of mathematics.

The equation provided in the problem is,

[tex]2\sqrt{18}+3\sqrt{2}+\sqrt{162}[/tex]

Let the simplified form of the above expression is n. Thus,

[tex]n=2\sqrt{18}+3\sqrt{2}+\sqrt{162}[/tex]

Rewrite the equation to solve it further as,

[tex]n=2\sqrt{3\times3\times2}+3\sqrt{2}+\sqrt{9\times9\times2}\\n=2\sqrt{3^2\times2}+3\sqrt{2}+\sqrt{9^2\times2}[/tex]

The square of the term cancel out the square root of it. Thus,

[tex]n=2\times3\sqrt{2}+3\sqrt{2}+9\sqrt{2}\\n=6\sqrt{2}+3\sqrt{2}+9\sqrt{2}\\n=(6+3+9)\sqrt{2}\\n=18\sqrt{2}[/tex]

Thus, the simplified form of the provided expression of 2 startroot 18 endroot +3 startroot 2 endroot startroot +162 endroot is 18√2.

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4/9 x 5/6 simplest form

Answers

5/6 x 4/9 = 10/27 as a fraction form. The work for 5/6 times 4/9 as a fraction provides more insight of how to find what is 5/6 times 4/9 in fraction form and the different variations of such problems.

PLS HELP ME I WILL MARK THE BRAINLIEST

Answers

#1

First the rectangle

L=18mB=7m

Area

18(7)126m^2.

For semicircle

d=7m=>r=3.5m

Area

=πr^2/2=12.25π/2

Total area

126+2(12.25π/2)126+12.25πm^2

#2

r=15fttheta=332°=332×π/180=0.92π

Area:-

r^2\theta15^2(0.92)207ft^2

Nick and his family travel by train to New York City.
The clocks show when the train leaves the station and when it arrives in New York City.

How long is the train ride?

Answers

Answer:4:15

Step-by-step explanation:

EZ

let l be the line through A(4,-3) and B(t,-2) that is parallel to the line through P(-2,4) and Q(4,-1) find the value of t

Answers

Answer:

t = [tex]\frac{14}{5}[/tex]

Step-by-step explanation:

Parallel lines have equal slopes.

calculate the slope m of PQ and then equate the slope of AB to slope of PQ

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = P (- 2, 4 ) and (x₂, y₂ ) = Q (4, - 1 )

[tex]m_{PQ}[/tex] = [tex]\frac{-1-4}{4-(-2)}[/tex] = [tex]\frac{-5}{4+2}[/tex] = - [tex]\frac{5}{6}[/tex]

now calculate slope of AB

with (x₁, y₁ ) = A (4, - 3 ) and (x₂, y₂ ) = B (t, - 2 )

[tex]m_{AB}[/tex] = [tex]\frac{-2-(-3)}{t-4}[/tex] = [tex]\frac{-2+3}{t-4}[/tex] = [tex]\frac{1}{t-4}[/tex]

equating the slopes gives

[tex]\frac{1}{t-4}[/tex] = - [tex]\frac{5}{6}[/tex] ( cross- multiply )

5(t - 4) = - 6

5t - 20 = - 6 ( add 20 to both sides )

5t = 14 ( divide both sides by 5 )

t = [tex]\frac{14}{5}[/tex]

Please Help!
In the diagram, secant AP intersects the circle at points A and B, and secant CP intersects the circle at points C and D. The lines intersect outside the circle at point P.
What is the length of AP?
(There are no answer options you must enter the correct value)

Answers

Answer AP might be 12

Step-by-step explanation:

The length of AP when secant AP intersects the circle at points A and B, and secant CP intersects the circle at points C and D. is 12 units.

The length of AP can be found using the following steps:

Draw a radius from the center of the circle to point P.

Let the radius intersect secant AP at point E.

Since AP and PE are secant segments, they share a common external tangent at point P.

Therefore, the two triangles, APE and BPF, are similar triangles.

The ratio of corresponding sides in similar triangles is equal, so:

AP/PB = PE/PF

We know that PB = 5 and PF = 20, so:

AP/5 = PE/20

Solving for AP, we get:

AP = 5 * 20/5 = 20

The diagram shows the two similar triangles, APE and BPF. The two triangles are similar because they share a common external tangent at point P. The ratio of corresponding sides in similar triangles is equal, so we can use the ratio of AP to PB to find the length of AP.

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(ii) Two of the lights at the local stadium start flickering at 9:15 p.m. One of the lights flickers every 8
minutes and the other light flickers every 12 minutes. What time both lights flicker at the same time
again?

PLSS HELPPP

Answers

Answer:

At 9:39 they both will Flick

Step-by-step explanation:

so when the first light flicks it resets and starts counting to anthor 8 mins while the other takes 4 mins extra just keep adding till they both have same time

HELP PLEASE I NEED IT NOW.

Answers

Answer:

Below :)

Step-by-step explanation:

1) 5^2 = 25

2) 12^2 = 144

3) 9^2 = 81

4) 15^2 = 225

5) 8^2 = 64

6) 7^2 = 49

7) 20^2 = 400

8) 13^2 = 169

9) 30^2 = 900

10) 25^2 = 625

There is an isosceles triangle which is also a right triangle. Its area is 50 square inches. Find the length of the base of the triangle

Answers

Answer: 10 inches

Step-by-step explanation:

What ratio forms a proportion with 2/3?
A. 2/4 B. 3/4 C. 4/6 D. 3/2

Answers

Answer:

c

Step-by-step explanation:

because you can simplify 4/6 by 2.

2 goes into 4 twice and then 2 goes into 6 3 times

2/3

PLEASE HELP I DONT UNDERSTAND IVE BEEN TRYING FOR 15 MINS AND STILL DONT GET IT

Find the lengths of the missing sides in the triangle. Write your answers as integers or as decimals rounded to the nearest tenth. The diagram is not drawn to scale. (picture of diagram included)​

Answers

The values of the length of the missing sides of triangle is x = 7√2 and y = 7.

What are special triangles?

Special right triangles are right triangles with three determined interior angles and fixed side ratios. If one side is known in these right-angled triangles, we can find the value of the two missing sides. The 45°- 45°-90° triangle and the 30°- 60°-90° triangle are other names for the two unique right triangles. Before going further, let's review the fundamental characteristics of a right triangle.

One of the angles of a right triangle is 90 degrees, and the total of the other two angles is also 90 degrees. The triangle's hypotenuse, which is the longest side, is the side that faces the right angle.

From the given figure we observe that the two angles are 45 degree and 90 degree.

Using the angle sum property we have:

45 + 90 + third angle = 180

third angle = 45 degrees.

The triangle is thus a 45-45-90 triangle.

The sides of 45-45-90 triangle correspond to the lengths as x : x : x√2.

Here, the angle corresponding to 45 is 7.

Thus, y = 7 and x = 7√2.

Hence, the values of the length of the missing sides of triangle is x = 7√2 and y = 7.

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. A sample of bacteria cells in a petri dish increases by 50% every hour. A scientist
starts with a sample of 30 bacteria cells. Write an equation that can be used to
determine the number of cells after x hours.

2. how many bacteria cells will be present in the dish after 3 hours?


3.how many bacteria cells will be present after 12 hours?

Answers

Answer:

you first divide fifty out of one hundred then we multiply it by thirty

The radius of a semicircle is 4 miles. What is the semicircle's area?

Answers

Answer:

8[tex]\pi[/tex] miles or 25.133 miles

Step-by-step explanation:

your radius is 4 miles.

The area of a circle is A= [tex]\pi r^{2}[/tex]

Therefore, the area of this circle is [tex]4^{2} \pi[/tex], or 16[tex]\pi[/tex]

Half of this area, because what you're looking for is a semi-circle, is:

8[tex]\pi[/tex] (exact) or 25.133 (rounded) miles.

– Using the order of operations, which operation should you perform last to evaluate this expression? (1 x 2.5) + (52-13) + (6.7 - 5) - (98+8) A Addition B Subtraction © Multiplication D Division​

Answers

Considering the order of operations, the operation that should be performed last is given by:

B Subtraction.

What is the order of operations?

The operations inside the parenthesis take precedence over every operation. Then, multiplication/division take precedence over sum/subtraction. If there are only multiplication/division or sum/subtraction, the precedence is from left to right.

In this problem, the expression is:

(1 x 2.5) + (52-13) + (6.7 - 5) - (98+8)

Solving the operations inside the parenthesis, the expression will be given by:

2.5 + 30 + 1.7 - 90

Only addition and subtraction, hence the order is from left to right, and the subtraction is done last, hence option B is correct.

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x = –8 –6x + 9y = 12 solve for substitution

Answers

Answer:

x= -8,y= -4

Step-by-step explanation:

Substitute x= -8

-6(-8)+9y=12

simplify

48+9y=12

isolate for y

y= -4

The solutions to the system of equations are:

x= -8 and y= -4

2 Which set of side lengths will form a triangle?
16 ft, 4 ft, 21 ft.
6 30 ft, 30 ft, 60 ft
12 ft, 12 ft, 20 ft
3ft, 5 ft, 10 ft

Answers

None of the above. To form a standard triangle, all 3 sides must be of equal length.

solve 2-6(1-x)=6-4(-x-2) for x

Answers

Answer:

x = 9

Step-by-step explanation:

Simplifying

2 + -6(1 + -1x) = 6 + -4(-1x + -2)

2 + (1 * -6 + -1x * -6) = 6 + -4(-1x + -2)

2 + (-6 + 6x) = 6 + -4(-1x + -2)

Combine like terms: 2 + -6 = -4

-4 + 6x = 6 + -4(-1x + -2)

Reorder the terms:

-4 + 6x = 6 + -4(-2 + -1x)

-4 + 6x = 6 + (-2 * -4 + -1x * -4)

-4 + 6x = 6 + (8 + 4x)

Combine like terms: 6 + 8 = 14

-4 + 6x = 14 + 4x

Solving

-4 + 6x = 14 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.

-4 + 6x + -4x = 14 + 4x + -4x

Combine like terms: 6x + -4x = 2x

-4 + 2x = 14 + 4x + -4x

Combine like terms: 4x + -4x = 0

-4 + 2x = 14 + 0

-4 + 2x = 14

Add '4' to each side of the equation.

-4 + 4 + 2x = 14 + 4

Combine like terms: -4 + 4 = 0

0 + 2x = 14 + 4

2x = 14 + 4

Combine like terms: 14 + 4 = 18

2x = 18

Divide each side by '2'.

x = 9

Simplifying

x = 9

Find the area of the trapezoid shown below. {?} square feet

Answers

Answer:

432

Step-by-step explanation:

Help!!! 8. Determine whether each pair of functions f and g are inverses. Explain your reasoning.

Answers

Answer:

I would say that a is NOT an inverse, however b is.

Step-by-step explanation:

If you look at the two tables for a, you can tell that every pair has swapped places (as they should) except 0 and 9. In which in the second table, what should be the 9 in the x row, is just another 0 in its place.

While if you look at the two tables for b, every single pair has been swapped like it should, meaning the second table is the inverse of the first table.

Hope this helps you btw. I'm sorry if it doesn't though.

Tamara attends a cycling class that starts at 6:00. The class lasts 45 minutes. What time does class end?

Answers

Answer:

6:45

Step-by-step explanation: add 45 min to 6:00 and you have your answer

Answer:6:45

Step-by-step explanation: 6:00 + 45minutes would be 6:45

Knowing that ΔBIG ≅ ΔFNS, an angle pair that is NOT necessarily congruent is:

Knowing that ΔDAL ≅ ΔEKS, a side pair that is NOT necessarily congruent is:

Answers

solutions:

1) G ≅ F

2) DA ≅  ES

Explanation:

Q)1

ΔBIG ≅ ΔFNS

pairs that are congruent:

B ≅ FI ≅ NG ≅ S

From the list given,

→ G ≅ F is not necessarily congruent.

Q)2

ΔDAL ≅ ΔEKS

pairs that are congruent:

DA ≅  EKAL ≅  KSDL ≅  ES

From the list given,

DA ≅  ES  is not necessarily congruent.

Usually the congruence is done according to naming

So

∆BIG≅∆FNS

<B=F

<I=<N

<G=<S

Option A

#2

Check the naming

∆DAL≅∆EKS

So

DA=EK

And DA may not be equal to ES

So option D

The following structure is composed of three right rectangular prisms: two that each measure 12 inches by 10 inches by 5 inches and one right rectangular prism that measures 10 inches by 8 inches by 36 inches. What is the total volume of the structure? Show your work and/or explain your reasoning..

Answers

The volume of the stucture made from three rectangular prism is 4080 ft³

What is volume?

Volume is the amount of space occupied by a three dimensional shape or object.

The volume of the rectangular prism = length * width * height = 12 * 10 * 5 = 600 ft³

The volume of the other prism = length * width * height = 10 * 8 * 36 = 2880 ft³

Volume of the structure = 600 ft³ + 600 ft³ + 2880 ft³ = 4080 ft³

The volume of the stucture made from three rectangular prism is 4080 ft³

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Solve for m.
m/9 + 2/3 =7/3

Answers

Answer:

m= 15

Step-by-step explanation:

[tex] \frac{m}{9} + \frac{2}{3} = \frac{7}{3} [/tex]

To solve for m, start by moving the constants (numbers that are not attached to any variable) to the other side of the equation.

[tex] \frac{m}{9} = \frac{7}{3} - \frac{2}{3} [/tex]

Simplify:

[tex] \frac{m}{9} = \frac{5}{3} [/tex]

Multiply both sides by 9:

[tex]m = \frac{5}{3} \times 9[/tex]

Crossing out 3 from the denominator and from 9:

m= 5(3)

m= 15

(15 points )

Find the x in the problem

(x−1)^2=9

Show steps if you can :)

Answers

Answer:

x=4 or x= -2

Step-by-step explanation:

(x-1)(x-1)

x(x-1)-1(x-1)

x^2-x-x+1

x^2-2x+1=9

x^2-2x+1-9=0

x^2-2x-8=0

p= -8

s= -2

1------ -8

2------ -4

x^2+2x-4x-8=0

x(x+2)-4(x+2)

(x+2)(x-4)=0

x+2=0

x-4=0

x= -2

or

x=4

Which inequality is shown in the graph?

Answers

Answer:

Step-by-step explanation:

solve- cbb to work it out

Answers

Answers:

➝ Hypotenuse of triangle ( a ) = 21.63 mm

➝ Hypotenuse of triangle ( b ) = 150 mm

➝ Hypotenuse of triangle ( c ) = 111.80 mm

[tex] \quad\rule{300pt}{1.5pt}\quad[/tex]

Solution:

We have to find the length of hypotenuse in the given 3 triangles, which can be done by using Pythagoras theorem.

Pythagoras theorem states that :

" In a right angled triangle, the square of hypotenuse side is equal to the sum of square of other two sides "

[tex] \qquad \bull \:{\pmb{\mathfrak{ h^2 = b^2 + p^2}}}[/tex]

And we have to convert the answer to the units indicated in red i.e, in mm.

Since 1cm = 10 mm, we will convert the given values of length of side in mm before putting the values in the formula

For triangle ( a )

[tex] :\implies\qquad \sf{ h^2 = b^2 + p^2}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{b^2 + p^2}}[/tex]

[tex] :\implies\qquad \sf{h=\sqrt{ (12)^2 + (18)^2 }}[/tex]

[tex] :\implies\qquad \sf{ h= \sqrt{144 + 324}}[/tex]

[tex] :\implies\qquad \sf{ h = \sqrt{468}}[/tex]

[tex] :\implies\qquad\underline{\underline{\pmb{ \sf{ h = 21.63 mm}}}}[/tex]

For triangle ( b )

[tex] :\implies\qquad \sf{ h^2 = b^2 + p^2}[/tex]

[tex] :\implies\qquad \sf{h =\sqrt{b^2 + p^2} }[/tex]

[tex] :\implies\qquad \sf{ h = \sqrt{(90)^2+(120)^2}}[/tex]

[tex] :\implies\qquad \sf{ h=\sqrt{8100+14400}}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{22500}}[/tex]

[tex] :\implies\qquad\underline{\underline{\pmb{ \sf{h = 150mm}}} }[/tex]

For triangle ( c )

[tex] :\implies\qquad \sf{h^2 = b^2 + p^2 }[/tex]

[tex] :\implies\qquad \sf{ h=\sqrt{b^2 + p^2}}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{(100)^2)+(50)^2}}[/tex]

[tex] :\implies\qquad \sf{ h=\sqrt{10000+2500}}[/tex]

[tex] :\implies\qquad \sf{ h =\sqrt{12500}}[/tex]

[tex] :\implies\qquad \underline{\underline{\pmb{\sf{h = 111.80mm}}} }[/tex]

Answers:

Hypotenuse of triangle ( a ) = 21.63 mm

Hypotenuse of triangle ( b ) = 150 mm

Hypotenuse of triangle ( c ) = 111.80 mm

Explanation :

find the length of hypotenuse in the given 3 triangles, which can be done by using Pythagoras theorem.

[tex]h^2 = b^2 + p^2[/tex]

And we have to convert the answer to the units indicated in red i.e, in mm.

Since 1cm = 10 mm, we will convert the given values of length of side in mm before putting the values in the formula

[tex]For \: \: triangle ( a )

\qquad \sf{ h^2 = b^2 + p^2}[/tex]

[tex]\qquad \sf{ h =\sqrt{b^2 + p^2}}[/tex][tex]\qquad \sf{h=\sqrt{ (12)^2 + (18)^2 }}[/tex][tex]\qquad\sf{h=\sqrt{ (12)^2 + (18)^2 }} \\ \\ \qquad \sf{ h= \sqrt{144 + 324}} \\ \\ \qquad \sf{ h = \sqrt{468}}

\\ \\\qquad\underline{\underline{\pmb{ \sf{ h = 21.63 mm}}}} \\ \\ For \: \: triangle ( b ) \qquad \sf{ h^2 = b^2 + p^2} \\ \\ \qquad \sf{h =\sqrt{b^2 + p^2} } \\ \\ \qquad \sf{ h = \sqrt{(90)^2+(120)^2}} \\ \\ \qquad \sf{ h=\sqrt{8100+14400}} \\ \\

\qquad \sf{ h =\sqrt{22500}} \\ \\\qquad\underline{\underline{\pmb{ \sf{h = 150mm}}} } \\ \\ For \: \: triangle ( c ) \qquad \sf{h^2 = b^2 + p^2 } \\ \\ \qquad \sf{ h=\sqrt{b^2 + p^2}} \\ \\\qquad\sf{ h=\sqrt{(100)^2)+(50)^2}} \\ \\\qquad\sf{ h=\sqrt{10000+2500}} \\ \\ \qquad \sf{ h =\sqrt{12500}} \\ \\

\qquad\underline{\underline{\pmb{\sf{h = 111.80mm}}} } [/tex]

What is the range of this relation? ​

Answers

Answer:

{- 1, 0, 4 }

Step-by-step explanation:

the range is the y- coordinates of the plotted points

the coordinates of the points are

(- 4, - 1 ) , (1, 0 ) , (1, 4 ) with y- coordinates - 1, 0, 4

then range is { - 1, 0, 4 }

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
The school band director has a budget $4,428.00 to spend on the band room, instruments, music, and uniforms. There are four sections in the band: drum corps, woodwinds, horns, and color guard. She has received three offers.

Option 1. Repair and replace uniforms at $564.00 per section and spend $182.00 on music.
Option 2. Repair and replace uniforms at $593.00 per section and spend $78.00 on music.
Option 3. Repair uniforms at $287.00 per section, spend $856.00 for improving the acoustics in the band room, and spend $422.00 on music and repairing instruments.
The remainder of the money will be split evenly among the four sections for additional costs. Match each option with the amount of money each section will receive for additional costs.

Answers

Answer:

The amount of money left for each section to spend from the budget in additional costs if they follow exact of the

options is

Option 1-$497.5

Option 2 - $494.5

Option 3 - $500.5

The image to show the amounts to match to isn't attagged to the question, but these are the answers and they should

be matched accordingly.

Step-by-step explanation:

We first calculate the amount left per section after following each of the options.

Budget $4,428.00

Option 1.

Repair and replace uniforms at $564.00 per section and spend $182.00 on music.

There are 4 sections, hence, total amount spent in this option:

4(564) + 182 $2438

Amount of money left from the budget after spending= 4428-2438 = $1990

Amount left per section = (1990/4) =

$497.5

Option 2

Repair and replace uniforms at $593.00 per section and spend $78.00 on music.

There are 4 sections, hence, total amount spent in this option:

4(593) + 78 $2450

Amount of money left from the budget after spending= 4428 - 2450= $1978

Amount left per section = (1978/4)=

$494.5

Option 3

Repair uniforms at $287.00 per

section, spend $856.00 for improving the acoustics in the band room, and spend $422.00 on music and repairing instruments.

There are 4 sections, hence, total amount spent in this option:

4(287) + 856 +422 = $2426

Amount of money left from the budget

after spending = 4428-2426 = $2002

Amount left per section = (2002/4)= $500.5

PLS HELP ME PLS I WILL MARK THE BRAINLIEST

Answers

Step-by-step explanation:

the area of a full circle (360°) is

pi×r²

r = 15 ft in our case

the area of a segment of a circle is the corresponding fraction of the whole circle area.

the angle of the shaded area is

360 - 332 = 28°

therefore, the area of the shaded area is

pi×15²×28/360 = pi×225×28/360 = pi×225×7/90 =

= pi×5×7/2 = 54.97787144... ft²

≈ 54.98 ft²

the area of the "ice rink" is the sum of a rectangle and a circle (which is split into 2 halves that are attached to both sides of the rectangle).

the radius of the circle is 7/2 = 3.5 meters.

the length of the rectangle in the middle is

18 - 2×3.5 = 18 - 7 = 11 meters.

so, the area of the rectangle is 11×7 = 77 m²

the area of the circle is

pi×r² = pi×3.5² = pi×12.25 = 38.48451001... m²

that means the total area is

77 + 38.48451001... = 115.48451... m² ≈ 115.48 m²

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