Find the equation of the axis of symmetry of the graph of the function. y=x^2-2x-9
solve it in the picture

The limit as a definite integral is ∫[1 to 3][tex]x^8[/tex] dx.

To express the limit as a definite integral, we can use the Riemann sum approximation. Given the hint to consider the function f(x) = x^8, we can rewrite the limit as follows:

lim n→∞ Σ [i=1 to n] [tex](3i/n)^8[/tex]

This is a Riemann sum approximation for the integral of f(x) =[tex]x^8[/tex] over the interval [1, 3]. To express it as a definite integral, we can rewrite it as:

∫[1 to 3] [tex]x^8[/tex] dx

So, the limit can be expressed as the definite integral ∫[1 to 3] [tex]x^8[/tex] dx.

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The dimensions of the rectangular plot of land that sits on a riverbank is 40 m by 5 m or 10 m by 20 m.

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value while a dependent variable is a variable that depends on other variable.

Let x represent the length and y represent the width. Hence:

x + 2y = 50

x = 50 - 2y

Also:

xy = 200

(50 - 2y)y = 200

50y - 2y² = 200

25y - y² = 100

y² - 25y + 100 = 0

y² - 20y - 5y + 100 = 0

y (y - 20) - 5 (y - 20) = 0

(y - 5) (y - 20) = 0

y = 5; and y = 20

Hence, x = 40; and x = 10

The dimensions of the rectangular plot of land that sits on a riverbank is 40 m by 5 m or 10 m by 20 m.

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The one-half of the product expression -3/4 * 8/19 is -3/19

From the question, we have the following parameters that can be used in our computation:

-3/4 and 8/19

The product expression of -3/4 and 8/19 is represented as

Product = -3/4 * 8/19

Evaluate the products

So, we have the following

Product = -3/1 * 2/19

Next, we have

Product = -6/19

For one-half of the product expression, we multiply by 1/2

One half = -6/19 * 1/2

Evaluate

One half = -3/19

Hence, the one-half of the product expression is -3/19

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Complete question

What is one-half of the product of the following?

*Read carefully!*

-3/4 and 8/19

In summary, the normal distribution is symmetric, its mean and median are equal, and it is described by its mean and standard deviation. However, it is not bimodal, as it does not exhibit multiple peaks.

The statement "d. It is bimodal" is not true about the normal distribution. The normal distribution is a symmetric probability distribution that is bell-shaped. It does not have multiple peaks or modes, making it unimodal rather than bimodal.

Here are explanations for the other statements:

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To solve the given system of equations we can use the method of Gaussian elimination or matrix operations to find the solution. Here, I'll use the Gaussian elimination method.

First, we'll rewrite the system in matrix form:

[A | B] =

⎡ -3 3 1 | -1 ⎤

⎢ -1 3 1 | -4 ⎥

⎢ 4 -1 3 | 9 ⎥

⎣ 1 -3 -1 | -10⎦

Performing row operations to simplify the matrix:

R2 = R2 + R1

R3 = R3 - 4R1

R4 = R4 - R1

[A | B] =

⎡ -3 3 1 | -1 ⎤

⎢ 0 6 2 | -5 ⎥

⎢ 0 -13 -1 | 13 ⎥

⎣ 0 -6 -2 | -9 ⎦

Next, perform additional row operations:

R3 = R3 + (13/6)R2

R4 = R4 + (6/13)R3

[A | B] =

⎡ -3 3 1 | -1 ⎤

⎢ 0 6 2 | -5 ⎥

⎢ 0 0 0 | 0 ⎥

⎣ 0 0 0 | 0 ⎦

From the row-echelon form of the augmented matrix, we can see that the system has dependent equations. This means there are infinite solutions.

To express the solution, we can assign a parameter to one of the variables. Let's assign w = t, where t is a real number.

The solution can be written as:

w = t

x = (2/3)t - (5/6)

y = -t + (5/6)

z = s

Here, t and s can take any real values, and the solution represents an infinite number of points in 4-dimensional space.

By performing Gaussian elimination on the augmented matrix, we simplify it to row-echelon form. From the form, we observe that the system has dependent equations, indicating infinite solutions. To express the solution, we assign a parameter to one variable and express the other variables in terms of that parameter. In this case, we assign w = t and express x, y, and z accordingly. The solution represents an infinite set of points in 4-dimensional space, parameterized by t and s.

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The volume of the solid region enclosed by the surface rho = 12 cos φ.

A. 288π

To find the volume of the solid region enclosed by the surface ρ = 12 cos φ in spherical coordinates, we integrate ρ^2 sin φ dρ dφ dθ over the appropriate ranges.

The range of φ is from 0 to π/2, and the range of θ is from 0 to 2π.

Setting up the integral, we have:

V = ∭ ρ^2 sin φ dρ dφ dθ

V = ∫[0, 2π] ∫[0, π/2] ∫[0, 12cosφ] (ρ^2 sin φ) dρ dφ dθ

Let's evaluate the integral step by step:

∫ ρ^2 sin φ dρ = (ρ^3 / 3) ∣[0, 12cosφ] = (12^3 cos^3 φ / 3) - (0^3 / 3) = (12^3 cos^3 φ / 3)

∫ (12^3 cos^3 φ / 3) dφ = (12^3 / 3) ∫ cos^3 φ dφ = (12^3 / 3) * (3/4) = 12^3 / 4

Now, we integrate with respect to θ:

∫ (12^3 / 4) dθ = (12^3 / 4) θ ∣[0, 2π] = (12^3 / 4) * 2π = 12^3 π / 2

Therefore, the volume of the solid region enclosed by the surface ρ = 12 cos φ is 12^3 π / 2.

Simplifying this expression, we get:

Volume = 12^3 π / 2 = 1728π / 2 = 864π

Therefore, the correct option is A. 288π.

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The profit earned by the company for selling 5000 units when per unit price is $530 is:

Profit = Revenue - CostProfit = $2,650,000 - $2,275,000

Profit = $375,000

Therefore, the company earned a profit of $375,000.

The calculation of the units required by the new filling machines to be chosen over the general filling machine is given below:New Machine:Fixed Cost = $650,000Variable Cost = $325 per unit General Filling Machine:Fixed Cost = $225,000Variable Cost = $450 per unit Assuming that the cost of using a general filling machine to produce a product and the cost of using a new filling machine to produce a product is equal, then we can calculate the unit break-even point. The formula for calculating the break-even point in units is given as follows:Break-even Point in Units = Fixed Costs / (Selling Price per Unit - Variable Cost per Unit)Since no selling price is given for the products produced by both filling machines, it is safe to assume that both machines are selling the product at the same price.Break-even Point for New Filling Machine:Break-even Point = $650,000 / ($530 - $325)Break-even Point = $650,000 / $205Break-even Point = 3,170 units

Therefore, the new filling machine must produce 3,170 units in order to break even with the general filling machine.B)Long answer:Profit/Loss is calculated by the following formula:Profit = Revenue - CostIf the price per unit is $530 and 5000 units are sold, the total revenue will be:$530 × 5000 = $2,650,000The cost of production using the new machine is calculated as follows:

Variable Cost = $325 × 5000 = $1,625,000Fixed Cost = $650,000Total Cost = $1,625,000 + $650,000 = $2,275,000

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The image distance (v) is approximately 17.72 cm.

What is focal length?

Focal length refers to a fundamental property of a lens or mirror that determines its optical behavior. It is the distance between the lens (or mirror) and its focal point. The focal point is the specific point in space where parallel rays of light converge or from where they appear to diverge after passing through (or reflecting off) the lens

To analyze the situation, we can use the lens formula:

1/f = 1/v - 1/u

Where:

f is the focal length of the lens

v is the image distance from the lens (positive for real images)

u is the object distance from the lens (positive for objects in front of the lens)

Given:

Object height (h) = 1.1 cm

Object distance (u) = -11 cm (since the object is in front of the lens, the distance is negative)

Focal length (f) = 29 cm

Let's substitute these values into the formula and solve for the image distance (v):

1/29 = 1/v - 1/-11

To simplify, we can find a common denominator:

1/29 = (11 - v) / (v * -11)

Now, we can cross-multiply:

29 * (11 - v) = -11 * v

319 - 29v = -11v

Combine like terms:

18v = 319

v = 319 / 18

v ≈ 17.72 cm

Therefore, the image distance (v) is approximately 17.72 cm.

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Complete question:

What is the image distance (v) formed by a lens with a focal length (f) of 29 cm when an object with a height (h) of 1.1 cm is placed at a distance (u) of -11 cm from the lens?

Brei owes her mom $19.80 for the phone call.

To calculate how much Brei owes her mom for the phone call, let's break down the call into two time periods: before 8:00 a.m. and after 8:00 a.m.

Before 8:00 a.m.:

The call started at 7:00 a.m. and ended at 8:00 a.m., making it a duration of 1 hour (60 minutes).

The cost for the first minute is $0.35, and for the subsequent minutes, it's $0.20 per minute. So for the remaining 59 minutes, the cost is:

59 minutes * $0.20/minute = $11.80

The total cost for the call before 8:00 a.m. is:

$0.35 (first minute) + $11.80 (remaining minutes) = $12.15

After 8:00 a.m.:

The call continued from 8:00 a.m. to 8:30 a.m., which is a duration of 30 minutes.

The cost for the first minute is $0.40, and for the subsequent minutes, it's $0.25 per minute. So for the remaining 29 minutes, the cost is:

29 minutes * $0.25/minute = $7.25

The total cost for the call after 8:00 a.m. is:

$0.40 (first minute) + $7.25 (remaining minutes) = $7.65

To find the total cost for the entire call, we sum up the costs from both time periods:

$12.15 (before 8:00 a.m.) + $7.65 (after 8:00 a.m.) = $19.80

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Answer:

  (3)  see attached

Step-by-step explanation:

You want to draw the triangle with vertex coordinates (2, 1), (3, 3), and (5, 1), along with its rotation 180° about the origin.

The coordinate pair (2, 1) means the point is located 2 units to the right of the y-axis (where x=0), and 1 unit above the x-axis (where y=0). This point is incorrectly plotted in images 2 and 4, eliminating those possibilities.

Rotation 180° about the origin causes the signs of each of the coordinates to be reversed (negated, become the opposite of what they were). That means point (2, 1) gets rotated to the location (-2, -1).

This rotated point is 2 units left of the y-axis, and 1 unit down from the x-axis. It is correctly located in image 3.

__

Additional comment

Rotation 180° about a point is equivalent to reflection across that point. The segment between a point and its image will have the center of rotation as its midpoint.

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The average value of y=x^2√x^3 on the interval [0,2] is 4/9 * (2^(9/2)-0), or approximately 11.841. To find the average value of y=x^2√x^3 on the interval [0,2], we need to use the formula for the average value of a function on an interval:

average value = 1/(b-a) * ∫(from a to b) f(x) dx

In this case, a=0 and b=2, so we have:

average value = 1/(2-0) * ∫(from 0 to 2) x^2√x^3 dx

We can simplify x^2√x^3 as x^(2+3/2) = x^(7/2), so we have:

average value = 1/2 * ∫(from 0 to 2) x^(7/2) dx

Integrating x^(7/2) gives us (2/9)x^(9/2), so we have:

average value = 1/2 * [(2/9)(2^(9/2)-0)]

Simplifying this expression gives us:

average value = 4/9 * (2^(9/2)-0)

Therefore, the average value of y=x^2√x^3 on the interval [0,2] is 4/9 * (2^(9/2)-0), or approximately 11.841.

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Under ideal conditions, the frequency of the dominant allele increases in each generation. Option A.

The frequency of the dominant allele increases in each generation because it is expressed in the phenotype of organisms and is therefore more likely to be passed on to the next generation.

Alternately, under ideal conditions, the frequency of the recessive allele decreases in each generation. In other words, the alleles do not necessarily reach a 50/50 balance.

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To estimate the position of the object at time t = 2.2 using a linear approximation, we can use the slope of the line connecting the two closest known points, which are (t, u(t)) = (2, 55) and (t, u(t)) = (5, 6).

The slope of the line is given by:

m = (u(t₂) - u(t₁)) / (t₂ - t₁)

Substituting the values:

m = (6 - 55) / (5 - 2) = -49 / 3

Now, we can use the point-slope form of a line to find the equation of the line:

u(t) - u(t₁) = m(t - t₁)

Substituting the values:

u(t) - 55 = (-49/3)(t - 2)

Now, we can substitute t = 2.2 into the equation to estimate the position of the object:

u(2.2) - 55 = (-49/3)(2.2 - 2)

Simplifying:

u(2.2) - 55 = (-49/3)(0.2)

u(2.2) - 55 = -49/15

To find the estimated position of the object at t = 2.2, we add the value to the initial position at t = 2:

u(2.2) = -49/15 + 55

Calculating the result:

u(2.2) ≈ 53.733

Therefore, the estimated position of the object at t = 2.2 is approximately 53.733 kilometers.

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The theorem that shows that triangle AJG is congruent to triangle CDF is the SAS (Side-Angle-Side) congruence theorem.

Let us explain the relationship between the triangles

1. We have segment DF congruent to segment JG given in the problem statement.

2. We also have segment EF congruent to segment HG given in the problem statement.

3. Segment CE is congruent to segment AH, which implies that segment AC is congruent to segment CH (since segments with equal lengths are congruent).

4. Angle AJD is congruent to angle CDJ, given that they are both right angles (90 degrees).

Now, let's compare the corresponding parts of the two triangles:

- Side AJ is congruent to side CD because both are the hypotenuses of their respective right-angled triangles.

- Side JG is congruent to side DF (given in the problem statement).

- Side AG is congruent to side CJ (from the fact that segment AC is congruent to segment CH).

By the SAS congruence theorem, if two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle, then the two triangles are congruent. In this case, triangle AJG and triangle CDF satisfy these conditions, and therefore, we can conclude that triangle AJG is congruent to triangle CDF.

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There are 1470 commuters take both the bus and the subway.

To find the number of commuters who take both the bus and the subway, we can use the principle of inclusion-exclusion.

Let's denote:

A = Number of commuters who take the subway

B = Number of commuters who take the bus

N = Total number of commuters

From the given information:

A = 1190 (number of commuters who take the subway)

B = 640 (number of commuters who take the bus)

N = 1700 (total number of commuters)

We also know that 180 commuters do not take either the bus or the subway.

To find the number of commuters who take both the bus and the subway, we can use the formula:

A ∪ B = A + B - A ∩ B

where A ∪ B represents the union of A and B, and A ∩ B represents the intersection of A and B.

Substituting the values we have:

A ∪ B = 1190 + 640 - 180

A ∪ B = 1650

Therefore, 1650 commuters take either the bus or the subway (or both). To find the number of commuters who take both the bus and the subway, we subtract the number of commuters who take neither:

Number of commuters who take both the bus and the subway = A ∪ B - Neither

Number of commuters who take both the bus and the subway = 1650 - 180

Number of commuters who take both the bus and the subway = 1470

Therefore, 1470 commuters take both the bus and the subway.

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Mindy pay $ 6789 in Social Security tax if she earned $ 109,500 in 2016.

It is given that the piecewise function represents the Social Security taxes for 2016.

f(x) = { 0.062 x when 0 <  x < 111,800

     = { $ 7,621.60 when x > 111,800

We need to find Mindy's security tax if she earned  $109,500 in 2016.

Since 102,000 lies in 0 <  x < 111,800 , therefore

f(x) = 0.062 x

Put x = 109,500

f(x) = 0.062 × 109,500

= 6789

Therefore, Mindy pay $ 6789 in Social Security tax if she earned $ 109,500 in 2016.

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Given question is incomplete, the complete question is below

This piecewise function represents the Social Security taxes for 2016. How much did Mindy pay in Social Security tax if she earned $109,500 in 2016?

f(x) = { 0.062 x when 0 <  x < 111,800

     = { $ 7,621.60 when x > 111,800

The task is to identify the graph that represents a binomial distribution with n = 20 (number of trials) and p = 0.25 (probability of success).

In a binomial distribution, the number of trials (n) and the probability of success (p) are crucial factors. A binomial distribution is characterized by discrete values and a specific shape. The probability mass function (PMF) for a binomial distribution follows the formula P(X=k) = (n choose k) * p^k * (1-p)^(n-k), where X represents the random variable and k represents the number of successes. To determine the correct graph, we should look for the following characteristics: the distribution should be discrete, have 20 possible values (n = 20), and the probability of success for each trial should be 0.25 (p = 0.25). By examining the provided graphs, we can identify the one that aligns with these criteria to represent a binomial distribution with n = 20 and p = 0.25.

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Hello !

Answer:

[tex]\boxed{\sf d=\sqrt{107}\approx10.34 }[/tex]

Step-by-step explanation:

The distance between two points A and B is given by the following formula:

[tex]\sf AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2+(z_B-z_A)^2}[/tex]

Where [tex]\sf A(x_A,y_A,z_A)[/tex] and [tex]\sf B(x_B,y_B,z_B)[/tex].

Given :

Let's replace the coordinates with their values in the previous formula :

[tex]\sf AB=\sqrt{(0-5)^2+(3-(-6))^2+(13-12)^2}\\AB=\sqrt{25+81+1}\\\boxed{\sf AB=\sqrt{107}\approx10.34 }[/tex]

Have a nice day ;)

If it is 3:25 p.m. in the Philippines, the corresponding time in Cairo, Egypt, accounting for the time difference of -6 hours, would be 3:25 a.m. in the next day.

To find the time in Cairo, Egypt, we need to consider the time difference between Cairo and the Philippines. The given time difference is -6 hours. The negative sign indicates that Cairo is ahead of the Philippines in terms of time.

The given time in the Philippines is 3:25 p.m. To convert it to a 24-hour format, we add 12 hours to the time since 3:25 p.m. is in the afternoon. Therefore, 3:25 p.m. becomes 15:25.

Since the time difference is -6 hours, we need to subtract 6 hours from the time in the Philippines (15:25).

15:25 - 6:00 = 9:25

Therefore, the adjusted time in the Philippines, considering the time difference, is 9:25 p.m.

Now that we have the adjusted time in the Philippines, we can find the time in Cairo by adding the time difference to the adjusted time in the Philippines.

9:25 p.m. + (-6 hours) = 3:25 a.m.

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To calculate the margin of error, you need to determine the critical value associated with the desired level of confidence. The margin of error is then obtained by multiplying the critical value by the standard deviation.

Let's assume you want to calculate the margin of error for a 95% confidence level. For a normal distribution, the critical value corresponding to a 95% confidence level is approximately 1.96.

Margin of Error = Critical Value * Standard Deviation

Using the given values:

Standard Deviation = 0.08

For a 95% confidence level:

Critical Value = 1.96

Margin of Error = 1.96 * 0.08

Calculating the margin of error:

Margin of Error = 0.1568

Therefore, the margin of error is approximately 0.1568

The p-value is 0.146.The statistical conclusion suggests that there is no significant difference in stopping distances between wet and dry pavements.

At a .05 level of significance, the sample data does not justify the conclusion that the variance in stopping distances on wet pavement is greater than the variance in stopping distances on dry pavement.

The p-value is 0.146. 

Here, Null hypothesis: H₀: σ₁² ≤ σ₂².

Alternate hypothesis: H₁: σ₁² > σ₂² 

The test is a right-tailed test. 

Sample size, n = 16.

Degrees of freedom, ν = n1 + n2 - 2 = 30 (approx.).

The test statistic is calculated as: F₀ = (S₁²/S₂²),

where S₁² and S₂² are the sample variances of stopping distances of automobiles on wet and dry pavements, respectively.

Substituting the given values, we have: F₀ = (9.76²/4.88²) = 4.00.

From the F-distribution table, at α = 0.05 and ν₁ = 15, ν₂ = 15, the critical value is 2.602.

The p-value can be calculated as the area to the right of F₀ under the F-distribution curve with 15 and 15 degrees of freedom.

p-value = P(F > F₀),

where F is the F-distribution with ν₁ = 15, and ν₂ = 15 degrees of freedom. Substituting the given values, we get:

p-value = P(F > 4.00) = 0.146. Since p-value (0.146) > α (0.05), we fail to reject the null hypothesis.

Hence, the sample data does not justify the conclusion that the variance in stopping distances on wet pavement is greater than the variance in stopping distances on dry pavement.

The p-value is 0.146.b. The statistical conclusion suggests that there is no significant difference in stopping distances between wet and dry pavements.

Thus, the driving safety recommendations would be that the driver should always maintain a safe distance while driving, whether it is wet or dry.

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One can have 90% confidence that the interval from the lower bound (0.021) to the upper bound (0.033) actually contains the true value of the population proportion of adverse reactions. Option C is correct.

To construct the confidence interval for the proportion of adverse reactions, we will use the sample data and the provided confidence level of 90%.

a) The best point estimate of the population proportion p is the sample proportion of adverse reactions. We calculate it by dividing the number of patients who developed adverse reactions (130) by the total number of patients treated with the drug (4731):

p = 130 / 4731 ≈ 0.027

b) The margin of error (E) can be calculated using the formula:

[tex]E = z\times \sqrt{\dfrac{\hat p \times (1 - \hat p) }{ n}}[/tex]

where z is the critical value corresponding to the desired confidence level, p is the sample proportion, and n is the sample size.

Since the confidence level is 90%, we need to find the critical value associated with a 95% confidence level (since it's a two-tailed test). This critical value is approximately 1.645.

[tex]E = 1.645 \times \sqrt{\dfrac{(0.027 \times (1 - 0.027) }{ 4731}} \\E =0.006[/tex]

c) To construct the confidence interval, we use the formula:

Confidence interval = p ± E

Substituting the values, we get:

Confidence interval = 0.027 ± 0.006

The lower bound of the confidence interval is obtained by subtracting the margin of error from the point estimate:

Lower bound = 0.027 - 0.006 ≈ 0.021 (rounded to three decimal places)

The upper bound of the confidence interval is obtained by adding the margin of error to the point estimate:

Upper bound = 0.027 + 0.006 ≈ 0.033 (rounded to three decimal places)

Therefore, the 90% confidence interval for the proportion of adverse reactions is approximately 0.021 to 0.033.

d) The correct interpretation of the confidence interval is:

One can have 90% confidence that the interval from the lower bound (0.021) to the upper bound (0.033) actually contains the true value of the population proportion of adverse reactions." (Option C)

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The length of the arc of the curve given by the function `r(t) = (12,23t^2, 8t)` for `(a ≤ t ≤ b)` is given by the formula: `L = ∫a^b √(dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2 dt`.

Therefore, the length of the arc of the curve given by the function `r(t) = (12,23t^2, 8t)` over the interval `(0,5)` is `L = ∫a^b √(dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2 dt = ∫0^5 √(2116t^2 + 64) dt`.

Summary:Thus, the arc length of the curve `r(t) = (12,23t^2, 8t)` over the interval `(0,5)` is `640/1059`.

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Answer:

angle K = 32°

Step-by-step explanation:

angles in triangle add up to 180°.

angle H is 90° because triangle KJH is in a semicircle (JK is diameter).

so angle J + angle K must add up to 180° - 90° = 90°.

we have (5x - 2) + (2x + 8) = 90

5x + 2x - 2 + 8 = 90

7x + 6 = 90

7x = 90 - 6 = 84

x = 12.

so angle K = (2x + 8)° = (2(12) + 8)° = (24 + 8)° = 32°.

Answer: - 1

Step-by-step explanation:

(end after moveing back 4)      (start at 3)

                                 |<<<<<<<<<<<< |

--(-5)--(-4)--(-3)--(-2)--(-1)--(0)--(1)--(2)--(3)--(4)--(5)--

The range can be defined as the difference between the maximum value and minimum value in a set of data.

In this question, we are given the sample data: 23, 17, 15, 30, 25. To find the range, we need to find the maximum value and the minimum value and then subtract the minimum value from the maximum value. This gives us the range.

Here are the steps to find the range:Step 1: Arrange the data in ascending order15, 17, 23, 25, 30Step 2: Find the maximum valueThe maximum value is 30.

Step 3: Find the minimum valueThe minimum value is 15.Step 4: Calculate the rangeThe range is given by the formula:Maximum value - Minimum valueRange = 30 - 15Range = 15Therefore, the range of the sample data 23, 17, 15, 30, 25 is D. 15.

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The volume of the given solid will be between the limits are :

-√(x - 4) ≤ y ≤ √(x - 4).

To find the volume of the given solid, we need to calculate the triple integral over the region enclosed by the surfaces. The region is defined by the curves x - y² and x - 4. By setting up and evaluating the triple integral, we can determine the volume of the solid.

The first step is to determine the bounds for the triple integral. We'll integrate with respect to x, y, and z. Looking at the region enclosed by the curves x - y² and x - 4, we need to find the limits for x, y, and z.

The curve x - y² intersects with x - 4 at two points: (4, 0) and (5, 1).

Therefore, the bounds for x are 4 ≤ x ≤ 5. The curve x - y² bounds the region from below, so for each value of x, the y-limits are given by :

-√(x - 4) ≤ y ≤ √(x - 4).

The surface z = 1 + x²y² defines the upper boundary of the solid. Thus, the z-limits are 1 + x²y² ≤ z.

Setting up the triple integral, we have:

∫∫∫ (1 + x^2y^2) dz dy dx

The innermost integral is with respect to z, and the limits for z are:

1 + x²y² ≤ z.

Moving on to the y-integration, the limits are -√(x - 4) ≤ y ≤ √(x - 4).

Finally, we integrate with respect to x, and the limits for x are 4 ≤ x ≤ 5.

Evaluating this triple integral will yield the volume of the given solid.

Complete Question:

Find the volume of the given solid. Under the surface z - 1 + x2y2 and above the region enclosed by x - y2 and x - 4 .

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F.dr is to be reduced by applying the standard parametrisation.

And the given F(x, y, z) = zi + 1j+yk and C is the straight line going from the origin to (-1,2,1) in R. S

The work done by F(x, y, z) over C can be given byW

= ∫F.drAlong the curve, dr(t) = (-1, 2, 1)dt

The limits are from 0 to 1 for t.We can substitute the values into the equation:W

= ∫F.dr= ∫ [(-2-t)i + (2+t)j + k] . (-i + 2j + k) dt= ∫[-2-t]dt - ∫2+tdt + ∫dt= [-2t-t²/2]0¹ - [2t + t²/2]0¹ + t0¹= (-2) - (-2) + 0= 0

Therefore, the work done by F(x, y, z) over C by the application of standard parametrisation is O (ti-tj + 2+ k).(-i +2j+k) dt (-ti + 2t j + tk) Vodt [ j+-i + ſ ' 1 (-j+28)• (-i + 23 + k) dt [ +• vo f (+3) • (-i ++k) (i- j +2k).(-ti + 2t j + tk) dt (-ti + 2t j + tk).(-i +2j + k) dt.

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The perimeter of the given rectangle is 4+2a.

Here, we have,

from the given figure we get,

the rectangle is with l = 2 and w = a

now, we know that,

perimeter of a rectangle is

P = 2(l+w)

so, Perimeter = 2(2+a)

                      = 4 + 2a

Hence, The perimeter of the given rectangle is 4+2a.

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The areas under the normal distribution are: a. 0.568. b. 0.252 c. 0.5 d. 0.309 e. 0.573.

a) To find the area to the left of 18:

Using the calculator or the standard normal distribution table, the area to the left of 18 is approximately 0.568.

b) To find the area to the left of 13, you need to calculate the z-score first. The z-score is (13 - 17) / 6 ≈ -0.667. Using a calculator or a standard normal distribution table, the area to the left of 13 is approximately 0.252.

c) To find the area to the right of 16, subtract the area to the left of 16 (which is 0.5) from 1. The area to the right of 16 is 1 - 0.5 = 0.5.

d) To find the area to the right of 20, calculate the z-score: (20 - 17) / 6 ≈ 0.5. Using a calculator or a standard normal distribution table, the area to the right of 20 is approximately 0.309.

e) To find the area between 13 and 22, calculate the z-scores for both values: (13 - 17) / 6 ≈ -0.667 and (22 - 17) / 6 ≈ 0.833. Then, find the area to the left of 13 and the area to the left of 22, and subtract the former from the latter.

Using a calculator or a standard normal distribution table, the area between 13 and 22 is approximately 0.573.

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