Find the area of a regularpolygon with 5 sides that has aside length of 6 inches and anapothem of 9 inches. Area = ?
Answers
SOLUTION
Write out the formula
[tex]\text{area of regular polygon=}\frac{A\text{ }\times P}{2}[/tex]where A= apothem and P= perimeter of the regular polygon
[tex]\begin{gathered} A=9in \\ P=6(5)=30in \\ \text{perimeter of the regular polygon is sum of all the lenght} \\ \text{the number of sides }\times the\text{ lenght of a side } \end{gathered}[/tex]The area of the regular polygon is
[tex]\frac{9\times30}{2}=9\times15=135in^2[/tex]Related Questions
GRAPH each triangle and CLASSIFY the triangle according to its sides and angles.
Answers
Answer:
[tex]\Delta CAT\text{ is an ISOSCELES triangle}[/tex]Explanation:
To properly classify the traingle, we need to get the length of the sides
To get the length of the sides, we need to get the distance between each two points using the distance between two points formula
Mathematically,we have the formula as:
[tex]D\text{ = }\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Where (x1,y1) refers to the coordiantes of the first point while (x2,y2) refers to the coordinates of the second point
let us get the coordinates of the individual points as seen from the plot shown
C (1,8)
A (5,10)
T (7,6)
So, let us find the distance between each two points
For AC, we have:
[tex]D\text{ = }\sqrt[]{(5-1)^2+(10-8)^2}\text{ = }\sqrt[]{20}[/tex]For AT, we have:
[tex]D=\sqrt[]{(7-5)^2+(6-10)^2\text{ }}\text{ = }\sqrt[]{20}[/tex]Lastly, for CT, we have:
[tex]D\text{ = }\sqrt[]{(7-1)^2+(6-8)^2\text{ }}\text{ = }\sqrt[]{40}[/tex]From our calculations, we can see that AC = AT
If we have a triangle which has two of its sides equal in length (the angle facing these sides would be same too), we call this an isosceles triangle
So, the class of triangle CAT is isosceles triangle
I will attach a picture to this question so you can understand it better.
Answers
Here are the given information:
1. 7 red beads for every 4 blue beads
2. total of 44 beads (red and blue)
Find: the number of red beads
Solution:
We can solve this in two ways. We can solve this using proportion or we can solve this by counting.
Let's start counting first. Let's say 7 red beads and 4 blue beads is 1 set. So, for every set, we already have 7 + 4 = 11 beads in total.
First set = 7 red bead + 4 blue beads = 11 beads
Second set = 7 red bead + 4 blue beads = 11 beads
Third set = 7 red bead + 4 blue beads = 11 beads
Fourth set = 7 red bead + 4 blue beads = 11 beads
If we add all the 4 sets, we have a total of 44 beads. If we add all the RED beads only, we get 7 red beads x 4 sets = 28 red beads.
Therefore, Lily used 28 red beads.
Now, using proportion, we can have this equation:
[tex]\frac{7\text{red beads}}{4\text{blue bead}}=\frac{x\text{ red beads}}{(44-x\text{ red)blue beads}}[/tex]where x = the total number of red beads and we got 44 - x as the number of blue beads.
The next thing that we need to do here is to solve for x.
1. To solve for x, do cross multiplication first.
[tex]7(44-x)=4x[/tex]2. Multiply 7 to the numbers inside the parenthesis.
[tex]308-7x=4x[/tex]3. Add 7x on both sides of the equation.
[tex]\begin{gathered} 308-7x+7x=4x+7x \\ 308=11x \end{gathered}[/tex]4. Lastly, divide both sides by 11.
[tex]\begin{gathered} \frac{308}{11}=\frac{11x}{11} \\ 28=x \end{gathered}[/tex]As we can see, the value of x = 28. Lily used 28 red beads.
Graph a right triangle with the two points forming the hypotenuse. Using the sides,find the distance between the two points in simplest radical form.
Answers
Answer:
Explanation:
Given the points:
[tex](7,-5)\text{ and }(2,-7)[/tex]The graphed right triangle is given below:
Using the sides, we then find the distance between the two points, d.
By the Pythagorean theorem:
[tex]\begin{gathered} d^2=[5-(-7)]^2+[7-2]^2 \\ d^2=[5+7]^2+5^2 \\ d^2=12^2+5^2 \\ d^2=144+25 \\ d^2=169 \\ d^2=13^2 \\ \implies d=13 \end{gathered}[/tex]The distance between the two poi
The force of gravity is 6 times greater on the earth than it is on the moon. What is the weight of a 150-pound man on the moon?
Answers
The force of gravity on the Earth is equal to 9.8m/s².
Now, if the force of gravity on the moon is 6 times lesser than Earth's gravity.
Then,
The weight of a 150-pound man on the moon is:
150-pound/ 6
= 25-pounds
Hence, the weight of the man is 25-pounds
Find the sum of the first 7 terms of the following sequence. Round to the nearest hundredth if necessary.5,−2,45,...5,−2, 54 ,...Sum of a finite geometric series:Sum of a finite geometric series:Sn=a1−a1rn1−rS n = 1−ra 1 −a 1 r n
Answers
Solution:
Given:
[tex]5,-2,\frac{4}{5},\ldots[/tex]To get the sum of the first 7 terms, the formula below is used;
[tex]S_n=\frac{a_1-a_1r^n}{1-r}[/tex]where;
[tex]\begin{gathered} n=7 \\ a_1\text{ is the first term = 5} \\ r\text{ is the co}mmon\text{ ratio=}\frac{-2}{5} \end{gathered}[/tex]Hence,
[tex]\begin{gathered} S_n=\frac{a_1-a_1r^n}{1-r} \\ S_7=\frac{5-5(-\frac{2}{5})^7}{1-(-\frac{2}{5})} \\ S_7=\frac{5-5(-0.4)^7}{1+\frac{2}{5}} \\ S_7=\frac{5-5(-0.0016384)}{1+0.4} \\ S_7=\frac{5+0.008192}{1.4} \\ S_7=\frac{5.008192}{1.4} \\ S_7=3.57728 \end{gathered}[/tex]Therefore, the sum of the first 7 terms is 3.57728
Find the circumference of each circle .(use 22/7 as an approximation for PI
Answers
Let us find the circumference of each circle.
The circumference of a circle is given by
[tex]C=2\pi r\: \: or\: \: C=\pi D[/tex]Where r is the radius and D is the diameter of the circle.
Circle 1:
Here we are given the diameter of the circle
D = 21 cm
[tex]C=\pi D=\frac{22}{7}\cdot21=22\cdot3=66\operatorname{cm}[/tex]So, the circumference of the circle is 66 cm.
Circle 2:
Here we are given the diameter of the circle
D = 91 ft
[tex]C=\pi D=\frac{22}{7}\cdot91=286\: ft[/tex]So, the circumference of the circle is 286 ft.
Circle 3:
hello can you help me with this question and this a homework assignment
Answers
Problem
Solution
For this case we can use the Cosine law and we have:
[tex]\cos (c)=\frac{a^2+b^2-c^2}{2ab}=\frac{35^2+56^2-33^2}{2\cdot35\cdot56}=0.8346938776[/tex][tex]\cos (b)=\frac{a^2+c^2-b^2}{2ac}=\frac{35^2+33^2-56^2}{2\cdot35\cdot33}=-0.356[/tex][tex]\cos (a)=\frac{c^2+b^2-a^2}{2cb}=\frac{33^2+56^2-35^2}{2\cdot33\cdot56}=0.8116883117[/tex]And then we can find the angles with the arcos like this:
[tex]<\gamma=ar\cos (0.8346938776)=33.42[/tex][tex]<\beta=ar\cos (-0.356)=110.85[/tex][tex]<\alpha=ar\cos (0.8116883117)=35.74[/tex]Can you see the new values for gamma and alfa
Vernon mixed 2 1/3 cups of water with 2 1/3 of white vinegar to make a cleaning solution.how much cleaning solution did he make
Answers
SOLUTION
Write out the information given
[tex]\begin{gathered} \text{Quantity of water=2}\frac{1}{3}cups\text{ } \\ \\ \text{Quantity of white vinegar=2}\frac{1}{3}cups \end{gathered}[/tex]The quantity of the cleaning solution will the sum of the quantity above
The number model will be
[tex]2\frac{1}{3}cups+2\frac{1}{3}\text{cups }[/tex]Then
[tex]\begin{gathered} 2\frac{1}{3}+2\frac{1}{3}=2\times(2\frac{1}{3})=2\times(\frac{7}{3})=\frac{14}{3} \\ \text{then} \\ \frac{14}{3}=4\frac{2}{3} \end{gathered}[/tex]hence the cleaning solution will be
[tex]4\frac{2}{3}[/tex]Answer: 4 2/3
Number 14. Need help finding the area of the shaded area. Forgot how to solve it. Please help.
Answers
To find the area of the shaded region we need to calculate the area of the square and subtract to it the area of the circle.
The area of a square is calculated as follows:
[tex]A=b^2[/tex]where b is the length of each side.
Substituting with b = 16 cm (given that the radius of the circle is 8 cm, then the length of the square's side is 2x8 = 16 cm):
[tex]\begin{gathered} A_1=16^2 \\ A_1=256\operatorname{cm}^2 \end{gathered}[/tex]The area of a circle is calculated as follows:
[tex]A=\pi r^2[/tex]where r is the radius of the circle.
Substituting with r = 8 cm, we get:
[tex]\begin{gathered} A_2=\pi\cdot8^2 \\ A_2=\pi\cdot64 \\ A_2\approx201\operatorname{cm}^2 \end{gathered}[/tex]Finally, the area of the shaded region is:
[tex]\begin{gathered} A_3=A_1-A_2 \\ A_3=256-201 \\ A_3=55\operatorname{cm}^2 \end{gathered}[/tex]Simplify the following sum of polynomials completely ( - 12s raise to power 2 + 10s - 3) + ( 2s raise to power 2 - 12s - 2)
Answers
ANSWER
[tex]-10s^2-2s-5[/tex]EXPLANATION
Given
[tex]\mleft(-12s^2+10s-3\mright)+\mleft(2s^2-12s-2\mright)[/tex]removing the brackets, we have;
[tex]-12s^2+10s-3+2s^2-12s-2[/tex]collecting like terms, we have
[tex]\begin{gathered} -12s^2+2s^2+10s-12s-3-2 \\ \end{gathered}[/tex]adding similar terms, we have;
[tex]-10s^2-2s-5[/tex]The solution is
[tex]-10s^2-2s-5[/tex]what is the value of the expression below when w=2 8w+10
Answers
Given the expression:
8w + 10
To find the value when w = 2, we need to substitute 2 for w in the expression.
Therfore, we have:
[tex]8(2)\text{ + 10}[/tex][tex]16\text{ + 10 = 26}[/tex]Therefore, the value of the expression when w = 2 is 26
ANSWER:
26
Solve the triangle: a = 25, C = 25, B = 25°. If it is not possible, say so.A=25*,b= 25, C = 250A=77.5*,b=10.8, C = 77.5eA=77.5', b = 24.1, C = 77.5This triangle is not solvable.
Answers
We will have the following:
First:
Since we have that sides a & c have the same length by theorem angles A & C are equal, so the following is true:
[tex]A+B+C=180\Rightarrow2A+B=180[/tex][tex]\Rightarrow2A=180-25\Rightarrow A=77.5[/tex]so, angles A & C have a measure of 77.5°.
*Second: We determine the measurement f the segment b, that is:
[tex]\frac{b}{\sin(25)}=\frac{25}{\sin(77.5)}\Rightarrow b=\frac{25\sin (25)}{\sin (77.5)}[/tex][tex]\Rightarrow b=10.8219807\Rightarrow b\approx10.8[/tex]So we will have that the measurements are:
A = 77.5°
b = 10.8
C = 77.5°
[Option B]
Identify the minimum from the tableType your answer as an ordered pair (x,y)
Answers
By definition, a function is a relation in which each input value has one and only one output value.
The input values are also known as x-values and the output values are also called y-values.
By definition, the Minimum is the lower point of the function.
Having the table shown in the exercise, you can identify the following points:
[tex]\begin{gathered} (-2,10) \\ (-1,8) \\ (0,6) \\ (1,4) \end{gathered}[/tex]You can identify that the lower y-value of all those points is:
[tex]y=4[/tex]Therefore, you can determine that the lower point of the function is:
[tex](1,4)[/tex]The answer is:
[tex](1,4)[/tex]please help me work through this, thank you! it specifies to round to 2 decimal places
Answers
Since they will collide the time taken for both to reach the intersection is the same.
Let the time taken by t.
Recall that for steady motion,
[tex]\begin{gathered} d=st \\ \text{ Where:} \\ d=\text{ the distance covered} \\ s=\text{ the speed} \\ t=\text{ the time} \end{gathered}[/tex]Substitute d = 4 and s = 442 into the equation:
[tex]\begin{gathered} 4=442t \\ \text{ Dividing both sides by }442,\text{ it follows that:} \\ t=\frac{4}{442} \end{gathered}[/tex]Therefore, the distance covered by the Coyote in this time is given by:
[tex]d=\frac{4}{442}\times481=\frac{74}{17}[/tex]Using the Pythagorean Rule, it follows that the distance between Road Runner and the Coyote along the diagonal is given by:
[tex]h=\sqrt{(\frac{74}{17})^2+4^2}[/tex]Since speed s for a body that travelled distance d in time t is given by:
[tex]s=\frac{d}{t}[/tex]it follows that the required speed is given by:
[tex]-\sqrt{(\frac{74}{17})^2+4^2}\times\frac{442}{4}=-65\sqrt{101}[/tex]Therefore, the required rate is -65√101 kph.
Using f(x) = 2x - 3 and g(x) = 5, find f(g(3)).7530None of the choices are correct.I don’t think my answer is right please help me thank you
Answers
As per given by the question,
There are given that function,
[tex]\begin{gathered} f(x)=2x-3,\text{ } \\ g(x)=5 \end{gathered}[/tex]Now,
Find the value of f(g(3)).
Then,
There are given that,
[tex]g(x)=5[/tex]And,
According to question, value of x is 3, that means g(3).
So,
Put the value of x in g(x).
Then,
[tex]\begin{gathered} g(x)=5 \\ g(3)=5 \end{gathered}[/tex]Now,
For find the value f(g(3));
Put the value of g(3) in the above condition,
f(g(3)).
So,
[tex]f(x)=2x-3[/tex]Instead of x in f(x), put the g(3).
Then,
[tex]\begin{gathered} f(g(3))=2x-3 \\ f(5)=2\times5-3 \\ f(5)=10-3 \\ f(5)=7 \end{gathered}[/tex]So, the value of f(g(x)) is 7.
Hence, the option first is correct.
5. What is the range of the graph?8all real numbers{y 1-1 sys1)(XI-15x51){x | xs-1 or x 21)
Answers
The correct option is option D
For more comprehension,
Option D is :
[tex]undefined[/tex]Question 6 What is the factored form of the expression below? 7 - 16 O OD (x-8)(x - 8) (x - 4)(x + 4) (x - 4)(x - 4) (x-8)(x + 8) Oo
Answers
If :
[tex]x^2-16[/tex][tex]\begin{gathered} \sqrt[]{x^2}=x \\ \sqrt[]{16}=4 \end{gathered}[/tex]Then:
[tex]x^2-16\text{ =(x-4)(x+4)}[/tex]Answer: ( x - 4 ) ( x + 4 )
What is the solution set of x² + 5x - 5 = 0?
Answers
The solution of x² + 5x - 5 = 0 is :
x = 0.854 and -5.854 .
Solution:
Here given equation,
x2 + 5x - 5 = 0
To solve the given equation use quadratic formula,
Using the quadratic formula,
x = [-b ± [tex]\sqrt{b2 - 4ac}[/tex] ] /2a
Here,
a = 1, b = 5 and c = -5
By substituting,
x = [-5 ± [tex]\sqrt{52 - 4(1)(-5)}[/tex] ] /2(1)
= [-5 ± √[tex]\sqrt{25 + 20}[/tex]] /2
= [-5 ± √45] /2
= [-5 ± 6.708] /2
So,
x = (-5 - 6.708)/2
= -11.708/2
= -5.854
= (-5 + 6.708)/2
= 1.708/2
= 0.854
∴ the solutions of equation is : 0.854 and -5.854.
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Any equation that can be rearranged in standard form as follows, where x stands for, is referred to be a quadratic equation in algebra.
What constitutes the x2 + 5x - 5 = 0 solution set?
We must figure out the equation's answer. The answers to the problem are thus 0.854 and -5.854. x^2 + 5x - 5 = 0
It is impossible to factor a quadratic equation like this one. It can be resolved either by completing the square or by applying the quadratic formula.
x = (-b +-sqrt(b2 - 4ac))/2a is the quadratic formula, where an is the coefficient of the x2, b is the coefficient of the x, and c is the constant.
a = 1, b = 5, c = -5
x = (-5 +- sqrt(25+20))/2
x = (-5 +- sqrt(45))/2
x = (-5 + - 3 sqt 5))/2
x = (-5 + 3sqrt5)/2 as well as x = (-5 - 3sqrt5)/2.
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Look at the first Model It. In the first place-value chart, why is the thousandths column for the decimal 5.67 empty?
Answers
The thousandths column for the decimal 5.67 is empty because there's no thousandth value in the decimal.
What is a place value?Place value is the value provided by a digit in a number based on its place in the number. For example, 7 hundreds or 700 is the place value of 7 in 3,743. Place value is the value provided by a digit in a number based on its place in the number.
In this case, the decimal that's given is illustrated as 5.67. It should be noted that 6 is the tenths value and 7 is the hundredth value. Therefore, there is no thousandth value. This is why it's empty.
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In 2012 the total population of individuals in the
United States who were between 14 and 17 years old
(inclusive) was about 17 million. If the survey results
are used to estimate information about summer
employment of teenagers across the country, which
of the following is the best estimate of the total
number of individuals between 16 and 17 years old in
the United States who had a summer job in 2012?
Answers
Answer:
Its B I'm not to good at explaining but I've done my math
Step-by-step explanation:
and its b just trust me
Takashi is driving to his grandmother's house. he is driving at a constant speed and will not make any stops along the way. Takashi’s distance in miles from his grandmother’s house h hours after leaving can be described by equationA. Identify and interpret the independent variable? B. Identify and interpret the coefficient? C. Identify and interpret the constant term ?D. Identify and interpret the dependent variable?
Answers
Let's begin by listing out the information given to us:
To calculate Takashi's distance from his grandmother's house is given by the formula:
[tex]\begin{gathered} distance=speed\cdot time \\ h=v\cdot t \end{gathered}[/tex]Independent variable refers to the variable that stands by itself and whose value is not affected by the other
Dependent variable refers to the variable whose value is affected by the value of another variable
A. The distance (h) does not change irrespective of Takashi's speed, hence it is the independent variable
B. The coefficient is the speed (v)
C. The constant is time (t)
D. The speed (v) changes with variation in time, hence it is the dependent variable
find the value or measure. Assume all lines that appear to be tangent are tangent. mPM=
Answers
Segments that crosses around a circle
MN ^2 = OP • ON
mm
then 59° = (
Consider the following relation: (1,12) ,(3, 8) , (3, 11) , (6, 9) , (7, 11) . Whichordered pair could be removed so thatthe relation is a function?Group of answer choices
Answers
Answer: Rajesh Kumar
Step-by-step explanation I took the wok to poland
Write a mathematical sentence that expresses the information given below. Use b as your variable name. If necessary:
type < = to mean
or > = to mean .
If you need to show multiplication, do not use the letter x. Use the asterisk ( * ) symbol instead, or simplify your answer.
Emily has 300 books. If Frank were to double the number of books that he now owns, he would still have fewer than Emily has.
Answers
The number of books owned by frank is represented as b < 150
What is inequality?Inequality represents the form of writing expressions where the left hand side of the expression is not exactly equal to the right hand side of the expression
How to represent the required expressionInformation gotten from the data include
Emily has 300 books
Frank were to double the number of books that he now owns, he would still have fewer than Emily has.
Let the number of books owned by frank be b and from the information we have that:
2b < 300
b < 150
hence the number of books owned by frank, b less than 150
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For her phone service, Mai pays a monthly fee of $19, and she pays an additional $0.04 per minute of use. The least she has been charged in a month is$70.28. What are the possible numbers of minutes she has used her phone in a month?
Answers
We have a phone service fee which can be divided in:
- A fixed fee of $19 per month.
- A variable fee of $0.04 per minute, so that the cost for m minutes is 0.04*m.
We can add the two fees to express the total cost in function of the minutes as:
[tex]C(m)=19+0.04m[/tex]For a month where the cost is C(m) = 70.28, we can calculate the minutes as:
[tex]\begin{gathered} C(m)=70.28 \\ 19+0.04m=70.28 \\ 0.04m=70.28-19 \\ 0.04m=51.28 \\ m=\frac{51.28}{0.04} \\ m=1282 \end{gathered}[/tex]Answer: if she pays at least $70.28, she has talked at least m = 1282 minutes per month.
1. Abby baked 2-dozen brownies. She took 1 dozen to her scout meeting. Her family ate 8, and she put the rest in a container in the refrigerator. How can Abby find the number of brownies left in the refrigerator?
Answers
The number of brownies left in the refrigerator is 4.
How to calculate the value?It's important to note that 1 dozen = 12
In this case, Abby baked 2-dozen brownies, she took 1 dozen to her scout meeting and her family ate 8, and she put the rest in a container in the refrigerator.
Therefore, the remaining amount will be:
= 2 dozens - 1. dozen - 8
= (2 × 12) - 12 - 8
= 24 - 12 - 8
= 4
There'll be 4 left. This illustrates the concept of subtraction.
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Which answer shows how to solve the given equation using the quadratic formula? 22 - 3. - 4= 0 3+, 22-4(2)(-4) 2(2) -(-3)=1/(-3)2-4(2)(-4) 2(2) 4+/(-3) -4(2)(-4) 2 3+1/32-4(-3)(-4) 2(2)
Answers
hello
the question here is a given quadratic equation and we're required to use quadratic formula to solve it.
[tex]2x^2-3x-4=0[/tex]now, to solve this, let's bring out quadratic formula first
[tex]x=-b\pm\frac{\sqrt[]{b^2-4ac}}{2a}[/tex]now from our equation given, we can easily identify a, b and c.
[tex]\begin{gathered} 2x^2-3x-4=0 \\ a=2 \\ b=-3 \\ c=-4 \end{gathered}[/tex]next we plug in the variables into the equation and solve
[tex]undefined[/tex]Graph v (standard position) and find its magnitude. Show all work.
Answers
EXPLANATION
[tex]\mathrm{Computing\: the\: Euclidean\: Length\: of\: a\: vector}\colon\quad \mleft|\mleft(x_1\: ,\: \: \ldots\: ,\: \: x_n\mright)\mright|=\sqrt{\sum_{i=1}^n\left|x_i\right|^2}[/tex][tex]=\sqrt{2^2+5^2}[/tex][tex]=\sqrt{4+5^2}[/tex][tex]=\sqrt{4+25}[/tex][tex]=\sqrt{29}[/tex]Now, we need to graph the vector as shown as follows:
Convert each slope-intercept or point slope equation into standard form.
y - 3 = 1/5(x + 6)
Answers
The Standard form of the equation will be as x - 5y = -21
What is Standard form of equation?The standard form of the equation is defined as; Ax + By = C
Where, A, B and C are integers.
Given that the equation in slope - intercept form is;
⇒ y - 3 = 1/5 (x + 6)
Now,
We need to convert the equation in standard form as;
⇒ y - 3 = 1/5 (x + 6)
Now Change into standard form as;
⇒ y - 3 = 1/5 (x + 6)
Then Multiply by 5 both side, we get:
⇒ 5( y - 3) = (x + 6)
⇒ 5y - 15 = x + 6
⇒ 5y = x + 21
Now Subtract 21 both side, we get:
⇒ 5y - 21 = x + 21 - 21
⇒ 5y - 21 = x
⇒ - 21 = x - 5y
⇒ x - 5y = -21
Therefore,
The Standard form of the equation will be as x - 5y = -21
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It is question 16 pls help
Answers
Answer: yes it is 16 i did my work let me know if you want me to show my work
Step-by-step explanation: