Find the 9th term of the geometric sequence 4, 16, 64, ...

Answers

Answer 1

Answer: Just keep multiplying by 4 after 64 like multiply 64 times 4 and do that number times  and keep doing that until its the 9th answer :)

Step-by-step explanation:

Answer 2

A geometric series is the sum of an unlimited number of terms with a fixed ratio between them. The 9th term of the geometric sequence 4, 16, 64, ... is 262,144.

What is geometrical series?

A geometric series is the sum of an unlimited number of terms with a fixed ratio between them.

The first term of the series is 4, while the ratio of the geometric sequence:

[tex]\rm Ratio, r = \dfrac{16}{4} = 4[/tex]

Thus, the 9th term of the geometric series can be written as,

[tex]a_n = a_1 \times r^{(n-1)}\\\\a_9 = 4 \times 4^8\\\\a_9 = 262,144[/tex]

Hence, the 9th term of the geometric sequence 4, 16, 64, ... is 262,144.

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Related Questions

The length of XY is 24 centimeters. The midpoint of XY is M, and C is on XM so that XD is 2/3 of XM. Point D is on MY so that MD is 3/4 of MY. What is the length of CD?

The length of CD is centimeters​

Answers

Answer:

  CD = 13 cm

Step-by-step explanation:

We assume you intend XC = 2/3 of XM, since XD cannot be that fraction of XM.

__

Of course XM = MY = 12, since M is the midpoint of a segment 24 cm long. Then 2/3 of XM is 8 cm, and 3/4 of MY is 9 cm.

  CD = CM + MD = 4 cm + 9 cm

  CD = 13 cm

NEED HELP ASAP!!! name each angle in as many ways different as possible

Answers

JGL,LGJ, GJ, GL are the four angles

how do i math? plssssssssssssssssss answer

Answers

Answer:

you just math you know pretty easy when you know what to do

Step-by-step explanation:

just practice

Two jugs and 4 bottles hold 40 ounces. One jug and 3 bottles hold 25 ounces. How many ounces does 1 jug hold?

Answers

Answer:

5 ounces

Step-by-step explanation:

Let the capacity of jug be j, bottle be b

[tex]2j + 4b = 40 \\ j + 3b = 25 \\ j = 25 - 3b \\ \\ therefore \: 50 - 6b + 4b = 40 \\ 2b = 10 \\ b = 5[/tex]

HELP PLZ AND.... HIIIII!

Answers

Answer:

0.002 meters per second

Answer: 0.0002 meters per second

The temperature in Miami, Florida is 22 degrees warmer than three times the temperature in Bangor, Maine. The temperature in Miami is 82 degrees. Write an equation to determine the temperature in Bangor.

Answers

Answer:

See Explanation

Step-by-step explanation:

Let the temperatures of Miami and Bangor be M and B degrees respectively.

According to the given information:

M = 3B + 22... (required equation)

Plug M = 82

82 = 3B + 22

82 - 22 = 3B

60 = 3B

B = 60/3

B = 20 degrees

Thus, the temperature in Bangor is 20 degrees.

The required temperature in Bangor is 52 degrees and the required equation is 82 = 3B + - 22.

Given that,
The temperature in Miami, Florida is 22 degrees warmer than three times the temperature in Bangor, Maine.
The temperature in Miami is 82 degrees.
An equation to determine the temperature in Bangor is to be determined.

What is arithmetic?

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,

Here,
Let the temperature in Bangor be B
The temperature in Miami is 82 degrees.
The temperature in Miami, Florida is 22 degrees warmer than three times the temperature in Bangor. Implies,

82 = 3B + - 22
3B = 82 + 22
3B = 104
B = 52 degrees

Thus, the required temperature in Bangor is 52 degrees.

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Which equation must be true for m(x) and n(x) to be inverse?

Answers

Answer:

  see below

Step-by-step explanation:

When the functions are inverses of each other, it will be true that ...

  m(n(x)) = n(m(x)) = x

The expanded form of this equation is shown below.

Write 1,762 in scientific notation.
A. 1.762 x 10>4
B. 1.762 x 10>3
C. 17.62 x 10>3
D. 17.62 x 10>1

Answers

Hey there!☺

[tex]Answer:\boxed{1.762\times10^3}[/tex]

[tex]Explanation:[/tex]

1,762 in scientific notation would be written like this:

[tex]1,762\times10^3[/tex]

Hope this helps!

Answer:

B

Step-by-step explanation:

Evaluate –32 + (2 – 6)(10)

Answers

Answer:

-72

Step-by-step explanation:

-32 + (2-6)(10)

-32 + (-4)(10)

-32 + -40

-72

Answer:

-72

Step-by-step explanation:

Use PEMDAS and solve from left to right.

2 - 6 = -4

Parenthesis means multiplication.

-4 x 10 = -40

Then you add the negatives.

-32 + -40 or

-32 - 40 = -72

put these numbers -23, 2, 0.7, 5, 16,0, 3.89, -4 in sections of rational, irrational, whole numbers, and integers

Answers

Vocabulary Check:

Integers are numbers that are neither fractions nor decimals.

Rational numbers are numbers that can be written as a fraction, unlike irrational numbers. Whole numbers are counting numbers, including 0.

Integers = -23, 2, 3, 16, 0, -4

Whole Numbers = 0, 2, 3, 16

Rational = -23, 2, 0.7, 5, 16, 0, 3.89, -4

Irrational: None

Use the distributive property to write an equivalent variable expression. -5(5q - 4)

Answers

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The speed limit for Stadium Drive is 45 miles per hour. Generate at least 3 different interpretations of the rate 45 miles per hour. Provide support/reasoning for each of your answers.

Answers

Step-by-step explanation:

The solution to this problem requires that we find other units besides the given one

1. ft/sec

2. km/h

3.m/s

1. converting to ft/sec

1 mile is 5280 ft

[tex]=\frac{45mile}{hour}* \frac{5280feet}{1 mile} *\frac{1 hours}{3600 secs} \\\\=66 ft/sec[/tex]

2. converting to km/h

1 mile is 1.60934

[tex]=\frac{45mile}{hour}* \frac{1.60934km}{1 mile} *\frac{1 hours}{1hour} \\\\=72.42km/h[/tex]

3. converting to m/s

1 mile is 1609.34

[tex]=\frac{45mile}{hour}* \frac{1609.34km}{1 mile} *\frac{1 hours}{3600 sec} \\\\=20.11m/s[/tex]

A car depreciated $1000 each year it was owned and driven. What type of depreciation is this?
A. Straight-line depreciation

B. Flat depreciation

C. Curved-line depreciation

D. Accelerated depreciation ​

Answers

Answer:

A. Straight-line depreciation

For a car depreciated $1000 each year it was owned and driven, it shows ''Straight-line depreciation.''

Option A is true.

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

A car depreciated $1000 each year it was owned and driven.

Since, A car depreciated $1000 each year it was owned and driven.

Hence, It shows Straight-line depreciation.

Thus, For a car depreciated $1000 each year it was owned and driven, it shows ''Straight-line depreciation.''

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Planes X and Y intersect at a right angle. Line A B and Line C G lie in plane X and do not intersect. Line R S lies in plane Y.

Vertical plane x intersects horizontal plane y. Line R S is horizontal on plane y. Lines A B and C G are vertical and beside each other on plane x. A right angle is indicated between the lines on the y plane and x plane. Lines A B and D G are parallel.

Which statements are true? Select three options.

Line A B and Line C G are parallel.
Line A B and Line R S are parallel.
Line C G and Line R S are perpendicular.
Line A B and Line R S must intersect.
Line segment C G lies in plane X.
Line segment R S lies in plane X.

Answers

Answer:

Line A B and Line C G are parallel.

Line C G and Line R S are perpendicular.

Line segment C G  lies in plane X.

Step-by-step explanation:

On my moma my answer 100%

The following statements are true:

Line AB and line CG are parallel.

Line CG and line RS are perpendicular.

Line segment CG lies in plane X.

What are parallel lines?

When the two lines lie in the same plane then they are said to be parallel lines.

Given information:

Planes X and Y intersect at a right angle.

Lies in plane X and do not intersect.

A) Line AB and Line CG are parallel: As both lines, AB and CG lie in plane X. Thus both are parallel and options A is the correct option.

B) Line AB and Line RS are parallel: As the line, AB lies in the plane X and the line RS lies in the plane Y. Thus both are perpendicular and not parallel. Option B is the incorrect option.

C)Line CG and Line RS are perpendiculars: As the line CG lies in the plane x and the line RS lies in the plane Y. Thus both are perpendicular. Option C is the correct option.

D) Line AB and Line RS must intersect: line RS passes from the middle of the plane Y and line AB passes from the left of the plane X centre. Thus they do not intersect each other. Option D is the incorrect option.

E) Line segment CG lies in plane X: As shown in the diagram, line CG lies in plane X. Thus option E is the correct option.

F) Line segment RS lies in plane X: As shown in the diagram, and the line lies RS in plane Y. Thus option F is the incorrect option.

Hence, the following statements  are true:

Line AB and line CG are parallel.

Line CG and line RS are perpendicular.

Line segment CG lies in plane X.

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Which choice correctly expresses the number below in scientific notation?

Answers

Answer:

I think 2nd option is correct

the answer is D because there is seven zeros

Find f '(a). f(x) = 1 − 2x

Answers

So the answer is f’(x)=1/1+2x

vertices of parallelogram ABCD are A(2, 0), B(4, 3), C(3, 1). How many possibilities are there for the position of the fourth vertex?

Answers

Answer:

1 possibility is there for the the position of the fourth vertex.

Before going to bed, Maria's
temperature was 103,2º. Her fever
broke in the night so that her
moming temperature was 3.7
degrees lower. What was Mana's
temperature the next morning?

Answers

Answer:

Her temperature was 99.5°

Step-by-step explanation:

103.2 - 3.7 = 99.5

Will mark Brainliest!!!!! Suppose A, R, and B are collinear on AB, and
AR: AB = 1/4 What are the coordinates of R?

Please give explanation

Answers

Answer:

[tex]R(x,y) = (\frac{7}{4},\frac{1}{4})[/tex]

Step-by-step explanation:

Given

[tex]A = (1,-1)[/tex]

[tex]B = (4,4)[/tex]

[tex]AR:AB = 1:4[/tex]

Required

Determine R

This question will be solved using line ratio formula

[tex]R(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2+ny_1}{m + n})[/tex]

Where

[tex]A = (1,-1)[/tex]

[tex]B = (4,4)[/tex]

[tex]m:n = AR : RB[/tex]

Since R is on A and B;

[tex]AB = AR + RB[/tex]

[tex]4 = 1 + RB[/tex]

[tex]RB = 3[/tex]

Hence;

[tex]m:n = 1 : 3[/tex]

[tex]A = (1,-1)[/tex]

[tex]B = (4,4)[/tex]

[tex]R(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2+ny_1}{m + n})[/tex] becomes

[tex]R(x,y) = (\frac{1 * 4 + 3 * 1}{1+3},\frac{1 * 4 + 3 * -1}{1 + 3})[/tex]

[tex]R(x,y) = (\frac{4 + 3}{4},\frac{4 - 3}{4})[/tex]

[tex]R(x,y) = (\frac{7}{4},\frac{1}{4})[/tex]

5p · 1 = 5p is what property

Answers

Answer:

034579+&_9&__78'_&666

(c) Given that the system has at least one type of defect, what is the probability that it has exactly one type of defect

Answers

Answer:

The probability is 0.357

Step-by-step explanation:

Given that,

The system has at least one type of defect,

Suppose, A certain system can experience three different types of defects.

Let [tex]A_{i}[/tex] (i = 1,2,3) denote the event that the system has a defect of type i.

Suppose that the following probabilities are,

[tex]P(A_{1})=0.11[/tex]

[tex]P(A_{2})=0.08[/tex]

[tex]P(A_{3})=0.05[/tex]

[tex]P(A_{1}\cup A_{2})=0.13[/tex]

[tex]P(A_{1}\cup A_{3})=0.13[/tex]

[tex]P(A_{2}\cup A_{3})=0.11[/tex]

[tex]P(A_{1}\cap A_{2}\cap A_{3})=0.01[/tex]

[tex]P(A_{1}\cap A_{2})=0.06[/tex]

[tex]P(A_{1}\cap A_{3})=0.03[/tex]

[tex]P(A_{2}\cap A_{3})=0.02[/tex]

[tex]P(A_{1}\cup A_{2}\cup A_{3})=0.14[/tex]

We need to calculate the probability that it has exactly one type of defect

Using given data

[tex]P=\dfrac{P(A_{1}\cap A_{2}'\cap A_{3}')}{P(A_{1}\cup A_{2}\cup A_{3})}+\dfrac{P(A_{1}'\cap A_{2}\cap A_{3}')}{P(A_{1}\cup A_{2}\cup A_{3})}+\dfrac{P(A_{1}'\cap A_{2}'\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]

[tex]P=\dfrac{P(A_{1})-P(A_{1}\cap A_{2})-P(A_{1}\cap A_{3})+P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex] + [tex]\dfrac{P(A_{2})-P(A_{1}\cap A_{2})-P(A_{2}\cap A_{3})+P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]+ [tex]\dfrac{P(A_{3})-P(A_{1}\cap A_{3})-P(A_{2}\cap A_{3})+P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]

P = [tex]\dfrac{P(A_{1})+P(A_{2})+P(A_{3})-2P(A_{1}\cap A_{2})-2P(A_{1}\cap A_{3})-2P(A_{2}\cap A_{3})+3P(A_{1}\cap A_{2}\cap A_{3})}{P(A_{1}\cup A_{2}\cup A_{3})}[/tex]

Put the value into the formula

[tex]P=\dfrac{0.11+0.08+0.05-2(0.06)-2(0.03)-2(0.02)+3(0.01)}{0.14}[/tex]

[tex]P=0.357[/tex]

Hence, The probability is 0.357

the square root of a number, less than nine (write into a verbal expression)

Answers

Answer: 9 - [tex]\sqrt{x}[/tex]

Step-by-step explanation:

Let say the number is x.

So the square root of x will  be [tex]\sqrt{x}[/tex]  and is less than 9  so we will subtract that from 9.

[tex]9-\sqrt{x}[/tex]

Find the next two terms of the sequence 1,5,14,30,50,...

Answers

Answer:

If the number were 55, then the next number is 72

Step-by-step explanation:

I think you wrote the number wrong?

I WILL MARK BRAINLIEST!!!

What is 178.80 as a fraction?

Answers

Answer: 178 4/5 or as an improper fraction 894/5

Hope this helps!

Please mark Brainliest!

Answer:

178.80 = 178 + 0.8 = 178 + 8/10
178 8/10 = 178 4/5 or 895/5

A box contains 8 white balls, 7 black balls, & 2 red balls.
a) how many red balls must be added to the box so that the probability of drawing a red ball is 8/9
b)how many black balls must be added to the original box so that the probability of drawing a white ball is 1/9?

Answers

Answer:

a) 118

b) 55

Step-by-step explanation:

a) Originally, there are 2 red balls and a total of 17 balls.

8/9 = (2 + x) / (17 + x)

8 (17 + x) = 9 (2 + x)

136 + 8x = 18 + 9x

x = 118

b) Originally, there are 8 white balls and a total of 17 balls.

1/9 = 8 / (17 + x)

17 + x = 72

x = 55

Evaluate –32 + (2 – 6)(10

Answers

Steps to solve:

-32 + (2 - 6)(10)

~Simplify

-32 + (-4)(10)

~Multiply

-32 - 40

~Subtract

-72

Best of Luck!

Answer:

The answer is -49

Step-by-step explanation:

The equation is: –32 + (2 – 6)(10).

Then u have to do PEMDAS

P=Parentheses

E=Exponents

M=Multiplication

D=Division

A=Addition

S=Subtraction

you follow the steps to get -49

What is the equation of a sine function with an amplitude of 2 and a period of 4

Answers

Answer: C

Step-by-step explanation:

For this problem, we need to know the standard form of a sine function and the meaning of each part.

Standard form: [tex]y=asin[b(x-h)]+k[/tex]

a=amplitude

b=period

h=phase shift

k=vertical replacement/shifting

Now that we know the standard form and the components, we know that we can forget about k and plug in 0 for h. This would leave us with [tex]y=asin[b(x)][/tex]. We know that the amplitude is 2, therefore, a=2. To find the period, you divide 2π by the given period. [tex]\frac{2\pi }{b} =\frac{2\pi }{4\pi } =\frac{2}{4} =\frac{1}{2}[/tex], therefore, b=1/2.

[tex]y=asin[b(x)][/tex]             [plug in a=2]

[tex]y=2sin[b(x)][/tex]             [plug in b=1/2]

[tex]y=2sin(\frac{1}{2}x)[/tex]

Therefore, C is the correct answer.

If Ben invests $3000 at 4% interest per year, how much additional money must he invest at 5.5 % annual interest to ensure that the interest he receives each year is 4.5 % of the total amount invested?

Answers

Answer:

$1500

Step-by-step explanation:

Investment 1 = $3000Interest 1 = 4%Investment 2 = xInterest 2 = 5.5%Total interest = 4.5%

Total interest:

3000*0.04 + x*0.055 = (3000+ x)*0.045    ⇒ multiply by 100 both sides3000*4 + 5.5x = 3000*4.5 + 4.5x                ⇒ parenthesis5.5x - 4.5x = 3000(4.5-4)                             ⇒ collect like termsx = 3000*0.5                                                ⇒ simplifyx = 1500                                                        ⇒ answer

Additional money is $1500

Please explain how this digraph works.

Answers

Angles XQL and MQR are congruent because they are vertical angles. So

209 - 13 b = 146 - 4 b

Solve for b :

209 - 13 b = 146 - 4 b

209 - 146 = 13 b - 4 b

63 = 9 b

b = 63/9 = 7

Then the measure of angle XQL is

(209 - 13*7)º = 118º

8×4-5×(3⅕-2½)+(4-1)²​

Answers

Answer:

101/2

Step-by-step explanation:

Answer:

75/2

Step-by-step explanation:

Simplify the following:

8×4 - 5 (3 + 1/5 - (2 + 1/2)) + (4 - 1)^2

Put 2 + 1/2 over the common denominator 2. 2 + 1/2 = (2×2)/2 + 1/2:

8×4 - 5 (3 + 1/5 - (2×2)/2 + 1/2) + (4 - 1)^2

2×2 = 4:

8×4 - 5 (3 + 1/5 - (4/2 + 1/2)) + (4 - 1)^2

4/2 + 1/2 = (4 + 1)/2:

8×4 - 5 (3 + 1/5 - (4 + 1)/2) + (4 - 1)^2

4 + 1 = 5:

8×4 - 5 (3 + 1/5 - 5/2) + (4 - 1)^2

Put 3 + 1/5 - 5/2 over the common denominator 10. 3 + 1/5 - 5/2 = (10×3)/10 + 2/10 + (5 (-5))/10:

8×4 - 5(10×3)/10 + 2/10 + (5 (-5))/10 + (4 - 1)^2

10×3 = 30:

8×4 - 5 (30/10 + 2/10 + (5 (-5))/10) + (4 - 1)^2

5 (-5) = -25:

8×4 - 5 (30/10 + 2/10 + (-25)/10) + (4 - 1)^2

30/10 + 2/10 - 25/10 = (30 + 2 - 25)/10:

8×4 - 5(30 + 2 - 25)/10 + (4 - 1)^2

30 + 2 = 32:

8×4 - 5 (32 - 25)/10 + (4 - 1)^2

| 2 | 12

| 3 | 2

- | 2 | 5

| 0 | 7:

8×4 - 5×7/10 + (4 - 1)^2

-5×7/10 = (-5×7)/10:

8×4 + (-5×7)/10 + (4 - 1)^2

The gcd of -5 and 10 is 5, so (-5×7)/10 = ((5 (-1)) 7)/(5×2) = 5/5×(-7)/2 = (-7)/2:

8×4 + (-1×7)/2 + (4 - 1)^2

4 - 1 = 3:

8×4 - 7/2 + 3^2

8×4 = 32:

32 - 7/2 + 3^2

3^2 = 9:

32 - 7/2 + 9

Put 32 - 7/2 + 9 over the common denominator 2. 32 - 7/2 + 9 = (2×32)/2 - 7/2 + (2×9)/2:

(2×32)/2 - 7/2 + (2×9)/2

2×32 = 64:

64/2 - 7/2 + (2×9)/2

2×9 = 18:

64/2 - 7/2 + 18/2

64/2 - 7/2 + 18/2 = (64 - 7 + 18)/2:

(64 - 7 + 18)/2

| 1 |  

| 6 | 4

+ | 1 | 8

| 8 | 2:

(82 - 7)/2

| 7 | 12

| 8 | 2

- | | 7

| 7 | 5:

Answer: 75/2

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