Find all numbers whose absolute value is .4]

Answers

Answer 1

The numbers 4 and - 4 have an absolute value equal to 4.

What numbers are associated to a given absolute value?

In this question we need to find all the numbers such that absolute value is equal to 4. This can be found by using the definition of absolute value:

|x| = x for x ≥ 0.|x| = - x for x < 0.

Absolute values are functions that contains only the magnitudes of the numbers, that is, their distances with respect to zero. Then, if the absolute value is 4, then, the number may be 4 or - 4.  

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Answer 2

The absolute value is 4, then, the number may be 4 or - 4.  

What are Absolute values?

Absolute value describes the distance from zero that a number is on the number line, without considering direction

To find all the numbers such that absolute value is equal to 4.

By definition of absolute value we have

|x| = x for x ≥ 0.

|x| = - x for x < 0.

Absolute values contains magnitude which does not have direction.

|4|=4 for 4≥ 0.

|4| = -4 for x < 0.

Then, if the absolute value is 4, then, the number may be 4 or - 4.  

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Related Questions

Michael earned some Money doing odd jobs last summer and put it in a savings account that earns 13% interest compounded quarterly after 2 years there is 100.00 in the account how much did Michael earn doing odd jobs

Answers

Michael earned some Money doing odd jobs last summer and put it in a savings account that earns 13% interest compounded quarterly after 2 years there is 100.00 in the account How much did Michael earn doing odd jobs​?

____________________________________

13% interest compounded quarterly

after 2 years there is 100.00

_________________________________-

interest compounded

A = P(1 + r/n)^nt

A= Final amount

P= Principal Amount

r= interest

n= number of compounding periods (year)

t= time (year)

_____________________

Data

A= 100.00

P= Principal Amount (The question)

r= interest (0.13)

n= number of compounding periods (4)

t= time (2)

_________________

Replacing

A = P(1 + r/n)nt

P = A / ((1 + r/n)^nt)

P = 100.00/ ((1 + 0.13/4)^4*5)

P= 100.00/ (1.0325^20)

P= 52

________________

Michael earns doing odd jobs 52 dollars.

Write the the function f(x) = -5(x + 5)² - 2 in the form f(x) = ax² +bx+c

Answers

[tex]-5(x+5)^2-2[/tex]

start expanding the squared expression using the square of a binomial,

[tex](a+b)^2=a^2+2\ast a\ast b+b^2[/tex]

then,

[tex]\begin{gathered} (x+5)^2=x^2+2\ast5\ast x+5^2 \\ (x+5)^2=x^2+10x+25 \end{gathered}[/tex]

replace in the original function

[tex]-5(x^2+10x+25)-2[/tex]

apply distributive and simplify

[tex]\begin{gathered} -5x^2-50x-125-2 \\ -5x^2-50x-127 \end{gathered}[/tex]

Answer:

[tex]-5x^2-50x-127[/tex]

An online bookstore is having a sale. All paperback books are $6.00 with a flat shipping fee of $1.25. you purchase "b" booms and your total is "c". What is the independent variable?$6.00"c" cost"b" books$1.25

Answers

Let:

c = total

a = cost of each book

w = flat shipping fee

Therefore, the total is given by:

[tex]c=ab+w[/tex]

where:

b = number of books

[tex]c=6x+1.25[/tex]

The independent variable is:

"b" books

Look at the circle below. D = 6 3What is the area of the circle if the diameter is 6 centimeters? Use 3.14 for pi. A 18.84 square centimetersB 28.26 square centimeters C 37.68 square centimeters D 113.04 square centimeters

Answers

we are asked to determine the area of a circle with a diameter of 6 cm. To do that we will use the following formula for the area of a circle:

[tex]A=\frac{\pi D^2}{4}[/tex]

Replacing the value of the radius:

[tex]A=\frac{\pi(6\operatorname{cm})^2}{4}[/tex]

Replacing the value of pi:

[tex]A=\frac{3.14(6\operatorname{cm})^2}{4}[/tex]

Solving the operations:

[tex]\begin{gathered} A=\frac{3.14(36cm^2)}{4} \\ \\ A=3.14(9cm^2)=28.26cm^2 \end{gathered}[/tex]

The initial directions are in the pic below. I’m sending 2 pics now. And the other 2 soon. For a total of 4.

Answers

Recall that the rule of transformation of a point reflected over the y-axis is as follows:

[tex](x,y)\rightarrow(-x,y).[/tex]

Therefore, the transformed coordinates of the vertices of the triangle are:

[tex]\begin{gathered} N(4,6)\rightarrow N^{\prime}(-4,6), \\ P(1,6)\rightarrow P^{\prime}(-1,6), \\ Q(3,4)\rightarrow Q^{\prime}(-3,4)\text{.} \end{gathered}[/tex]

Therefore, the image of the triangle is the triangle with the above vertices.

Answer:

a store sells gift cards in preset amount. You can purchase gift cards for $20 or $30 . You spent $380 on gift cards. let x be the number of gift cards for $20 And let y be your gift cards for $30 . Write an equation in standards for to represent this situation
ANSWER= 20x+30y=380
but what ab this one
What are three combinations of gift cards you could have​ purchased?

Answers

The equation that represent the situation is as follows:

20x + 30y = 380

The three combination of the gift cards you can purchase is as follows:

13 and 410 and 67 and 8

How to represent equation in standard form?

The store sells gift cards. One can purchase  gift cards for $20 or $30 .

You spent $380 on gift cards. let x be the number of gift cards for $20 And let y be your gift cards for $30 .

The equation in standard form to represent the situation is as follows:

The standard form of a linear equation is A x + By = C.  A, B, and C are

constants, while x and y are variables.

Therefore,

x = number of gift cards for 20 dollars

y = number of gift card for 30 dollars

Hence,

20x + 30y = 380

The three combination one could have purchased is as follows:

20(13) + 30(4) = 38020(10) + 30(6) = 38020(7) + 30(8) = 380

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given the parent function f (x) identify whether g (x) is a reflection about a horizontal line of reflection or vertical line of reflectionf (x) = 6^x and g (x) = - (6^x)

Answers

[tex]\begin{gathered} f(x)=6^x^{} \\ g(x)=-(6^x) \end{gathered}[/tex]

The relation between this two functions is g(x) = -f(x)

This means that g(x) is a reflection of f(x) about the x-axis, that is, a reflection about a horizontal line

Given the triangle ABC with the points A = ( 4, 6 ) B = ( 2, 8 ) C = ( 5, 10 ) and it's dilation, triangle A'B'C', with points A' = ( 2, 3 ) B' = ( 1, 4 ) C' = ( 2.5, 5 ) what is the scale factor?

Answers

Answer:

Explanation:

Given A = (4, 6) B = (2, 8) C = (5, 10)

[tex]\begin{gathered} AB=\sqrt{(2-4)^2+(8-6)^2} \\ \\ =\sqrt{8} \\ \\ BC=\sqrt{(5-2)^2+(10-8)^2} \\ \\ =\sqrt{8} \end{gathered}[/tex]

SImilarly, for A' = (2, 3) B' = (1, 4) C' = (2.5, 5)

[tex]\begin{gathered} A^{\prime}B^{\prime}=\sqrt{(1-2)^2+(4-3)^2} \\ \\ =\sqrt{2} \\ \\ B^{\prime}C^{\prime}=\sqrt{(2.5-1)^2+(5-4)^2} \\ \\ =\sqrt{3.25} \end{gathered}[/tex]

Since it is a dilation, AB/A'B' should be the same as BC/B'C', but that is not the case here.

Put these numbers in order from least to greatest. -27/36, 6, 18/40, 5/20

Answers

We have four numbers. We have to know that negative numbers are "smaller" than positive numbers, and when numbers are far away from zero are even "bigger".

The least number is -27/36. It is a negative number.

We can also see that we have some fractions. A fraction is a part of "a whole".

So, as we can see 6 is not a fraction. Therefore, 6 is the greatest number from this list.

So we have the least and the greatest: -27/36 and 6, respectively.

We also need to compare 18/40 and 5/20. What fraction is bigger?

In order to compare them, we need to have two fractions with the same denominator. Then, the fraction with the greatest numerator is "bigger" than the other fraction.

Let us see:

If we divide the numerator and the denominator of 18/40 by 2, we have:

18/2 = 9

40/2 = 20

Then, the equivalent fraction is 9/20 (or 9/20 is equivalent to 18/40). Now, we can compare them:

9/20 and 5/20. So, which one is the greatest? The one with the greatest numerator: 9/20.

Our final list is this way, from least to the greatest as follows:

-27/36, 5/20, 18/40 (9/20), 6.

three more than the difference of five and a number

Answers

5x + 3
hope this helped

Answer:

5x+3

Step-by-step explanation:

Three more than means we add 3

The product of 5 and a number means some number multiplied by 5 call it 5x

so three more than 5x is 5x+3.

Mr. Edmonds is packing school lunches for a field trip for the 6th graders of Apollo Middle school. He has 50 apples and 40 bananas chips. Each group of students will be given one bag containing all of their lunches for the day. Mr. Edmonds wants to put the same number of apples and the same number of bananas in each bag of lunches. What is the greatest number of bags of lunches Mr. Edmonds can make? How many apples and bananas will be in each bag?

Answers

The greatest number of bags of lunches Mr. Edmonds can make = 40, And , in each bag there will be one apple and one banana chips bag.

In the above question, the following information is given :

Mr. Edmonds wants to pack lunches for the schools field trip where he wants to put the same number of apples and the same number of bananas in each bag of lunches

We are given that,

Number of available bananas chips packs = 40

Number of available apples = 50

We need to find the greatest number of bags of lunches Mr. Edmonds can make

As the pair should be an even number and we have less number of banana chips bags than apples. So the number of lunches which can be packed with equal number of apples and banana chips bags depend on banana chips bags

Therefore, the greatest number of bags of lunches Mr. Edmonds can make = 40

And , in each bag there will be one apple and one banana chips bag.

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A ball bounces to a height of 6.1 feet on the first bounce. Each subsequent bounce reaches a height that is 82% of the previous bounce. What is the height, in feet, of the fifth bounce? Round your answer to the thousandths place.

Answers

In the first bounce, the height is

[tex]6.1\times(0.82)^0=6.1[/tex]

In the second bounce, the height is

[tex]6.1\times(0.82)^2=5.002[/tex]

Then, we can note that the pattern is

[tex]6.1\times(0.82)^{n-1}[/tex]

where n represents the number of bounces of the ball. Then, for n=5 (fifth bounce), we get

[tex]\begin{gathered} 6.1\times(0.82)^{5-1} \\ 6.1\times(0.82)^4 \end{gathered}[/tex]

which gives

[tex]6.1\times(0.82)^4=2.7579[/tex]

Therefore, by rounding to the nearest thousandths, the answer is 2.758 feet

0. Taylor earned the following amount each day. One dollar on the first day Three dollars on the second day Nine dollars on the third day Twenty-seven dollars on the fourth day

Answers

Question:

Solution:

Answer:

[tex]f(t)=3^{(t-1)}[/tex]

Step-by-step explanation:

one dollar of the first day = 3^0

three dollars on the second day = 3^1

nine dollars on the third day = 3^2

twenty-seven dollars on the fourth day = 3^3

Numbers increase 3 times a day, it is an exponential function, powers of 3

The function is going to be:

[tex]f(t)=3^{(t-1)}[/tex]

Use the sample data and confidence level given below to complete parts (a) through (d). A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4519 patients treated with the drug. 133 developed the adverse reaction of nausea Construct a 90% confidence interval for the proportion of adverse reactions. a) Find the best point estimate of the population proportion p.

Answers

We will have the following:

*First: We determine the standard deviation of the statistic, this is:

[tex]\sigma=\sqrt[]{\frac{\sum ^{133}_1(x_i-\mu)^2}{N}}[/tex]

So, we will have:

[tex]\mu=\frac{\sum^{133}_1x_i}{N}\Rightarrow\mu=\frac{8911}{133}\Rightarrow\mu=67[/tex]

Then:

[tex]\sigma=\sqrt[]{\frac{\sum^{133}_1(x_i-67)^2}{133}}\Rightarrow\sigma=\sqrt[]{\frac{196042}{133}}\Rightarrow\sigma=\sqrt[]{1474}\Rightarrow\sigma=38.39270764\ldots[/tex]

And so, we obtain the standar deviation.

*Second: We determine the margin of error:

[tex]me=cv\cdot\sigma[/tex]

Here me represents the margin of error, cv represents the critical value and this is multiplied by the standard deviation. We know that the critica value for a 90% confidence interval is of 1.645, so:

[tex]me=1.645\cdot38.39270764\ldots\Rightarrow me=63.15600407\ldots\Rightarrow me\approx63.156[/tex]

*Third: We determine the confidence interval as follows:

[tex]ci=ss\pm me[/tex]

Here ci is the confidence interval, ss is the saple statistic and me is the margin of error:

[tex]ci\approx133\pm63.156\Rightarrow ci\approx(69.844,196.256)[/tex]

And that is the confidence interval,

a certain number was multiplied by 3. then, this product was divided by 10.2. finally, 12.4 was subtracted from this quotient, resulting in a difference of -8.4. what was this number

Answers

A certain number was multiplied by 3. then, this product was divided by 3. Finally, 5 was subtracted from this quotient, resulting in a ...

Answer:

13.6

Step-by-step explanation:

[tex] \frac{3x}{10.2} - 12.4 = - 8.4[/tex]

[tex] \frac{3x}{10.2} = 4[/tex]

[tex]3x = 40.8[/tex]

[tex]x = 13.6[/tex]

х3,2y=x?(x, y)00(0,0)2.4(2, 4)For which value of x is the row in the table of values incorrect?3The function is the quadratic function y = -x?4366를18(3,6)(5,18 )5

Answers

Since the given equation is

[tex]y=\frac{3}{4}x^2[/tex]

If x = 0, then

[tex]y=\frac{3}{4}(0)^2=0[/tex]

Then x = 0 is correct because it gives the same value of y in the table

If x = 2

[tex]\begin{gathered} y=\frac{3}{4}(2)^2 \\ y=\frac{3}{4}(4) \\ y=3 \end{gathered}[/tex]

Since the value of y in the table is 4

Then x = 2 is incorrect

what is the slope of the line which goes through the points (-2, -9) and (2, 11) the slope of the line is___

Answers

Slope of a line

We know the equation of a line is given by:

[tex]y=mx+b[/tex]

where m is its slope and b its interpcetion with y - axis.

We know the slope equation is

[tex]\begin{gathered} m=\frac{\Delta y}{\Delta x} \\ =\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]

If (x₁, y₁) = (-2, -9) and (x, y) = (2, 11) then replacing in the slope equation

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ =\frac{11-(-9)}{2-(-2)} \\ =\frac{11+9}{2+2} \\ =\frac{20}{4}=5 \end{gathered}[/tex]Answer: the slope of the line is 5

a sample size 115 will be drawn from a population with mean 48 and standard deviation 12. find the probability that x will be greater than 45. round the final answer to at least four decimal places
B) find the 90th percentile of x. round to at least two decimal places.

Answers

The probability that x will be greater than 45 is 0.1974.

The 90th percentile of x is 63.3786

Given,

The sample size drawn from  a population = 115

The mean of the sample size = 48

Standard deviation of the sample size = 12

a) We have to find the probability that x will be greater than 45.

Here,

Subtract 1 from p value of the z score when x = 45

Then,

z = (x - μ) / σ

z = (45 - 48) / 12 = -3/12 = -0.25

The p value of z score -0.25 is 0.8026

1 - 0.8026 = 0.1974

That is,

The probability that x will be greater than 45 is 0.1974.

b) We have to find the 90th percentile of x.

Here,

p value is 0.90

Then, z score will be equal to 1.28155

Now find x.

z = (x - μ) / σ

1.28155 = (x - 48) / 12

15.3786 = x - 48

x = 15.3786 + 48

x = 63.3786

That is,

The 90th percentile of x is 63.3786

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Compute P(7,4)
From probability and statistics

Answers

The resultant answer from computing P(7,4) from probability and statistics is 840.

What is probability?The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.The probability is computed by dividing the total number of possible outcomes by the number of possible ways the event could occur.

So, P(7,4):

This is a permutation and can be calculated as:

ₙPₓ= n! / (n - x)!Here, n = 7 and x = 4

Put the values in the given formula:

P(7, 4) = 7! / (7 - 4)!P(7, 4) = 7! / 3!P(7, 4) = 840

Therefore, the resultant answer from computing P(7,4) from probability and statistics is 840.

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Select all rational numbers
help ASAP please
15 points

Answers

The resulting rational number is √100

Rational numbers:

A rational number is a number that can be represented a/b where a and b are integers and b is not equal to 0.

Given,

Here we have the following list of numbers

√75, -√25, 2√7, √100, √0.36, √0.0144, √3/7 , -√36/49

Now, we need to identify whether these are the rational numbers or not.

AS per the definition of rational number,

When we take the  root for the value √75, we get 8.660 that is a non-whole square root, 8.660 is not a rational number.

The value -√25 takes the negative value so it is not a rational number.

The number 2√7, this one also produce on-whole square root, so this one is not a rational number.

The value of √100 is 10, and it is a rational number.

The value of √0.36 is 0.6 which is less than 0, so it is not a rational number.

The value of √0.0144 is 0.012 which is less than 0, so it is not a rational number.

The value of √3/7 this one also produce on-whole square root, so this one is not a rational number.

The value -√36/49 takes the negative value so it is not a rational number.

Therefore, the rational number is √100.

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See if anybody can answer this. A concession stand sells lemonade for $2 each and sports drinks for $3 each. The concession stand sells 54 cups of lemonade and sport drinks. The total money collected for these items is $204. How much money was collected on sports drinks?​

Answers

Let x = cups of lemonade
Let y = cups of sports drink

x + y = 54
2x + 3y = 204



$96 dollars were collected from selling sports drinks.

write an equation that gives the proportinal relationship of the graph

Answers

Answer:

y=5x

Explanation:

The slope-intercept form of the equation of a line is:

[tex]y=mx+b\text{ where }\begin{cases}m=\text{slope} \\ b=y-\text{intercept}\end{cases}[/tex]

First, we find the slope of the line by picking two points from the line.

• The points are (0,0) and (3,15).

[tex]\begin{gathered} \text{Slope},m=\frac{Change\text{ in y-axis}}{Change\text{ in x-axis}}=\frac{15-0}{3-0}=\frac{15}{3} \\ \implies m=5 \end{gathered}[/tex]

Next, the line crosses the y-axis at y=0.

Therefore, the y-intercept, b=0.

Substitute m=5 and b=0 into the slope-intercept form:

[tex]\begin{gathered} y=5x+0 \\ \implies y=5x \end{gathered}[/tex]

The equation that gives the proportional relationship of the graph is y=5x.

Find the area of the triangle below.9 cm6 cm2 cm

Answers

We recall that the area of a triangle is defined by the product of the triangle's base times its height divided by 2.

So we notice that in our image, we know the height (6 cm), and we also know the base of the triangle (2 cm)

Therefore the triangles are is easily estimated via the formula:

[tex]\text{Area}=\frac{base\cdot height}{2}=\frac{2\cdot6}{2}=6\, \, cm^2[/tex]

Then the area is 6 square cm.

40. Coach Hesky bought 3 new uniforms for his basketball team. He spent a total of $486. If the same amount was spent on each uniform, how much did he spend per player? .

Answers

new uniforms = 3

Total amount spent = $486

Amount spent per player = $486 /3 = $162

Write an equation of the line that is parallel to the line y=4x+2 and y-3x=6 are parallel, perpendicular, or neither.

Answers

Given:

The point is (-2,3).

The parallel line is y=4x+2.

This is of the form

[tex]y=mx+b_1[/tex]

where slope m=4.

We know that the slope of the parallel lines is equal.

Thus we get the slope m =4 for the required line.

Consider the line equaiton

[tex]y=mx+b[/tex]

Substitute x= -2,y=3, and m =4 in the equation to find the value of b.

[tex]3=4(-2)+b[/tex]

[tex]3=-8+b[/tex]

Adding 8 on both sides of the equation, we get

[tex]3+8=-8+b+8[/tex]

[tex]11=b[/tex]

We get b=11.

Substitute m=4 and b=11 in the equation, we get

[tex]y=4x+11[/tex]

Hence the line equation that passes through the point (-2,3) and parallel to y=4x+2 is

[tex]y=4x+11[/tex]

In the accompanying diagram of circle O, COA is adiameter, O is the origin, OA = 1, and mLBOA = 30. Whatare the coordinates of B?

Answers

Given:

COA is a diameter

O is the origin

OA = 1

m< BOA = 30

Re-drawing the diagram to show the coordinates of the B:

Let the coordinates of B be (x,y)

Using trigonometric ratio, we can find the length of side AB

From trigonometric ratio, we have:

[tex]tan\text{ }\theta\text{ = }\frac{opposite}{adjacent}[/tex]

Substituting we have:

[tex]\begin{gathered} tan\text{ 30 = }\frac{y}{1} \\ Cross-Multiply \\ y\text{ = tan30 }\times\text{ 1} \\ y\text{ = 0.577} \\ y\text{ }\approx\text{ 0.58} \end{gathered}[/tex]

Hence, the coordinates of B is (1, 0.58)

I don't understand any of this (for a practice assessment)

Answers

Answer:

a. The total weight

b. 2 times the weight of Jet

c. The weight of Fido

d. The total weight

Explanation:

We know that Fido weighs 10 pounds more than Jet and together they weigh 46 pounds. So, if j represents Jet's weight, the bar model is:

Now, we can answer each part as:

a. 46 represents the total weight of the small dogs

b. 2j represents 2 times the weight of Jet

c. j + 10 represents the weight of Fido because its weight is the weight of Jet j added to 10.

d. 2j + 10 also represents the sum of the weights of the small dogs.

So, the answers are:

a. The total weight

b. 2 times the weight of Jet

c. The weight of Fido

d. The total weight

Given the following absolute value function sketch the graph of the function and find the domain and range.

ƒ(x) = |x + 3| - 1

pls show how did u solve it

Answers

Given

Absolute value function f(x) = |x + 3| - 1

To find

Sketch the graph,Find its domain,Find its range.

Solution

In order to sketch the graph we need to find the vertex and two more points to connect with the vertex.

To do so set the inside of absolute value to zero:

x + 3 = 0x = - 3

The y-coordinate of same is:

f(-3) = 0 - 1 = - 1.

So the vertex is (- 3, - 1).

Since the coefficient of the absolute value is positive, the graph opens up, and the vertex is below the x-axis as we found above.

Find the x-intercepts by setting the function equal to zero:

|x + 3| - 1 = 0x + 3 - 1 = 0 or - x - 3 - 1 = 0x + 2 = 0 or - x - 4 = 0x = - 2 or x = - 4

We have two x-intercepts (-4, 0) and (-2, 0).

Now plot all three points and connect the vertex with both x-intercepts.

Now, from the graph we see there is no domain restrictions but the range is restricted to y-coordinate of the vertex.

It can be shown as:

Domain: x ∈ ( - ∞, + ∞),Range: y ∈ [ - 1, + ∞)

Answer:

Vertex = (-3, -1).y-intercept = (0, 2).x-intercepts = (-2, 0) and (-4, 0).Domain = (-∞, ∞).Range = [-1, ∞).

Step-by-step explanation:

Given absolute value function:

[tex]f(x)=|x+3|-1[/tex]

The parent function of the given function is:

[tex]f(x)=|x|[/tex]

Graph of the parent absolute function:

Line |y| = -x where x ≤ 0Line |y| = x where x ≥ 0Vertex at (0, 0)

Translations

[tex]f(x+a) \implies f(x) \: \textsf{translated $a$ units left}.[/tex]

[tex]f(x-a) \implies f(x) \: \textsf{translated $a$ units right}.[/tex]

[tex]f(x)+a \implies f(x) \: \textsf{translated $a$ units up}.[/tex]

[tex]f(x)-a \implies f(x) \: \textsf{translated $a$ units down}.[/tex]

Therefore, the given function is the parent function translated 3 units left and 1 unit down.

If the vertex of the parent function is (0, 0) then the vertex of the given function is:

⇒ Vertex = (0 - 3, 0 - 1) = (-3, -1)

To find the y-intercept, substitute x = 0 into the given function:

[tex]\implies \textsf{$y$-intercept}=|0+3|-1=2[/tex]

To find the x-intercepts, set the function to zero and solve for x:

[tex]\implies |x+3|-1=0[/tex]

[tex]\implies |x+3|=1[/tex]

Therefore:

[tex]\implies x+3=1 \implies x=-2[/tex]

[tex]\implies x+3=-1 \implies x=-4[/tex]

Therefore, the x-intercepts are (-2, 0) and (-4, 0).

To sketch the graph:

Plot the found vertex, y-intercept and x-intercepts.Draw a straight line from the vertex through (-2, 0) and the y-intercept.Draw a straight line from the vertex through (-4, 0).Ensure the graph is symmetrical about x = -3.

Note: When sketching a graph, be sure to label all points where the line crosses the axes.

The domain of a function is the set of all possible input values (x-values).

The domain of the given function is unrestricted and therefore (-∞, ∞).

The range of a function is the set of all possible output values (y-values).

The minimum of the function is the y-value of the vertex:  y = -1.

Therefore, the range of the given function is:  [-1, ∞).

NO LINKS!! Please help me with this probability question. 4a​

Answers

Answer:  11.5%  (choice B)

=====================================================

Explanation:

mu = 500 = mean

sigma = 100 = standard deviation

We'll need the z score for x = 620

z = (x - mu)/sigma

z = (620-500)/100

z = 1.20

The task of finding P(x > 620) is equivalent to P(z > 1.20)

Use a Z table or a Z calculator to find that

P(Z < 1.20) = 0.88493

which leads to

P(Z > 1.20) = 1 - P(Z < 1.20)

P(Z > 1.20) = 1 - 0.88493

P(Z > 1.20) = 0.11507

This converts to 11.507% and rounds to 11.5%

About 11.5% of the students score higher than a 620 on the SAT.

-------------------------

Another approach:

Open your favorite spreadsheet program. The command we'll be using is called NORMDIST. The template is this

NORMDIST(x, mu, sigma, 1)

x = 620 = critical valuemu = 500 = meansigma = 100 = standard deviationThe 1 at the end tells the spreadsheet to use a CDF instead of PDF. Use 0 if you want a PDF value.

If you were to type in [tex]\text{=NORMDIST(620,500,100,1)}[/tex] then you'll get the area under the normal distribution to the left of x = 620

This means [tex]\text{=1-NORMDIST(620,500,100,1)}[/tex] will get us the area to the right of 620. The result of that calculation is approximately 0.11507 which leads to the same answer of 11.5% as found earlier.

When using a spreadsheet, don't forget about the equal sign up front. Otherwise, the spreadsheet will treat the input as text and won't evaluate the command.

-------------------------

Another option is to use a TI83 or TI84 calculator.

Press the button labeled "2nd" in the top left corner. Then press the VARS key. Scroll down to "normalcdf"

The template is

normalcdf(L, U, mu, sigma)

L = lower boundaryU = upper boundarymu = mean sigma = standard deviation

The mu and sigma values aren't anything new here. But the L and U are. In this case L = 620 is the lower boundary and technically there isn't an upper boundary since it's infinity. Unfortunately the calculator wants a number here, so we just pick something very large. You could go for U = 99999 as the stand in for "infinity". The key is to make sure it's more than 3 standard deviations away from the mean.  

So if you were to type in [tex]\text{normalcdf(620,99999,500,100)}[/tex] then the calculator will display roughly 0.11507, which is in line with the other answers mentioned earlier.

As you can see, there are many options to pick from. Searching out "normal distribution calculator" or "z calculator" will yield many free options. Feel free to pick your favorite.

In physics, the Ideal Gas Law describes the relationship among the pressure, volume, and temperature of a gas sample. This law is represented by the formula PV = nRT, where P is the pressure, V is the volume, T is the temperature, n is the amount of gas, and R is a physical constant. Select all the equations that are equivalent to the formula PV = nRT.

Answers

The equations that are equivalent to the formula PV = nRT are  V = nRT/P,  n = PV/RT and R = PVnT. Option B, C and D

How to determine the equations

From the information given, we have that;

The Ideal Gas law is represented as;

PV = nRT

Given that;

P is the pressure V is the volumeT is the temperaturen is the amount of gasR is a physical constant

Subject of formula is described as the variable expressed in terms of other variables in an equation.

It is made to stand on its own on one end of the equality sign.

Let's make 'V' the subject of formula

Divide both sides by the coefficient of V which is the variable 'P', we have;

V = nRT/P

Making 'R' the subject of formula, we have

R = PV/ nT

Making 'n' the subject of formula, we have;

n = PV/RT

Hence, the equations are options B, C and D

Learn more about subject of formula here:

https://brainly.com/question/10643782

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The complete question:

In physics, the Ideal Gas Law describes the relationship among the pressure, volume, and temperature of a gas sample. This law is represented by the formula PV = nRT, where P is the pressure, V is the volume, T is the temperature, n is the amount of gas, and R is a physical constant. Which of the equations below are equivalent to the formula PV = nRT? Select all that apply. A. P = VnRT B. V = nRT/P C. n = PV/RT D. R = PVnT E. T = nR/PV

Answer:Pv=NRT

Step-by-step explanation:

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