Answer:
A) 24;12;0;-12;-24 because the numbers are gradually going down and they go into the negatives which means they repeat the numbers in the beginning.
B)-36;-25;-16;-9;-4 i am uncertian on this one but i think im doing it right.
A question to upload the GeoGebra downloaded file : Graph the quadratic function of your choice and find the vertex and axis of symmetry .
Answer:I drew a quadratic function with a vertex and axis of symmetry, hope this helps
The growth of plants in one week are recorded for 6 plants with a sample standard deviation of 4inches and sample mean of 11 inches.
t* at the 0.05 significance level=__
Margin of error = ___
Confidence interval = _____
Answer:
from my side it's blurry
Margin of error = 0.8226401
Confidence interval = (9.17736,10.82264)
We have given data for one week recorded for 6 plants.
With a sample standard deviation of 1 inch and a sample mean of 10 inches.
For this sample, it is given that,
Sample size = n = 6
Sample SD = s = 1
Sample mean = x = 10
At a 0.10 significance level, the critical point is with t-distribution (n-1)df=5 df,
t* =2.015048
Margin of error = E=2.015048*s/ √n = 0.8226401
Confidence interval
= (9.17736,10.82264)
Learn more about Margin of error here: https://brainly.com/question/10218601
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Pattern A follows the rule "add 5" and Pattern B follows the rule "subtract 2." Pattern A 5 10 15 20 25 Pattern B 20 18 16 14 12 Which ordered pairs are formed from combining a term in Pattern A with its corresponding term in Pattern B? Select all correct answers.
Answer:
(10, 20)
(25, 12)
(15, 20)
Step-by-step explanation:
Hopes this helps! :)
Answer:
the correct answers are,
(15, 16)
(25, 12)
(5, 20)
Please help fast!!!!
How many solutions does the equation y + 12 = y + 10 + 2 have?
O Zero
One
O Two
O Infinitely many
Answer:
Infinitely many
Step-by-step explanation:
Given:
[tex]y + 12 = y + 10 + 2[/tex]
Solve:
Subtract y from both sides
[tex]y+12-y=y+10+2-y[/tex]
Simplify
[tex]12=10+2[/tex]
Now add : 10 + 2
[tex]12=12[/tex]
Both side are equal
Since both sides are equal then answer = Infinitely many
[RevyBreeze]
If a chain is on 24 tooth front gear and 8 tooth rear gear determine whether this combination will result in high speed than a 2 to 1 gear ratio, assuming the speed you are pedalling is the same
24/8 = 3
the 24 to 8 gear = 3:1 ratio which is greater than 2:1
PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPP
Consider this dilation.
(a) Is the image of the dilation a reduction or an enlargement of the original figure? Explain.
(b) What is the scale factor? Explain and show your work.
ANSWER BOTH PARTS YOU MAY GET EXTRA POINTS!
Answer:
reductionscale factor 1/2Step-by-step explanation:
The usual English meanings of the words "reduction" and "enlargement" apply to geometrical figures.
(a)Figure A'B'C'D' is smaller than figure ABCD, so represents a reduction.
__
(b)Every coordinate of every image point is half as far from the origin in A'B'C'D' as in the original figure ABCD. For example, the x-coordinate of C' is 2, and the x-coordinae of C is 4. The dilation factor is the ratio of these values:
k = Cx'/Cx = 2/4 = 1/2
The scale factor is 1/2.
Let
[tex]Let \\ \displaystyle\sf S = \sum_{k=1}^n \dfrac{n}{n^2+kn + k^2} [/tex] and ,
[tex]\displaystyle \sf T_n =\sum_{k=0}^{n-1}\dfrac{n}{n^2+kn+k^2}[/tex] ,
[/tex]
where n = 1,2,3,4..... Then ,
[tex]A)\quad S_n < \dfrac{\pi}{3\sqrt3} \qquad \qquad B)\quad S_n >\dfrac{\pi}{3\sqrt3}\\\\ C)\quad T_n >\dfrac{\pi}{3\sqrt3}\qquad\qquad D)\quad T_n < \dfrac{\pi}{3\sqrt3}[/tex]
Answer:
A, D
Step-by-step explanation:
You want to know the bound for the values of Sn and Tn, given their definitions as ...
[tex]\displaystyle S_n=\sum_{k=1}^n{\dfrac{n}{n^2+kn+k^2}}\\\\T_n=\sum_{k=1}^{n-1}{\dfrac{n}{n^2+kn+k^2}}[/tex]
ValuesAll we need to do to determine the correct answer choices is evaluate the sums for some value of n.
For n=2, the value of S2 is ...
S2 = 2/(4+2+1) +2/(4+4+4) = 2/7 +2/12 = 19/42 ≈ 0.4524
For n=2, the value of T2 is ...
T2 = 2/(4+2+1) = 2/7 ≈ 0.2857 . . . . . 1/(3n) less than the value of Sn
Both of these values are less than π/(3√3) ≈ 0.6046.
The correct answer choices are ...
A) Sn < π/(3√3)
D) Tn < π/(3√3)
__
Additional comment
For the purpose here, it is not necessary to determine the limiting value of either Sn or Tn. It is only necessary to demonstrate which side of the given value the terms of either sequence lie.
<95141404393>
Find the measures of angles 1 through 6.
Answer:
<1 = 88° , <2 = 129°, <3 = 82°, <4 = 147°, <5 = 94°, <6 = 86°
Step-by-step explanation:
<1 + 92° = 180°
<1 = 88°
<2 + 51° = 180°
<2 = 129°
<3 + 98° = 180°
<3 = 82°
<4 + 33° = 180°
<4 = 147°
<1 + <2 + <3 + <4 + <5 = 540°
88° + 129° + 82° + 147 + <5 = 540°
<5 = 94°
<5 + <6 = 180°
94° + <6 =180°
<6 = 86°
26 rooms on 2 floors = ____ rooms on 4 floors
Answer:
There would be 104 rooms on 4 floors in total.
Step-by-step explanation:
If there were 26 rooms on 2 floors, then you multiply 26 x 4, the result would be 104 rooms on 4 floors in total.
Answer:
52 rooms
Step-by-step explanation:
you could set up a proportion to solve this
26 rooms/ 2 floors = ?/4 floors
to find the answer for the question mark you can divide the amount of rooms by floors and get 13.
With the 13 you can multiply that by 4 to get 52 rooms. You basically used the 13 as the amount of increase
i hope this helped
if you have anymore questions feel free to ask again:3
What is the simplest form of the quotient? Simplify by rationalizing the denominator.
[tex]\frac{\sqrt{3x^{12} y^{10}}}{\sqrt{5x^{6} y^{3}}}[/tex]
A. [tex]5x^{3} y^3 \sqrt{15y}[/tex]
B. [tex]\frac{x^3 y^3 \sqrt{15y} }{5}[/tex]
C. [tex]\frac{\sqrt{15x^{18} y^{13}}}{5x^6 y^3}[/tex]
D. none of these
Answer:
[tex]5x^{3} y^3 \sqrt{15y}[/tex] is the right answer and other are wrong
If the data for the heights of players on a basketball team is skewed right, which statistical measure represents the spread of the data best?
A. Interquartile Range
B. Mean
C. Median
D. Range
Answer:
Median
Step-by-step explanation:
I know that you can't do Range, since it's skewed right.
The mean can't be it since it's also not representative when it's skewed right.
I'd say Median, or IQR at first glance but if you look at a graph, the IQR might follow with the skewed and move over a bit.
That leaves Median.
The correct statistical measure which represents the spread of the data best is, Median.
Given that;
The data for the heights of players on a basketball team is skewed right.
Since, We know that;
For the data for the heights of players on a basketball team is skewed right,
We can use Median for the spread of the data best.
Hence, The correct statistical measure which represents the spread of the data best is, Median.
Learn more about the median visit:
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What are the coordinates of a point on the unit circle if the angle formed by the positive x-axis and the radius is 45? (WHO WANTS BRAINLIEST?!)
Answer:
the 45 degree angle is in the first quadrant, the coordinates are (√2/2, √2/2) (square root of 2 on the top, 2 on the bottom)
Financial Literacy Paul earns $25 for grooming a dog plus $18.50
per day for boarding the same dog.
e. Write an equation to find the amount of money Paul earned m
for grooming a dog once and boarding it for any number of days d.
f. Make a table to find his earnings for 5, 6, 7, or 8 days. Then graph
the ordered pairs.
Answer:
e): m=18.50d + 25
Step-by-step explanation:
6 math questions, answer all please for all points
Answer:
See below for answers and explanations
Step-by-step explanation:
Problem 1
Recall that the projection of a vector [tex]u[/tex] onto [tex]v[/tex] is [tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v[/tex].
Identify the vectors:
[tex]u=\langle-10,-7\rangle[/tex]
[tex]v=\langle-8,4\rangle[/tex]
Compute the dot product:
[tex]u\cdot v=(-10*-8)+(-7*4)=80+(-28)=52[/tex]
Find the square of the magnitude of vector v:
[tex]||v||^2=\sqrt{(-8)^2+(4)^2}^2=64+16=80[/tex]
Find the projection of vector u onto v:
[tex]\displaystyle proj_vu=\biggr(\frac{u\cdot v}{||v||^2}\biggr)v\\\\proj_vu=\biggr(\frac{52}{80}\biggr)\langle-8,4\rangle\\\\proj_vu=\biggr\langle\frac{-416}{80} ,\frac{208}{80}\biggr\rangle\\\\proj_vu=\biggr\langle\frac{-26}{5} ,\frac{13}{5}\biggr\rangle\\\\proj_vu=\langle-5.2,2.6\rangle[/tex]
Thus, B is the correct answer
Problem 2
Treat the football and wind as vectors:
Football: [tex]u=\langle42\cos172^\circ,42\sin172^\circ\rangle[/tex]
Wind: [tex]v=\langle13\cos345^\circ,13\sin345^\circ\rangle[/tex]
Add the vectors: [tex]u+v=\langle42\cos172^\circ+13\cos345^\circ,42\sin172^\circ+13\sin345^\circ\rangle\approx\langle-29.034,2.481\rangle[/tex]
Find the magnitude of the resultant vector:
[tex]||u+v||=\sqrt{(-29.034)^2+(2.481)^2}\approx29.14[/tex]
Find the direction of the resultant vector:
[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{2.841}{-29.034}\biggr)\approx -5^\circ[/tex]
Because our resultant vector is in Quadrant II, the true direction angle is 6° clockwise from the negative axis. This means that our true direction angle is [tex]180^\circ-5^\circ=175^\circ[/tex]
Thus, C is the correct answer
Problem 3
We identify the initial point to be [tex]R(-2,12)[/tex] and the terminal point to be [tex]S(-7,6)[/tex]. The vector in component form can be found by subtracting the initial point from the terminal point:
[tex]v=\langle-7-(-2),6-12\rangle=\langle-7+2,-6\rangle=\langle-5,-6\rangle[/tex]
Next, we find the magnitude of the vector:
[tex]||v||=\sqrt{(-5)^2+(-6)^2}=\sqrt{25+36}=\sqrt{61}\approx7.81[/tex]
And finally, we find the direction of the vector:
[tex]\displaystyle \theta=tan^{-1}\biggr(\frac{6}{5}\biggr)\approx50.194^\circ[/tex]
Keep in mind that since our vector is in Quadrant III, our direction angle also needs to be in Quadrant III, so the true direction angle is [tex]180^\circ+50.194^\circ=230.194^\circ[/tex].
Thus, A is the correct answer
Problem 4
Add the vectors:
[tex]v_1+v_2=\langle-60,3\rangle+\langle4,14\rangle=\langle-60+4,3+14\rangle=\langle-56,17\rangle[/tex]
Determine the magnitude of the vector:
[tex]||v_1+v_2||=\sqrt{(-56)^2+(17)^2}=\sqrt{3136+289}=\sqrt{3425}\approx58.524[/tex]
Find the direction of the vector:
[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{17}{-56} \biggr)\approx-17^\circ[/tex]
Because our vector is in Quadrant II, then the direction angle we found is a reference angle, telling us the true direction angle is 17° clockwise from the negative x-axis, so the true direction angle is [tex]180^\circ-17^\circ=163^\circ[/tex]
Thus, A is the correct answer
Problem 5
A vector in trigonometric form is represented as [tex]w=||w||(\cos\theta i+\sin\theta i)[/tex] where [tex]||w||[/tex] is the magnitude of vector [tex]w[/tex] and [tex]\theta[/tex] is the direction of vector [tex]w[/tex].
Magnitude: [tex]||w||=\sqrt{(-16)^2+(-63)^2}=\sqrt{256+3969}=\sqrt{4225}=65[/tex]
Direction: [tex]\displaystyle \theta=tan^{-1}\biggr(\frac{-63}{-16}\biggr)\approx75.75^\circ[/tex]
As our vector is in Quadrant III, our true direction angle will be 75.75° counterclockwise from the negative x-axis, so our true direction angle will be [tex]180^\circ+75.75^\circ=255.75^\circ[/tex].
This means that our vector in trigonometric form is [tex]w=65(\cos255.75^\circ i+\sin255.75^\circ j)[/tex]
Thus, C is the correct answer
Problem 6
Write the vectors in trigonometric form:
[tex]u=\langle40\cos30^\circ,40\sin30^\circ\rangle\\v=\langle50\cos140^\circ,50\sin140^\circ\rangle[/tex]
Add the vectors:
[tex]u+v=\langle40\cos30^\circ+50\cos140^\circ,40\sin30^\circ+50\sin140^\circ\rangle\approx\langle-3.661,52.139\rangle[/tex]
Find the magnitude of the resultant vector:
[tex]||u+v||=\sqrt{3.661^2+52.139^2}\approx52.268[/tex]
Find the direction of the resultant vector:
[tex]\displaystyle\theta=tan^{-1}\biggr(\frac{52.139}{-3.661} \biggr)\approx-86^\circ[/tex]
Because our resultant vector is in Quadrant II, then our true direction angle will be 86° clockwise from the negative x-axis. So, our true direction angle is [tex]180^\circ-86^\circ=94^\circ[/tex].
Thus, B is the correct answer
Find the sum of 3.0478 and 4.92 using the correct number of significant digits.
A. 7.967
B. 7.97
C. 7.9
D. 8
Answer:
Since the least number of digits in the number is 2 decimal places
Round 3.0478 to 2 dp
3.05+4.92=7.97
B is the answer
Step-by-step explanation:
Give brainliest please
Answer:
B
Step-by-step explanation:
1\6 + 1\6 + 1\6= pl help answers 3\6, 6\3, 3/18, 1\18
ANSWER THE FOLLOWING:
Step-by-step explanation:
2. since there are 15 shirt
the probability of her wearing a blue shirt is 5/15
the probability of her wearing a blue shirt is 4/15
which statement about the transformation is true? A. the unshaded octagon is a reflection because it is a flip over a diagonal line B. the unshaded octagon is a dilation because it is smaller than the shaded octagon C. the unshaded octagon is a horizontal translation because it is directly to the left of the shaded octagon D. the unshaded octagon is a vertical translation because it is directly under the shaded octagon
Find any in the sequence -3, 6, -12, 24
Answer: 3
Step-by-step explanation:
go in evenly
using wqdevdsqxcsqsd
How do I use Brainly math for solving stuff like this and how do I show my evidence on paper?
Answer:
a) 3
b) 1/3
Step-by-step explanation:
I've never used Brainly math before, but I can help you out with the work for these problems.
Part A
3(x + 1) - x = 15
3x + 3 - x = 15
4x + 3 = 15
4x = 12
x = 3
Part B
5(x + 2) - 2x = 11
5x + 10 - 2x = 11
3x + 10 = 11
3x = 1
x = 1/3
Hope this helps!
A.
B.
C.
D.
Please help
Answer:
I Think the answer is B I'm sorry if I'm wrong
The probability distribution for a random variable x is given in the table.
(see image)
Find the probability that x<-3
Answer:
30%
Step-by-step explanation:
The sign means that x can be equal to or LESS than -3. The only ones are -3 and -5. 0.17+0.13=0.30
someone help me with my homework
Answer:
Cite evidence from the text to explain Her as role in Greek mythology
The following can be deposited in a savings account: (check all that apply)
1. Jewels
2. Cash
3. Paycheck
4. Coin
5. Checks
Answer: cash, paychecks, checks
Step-by-step explanation:
(: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (: (:
A rectangle has an area of 20 cm^2. What will the area be if the rectangle tripled in size?
Answer:
180 cm^2
Step-by-step explanation:
For similar figures the ratio of areas is the square of the ratio of linear dimensions.
We take "tripled in size" to mean that the linear dimensions of the larger rectangle are 3 times those of the smaller rectangle. That means the area of the larger rectangle will be 3² = 9 times the area of the smaller one.
Area = (3²)(20 cm²) = 180 cm² . . . . area after tripled in size
The sum of the three interior angles of a triangle is 180. Suppose one angle is 74 and the remaining two angles are the same measure. Reason numerically to find the measures of the remaining angles.
Answer:
53
Step-by-step explanation:
[tex]sum \: of \: angles = 180 \\ 180 = 74 + 2x \: where \: x \: is \: the \: measure \: of \: the \: other \: angles \\ 180 - 74 = 2x \\ 106 = 2x \\ x = \frac{106}{2} \\ x = 53[/tex]
Always welcome
After your training program is completed, what should you do?
A. Evaluate progress
B. None apply
C. Start the program again
D. Add on more time

Answer:
A. evaluate progress
Step-by-step explanation:
common sense
Find the exact value, without a
calculator.
30°
sin 15° sin
tan 15º =
2
cos 15° 30°
2
COS
II
[ ? ] - [
] + [
Enter
[tex]sin\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1-cos(\theta)}{2}} \qquad cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin\left( \cfrac{30^o}{2} \right)\implies \sqrt{\cfrac{1-cos(30^o)}{2}}\implies \sqrt{\cfrac{1-\frac{\sqrt{3}}{2}}{2}}\implies \sqrt{\cfrac{~~\frac{2-\sqrt{3}}{2}~~}{2}}[/tex]
[tex]\sqrt{\cfrac{2-\sqrt{3}}{2}\cdot \cfrac{1}{2}}\implies \sqrt{\cfrac{2-\sqrt{3}}{4}}\implies \boxed{\cfrac{\sqrt{2-\sqrt{3}}}{2}} \\\\[-0.35em] ~\dotfill\\\\ cos\left( \cfrac{30^o}{2} \right)\implies \sqrt{\cfrac{1+cos(30^o)}{2}}\implies \sqrt{\cfrac{1+\frac{\sqrt{3}}{2}}{2}}\implies \sqrt{\cfrac{~~\frac{2+\sqrt{3}}{2}~~}{2}} \\\\\\ \sqrt{\cfrac{2+\sqrt{3}}{2}\cdot \cfrac{1}{2}}\implies \sqrt{\cfrac{2+\sqrt{3}}{4}}\implies \boxed{\cfrac{\sqrt{2+\sqrt{3}}}{2}} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\cfrac{~~ sin\left( \frac{30^o}{2} \right)~~}{cos\left( \frac{30^o}{2} \right)}\implies \cfrac{~~\frac{\sqrt{2-\sqrt{3}}}{2} ~~}{\frac{\sqrt{2+\sqrt{3}}}{2}}\implies \cfrac{\sqrt{2-\sqrt{3}}}{2}\cdot \cfrac{2}{\sqrt{2+\sqrt{3}}} \\\\\\ \cfrac{\sqrt{2-\sqrt{3}}}{\sqrt{2+\sqrt{3}}}\implies \blacktriangleright \sqrt{\cfrac{2-\sqrt{3}}{2+\sqrt{3}}} \blacktriangleleft[/tex]
How many symmetrical sides does a star have?
Answer:
Depends on how many points the star has. For example, a 5 pointed star will have 5 lines of symmetry. Knowing this, you should be able to count using a diagram or drawing of the star