SOLUTION:
Step 1:
In this question, we are given the following:
Principal = $ 18,000
Time = 60 month = 60/ 12 = 5 years
Interest = 4. 3%
Step 2:
The total amount she will pay at the end of the 5 -year period is given as follows:
[tex]\begin{gathered} A\text{ = P ( 1 + }\frac{R}{100})^t \\ A\text{ = 18000 ( 1 + }\frac{4.3}{100})^5 \\ \end{gathered}[/tex][tex]\begin{gathered} A\text{ = 22,217. 4416} \\ A\text{ }\approx\text{ }22,217.44\text{ dollars} \end{gathered}[/tex]Step 3:
Now, we have that the amount = 22, 217. 44 dollars.
And the Principal = 18,000 dollars
If she makes all the monthly payments,
Then, the total amount of interest she will pay on the loan is:
[tex]22,\text{ 217. 44 - 18,000 = 4,217. 44 dollars}[/tex]CONCLUSION:
The total amount of interest she will pay on the loan = 4, 217. 44 dollars.
2) A humane society claims that 30% of U.S. households own a cat. In a random sample of 210 U.S. households, 80 say they own a cat. Is there enough evidence to show this percent has changed? Use a level of significance of 0.05.
ANSWER:
There is enough evidence to reject the humane society claims
STEP-BY-STEP EXPLANATION:
Given:
p = 0.3
q = 1 - p = 1 - 0.3 = 0.7
n = 210
x = 80
Therefore:
[tex]\hat{p}=\frac{x}{n}=\frac{80}{210}=0.381[/tex]The critical values are:
[tex]Z_0=\pm1.96\text{ due }\alpha=0.05[/tex]The test statistic is:
[tex]\begin{gathered} Z=\frac{\hat{p}-p}{\sqrt[]{\frac{pq}{n}}} \\ \text{ replacing:} \\ Z=\frac{0.381-0.3}{\sqrt{\frac{0.3\cdot0.7}{210}}} \\ Z=2.56 \end{gathered}[/tex]Observe that
Z < 1.96
Therefore, reject the null hypothesis
There is enough evidence to reject the humane society claims
ANSWER:
There is enough evidence to reject the humane society claims
STEP-BY-STEP EXPLANATION:
Given:
p = 0.3
q = 1 - p = 1 - 0.3 = 0.7
n = 210
x = 80
Therefore:
[tex]\hat{p}=\frac{x}{n}=\frac{80}{210}=0.381[/tex]The critical values are:
[tex]Z_0=\pm1.96\text{ due }\alpha=0.05[/tex]The test statistic is:
[tex]\begin{gathered} Z=\frac{\hat{p}-p}{\sqrt[]{\frac{pq}{n}}} \\ \text{ replacing:} \\ Z=\frac{0.381-0.3}{\sqrt{\frac{0.3\cdot0.7}{210}}} \\ Z=2.56 \end{gathered}[/tex]Observe that
Z < 1.96
Therefore, reject the null hypothesis
There is enough evidence to reject the humane society claims
What is the value of the expression below when w = 3?5W^2 – 5W – 8
According to the given data we have the following expression:
5W^2 – 5W – 8
In order to calculate the value of the expression above when w=3 we would need to substitute the w with 3 and then calculate the expression.
So, if w=3 then:
5(3)^2 -5(3) -8
=45 - 15 -8
=22
The value of 5W^2 – 5W – 8 when w = 3 would be 22
use the listing method to represent the following set. picture attached
The correct option is A
{3, 4, 5, 6, ...}
Explanation:The condition given states that x is greater or equal to 3.
The only option that corresponds to this condition is:
{3, 4, 5, 6, ...}
(1 point) A variable of a population has a mean of I = 250 and a standard deviation of o = 49.
Solution
Question 1a:
- The population mean and sample mean are approximately the same in theory. The only difference is that the distribution of the sample will be wider due to a larger uncertainty caused by having less data to work with.
- Thus, we have:
[tex]\begin{gathered} \text{ Sample Mean:} \\ 250 \\ \\ \text{ Standard Deviation:} \\ \frac{\sigma}{\sqrt{n}}=\frac{49}{\sqrt{49}}=\frac{49}{7}=7 \\ \end{gathered}[/tex]Question 1b:
- The assumption is that the distribution is a normal distribution (OPTION C)
Question 1c:
Yes, the sampling distribution of the sample mean is always normal (OPTION B). This is in accordance with the central limit theorem.
what's the leading term and constant of -.5x^5+1.5
We have the following polynomial:
[tex]-0.5x^5+1.5[/tex]And we have to determine which is the leading term, and the constant term of that polynomial.
1. To determine that we know that the leading term is that term in the polynomial that contains the highest power of the variable. In this case, the variable is x, and the term with the highest variable is:
[tex]-0.5x^5\rightarrow\text{ This is the leading term}[/tex]2. To determine the constant term, we have to remember that this term is not associated with the variable, that is, is not a coefficient of the variable. Therefore, the constant term is 1.5.
Hence, in summary, we have that:
[tex]\text{ Leading term: }-0.5x^5[/tex]And
[tex]\text{ Constant term: }1.5[/tex]5-74.The number of girls at Middle SchoolCyber Summer Camp was six morethan twice the number of boys. Therewere a total of 156 middle schoolstudents at the camp. Use the 5-DProcess to find the number of boysand the number of girls at camp.
We have the following:
Describe/Draw
The statement tells us that the number of girls was 6 plus twice the number of boys and that in total there are 156 students.
Define
Number of girls: y, y = 6 + 2x
Number of boys: x
Number of students: 154
Do
[tex]\begin{gathered} x+y=156 \\ x+6+2x=156 \\ 3x=156-6 \\ x=\frac{150}{3} \\ x=50 \end{gathered}[/tex]for y:
[tex]y=6+2\cdot50=6+100=106[/tex]Decide
The answer is correct because the sum of both is equal to 156 students
Declare
In total there are 50 boys and 106 girls
If the line y-7=3(x+5) is dilated with a center at the origin and a scale factor of 4, which of the following equations would describe its image?
When we dilate a line with a scale factor of "a", we change its equation by changing the slope.
The slope gets multiplied by "a".
In the equation given, the slope is "3". After a dilation with a scale factor of 4, the slope would become:
3 * 4 = 12
The equation, after dilation, would be:
[tex]y-7=12(x+5)[/tex]Solve the problems. Simon is organizing his 36 toy cars into equal-sized piles. Which list shows all of the possible numbers of cars that could be in each pile? A 2. 3,4,6 B 1, 2, 3, 4,6 C 2, 3, 4, 6, 9, 12, 18 D 1, 2, 3, 4, 6, 9, 12, 18, 36
Consider that the total available toy cars is 36.
The factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36.
So Simon can make 1 pile of 36 toy cars, 2 piles of 18 cars each, 3 piles of 12 cars each, 4 piles of 9 cars each, 6 piles of 6 cars each, 9 piles of 4 cars each, 12 piles of 3 cars each, 18 piles of 2 cars each, and 36 piles of 1 car each.
Thus, the possible number of cars that could be in each pile are 1,2, 3, 4, 6, 9, 12, 18, 36.
Therefore, option D is the correct choice.
A survey team is trying to estimate the height of a mountain above a level plain. From one point on the plain, the team observes that the angle of elevation to the top of the mountain is 32o. From a point 2,000 feet closer to the mountain along the plain, the team finds that the angle of elevation is 35o. How tall (in feet) is the mountain? Round to two decimal places.
___________
To calculate the angle of elevation, just measure the angle formed by the line of sight and the level plain. The elevation of the peak is 10406.58 feet at its highest point.
This is further explained below.
What is the height of the mountain?Where
<A=30
AB=2000
<A B C=180-33
<A B C=147
<B C A=180-<A-<A B C
< B C A=180-30-147
<BCA=3
To begin, the side length BC may be calculated by using the following formula:
[tex]\frac{B C}{\sin A}=\frac{A B}{\sin C}[/tex]
So, we have:
B C=sin A *(A B/sin C)
B C=sin (30) *2000/sin (3)
B C=19107.3
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Two right rectangular prisms are shown below. 2 inches 5 Inches 9 inches inches 7 NI inches inches Prism I Prism II If each prism is packed with small cubes of side length 1 inch, how many more cubes are in Prism Il than in Prism I? O 42 cubes О 210 cubes O 510 cubes O 720 cubes
The number of small cubes in the prism I can be determined as,
[tex]\begin{gathered} N_1=\frac{Volume\text{ of prism I}}{Volume\text{ of one small cube}} \\ =\frac{\frac{7}{4}\text{ in}\times\frac{5}{4}\text{ in}\times\frac{3}{2}\text{ in}}{\frac{1}{4}\text{ in}\times\frac{1}{4}\text{ in}\times\frac{1}{4}\text{ in}} \\ =210 \end{gathered}[/tex]The number of cubes in the prism II can be determined as,
[tex]\begin{gathered} N_2=\frac{2\text{ in}\times\frac{5}{2}\text{ in}\times\frac{9}{4}in}{\frac{1}{4}in\times\frac{1}{4}in\times\frac{1}{4}in} \\ N_2=720 \end{gathered}[/tex]The difference in the number of cubes is,
[tex]\begin{gathered} N_2-N_1=720-210 \\ =510 \end{gathered}[/tex]Thus, Prism II has 510 more cubes than Prism I.
Thus, option (c) is the correct solution.
You might need:CalculatorHiro painted his room. After 3 hours of painting at a rate of 8 square meters per hour, he had 28 squaremeters left to paint.Let y represent the area (in square meters) left to paint after chours.Which of the following information about the graph of the relationship is given?
The graph is that of area painted against the number of hours. Given that he painted 8 square meters per hour, the slope is 8 square meters per hour because slope is known as unit rate.
After 3 hours of painting, he would have painted 8*3 = 24 square meters.
Since he has 28 meters left to paint, it means that the total rea of the room that
y= -2x - 7x - y = -8
Given the system of equations:
[tex]\begin{gathered} y=-2x-7\rightarrow(1) \\ x-y=-8\rightarrow(2) \end{gathered}[/tex]we will find the solution to the system by graphing
To draw the lines, we need to know two points on each line
so, substitute with two values of x and calculate the corresponding value of y
For line (1): y = -2x - 7
[tex]\begin{gathered} x=0\rightarrow y=-2\cdot0-7=-7 \\ x=1\rightarrow y=-2\cdot1-7=-9 \end{gathered}[/tex]so, line (1) passes through the points ( 0, -7) and ( 1, -9)
For line (2): x - y = -8
y = x + 8
[tex]\begin{gathered} x=0\rightarrow y=8 \\ x=1\rightarrow y=1+8=9 \end{gathered}[/tex]So, line 2 passes through the points ( 0, 8) and ( 1, 9)
The graph of the line will be as shown in the following picture
As shown in the figure:
Line (1) is the blue line
Line (2) is the red line
The point of intersection = ( -5, 3)
So, the solution is point ( -5, 3)
Suppose that a regression line for some data transformed with logarithmspredicts that when x equals 4, log(y) will equal 2.671. What does theregression line predict y will equal when x equals 4?
Explanation:
The information that we have is that when the value of x is 4
[tex]x=4[/tex]The logarithm of y is 2.671
[tex]log(y)=2.671[/tex]The question is:
What does the regression line predict y will equal when x =4?
That means we need to solve for y in
[tex]log(y)=2.671[/tex]To find the predicted y-value.
To solve for y, we make 10 the base of the two sides of the equation as shown in the following expression:
[tex]10^{log(y)}=10^{2.671}[/tex]Due to the properties of logarithms, on the left side, we will be left only with 'y'
[tex]y=10^{2.671}[/tex]And finally, solving the operations on the right-hand side, the result is:
[tex]y=468.813[/tex]Answer:
[tex]y=468.813[/tex]Find the due date of a note dated October 24, 2018 for 2 months.
2 months after october 24th 2018 will be:
24th December 2018 which was a monday.
Add 3 days of grace period will give the due date to be 27th December 2018.
The same set of data has been fit using two different functions. The following images show the residual plots of each function.
We have the residuals of each function graphed.
They represent the distance, taking into account the sign, of each data point to the line of best fit.
A good fit will have residuals that are close to the x-axis. Also, the distribution for the residuals should not have too much spread, meaning that all the points should have approximately the same residual in ideal conditions.
In this case, we see that Function A has most residuals around the horizontal axis. Except for one of the points, that may be considered an outliert.
In the case of Function B there is a clear pattern (a quadratic relation between x and the residual) that shows that the degree of the best fit function is not the adequate (maybe two degrees lower than what should be).
This results in residuals that have a wide spread depending on the value of x.
Then, we can conclude that Function A has a better fit because the points are clustered around the x-axis.
Answer: Function A has a better fit because the points are clustered around the x-axis [Third option]
use the quadratic formula to find both solitions to the quadratic equation given below x^2+6×=16
Answer:
x1=4
x2=-8
Step-by-step explanation:
x^2+6x-16=0
a=1 b=6 c=-16
D=b^2 - 4ab= 36+64=100
D>0, 2 sqrt
x1= -b+sqrt{D} /2= -6+10/2= 4
x2= -b-sqrt{D} /2= -6-10/2= -8
(That's what we were taught!)
URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100
POINTS!!!!!
The transformation of the map is given as; translation of 1 unit to the right and rotated 180 degree counterclockwise about origin.
What is termed as the translation?In geometry, translation refers to a function which moves an object a specified distance. The element is not otherwise altered. It is not rotated, mirrored, or resized.Each point of the element must be relocated within the same direction and at the same distance during a translation.When performing a translation, this same initial object is referred to as the pre-image, and the element after the translation is referred to as the image.For the given question;
The graph of the triangle is given,
The triangle is first translated to the 1 unit to its right such that vertex of the triangles lies on the y -axis.
Now, the triangle is rotated about origin in counter clock wise direction about 180 degrees.
Thus, the final image is shown by red triangle.
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The stem-and-leaf plot shows the number of hours per semester that students in a certain school club watchtelevision. What is the greatest number of hours that were watched?
Answer:
45
Explanation:
The number on the left of the line represent the tens and the numbers on the right of the line represent the units, so data for the stem and leaf plot is:
20, 22, 22, 22, 23, 23
30, 31, 33, 35
40, 42, 42, 43, 43, 43, 45
It means that the greatest number of hours is 45.
Then, the answer is 45.
hello I don't know if you can help me with this but I no am doing something wrong. because at the bottom its not spelling right
8. The difference of three and a number means x+3 or x-3 because in both equations you have three units plus or minus the number X.
10. '"4 times the sum of a number and three" means
[tex]4\cdot(x+3)=4x+12[/tex]Letter D
What is the solution to the equation?
-6 = x/8
Enter your answer in the box.
X =
Answer:
-48
Step-by-step explanation:
First, you multiple the fraction by the denominator, which is 8. You multiple both sides of the equation by 8. -6*8=-48. x/8 * 8 = x. In conclusion, -48 = x or x = -48.
A gamer spinner, circle O, is divided into 3 regions as shown. RP is a diameter. what is the area of the shaded sector ROS if RP=8 in a m
we get that the radius is 4 and the angle is 135° which is radians 3/4 pi
so the area is
[tex]A=\frac{\pi}{2}\cdot4^2-\frac{\pi}{8}\cdot4^2=8\pi-2\pi=6\pi\approx18.85[/tex]4(3c+3)-3c+1=3(3c+5)-2
The given equation is,
[tex]4(3c+3)-3c+1=3(3c+5)-2[/tex]The above equation can be simplified as follow,
[tex]undefined[/tex]The graph shows the first four ordered pairs formed by the corresponding terms of two patterns. Which ordered pair would be the fifth point on this graph? (4,12) (12,4) (12,8) (10, 4) Q1 6 7 8 9 10 11 12
As shown in the graph:
There are four points:
(0,0) , (3, 1) , ( 6, 2) and ( 9, 3)
The points represent a proportion relation between x and y
The relation will be:
[tex]y=\frac{1}{3}x[/tex]So, the fifth point will be: ( 12, 4)
While waiting for the school bus, Michiko records the colors, of all cars passing through an intersection. Thetable shows the results, Estimate the probability that the next car through the intersection will be red. Exgressyour answer as a percent. If necessary, round your anewer to the nearest tenth
Given the following question:
Estimate the probability that the next car will be red.
11, 24, 16, 9
[tex]\begin{gathered} 11\text{ + 24}=35 \\ 35\text{ + 16 = 51} \\ 51\text{ + 9 = }60 \\ 60=100\text{per} \end{gathered}[/tex][tex]p=\frac{11}{60}[/tex][tex]\frac{11}{60}\times100=18.333333[/tex][tex]\begin{gathered} 18.333333 \\ 3\text{ < 5} \\ 18.3 \end{gathered}[/tex]18.3% or the first option.
Determine the value(s) of x at which the function is discontinuous. Describe the discontinuity as removale or non-removable.
Answer with explanation: To find the values of x where the f(x) is discontinuous, we have to set the denominator equal to zero, doing this gives:
[tex]\begin{gathered} f(x)=\frac{x^2+10+9}{x^2-81}\Rightarrow x^2-81=0 \\ x=\sqrt[]{81}=9 \\ x=9 \end{gathered}[/tex]The f(x) is discontinuous at x = 9, following graph confirms it:
In conclusion, discontinuity is non-removable.
Fred takes out a mortgage for $60,000 at 7% for 20 years. What are his monttpayment, the total amount paid, and the cost of the mortgage?
We will have the following:
First, we determine the monthly rate:
[tex]r_m=\frac{0.07}{12}=\frac{7}{1200}[/tex]Now, we determine the monthly payment:
[tex]\begin{gathered} A=P\frac{(1+r_m)^n}{(1+r_m)^n-1} \\ \\ \Rightarrow A=60000\frac{(1+(7/1200))^{^{240}}}{(1+(7/1200))^{240}-1}\Rightarrow A\approx465.18 \end{gathered}[/tex]So, the monthly payment will be approximately $465.18.
The total amount paid will be:
[tex]\begin{gathered} X=A\ast n\ast t \\ \\ \Rightarrow X=(465.18)(12)(20)\Rightarrow X\approx111643.2 \end{gathered}[/tex]So, the total payment will be approximately $111 643.2.
The cost of the mortgage is:
[tex]c=111643.2-60000\Rightarrow c\approx51643.2[/tex]So, the cost of the mortgage is approximately $51 643.2.
The state of California charges homeowners approximately $1,200 per year in property taxes for every $100,000 a person's home is worth. If Mr. Cohen's home in Studio City, CA is worth $1,600,000, how much does he have to pay in property taxes per year? Set up a pair of equivalent ratios and then use your knowledge of cross products to solve. You may use calculator.
We have the next information
1,200 ----- 100,000
x ----- 1,600,000
x is the missing quantity
x can be calculated in this way
[tex]x=\frac{1,600,000\cdot1200}{100,000}=19200[/tex]Mr. Cohen has to pay per year $19,200 taxes per year
Statistics: a professor recorded 10 exam grades but one of the grades is not readable. if the mean score on the exam was 82 and the mean of the 9 readable scores is 84 what is the value of the unreadable score?
To mean of a set is given by the sum of all values in the data-set divided by the number of values.
We have that the mean of the whole set is 82.
The mean of the 9 readable scores is 84.
So:
[tex]\begin{gathered} \frac{x}{9}=84 \\ x=84\cdot9 \\ x=756 \end{gathered}[/tex]So, we 9 readable scores add up to 801. If we add 756 to a number, y, and divide by 10, we'll have the mean score of the exam, 82.
[tex]\begin{gathered} \frac{756+y}{10}=82 \\ 756+y=820 \\ y=820-756 \\ y=64 \end{gathered}[/tex]So, the grade of the unreadable score was 64.
What is period of the function, give the exact value
Solution
Step 1:
Find the midline
[tex]\begin{gathered} Midline\text{ = }\frac{maximum\text{ + minimum}}{2} \\ Maximum\text{ = 11.4} \\ minimum\text{ = -5.5} \\ midline\text{ = }\frac{11.4\text{ + \lparen-5.5\rparen}}{2} \\ midline\text{ = }\frac{5.9}{2} \\ midline\text{ = 2.95} \end{gathered}[/tex]Step 2:
Find the amplitude
[tex]\begin{gathered} Amplitude\text{ = }\frac{maximum\text{ - minimum}}{2} \\ Amplitude\text{ = }\frac{11.4\text{ - \lparen-5.5\rparen}}{2} \\ Amplitude\text{ = 8.45} \end{gathered}[/tex]Step 3:
Period:
To find the period, use the values of x.
[tex]\begin{gathered} Period\text{ = 2\lparen11.4 + 5.5\rparen} \\ Period\text{ = 2 }\times\text{ 16.9} \\ period\text{ = 33.8} \end{gathered}[/tex]Final answer
Period = 33.8
Use a sample mean to estimate a population mean with a certain specified OA certainty OB. accuracy OC. confidence OD. determination
SOLUTION
Given the question on the question tab;
Explanation:
When the sample mean is used as a point estimate of the population mean, some error can ... Lower levels of confidence lead to even more narrow intervals.
Final answer: