F all of the energy in a falling object's gravitational potential energy store is transferred to its kinetic energy store by the time it lands, then the relationship shown below can be used. Which of the four options below it correctly shows how this relationship can be expressed in terms of height, h?

It's gonna take a huge amount of time and effort, and we're gonna spend a huge amount of money, to build a vacuum chamber big enough to do this experiment.  

So when we're finally ready to try it, the cannonball and golf ball will make a  kind of cute experiment, but let's make it really interesting.  Let's ALSO try it with a feather, an apple, a watermelon, a tennis ball, a basketball, a coffeepot, a chair, an old computer, a set of dishes, a trombone, a bicycle, a math book, a TV set, a gallon of milk, a skateboard, a shotgun, a concrete block, a car, a waterbed, a schoolbus, a battleship, your dog, and my wife !

Drop every single one of them from a height of 10 meters.

Every single one of them accelerates at 9.8 m/s² as it falls, takes 1.429 seconds to reach the floor, and hits the floor at a speed of 14 m/s.  The feather, the schoolbus, and my wife stay together all the way down.

The only way this doesn't happen is if ...

-- you do this experiment in some other place that's not Earth, or

-- you throw one of the objects and you don't just drop it, or

-- the vacuum chamber has a leak and some air gets into it.

Because that's how gravity works.

The time of flight of the soccer ball is 2 seconds.

Given the following data:

To find the time of flight of the soccer ball;

Mathematically, the time of flight for a horizontal displacement is given by the formula;

[tex]Time \;of \;flight = \frac{Displacement}{Initial \; velocity}[/tex]

Substituting the values into the formula, we have;

[tex]Time \;of \;flight = \frac{16}{8}[/tex]

Time of flight = 2 seconds.

Therefore, the time of flight of the soccer ball is 2 seconds.

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Answer:

Δx = -80m

Explanation:

The object's displacement is -80m because it landed 80m below where it started.

Answer:

[tex]\boxed {\tt t\approx 38.89 \ s}[/tex]

Explanation:

Time can be found by dividing the distance by the speed.

[tex]t=\frac{d}{s}[/tex]

The distance is 350 meters.

The speed is 9 meters per second.

[tex]d= 350 \ m \\s= 9 \ m/s[/tex]

Substitute the values into the formula.

[tex]t=\frac{350 \ m}{9 \ m/s}[/tex]

Divide. Note that the meters or "m" will cancel each other out and the seconds or "s" will move to the numerator.

[tex]t=\frac{350 }{9 \ s}[/tex]

[tex]t=\frac{350 \ s}{9}[/tex]

[tex]t=38.8888889 \ s[/tex]

Round to the nearest hundredth. The 8 in the thousandth place tells us to round the 8 to a 9.

[tex]t \approx38.89 \ s[/tex]

It will take about 38.89 seconds to swim 350 meters at 9 meters per second.

Answer:

272

Explanation:

hope this helps you!!!

Answer:

30 J

Explanation:

height = 3 m

mass = 1kg

acceleration due to gravity = 10m/s²

Potential Energy = mass× gravity × height

= 1kg ×10m/s²× 3m

= 30 J

Answer:

4.00 A

Explanation:

Answer

F (force of gravity) = M (mass of an object) × G (acceleration due to gravity)

Step-by-step explanation:

Force of gravity (F) = Mass (M) × Gravitational acceleration (G)

The weight of an abject is equal to its gravitational force!

Explanation:

Answer:

[tex]F_{g} = \frac{m}{d^{2} }[/tex] shows the relationship between gravity and mass.

Explanation:

According to the Newton's law of gravitation, the gravitational force between two bodies is,

       [tex]F_{g} = G.\frac{m_{1}.m_{2} }{d^{2} }[/tex]

here [tex]m_{1} and m_{2}[/tex] are masses, d is distance between them.

It states that gravitational force acting two bodies is directly proportional to the product of masses and inversely proportional to the square of the distance between them.

In above formula ,

If [tex]m_{1} = 1 and[/tex]  [tex]m_{2} = m[/tex]

so [tex]F_{g} = G \frac{m}{d^{2} }[/tex]

Since G is constant ,

    [tex]F_{g}[/tex] ∝[tex]\frac{m}{d^{2} }[/tex]

Hence second option is correctly showing relationship between gravity and mass.

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Answer:

we can not use permanent magnets in radio and electric bells , because permanent magnets loose their property after some time whereas we can change the properties of electromagnet.

Answer:

Its being pushed.

Explanation:

There is no air but its being pushed by the flames coming from the rocket.

Answer:

Explanation:

Time taken by jogger to travel the distance to finishing line = 2.1 / 7.3

= .28767 hr

Bird will keep flying for this time period

distance covered by bird = speed x time

= 29.2 x .28767 km

= 8.4 km .

Answer:  SEE EXPLANATION!

Explanation:

When waves travel from one medium to another the frequency never changes. As waves travel into the denser medium, they slow down and wavelength decreases. Part of the wave travels faster for longer causing the wave to turn. The wave is slower but the wavelength is shorter meaning frequency remains the same.

I hope this helps you!

Answer:

True

Explanation:

The term 'plyometrics' is used interchangeably with the term 'jump training'. The technique can be used for training in sports that require explosive movements.

Answer:

Hope it help you

Stayhomestaysafe

Plz mark my answer brainliest✍️✍️

Explanation:

Sound travels fastest through solids. This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.

Option b

REAL NAME - SHRESTH DUBEY

Answer:

1305 I think but not sure

Answer:

5N westward, acting on the student

Explanation:

Answer: 5N westward, acting on the student

Explanation:

Answer:

Explanation:

The momentum of an object can be found by using the formula

From the question

mass = 200 kg

velocity / speed = 8m/s

We have

momentum = 200 × 8

We have the final answer as

Hope this helps you

Answer:

Mechanical energy

Explanation:

Mechanical energy is needed for movement of objects. Muscles convert chemical energy provided by the rest of the body to allow movement.

Answer:

The answer is Both types of government work well in countries with large populations.

Explanation:

Answer:

its d

Explanation:

Answer:

The "distance" is the answer to the question,

Explanation:

Answer:

bada bop boop pow

Explanation:

Answer:

False

Explanation:

More than one management style with all people is the most effective leadership technique for any organization. So, the given statement is False.

Leadership styles are defined as those adopted by company leaders to increase efficiency, satisfaction, growth and advancement in all positions in the organization. It requires a different style in different situations and each leader needs to know when to show a special behavior.

These strategies define every leader's personal leadership style. Some effective leadership Techniques are as follows:

Thus, more than one management style with all people is the most effective leadership technique for any organization. So, the given statement is False.

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Complete Question  

The complete question is shown on the first and second uploaded image  

Answer:

When water is used the reading is  [tex]    R =  2281.6 \  cm  [/tex]

When mercury is used the reading is [tex]   R =  23.83 \ cm [/tex]  

The best fluid to use is mercury because for water a slight change in toluene level will cause a  large change in height .

Explanation:

From the question we are told that  

    The length of the leg of the manometer to the top of the tank is  d =  500cm

   The toluene level where in the tank where the height of the manometer fluid level in the open arm is equal to the height where the manometer is connected to the tank is  h =150 cm  

   The manometer reading is  R  

Generally at the point where the height of the open arm is equal to the height of the of the point connected to the tank ,  

   The pressure at the height of the both arms of the manometer corresponding to the base of the tank are equal  

     i.e   [tex]P_1 = P_2[/tex]

Here [tex]P_1[/tex] is the pressure of the manometer at the point corresponding to the base of the tank and this is mathematically represented as  

       [tex] P_{atm} + P_1 =  P_{atm} + P_t[/tex]

Here [tex]P_t[/tex] is the pressure due to the toluene level in the tank and in the arm of the manometer connected to the tank and this is mathematically represented as  

         [tex]P_t  =  \rho_t  * g  * h_i[/tex]

Here  

      [tex]\rho_t [/tex] is the density of toluene with value  [tex]\rho_t =  867 kg/m^3 [/tex]

 [tex]h_i[/tex] is the height of the connected arm above the point equivalent to the base of the tank , this mathematically represented as

          [tex]h_i =  d - h + R[/tex]

  and  [tex] P_2 [/tex] is the the pressure at the open arm of the manometer at the point equivalent to the base of the base of the tank and this is mathematically represented as

         [tex] P_2 =  \rho_f * g *  h_f [/tex]

Here  

       [tex]\rho_f[/tex] is the density of the fluid in use , if it is water the density is  

       [tex]\rho_w =  1000 \  kg /m^3 [/tex]

and  if it is  mercury the density is  

        [tex]\rho_m =  13600 \  kg /m^3 [/tex]

[tex]h_f[/tex] is the height of the  fluid in the open arm of the manometer from the point equivalent to the base of the tank which is equivalent the manometer reading R

So when the fluid is water we have

      [tex] P_{atm} +  \rho_t* g *(d - h + R) =  P_{atm} + \rho_f * g *  h_f[/tex]

=>   [tex]   \rho_t* (d - h + R) =   \rho_w *  h_f[/tex]        

=>   [tex]    867  (500 - 150 + R) =    1000 *  R [/tex]

=>    [tex]    R =  2281.6 \  cm  [/tex]

So when the fluid is mercury we have      

  [tex]   \rho_t* (d - h + R) =   \rho_m *  h_f[/tex]          

=>   [tex]    867  (500 - 150 + R) =   13600  *  R [/tex]  

=>   [tex]   R =  23.83 \ cm [/tex]  

The difference in the mercury reading for mercury due to the fact that they have different densities as we have seen in this calculation

So the best fluid to use is mercury because for water a slight change in toluene level will cause a  large change in height .

Answer:

99n

Explanation:

===========================================================

Explanation:

Consider a mass of 10 kg, so m = 10

Let's say we apply a net force of 20 newtons, so F = 20

The acceleration 'a' is...

F = ma

20 = 10a

20/10 = a

2 = a

a = 2

The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.

---------------

Now let's double the net force on the object

F = 20 goes to F = 40

m = 10 stays the same

F = ma

40 = 10a

10a = 40

a = 40/10

a = 4

The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.

---------------

In summary, if you double the net force applied to the object, then the acceleration doubles as well.

Acceleration is directly proportional to the net force on an object, and inversely proportional to its mass.

So if an object's mass stays the same while the net force on it doubles, then its acceleration will also double.

We don't know anything about the "trials".  This sounds like it might be a follow-up to a lab experiment that was performed when we weren't there.

We also don't know anything about "question 1".

Answer:

14.4m/s

Explanation:

To calculate the final velocity (V), we use the formula:

v = u + at

Where; v = final velocity (m/s)

u = initial velocity (m/s)

a = acceleration (m/s²)

t = time (s)

According to the provided information in this question, v = ?, u = 0m/s, a = 1.8m/s², t = 8s

Hence, v = u + at

v = 0 + (1.8 × 8)

v = 0 + 14.4

v = 14.4m/s

Therefore, his final velocity at the end of those 8 seconds is 14.4m/s.

Answer:

2991.47 [cm^2]

Explanation:

To solve this problem we must perform a dimensional analysis and use the corresponding conversion values:

[tex]3.22[ft^{2}]*\frac{12^{2}in^{2} }{1^{2}ft^{2}} *\frac{2.54^{2}cm^{2} }{1^{2}in^{2} } \\2991.47[cm^{2}][/tex]

Answer:

d

Explanation:

Answer:

9.8 m/s/s

Explanation:

As such, all objects free fall at the same rate regardless of their mass. Because the 9.8 N/kg gravitational field at Earth's surface causes a 9.8 m/s/s acceleration of any object placed there, we often call this ratio the acceleration of gravity