Answer:
The age of the bedrock increases the further you get away from the mid atlantic ridge because it is at the ridge that the new bedrock is formed. At the Ridge, the diverging plates cause magma to rise up and harden, forming new bedrock. As this happens, the older bedrock is pushed outwards, further and further away from the Ridge.
Explanation:
Hope it helps.
A microwave has a period 0.000015 s has a wavelenth of ?
(Round your answer to the nearest hundreth. Add a zero to the begining of the number if necessary.)
Answer:
30 cm to 1 mm
Explanation:
30 cm to 1 mm
A long thing bar of copper is heated evenly along it's length
Answer:
It becomes less heavy
Explanation:
Hopefully it helps!
What would happen to the particles in this box if it lost heat energy?
the particles would slow down and become less dense
the particles would slow down and become denser.
The particles would speed up and become denser
the particles inside of the box would evaporate
Answer:
A
Explanation:
i think its A
According to the inverse square law, the force due to gravity between two masses will _____________.
Answer:
The inverse square law proposed by Newton suggests that the force of gravity acting between any two objects is inversely proportional to the square of the separation distance between the object's centers.
Explanation:
A mass m on a frictionless plane, inclined at an angle θ with respect to the horizontal, is connected by a cord that runs parallel to the inclined plane and is wrapped around a flywheel of radius r and moment of inertia
[tex]i=\frac{3mr^{2}}{4}[/tex]
what is the acceleration of the mass down
the plane?
The acceleration of the mass down the plane is determined as (4mg sinθ)/(3mr²).
Conservation of angular momentumThe acceleration of the mass down the plane is determined by applying the principle of conservation of angular momentum.
Fr = Iα
where;
F is weight of the object parallel to the planer is the radius of the flywheelI is moment of inertiaα is angular acceleration(mg sinθ)r = Iα
(mg sinθ)r = I(ar)
(mg sinθ) = I(a)
[tex]a = \frac{mg \times sin(\theta)}{I} \\\\a = \frac{mg \times sin(\theta)}{3mr^2/4} \\\\a = \frac{4mg \times sin(\theta)}{3mr^2}[/tex]
Thus, the acceleration of the mass down the plane is determined as (4mg sinθ)/(3mr²).
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Is distance a vector quantity
Explanation:
Nope, displacement is a vector quantity, whereas distance is the scalar (magnitude) of the total displacement.
Hope this clears things up :))
How can we make a simple energy flow diagram to show the heat transfer between animals, heat lamps and environment?
Answer:
Remember a few key things:
1.) Oil comes from plants, but also animals
2.) When heat lamps are done or useless, they go to landfills
3.) Things in landfills go back to the environment after a few years or even decades.
4.) Sometimes there are all-natural oils for heat lamps
1. Which of the following represents the distance (how much ground the particle covers) moved by a particle in a simple harmonic motion in one time period? (Here, A represents the amplitude of the oscillation.)
0 cm
A cm
2A cm
4A cm
Please show all of your work.
What's the relationship
[tex]\\ \rm\Rrightarrow T=2\pi \sqrt{\dfrac{l}{g}}[/tex]
[tex]\\ \rm\Rrightarrow T^2g=4\pi ^2\ell[/tex]
[tex]\\ \rm\Rrightarrow\ell=\dfrac{T^2g}{4\pi^2}[/tex]
4A can be correct
The correct option is: 2A cm
What is simple harmonic motion?In a simple harmonic motion, the particle moves back and forth around a mean position. The distance covered by the particle in one time period depends on the amplitude of the oscillation.
The time period (T) of a simple harmonic motion can be expressed in terms of the frequency (f) as:
T = 1/f
The frequency (f) of a simple harmonic motion can be related to the angular frequency (ω) as:
ω = 2πf
Therefore, the time period (T) can also be expressed in terms of the angular frequency (ω) as:
T = 2π/ω
The displacement of the particle at any time (t) during the simple harmonic motion can be expressed as:
x = A cos(ωt)
where x is the displacement, A is the amplitude, and cos(ωt) is the cosine function.
The particle moves from its initial position to its maximum displacement (+A), then back to its initial position, and finally to its maximum displacement in the opposite direction (-A), before returning to its initial position again. Therefore, the distance covered by the particle in one time period is twice the amplitude (2A).
Therefore, the correct option is:
2A cm
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Planets A and B have the same mass, but planet A is half the size of planet B.
Which statement correctly explains the weight you would experience on each
planet?
A. You would weigh the same on both planets because the masses
of the planets are the same.
B. You would weigh less on planet A because the distance between
you and the planet's center of gravity would be smaller.
C. You would weigh the same on both planets because your mass
would be the same on both.
O D. You would weigh more on planet A because the distance between
you and the planet's center of gravity would be smaller.
Answer:
the correct one is A hope it helps
A 20 kg child and a 80 kg man are standing 10 meters apart on frictionless ice. How far from the man is the center of mass of the system?
1 meter?
2 meters?
3 meters?
4 meters?
5 meters?
6 meters?
7 meters?
8 meters?
9 meters?
If the electric potential in a region is given by v(x)=7/x2 the x component of the electric field in that region is
Hi there!
Recall that:
[tex]\Delta V = -\int\limits^a_b {E \cdot } \, dx[/tex]
Given an electric field, the potential difference can be solved by using integration. Similarly:
[tex]E = -\frac{dV}{dx}[/tex]
We can differentiate the electric potential equation to solve for the electric field.
Use the power rule:
[tex]\frac{dy}{dx} x^n = nx^{n - 1}[/tex]
Differentiate the given equation.
[tex]-\frac{dV}{dx}\frac{7}{x^2} =- \frac{dV}{dx}7x^{-2} = -(-14x^{-3}) = \frac{14}{x^3}[/tex]
Or:
[tex]\boxed{E(x) = \frac{14}{x^3}}[/tex]
The component of the electric field in that region is E = 14/x³ if the electric potential in a region is given by v(x)=7/x2
What is an electric field?An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.
We have:
The electric potential in a region is given by:
[tex]\rm V(x) = \frac{7}{x^2}[/tex]
We know the relation between potential difference and an electric field is given by:
[tex]\rm \triangle V = \int\limits^a_b {E.} \, dx[/tex]
If the electric field is given, then:
[tex]\rm E = -\frac{dV}{dx}[/tex]
[tex]\rm E = -\frac{d(7x^{-2} )}{dx}[/tex]
After differentiate:
[tex]\rm E = -(-14x^{-3})[/tex] or
[tex]\rm E = \frac{14}{x^3}[/tex]
Thus, the component of the electric field in that region is E = 14/x³ if the electric potential in a region is given by v(x)=7/x2
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Ring of mass straight m and radius straight r is attached to the end of a thin rod of mass straight m and radius 2 straight r
The total moment of inertia about an axis is : [tex]L^{2} ( \frac{M}{3} + m ) + \frac{2mr^2}{5}[/tex] for a ring of mass m and radius straight r attached to a thin rod.
Determine the Total moment of Inertia about an axisGiven data:
mass of ring --> m
radius of ring --> r
mass of rod --> M
Length of rod ---> L ( 2 * radius )
Total Moment of Inertia about an axis = Irod + Iring
where : Irod = moment of inertia of rod, Iring = moment of inertia of ring
Irod = ML² / 3
Iring = 2mr² / 5
moment of inertia around an axis by Iring = I
where ; I = 2mr² / 5 + ML² according to parallel axis theorem
Hence the Total moment of Inertia about an axis is :
Itotal = 2mr²/5 + ML² + ML² / 3
= [tex]L^{2} ( \frac{M}{3} + m ) + \frac{2mr^2}{5}[/tex]
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For a ring of mass m and radius straight r connected to a thin rod, the total moment of inertia about an axis is [tex]\rm I= L^2 (\frac{M}{3} +m)+\frac{2mr^2}{5}[/tex].
What is a moment of inertia?The sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation expresses a body's tendency to resist angular acceleration.
The given data in the problem is;
m is the ring's mass.
r is the radius of a ring.
L is the rod length = 2r
The total Moment of Inertia about an axis;
[tex]\rm I = I_{rod}+I_{ring} \\\\ \rm I =\frac{ML^2}{3} +\frac{2mr^2}{5}[/tex]
According to the parallel axis theorem,
[tex]\rm I = \frac{2mr^2}{5} + ML^2[/tex]
The total Moment of Inertia about an axis will be;
[tex]\rm I_{total} = \frac{ML^2}{3} +\frac{2mr^2}{5}+ML^2 \\\\ \rm I_{total} =L^2 (\frac{M}{3} +m)+\frac{2mr^2}{5}[/tex]
Hence for a ring of mass m and radius straight r connected to a thin rod, the total moment of inertia about an axis is [tex]\rm I= L^2 (\frac{M}{3} +m)+\frac{2mr^2}{5}[/tex].
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according to this passage when making healthcare decisions, how should a person approach the decision making process
Answer:
What is your name?
Explanation:
no bro I don't know I am New of this app so I don't know
a 600kg wrecking ball is swinging from a crane as shown. When the wrecking ball reached the bottom of the path, the wrecking ball is moving 10m/s
Answer:
Explanation:
The picture is cut off so the wrecking ball and its path are not shown. It would be better if the whole picture is available.
Based on the written info, at the bottom of the path, the wrecking ball is moving at 10m/s.
The centripetal acceleration = velocity^2 / radius
= 10^2 / 25
= 100 / 25
= 4m/s^2
The centripetal force = mass * centripetal acceleration
= 600*4
= 2400N
As the ball is moving horizontally at the bottom, net vertical force is zero.
So Tension force in cable = Wrecking ball weight + Centripetal force
= 600*g + 2400
= 6000 + 2400; assuming g is 10m/s^2
= 8400N
What is the electric potential energy of a charge that experiences a force of 3. 6 × 10–4 N when it is 9. 8 × 10–5 m from the source of the electric field? 3. 5 × 10–8 J 4. 6 × 10–4 J 2. 7 × 10–1 J 3. 7 × 100 J.
The electric potential energy of the charge will be =3.5*10^8 J
What is Electric potential energy?Electric potential energy is the energy that is needed to move a charge against an electric field.
F=Force experienced by the charge = 3.6*10^-4 N
q1 = magnitude of charge producing the electric field
q2 = magnitude of charge experiencing the electric force
r1 = distance between the two charges
Electric force experienced by the charge is given using coulomb's law as
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
[tex]3.6\times 10^{-4}=\dfrac{9\times 10^9 q_1q_2}{(9.8\times 10^{-5})^2}[/tex]
[tex]q_1q_2=3.84\times 10^{-22}[/tex]
Electric potential energy of the charge can be given as
[tex]U=\dfrac{kq_1q_2}{r}[/tex]
[tex]U=\dfrac{(9\times 10^9)q_1q_2}{(9.8\times 10^{-5})^2}[/tex]
[tex]U=3.5\times 10^{-8}\ J[/tex]
Thus Electric potential energy of the charge can be given as [tex]U=3.5\times 10^{-8}\ J[/tex]
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The study of electrons as it relates to their use in electric devices
Answer:
An electron is a component of the broader term, electricity. Generally electricity refers to the control, manipulation, and use of the movement of electrons to perform some kind of work (motion/rotation, light, heat, etc…).
Explanation:
Or
put this
The study of electrons as it relates to their use in electric devices is electricity.
But I will go with the first one
Why does the spectroscopic parallax method only work for main sequence stars?.
Answer:
Only main sequence stars have a well-defined relationship between spectral type and luminosity.
Explanation:
Low-mass stars have much longer lifetimes than high-mass stars.
11. Which of the following gives the correct relation between the acceleration due to gravity and period of a pendulum?
g = 2πLT2
g = 4π2LT2
g = 2πLT
g = 2π2LT
Please show all of your algebra.
[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]
Derive g[tex]\\ \rm\rightarrowtail T^2=4\pi^2\dfrac{l}{g}[/tex]
[tex]\\ \rm\rightarrowtail g=\dfrac{4\pi ^2\ell}{T^2}[/tex]
[tex]\\ \rm\rightarrowtail g=\left(\dfrac{2\pi\sqrt{l}}{T}\right)^2[/tex]
The electric field is measured for points at distances r from the center of a uniformly charged insulating sphere that has volume charge densi
For the electric field is measured for points at distances r,Electric field is mathematically given as
E=19.9*10^{-5}c/m^3
What is the Electric field?Generally, the equation for the electric field uniform charged is mathematically given as
[tex]E=\frac{lr}{3e0}[/tex]
Therefore
E=lr/3E0=3Ee0/r
Therefore
E=3*6*10^4*8.85*10^{-12}
E=19.9*10^{-5}c/m^3
In conclusion, E=19.9*10^{-5}c/m^3
E=19.9*10^{-5}c/m^3
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CQ
Complete question attached below
Franklin is loading a truck at work and his truck has a ramp that helps him move the boxes up. the incline of the ramp is 9 feet long and the top of the ramp is 3 feet off of the ground. what is the mechanical advantage of the incline franklin is using?
Answer:
Explanation:
Formula
MA = length of ramp / height
Givens
ramp length = 9 feet
height = 3 feet
Solution
MA = 9 / 3
MA = 3
Answer Mechanical advantage = 3
A body of mass 0.1 kg falling freely under gravity takes 10 s to reach the ground. Calculate the kinetic energy and potential energy of the body when it has travelled for first 6 s. Given, g = 9.8 m/ s²
Answer: KE = 172.872 J
PE = 307.328 J
Explanation:
For KE: acceleration = change in velocity / time → 9.8 = final velocity - 0 (because initial velocity is zero) / 6s → final velocity after 6s = 58.8 m/s.
Now, plug this into: KE = 1/2(m)(v^2) → KE = 1/2(.1)(58.8^2) = 172.872 J.
For PE: Find the velocity after 10 s: acceleration = change in velocity / time → 9.8 = final velocity - 0 (because initial velocity is zero) / 10s → final velocity after 10s = 98 m/s.
Now, find the total height: (v final)^2 = (v initial)^2 + 2*a*d → 98^2 = 0^2 + 2*9.8*d → d = total height = 490 m.
Now, find the change in height after 6 s: (v final)^2 = (v initial)^2 + 2*a*d → 58.8^2 = 0^2 + 2*9.8*d → d = change in height after 6 s → 176.4 m
Now, subtract the change in height from the total height to get its height after 6s: 490-176.4=313.6m
PE = m*g*h → Pe=.1*9.8*313.6 = 307.328 J :)
When a 10-V battery is connected to a resistor, 2 A of current flow in the resistor. What is the resistor's value
Hi there!
We can use Ohm's law to solve:
[tex]V = IR[/tex]
V = Potential Difference (V)
I = Current (A)
R = Resistance (Ω)
We can rearrange the equation to solve for resistance:
[tex]R = \frac{V}{I}[/tex]
Plug in the given values to solve.
[tex]R = \frac{10}{2} = \boxed{5 \Omega}[/tex]
Please help me
Think about a time when you walked down an empty hallway
and heard the echo of your footsteps. Write what you think
caused the echo.
Answer:
Explanation:
There are a few conditions as mentioned: "you walked down an empty hallway and heard the echo of your footsteps." So first thing is as you walk, your shoes touch the floor and make noises. Those are sounds of your footsteps. You are in a hallway so the sounds are trapped within the hallway. It is empty so there is nothing like people who would block and absorb the sounds. With sounds bouncing around walls and floor of the hallway, they bounce back to the source: you. That is when you hear the echo of your footsteps.
What are radio isotopes??
Give one example of a radio isotope State one use too..
Don't spam..
Answer:
An isotope is one of two or more species of atoms of a chemical element with the same atomic number and position in the periodic table and nearly identical chemical behavior but with different atomic masses and physical properties. In medicine, for example, cobalt-60 is extensively employed as a radiation source to arrest the development of cancer. Other radioactive isotopes are used as tracers for diagnostic purposes as well as in research on metabolic processes.
Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!
Those isotopes which are unstable due to the presence of extra neutrons in their nuclei and emit various types of radiations are called radioactive isotopes. The radiations emitted are in the form of alpha particles, beta particles and gamma rays.
For eg :- carbon,hydrogen and chlorine.
Hope it helps you!!hey guys can y’all help quickly?
how to induce a positive temporary charge on the right side of a metal ball
Answer:
Temporary? You have two options
If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).
If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).
Either way, the electron cloud will migrate towards the right side of the of your sphere.
Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.
A coin has a mass of 7.0g. It is made of a metal alloy of density 5.6g/cm3. Calculate the volume of the coin.
[tex]\text{Density,}\\\\~~~~~~~~\rho = \dfrac mV\\\\\\\implies V = \dfrac m{\rho}\\\\\\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{\tfrac{5.6 \times 10^{-3}~ \text{kg}}{ 10^{-6} ~\text{m}^3} }\\\\ \\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{5.6 \times 10^{-3} \times 10^6~~ \text{kg}~ \text{m}^{-3}}\\\\\\ \implies V = 1.25 \times 10^{-6}~ \text m^3\\\\\\\implies V =0.00000125~ \text m^3\\\\\text{Hence the volume of the coin is 0.00000125}~ \text m^3[/tex]
Water has a heat capacity or 4.184 j/g C. If 50 g of water has a temperature of 30C and a piece of hot copper is added to the water causing the temperature to increase to 70C. What is the amount of heat absorbed by the water.
Answer:
Ethanol C2H5OH or propane C3H8 have more energy
Explanation:
Calculate the average force with which the Sun pulls the Earth. It will help to know
that rsun_Earth = 9.4E9 m.
Answer:
7.9 x 10^21 pound-force
Explanation:
The average distance between the Earth and sun is 150 trillion meters, or 1.5 x 10^11 meters. The mass of the sun is 1.99 x 10^30 kilograms, while the Earth weighs in at 6.0 x 10^24 kilograms. The gravitational constant is 6.67 x 10^-11 meter^3 / (kilogram - second^2). So the Earth and sun pull on each other with a force equal to 3.52 x 10^22 newtons. The newton is a unit of force equal to a kilogram-meter/second^2. One newton is equal to 0.22 of the rarely used English unit called pound-force, so 3.52 x 10^22 newtons is 7.9 x 10^21 pound-force.
How does the maximum value of the current depend on the frequency of the ac voltage source?.
The maximum value of the current depend on the frequency of the ac voltage source because it increases as the frequency increases.
What is peak current of AC source?
The peak current of an ac source is the amplitude current flowing in the ac circuit.
The magnitude of the peak current is calculated as follows;
I₀ = i/(sin ωt)
I₀ = i/(sin 2πft)
where;
I₀ is the peak currenti is the ac currentω is angular speedf is the frequencyt is timemaximum value ac currenti = I₀ x sin 2πft
From the equation above, as the frequency of the of the ac voltage source increases, the value of the ac current (i) increases.
Thus, the maximum value of the current depend on the frequency of the ac voltage source because it increases as the frequency increases.
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An iron sphere of radius 0.18m has mass 190 kg. Calculate the density of the iron
Volume:-
[tex]\\ \sf\rightarrowtail \dfrac{4}{3}\pi r^3[/tex]
[tex]\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.18)^3[/tex]
[tex]\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.005832)[/tex]
[tex]\\ \sf\rightarrowtail 0.024m^3[/tex]
Mass=190kgDensity:-
[tex]\\ \sf\rightarrowtail \dfrac{Mass}{Volume}[/tex]
[tex]\\ \sf\rightarrowtail \dfrac{190}{0.024}[/tex]
[tex]\\ \sf\rightarrowtail 7916.67kg/m^3[/tex]