Examine the following wavelength.
2 functions on a coordinate plane. One has 7 wavelengths and the other has 3.5 wavelengths.
What is the ratio of the wavelengths of these two notes?
a.
5 to 4
b.
3 to 2
c.
6 to 5
d.
2 to 1



Please select the best answer from the choices provided

The correct option is c) 729

Explanation :-

Now , we just need to substitute " x = 3 " and " y = -1 " in the equation above.

Answer:

6 Hours

Explanation:

Linear Equation: mx+b=y

x variable: Hour

Hourly Fee: $15(x)

(Initial) Rent Fee: $25

Balance: $100

Equation:

15x+25=100

15x+25-25=100-25 -- Separate the constant terms from the x by subtracting 25 from both sides.

15x=100

15x/15=100/15 -- Isolate the x variable by dividing 15 from both sides.

x=6.6.. -- Round down to 6 (not 7) because you can't afford to snowboard for 7 hours with less than $15.

x=6 Hours

answer: 6 hours

Step-by-step explanation:

I did this on a paper

Answer:

D

Step-by-step explanation:

Here's why I think it's D.

y = x + 44 is the equation the car wash owner uses

x represents the number of days

y represents the number of cars (washed)

so if we plug in one of the given numbers (from the chart)

example:

Day 2 Numbers of Cars Washed 44

2 will represent the "number of days" also known as x

44 will represent the "number of cars" also known as y

so if we plug in those values to the equation the car wash owner uses

y = x + 44, it doesn't match

__________________________________

(44) = 2 + (44)

44 [tex]\neq[/tex] 46

Therefore, I believe the answer is D

Answer:

D

Step-by-step explanation:

[tex] \: [/tex]

Step-by-step explanation:

It is given that, the height of a triangle is 3cm, and its base is 3cm and we are to find the area of triangle.

[tex] \: [/tex]

To find the area of the triangle, we have to know this formula :

[tex]\\ {\longrightarrow \pmb{\frak {\qquad Area_{(Triangle)} = \: \frac{1}{2} \times Base \times Height \:}}} \\ \\ [/tex]

Now, substituting the values in the formula :

[tex]{\longrightarrow \pmb{\sf {\qquad Area_{(Triangle)} = \: \frac{1}{2} \times 3 \times 3 \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad Area_{(Triangle)} = \: \frac{1}{2} \times 9 \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad Area_{(Triangle)} = \: \frac{9}{2} \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\frak {\qquad Area_{(Triangle)} = \: 4.5 \:}}} \\ \\ [/tex]

Therefore,

Answer:

4.5cm^2

Step-by-step explanation:

Find area of a square 3*3=9

Half of a square is 9/2=4.5

Answer:

what do you want to ask brother...

Step-by-step explanation:

or you post this by mistake.....

Answer:

3(x-6)=3x-18

Step-by-step explanation:

The name of the provided polynomial equation is trinomial and the degree of the polynomial is 2.

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

Types of polynomial equation on the basis of number of terms:

The given expression is,

[tex]3x^2 + x^2 +x[/tex]

Hence,  the name of the provided polynomial equation is trinomial and the degree of the polynomial is 2.

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65%= 234

100%= 234÷65×100

100%= 360

75%= 360÷100×75

75%= 270

Answer:

It should be called A decic polynomial

Step-by-step explanation:

A best example of an out-of-pocket cost is: C. A deductible.

An out-of-pocket cost can be described as a cost you pay from your own personal reserve, which may include coinsurance, deductibles, copays, and some services covered by an individual's health plan.

Out-of-pocket cost may be reimbursed.

Thus, a best example of an out-of-pocket cost is: C. A deductible.

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Answer: C. A deductible

Step-by-step explanation:

Answer:

Area is 24 unit ²

Step-by-step explanation:

Given :-

To find:-

Solution:-

We know , The formula for finding area of triangle is 1/2×b×h

putting the known values ,

Area = 1/2 × 8 × 6 unit²

Area = 24 unit²

Use L'Hopital's rule twice:

[tex]\displaystyle \lim_{x\to0^+} \frac1{\sin^2(x)} \int_{\frac x2}^x \sin^{-1}(t) \, dt = \lim_{x\to0^+} \frac1{\sin^2(x)} \left(\int_0^x \sin^{-1}(t) \, dt - \int_0^{\frac x2} \sin^{-1}(t) \, dt\right) \\\\ = \lim_{x\to0^+} \frac{\sin^{-1}(x) - \frac12 \sin^{-1}\left(\frac x2\right)}{2\sin(x)\cos(x)} ~~~~~~~~~~ (LHR) \\\\ = \lim_{x\to0^+} \frac{2\sin^{-1}(x) - \sin^{-1}\left(\frac x2\right)}{2\sin(2x)} \\\\ = \lim_{x\to0^+} \frac{\frac2{\sqrt{1-x^2}} - \frac1{2\sqrt{1-\frac{x^2}4}}}{4\cos(2x)}  ~~~~~~~~~~ (LHR) \\\\ = \lim_{x\to0^+} \frac{\frac2{\sqrt{1-x^2}} - \frac1{\sqrt{4-x^2}}}{4\cos(2x)}[/tex]

The remaining limand is continuous at x = 0, and the limit is

[tex]\displaystyle \lim_{x\to0^+} \frac1{\sin^2(x)} \int_{\frac x2}^x \sin^{-1}(t) \, dt = \frac{2-\frac12}4 = \boxed{\frac38}[/tex]

16 students take both maths and english, 4 students took neither and 15.38% of the students are taking math but not English

Probability is the likelihood of occurrence of an event. It is given by:

Probability = number of occurrence / total possible outcomes.

Let x represent the number of students that took both maths and english, hence:

Number of students taking only maths = 20 - x

Number of students taking only english = 22 - x

26 = 20 - x + (22 - x) + x

42 - x = 26

x = 16

b) Those who took neither = 30 - 26 = 4

c) those taking only math = 20 - 16 = 4.

Percentage = (4/26) * 100 = 15.38%

16 students take both maths and english, 4 students took neither and 15.38% of the students are taking math but not English

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Answer:

15.6204994

Step-by-step explanation:

[tex]15.6204994^{2} = 244\\so\\\sqrt{244} = 15.6204994[/tex]

hope this helps!

Answer:

75 kilómetros por hora creo no estoy muy seguro

Step-by-step explanation:

question no. 21 answer

8 units

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

By using Distance formula ~

[tex]\qquad❖ \: \sf \: \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} } [/tex]

[tex]\qquad❖ \: \sf \: \sqrt{ ( - 8 - ( - 8)) {}^{2} + ( - 8 - 5) {}^{2} } [/tex]

[tex]\qquad❖ \: \sf \: \sqrt{0 + ( - 13) {}^{2} } [/tex]

[tex]\qquad❖ \: \sf \: \sqrt{169} [/tex]

[tex]\qquad❖ \: \sf \:13 \: \: units[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

The distance between the points is 13 units

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's find the circumference of given circle ~

Circumference :

[tex]\qquad \tt\dashrightarrow \:c =2 \pi r[/tex]

where,

now, let's calculate circumference ~

[tex]\qquad \tt  \dashrightarrow \:c = 2 \times \pi \times 3[/tex]

[tex]\qquad \tt  \dashrightarrow \:c = 6 \pi \: \: yd[/tex]

Now, let's plug in approximate value of pi :

[tex]\qquad \tt  \dashrightarrow \:c = 6 \times 3.14 \: \: [/tex]

[tex]\qquad \tt \dashrightarrow \:c = 18.84 \: \: yd[/tex]

So, here in part a), we are given n terms (no specific no. of terms given), so no. of terms = n , also, the common difference is defined as the difference between the next term to a specific term and the term, i.e [tex]{\bf{d=a_{n}-a_{n-1}}}[/tex], where d is the common difference, so here d = 49 - 45 = 4

Also, here the last term is 49 let say it the nth term, as no number of terms are given, so using the Arithmetic Progression formula, we can write as ;

[tex]{:\implies \quad \sf a+(n-1)d=49}[/tex]

[tex]{:\implies \quad \sf a+(n-1)4=49}[/tex]

[tex]{:\implies \quad \sf a+4n-4=49}[/tex]

[tex]{:\implies \quad \sf a=49+4-4n=\boxed{\bf{53-4n}}}[/tex]

Now, as we assumed there are n terms, so using the sum formula, we can have ;

[tex]{:\implies \quad \sf S_{n}=\dfrac{n}{2}(a+a_{n})}[/tex]

[tex]{:\implies \quad \sf S_{n}=\dfrac{n}{2}(53-4n+49)}[/tex]

[tex]{:\implies \quad \sf S_{n}=\dfrac{n}{2}(102-4n)}[/tex]

[tex]{:\implies \quad \sf S_{n}=n(56-2n)=\boxed{\bf{-2n^{2}+56n}}}[/tex]

Now, for part b) we are given a geometric progression with first term = a = 1, common ratio = r = (3/1) = 3, and no. of terms = n = 6, so now putting all values in the sum formula we will have;

[tex]{:\implies \quad \sf S_{6}=\dfrac{1\{1-(3)^{6}\}}{1-3}}[/tex]

[tex]{:\implies \quad \sf S_{6}=\dfrac{1-729}{-2}}[/tex]

[tex]{:\implies \quad \sf S_{6}=\dfrac{-728}{-2}=\boxed{\bf{364}}}[/tex]

Answer:

4240 in²

rectangle prism area: 2(wl+hl+hw)

=======

area:

Answer:

x = 45

Step-by-step explanation:

Note that:

The sum of the interior angles of a quadrilateral is 360°.

Angle: ADC+BAD+ABC+BCD = 360°

Thus, Substitute  ∠ABC = 3x, ∠BAD = (2x-5) , ∠ ADC = (x+15), ∠ BCD = 80 turn into ADC+BAD+ABC+BCD = 360° :

Also known as :

(x+15) +(2x-5) + 3x+80=360

Solving for x

Add the numbers

x + 90+2x+3x=360

Combine like terms

6x + 90=360

subtract 90 from both sides

6x = 270

x = 45

Hence the value of x = 45

Kavinsky

Answer:

C. 45

Step-by-step explanation:

1) Sum of the interior angles of any shape:

(n - 2) x 180, where n is the number of vertices of a shape. In this case, we have 4 vertices.

= (4 - 2) x 180

= 2 x 180

= 360°

2) Add all the given values equating to 360.

2x - 5 + 3x + 80 + x + 15 = 360

6x + 90 = 360

6x = 360 - 90

6x = 270

x = 270/6

x = 45

The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 is 0.4179.

The probability that a candidate chosen at random from among these two sets of candidates will have selected questions 1, 2 and 3 will ba calculated thus:

= [(9C6 /12C9) × 1/2] + [(9C7)/12C10) × 1/2]

= 42/220 + 18/66

= 0.1909 + 0.2727

= 0.4179

In conclusion, the probability is 0.4179.

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Answer:

111.3 cubic inches

Step-by-step explanation:

The dimensions of the rectangular prism are 5.9 x 3.4 x 5.1

volume = length x width x height

V = 5.9 x 3.4 x 5.3

V = 102.306

The dimesnsions of the triangular prism are 3.4 x 5.9 x ?

to find the missing length, 6 - 5.1 = 0.9

3.4 x 5.9 x 0.9

Volume = (3.4 x 5.9 x 0.9)/2

V = 18.054/2

V = 9.027

Add the volumes together

102.306 + 9.027 = 111.333

Round

111.3

Answer: 1/4

Step-by-step explanation: 1/8 plus 1/8 is 2/8. it can be simplified to 1/4

The TRUE statement that compares debit cards to credit cards is D) Debit cards make tracking day-to-day spending easier than credit cards.

Debit cards are payment cards linked to the holder's bank account. Payment transactions are automatically deducted from the account.

Debit cards depend on the holder's bank balance to make payments, unlike credit cards that give access to borrowing money for purchases so that repayment may be made later.

Thus, the main difference between debit cards and credit cards is that debit cards make the holder accountable for their spending while credit cards give access to credit borrowing.

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Answer:

1. The wind has blown all the leaves off the tree.

2. All the leaves have fallen to the ground.

3. My kite is being flown in the wind.

4. A shower of acorns have fallen from the sky

5. A busy squirrel dug for his acorns.

6. In the garden, pumpkins have grown.

7. Yesterday my friend and I rode to the park.

8. We have rode to the skate park.

9. My brother wrote me a letter.

10. He has written a essay.

11. Our neighbor had given us a pie.

12. Mom and Dad have spoken to me about cleaning my room.

Step-by-step explanation:

Answer:

Your answer would be 12cm

Step-by-step explanation:

I just take a quiz and got it right.

Given Information :-

⠀⠀

⠀

To Find :-

⠀

⠀

Solution :-

⠀

To find the percentage of expenditure, we must know how much amount does he really spend, thus :

⠀

➥ Expenditure = Earnings - Savings

➥ Expenditure = Rs. 9600 - Rs. 2400

➥ Expenditure = Rs. 7200

⠀

Now, we can find the percentage,

⠀

[tex] \sf \hookrightarrow Percentage_{expenditure} = \dfrac{Expenditure}{Earnings} \times 100 \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{7200}{9600} \times 100 \qquad \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{72 \cancel{00}}{96 \cancel{00}} \times 100 \qquad \quad \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \frac{ \cancel{72}}{ \cancel{96}} \times 100 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \cancel \frac{3}{4} \times 100 \qquad \qquad \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = 0.75 \times 100 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Percentage_{expenditure} = \underline{ \boxed{ \orange {\frak{75\%}}}} \: \star \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ [/tex]

Thus, the percentage of his expenditure is 75%.

⠀

[tex] \underline { \rule{227pt}{2pt}}[/tex]

⠀

Answer:

5%

Step-by-step explanation:

Earns= Rs 640

Spends= Rs 608

Saves= (Rs 640 - Rs 608) =Rs 32

therefore, 32/640x100

The total amount of money in Mr Baldera's savings account at this point in time is $3231.33.

The formula that can be used to determine the future value with annual compounding is:

FV = P (1 + r)^n

150 x (1.0674)^47 = $3231.33.

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Answer:

6x-3(2x-5)=9

6x-6x+15=9

15=9

no sollution

Null hypothesis (H0): The mean level of the chemical in tomatoes from this producer is equal to or less than the recommended level of 0.4 ppm.

Given that, the maximum acceptable level of a certain toxic chemical in vegetables has been set at 0.4 parts per million (ppm).

Alternative hypothesis (H1): The mean level of the chemical in tomatoes from this producer is greater than the recommended level of 0.4 ppm.

To test the claim, we will use a one-tailed hypothesis test with a significance level of 0.05. The test statistic is calculated by subtracting the mean of the sample from the mean of the population, and dividing the result by the standard deviation of the population.

Test statistic = (Sample mean - Population mean) / Standard deviation of population

Test statistic = (0.465 - 0.4) / 0.21

Test statistic = 2.38

Since the test statistic is positive, we can reject the null hypothesis. The P-value for this test statistic is 0.0095, which is less than 0.05.

Therefore, the data provides sufficient evidence to support the claim that the mean level of the chemical in tomatoes from this producer is greater than the recommended level of 0.4 ppm.

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