[tex]4 {}^{3} .(100 \div 25) - 5 {}^{0} [/tex]
Solution[tex] {4}^{3} \times (100 \div 25) - {5}^{0} \\ \\ = 64 \times 4 - 1 \\ \\ = 256 - 1 \\ \\ = 255[/tex]
[tex] \fbox \red{Hope This Helps }[/tex]
Answer:
255
Step-by-step explanation:
1) Simplify 100 ÷ 25 to 4.
4³ × 4 - 5⁰
2) Use Rule of Zero: x⁰=1
4³ × 4 - 1
3) Use Product Rule
4⁴ - 1
4) Simplify 4⁴ to 256
256 - 1
5) Simplify
255
A student's height is measured as 66 in. to the nearest inch. What are the
student's minimum and maximum possible heights?
Help asapppp pleaseeeeeee
Find the perimeter and area of the figure with the given coordinates:
A(-2,-1), B(-2,-4), C(3,-4), D(3,-1)
show your solution need an answer, please need an answer, please.
Answer:
As follows,
Step-by-step explanation:
You can solve these either by factoring or using the quadratic formula or other ways,
1. x^2+2x+1=0
Factoring,
(x+1)^2=0
x+1=0
x=-1
2.y^2-y-2=0
Using quadratic formula,
(-b±√(b^2-4ac))/2a
(--1±√(-1^2-4*1*-2))/2*1
(1±√(1+8))/2
(1±√(9))/2
(1±3)/2
y=(1±3)/2
y=(1+3)/2 y=(1-3)/2
y=4/2 y=-2/2
y=2 y=-1
3.y^2+y+1=0
Using quadratic formula,
(-b±√(b^2-4ac))/2a
(-1±√(1^2-4*1*1))/2*1
(-1±√(1-4))/2
(-1±√(3))/2
No real roots
4. x^2+9x+18=0
Using quadratic formula,
(-9±√(9^2-4*1*18))/2*1
(-9±√(81-72))/2
(-9±√(9))/2
(-9±3)/2
x=(-9+3)/2 x= (-9-3)/2
x=-6/2 x=-12/2
x=-3 x=-6
5.x^2+5x+6=0
Using quadratic formula,
(-5±√(b^2-4ac))/2a
(-5±√(5^2-4*1*6))/2*1
(-5±√(25-24)/2
(-5±1)/2
x=(-5+1)/2 x=(-5-1)/2
x=-4/2 x=-6/2
x=-2 x=-3
6. 3n^2-13n-10=0
Using quadratic formula,
(-b±√(b^2-4ac))/2a
(-(-13)±√(-13^2-4*3*(-10)))/2*3
(13±√(169-(-120))/6
(13±√289)/6
The discriminant b^2−4ac>0
So there are 2 real roots.
x=(13±17)/6
x=30/6 or x=-4/6
x=5 or x=-2/3
please help with #2 and #4
Answer:
Problem 2: k = 3
Problem 4: NO SOLUTION
Step-by-step explanation:
Problem 2 work:
-4/3(12k + 27) = -57 - 9k
-16k - 36 = -57 - 9k -ADD THE -9k TO ITSELF AND TO -16k-
-7k - 36 = -57 -ADD THE -36 TO ITSELF AND -57-
-7k = -21
k = 3
Problem 4 work:
5/2(6w - 16) = 18w -(3w + 40)
15w - 40 = 18w - 3w - 40 -ADD THE -3w TO THE 18w-
15w - 40 = 15w - 40
NO SOLUTION BECAUSE BOTH SIDES ARE THE SAME
Answer:
5;:':;;gighifighfutfdyfuhufgfyhxfkcy
30/40 in simple form
Answer:
The simplest form is 3/4
Step-by-step explanation:
Cancel the common factor of 30 and 40
Write the Fraction in Simplest Form Of 30/40
Proof Hexagon:
Hey, I'm a German 11th grader and we currently have a tough geometry question: The centers A, B, C of three congruent circles that have no common points do not lie on the same straight line. From points A, B, C, the six tangents shown in the figure are placed on the circles that enclose a convex hexagon.Prove: The sums of the lengths of three pairs of not immediately adjacent sides of this hexagon are equal, i.e. | PQ | + | RS | + | TU | = | QR | + | ST | + | UP |
How can I prove this? I already found out that the triangles on the sides of the hexagon are not pairwisely congruent, as i first thought. I think my other idea that the red and orange triangles (attachment) are congruent, so the sum of the areas of the triangles on the above mentioned sides is equal, but the congruency of red and orange must be proven too. Any help is appreciated!
If I'm not wrong, then the answer will be:-
Given
• centers A, B, C
• three congruent sides
• have no common points
So, the result is:-
| PQ | + | RS | + | TU | = | QR | + | ST | + | UP |
ProvedI hope this answer is correct and helps you.
✍️ By Benjemin ☺️
Suppose that G(x) = F(x) + 6. Which statement best compares the graph of
G(x) with the graph of F(x)?
O A. The graph of G(x) is the graph of Fx) shifted 6 units to the right.
O B. The graph of G(X) is the graph of F(x) shifted 6 units up.
O C. The graph of G(x) is the graph of F(X) shifted 6 units down.
O D. The graph of G(x) is the graph of Fx) shifted 6 units to the left.
9514 1404 393
Answer:
B. (the correct choice is marked)
Step-by-step explanation:
The value of the function for a given x is the vertical position of the point on the graph. Adding 6 to the function value shifts the graph up 6 units.
The graph of G(x) is the graph of F(x) shifted 6 units up.
x + 3y >/3
5x + 3y -9
which data set shows greater variability ?why?
A or B
shows greater variability because the MAD is greater that the MAD for
A or B
Solve 15t – 6 < 12t.
t > 2
t < 2
t < -2
t > -2
Answer:
T<2 its the answers
Your welcome
For a experimental to produce useful data, what must happen
Answer:
cr qe deobpaase r
Step-by-step explanation:
Please help!!!!!!!!!!!!!!!!!!!!!!
Answer:
45∘
Step-by-step explanation:
So, the reference angle is 360∘−315∘=45∘
Hope this helps! :D
HELPPPP!!!!! PLEASEEE IM BEING TIMED !!!!!!!!!!!
Answer:
[tex]x=89[/tex]
Step-by-step explanation:
We can plug into the formula for the mean to get [tex](87+73+84+82+x)/5=83[/tex].
We can combine like terms on the left side to get [tex](326+x)/5=83[/tex].
We can multiply by [tex]5[/tex] on both sides to get [tex]326+x=415[/tex].
We can finally subtract [tex]326[/tex] from both sides to get [tex]x=89[/tex].
So, the answer is [tex]\boxed{x=89}[/tex] and we're done!
3 T-shirts cost $12. How
much will 50 T-shirts
cost?
Answer:
$200
Step-by-step explanation:
First, find the unit rate:
12/3= 4
Then multiply:
4*50= 200
Hope this helps!
george started a coin collection. his dad gave him 75 coins. each month he will add 20 coins. Which equation can be used to find y, the total number of coins in george's collection after x months? A. y = 75x + 20x By = 20x + 75 C. y = 75x - 20 D. 20x - 75
Answer: B
Step-by-step explanation: Hope this helps!
he got a one time thing of 75 coins and now gets 20 coins for each month which explains 20x. (X being the number of months)
The equation that could be used for determining the y should be option B y = 20x + 75
Calculation of an equation:
Since dad gave him 75 coins. each month he will add 20 coins.
Here we assume a number of months be x
So, the equation is
y = 20x + 75
Therefore, we can conclude that The equation that could be used for determining the y should be option B y = 20x + 75
learn more about an equation here: https://brainly.com/question/24271130
1.
WRITE "six million five hundred thousand four" in standard form.
Last year, the amount of 6th grade students currently enrolled in orchestra is twice the amount of 8th grade students. There are 10 more 7th grade students in orchestra than 8th grade students
Write expressions for the number of students in orchestra at each grade level if the number of students is represented by x students
Answer:
X=8th grade 2x=6th grade x +10=7th grade
I need help guys please
i will be thankful
Answer:
16.94 cm
Step-by-step explanation:
Jenny runs 7 miles in 80 minutes. At the same rate, how many miles would she run in 64 minutes?
Answer:
5.6miles
Step-by-step explanation:
find Jenny's speed per minute,
ie distance/time
[tex]\frac{7}{80} miles \: per \: minute[/tex]
find the distance travelled by multiplying the speed by the time
[
[tex] \frac{7}{80} \times 64 = \frac{56}{10} \\ = 5.6[/tex]
Which graph represents the solution set of this inequality?
5y + 9 < 24
Answer:
D
Step-by-step explanation:
open circle cause there is no line under the sign and the sign points left
PLEASE HELP ME LAST TIME I USED THIS APP SOEMBODY PUT RANDOM STUFF
Answer:
[tex]3.17 \times {10}^{ - 3} [/tex]
Step-by-step explanation:
First let's put the distance of Pluto in scientific notation:
3,670,000,000 = 3.67•10⁹
Now, to find the time you have to divide the distance by the speed, in this case is the distance from sun to Pluto, and the speed of light:
(1.17•10⁷)÷(3.67•10⁹) = 0.00317 minutes
Now put the result in scientific notation:
0.00317 = 3.17•10-³
Calculus, derivatives. Please help! Show work, if possible. Thanks! :)
Answer:
a. y=4
b. graph the given and y=4
Step-by-step explanation:
The given is y= 8 sin(x) cos(x)
to get y' which is the slope of the tangent line we take the derivative
for this problem, the derivative involves the constant rule (which states that the derivative a constant times a value is just the constant times the derivative of said value) and the multiplication rule (assuming that the two parts in question are represented by the variables a and b then the derivative of a*b = a*b'+b*a')
thus we get 8*(sin(x)*-sin(x)+cos(x)*cos(x))
-8sin^2(x)+8cos^2(x)
You can also leave the 8 differentiated out depending on the form you need.
Now that we have the derivative we can plug pi/4 into this equation to get the slope of the tangent line at that point
=8sin^2(pi/4)+8cos^2(pi/4)
this would equal -8*1/2 +8*1/2 which equals 0
the slope of the tangent at this point would be zero
To get the point for point slope form we plug the pi/4 into the given equation to get a y value and get the point (pi/4, 4)
this means the point slope equation would be
y-4=0(x-pi/4)
y-4=0
y=4
To graph you would just enter the given equation and the equation for the tangent line into a graphing software or calculator and see if the line is tangent at the point (pi/4, 4)
94. Birth Rate of Unmarried Women In the United States, the birth rate B of unmarried women (births per 1000 unmarried women) for women whose age is a is modeled by the function B(a) = -0.33a + 19.17a-213.37. (a) What is the age of unmarried women with the highest birth rate? 29.0 years (b) What is the highest birth rate of unmarried women? (e) Evaluate and interpret B(40).
Using concepts of quadratic equation, we have that:
a) The age of unmarried women with the highest birth rate 29 years.
b) The highest birth rate of unmarried women is of 65 births per 1000 unmarried women.
c) B(40) = 25.43, which means that the birth rate of unmarried women of age 40 is of 25.43 births per 1000 unmarried women.
The birth-rate for women of age a is given by:
[tex]B(a) = -0.33a^2 + 19.17a - 213.37[/tex]
Which is a quadratic equation with coefficients [tex]a = -0.33, b = 19.17, c = -213.37[/tex]
Item a:
The age with the highest value is the a-value for the vertex, which is:
[tex]a_V = -\frac{b}{2a} = -\frac{19.17}{2(-0.33)} = 29[/tex]
The age of unmarried women with the highest birth rate 29 years.
Item b:
The rate is B(29), which is:
[tex]B(29) = -0.33(29)^2 + 19.17(29) - 213.37 = 65[/tex]
The highest birth rate of unmarried women is of 65 births per 1000 unmarried women.
Item c:
[tex]B(40) = -0.33(40)^2 + 19.17(40) - 213.37 = 25.43[/tex]
B(40) = 25.43, which means that the birth rate of unmarried women of age 40 is of 25.43 births per 1000 unmarried women.
A similar problem is given at https://brainly.com/question/24626341
Solve for d.
Help is appreciated thank u!!
Answer:
d = 16.88
Step-by-step explanation:
Start by simplifying both sides of the equation then isolate the variable
For a quadrilateral ABCD inscribed in a circle of radius 1, let AB : AD = 1 : 2 and ∠BAD = 120°. Also, when the point of intersection of diagonals BD and AC is denoted by E, let BE : ED = 3 : 4. Please find the area of triangle ABD and triangle BCD. (Show work)
The area of triangle ABD = x² * √3 / 2 and The area of triangle BCD = y * √(5x² + 4y² - 2xy√5)
To find the area of triangle ABD, we can use the formula for the area of a triangle: Area = (1/2) * base * height
In triangle ABD, the base is AD and the height is the perpendicular distance from point B to line AD. Since AB : AD = 1 : 2, we can let AB = x and AD = 2x.
Now, we can use the Law of Cosines to find the length of side BD. In triangle ABD, we have:
BD² = AB² + AD² - 2 * AB * AD * cos(∠BAD)
BD² = x² + (2x)² - 2 * x * (2x) * cos(120°)
Simplifying the equation:
BD² = x² + 4x² - 4x² * (-1/2)
BD² = 5x²
Taking the square root of both sides:
BD = √(5x²) = x√5
Since BE : ED = 3 : 4, we can let BE = 3y and ED = 4y.
Now, we can find the length of side BC. In triangle BCD, we have:
BC² = BD² + CD² - 2 * BD * CD * cos(∠BCD)
BC² = (x√5)² + (2y)² - 2 * (x√5) * (2y) * cos(∠BCD)
BC² = 5x² + 4y² - 4xy√5 * cos(∠BCD)
Since the quadrilateral ABCD is inscribed in a circle, ∠BCD = 180° - ∠BAD = 60°.
BC² = 5x² + 4y² - 4xy√5 * cos(60°)
BC² = 5x² + 4y² - 4xy√5 * (1/2)
BC² = 5x² + 4y² - 2xy√5
The area of triangle ABD is given by:
Area ABD = (1/2) * AB * AD * sin(∠BAD)
Area ABD = (1/2) * x * 2x * sin(120°)
Area ABD = x² * √3 / 2
The area of triangle BCD is given by:
Area BCD = (1/2) * BC * CD * sin(∠BCD)
Area BCD = (1/2) * √(5x² + 4y² - 2xy√5) * 2y * sin(60°)
Area BCD = y * √(5x² + 4y² - 2xy√5)
Further calculations require numerical values for x and y to obtain specific areas.
For more such questions on area of triangle
https://brainly.com/question/28470545
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4. Tom rides his bike a total of 6 14 miles to work over the course of 5 days.
How far does he ride each day?
How far will Tom ride his bike to and from work in 3 weeks?
6 14 miles in 5 days.
In 1 day Tom rides 6 14/5 = 1 228 miles
1 week has 7 days
5 weeks have 35 days
1 day Tom rides 1 228 miles
35 days Tom rides for 1 228 * 35 = 42 98miles.
A student pushed a cart and records its position as it moves along a track. During
which part or parts of the track did the cart experience unbalanced forces? *
Motionless
Speed Increased
Speed Decreased
E--
OO
Part 1 only
Parts 1 and 2 only
Part 3 only
Parts 2 and 3 only
What number would you get if you multiply the's numbers
1,2,3,4,5,6,7,8,9,10 ?
6(2 – 3) = 2(3z - 9)
[tex]▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ [/tex]
let's solve for z :
[tex]6(2 - 3) = 2(3z - 9)[/tex][tex]6( - 1) = 6z - 18[/tex][tex] - 6 + 18 = 6z[/tex][tex]6z = 12[/tex][tex]z = \dfrac{12}{6} [/tex][tex]z = 2[/tex]Answer:
z = 2
Step-by-step explanation:
6(2 - 3) = 2(3z - 9)
12 - 18 = 6z - 18
12 = 6z
2 = z
Hopefully this helped!
Brainliest please?