engineering economics​

A geostationary orbit is in same direction as the spinning of the earth while polar orbit is along the poles

Orbit describes the pathway a satellite moves. the pathway is usually circular.

Polar orbit refers to orbits that traces along the poles that is North pole and South pole. owing to the spherical nature of the earth polar orbits are shorter. This allows for a shorter time to complete a revolution.

Geostationary orbit as against the polar orbit , geostationary orbits traces same path as the Earth's spinning. This path os longer and will require more time to complete. Satellites tracing this orbits are launched further away about 36000 km above the earths surface while satellites on polar orbits is shorter about 200 km - 2000 km

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Answer:

Number1 = input("Choose a number: )

Number2 = input("Choose a second number: )

if number1 > number2:

print(number2\nnumber1)

else:

print(number1\nnumber2)

Explanation:

I'm assuming that you want it in python.

Answer:

2035

Explanation:

Most car and truck companies say that they will completely get rid of internal combustion engines by 2035.

Answer:

ill try to help you :)

Explanation:

The things that the professional in an increased demand green construction occupation can add in the construction of a shopping center include:

It should be noted that a green building simply means a design, construction, or operation that eliminates the negative impact on the climate and natural environment.

In this case, in order to illustrate energy efficiency, it's important to use radiant floors, geothermal system, energy efficient window systems, etc.

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Answer:

Explanation:

he metallic rod is fixed into the dies by using a die holder and then a drawing head is used in which the metallic rod is fixed through a jaw mechanism. And then the bar is stretched and slides between the surfaces of the die

Engineers take periodic site measurements to verify the scale conveys true information

measureants is the amount or extent of something ascertained through use of calibrated instrument called measuring instrument. When measurements are done on site it is called site measurements.

Engineers use the site measurements to scale their sketches hence to ensure the scale is always correct periodic measurements should be taken.

On-site measurements value and sketch measurement value gives the scale which  is the ratio, should be maintained always

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Answer:

With the ongoing pandemic, businesses have shifted their operations to online platforms while people have been forced to resort to work-from-home lifestyles to prevent the further prevent the spread of the virus.

Since this traffic flow has a jam density of 122 veh/km, the maximum flow is equal to 3,599 veh/hr.

Given the following data:

According to Greenshield Model, maximum flow is given by this formula:

[tex]q_{max}=\frac{V_f \times K_i}{4}[/tex]

Where:

In order to calculate the free flow speed, we would use this formula:

[tex]V_f =2 V\\\\V_f =2\times 59\\\\V_f=118\;km/hr[/tex]

Substituting the parameters into the model, we have:

[tex]q_{max}=\frac{118 \times 122}{4}\\\\q_{max}=\frac{14396}{4}[/tex]

Max flow = 3,599 veh/hr.

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Due to the fact that there is a 14.3inch deflection in the manometer, water is flowing towards the regions that have low pressure.

The fluid that is contained in the manometer is moving towards areas of low pressure. This means they are going to areas with high velocity.

The areas that have low cross sections would flow with a constant rate. This venturi would have low pressure because it has low cross sectional area.

The fluid in the device would then have to move from bottom to top towards the neck of the mercury.

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Answer:

When the AC power is larger than the DC load's needs, a big filter capacitor is typically employed to absorb and store energy, and to give energy to the load when the AC power is lower.

Explanation:

Explanation:

Structural Engineers create drawings and specifications, perform calculations, review the work of other engineers, write reports and evaluations, and observe construction sites. A Professional Engineer's license is required in order to practice Structural Engineering.

Answer:

Hold the tape in place and go down to the end.

Explanation:

This question is about Circle Geometry. it evaluates connected and broken lines with respect to circles.

This refers to the body of knowledge in mathematics that has to do with the various problems associated with the Circle.

In real-world scenarios, circle geometry is used in technologies involving:

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By using the concept of heat transfer, we need to add 0.045kg or 45g of ice to the glass of water to cool it from 20∘C to 0∘C.

The heat lost by the water is equal to the heat gained by the ice cubes. We can use the following equation to calculate the heat transfer:

Q = m_w * c_w * ΔT + m_i * L_f

where Q is the heat transfer, m_w is the mass of water, c_w is the specific heat of water, ΔT is the temperature change (20-0 = 20∘C), m_i is the mass of ice, and L_f is the latent heat of fusion of ice.

We know the values of m_w (0.45kg), c_w (4.18kJ/kg⋅∘C), ΔT (20∘C), and L_f (334kJ/kg). We can rearrange the equation to solve for m_i:

m_i = (Q - m_w * c_w * ΔT) / L_f

Substituting the values, we get:

m_i = [(0.45kg) * (4.18kJ/kg⋅∘C) * (20∘C) - 0] / (334kJ/kg

m_i = 0.045kg

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Answer:

He could put up advertisements all over the town and pay a few websites or search engines to have his company and ads be more common. He should also use some designs and make his company's sign very adequate.

The aliased frequency that is due to small sampling frequency is 675 Hz.

The proposed sampling frequency is 2f = 120

The signal frequency that is given in the question is 60Hz

The sampling frequency is 90Hz

a. Using Nyquist frequency,

fn = 0.5*90Hz = 45Hz

The aliased frequency =  |n*fn - fs|

aliased frequency = |n*fn - fs|

We have  n >= 1/Fs = 17ms

Then the aliased frequency is = 17 x 45 - 90

= 675 Hz

In order to avoid aliasing the sampling frequency, this has to be at least two times the highest frequency.

Therefore Fs =

2xF = 120Hz

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Answer:

I think it's the no 3rd

Explanation:

hope this helps

Hi :)

The answer is B. A cast part

How does a cast part form?

Molten material is then poured into a mould cavity that takes the form of the finished part. The molten material then cools, with heat generally until it solidifies into the desired shape.

Hope this helps!

Give the other person brainliest, they answered first

Hope this helps!

~NatLikesAnime~

#LearningWithBrainly.

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Tensile stress in a thin wall spherical shell is given by

σ = ( p r ) /2t

This is the type of stress that involves pulling out. it is the opposite of compressive stress.

The tensile stress, σ  at the circumference of the shell is the hoop stress. The value equals that of pressure acting on the area.

Therefore:

σ * 2πr * t = p * πr^2

where

2πr = circumference of a circle

πr^2 = area of a circle

p = internal pressure

t = thickness

σ * 2πr * t = p * πr^2

σ = ( p r ) /2t

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The minimum safety power that is safely dissipated using a transistor of height 0.4cm and diameter 0.06cm is 0.04665

[tex]\pi DL +\frac{\pi }{4} D^2\\\\Area = 3.14 * 0.6*0.4+\frac{3.14}{4} *0.6^2[/tex]

D = diameter = 0.6cm

Length = height = 0.4cm

Area = 1.0367cm²

hA (Ts - Tair)

30 * 1.0367 x 10⁻⁴(70-55)

= 0.04665

The minimum safety power that is safely dissipated is 0.04665W

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The type of Pass that Joe Maylan should be given is called; Temporary Pass

In factories or industries, there are different types of pass given to workers and visitors visit such places on a daily basis. In this case Joe maylan is going to do a job in the company for just 2 days and as such the type of pass he willl get will be a temporary pass.

It will be a temporary pass because it is a document pass issued for short-term use or due to an emergency.

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By using the boundary layer equation, the average heat transfer coefficient for the plate is equal to 4.87 W/m²k.

Given the following data:

Surface temperature = 15°C

Bulk temperature = 75°C

Side length of plate = 150 mm to m = 0.15 meter.

Since we have a quiescent room air and a uniform pole surface temperature, the film temperature is given by:

[tex]T_f=\frac{T_{s} + T_{\infty} }{2} \\\\T_f=\frac{15 + 75 }{2} \\\\T_f = 45[/tex]

Film temperature = 45°C to K = 273 + 45 = 318 K.

For the coefficient of thermal expansion, we have:

[tex]\beta =\frac{1}{T_f} \\\\\beta =\frac{1}{318}[/tex]

From table A-9, the properties of air at a pressure of 1 atm and temperature of 45°C are:

Next, we would solve for the Rayleigh number to enable us determine the heat transfer coefficient by using the boundary layer equations:

[tex]R_{aL}=\frac{g\beta \Delta T l^3}{v\alpha } \\\\R_{aL}=\frac{9.8 \;\times \;\frac{1}{318} \;\times \;(75-15) \;\times \;0.15^3 }{1.750 \times 10^{-5}\; \times \;2.416 \times 10^{-5} } \\\\R_{aL}=\frac{9.8\; \times 0.00315 \;\times \;60\; \times\; 0.003375 }{4.228 \times 10^{-10} }\\\\R_{aL}=1.48 \times 10^{7}[/tex]

Also take note, g(Pr) is given by this equation:

[tex]g(P_r)=\frac{0.75P_r}{[0.609 \;+\;1.221\sqrt{P_r}\; +\;1.238P_r]^\frac{1}{4} } \\\\g(P_r)=\frac{0.75(0.7241)}{[0.609 \;+\;1.221\sqrt{0.7241}\; +\;1.238(0.7241)]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{[0.609 \;+\;1.221\sqrt{0.7241}\; +\;1.238(0.7241)]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{[2.5444]^\frac{1}{4} }\\\\g(P_r)=\frac{0.543075}{1.2630 }[/tex]

g(Pr) = 0.430

For GrL, we have:

[tex]G_{rL}=\frac{R_{aL}}{P_r} \\\\G_{rL}=\frac{1.48 \times 10^7}{0.7241} \\\\G_{rL}=1.99 \times 10^7[/tex]

Since the Rayleigh number is less than 10⁹, the flow is laminar and the condition is given by:

[tex]N_{uL}=\frac{h_{L}L}{k} = \frac{4}{3} (\frac{G_{rL}}{4} )^\frac{1}{4} g(P_r)\\\\h_{L}=\frac{0.02699}{0.15} \times [\frac{4}{3} \times (\frac{1.99 \times 10^7}{4} )^\frac{1}{4} ]\times 0.430\\\\h_{L}= 0.1799 \times 62.9705 \times 0.430\\\\h_{L}=4.87\;W/m^2k[/tex]

Based on empirical correlation method, the average heat transfer coefficient for the plate is given by this equation:

[tex]N_{uL}=\frac{h_{L}L}{k} =0.68 + \frac{0.670 R_{aL}^\frac{1}{4}}{[1+(\frac{0.492}{P_r})^\frac{9}{16}]^\frac{4}{19} } \\\\h_{L}=\frac{0.02699}{0.15} \times ( 0.68 + \frac{0.670 (1.48 \times 10^7)^\frac{1}{4}}{[1+(\frac{0.492}{0.7241})^\frac{9}{16}]^\frac{4}{19} })\\\\h_{L}=4.87\;W/m^2k[/tex]

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A: Copper has a higher elastic modulus than aluminum.

B: The density of copper is closer to that of aluminum than it is to iron.

C: Bronze is an alloy of copper and zinc.

D: Copper and its alloys form a green tarnish over time, consisting of sulfides and carbonates.

E: Copper is relatively resistant to corrosion by neutral and even mildly basic water, making it useful for freshwater plumbing applications.

Answer:

Aerospace engineering is a broader subject that includes both aircraft and spacecraft studies. Aeronautical engineering focuses more on aircraft design and construction that flies within the Earth's atmosphere.

Explanation:

Aerospace engineering is a vast topic that involves research on both airplanes and spacecraft, further explained in the following paragraph.

The median annual pay for aerospace engineers is $116,500, according to the US Bureau of Labor Statistics. Aerospace engineers, on the other hand, make $56.01 per hour. According to Glassdoor, the national average compensation for an Aeronautical Engineer in the United States is $80,000.

Aerospace engineering is a vast topic that involves research on both airplanes and spacecraft. Aeronautical engineering is concerned with the design and building of aircraft that fly within the atmosphere.

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Answer:

Tungsten element has the second highest melting point. Pure tungsten can easily cut down with the help of hacksaw.

Answer: Because it does not undergo oxidation and it has a very high melting point when it glows in bulb it temperature goes upto 2500°C

Step-by-step Explanation:

The strength is mainly depends on the some of factors which are described below.

●molecular structure:- The molecular structure is responsible fir the intermolecular force of a metal or material which causes the increase and decrease of strngth of a metal. Tungsten molecular structure is much stringer then that of aluminium.

●Temperature:-The temlerature also plays a rule in the strenghtNess of a metal. Tge high temprature makes a metal soft.

●Composition :- The composition is mostly important for the strengthnesa of material. For ex the pure iron metal is much weeker the alotrophy of iron.