Number of observations would be necessary to determine the true cycle time with a 95% confidence level and an accuracy are 16.
Sample timings as observed are 3.5, 3.1, 4.0, 3.5, and 3.9.
Sample-time average (X) = (3.5+3.1+4+3.5+3.9)/5
The average sample time (X) is 3.6.
Observed time (T) Mean (X) (X - T) (X - T)^2
3.5 3.6 0.1 0.01
3.1 3.6 0.5 0.25
4.0 3.6 -0.4 0.16
3.5 3.6 0.1 0.01
3.9 3.6 -0.3 0.09
Allow Standard deviation to be S.
2 in (X-T) - 1 n
[tex]S=\sqrt{\frac{0.52}{4}}[/tex]
S = 0.3605
Considering that (h) = 0.05,
Given that 95% of the time,
Z value at 95% confidence interval = 1.96
Let N be the number of observations.
2 N= Z.S hX
[tex]N=(\frac{1.96X0.3605}{0.05X3.6})[/tex]
N = 15.4
N = 16 (rounded off to next whole number) (rounded off to next whole number)
Consequently, 16 observations are required.
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Answer:
Step-by-step explanation:
Number of observations would be necessary to determine the true cycle time with a 95% confidence level and an accuracy of 16.
Sample-time average (X) = (3.5+3.1+4+3.5+3.9)/5
The average sample time (X) is 3.6. Observed time (T) Mean (X) (XT) (X-T)^2
3.5 3.6 0.1 0.01
3.1 3.6 0.5 0.25
4.0 3.6 -0.4 0.16
3.5 3.6 0.1 0.01
3.9 3.6-0.3 0.09
Allow Standard deviation to be S.
2 in (X-T) - 1n
S=√0.52/4
S=0.3605
Considering that (h) = 0.05,
Given that 95% of the time,
Z value at 95% confidence interval = 1.96 Let N be the number of observations.
2 N=Z.S hx
N=(1.96X0.3605)÷(0.05×3.6)
N = 15.4
N = 16 (rounded off to next whole number) (rounded off to next whole number) Consequently, 16 observations are required.
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At a conference 1 car was provided for every 4 people if there were 17 cars how many people were there
Answer:
just multiply 17×4=?
and it will give u an anserew..
Answer:68 people
Step-by-step explanation:
You take the 17 cars multiplied by four people and you get 68
At a high school, the cafeteria staff provides optional comment cards to students eating in the cafeteria. Students who wish to make a comment can obtain and fill out a comment card and return it to a drop box in the front office. At the end of the semester, the staff analyzes the responses and finds that 72% of the students who filled out a comment card recommend major changes to the food selection. What conclusions can the cafeteria staff draw from these responses?.
Based on the described sampling approach, it should be concluded that the responses were from a voluntary response sample, so the cafeteria staff should not use the results to draw any conclusions. (Option D).
Voluntary response sample refers to a response sample in which the researcher puts out a request for population members to join the sample, and the decision of whether or not to be in the sample resides with the people. As it is a sample comprising of voluntarily participants, people who chose to participate usually do so as they have a strong opinion on the subject of the survey. Typically, voluntary response samples oversample members with strong opinions and under sample members with little to no opinion on the subject of the survey. Hence, inferences from a voluntary response sample are not as reliable as conclusions based on a random sample of the entire population under consideration.
Note: Question is incomplete. The options were missing which are a. Since all of the students had an opportunity to respond, this is evidence that a majority of all the students supports major changes. b. The cafeteria staff should not use the results to draw any conclusions since some students may not have filled out a comment card, which is nonresponse. c. If the students recorded their grade level with their response, the staff could make the original sample a stratified sample and use the responses to learn what proportion of each grade recommends major changes to food selection. d. The responses were from a voluntary response sample, so the cafeteria staff should not use the results to draw any conclusions. e. The opportunity to fill out comment cards should be offered to students at all high schools in the school district to get a larger sample size, which will make the results more reliable
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3 3 Luke started a weight-loss program. The first week, he lost x pounds. The second week, he lost 2 pounds less than 2 times the pounds 3 he lost the first week. The third week, he lost 1 pound more than ã of the pounds he lost the first week. 3 Liam started a weight-loss program when Luke did. The first week, he lost 1 pound less than 2 times the pounds Luke lost the first 5 week. The second week, he lost 4 pounds less than 2 times the pounds Luke lost the first week. The third week, he lost 2 pound more 5 than 3 times the pounds Luke lost the first week. Assuming they both lost the same number of pounds over the three weeks, complete the following sentences. 4 pounds 6 pounds 21 4 2 pounds 13 - 40Luke started a weight loss program the first week he lost X pounds the second week he lost 3/2 pounds less than 3/2 times the pounds he lost the first week the third week he lost 1 pound more than three-fourths of the Pouncey lost the first week
We know that Luke lost x pounds the first week.
We also know that the second week 3/2 less than 3/2 times the pounds he lost the first week, this means that the secons week he lost:
[tex]\frac{3}{2}x-\frac{3}{2}[/tex]Finally the third week he lost 1 pound more than 3/4 of the pounds he lost the first week. This can be written as:
[tex]\frac{3}{4}x+1[/tex]Hence luke lost a total of:
[tex]x+\frac{3}{2}x-\frac{3}{2}+\frac{3}{4}x+1=\frac{13}{4}x-\frac{1}{2}[/tex]Therefore the expression for Luke's weight loss is:
[tex]\frac{13}{4}x-\frac{1}{2}[/tex]Liam lost the first week 1 pound less than 3/2 times the loss Luke had the first week this can be express as:
[tex]\frac{3}{2}x-1[/tex]The second week he lost 4 pounds less than 5/2 times the loss of Luke the firs week then we have:
[tex]\frac{5}{2}x-4[/tex]Finally Liam lost 1/2 pound more than 5/4 times the loss of Luke the first week, then:
[tex]\frac{5}{4}x+\frac{1}{2}[/tex]Adding this we have:
[tex]\frac{3}{2}x-1+\frac{5}{2}x-4+\frac{5}{4}x+\frac{1}{2}=\frac{21}{4}x-\frac{9}{2}[/tex]Therefore Liam's expression is:
[tex]\frac{21}{4}x-\frac{9}{2}[/tex]Now, we know that both of them lost the same weight, then we have the equation:
[tex]\frac{13}{4}x-\frac{1}{2}=\frac{21}{4}x-\frac{9}{2}[/tex]Solving for x we have:
[tex]\begin{gathered} \frac{13}{4}x-\frac{1}{2}=\frac{21}{4}x-\frac{9}{2} \\ \frac{21}{4}x-\frac{13}{4}x=\frac{9}{2}-\frac{1}{2} \\ \frac{8}{4}x=4 \\ x=\frac{4}{\frac{8}{4}} \\ x=2 \end{gathered}[/tex]Therefore Luke lost 2 pound the first week.
Finally we plug the value of x in the expression for Luke's weight loss to get the total amount over the three weeks:
[tex]\begin{gathered} \frac{13}{4}(2)-\frac{1}{2}=\frac{13}{2}-\frac{1}{2} \\ =\frac{12}{2} \\ =6 \end{gathered}[/tex]Therefore they lost 6 pounds in three weeks.
a particular community in the mid west experiences on average 3.9 tornadoes every year. what's the probability that the next tornado comes after 7 months have passed? give your answer in decimal form with three significant digits.
0.8973 is the probability that the next tornado will occur within the next seven months.
Applying the rule of three, we can infer that since the average number of tornadoes in a year is 3.9, the average number of tornadoes in a nine-month period is 3.9*7/12 = 2.275. It is reasonable to believe that the distribution of tornadoes over time is Poisson. Let's refer to X as the number of tornadoes in a seven-month period. X has a Poisson distribution with a parameter of 2.27.
The probability of X being greater than or equal to 1 is equivalent to the likelihood that the next tornado will occur within the next seven months.. However P(X≥1) = 1-P(X=0), and
[tex]p(X=0) = (e^{2.275} * 2.275^{0}) / 0![/tex] = 0.1027
Thus, the probability that the next tornado comes within the next 7 months is 1-0.1027 = 0.8973.
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The time in seconds that it takes an object to fall d feet can be found
using the expression ((sqrt(d))/(4)) , Suppose aiden drops a tennis ball from a height of 50 feet at the same time masons drops a similar tennis ball from a height of 20 feet . How much longer will it take Aiden's tennis ball to reach the ground than Mason's tennis ball? Round to the nearest hundredth .
Aiden's tennis ball will reach the ground 0.65 seconds than Mason's tennis ball
How to determine the time difference in reaching the groundThe function of time with respect to distance is given as
(sqrt(d)/(4))
Rewrite the function properly
This is represented as follows
√d/4
It can also be written as
t = 1/4√d
From the question, we have
Aiden = 50 meters
Mason = 20 meters
The time difference is then calculated as
T = t₁ - t₂
So, we have
T = 1/4√d₁ - 1/4√d₂
The equation becomes
T = 1/4√50 - 1/4√20
This gives
T = 1/4(√50 - √20)
Evaluate
T = 0.65
Hence, the time difference is 0.65 seconds
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Suppose the commute times for employees of a large company follow anormal distribution. If the mean time is 24 minutes and the standarddeviation is 5 minutes, 95% of the employees will have a travel time within which range?
The empirical rule state that, for normally distributed data, almost all of the data fall within three standard deviations either side of the mean. Specifically,
-68% of data within 1 standard deviation.
-95% of data within 2 standard deviation
-99.7 of data within 3 standard deviation.
In our case the mean is
[tex]\mu=24[/tex]and the standard deviation is
[tex]\sigma=5[/tex]then, the empirical formula imply that
[tex]\begin{gathered} \mu-2\sigma=24-2\cdot5 \\ \mu-2\sigma=24-10 \\ \mu-2\sigma=14 \end{gathered}[/tex]and
[tex]\begin{gathered} \mu+2\sigma=24+2\cdot10 \\ \mu+2\sigma=24+10 \\ \mu+2\sigma=34 \end{gathered}[/tex]then, the answer is 14 minutes to 34 minutes
Answer:
D
Step-by-step explanation:
Adriel is going to invest in an account paying an interest rate of 2.4% compounded monthly. How much would Adriel need to invest, to the nearest ten dollars, for the value of the account to reach $120,000 in 8 years?
The principal amount is $99,055.82.
What is Compound interest?When you add the interest you have already earned back into your principal balance, you are earning compound interest, which increases your profits. Consider that you have $1,000 in a savings account earning 5% interest annually. If you made $50 in the first year, your new balance would be $1,050.
Given:
Amount = 120,000
r = R/100
r = 2.4/100
r = 0.024 per year,
Then, solve the equation for P
P = A / [tex](1 + r/n)^{nt}[/tex]
P = 120,000.00 /[tex](1 + 0.024/12)^{(12)(8)[/tex]
P = 120,000.00 / [tex](1 + 0.002)^{(96)[/tex]
P = $99,055.82
Hence, the principal amount is $99,055.82.
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Carter wants to use the model above to solve 273 ÷ 13. Explain how he would find parts A, B, and C of the model.
Using the model Carter will find parts A, B and C b to be
Part A = 26 tens
Part B = 13
Part C = 13 ones
What is a model?A model is a representation in form of shape used for to achieve a desired aim. Models are choose with respect to the importance
How to determine parts A. part B, and part C using the modelThe given model is a rectangle
Subtracting 13 from 273 to give 260. This can be arranged in tens by doing
= 260 / 10
= 26
Hence, A is 26 tens
Representing the C part in place value we have 13 ones
Since B = C, we have B = 13
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Use the number line shown below. What is the location of Z between X and Y such that the length of ZY is 3 times the length of XZ.
-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
X = -5
Y = 4
Answer:
z is -2
Step-by-step explanation:
x = -5 y = 4
<----------------------------------------->
-6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6
Z is between x and y but is 3 times the lenght of x&z
so jumb from -5 to -3 thats one, however jumb from -2 to 0 that is 1, and form 0 to 2 that is 2, and from 2 to 4 that is 3.
when 9 times a number is increased by 30, the answer is the same as when 140 is decreased by the number. Find this number
Answer: 11
Step-by-step explanation:
Let the number be x.
[tex]9x+30=140-x\\\\10x=110\\\\x=11[/tex]
Given two terms from a geometric sequence, identify the first term and the common ratio: a10 = 1 and a12=1/25
Given:
a denotes first term and r denotes the common ratio.
[tex]a_{10}=1\colon a_{12}=\frac{1}{25}[/tex][tex]a_n=ar^{n-1}[/tex][tex]a_{10}=ar^{10-1}[/tex][tex]1=ar^9\ldots.\text{ (1) }[/tex][tex]a_{12}=ar^{12-1}[/tex][tex]\frac{1}{25}=ar^{11}\ldots.(2)[/tex]Divide the equation (2) by (1)
[tex]\frac{\frac{1}{25}}{1}=\frac{ar^{11}}{ar^9}[/tex][tex]\frac{1}{25}=r^2[/tex][tex]r=\pm\frac{1}{5}[/tex][tex]\text{If r=}\frac{1}{5}[/tex][tex]1=a(\frac{1}{5})^9[/tex][tex]a=1953125[/tex][tex]\text{If r=-}\frac{1}{5}[/tex][tex]1=a(-\frac{1}{5})^9[/tex][tex]a=-1953125[/tex][tex]a=-1953125\text{ ; r = -}\frac{1}{5}[/tex][tex]a=1953125\text{ ; r = }\frac{1}{5}[/tex]Find the volume of this cylinder. Use 3 for a.14 ftV = 7r2h=9 ftVV ~ [?]ft3
The formula for the Volume(V) of the cylinder is given as,
[tex]V=\pi r^2h[/tex]Given:
[tex]\begin{gathered} \pi=3 \\ r=14ft \\ h=9ft \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} V=3\times14^2\times9=3\times196\times9=5292ft^3 \\ \therefore V=5292ft^3 \end{gathered}[/tex]Hence, the volume of the cylinder is
[tex]5292ft^3[/tex]The vertices of ∆DEF are D(2,5), E(6,3), and F(4,0). Graph ∆DEF and its image when you translate ∆DEF using the vector (-3,-7)
The resulting coordinate of △ D'E'F' is translated by the vector is
(-1, -2), (3,-4), and (1, -7)
Given the vertices of ∆DEF are D(2,5), E(6,3), and F(4,0).
we are asked to graph ∆DEF and its image when you translate ∆DEF using the vector (-3,-7).
If the coordinate of the vertices is translated by the vector (-3, -7), the resulting coordinates of △ D'E'F' will be expressed as:
D'= (2-3, 5 - 7) = (-1,-2)
E' = (6 - 3, 3 - 7) = (3, -4)
F' = (4 -3 , 0 - 7) = (1, -7)
Hence we get the required coordinates of the translated image.
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Salesman A gets paid $300 a month plus $8 for every sale he makes. Salesman B gets paid $1500 a mont. Write and equation and solve to see how many salesman a must make in order to make the same amount of salesman b
The salesman A must make 150 order to make the same amount of salesman B .
In the question ,
it is given that ,
Salesman A gets paid $300 per month
for every sale salesman A get $8 .
let the number of sales made by salesman A be "x" .
So, amount made by salesman A = 300 + 8x
Salesman B earns per month = $1500 .
To make the amount earned by both the salesman same ,
300 + 8x = 1500
8x = 1500 - 300
8x = 1200
x = 1200/8
x = 150
Therefore , The salesman A must make 150 order to make the same amount of salesman B .
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I REALLY NEED HELP WITH FACTORISING AFTER THIS CAN WE PLEASE DO SOME QUESTIONS BASED ON IT
Step 1:
Write the expression
[tex]14x^2\text{ }-\text{ x - 3}[/tex]Step 2:
To factorize the expression, multiply the leading coefficient with the constant term.
[tex]\begin{gathered} \text{Leading coefficent = 14} \\ \text{constant term = -3} \\ =\text{ 14 }\times\text{ -3 = -42} \end{gathered}[/tex]Step 4
Choose two numbers whose product is -42 and the sum is -1 (that is the coefficient of x)
[tex]\begin{gathered} \text{The two numbers are: 6 and -7} \\ \text{Then, split -x into -7x and 6x} \\ \text{Therefore} \\ 14x^2-x-3=14x^2\text{ - 7x + 6x }-3 \\ 14x^2\text{ - 7x + 6x - 3} \\ \text{Pair two terms and factor out the co}mmon\text{ factors} \\ 7x(2x\text{ - 1) + 3(2x - 1)} \\ (2x\text{ - 1)(7x + 3)} \end{gathered}[/tex]Final answer
(2x - 1)(7x + 3)
The amount of money an engineer receives from a bank if he invests $50,000 for 7 years at 11.5% per annum compound interest.
Answer:
$107125.80
working out:
50000x1.115^7=107125.8 (rounded)
Suppose U = {1, 2, 3, 4, 5, 6, 7, 8} is the universal set and P = {2, 4, 6, 8}. What is P' ?
{2, 4, 6, 8}
{1, 2, 3, 4, 5, 6, 7, 8}
{1, 3, 5, 7}
{1, 3, 5, 7, 8}
Answer:
{1, 3, 5, 7}
Step-by-step explanation:
U = {1, 2, 3, 4, 5, 6, 7, 8}
P = {2, 4, 6, 8}
P'= {1, 3, 5, 7}
Students make 93.5 ounces of liquid soap for a craft fair they put the soap in a 8.5 ounce bottles and sell each bottle for 5.50 how much do the students earn if they sell all the bottles of liquid soap
For a craft show, students make 93.5 ounces of liquid soap. They package the soap in 8.5 ounce bottles and charge $5.50 per bottle. The students will earn $60.5.
Given that,
For a craft show, students make 93.5 ounces of liquid soap. They package the soap in 8.5 ounce bottles and charge $5.50 per bottle.
We have to find how much money will the students make if they sell all the liquid soap bottles.
Total amount of liquid soap prepared by the students for a craft fair = 93.5 ounces
Weight of each bottle in which students poured the soap = 8.5 ounces
Let us first calculate the number of bottles, each contains 8.5 ounces of soap from 93.5 ounces of soap.
So, Number of bottles = 93.5/8.5
= 11
So, 11 bottles are prepared which contains 8.5 ounces of soap from 93.5 ounces of soap.
The amount at which each bottle is sold = $5.50
The total amount earned by selling all the bottles of liquid soap = 11×5.50
= $60.5
Therefore, the students will earn $60.5 if they sell all the bottles of liquid soap.
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One of the fastest species of beetle can actually run at a speed of about 9 kilometers per hour. Convert 9 kilometer per hour to centimeters per second.
Given:
The speed of the beetle is, s = 9 km/h.
The objective is to convert the speed into centimeters per second.
Explanation:
Since, it is known that,
[tex]\begin{gathered} 1\text{ km=1,00,000 cm} \\ 1\text{ hour=3600 s} \end{gathered}[/tex]Conversion;
Then, the speed can be converted as,
[tex]\begin{gathered} s=9(\frac{km}{hr})(\frac{1,00,000\text{ cm}}{1\text{ km}})(\frac{1\text{ hr}}{3600\text{ s}}) \\ =250\text{ cm/s} \end{gathered}[/tex]Hence, the the converted value is 250 cm/s.
Look at this table:
England
Wules
Birth rate per 1000 population
1961
1994
17.6
17.0
12.2
(a) In England, from 1961 to 1994, the birth rate fell by 26.1%
What was the birth rate in England in 1994? Show your working.
(b) In Wales, the birth rate also fell.
Calculate the percentage fall from 1961 to 1994. Show your working.
The birth rate in England in 1994 is 13 and the percentage fall in Wales is 28.23%
(a)In England, from 1961 to 1994, the birth rate fell by 26.1%
We need to find the birth rate in England in 1994
Birth rate in 1961 is 17.6
Birth rate in 1994 = 17.6 - 17.6 x26.1/100
= 17.6 - 17.6 x261/1000
= 17.6 - 4.6
= 13
(b) In Wales, the birth rate also fell.
The birth rate in 1961 is 17.0
The birth rate in 1994 is 12.2
Percentage fall is 100 x (17.0 - 12.2)/17.0
Percentage fall is 28.23 %
Therefore, the birth rate in England in 1994 is 13 and the percentage fall in Wales is 28.23%
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teresa earned 425 dollars for working 25 hours last week what is her hourly rate
Answer: $17
Step-by-step explanation:
$425 divided by 25
Answer:
Her hourly rate is $17/hr.
Step-by-step explanation:
We can figure this out by taking the total dollars ($425) and dividing it by how many hours she spent working (25). 425 divided by 25= 17. Therefore, her hourly rate is 17$/hr.
fine the value of x. please help
The algebraic expression should often take one of the following forms: addition, subtraction, multiplication, or division. Bring the variable to the left and the remaining values to the right to determine the value of x. To determine the outcome, simplify the values.
How do you find the value of x/ In algebra, the letter "x" is frequently used to denote an unknown value. It is referred to as a "variable" or occasionally a "unknown. "x is a variable in x + 2 = 7, but we can figure out its value if we try! The order in which you perform operations in arithmetic and algebra is governed by a number of laws. The Commutative, Associative, and Distributive Laws are the three that receive the most attention.People have discovered over time that the sequence of the numbers has no bearing on the results of addition or multiplication.x+ 38+103= 180
x+141 =180
x =180- 141
x = 39
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Wxyz is a parallelogram in the coordinate plane. the vertices for the parallelogram are w(0,0), (b,c), y (a + b,c), and z(a,0), where a > 0,b > 0, and c> 0 what set of statements prove that the diagonals of the parallelogram bisect each other?
The diagonals WY and XZ intersect at E, we must prove that WE ∼ = YE and XE ∼ = ZE. The converse exists also true: If the diagonals of a quadrilateral bisect each other, then the quadrilateral exists as a parallelogram.
Why quadrilateral WXYZ is a parallelogram?WXYZ cannot be a parallelogram because the value of x that creates one pair of sides congruent does not create the other pair of sides congruent.
Given that WXYZ, let the diagonals WY and XZ intersect at E, we must prove that WE ∼ = YE and XE ∼ = ZE. The converse exists also true: If the diagonals of a quadrilateral bisect each other, then the quadrilateral exists as a parallelogram.
A rhombus, therefore, contains all the properties of a parallelogram: Its opposite sides exist parallel. Its opposite angles exist equally. Its diagonals bisect each other.
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HELp ASAP PLSSSPLSPLSPLSS
(view attatched image
Answer:
Ok...I've worked out the math and the correct answer should be the first one...
x | g(x)
1 | -2
2 | 4
3 | 10
Step-by-step explanation:
Hope this helps!!
2x + 3y = 13
Step 2 of 2: Determine the missing coordinate in the ordered pair (?, 3/2) so that it will satisfy the given equation
Answer:
[tex]\frac{17}{4}[/tex]
Step-by-step explanation:
Replace y with 3/2 and solve for x
2x + 3(3/2) = 13
2x + 9/2 = 13 Subtract 9/2 from both sides
2x = [tex]\frac{13}{1}[/tex] - [tex]\frac{9}{2}[/tex]
2x = [tex]\frac{26}{2}[/tex] - [tex]\frac{9}{2}[/tex]
2x = [tex]\frac{17}{2}[/tex] Divide both sides by 2
x = [tex]\frac{17}{2}[/tex] ÷ [tex]\frac{2}{1}[/tex]
x = [tex]\frac{17}{2}[/tex] x [tex]\frac{1}{2}[/tex]
x = [tex]\frac{17}{4}[/tex] o r4 [tex]\frac{1}{4}[/tex] or 4.25
Last winter it snowed 5 inches in December 17 inches in January 13 inches in February and 2 inches in March how much snow fell during the entire winter 
37 inches total, but 35 with just December, January, and February (depending on the definition of winter)
Find the value of x that satisfies the given conditions. Then graph the line on a separate sheet of paper.
The line containing (4, -2) and (x,-6) is perpendicular to the line containing (-2, -9) and (3,-4).
The value of x will be 8.
And, Graph of the line y = -x + 2 is shown in figure.
What is Equation of line?
The equation of line passing through the points (x₁ , y₁) and (x₂, y₂) with slope m is defined as;
y - y₁ = m (x - x₁)
Where, m = (y₂ - y₁) / (x₂ - x₁)
Given that;
The condition is;
The line containing the points (4, -2) and (x,-6) is perpendicular to the line containing the points (-2, -9) and (3,-4).
Since, Multiplication of Slopes of perpendicular lines are -1.
That is;
m₁ m₂ = -1
Where, m₁ is slope of first perpendicular line and m₂ is slope of second perpendicular line.
Now, Find the slopes of lines as;
m₁ = (-6 - (-2)) / (x - 4)
m₁ = - 6 + 2 / x - 4
m₁ = - 4 / (x - 4)
And, Slope of second line,
m₂ = (-4 - (-9)) / (3 - (-2))
m₂ = (-4 + 9) / (3 + 2)
m₂ = 5 / 5
m₂ = 1
Hence,
m₁ m₂ = -1
Substitute all the values, we get;
- 4 / (x - 4) × 1 = -1
4 = x - 4
x = 4 + 4
x = 8
Thus, The points on the line is (4 , -2) and (8 , -6).
So, Slope (m₁) = (- 6 - (-2)) / (8 - 4)
= (-6 + 2) / 4
= - 4 / 4
= -1
Thus, The equation of line passing through the points (4 , -2) and
(8 , -6) with slope -1 is;
y - (-2) = - 1 (x - 4)
y + 2 = -x + 4
y = - x + 4 - 2
y = - x + 2
Therefore,
The value of x will be 8.
And, Graph of the line y = -x + 2 is shown in figure.
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two functions are given below: f(x) and h(x). state the axis of symmetry for each function and explain how to find it
HELP ME PLEASE
The axis of symmetry for function
f(x) is x = 8 and for h(x) is x = 3.
We know that the quadratic equation in vertex form is, y = a (x - m)² + n
where (m, n) is the vertex of the parabola.
And, the axis of symmetry is x = m.
Consider function f(x)
f(x) = -4(x - 8)² + 3
This function represents a quadratic equation in vertex form with vertex (8, 3)
So, the axis of symmetry for function f(x) would be x = 8
We know that the axis of symmetry is the vertical line that goes through the vertex of a parabola so the left and right sides of the parabola are symmetrical.
Consider the function h(x)
We can observe that the vertex of parabola is (3, 2)
So, the axis of symmetry would be x = 3.
Therefore, the axis of symmetry for function
f(x) is x = 8 and for h(x) is x = 3.
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consider a normal distribution with mean 20 and standard deviation 9. what is the probability a value selected at random from this distribution is greater than 20? (round your answer to two decimal places.)
The probability that a value selected at random from this distribution is greater than 20 is 0.5.
What is a probability with normal distribution?
The majority of the observations are centered around the middle peak of the normal distribution, which is a continuous probability distribution that is symmetrical around its mean. The probabilities for values that are farther from the mean taper off equally in both directions.
Here,
Let us assume that X follows a normal distribution.
If X follows a normal distribution, then
z = (X−μ) /σ, follows a standard normal distribution.
The probability of a value selected at random from this distribution is greater than 20:
P (X > 20) = 1 − P (X ≤ 20)
P ((X − μ) / σ > 20) = 1−P((X − μ) / σ ≤ 20)
P (z > (20 − 20) /5) = 1 − P (z ≤ (20−20 / 5))
P (z > 0) = 1 − P (z ≤ 0)
The value of probability is obtained from the standard normal table as:
P (z > 0) = 1 − P (z ≤ 0)
= 1 - 0.5
= 0.5
Hence, the probability that a value selected at random from this distribution is greater than 20 is 0.5.
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Write a polynomial function, p(x), with degree 3 that has p(7) =0
The polynomial function, p(x), with degree 3 that has p(7) = 0 is p(x) = [tex]x^{3} -7x^{2} +12x-84=0[/tex].
According to the question,
We have the following conditions to find the polynomial function, p(x):
The degree has to be 3 and the value of p(7) should be 0.
Now, we are sure that we have one term as [tex]x^{3}[/tex].
Now, when 7 has to be multiplied three times we have 343 as the result.
So, we will try to make it zero in the next term.
The next term can be[tex]-7x^{2}[/tex] because we will get -343 and the result of the first two terms will be 0.
Now, the third term can be 12x (you can take any term but we have to make sure that the end result is 0).
Now, the result will be 84 when we put 7 in place of x.
Now, we can have -84.
So, we will add these 4 terms to form the polynomial function:
p(x) = [tex]x^{3} -7x^{2} +12x-84=0[/tex]
Hence, the required polynomial function is p(x) = [tex]x^{3} -7x^{2} +12x-84=0[/tex].
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