Draw the following vector: 350 N, 30° south of east [1 cm = 50 N]

Answer:

hottest plant: vensus, close to the sun

coldest plant: Neptune, farthest from the sun

Explanation:

Using law of conservation of momentum

[tex]\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3[/tex]

[tex]\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3[/tex]

[tex]\\ \sf\Rrightarrow 7500-21000=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow -13500=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow v_3=-3m/s[/tex]

Explanation:

What we know:

Sa + Sb = 350 km

Ta + Tb = 4h

S = Vt

With these equations above we can write a system of equations and find Tb, as you see in the picture(s).

After having Tb you can easily find Ta and then Sa and Sb. Hopefully it was clear.

Answer:

Doubling the large mass

Explanation:

By doubling the mass you will get more gravational force

Answer:

1. around 22m

Explanation:

Annie traveled 9 meters during that time. Her average acceleration was -8 m/s².

Annie's initial speed was 12 m/s.

Her final speed was 0 m/s.

The time it took her to stop was 1.5 seconds.

Therefore, the distance she traveled during that time is:

distance = (initial speed + final speed)/2 * time

= (12 m/s + 0 m/s)/2 * 1.5 seconds

= 9 meters

Annie's average acceleration is calculated by dividing her change in velocity by time it took for that change to occur.

In this case, her change in velocity is from 12 m/s to 0 m/s, which is a decrease of 12 m/s.

The time it took for this change to occur is 1.5 seconds.

Therefore, Annie's average acceleration is:

acceleration = change in velocity / time

= -12 m/s / 1.5 seconds

= -8 m/s²

The negative sign indicates that Annie was slowing down.

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Answer:

-8

5.092×10

Explanation:

given,

distance (d) =15m

mass (M1) =350kg

mass(M2) = 492kg

Gravitational constant (G)=6.67×10^-11

we know,

gravitational force=(Gm1m2)÷d^2

=(6.67×10^-11×350×492)÷15^2

= (1.14857×10^-5)÷225

= 5.092×10^-8

Answer:

Explanation:

The speed of the wave given only it's frequency and wavelength can be found by using the formula

[tex]c = f \times \lambda[/tex]

where

c is the velocity of the wave in m/s

[tex] \lambda[/tex] is the wavelength in m

f is the frequency in Hz

From the question

c = 2700 × 6 = 16,200

We have the final answer as

Hope this helps you

Answer:

We are required to analyze the conservation of kinetic energy in a perfectly inelastic collision.

kinetic energy:K=1/2mv²

momentum:p=mv

Explanation:

Using the equations for final velocity in terms of masses and initial velocity for a perfectly inelastic collision, work out the final kinetic energy. Calculate the initial kinetic energy and show that kinetic energy is not conserved. Use variables, no numbers

You need to follow law of conservation of energy

We know

You may use momentum formula mass×velocity

In both you need to form equations then solve for final velocity

[tex]\large{\underline{\underline{\maltese{\pink{\pmb{\sf{ \; Question \; :- }}}}}}}[/tex]

An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec² in the forward direction. What is the net force acting on the automobile?

_________________________________________

[tex]\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; Given\; :- }}}}}}}[/tex]

_________________________________________

[tex]\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; To \: Find \; :- }}}}}}}[/tex]

_________________________________________

[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Concept \: and \: Formula \: Used \; :- }}}}}}}[/tex]

➯ Force is defined as the product of the mass of the body and its acceleration.

[tex] \bigstar \: \small{ \fbox {\textsf {\textbf{F = ma}}}}[/tex]

Where :

[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Substituting \: the\: Given\: Values :- }}}}}}}[/tex]

[tex]⇝ \: \: \small \textsf {\textbf{ F = (1250 × 4) N }}[/tex]

[tex]⇝ \: \: \small \textsf {\textbf{ F = 5000 N }}[/tex]

[tex]\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Therefore \; :- }}}}}}}[/tex]

❝ The net force acting on the automobile is 5000 N. ❞

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Answer:

This above a triangle that models our situation.

Explanation:

We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.

Let the component that travel in the south be the length of a.

According to the problem, the westard component is half of that so let that length be a/2.

Now we must find the angle of the wind in the South.

This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.

[tex] \tan(x) = \frac{opp}{adj} [/tex]

Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have

[tex] \tan(x) = \frac{ - \frac{a}{2} }{ - a} [/tex]

[tex] \tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2} [/tex]

Now we take the arctan or inverse tan of 1/2.

[tex] \tan {}^{ - 1} ( \frac{1}{2} ) = 26.57[/tex]

Based on the information about vector components and graph provided, the angle of the wind with the south is 26.57°.

The western and southern component have a negative displacement as shown in the graph.

Let the southern component be -x

The western component is half of -x = -x/2

Since the angle is with the south, the trigonometric ratio to be used to find the angle is:

Tan θ = -×/2 /-x

Tan θ = 1/2

θ = tan^-1(0.5)

θ = 26.6°

Therefore, angle of the wind with the south is 26.57°.

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When NaOH is added to water, it separates into Na+ and OH-. The hydroxyls make it more basic.

A basic solution is an aqueous solution containing more OH⁻ ions than H⁺ ions.

When NaOH as a solute is mixed into the solvent like water, it separates NaOH into Na+ and OH-. The sodium ions Na⁺ have little effect on the solution, but the hydroxyls OH⁻ ions makes the solution more basic.

Thus, NaOH form a basic solution by the presence of OH⁻ ions  into it.

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Answer:

e = k q / r² then,

e = 9×10^9 * 1×10^-6 / 50² = 3.6 N/C

hope this helps ❤.

Answer:

Atomic mass

Explanation:

Answer:

atomic mass

Click thanks if thankc if this helped

Hi there!

[tex]\large\boxed{\text{Angular acceleration.}}[/tex]

For a rigid body rotating about a fixed axis, its angular characteristics ⇒ angular acceleration and velocity are constant throughout.

However, its LINEAR velocities/accelerations differ because of the following relationships:

v = ωr

a = αr

Thus, a point closer to the axis of rotation has a smaller linear velocity or acceleration compared to a point along the edge.

The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:

a)  we have four sections;

b)  The acceleration is the first 8 s is:  a = 0.25 m / s²

c) The maximum acceleration is:    a = 1 m / s²

d) The displacement   is:  i) d₁ =  8m,     ii)  [tex]d_{total}[/tex]= 16 m

e) maximum speed  is:      v = 6 m / s

Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.

        v = v₀ + a t

        y = v₀ t + ½ a t²

where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.

In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:

Let's answer the different questions about the system.

a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;

b) The acceleration is the first 8 s

          v = v₀ + a t

          [tex]a = \frac{v-v_o}{\Delta t}[/tex]  

          [tex]a = \frac{2-0}{8-0}[/tex]  

          a = 0.25 m / s²

c) The maximum acceleration is when the slope is maximum.

          [tex]a = \frac{6-2}{ 14-10}[/tex]  

          a = 1 m / s²

Therefore the acceleration is maximum in the section between 10 and 14 s

d) The total displacement is the sum of the displacements of each section.

         [tex]d_{total } = d_1 +d_2 + d_3 +d_4[/tex]  

We look for every displacement.

       d₁ = v₀ + ½ a₁ Δt²

       d₁ = 0 + ½ 0.25 8²

       d₁ = 8 m

In the second section the velocity is constant

         d₂ = v₂ Δt₂

         d₂ = 2 (10-8)

         d₂ = 4 m

The third section.

    d₃ = v₀ + ½ a t²

    d₃ = 2 + ½ 1 (14-10) ²

    d₃ = 10 m

The distance of the fourth section.

we look for acceleration

          a₄ = [tex]\frac{v-v_o}{\Delta t}[/tex]  

          a₄ = [tex]\frac{0-6}{18-14}[/tex]  

          a₄ = -1.5 m / s²

          d₄ = 6 + ½ (-1.5) (1814) ²

          d₄ = -6 m

The total displacement is;

          [tex]d_{total}[/tex] = 8 + 4 + 10 -6

          [tex]d_{total}[/tex] = 16 m

e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to

          v = 6 m / s

In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:

  a)  we have four sections;

b)  The acceleration is the first 8 s is:  a = 0.25 m / s²

c) The maximum acceleration is:    a = 1 m / s²

d) The displacement   is:  i) d₁ =  8m,     ii)  [tex]d_{total}[/tex]= 16 m

e) maximum speed  is:      v = 6 m / s

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The largest producer of primary air pollution in the United States is what? electricity producing plants.

Answer:

electricity production

Explanation:

Answer:

Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.

Explanation:

Answer:

potential energy = mgh = 300 × 10 × 6m = 18000 joule or 18 kilo joule.

Explanation:

Answer:

>400N is needed to balance that lever

The correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

Newton's third law of motion states that for every action or force, there is an equal but oppositely directed force.

Force with which the sledgehammer hits the wall = 1000 N

Thus, the force exerted by the sledgehammer on the wall = -1000 N

Thus, the correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

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Total displacement:-

[tex]\\ \sf\Rrightarrow 10-30=20m[/tex]

Total distance

[tex]\\ \sf\Rrightarrow 10+30=40m[/tex]

The feeling can either be positive or negative.

A positive feeling can occur when one performs very well in the given home. Also, a positive feeling can come from a high level of satisfaction in the homework. When you complete your homework on time using the recommended steps, you will be sure to do well on the homework.

In other hand, a negative feeling may result from poor performance in the homework. In ability to complete the homework or missing some steps in the homework can increase your level of trepidation even before seeing your score.

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Answer:

2 miles

Explanation:

Answer:

I believe its A: Sports biomechanics.

Answer:

There are many forces involved in the game of football. These are: Force of Gravity, Normal Force, Force of Friction, and Applied Force. Force of Gravity applies to football when the football is thrown or kicked, when a player jumps in the air to avoid a tackle or catch a ball, and is constantly being applied.

Explanation:

How physics is used in football?

When you throw a football across the yard to your friend, you are using physics. You make adjustments for all the factors, such as distance, wind and the weight of the ball. The farther away your friend is, the harder you have to throw the ball, or the steeper the angle of your throw.

Answer:

The inductive time  constant is just T = L / R

T = 10E-3 henry/ 10 ohm = 10E-2 sec = .1 sec  

(.01 / 10 = .1)

Answer:

Vertebrate zoology

Explanation:

Have a great day!

Happy Holidays!

We can use the following equation to solve for the gravitational force:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]

Fg = force due to gravity (N)

G = Gravitational constant

m1,m2 = masses of the objects (kg)

r = distance between the objects (m)

Plug in the given values into the equation:

[tex]F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}[/tex]