Regarding the graphed function, we have that:
a. The critical points are given as follows:
x = -2: neither maximum nor minimum.x = 1: minimum.x = 3: maximum.b. The function is concave up and decreasing on the intervals (-3,-2) U (0,1), as the first derivative is both negative and increasing on these intervals.
c. The inflection points are x = -2, x = 0 and x = 2.
Critical pointsThe critical points of a function are the points in which the derivative is of 0, and can be classified as maximum or minimum, as follows:
Relative maximum: derivative is positive to left and negative to right.Relative minimum: derivative negative to left and positive to right.Neither: derivative is negative/positive to right and left.We are given the graph of the derivative, hence the zeros are the critical points, as follows:
x = -2: neither. (derivative is negative both to left and to right).x = 1: minimum (negative to left and positive to right).x = 3: maximum. (positive to left and negative to right).Points of inflectionThe points of the inflection of a function are the points in which the second derivative is of zero.
We are given the graph of the first derivative, hence the inflection points are where the graph changes from increasing to decreasing or decreasing to increasing, as follows:
x = -2, x = 0 and x = 2.
The curve is classified as concave up or concave down as follows:
Concave up: second derivative positive -> first derivative increasing.Concave down: second derivative negative -> first derivative decreasing.The first derivative is increasing in these following intervals:
(-3, -2) U (0,2).
Meaning that the function is concave up on this interval.
The function is decreasing when the first derivative is negative, hence the interval is:
(-3, 1) U (3, 4).
The intervals in which the first derivative is both negative and increasing are:
(-3,-2) U (0,1).
Which are the intervals in which the function is both concave up and decreasing.
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