Do) 13. Which image BEST represents our galaxy?

Do) 13. Which Image BEST Represents Our Galaxy?

Answers

Answer 1
The second option !
Hope this helps
Answer 2

The best image of galaxy is second option.

What is galaxy?

Galaxies are vast systems of gravity-bound gas, dust, dark matter, and anything from a million to a trillion stars. Supermassive black holes are expected to be present at the centers of almost all big galaxies. The sun is merely one of 100 to 400 billion rotating stars in our own galaxy, the Milky Way.

There are more galaxies visible as we gaze farther into space. According to a 2016 study, there are two trillion, or two million million, galaxies in the observable universe. While some of those far-off systems resemble our own Milky Way galaxy, others are very dissimilar,

There are three general types of galaxies elliptical, spiral, and irregular.

So the best shape is second option elliptical with boundary.

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Related Questions

16. True/False: Protons are exchanged between objects by induction

Answers

False: only electrons move through induction.

help do number 16 and 17​

Answers

Answer:

16 is d and i have no idea for 17

Help PLZ ;)

If the distance between two objects increases, what happens to the force of gravity between them?
(A) Increases
(B) Decreases
(C) Stays the same

Answers

Answer:

B) Decreases

Explanation:

Gravitational force is inversely proportional to distance. As distance between 2 objects increase, gravitational force between the 2 objects decreases.

Hope this helps!

Answer:

The answer would be B

Explanation:

You walk east for 30 m, then decide to walk north foranother 30 m. What is the angle of direction of your displacement?​

Answers

Answer:

Displacement is 42.426 m NE and the angle is opposite/adjacent or 30/30 which would equal 1 degree which doesn't seem right but hopefully its an answer.

Explanation:

Give reasons.
a. A stretched catapult has potential energy.
b A stone on ground has zero energy.
C. Rolling a drum is work against friction.
d. Lifting a stone is work against gravity.
e. Work and energy both have same unit.​

Answers

a. A stretched catapult can do work when released so it must have potential energy.

b. A stone on the ground will not move on its own ever again so it has zero energy.

c. In order to roll an object there must be a friction force between the object and the ground (otherwise it will slide)

d. To lift a stone you must overcome the weight which is the force due to gravity.

e. Work and energy are both measured in Joules.

4. Which of the following statements is correct?
A Mass and weight are different names for the same thing
B The mass of an object is different if the object is taken to the Moon
C The weight of a cer is one of the forces acting on the car.
D The weight of a chocolate beris measured in kilograms

Answers

Answer:

Explanation:

A: wrong. Mass and weight are different.

B: Wrong. The mass here and the mass on the moon are the same. The weight, which is Mass * the acceleration  is equal to weight.

C: Correct.

D: Wrong. Weight is not measured in Kg. Mass is.

HELP PLEASE!!! 15 POINTS
How does the speed of waves vary in different media?

Radio waves are used to transmit verbal messages through space.
IS THIS TRUE OR FALSEE???

Answers

This will be true plz give me brainless

The gradual change in a species over time is called
a.
mutation.
b.
evolution.
c.
migration.
d.
variation.
PLZ HURRY WILL GIVE BRAINLIEST

Answers

Answer: B. Evolution

Explanation:

As species grow older over time they will gradually evolve through natural selection and evolution.

The gradual change in a species over time is known as evolution (b).

The process of evolution occurs through several mechanisms, including mutation, migration, and natural selection.

Mutation (a) is the spontaneous change in the genetic material of an organism. These changes can result in new traits that may be advantageous, disadvantageous, or neutral for survival. When mutations occur, they can introduce genetic variation within a population, which serves as the raw material for evolution.

Natural selection is a crucial factor driving evolution. Individuals with advantageous traits that better suit their environment are more likely to survive and reproduce, passing on these advantageous traits to their offspring. Over generations, the frequency of beneficial traits increases in the population, leading to the adaptation and evolution of the species.

Variation (d) encompasses the differences in physical traits and genetic makeup among individuals within a population. This variation is essential for evolution to occur since it provides the raw material for natural selection to act upon.

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What is the speed of an object that travels 60 meters in 4 seconds?
a) 240 m/s
b) 15 m/s
c) 0.067 m/s
d) 15 mph

Answers

Answer:

B) 15 m/s

Explanation:

Since most of the answer choices are in m/s, you can try dividing 60 meters/4 seconds in order to get the seconds on the bottom to become 1 second.

You want to find how many meters the object can travel in 1 second, rather than 4 seconds.

[tex]\frac{60 \ m}{4 \ s} \div \frac{4}{4} = \frac{15 \ m}{1 \ s}[/tex]

Now you can see that for every 1 second of time, the object can travel 15 meters. This corresponds to answer choice B) 15 m/s.

The last option, D, is incorrect because we are not dealing with hours as our unit of time. We are dealing with seconds.

Answer:

b) 15 m/s

hope it help you

how can magnetic potential energy be transferred to kinetic energy

Answers

Answer:

A magnetic force can convert kinetic energy stored in a magnetic field to potential energy. Kinetic energy can convert potential energy stored in a gravitational field. A magnetic energy can convert potential energy stored in a gravitational field to kinetic energy.

A car starts from rest and accelerates for 2.9 s
with an acceleration of 2 m/s2.
How far does it travel?
Answer in units of m.

Answers

Answer:

[tex]a \: = \frac{v - u}{t} [/tex]

2 = v-0/2.9

2× 2.9 = v

v = 5.8 m/s

[tex]v \: = \frac{d}{t} [/tex]

5.8 = d/2.9

5.8×2.9 = d

d = 16.82 m

The planet's hawks and block their near each other in the door again system the dworkin's have very advanced technology and a dork and scientist want to increase the pull of gravity between the 2 planets which proposals with the scientists make to accomplish this goal check all that aply

Answers

Answer: A,B, and E

Explanation: Just checked I got them right:)

The shortest path between two points is:

1) displacement

2) breadth

Answers

Answer:

the shortest path between two points is displacement..

Explanation:

Hope this helps you✌️✌️

Thanks .....

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The shorts path between two points is displacement.

Yodelin has fifty quarters and dimes. Their total value is $9.80. Which of these systems of equations can be used to find the number of quarters (q) and
dimes (d) Yodelin has?

Answers

Answer:

q + d = 50

25q + 10d = 980

Explanation:

The equation that can be employed to determine the number of quarters(q), as well as, dimes(d) that Yodelin has would be:

q + d = 50...(1)

25q + 10d = 980...(2)

Multiplying (1) by 25

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

subtracting (4) from (3)

15d = 270

d = 18

q = 50 - 18

    = 32

The system of the equations could be

q + d = 50

25q + 10d = 980

Calculation of the equation and the number of quarters and dimes:

Since Yodelin has fifty quarters and dimes. Their total value is $9.80.

So here the equations be

q + d = 50...(1)

25q + 10d = 980...(2)

Now we have to Multiplying (1) by 25

So,

25q + 25d = 1250 ...(3)

25q + 10d = 980...(4)

Now

subtracting (4) from (3)

15d = 270

d = 18

So,

q = 50 - 18

   = 32

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Determine the weight of a 10.0-kg person who is running with a speed of 5.0 m/s. Enter a
numerical answer.

Answers

Answer:

weight=mass*gravity

weight=10.0*10

so weight=100N

Activity 3. Let's Do The Mathi
Direction: Use Newton's second law equation to solve for force, mass, and acceleration
Problem 1- A ball with a mass of 0.5 kg is hit with a force of 2.5N. What is its acceleration?
Problem 2- What is the acceleration of a 15kg box that is pushed across a horizontal surface
with a force of 50N?
Problem 3- An object with a mass of 2.0 kg has a force of 5.0 N applied to it. What is the
resulting acceleration of the object?
Problem 4- An object with a mass of 3.0 kg accelerates 2.5 m/s2 when an unknown force is
applied to it. What is the amount of the force?
Problem 5- An object accelerates 12.0 m/s2 when a force of 6.0 N is applied to it. What is the
mass of the object?

Answers

Answer:

Problem 1-

The acceleration = 5 m/s²

Problem 2 -

The acceleration = 3.[tex]\overline 3[/tex] m/s²

Problem 3 -

The acceleration = 2.5 m/s²

Problem 4-

The force applied = 7.5 N

Problem 5-

The mass of the object,  = 0.5 kg.

Explanation:

Problem 1-

The mass of the ball, m = 0.5 kg

The force (applied) with which it was hit, F = 2.5 N

The acceleration, a = Force/Mass = 2.5 N/(0.5 kg) = 5 m/s²

The acceleration = 5 m/s²

Problem 2 -

The mass of the box, m = 15 kg

The force (applied) with which it was hit, F = 50 N

The acceleration, a = Force/Mass = 50 N/(15 kg) = 10/3 = 3.[tex]\overline 3[/tex] m/s²

The acceleration = 3.[tex]\overline 3[/tex] m/s²

Problem 3 -

The mass of the object, m = 2.0 kg

The force (applied) with which it was hit, F = 5.0 N

The acceleration, a = Force/Mass = 5.0 N/(2.0 kg) = 2.5 m/s²

The acceleration = 2.5 m/s²

Problem 4-

The mass of the object, m = 3.0 kg

The acceleration, a, of the object = 2.5 m/s²

The force applied to it, F = Mass × Acceleration = 3.0 kg × 2.5 m/s² = 7.5 N

The force applied = 7.5 N

Problem 5-

The acceleration, a, of the object = 12 m/s²

The force applied, F = 6.0 N

The mass of the object, m = Force/Acceleration = 6.0 N/(12 m/s²) = 0.5 kg

The mass of the object,  = 0.5 kg.

Explain how if a solid, liquid, and gas are put into individual containers how they fill the container.

Answers

Answer:

serial in which container is filled

Solid -base of container

Liquid- above solid

Gas- above liquid

Explanation:

If any mixture of  matter in different state (that solid , liquid or gas )are kept in any container, then substance with higher density will be settled at lowest surface first and similarly the substance with lowest density will be at upper part of container.

In the given container we have to keep solid, liquid and gas

sold has the highest density,gas the lowest density andliquid has the density higher than gas but less than solid.

based on this

solid will be at surface of container

above sold will be liquid

above liquid will be presence of Gas

serial in which container is filled

Solid -base of container

Liquid- above solid

Gas- above liquid

How do you find the distance a object has traveled

Answers

Answer: Got this from a web search... Change the answer up a bit

Explanation:

The distance travelled is the path taken by a body to get from an initial point to an end point in a given period of time, at a certain velocity. If the velocity is constant: Distance = time * velocity. d = v*t.

Answer:

I researched and found it to be TIME * VELOCITY ( d= v*t)

Explanation:

When I use * I just mean multiply. So its time 'multiplied by velocity' in order to get 'distance'

m1=200g m2=150g
find the acceleration
the track is horizontal and frictionless

Answers

Answer:

50 or 1.3333

Explanation: Explanation you cancel out the mass and the force to see what your acceleration would be or you could divide F by M

Which property describes the number of waves that move past a point each second.
A) Speed
B) Frequency
C) Period
D) Wavelength

Answers

Answer:B) Frequency

Explanation:

Answer:

B) Frequency

Explanation:

An object has an acceleration of 6m/s/s. If the net force was tripled and the mass was doubled, then the new acceleration would be ​

Answers

Acceleration = Force / mass
New acceleration = 3F / 2m = 1.5 x the old acc = 9 m/s/s

10 N force is acting on the body of mass 5kg which is at rest. The velocity
gained by the body in 5 seconds is

Answers

Answer:

= 4m/s^2

Explanation:

Change in velocity is

20-0/5 = 4

What would you not find on an acceleration graph? *
O pie chart
O x axis
O time
O velocity

Answers

Pie Chart is the correct answer

Two ropes are attached a wagon one horizontal to the west with a tension force of 75N and other east and at an angle of 38 degrees upward from horizontal with a lension force of 125 N Find the components of the net force on the cart Show your work

Answers

Answer:

The components of the net force acting on the cart are;

Horizontal force, Fₓ ≈ 23.5 N acting east

The vertical force, [tex]F_y[/tex] ≈ 76.96 N

Explanation:

The parameters given in the question are;

The magnitude of the force on the rope acting horizontally to the west = 75 N

The magnitude of the force on the other rope east acting at an angle to the horizontal = 125 N

The angle to the horizontal of the force on the other rope east to the horizontal = 38°

Therefore, we have;

The horizontal component of the force acting east = 125 × cos(38°) ≈ 98.5 N

The net sum of the horizontal forces, ∑Fₓ noting that the horizontal forces are acting in opposite direction is given as follows;

∑Fₓ = 75 - 125 × cos(38°) = 75 - 98.3 = -23.5N

Given that the difference in forces is negative, and hat we took the force acting east as negative, we have that the net horizontal force is acting east with a horizontal component of 23.5N

The net vertical force, ∑F[tex]_y[/tex], is given as follows;

∑F[tex]_y[/tex] = 125 × sin(38°) ≈ 76.96 N

Therefore, the components of the net force acting on the cart are;

Horizontal force, Fₓ ≈ 23.5 N, the vertical force, [tex]F_y[/tex] ≈ 76.96 N

The components of the net force on the cart are 23.5 Newton and 76.96 Newton.

Given the following data:

Tension force (horizontal) due west = 75 NTension force (horizontal) due east = 125 NAngle of inclination = 38°

To find the components of the net force on the cart:

First of all, we would determine the horizontal component of the force acting due east.

[tex]F_y = Fcos(\theta)\\\\F_y = 125cos(38)\\\\F_y = 125 \times 0.7880\\\\F_y = 98.5 \; Newton[/tex]

Next, we would find the resultant horizontal forces:

[tex]\sum F_y = F + F_y\\\\\sum F_y = 75 + (- 98.5)\\\\\sum F_y = -23.5 \;Newton[/tex]

Therefore, the horizontal component of the net force acts in the opposite direction due east.

Horizontal component of the net force = 23.5 Newton

For the vertical component of the net force:

[tex]\sum F_x = Fsin(\theta)\\\\\sum F_x = 125cos(38)\\\\ \sum F_x = 125 \times 0.6157\\\\ \sum F_x = 76.96\; Newton[/tex]

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1. Which of the following provides a correct answer for a problem that can be solved using the kinematic equations?
A A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
position is 32 m.
B A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
velocity is 16 m/s
C A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's travels a
distance of 16 m
A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
velocity is 24 m/s
E A body starts from rest and accelerates at 8 m/s/s for 3 s. The body's final
position is 30 m.
1 of 14
2
3
5 6 7 8
9

Answers

Answer:

12

Explanation:

12

Why should you never do an exercise such as the bench press without a spotter?​

Answers

Answer:

you could hurt yourself

Explanation:

Answer

You should never do an exercise such as the bench press without a spotter because you could hurt yourself or push your self too much.

Explanation:

can you help me doing an essay about actual self​

Answers

Answer:

yes absolutely

Explanation:

why not

chemical formulawhat is the chemical formula ​

Answers

a set of chemical symbols showing the elements present in a compound and their relative proportions, and in some cases the structure of the compound.

That’s the definition

Answer: A chemical formula is a way of showing and representing information about a chemical proportion of atoms that constitute a particular chemical compound or molecule

please can i have help with this question ​

Answers

Opposites attract so north goes to south and Vice versa. When the same poles are facing each other they push away when they are opposites they attract.

Alguien ayudeme con estos problemas de fisica porfa 1. Una persona recorre 4200 m en 25 minutos, luego 4.54 Km en un hora y finalmente 9000 m en 55 minutos. Halle, el tiempo total empleado en minutos, su velocidad y rapidez. 2. Una partícula en una circunferencia de 40 cm de diámetro da 30 vueltas completas en dos minutos. Halle la velocidad y rapidez de la partícula. 3. Una persona da 500 pasos de 40 cm al oeste, luego 400 pasos de 35 cm al norte y finalmente 300 pasos de 30 cm al este utilizando en total 2 min y 120 segundos. Halle la distancia recorrida, desplazamiento, velocidad y rapidez. 4. Una persona recorre una pista circular de 250 metros de radio, ¿Cuál es su distancia, desplazamiento, velocidad y rapidez en dar media vuelta a la pista si el tiempo empleado es de 90 segundos

Answers

Answer:

1) t_total = 140 min ,  v = 126.7 m / min ,  2)  v = 0.628 m / s ,

3) v = 0.592 m / s ,  θ = -39.3 º

Explanation:

Here we have some short kinematics problems

1) d₁ = 4200 m at T1 = 25 min

    d₂ = 4.54 km at t2 = 1 h

    d₃ = 9000 m at t3 = 55 min

of the statement the direction of each route is the same

Let's reduce the distances to the SI system

     d₂ = 4.54 km (1000 m / 1 km) = 4540 m

     t₂ = 1 h (60 min / 1 h) = 60 min

 

Total time is

    t_total = t1 + t2 + t3

   t_total = 25 + 60 +55

   t_total = 140 min

the distance is

    d_total = 4200 + 4540 +9000

     d_total = 17740 m

with movement it is in one dimension and all displacement is in the same direction, distance equals displacement.

Speed ​​is

       v = 17740/140

       v = 126.7 m / min

in the direction of travel

Speed ​​is the modulus of speed

        | v | = 126.7 m / min

2) the angular velocity is

        w = θ / t

In this exercise

        t = 2 min (60 s / 1min) = 120 s

        θ = 30 rev (2π rad / 1 rev) = 60π rad

         

         w = 60π / 120

         w = 1.57 rad / s

linear velocity  is

        v = w r

        v = 1.57 0.40

        v = 0.628 m / s

velocity is the speed tangential to the  trajectory

3) the data for this exercise are

     distance = (number of steps) (distance of one step)

         d₁ = 500 0.40 m = 200 m West

         d₂ = 400 0.35 m = 140 m North

         d₃ = 300 0.30 m = 90 m East

in a total time of t = 2 min and 120 s

           t = 2  60 + 120 = 240 s

the distance traveled is

x axis we assume the direction towards + x (East) positive

           x_total = d₃ -d₁

           x_total = 90-200 = -110 m

y axis  

          y_total = d₂

          y_total = 140 m

we use the Pythagorean theorem to find the distance0

           D = √ (x_total² + y_total²)

           D = √ (110² + 90²)

           D = 142.13 m

The speed is

           v = D / t

            v = 142.13 / 240

           v = 0.592 m / s

speed is

           v = 0592 m / s

           tan θ = Y / X

           θ = tan -1 y / x

           θ = tan -1 (90 / (- 110))

           θ = -39.3 º

4) This angle is measured on the positive side of the x axis in a clockwise direction

          θ = 1.5 rev (2π rad / 1 rev) = 3π rad

           t = 90 s

the angular velocity is

           w = θ / t

           w = 3πi / 90

           w = 0.1047 rad / s

the speed is

            v = w R

            v = 0.14047 250

            v = 26.17 m / s

velocity is tangent to path

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