Determine whether point (4, -3) lies on the line with equation y = -2x + 5 by using substitution and by graphing.
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The equation of the line is:
[tex]y=-2x+5[/tex]And we need to find if the point (4,-3) lies on the line.
To solve by using substitution, we need to remember that an ordered pair always has the form (x, y) --> the first number is the x-value, and the second number is the y-value.
In this case (4,-3):
x=4
and
y=-3
So now, we substitute the x value into the equation, and if the y-value we get in return is -3 --> the point lies on the line. If not, the point does not lie on the line.
[tex]\begin{gathered} y=-2x+5 \\ \text{Substituting x=4} \\ y=-2(4)+5 \\ y=-8+5 \\ y=-3 \end{gathered}[/tex]We do get -3 as the y-value which matches with the indicated y value of the point.
Thus, by substitution, we confirm that the point lies on the line.
To check the result by graphing, we need to graph the line. The graph of the line is shown in the following image:
In the image, we can see that the marked point on the line is the point we were looking for (4,-3). So we confirm by the graphing method that the point lies on the line.
Answer: It is confirmed by substitution and graphing that the point (4,-3) lies on the line.
Related Questions
From the diagram below, given the side lengths marked, and if we know that < C is congruent to < F, we can say that ___
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SAS Similarity Theorem: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar.
AC is proportional to DE while BC is proportional to FE, but F is not the included angle between those sides, therefore, those triangles are not similar by SAS.
The Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. Since we have information only about one of the angles, ASA also doesn't apply.
For two triangles to be congruent, all of their measures must be congruent, which is not the case of our triangles.
The answer is option d. The two cannot be proven to be similar.
Fiona is making a banner in the shape of a triangle for a school project. She graphs the banner on a coordinate plane with vertices at P(0, 4) , Q(2, 8) , and R(−3, 6) . She wants to reflect the banner over the line x=1. Identify the image of the banner reflected in the line x=1.
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The coordinates of the banner after the reflection across x = 1 is P'(2, 4), Q'(0, 8), and R'(5, 6)
How to determine the coordinates of the banner after the reflection?From the question, the coordinates are given as
P(0, 4), Q(2, 8), and R(−3, 6)
The line of reflection is given as
x = 1
The rule of reflection across the line x = 1 is represented as
(x, y) = (-x + 2, y)
When the above rule is applied, we have
P'(2, 4), Q'(0, 8), and R'(5, 6)
This means that the coordinate of the image are P'(2, 4), Q'(0, 8), and R'(5, 6)
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How would these look graphed ? Look at image attached .
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These are two lines intersected ,in one point
One is positive inclined, the other negative.
Then now GRAPH
THEN BOTH LINES INTERSECT AT
Which equation is equivalent to: 3r=78+14 ?A. −3r=−78+14B. 3r−14=78C. 3r=78−14D. −3r=78−14
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Melanie has pears and papayas in a ratio of 13:25. How many pears does she have ifshe has 2500 papayas?On the double number line below, fill in the given values, then use multiplication ordivision to find the missing value.
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Given that the ratio of pears to papayas is 13:25,
[tex]\frac{\text{ Pears}}{\text{ Papayas}}=\frac{13}{25}[/tex]It means that Melanie has 13 pears, then the number of papayas must be 25.
It is asked to determine the number of pears corresponding to 2500 papayas.
First plot the values in the blank boxes on the double number line as below,
Let 'x' be the number of pears corresponding to 2500 papayas.
Now, cross multiply the terms,
[tex]25\cdot x=13\cdot2500[/tex]Divide both sides by 25,
[tex]\begin{gathered} 25\cdot x\cdot\frac{1}{25}=13\cdot2500\cdot\frac{1}{25} \\ x=13\cdot100 \\ x=1300 \end{gathered}[/tex]Thus, there should be 1300 pears corresponding to 2500 papayas.
Triangle KLM has KL = 28, KM = 28, and LM = 21. What is the area of the triangle?The area of AKLM is about(Simplify your answer. Round to one decimal place as needed.)
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Area = (b * h)/2, b = 21 bu we don't know h, s we have to calculate it
To calculate the height "h" we can use pythagoras with a triangle rectangle with base = 21/2 = 10.5 and hypothenuse = 28, so the height "h" is:
28² = h² + 10.5² ==> h² = 28² - 10.5² = 784 - 110.25 = 673.75
h² = 673.75
h = 25.96
Now that we have the height, the Area of the triangle = (b * h)/2 = (21 * 25.96)/2 = 272.5
Answer:
272.5
1. ¿Qué expresiones a continuación se pueden usar para encontrar el área del prisma rectangular de abajo? ¡ELIJA TODOS LOS QUE SE APLIQUEN! Nota: Puede probarlos todos para asegurarse de que sean iguales. * 15 (5x2x3) + (2x3x3) (5x2) + (5x2) + (5x2) + (5x2) 5x2x2 2 (5x2) + 2 (5x2) + 2 (2x2)
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We need to find the area of the prism given in the following image:
You need to add the surfaces of ALL rectangles in the image (recall that the area of a rectangle is : Base x Height)
So for this prism we have:
FOUR rectangles that measure 5 x 2
and also TWO small squares of area 2 x 2
So we need to select all the formulas they give you that read like the addition of the two above:
(5x2) + (5x2) + (5x2) + (5x2) + (2x2) + (2x2)
It can also be written as:
2 (5x2) + 2 (5x2) + 2 (2x2)
Solve the missing elements for each problem. Use 3.14 for π. Area = πr^2; C=π D
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Given,
Diameter = 32 cm
Radius
We know the radius is half of the diameter. Thus,
[tex]\begin{gathered} r=\frac{32}{2} \\ r=16 \end{gathered}[/tex]Radius 16 cm
Circumference
The formula is:
[tex]C=\pi D[/tex]Where
D is the diameter
So,
[tex]\begin{gathered} C=\pi D \\ C=(3.14)(32) \\ C=100.48 \end{gathered}[/tex]Circumference = 100.48 cm
Area
The formula is:
[tex]A=\pi r^2[/tex]Where
r is the radius
So,
[tex]\begin{gathered} A=\pi r^2 \\ A=(3.14)(16)^2 \\ A=(3.14)(256) \\ A=803.84 \end{gathered}[/tex]Area = 803.84 sq. cm.
which of the following is true?Blaine and Cruz made an error in picking their first steps.Cruz made and error in picking his first step All three made an error because the right side equals -1.All three chose a valid first step toward solving the equation.
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Given data:
The given expression is 4/7 (7-n)=-1.
Aaron starts with multiplying 7/4 on both sides, Blaine starts with distributive property by multiplying 4/7 with 7 and -u, Cruz starts by dividiing 4/7 on both sides.
Thus, all of them are correct, correct option is last one.
Answer: d
Step-by-step explanation: yw
Find the equation of the line passing through points (6,0) and (-1,14)
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Answer:
y = -2x + 12
Step-by-step explanation:
Hope this helps!!
Can I Plss get some help I got stuck I don’t know how to find x
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Using Sine of angles to evaluate for x
The formula is,
[tex]sin\theta=\frac{Opposite}{Hypotenuse}[/tex]Given:
[tex]\begin{gathered} Opposite=x \\ Hypotenuse=19 \\ \theta=21^0 \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} sin21^0=\frac{x}{19} \\ \therefore x=19\times sin21^0 \end{gathered}[/tex]Simplify
[tex]x=6.80899\approx6.81\text{ \lparen2 decimal places\rparen}[/tex]Hence,
[tex]x=6.81[/tex]Could you tell me the process of solving the problem?
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Given:
[tex]Ln8=\frac{2\pi m\xi}{\sqrt{1-\xi^2}}[/tex]m=250
Required:
Find the value of
[tex]\xi[/tex]Explanation:
The value of ln8 is:
[tex]ln8=2.079[/tex][tex]\begin{gathered} 2.079=\frac{2\times3.14\times\xi}{\sqrt{1-\xi^2}} \\ 2.079(\sqrt{1-\xi^2})=6.28\xi^ \end{gathered}[/tex]Take the square on both sides.
[tex]\begin{gathered} 4.322(1-\xi^2)=39.44\xi^2 \\ \frac{1-\xi^2}{\xi^2}=\frac{39.4384}{4.322} \\ \frac{1}{\xi^2}-1=9.125 \\ \frac{1}{\xi^2}=9.125+1 \\ \frac{1}{\xi^2}=10.125 \end{gathered}[/tex]the ratio of the length to the width of a rectangular hall is 5:3. if the width is 1500cm, find the lenght.
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Step-by-step explanation:
The ratio of the length to the width that is- length:width = 5:3
Take x as a common value,
5x= length
3x= width
Width of the rectangle= 1500 cm
3x= 1500 cm
x= 1500/3
x= 500 cm
Length of the rectangle= 5x
x=500 cm
Length= 5*500
=2500 cm
Length of the rectangle= 2500 cm
Find the distance between the points (5,5) and (-3,7). Round your answer to the nearest tenth, if necessary.8.2 units11.8 units3.2 units12.2 units
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The formula for the distance between two points in the plane is:
[tex]d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]So:
[tex]\begin{gathered} (x_1,y_1)=(5,5) \\ (x_2,y_2)=(-3,7) \\ d=\sqrt[]{(5-(-3))^2+(5-7)^2} \\ d=\sqrt[]{(8)^2+(-2)^2} \\ d=\sqrt[]{64+4} \\ d=\sqrt[]{68} \\ d=8.2462\ldots\approx8.2 \end{gathered}[/tex]So, the distance is approximately 8.2 units.
400 meters to 350 meters increase or decrease
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In this case we have a negative change, therefore decrease
answer: decrease
Martha's video game rental plan costs $18 per month. Which tableshows the sum of the amounts that Martha will pay for her video gamerental plan over the next 5 months?
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Let's complete a table with the amounts of cost per month:
Month Sum od cost
1 18
2 2 * 18 = 36
3 3 * 18 = 54
4 4 * 18 = 72
5 5 * 18 = 90
So, please select the table that is correct
Find all X values where the tangent line to the graph of the function…
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Consider the function,
[tex]f(x)=6\sin x+\frac{9}{8}[/tex]The first derivative gives the slope (m) of the tangent of the curve,
[tex]\begin{gathered} m=f^{\prime}(x) \\ m=\frac{d}{dx}(6\sin x+\frac{9}{8}) \\ m=6\cos x+0 \\ m=6\cos x \end{gathered}[/tex]The equation of the line is given as,
[tex]y-3\sqrt[]{3}x=\frac{7}{3}[/tex]This can be written as,
[tex]y=3\sqrt[]{3}x+\frac{7}{3}[/tex]Comparing with the slope-intercept form of the equation of a line, it can be concluded that the given line has a slope,
[tex]m^{\prime}=3\sqrt[]{3}[/tex]Given that the tangent to the curve is parallel to this line, so their slopes must also be equal,
[tex]\begin{gathered} m=m^{\prime} \\ 6\cos x=3\sqrt[]{3} \\ \cos x=\frac{\sqrt[]{3}}{2} \\ \cos x=\cos (\frac{\pi}{6}) \end{gathered}[/tex]Consider the formula,
[tex]\cos A=\cos B\Rightarrow A=2k\pi\pm B[/tex]Applying the formula,
[tex]x=2k\pi\pm\frac{\pi}{6}[/tex]Thus, the required values of 'x' are,
[tex]x=2k\pi\pm\frac{\pi}{6}[/tex]Therefore, options 1st and 2nd are the correct choices.
i inserted a picture of the question can you please state whether the answer is A,B, C or D check all that apply
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Solution:
In the given figures, angles of the triangle ABC are corresponding equal to triangle DEF and the sides are proportional to each other.
[tex]\frac{AB}{DE}=\frac{BC}{EF}=\frac{AC}{DF}=\frac{1}{2}[/tex]Thus, the triangle ABC is similar to triangle DEF.
Therefore, the relationship between both triangles is the proportional side lengths.
Both triangles are not of the same size as their sides are not equal.
Both triangles are also not congruent as they do not satisfy any five conditions of congruence.
Hence, the correct option is A.
In the diagram below of AGJK, H is a point onGJ, HJ = JK, m2 = 28, and mZGJK = 76.What is mZGKH?2870H
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Problem
Solution
For the triangle GKJ we can find the angle K on this way:
28 +70 + Now we know that HJ= JK so then the triangle HJK is an isosceles triangle so then < JHK = < HKJ and we can do this:
70+ 2x = 180
2x= 110
x= 55
And then we can find the angle < GKH with the following equation:
28+70 + (55+y) = 180
y= 180-55 -28-70= 27
Paulina bought a used car as she was entering college and planned to trade it in when she graduated four years later. She had learned in her high school financial algebra class that the average used car depreciated at an annual rate of 15%. If she had paid $13,900 for her car, how much can she expect to get when it is time for her to trade it in for a new car?
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1st year
depreciable value: $13900
annual depreciation: $13900*15% = $2085
2nd year
depreciable value: $13900 - $2085 = $11815
annual depreciation: $11815*15% = $1772.25
3rd year
depreciable value: $11815 - $1772.25 = $10042.75
annual depreciation: $10042.75*15% = $1506.41
4th year
depreciable value: $10042.75 - $1506.41 = $8536.34
annual depreciation: $8536.34*15% = $1280.45
Final value: $8536.34 - $1280.45 = $7255.89
A bookstore sells a college algebra book for $90. If the bookstore makes a profit of 25% on each sale,what does the bookstore pay the publisher for each book?
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Okay, here we have this:
Considering the provided information, we obtain that:
The total price = Commission of the bookstore + Payment to the publisher
Replacing:
$90=$90(0.25)+Payment to the publisher
Payment to the publisher=$90-$90(0.25)
Payment to the publisher=$90-$22.5
Payment to the publisher=$67.5
Finally we obtain that the bookstore pay $67.5 to the publisher for each book.
a regular octagon has an area of 49 m 2 . find the scale factor of this octagon to a similar octagon with an area of 100 m 2
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Given,
The area of the regular octagon is 49 square metre.
The area of the another regular octagon is 100 square metre.
[tex]\begin{gathered} \text{Scaling factor=}\frac{\sqrt{\text{area of regular polygon}}}{\sqrt[]{\text{area of another regular plogon}}\text{ }} \\ \text{Scaling factor=}\frac{\sqrt[]{\text{4}9}}{\sqrt[]{\text{1}00}\text{ }} \\ \text{Scaling factor=}\frac{7}{10\text{ }} \end{gathered}[/tex]Here, the scaling factor of the regualar octagon is 7:10
Hence, the scaling factor is 7:10.
what is the driving distance between the police station and Art Museum
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First, locate the coordinate points (x,y) of each place, by looking at the graph:
Police station = (0,-4)
Art museum = (6,1)
Apply the distance formula:
[tex]D=\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex]Replacing:
[tex]D=\sqrt[]{(6-0)^2+(1-(-4))^2}=\sqrt[]{6^2+5^2}=\sqrt[]{36+25}=\sqrt[]{61}=7.81[/tex]What is the value of x? 20/72=x/360
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The value of x = 100
Been looking for help for 2 hrs hopefully you can help
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Given:
[tex]\begin{gathered} \mu=19.9 \\ \sigma=33.1 \\ n=40 \end{gathered}[/tex]To Determine:
[tex]P(X>8.9)[/tex]Solution
[tex]\begin{gathered} P(X>z) \\ z=\frac{x-\mu}{\sigma}=\frac{8.9-19.9}{33.1}=\frac{-11}{33.1}=-0.3323 \end{gathered}[/tex][tex]P(X>8.9)=1-P(X<8.9)=1-0.36982=0.63018[/tex]Hence, P(x>8.9) = 0.6302 (nearest 4 d. p)
can you help me solve this in expanded form. 156 X 687 = ?
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Given data:
The given expression is 156x687.
The given expression can be written as,
[tex]\begin{gathered} (100+50+6)(600+80+7)=60000+8000+700+30000+4000+350+3600+480+42 \\ =107172 \end{gathered}[/tex]Thus, the value of the given expression is 107172.
40% of what number is 26? Please show work!
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65
1) To find that, we need to write an equation:
[tex]x(0.4)=26[/tex]Note that we rewrote that 40% as 0.4.
2) Now, let's solve it
[tex]\begin{gathered} x0.4=26 \\ \frac{0.4x}{0.4}=\frac{26}{0.4} \\ x=65 \end{gathered}[/tex]3) So the 26 is 40% of 65
six reduced by the product of 5 and h
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F(x)=1/x g (x)=x-4 can you evaluate (golf)(0)? Explain why or why not.
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If f(x) = 1/x and g(x) = x-4 , then (gof)(0) cannot be evaluated as the function becomes not defined .
In the question
it is given that the functions
f(x) = 1/x
and g(x) = x-4
to find g=(gof)(x) ,
(gof)(x) = g(f(x))
= g(1/x) ... because f(x) = 1/x
= 1/x - 4 ....because g(x) = x-4
On simplifying further , we get
= (1-4x)/4x
On substituting x=0 , we get
gof(0) = (1-0)/4(0)
= 1/0
which is not defined , hence cannot be evaluated.
Therefore , if f(x) = 1/x and g(x) = x-4 , then (gof)(0) cannot be evaluated as the function becomes not defined .
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the cone has a height of 19 mm and the radius of 15 mm what is its volume use pie and round your answer to the nearest hundredth
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Answer
Volume = 4,478.57 mm³
Explanation
The volume of a cone is given as
Volume = ⅓ (πr²h)
where
π = pi = 3.142
r = radius of the cone = 15 mm
h = height of the cone = 19 mm
Volume = ?
Volume = ⅓ (πr²h)
Volume = ⅓ (3.142 × 15² × 19) = 4,478.57 mm³
Hope this Helps!!!