determine the volume of each rectangular or triangular prism round to the nearest tenth if necessary
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Determine the volume of each rectangular or triangular prism round to the nearest tenth if necessary
____________________
volume = base (B)* height (H)
_____________________
Base area
Triangle
B = b*h/2
Rectangle
B= L1*L2
__________________
volume = base (B)* height (H)
H= 15
Triangle case
B = 4.8 *9.6 /2
B = 46.08 / 2
B= 23.04
V= 23. 04* 15
V= 345.6 in ^3
Related Questions
i inserted a picture of the question can you please state whether the answer is A,B, C or D check all that apply
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Solution:
In the given figures, angles of the triangle ABC are corresponding equal to triangle DEF and the sides are proportional to each other.
[tex]\frac{AB}{DE}=\frac{BC}{EF}=\frac{AC}{DF}=\frac{1}{2}[/tex]Thus, the triangle ABC is similar to triangle DEF.
Therefore, the relationship between both triangles is the proportional side lengths.
Both triangles are not of the same size as their sides are not equal.
Both triangles are also not congruent as they do not satisfy any five conditions of congruence.
Hence, the correct option is A.
From the diagram below, given the side lengths marked, and if we know that < C is congruent to < F, we can say that ___
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SAS Similarity Theorem: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar.
AC is proportional to DE while BC is proportional to FE, but F is not the included angle between those sides, therefore, those triangles are not similar by SAS.
The Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. Since we have information only about one of the angles, ASA also doesn't apply.
For two triangles to be congruent, all of their measures must be congruent, which is not the case of our triangles.
The answer is option d. The two cannot be proven to be similar.
f(x) = - 3x + 4; g(x) = f(x) + 1
Graph it and then describe the graph
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The graph of function f(x) and g(x) is parallel lines separated by 1 unit.
In this question we have been given two functions f(x) = - 3x + 4 and g(x) = f(x) + 1
We need to graph these functions and then describe the graph.
The graph of given functions is as shown below.
The graph of function f(x) is a straight line with slope -3 and y-intercept 4.
The function g(x) is nothing but but function f(x) translated upward by 1 unit.
The graph of function g(x) is also a straight line with slope -3 and y-intercept 5.
Therefore, the graph of function f(x) and g(x) is parallel lines separated by 1 unit.
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Which equation is equivalent to: 3r=78+14 ?A. −3r=−78+14B. 3r−14=78C. 3r=78−14D. −3r=78−14
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An album received the following ratings on a 1-to-10 scale from10 music critics. What is the mean of the ratings?9.6, 9.8, 7.2, 6.4, 10.0, 8.9, 5.0, 9.8, 9.4, 6.8
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Given:
The ratings are
[tex]9.6,9.8,7.2,6.4,10.0,8.9,5.0,9.8,9.4,6.8[/tex][tex]\begin{gathered} \text{Mean}=\frac{9.6+9.8+7.2+6.4+10.0+8.9+5.0+9.8+9.4+6.8}{10} \\ \text{Mean}=\frac{82.9}{10} \\ \text{Mean}=8.29 \end{gathered}[/tex]Martha's video game rental plan costs $18 per month. Which tableshows the sum of the amounts that Martha will pay for her video gamerental plan over the next 5 months?
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Let's complete a table with the amounts of cost per month:
Month Sum od cost
1 18
2 2 * 18 = 36
3 3 * 18 = 54
4 4 * 18 = 72
5 5 * 18 = 90
So, please select the table that is correct
Find the distance between the points (5,5) and (-3,7). Round your answer to the nearest tenth, if necessary.8.2 units11.8 units3.2 units12.2 units
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The formula for the distance between two points in the plane is:
[tex]d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]So:
[tex]\begin{gathered} (x_1,y_1)=(5,5) \\ (x_2,y_2)=(-3,7) \\ d=\sqrt[]{(5-(-3))^2+(5-7)^2} \\ d=\sqrt[]{(8)^2+(-2)^2} \\ d=\sqrt[]{64+4} \\ d=\sqrt[]{68} \\ d=8.2462\ldots\approx8.2 \end{gathered}[/tex]So, the distance is approximately 8.2 units.
40% of what number is 26? Please show work!
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65
1) To find that, we need to write an equation:
[tex]x(0.4)=26[/tex]Note that we rewrote that 40% as 0.4.
2) Now, let's solve it
[tex]\begin{gathered} x0.4=26 \\ \frac{0.4x}{0.4}=\frac{26}{0.4} \\ x=65 \end{gathered}[/tex]3) So the 26 is 40% of 65
Could you tell me the process of solving the problem?
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Given:
[tex]Ln8=\frac{2\pi m\xi}{\sqrt{1-\xi^2}}[/tex]m=250
Required:
Find the value of
[tex]\xi[/tex]Explanation:
The value of ln8 is:
[tex]ln8=2.079[/tex][tex]\begin{gathered} 2.079=\frac{2\times3.14\times\xi}{\sqrt{1-\xi^2}} \\ 2.079(\sqrt{1-\xi^2})=6.28\xi^ \end{gathered}[/tex]Take the square on both sides.
[tex]\begin{gathered} 4.322(1-\xi^2)=39.44\xi^2 \\ \frac{1-\xi^2}{\xi^2}=\frac{39.4384}{4.322} \\ \frac{1}{\xi^2}-1=9.125 \\ \frac{1}{\xi^2}=9.125+1 \\ \frac{1}{\xi^2}=10.125 \end{gathered}[/tex]the ratio of the length to the width of a rectangular hall is 5:3. if the width is 1500cm, find the lenght.
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Step-by-step explanation:
The ratio of the length to the width that is- length:width = 5:3
Take x as a common value,
5x= length
3x= width
Width of the rectangle= 1500 cm
3x= 1500 cm
x= 1500/3
x= 500 cm
Length of the rectangle= 5x
x=500 cm
Length= 5*500
=2500 cm
Length of the rectangle= 2500 cm
Triangle KLM has KL = 28, KM = 28, and LM = 21. What is the area of the triangle?The area of AKLM is about(Simplify your answer. Round to one decimal place as needed.)
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Area = (b * h)/2, b = 21 bu we don't know h, s we have to calculate it
To calculate the height "h" we can use pythagoras with a triangle rectangle with base = 21/2 = 10.5 and hypothenuse = 28, so the height "h" is:
28² = h² + 10.5² ==> h² = 28² - 10.5² = 784 - 110.25 = 673.75
h² = 673.75
h = 25.96
Now that we have the height, the Area of the triangle = (b * h)/2 = (21 * 25.96)/2 = 272.5
Answer:
272.5
Find the equation of the line passing through points (6,0) and (-1,14)
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Answer:
y = -2x + 12
Step-by-step explanation:
Hope this helps!!
How do I write down the size of Angles and marked by letters?
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we can assume the lines are parallels so both triangles will have equal angles, so:
s=55° and p=x
now if we add 110 and x, we have a line this means
110+x=180
x=180-100
x=80
so p=x=80
and finally, the angles inside a triangle must add 180° so
55+p+t=180
55+80+t=180
135+t=180
t=180-135=45
So the answer is:
p=80°
s=55°
t=45°
Using this picture, describe what we are doing with the factored form of p(x) shown in the image in order to create a sketch of the function.
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Given:
[tex]p(x)=(x-1)(x+1)(x-4)^2[/tex]Sol:
[tex]\begin{gathered} p(x)=(x-1)(x+1)(x-4)^2 \\ \\ p(0)=(0-1)(0+1)(0-4)^2 \\ \\ p(0)=-16 \end{gathered}[/tex]X-intercept is at p(x) = 0 then,
[tex]\begin{gathered} p(x)=0 \\ \\ p(x)=(x-1)(x+1)(x-4)^2 \\ \\ 0=(x-1)(x+1)(x-4)^2 \\ \\ x=-1,1,4 \end{gathered}[/tex]At y- intercept the value of x is zero and at x = 0 function value is:
[tex]\begin{gathered} y=-16 \\ \\ \text{ The point is:} \\ (0,-16) \end{gathered}[/tex]At x-intercept y value is zero and x-intercept is -1,1,4 is:
[tex]\begin{gathered} \text{ At }x=-1 \\ \\ the\text{ value of }y=0 \\ \\ (-1,0) \\ \\ At\text{ }x=1 \\ \\ \text{ The value of }y=0 \\ \\ (1,0) \\ \\ \text{ At }x=4 \\ \\ \text{ The value of }y=0 \\ \\ (4,0) \end{gathered}[/tex]So all point is (-1,0) ,(1,0) and (4,0)
1. ¿Qué expresiones a continuación se pueden usar para encontrar el área del prisma rectangular de abajo? ¡ELIJA TODOS LOS QUE SE APLIQUEN! Nota: Puede probarlos todos para asegurarse de que sean iguales. * 15 (5x2x3) + (2x3x3) (5x2) + (5x2) + (5x2) + (5x2) 5x2x2 2 (5x2) + 2 (5x2) + 2 (2x2)
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We need to find the area of the prism given in the following image:
You need to add the surfaces of ALL rectangles in the image (recall that the area of a rectangle is : Base x Height)
So for this prism we have:
FOUR rectangles that measure 5 x 2
and also TWO small squares of area 2 x 2
So we need to select all the formulas they give you that read like the addition of the two above:
(5x2) + (5x2) + (5x2) + (5x2) + (2x2) + (2x2)
It can also be written as:
2 (5x2) + 2 (5x2) + 2 (2x2)
In the diagram below of AGJK, H is a point onGJ, HJ = JK, m2 = 28, and mZGJK = 76.What is mZGKH?2870H
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Problem
Solution
For the triangle GKJ we can find the angle K on this way:
28 +70 + Now we know that HJ= JK so then the triangle HJK is an isosceles triangle so then < JHK = < HKJ and we can do this:
70+ 2x = 180
2x= 110
x= 55
And then we can find the angle < GKH with the following equation:
28+70 + (55+y) = 180
y= 180-55 -28-70= 27
Find all X values where the tangent line to the graph of the function…
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Consider the function,
[tex]f(x)=6\sin x+\frac{9}{8}[/tex]The first derivative gives the slope (m) of the tangent of the curve,
[tex]\begin{gathered} m=f^{\prime}(x) \\ m=\frac{d}{dx}(6\sin x+\frac{9}{8}) \\ m=6\cos x+0 \\ m=6\cos x \end{gathered}[/tex]The equation of the line is given as,
[tex]y-3\sqrt[]{3}x=\frac{7}{3}[/tex]This can be written as,
[tex]y=3\sqrt[]{3}x+\frac{7}{3}[/tex]Comparing with the slope-intercept form of the equation of a line, it can be concluded that the given line has a slope,
[tex]m^{\prime}=3\sqrt[]{3}[/tex]Given that the tangent to the curve is parallel to this line, so their slopes must also be equal,
[tex]\begin{gathered} m=m^{\prime} \\ 6\cos x=3\sqrt[]{3} \\ \cos x=\frac{\sqrt[]{3}}{2} \\ \cos x=\cos (\frac{\pi}{6}) \end{gathered}[/tex]Consider the formula,
[tex]\cos A=\cos B\Rightarrow A=2k\pi\pm B[/tex]Applying the formula,
[tex]x=2k\pi\pm\frac{\pi}{6}[/tex]Thus, the required values of 'x' are,
[tex]x=2k\pi\pm\frac{\pi}{6}[/tex]Therefore, options 1st and 2nd are the correct choices.
What is the value of x? 20/72=x/360
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The value of x = 100
what is the driving distance between the police station and Art Museum
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First, locate the coordinate points (x,y) of each place, by looking at the graph:
Police station = (0,-4)
Art museum = (6,1)
Apply the distance formula:
[tex]D=\sqrt[]{(x2-x1)^2+(y2-y1)^2}[/tex]Replacing:
[tex]D=\sqrt[]{(6-0)^2+(1-(-4))^2}=\sqrt[]{6^2+5^2}=\sqrt[]{36+25}=\sqrt[]{61}=7.81[/tex]a regular octagon has an area of 49 m 2 . find the scale factor of this octagon to a similar octagon with an area of 100 m 2
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Given,
The area of the regular octagon is 49 square metre.
The area of the another regular octagon is 100 square metre.
[tex]\begin{gathered} \text{Scaling factor=}\frac{\sqrt{\text{area of regular polygon}}}{\sqrt[]{\text{area of another regular plogon}}\text{ }} \\ \text{Scaling factor=}\frac{\sqrt[]{\text{4}9}}{\sqrt[]{\text{1}00}\text{ }} \\ \text{Scaling factor=}\frac{7}{10\text{ }} \end{gathered}[/tex]Here, the scaling factor of the regualar octagon is 7:10
Hence, the scaling factor is 7:10.
which of the following is true?Blaine and Cruz made an error in picking their first steps.Cruz made and error in picking his first step All three made an error because the right side equals -1.All three chose a valid first step toward solving the equation.
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Given data:
The given expression is 4/7 (7-n)=-1.
Aaron starts with multiplying 7/4 on both sides, Blaine starts with distributive property by multiplying 4/7 with 7 and -u, Cruz starts by dividiing 4/7 on both sides.
Thus, all of them are correct, correct option is last one.
Answer: d
Step-by-step explanation: yw
six reduced by the product of 5 and h
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ILL GIVE BRAINLY AND 15 POINTS
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Using functions, it is found that:
a. The costs for two years are as follows:
Option A: $4,600.Option B: $1,720.b. The pros and cons are as follows:
Option A: pro is the lower fixed fees, con is the higher hourly fee.Option B: pro is the lower hourly fee, con is the higher fixed fees.Option A functionThe cost of $2,600 for the first year is obtained as follows:
$500 set up fee.$2,000 of the 100 hours at $20 per hour.$100 of the hosting fee.For the second year, only the hourly cost will be paid, hence $2,000 will be added and the total cost is of:
$2,600 + $2,000 = $4,600.
The pros of Option A are the lower initial fees, hence for a lower number of hour, the cost is smaller, while the con is the high hourly price, meaning that for a high number of hours, option B is better.
Option B functionThe cost of $2,600 for the first year is obtained as follows:
$1,000 set up fee.$30 a month of hosting fee.For the second year, only the hosting fee is paid, meaning that $360 is added to the cost, thus:
$1,360 + $360 = $1,720.
The pros and cons are basically opposite of option A, higher basic fees with lower hourly/monthly fees, meaning that it is better over longer periods.
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how do you simplify this complex fraction in the lowest terms
[tex]\frac{77x^9/15y^5}{7x^7/10y^4}[/tex]
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Answer:
[tex]\frac{22x^{2}}{3y}[/tex]
Step-by-step explanation:
[tex]\frac{(77x^{9})(10y^{4}) }{(7x^{7})(15y^{5}) }[/tex]
[tex]\frac{(11x^{2})(2)}{3y}[/tex]
Melanie has pears and papayas in a ratio of 13:25. How many pears does she have ifshe has 2500 papayas?On the double number line below, fill in the given values, then use multiplication ordivision to find the missing value.
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Given that the ratio of pears to papayas is 13:25,
[tex]\frac{\text{ Pears}}{\text{ Papayas}}=\frac{13}{25}[/tex]It means that Melanie has 13 pears, then the number of papayas must be 25.
It is asked to determine the number of pears corresponding to 2500 papayas.
First plot the values in the blank boxes on the double number line as below,
Let 'x' be the number of pears corresponding to 2500 papayas.
Now, cross multiply the terms,
[tex]25\cdot x=13\cdot2500[/tex]Divide both sides by 25,
[tex]\begin{gathered} 25\cdot x\cdot\frac{1}{25}=13\cdot2500\cdot\frac{1}{25} \\ x=13\cdot100 \\ x=1300 \end{gathered}[/tex]Thus, there should be 1300 pears corresponding to 2500 papayas.
the cone has a height of 19 mm and the radius of 15 mm what is its volume use pie and round your answer to the nearest hundredth
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Answer
Volume = 4,478.57 mm³
Explanation
The volume of a cone is given as
Volume = ⅓ (πr²h)
where
π = pi = 3.142
r = radius of the cone = 15 mm
h = height of the cone = 19 mm
Volume = ?
Volume = ⅓ (πr²h)
Volume = ⅓ (3.142 × 15² × 19) = 4,478.57 mm³
Hope this Helps!!!
400 meters to 350 meters increase or decrease
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In this case we have a negative change, therefore decrease
answer: decrease
F(x)=1/x g (x)=x-4 can you evaluate (golf)(0)? Explain why or why not.
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If f(x) = 1/x and g(x) = x-4 , then (gof)(0) cannot be evaluated as the function becomes not defined .
In the question
it is given that the functions
f(x) = 1/x
and g(x) = x-4
to find g=(gof)(x) ,
(gof)(x) = g(f(x))
= g(1/x) ... because f(x) = 1/x
= 1/x - 4 ....because g(x) = x-4
On simplifying further , we get
= (1-4x)/4x
On substituting x=0 , we get
gof(0) = (1-0)/4(0)
= 1/0
which is not defined , hence cannot be evaluated.
Therefore , if f(x) = 1/x and g(x) = x-4 , then (gof)(0) cannot be evaluated as the function becomes not defined .
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Been looking for help for 2 hrs hopefully you can help
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Given:
[tex]\begin{gathered} \mu=19.9 \\ \sigma=33.1 \\ n=40 \end{gathered}[/tex]To Determine:
[tex]P(X>8.9)[/tex]Solution
[tex]\begin{gathered} P(X>z) \\ z=\frac{x-\mu}{\sigma}=\frac{8.9-19.9}{33.1}=\frac{-11}{33.1}=-0.3323 \end{gathered}[/tex][tex]P(X>8.9)=1-P(X<8.9)=1-0.36982=0.63018[/tex]Hence, P(x>8.9) = 0.6302 (nearest 4 d. p)
Paulina bought a used car as she was entering college and planned to trade it in when she graduated four years later. She had learned in her high school financial algebra class that the average used car depreciated at an annual rate of 15%. If she had paid $13,900 for her car, how much can she expect to get when it is time for her to trade it in for a new car?
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1st year
depreciable value: $13900
annual depreciation: $13900*15% = $2085
2nd year
depreciable value: $13900 - $2085 = $11815
annual depreciation: $11815*15% = $1772.25
3rd year
depreciable value: $11815 - $1772.25 = $10042.75
annual depreciation: $10042.75*15% = $1506.41
4th year
depreciable value: $10042.75 - $1506.41 = $8536.34
annual depreciation: $8536.34*15% = $1280.45
Final value: $8536.34 - $1280.45 = $7255.89