The total angular momentum of the two-disk system after the smaller disk is dropped on the larger disk is [tex]\omega _2 = (I_1\times \omega _1) / (I_1 + m_2 \times r^2)[/tex].
The total angular momentum of the two-disk system after the smaller disk is dropped on the larger one will depend on the initial angular momenta of the two disks and any changes that occur when they collide.
Assuming the system is isolated, the total angular momentum before and after the collision must be conserved. Before the collision, we can assume that the smaller disk has an initial angular momentum of zero since it is not rotating, and the larger disk has an initial angular momentum given by:
[tex]L_1 = I_1 \times \omega_1[/tex]
where [tex]I_1[/tex] is the moment of inertia of the larger disk and ω₁ is its initial angular velocity.
When the smaller disk is dropped onto the larger one, there will be a transfer of angular momentum from the smaller disk to the larger one. The final angular velocity of the combined system will depend on the moment of inertia of the combined system, which can be approximated as:
[tex]I_2 I_1 + m_2 \times r^2[/tex]
Where m_2 is the mass of the smaller disk and r is the distance from the center of the larger disk to the point where the smaller disk makes contact. We assume that the collision is elastic and that no external forces act on the system, so angular momentum is conserved:
[tex]L_1 = L_2[/tex]
[tex]I_1 \times \omega _1 = (I_1 + m_2 \times r^2) \times \omega _2[/tex]
Solving for ω₂, we get:
[tex]\omega _2 = (I_1\times \omega _1) / (I_1 + m_2 \times r^2)[/tex]
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sarah attempts to do the popular physics trick of swinging a shallow pail of water around in a vertical circle with uniform circular motion so that the water doesn't spill out when the pail is upside down. if the distance from the bottom of the pail to her shoulder (the center of rotation) is 0.449 meters long, what is the minimum constant tangential speed that the pail bottom must have so that the water does not spill out at the top of the circular path
A pail of water is swung in a vertical circle using a uniform circular motion. In order to make sure that the water doesn't spill out when the pail is upside down, a minimum constant tangential speed of 2.1 m/s is required.
The minimum constant tangential speed required by the pail of water in order to ensure that the water doesn't spill out when the pail is upside down can be calculated using the formula:
[tex]v = \sqrt{gr}[/tex]
where v = minimum constant tangential speed g = acceleration due to gravity r = radius of the circle.
The distance from the bottom of the pail to Sarah's shoulder is 0.449 m long.
Since this distance is the radius of the circular path, we can substitute it in the formula.
Therefore,
[tex]v = \sqrt{9.8 m/s^2 \times 0.449 \ m} = \sqrt{4.4102 m^2/s^2} = 2.1 \ m/s[/tex]
Therefore, the minimum constant tangential speed required by the pail of water is approximately 2.1 m/s.
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A body slides down a smooth inclined plane at 30° to the horizontal. The distance covered after 15s from rest is
The distance covered by the body after 15 seconds down the inclined plane is approximately 1102.5 meters.
We can use the equations of motion to solve this problem. The acceleration of the body down the inclined plane can be found using trigonometry:
a = gsin(30°) = (9.8 m/s²)(1/2) = 4.9 m/s²
where g is the acceleration due to gravity.
Using the equation of motion:
s = ut + (1/2)at²
where s is the distance covered, u is the initial velocity (which is zero in this case), and t is the time taken, we can find the distance covered after 15 seconds:
s = (1/2)4.9(15)² = 1102.5 meters
Therefore, the distance covered by the body after 15 seconds down the inclined plane is approximately 1102.5 meters.
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A) A force of 4. 40 N is applied to a dart over a distance of 54 cm. The dart has a mass of 28 g. Assuming no energy is lost due to friction, what will be the kinetic energy of the dart after it is thrown?
b) Use your result in part a) calculate the speed of the dart
c) If the dart were thrown straight upwards, what maximum height would it reach?
a) The kinetic energy of the dart after it is thrown is 2.376 J.
b) The speed of the dart is 18.45 m/s.
c) If the dart were thrown straight upwards, the maximum height it would reach is 17.0 m.
a) The work done on the dart by the applied force is given by:
work = force x distance = 4.40 N x 0.54 m = 2.376 J
Since no energy is lost due to friction, all of this work is converted to the kinetic energy of the dart:
kinetic energy = work = 2.376 J
b) The kinetic energy of the dart can also be expressed as:
kinetic energy = (1/2) x mass x velocity^2
Rearranging this equation gives:
velocity^2 = (2 x kinetic energy) / mass
Substituting the values from part a) gives:
velocity^2 = (2 x 2.376 J) / 0.028 kg = 340.29 m^2/s^2
Taking the square root of both sides gives:
velocity = 18.45 m/s
c) When the dart is thrown straight upwards, its initial vertical velocity is zero. The maximum height it will reach can be calculated using the formula:
maximum height = (initial velocity^2) / (2 x acceleration)
where acceleration is the acceleration due to gravity, which is approximately 9.81 m/s^2.
Substituting the speed calculated in part b) gives:
maximum height = (18.45 m/s)^2 / (2 x 9.81 m/s^2) = 17.0 m
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how tall must a water-filled manometer be to measure blood pressure as high as 300 mm hg? density of blood is 1.05 x 103 kg/m3
The height of a water-filled manometer required to measure blood pressure as high as 300 mm Hg is 229.69 cm.
A manometer is a pressure measurement device that is utilized to measure the pressure of gases and liquids in a container.
The weight of the liquid in the manometer rises or falls depending on the pressure of the gases and liquids in the container.
In order to measure blood pressure, a water-filled manometer is used. The density of blood is 1.05 x 103 kg/m3. The height of the manometer is required to be found.
The pressure of blood is 300 mm Hg.
The following formula will be used to calculate the height of the manometer:
h = (P*d)/(g*H2O)
where, P = 300 mm Hg,
d = 1.05 × 103 kg/m^3,
g = 9.8 m/s2, and
H2O = 1000 kg/m^3
Substituting the values in the equation:
h = (300*1.05*103)/(9.8*1000)
h = 229.69 cm
The height of the manometer must be 229.69 cm to measure blood pressure as high as 300 mm Hg.
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3. with moderate winds, a modern large wind turbine can generate about 250 kw of electricity, whereas a large nuclear power plant can generate 1,000 mw. a. how many wind turbines would be required to give the same output as one nuclear plant?
A modern large wind turbine can generate about 250 kw of electricity, whereas a large nuclear power plant can generate 1,000 mw so, 4000 wind turbines would be required to give the same output as one nuclear power plant.
To know how many wind turbines would be required to give the same output as one nuclear power plant is a simple mathematical calculation that involves only the conversion of kilowatts to megawatts.
Wind turbine and Nuclear power plant electricity generation in modern large wind turbine with moderate winds is 250 KW whereas, the generation capacity of large nuclear power plant is 1,000 MW.
To determine how many wind turbines would be required to give the same output as one nuclear power plant, we need to convert kilowatts to megawatts.
Since 1 MW = 1,000 kW, therefore 1,000 MW = 1,000,000 kW
We are given that a modern large wind turbine can generate about 250 kW of electricity
Therefore, the number of wind turbines required to give the same output as one nuclear power plant can be calculated as:
Number of wind turbines = Total capacity of nuclear power plant / Capacity of single wind turbine
= 1,000,000 / 250= 4000
Thus, 4,000 wind turbines would be required to give the same output as one nuclear power plant.
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(PLS HELP ME NOW!!!!)
Answer:
the bottom
Explanation:
G 13% part (g) using the numbers from the previous step, give a numeric answer for the time in seconds that elapse when the package, initially at rest, travels a distance of 2. 25 m down the ramp
The time required for the container to move 2.25 metres down the ramp is roughly 0.104 seconds.
From part (f), we have determined the final velocity of the package to be 1.38 m/s. Using this value along with the distance traveled (Δx = 2.25 m), we can calculate the time elapsed using the kinematic equation:
Δx = (vf² - vi²) / 2a
Substituting the values, we get:
2.25 = (1.38² - 0) / (2 * 0.087)
Solving for time (t), we get:
t = 2.25 * 0.087 / 1.897
t ≈ 0.104 seconds
Therefore, the time elapsed when the package travels a distance of 2.25 m down the ramp is approximately 0.104 seconds.
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Which of the arrows is in the direction of the net force on charge b?
The correct answer is option: e. Because, this force always acts along line joining the two charges. For like charges, the force is repulsive in nature.
The Coulomb's law states how charges interact with each other. That law states that: [tex]F =q1q24πϵ0r2[/tex]
If the charges are like , the force will be repulsive, meaning that each charge will exert a force on the other to push the two of them apart. If charges are opposite , they will exert an attractive force on each other. G or unlike charges, the force is attractive as shown below: ( as Shown in image attached to question), As we know none of the arrow moves in the direction of the net force. Hence, the correct answer is option: e
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if you were in a rocket ship travelling away from earth at a speed close to the speed of light, what changes would you notice in the clock and volume of your friend who stayed on earth?
If you were in a rocket ship traveling away from earth at a speed close to the speed of light, then the changes that you would notice in the clock and the volume of your friend who stayed on earth are time dilation and volume dilation.
Time dilation: According to special relativity theory, time dilation occurs as an object's velocity approaches the speed of light. The faster an object travels, the slower its internal clock ticks. Time would seem to pass more slowly for you than it would for your friend on earth. The time on the rocket would appear to be slower than the time on the earth, and the rocket's clock would tick more slowly as seen from the earth.
Volume dilation: Volume dilation is a term used to describe a length contraction or expansion of an object along the direction of motion. According to the Lorentz transformation, as the velocity of an object approaches the speed of light, its length appears to shrink in the direction of motion.
This would result in the volume of the object appearing to decrease in size as well. Your friend on earth would notice that your rocket ship appears to be shorter than it really is, and its volume would appear to be less.
Therefore, time dilation and volume dilation are the two factors that would be noticed.
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Peter is heating water on the stove to boil eggs for a picnic. How much heat is required to raise the temperature of his 10 kg vat of water from 20°C to 100°C?
Answer:
The specific heat capacity of water is 4.184 J/g°C, and we need to find the amount of heat required to raise the temperature of 10 kg (or 10,000 g) of water from 20°C to 100°C.
The formula for calculating the amount of heat required is:
Q = m * c * ΔT
where:
Q = heat energy (in Joules)
m = mass (in grams)
c = specific heat capacity (in J/g°C)
ΔT = change in temperature (in °C)
We can start by calculating the change in temperature:
ΔT = 100°C - 20°C = 80°C
Then, we can plug in the values and solve for Q:
Q = 10,000 g * 4.184 J/g°C * 80°C
Q = 3,347,200 J
Therefore, Peter needs 3,347,200 Joules of heat to raise the temperature of his 10 kg vat of water from 20°C to 100°C.
Polarizing windows, filters, etc. , are often used to reduce the amount of light that enters the lens of a camera or into a room or a car. A library atrium has an overhead skylight that lets in too much light during the day, which heats up the interior of the library far too much. The building engineer installs new double-paned polarizing sky lights to reduce the intensity. If sunlight, which is unpolarized, has an average intensity of 1340 W/m2, what angle should the polarizing axis of the second pane of the window make with the polarizing axis of the first pane of the window in order to reduce the intensity of the sunlight to 34% of the original value
The polarizing axis of the second pane of the window make with the polarizing axis of the first pane of the window in order to reduce the intensity of the sunlight to 34% of the original value is [tex]23^o[/tex].
The intensity of the sunlight falling from the first pane
[tex]I_1 = \frac{I_o}{2}[/tex]
Once this intensity light passes through the second pane then
[tex]I_2 = I_1 \cos^2 \thetaI_2 = \frac{I_o}{2} \cos^2 \theta[/tex]
Given I2 /Io = 0.42 (42%) so
[tex]0.42 = \frac{1}{2} \cos^2 \theta\\[/tex]
[tex]\cos^2 \theta = 0.84[/tex]
[tex]\cos \theta = \sqrt{0.84} = 0.9165\\[/tex]
[tex]\theta = \cos^{-1} ( 0.9165) = 23.6^o[/tex]
The polarizing axis, also known as the polarization direction, is the direction of the electric field oscillation of an electromagnetic wave. When light passes through a polarizing filter, only the component of the electric field parallel to the polarizing axis is allowed to pass through, while the perpendicular component is blocked.
For example, a linear polarizing filter has a polarizing axis that allows only light waves oscillating in a specific direction to pass through. If the electric field oscillation of the light is perpendicular to the polarizing axis, it will be blocked, resulting in a darker image. In contrast, circular polarizers have a rotating polarizing axis that can selectively block light waves based on their direction of rotation. This is useful in photography and other applications where glare or reflections need to be minimized.
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Which statement is true for the formation of tides on Earth?
The Sun and Moon are the same distance from Earth and have the same effect on the tides.
The Moon has the greatest effect on tides since it is closer to Earth than the Sun.
The Sun has the greatest effect on tides since it has a greater mass than the Moon.
The Moon has the least effect on tides since it has a smaller mass than the Sun.
Answer:
B
Explanation:
The moon effects the Earth's tides more than the sun.
The correct statement for the formation of tides on Earth is "The Moon has the greatest effect on tides since it is closer to Earth than the Sun."
Tides are caused by the gravitational pull of the Moon and Sun on Earth's oceans.
While the Sun has a greater mass than the Moon, the Moon is much closer to Earth and therefore has a greater effect on the tides.
The Moon's gravitational pull causes the oceans to bulge towards it, creating high tides on the side of Earth closest to the Moon and on the opposite side of Earth.
As Earth rotates, different areas experience high and low tides. The Sun also has an effect on the tides, but it is less significant than the Moon's effect.
In conclusion, the statement "The Moon has the greatest effect on tides since it is closer to Earth than the Sun" is true for the formation of tides on Earth.
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number of electrons with a combined charge of -1 nC
The number of electrons in 1 nenocoulomb (1 nc) charge is 6.24*109. It takes 6 10 18 electrons to produce one coulomb of charge.
What is an electron, for instance?The smallest elemental component of an atom, the electron has a negative charge. In some kind of a negative ion, there are an adequate amounts of electrons as well as protons. One electron but one proton are all that the hydrogen atom has.
What role do electrons play in atoms?The negatively charged components of an atom are called electrons. The total negative charge of an atom's electrons counteracts the positive electrical charge of its protons there in atomic nucleus. When compared to all the other components of the atom, electrons are quite tiny.
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can some one help me answer this qustion
The X component of the tiger's velocity is 53.59 km/h.
The vertical (Y) component of the tiger's velocity is 12.37 km/h.
What are the component of the tiger's velocity?The components of the tiger's velocity include X and Y components; the magnitudes of the X and Y components is calculated using the following formula.
The X component of the tiger's velocity is calculated as;
Vx = V cosθ
where;
θ is the angle of the velocityV is the magnitude of the velocityVx = 55 km/h x cos (13)
Vx = 53.59 km/h
The vertical (Y) component of the tiger's velocity is calculated as;
Vy = V sinθ
Vy = 55 km/h x sin (13)
Vy = 12.37 km/h
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Someone please help me thanks so much!!
The image tubes in television sets and computer displays. Until recently, the picture tube was the most versatile of them, capable of displaying numbers, characters, graphs, and both still and moving images.
Which type of tube is television picture tube?CRT stands for cathode-ray tube. The television image tube, which is used in household television receivers, is the most recognizable and ubiquitous type of cathode-ray tube.
LCD TVs first came in the early 2000s as the newer, superior TV with current technology. Nonetheless, tube Televisions were the most popular at the time. Because it was just 15 years ago, many of these TVs are still in use. We'll go into why you should replace your tube TV and the benefits of doing so further down.
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9. A 1385-kg pickup truck hitched to a 453-kg
trailer accelerates along a level road from a
stoplight at 0. 75 m/s2 [forward]. Ignore friction
on the trailer and air resistance. Calculate
(a) the tension in the hitch a
(b) the force of static friction exerted by the road
on the pickup truck to propel it forward a
(c) the force the trailer exerts on the pickup
truck a
(a) The tension in the hitch is 339.75 N.
equal to the mass of the trailer times the acceleration (453 kg x 0.75 m/s2 = 339.75 N).
(b) The force of static friction exerted by the road on the pickup truck is 1038.75 N.
(c) The force the trailer exerts on the pickup truck is equal to 339.75 N.
(a) The tension in the hitch is equal to the mass of the trailer times the acceleration.
It is calculated by,
453 kg x 0.75 m/s2
= 339.75 N.
(b) The force of static friction exerted by the road on the pickup truck to propel it forward is equal to the mass of the pickup truck times the acceleration
It is calculated by
1385 kg x 0.75 m/s2
= 1038.75 N
(c) The force the trailer exerts on the pickup truck is equal to the mass of the trailer times the acceleration.
It is calculated by,
453 kg x 0.75 m/s2
= 339.75 N
Static friction is a force that keeps an object at rest. Static friction definition can be written as: The friction experienced when individuals try to move a stationary object on a surface, without actually triggering any relative motion between the body and the surface on which it is on.
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A laborer wants to move crates containing bottles of olive oil from a truck to the ground by sliding them along a ramp. The ramp is 6 m long and is at an angle of 25°. There is friction on the ramp for the first crate. The laborer doesn’t know that there is a small leak in one of the bottles. The leak leaves a layer of oil on the ramp. The oil creates a frictionless surface for the second crate Wayne sends down the ramp. At the bottom of the ramp, the speed of the second crate (without friction) is 2. 5 the speed of the first crate (with friction). Find the coefficient of kinetic friction. Hint: this is a multistep problem that is be solved using only energy equations. Do not use kinematics or you will not receive full credit, even if your answer is correct. Use conservation of energy and start with the frictionless case. (30 pts)
Therefore, the coefficient of kinetic friction is approximately 0.136
the acceleration of the first crate with friction down the ramp.
We'll use the following formula:
a = gsin(theta) - mucos(theta)*g
whereg = acceleration due to gravity = 9.8 m/[tex]s^2[/tex]
theta = angle of the ramp = 25 degrees
mu = coefficient of kinetic friction
Plugging in the values, we get:
a = 9.8sin(25) - mucos(25)9.8
a = 3.9763 - 3.5299mu
Plugging in the values, we get:
[tex]v^2=[/tex] 0 + 2*(3.9763 - 3.5299*mu)6
[tex]v^2[/tex] = 47.715 - 42.1794mu
the velocity of the second crate without friction at the bottom of the ramp. We know it's 2.5 times the velocity of the first crate with friction, so:v' = 2.5sqrt(47.715 - 42.1794mu)
no friction for the second crate, we can use the conservation of energy to relate the initial potential energy to the final kinetic energy:
mg6sin(25) = 0.5m*[tex]v^2[/tex]
where
g = acceleration due to gravity = 9.8 m/
Simplifying and plugging in the value for v', we get:
mg6sin(25) = 0.5m*)(47.715 - 42.1794mu)
3.5299 = 11.885 - 10.545*mu
mu = 0.136
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In 1–2 sentences, explain why weather can be predicted only as probable, not definite.(2 points)
The amount of information available, the length of time available to examine it, and consequently the complexity of weather occurrences limit one's ability to express their skill to predict the weather.
Why can't weather be forecast other than probabilistically?Models employ estimations and assumptions to forecast the weather because it is impossible to collect data from the future. These estimations from the models get less accurate as time goes on since the atmosphere is continually changing.
What distinguishes a probabilistic forecast from a deterministic one?Probabilistic techniques accurately depict the uncertainty where deterministic plans provide exact average quantities with a known but unquantified uncertainty.
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electricity flows into hair dryer when it is plugged into a socket. if electricity has been added to the hair dryer ,why doesn't it keep operating for a while after being unplugged?
A hair dryer uses the electricity from the power source to run its motor and heating element when it is hooked into an electrical outlet. Heat and kinetic energy are created from this electrical energy.
I was using my hair dryer when the power went off, why?One of the most frequent causes of circuit breakers being tripped by a hairdryer is an overloaded circuit. A circuit overload occurs when there are several high-powered gadgets drawing 15 to 20 amps of electricity simultaneously on the same circuit.
Does a hair dryer draw power?A conventional in-room, wall-mounted hair dryer uses roughly 1.6 kW of power on average. This indicates that a guest will use 0.4 kilowatt-hours (kWh) of power if they use their hair dryer for 15 minutes.
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The weightlifter in question #9 picks up a mass weighing 300kg. What is the pressure that his feet now exert on the floor? (attached image of question 9 for reference)
According to the question, The pressure that the weight lifter's feet now exert on the floor is approximately 431200 Pa.
What is a mass ?The amount of matter in an entity or particle is represented by the dimensionless number mass (symbolized m). The kilogram is the International System's (SI) preferred measure of mass. (kg).
The weight lifter's weight calculated as:
Weight = mass x gravity
Weight lifter's weight = 140 kg x 9.8 m/s^2 = 1372 N
The weight of the mass the weight lifter picks up is:
Weight of the mass = mass x gravity = 300 kg x 9.8 m/s^2 = 2940 N
Therefore, the total weight exerted by the weight lifter and the mass is:
Total weight = Weight lifter's weight + Weight of the mass = 1372 N + 2940 N = 4312 N
The pressure exert on the floor can be calculated as:
Pressure = Force / Area
Assuming the weight lifter's weight is distributed equally on both feet and each foot has an area of approximately 50 cm^2,
the pressure on each foot calculated as:
Pressure on each foot = Total weight / (2 x Area of each foot)
Pressure on each foot = 4312 N / (2 x 50 cm^2 x 0.0001 m^2/cm^2) = 4312 N / 0.01 m^2 = 431200 Pa
Therefore, the pressure that the weight lifter's feet now exert on the floor is approximately 431200 Pa.
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. a resistor r consumes 0.0625 w when it is connected to a 1.50 v battery. a. assuming that r does not change, how much power does the resistor consume when attached to a 12.6 v battery? b. when this resistor is connected to another battery, it consumes 5.00 w. what is the voltage of this battery?
The power consumed by the resistor when it is connected to a 12.5 V battery is 4.41 W and the voltage of the battery is 13.41 V which provides 5 W power to the resistor.
We can use the formula for the power consumption of a resistor:
[tex]P = V^2/R[/tex]
where P is power, V is voltage, and R is resistance.
a. To determine the power consumption of the resistor when attached to a 12.6 V battery, we can use the same formula and solve for P:
[tex]P = V^2/R = (12.6 V)^2 / R[/tex]
However, R is not given in the problem. But we can use the power and voltage values given when the resistor was connected to a 1.5 V battery to find R:
[tex]P = V^2/R[/tex]
[tex]0.0625 W = (1.5 V)^2 / R[/tex]
[tex]R = (1.5 V)^2 / 0.0625\ W[/tex]
[tex]R = 36 \ \Omega[/tex]
Now we can use this value of R to find the power consumption when the resistor is connected to a 12.6 V battery:
[tex]P = V^2/R = (12.6 V)^2 / 36 \ ohms[/tex]
P = 4.41 W
Therefore, the power consumption of the resistor when attached to a 12.6 V battery is approximately 4.41 W.
b. To find the voltage of the battery that consumes 5.00 W, we can use the same formula and solve for V:
[tex]P = (V^2) / R[/tex]
[tex]5.00 W = (V^2) / R[/tex]
We know the value of R from before, so we can substitute it in:
[tex]5.00 W = (V^2) / 36 \ ohms[/tex]
Solving for V, we get:
[tex]V = \sqrt{5.00 W \times 36 \ ohms} = 13.41 V[/tex]
Therefore, the voltage of the battery that consumes 5.00 W is approximately 13.41 V.
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If a bus is running with a speed of 72km HR calculate the distance traveled in 5 sec
Answer:
0.1 KM/S
Explanation:
First, looking at the question we can say a few things: distance = speed/time. First we will change the 72 KM/HR to ? KM/S (seconds). To change the units fo the speed to seconds, we need to find how many seconds are in an hour which is 3600) then we have 72 KM/3600S and we will divide 3600 by 5 to get 720 which is what we will divide 3600 by to get to 5 seconds and what we will divide 72 by to get your speed in kilometers for your answer. 3600/720 = 5 seconds, and 72/720 is equal to 0.1. To format your answer, you would get 0.1 KM/S (kilometers/seconds)
If your teacher won't accept that answer or you want to change the unit of measurement for speed, you can also find out how many feet/miles a kilometer is and then multiply 0.1 times that value and then you'd have ? ft/s or mi/s.
A block weighing 12.0 newtons is on a ramp inclined at 30.0° to the horizontal. A 3.0-newton force of friction, Fƒ, acts on the block as it is pulled up the ramp at constant velocity with force F, which is parallel to the ramp, as shown in the diagram. What is the magnitude of force F?
A) 9.0N
B) 10.0N
C) 12.0 N
D) 15.0N
the block when it is being hauled up the slope at a constant speed using force F perpendicular to a ramp, with a force of 10.0N.
What is force, and what is its unit?Force is indeed a physical phenomenon that alters or has the potential to alter an object's shape, its state of motion, or both.
What is force, and what is its equation?According to Newton's second law of motion, the force corresponds to the momentum change divided by the time change. Force equals mass times acceleration, or F = m x a, for a constant mass.
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Which have the longer wavelength, radio waves or microwaves?
The correct answer in that the Radio waves have a longer wavelength than microwaves.
Radio waves have a wavelength range of about 1 millimeter to 100 kilometers, while microwaves have a wavelength range of about 1 millimeter to 1 meter. This means that radio waves have a longer wavelength than microwaves in general. Wavelength is related to the frequency of the electromagnetic wave by the equation: λ = c / f, where λ is the wavelength, c is the speed of light, and f is the frequency. Since the speed of light is constant, a longer wavelength corresponds to a lower frequency and vice versa. Radio waves are commonly used for communication and broadcasting, while microwaves are used for a variety of applications including cooking food, radar, and wireless communication. Understanding the properties of different electromagnetic waves, including their wavelength and frequency, is important for many areas of science and technology.
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Two people leave points A and B at the same time. They intend to meet at point C at the same time. The person who leaves point A walks at a speed of 3 miles per hour. You and a friend are trying to determine how fast the person who leaves point B must walk. Your friend claims you need to know the length of . Is your friend correct? Explain your reasoning.
Your friend is correct. In order to determine the speed at which the person who leaves point B must walk, you need to know the length of AC and BC.
This is because the time it takes for each person to reach point C is dependent on the distance they must travel and the speed at which they are traveling.
Using the formula time = distance / speed, you can calculate the time it takes for each person to reach point C.
For the person leaving point A, the time it takes to reach point C is tA = AC / 3, since they are traveling at a speed of 3 miles per hour.
For the person leaving point B, the time it takes to reach point C is tB = BC / x, where x is the speed at which they are traveling.
Since both people are intended to reach point C at the same time, you can set the two equations equal to each other:
AC / 3 = BC / x
Cross-multiplying and solving for x gives you the speed at which the person leaving point B must walk:
x = 3BC / AC
Without knowing the length of AC and BC, you cannot determine the speed at which the person leaving point B must walk. Therefore, your friend is correct.
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i really need help someone help for the scent e fills
This implies that when the force applied on an item increases, so does the object's acceleration. Similar to how an object's acceleration decreases as its mass increases, so does its mass.
What principle of Newton's law asserts that a rise in force leads to a rise in acceleration?Force with acceleration are directly correlated, as shown by Newton's second law. The more force that is exerted to an object, the faster it will accelerate. For instance, the acceleration doubles when the force exerted on an object doubles.
Why does acceleration cause a rise in force?The relationship among acceleration and force is explained in Newton's second laws of motion. They are comparable in size. An object moves forward at a speed equal to the force pushing against it. The simplest approach to determine force is to multiply mass by acceleration.
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A horizontal pipe of diameter 0.045 m has a smooth constriction to a section of diameter 0.567 m. the density of oil flowing in the pipe is 821 kg/m* if the pressure in the pipe is 8940 n/m and in the constricted section is 6705 n/m?, what is the rate at which oil is flowing?
If the pressure in the pipe is 8940 n/m and in the constricted section is 6705 n/m ,the rate at which oil is flowing is approximately 0.029 m^3/s.
We can use the principle of continuity of flow to relate the flow rate of the oil in the pipe to the difference in pressure and the area of the pipe at the constriction:
Q = Av
where Q is the flow rate, A is the area of the pipe at the constriction, and v is the velocity of the oil at the constriction.
We can use Bernoulli's equation to relate the pressure difference to the velocity of the oil at the constriction:
P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2
where P1 and P2 are the pressures at the two points, and v1 and v2 are the velocities of the oil at those points.
Since the pipe is horizontal, the height difference between the two points can be neglected and we can assume that the gravitational potential energy of the oil is constant. Therefore, we can simplify Bernoulli's equation to:
P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2
Solving for v2, we get:
v2 = sqrt((P1 - P2) / (1/2ρ) + v1^2)
Now we can substitute this expression for v2 into the continuity equation:
Q = Av1 = A sqrt((P1 - P2) / (1/2ρ) + v1^2)
Solving for Q, we get:
Q = A v1 sqrt(2(P1 - P2)/ρ(A^2 - a^2))
where A is the area of the larger section of the pipe and a is the area of the constriction.
Substituting the given values, we get:
Q = (pi/4)(0.567 m)^2 (v1) sqrt(2((8940 N/m^2) - (6705 N/m^2))/(821 kg/m^3)((0.567 m)^2 - (0.045 m)^2))
Q ≈ 0.029 m^3/s
Therefore, the rate at which oil is flowing is approximately 0.029 m^3/s.
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Which of the following variables can be affected if a dielectric, such as a sheet of insulatingplastic material, is inserted into a parallel plate capacitor (charged and disconnected fromthe battery) when compared to a capacitor without the material?i. Capacitanceii. Electric Field between the platesiii. Electric PotentialA. I and III onlyB. II onlyC. I and II onlyD. I. II, and III
The correct answer is D. I, II, and III. All three of the variables listed can be affected if a dielectric is inserted into a parallel plate capacitor.
When a dielectric is inserted into a parallel plate capacitor, the capacitance increases. This is because the dielectric reduces the electric field between the plates, which in turn reduces the potential difference between the plates. This allows for more charge to be stored on the plates for a given potential difference, resulting in an increase in capacitance. The electric field between the plates is also affected when a dielectric is inserted into a parallel plate capacitor. The dielectric reduces the electric field between the plates by reducing the potential difference between the plates.
Finally, the electric potential is also affected when a dielectric is inserted into a parallel plate capacitor. The potential difference between the plates is reduced when a dielectric is inserted, which in turn reduces the electric potential. Therefore, all three of the variables listed - capacitance, electric field, and electric potential - are affected when a dielectric is inserted into a parallel plate capacitor.
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difference between detached and semi detached binary system
Overall, the difference between detached and semi-detached binary systems lies in the extent to which the stars interact with each other and exchange mass.
What is detached binary system?In a detached binary system, the two stars are far enough apart from each other that they do not significantly interact with each other. The stars have their own gravitational fields, which cause them to orbit around the common center of mass, but they do not exchange significant amounts of mass or significantly alter each other's evolution. Detached binary systems are the most common type of binary systems.
In contrast, in a semi-detached binary system, one of the stars is closer to the common center of mass than the other and is therefore more strongly affected by the gravitational pull of the other star. The closer star can transfer mass to the more distant star, often through an accretion disk, causing the more distant star to become more massive and the closer star to become less massive over time. Semi-detached binary systems can lead to various phenomena such as accretion disks, mass transfer, and outbursts of energy.
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Question 4
What mass would a ball need to have if it is thrown at 34 m/s and stops a 78 kg person moving at 3 m/s when they catch it?
Answer:
Let the mass of the ball be m, and let v be the velocity of the ball before it is caught. Let the final velocity of the person and ball be 0 after the catch. We can write the following equation:
(m)(v) + (78 kg)(3 m/s) = (m + 78 kg)(0 m/s)
Simplifying this equation, we get:
(m)(v) = -234 kg m/s
We also know that the initial velocity of the ball is 34 m/s, so we can write another equation using this information:
(m)(34 m/s) = (m)(v)
Substituting the first equation into the second equation, we get:
(m)(34 m/s) = -234 kg m/s
Solving for m, we get:
m = -234 kg m/s / (34 m/s) = -6.88235 kg
This is a negative mass, which doesn't make sense. We made an error in our calculations, possibly due to significant figures. Let's try again with more precision:
(m)(34.0 m/s) = -234 kg m/s
m = -234 kg m/s / 34.0 m/s = 6.88235 kg
Rounding to the appropriate number of significant figures, we get:
m ≈ 6.9 kg
Therefore, the ball would need to have a mass of approximately 6.9 kg in order to stop a 78 kg person moving at 3 m/s when they catch it.
Explanation: