Determine the mass of an 80 N dog.

The structure given in question is hydrogen bonding. Hydrogen bonding is a special type of dipole-dipole attraction between molecules.

Hydrogen bond is an electrostatic force of attraction between hydrogen atom which is covalently bound to a more electronegative "donor" atom/ group and another electronegative atom bearing lone pair of electrons— hydrogen bond acceptor.

Hydrogen bonding is a special type of dipole-dipole attraction between molecules and not a covalent bond to hydrogen atom. It results from attractive force between hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom and another very electronegative atom.

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A fungus, is responsible for grey mould (Botrytis cinerea). It affects tomato plants (and other plants) in greenhouses and fields and is a frequent and frequently serious fungal disease.

A structure with glass roof and walls is known as a greenhouse. Tropical flowers and tomatoes are among the plants that are grown in greenhouses. Even in the winter, a greenhouse keeps a comfortable temperature inside. Sunlight enters the greenhouse during the day and heats the air and plants within.

The industry contributes considerably to climate change by emitting more than 3.3 million tonnes of greenhouse gases each year. In general, building greenhouses pollutes the environment and has negative effects. Construction sites contribute to contamination of the air, water, soil, and noise.

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A primary standard for figuring out the concentration of a sodium hydroxide (NaOH) solution is KHP (potassium hydrogen phthalate). The NaOH solution has a molarity of 0.0859 M.

For the reaction between KHP and NaOH, the following chemical equation is balanced:

NaKP + H2O → KHP + NaOH

We can see from the equation that it is balanced that one mole of KHP reacts with one mole of NaOH.

KHP mass divided by its molar mass yields moles of KHP.

0.003007 moles of KHP are equal to 0.614 g/204.22 g/mol.

NaOH volume is 35.01 mL, or 0.03501 L.

Molarity of NaOH is equal to moles of NaOH divided by its volume.

NaOH has a molarity of 0.003007 mol/0.0351 L, or 0.0859 M.

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"Helium is different than other elements with two valence electrons, such as beryllium, because it has a full outer shell of electrons. Helium's electron configuration is 1s², which means its first energy level (or shell) is completely filled with two electrons. This makes helium extremely stable and unreactive with other elements, unlike beryllium, which has two valence electrons in an incomplete outer shell and is more reactive.

In contrast, neon (Ne) also has a full outer shell of electrons, but it has a larger number of electrons in total than helium. Neon's electron configuration is 1s² 2s² 2p⁶, meaning its second energy level is also filled, providing additional stability. Therefore, helium is more similar to neon in terms of its electron configuration and chemical behavior than it is to beryllium, which has a partially-filled outer shell and is more reactive." (ChatGPT, 2023)

The volume of nitrogen gas produced is 1.11 L according to the chemical equation for the interaction between potassium and nitric acid: 2K + 6HNO3 3H2O + 2KNO3 + NH4NO3.

The equilibrium vapour pressure of the material is this partial pressure of vapour in equilibrium above a liquid. Water has a vapour pressure of 0.0313 atm, or 23.8 mm of mercury, at ambient temperature (25 °C; 760 mm Hg = 1 atm).

The volume of nitrogen gas generated can be calculated using the ideal gas law: PV = nRT

To determine how many moles of hydrogen gas were generated:

PV = nRT

n = PV/RT

n = (1.01 atm - 0.0293 atm) * 1.03 L / (0.0821 L·atm/mol·K * 297 K)

n = 0.0392 mol

The balanced chemical equation states that 1 mole of nitrogen gas is created when 2 moles of potassium react. As a result, the amount of nitrogen gas generated is:

n(N2) = 0.5 * n(K)

n(N2) = 0.5 * 3.64 g / 39.10 g/mol

n(N2) = 0.0441 mol

The volume of nitrogen gas created can now be calculated using the ideal gas law once more:

PV = nRT

V = nRT/P

V = 0.0441 mol * 0.0821 L·atm/mol·K * 297 K / (1.01 atm - 0.0293 atm)

V = 1.11 L

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Answer:

The half-life of an isotope is the time taken for half of the original activity to decay.

We know that the isotope decays to 12.5% of its original activity. So, the fraction of the original activity remaining is:

0.125 = 1/2^3

This means that the isotope has undergone three half-lives.

The time taken for three half-lives is:

3 x half-life = 3 x 64.9 h = 194.7 h

Therefore, the half-life of the isotope is:

time/half-life = number of half-lives

64.9 h/half-life = 1

194.7 h/half-life = 3

Solving for half-life:

64.9 h/half-life = 1

half-life = 64.9 h

Therefore, the half-life of the isotope is 64.9 hours.

29.15 g mL Calculate the following and provide the answers rounded off to the correct accuracy.

Accuracy is a measure of how closely a given set of data or results match their expected values. It is a measure of the degree of correctness and precision of a system's output. Accuracy is often expressed as a percentage and can be determined by comparing a system's results to known or accepted values. Accuracy is important in many fields, from scientific research, to medicine, to engineering, to business, and beyond. It is essential for achieving accurate results and making decisions based on reliable data.

The calculation for this problem is (8.12 - 0.9800) g × (3.4501 + 0.16) mL = (7.14 g) × (3.61 mL) = 25.8954 g mL. Rounded off to the correct accuracy, the answer is 29.15 g mL.

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Many impure metals in use in manufacturing, wiring, as well as other applications can be refined by electrometallurgy.

The term "electrometallurgy" refers to a range of technologies used to separate metals from solutions, such as molten salt solutions, or to refine metals through electrochemical dissolution into or deposition out of such solutions.

An important area of metallurgy called electrometallurgy makes use of electricity to refine crude metals acquired by pyrometallurgy, hydrometallurgy, and electrometallurgy as well as to extract metals from leach liquors.

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Answer:

49.6ml

Explanation:

formula: L solution = mols/M

First convert CuNO3 to mols by using its molar mass. 93.56 g

then plug into the formula I gave. 3.90 g CuNO3=0.0417 mols

Answer:

The expected change in freezing point of water can be calculated using the formula:

ΔTf = Kf x molality

Where ΔTf is the change in freezing point, Kf is the freezing point depression constant for water (1.86°C/m), and molality is the molal concentration of the solute (mol of solute/kg of solvent).

Assuming complete dissociation of MgCl2 in water, the molality of the solution can be calculated as:

molality = (1.00 mol MgCl2 / 0.1 kg H2O) = 10.0 mol/kg

Substituting the values into the equation, we get:

ΔTf = (1.86°C/m) x (10.0 mol/kg) = -18.6°C

Therefore, the expected change in the freezing point of water for a 1.00 m MgCl2 solution is -18.6°C.

We need 10.7 g of KClO3 to produce 6.5 g of KCl. Protons and neutrons have approximately the same mass, which is about 1 amu, so the atomic mass of an element is roughly the sum of the number of protons and neutrons in its nucleus.

What is Atomic Mass?

Atomic mass is the mass of an atom of a chemical element. It is usually expressed in atomic mass units (amu) or in grams per mole (g/mol). The atomic mass of an element is determined by the number of protons and neutrons in the nucleus of an atom.

The balanced chemical equation for the reaction of KClO3 producing KCl is:

2KClO3 → 2KCl + 3O2

We can see from the equation that 2 moles of KClO3 produce 2 moles of KCl. We need to calculate how many moles of KCl are produced from 6.5g of KCl, and then use the mole ratio to find the amount of KClO3 needed.

First, we need to convert the mass of KCl to moles:

moles of KCl = mass of KCl / molar mass of KCl

= 6.5g / 74.55 g/mol

= 0.0872 mol

From the balanced equation, we know that 2 moles of KClO3 produce 2 moles of KCl. Therefore, to find the moles of KClO3 needed to produce 0.0872 mol of KCl, we can use the following proportion:

2 mol KClO3 / 2 mol KCl = x mol KClO3 / 0.0872 mol KCl

Solving for x, we get:

x = 0.0872 mol KClO3 x (2 mol KClO3 / 2 mol KCl)

= 0.0872 mol KClO3

Finally, we can convert the moles of KClO3 to grams using its molar mass:

mass of KClO3 = moles of KClO3 x molar mass of KClO3

= 0.0872 mol x 122.55 g/mol

= 10.7 g

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Answer: To balance the equation (NH4)3PO4(aq) + MgCl2(aq) → Mg3(PO4)2(s) + NH4Cl(aq), you need to ensure that the number of atoms of each element is equal on both sides of the equation.

Start by counting the number of atoms of each element on both sides:

Left side: (NH4)3PO4(aq) + MgCl2(aq)

3 nitrogen atoms (N)

12 hydrogen atoms (H)

1 phosphorus atom (P)

4 oxygen atoms (O)

1 magnesium atom (Mg)

2 chlorine atoms (Cl)

Right side: Mg3(PO4)2(s) + NH4Cl(aq)

3 magnesium atoms (Mg)

2 phosphorus atoms (P)

8 oxygen atoms (O)

4 nitrogen atoms (N)

1 chlorine atom (Cl)

1 hydrogen atom (H)

The equation is not balanced as the number of atoms of some elements are not equal on both sides. To balance the equation, you can follow these steps:

Balance the number of nitrogen atoms by putting a coefficient of 3 in front of NH4Cl:

(NH4)3PO4(aq) + MgCl2(aq) → Mg3(PO4)2(s) + 3NH4Cl(aq)

Balance the number of hydrogen atoms by putting a coefficient of 12 in front of Mg3(PO4)2:

(NH4)3PO4(aq) + MgCl2(aq) → 3Mg3(PO4)2(s) + 3NH4Cl(aq)

Balance the number of chlorine atoms by putting a coefficient of 2 in front of MgCl2:

(NH4)3PO4(aq) + 2MgCl2(aq) → 3Mg3(PO4)2(s) + 3NH4Cl(aq)

The final balanced equation is:

(NH4)3PO4(aq) + 2MgCl2(aq) → 3Mg3(PO4)2(s) + 3NH4Cl(aq)

Brainliest is appericated this took me a while.  (:

Explanation:

When water is added to 2 moles of sodium chloride to make 0.5 liters, the molarity is 4M.

1. The molarity of a solution is 1 M when 1 mole of sodium chloride is dissolved in 1 liter of water. This is because molarity is defined as the number of molecules of a solute (in this case, sodium chloride) added to the liter of treatment solution. The molarity is 1 M because we have 1 mole of sodium chloride in 1 liter of solution.

2. The molarity of a solution is 4 M when 2 moles of sodium chloride are dissolved in 0.5 liters of water. This is because we have twice as many moles of sodium chloride as in the previous case but only half the volume of water. As a result, the concentration of sodium chloride in the solution is doubled,  resulting in a molarity of 4 M.

Mathematically, we can calculate the molarity as follows:

Molarity = the number of moles of solution mass in liters.

In this case, we have 2 moles of Sodium chloride, and its mass is 0.5 liters:

Molarity = 2 moles / 0.5 liters = 4 M

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the value of the rate constant k is 0.00734 s^-1.

What is the first-order integrated rate law, and how can it be used to determine the rate constant k?

ln[A]t = -kt + ln[A]0

Where [A]t is the concentration of A at time t, [A]0 is the initial concentration of A, k is the rate constant, and ln represents the natural logarithm.

We can rearrange the equation to solve for k:

k = (ln[A]0 - ln[A]t) / t

Plugging in the values given in the problem:

[A]0 = 0.165 M

[A]t = 0.111 M

t = 116 s

k = (ln[0.165] - ln[0.111]) / 116 s

Using a calculator, we get:

k = 0.00734 s^-1

Therefore, the value of the rate constant k is 0.00734 s^-1.

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Demand for the environmental assets utilized to produce a synthetic materials rises in tandem with that demand. Obtaining the resources necessary to produce a synthetic material occasionally results in significant changes in that ecosystem.

Natural resources like wood & sand are used to make "natural" items. Natural resources are also used to make "synthetic" products. For instance, petroleum that is extracted from the soil is used to make synthetic materials like plastic. Natural resources include petroleum.

For instance, toxins from manufactured products can leak into the environment and kill wildlife or poison water sources. Synthetic products can also consume more resources then natural ones, which can have a negative impact on the environment in such a number of ways, including by accelerating climate change.

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The electronegativity difference between C (carbon) and F (fluorine) is approximately 1.5.

Electronegativity is a measure of an atom's ability to attract electrons towards itself when it is part of a chemical bond. Fluorine is the most electronegative element on the periodic table, with an electronegativity value of 4.0, while carbon has an electronegativity value of 2.5.

The electronegativity difference between two atoms in a bond determines the polarity of the bond and the distribution of electrons within the molecule. In the case of C and F, the bond is polar covalent, with the electron density being pulled more towards the fluorine atom due to its higher electronegativity.

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The chemical MgCl2 has the highest lattice energy of the ones listed. This occurs as a result of the Mg2+ ion's greater charge density compared to the Na+, Rb+, and Ca2+ ions.

More lattice energy results from smaller ions, stronger charges, and larger charges. AlN has the highest lattice energy as a result.

Higher charged ions and closer spaced ions have higher lattice energies. The Born-Haber cycle, which incorporates all of the energy stages required to transform elements into an ionic molecule, is frequently used to compute lattice energies.

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As voltages is a potential in relation to a reference, one probe must be on the reference or "zero" planes and the other must be on the point being measured.

because the voltmeter uses some of the main circuit's current. Main present in the circuit diminishes as a result, and the voltmeter's reading of the potential difference does not correspond to its true value.

Nothing is measured at a specific point by the voltmeter. It gauges the voltage (V) differential between two circuit locations. Thus, a multimeter has two leads rather than one.

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acid can kill and decay bodies if your needing to get rid of human remains

Answer:

a. At STP, the temperature is 273 K and the pressure is 101.3 kPa. Therefore, the number of moles of helium gas present in a 3.0 L balloon at STP is:

n = PV/RT = (101.3 kPa)(3.0 L) / (8.31 J/K/mol)(273 K)

n = 0.1209 mol

b. To solve for the number of moles of helium gas at a different temperature and pressure, we need to use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we convert the temperature to Kelvin: T = 33°C + 273 = 306 K

Then we can solve for n:

n = PV/RT = (99.5 kPa)(3.0 L) / (8.31 J/K/mol)(306 K)

n = 0.109 mol

c. The number of moles of oxygen consumed by the man can be found using the ideal gas law:

n = PV/RT

We are given the pressure, volume, and temperature, so we can plug those in and solve for n. However, we need to convert the volume from L to m3 and the pressure from kPa to Pa:

V = 14 L = 0.014 m3

P = 100.0 kPa = 100000 Pa

T = 25°C + 273 = 298 K

n = PV/RT = (100000 Pa)(0.014 m3) / (8.31 J/K/mol)(298 K)

n = 0.006 mol

Therefore, the man consumes 0.006 moles of oxygen per hour.

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Answer:

The resonense structures as follows:

Explanation:

Refer to the image attached for the full answer.

Answer: 8.824 g/cm³

Explanation: To find the density of the piece of metal, we must divide the mass by the volume of the metal. To find the metal's volume, we subtract the initial volume from the total volume.

Volume of metal = Final Volume - Initial Volume

Volume of metal = 9.90 - 6.45

Volume of metal = 3.45 cm³

Now, we can implement the metal's volume into the division process to find the density:

Density = 30.4571 ÷ 3.45

Density = 8.824 g/cm³

Hence, the density of the piece of metal is 8.824 g/cm³.

Answer:

1) Ethoxyethane can be prepared from ethene by the reaction of ethene with ethanol in the presence of a catalyst such as sulfuric acid. This is an example of an addition reaction.

Equation:

C2H4 + C2H5OH → C4H10O (ethoxyethane)

2) Propanoic acid can be prepared from prop-1-ene by the reaction of prop-1-ene with potassium permanganate (KMnO4) in the presence of water. This is an example of an oxidation reaction.

Equation:

CH2=CHCH3 + 2KMnO4 + 3H2O → CH3CH2COOH (propanoic acid) + 2MnO2 + 2KOH

3) The order of increasing boiling points is: butane < butan-2-ol < butan-2-one < butanoic acid.

Butane is a nonpolar molecule and has only weak London dispersion forces between its molecules, so it has the lowest boiling point.

Butan-2-ol has a polar hydroxyl group (-OH) which allows for hydrogen bonding between its molecules, increasing its boiling point compared to butane.

Butan-2-one has a polar carbonyl group (C=O) which also allows for dipole-dipole interactions between its molecules, increasing its boiling point compared to butan-2-ol.

Butanoic acid has a polar carboxyl group (-COOH) which allows for hydrogen bonding between its molecules, making it the most polar and highest boiling compound among the given options.

The molecular formula of glucose is C6H12O6, which means it contains 6 carbon atoms.

To calculate the mass of carbon in 100g of glucose, we can use the molar mass of glucose and the molar mass of carbon to find the mass fraction of carbon in glucose:

The molar mass of glucose (C6H12O6) is 180.16 g/mol (6 carbon atoms x 12.01 g/mol + 12 hydrogen atoms x 1.01 g/mol + 6 oxygen atoms x 16.00 g/mol).

The molar mass of carbon is 12.01 g/mol.

The mass fraction of carbon in glucose is:

(6 carbon atoms x 12.01 g/mol) / (1 molecule of glucose x 180.16 g/mol) = 0.4

This means that 40% of the mass of glucose comes from carbon. Therefore, in 100g of glucose, there would be:

100g x 0.4 = 40g of carbon.

So, there are 40 grams of carbon in 100g of glucose.

Answer:

The molar mass of BeSO4 is:

9 + 32 + (4x16) = 137 g/mol

To calculate the volume of a 9 M solution containing 90 grams of BeSO4, we can use the formula:

moles = mass / molar mass

moles = 90 g / 137 g/mol

moles = 0.657 g

Then, we can use the formula:

M = moles / volume (in liters)

Rearranging this formula, we get:

volume (in liters) = moles / M

volume (in liters) = 0.657 / 9

volume (in liters) = 0.073 L

Finally, we convert the volume from liters to milliliters:

volume (in mL) = 0.073 L x 1000 mL/L

volume (in mL) = 73 mL

Therefore, the answer is not one of the choices provided. The closest option is C) 77 mL.

Answer: Chemical reactions involve breaking chemical bonds between reactant molecules (particles) and forming new bonds between atoms in product particles (molecules). The number of atoms before and after the chemical change is the same but the number of molecules will change.

Answer:

Mass and volume are extensive properties because they depend on the size or amount of matter present in a system. For example, if we double the amount of a substance, its mass and volume will also double. Extensive properties are additive and their value changes with the size or amount of the system.

On the other hand, density is an intensive property because it does not depend on the amount of matter present in a system, but only on its composition and physical state. Density is defined as the mass of a substance per unit volume, which means that for a given substance, the density will always be the same regardless of the size or amount of the sample. Intensive properties are not additive and their value is independent of the size or amount of the system.

The calculated molarity of Br is 0.0093 mol/L. Molarity is the number of moles of solute per one liter of solution

Mol FeBr2 = mass / molar mass

= 0.30 g / 215.65 g/mol

= 0.00139 mol

Each mol FeBr2 has two mol Br- anions , so mol Br- ions here will be :

= 2 x 0.00139 mol

= 0.00278 mol

Molarity of Br- anions = mol / volume (L)

= 0.00278 mol / 0.300 L

= 0.0093 mol/L

Molarity (M) is the most common way to describe the concentration of a solution. Molarity is calculated by dividing the volume of the solution in liters by the molecular weight of the solute: M is equal to moles of solute per liter of solution.

One of the most common units used to measure a solution's concentration is molarity. A solution's molarity is useful because it tells you not only whether it has been diluted or concentrated, but also its actual concentration.

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