Answers
Explanation: Let's consider two things
- Domain = represented by the minimum and maximum x-values
- Range = represented by the minimum and maximum y-values
Step 1: Let's take a look at the picture below
As we can see above
max x-value = + ∞
min x-value = - ∞
max y-value = 4
min y-value = - ∞
Final answer: So the final answer is
[tex]\begin{gathered} \text{domain}\Rightarrow(-\infty,+\infty) \\ \text{range}\Rightarrow(-\infty,4) \end{gathered}[/tex].
Related Questions
On December 13, 2007, one South African rand was worth 0.15 U.S. dollars.(a) On that date, how many rand was 44.11 dollars worth?Round your answer to the nearest hundredth of a rand.rand(b) On that date, how many dollars was 168.18 rand worth?Round your answer to the nearest hundredth of a dollars. I need help with this math problem.
Answers
Explanation
Part A
Given that one South African rand was worth 0.15 U.S. dollars. 44.11 dollars will be worth
[tex]\frac{44.11}{0.15}=294.07[/tex]Answer: 294.07 rands
Part B
On that date, how many dollars was 168.18 rand worth?
[tex]168.18\times0.15=25.23[/tex]Answer: 25.23 dollars
Lincoln made 3 quarts of iced tea and Jasmine made 5 quarts of iced tea using the same recipe. Part A: How many cups of iced tea did Lincoln and Jasmine make all together? cho mark
Answers
Part A
number of ice tea lincoln made = 3 quarts
number of ice tea jasmine made = 5 quarts
Altogether we have = 8 quarts
But, there are four cups in 1 quart
Therefore, 8 quarts would give 8 x 4 cups = 32 cups
In conclusion, jasmine and lincoln made 32 cups of ice tea altogether.
Part B
There are 16 cups in one gallon
Lincoln and jasmine made 32 cups of ice tea
Therefore the number of gallons of ice tea they made is
=32/16 = 2gallons
Also, 1/2 bottle = 1 gallon
Therefore, the 2 gallons would give
[tex]\begin{gathered} =\frac{2}{\frac{1}{2}}=\frac{2}{0.5}=4 \\ \end{gathered}[/tex]Therefore the 2 gallons would give 4 bottles of ice tea
A rectangular vegetable garden will have a width that is 3 feet less than the length, and an area of 54 square feet. If x
represents the length, then the length can be found by solving the equation:
x(x-3) = 54
What is the length, x, of the garden?
The length is
feet.
The solution is?
Answers
To determine the length of the rectangular flower garden, we need to derive equations from the given measurements and relations. The given measurements are the area, and the relation of the width and the length. From these, we generate the equation needed. We do as follows:
Area = Length x Width
where length = x ft
width = x - 3 ft
area = 54 ft^2
54 ft^2 = x ft (x -3) ft
54 ft^2 = x^2 - 3x ft^2
Solving for the value of x, we will have two values which are
x = -6 ft ( NOTE: this value can't be the answer since we cannot have a negative value for the length)
x = 9 ft = length
How far is the girl from the monument that is 30 ft high? Round your answer to a nearest foot. Show your work.
Answers
Given:
The diagram is shown alongside.
The height of the monument is 30 ft high.
The angle of elevation is 63 degrees
The objective is to find the distance between the monument and where the girl is standing.
Since it forms a right angled triangle so we can apply trigonometric ratios:
Now,
[tex]\tan 63^{\circ}=\frac{perpendicular}{\text{base}}[/tex]Perpendicular = 30 ft
Base = ?
Substituting the values,
[tex]\begin{gathered} \tan 63^{\circ}=\frac{30}{\text{base}} \\ \text{Base}=\frac{30}{\tan63^{\circ}} \\ \text{base}=\frac{30}{1.962610} \\ \text{base}=15.285767422\text{ ft} \end{gathered}[/tex]Therefore, the girl is at a distance of 15 ft from the monument.
Which table shows a proportional relationship between miles traveled and gas used?
Miles Traveled Gas Used
27.3 mi 1.5 gal
49.16 mi 3.8 gal
Miles Traveled Gas Used
120 mi 6.2 gal
180 mi 12.2 gal
Miles Traveled Gas Used
135 mi 7.4 gal
135.5 mi 7.9 gal
Miles Traveled Gas Used
270 mi 15 gal
135 mi 7.5 gal
Answers
Answer:
D
Step-by-step explanation:
270mi 15gal
135mi 7.5gal
135/270=0.5
7.5/15=0.5
or
135/7.5=18
270/15=18
all you need is in the photo I DON'T WANT STEP BY STEP ANSWER FAST please fdsd
Answers
We have the following:
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ a=5 \\ b=0 \\ c=-80 \end{gathered}[/tex]replacing:
[tex]\begin{gathered} x=\frac{-0\pm\sqrt[]{0^2-4\cdot5\cdot-80}}{2\cdot5}=\frac{\pm\sqrt[]{1600}}{10}=\frac{\pm40}{10}=\pm4 \\ x_1=4 \\ x_2=-4 \end{gathered}[/tex]You are a landscaper working on the design of a parking lot in a new shopping center. You are measuring the length of a grass median that will be exactly as long as four parking spots and their dividing lines. One of these spots is a handicapped spot, which is 1018 feet wide and next to the curb. The other three spots are 838 feet wide. There are four dividing lines between the spots, and each measures 18 foot. What is the length of the grass median, D?
Answers
SOLUTION
From the given information:
one of the spots is
[tex]10\frac{1}{8}ft[/tex]Other three spots are
[tex]8\frac{3}{8}ft\text{ wide}[/tex]There are four dividing line of
[tex]\frac{1}{8}\text{foot}[/tex]The total length of the grass median is:
[tex]10\frac{1}{8}+3(8\frac{3}{8})+4(\frac{1}{8})[/tex]Calculate the value
[tex]\begin{gathered} \frac{81}{8}+3(\frac{67}{8})+\frac{4}{8} \\ =\frac{81}{8}+\frac{201}{8}+\frac{4}{8} \\ =\frac{81+201+4}{8} \\ =\frac{286}{8} \end{gathered}[/tex]Reduce the fraction
[tex]\frac{286}{8}=35\frac{6}{8}=35\frac{3}{4}[/tex]Therefore the length of the grass median is
[tex]35\frac{3}{4}[/tex]a diver takes a dive in the red sea. He initially descends 100 feet. Then rises 28 before descending another 33. What is his final position
Answers
Descending: subtraction
Rises: Addition
The diver descends 100ft: Position -100 (the 0 is the sea level)
Then rises 28: Add 28 to the previous position: Position -72
[tex]-100+28=-72[/tex]...before descending another 33: Subtract 33 to the previous position:
[tex]-72-33=-105[/tex]Then, the final position is -105ft (105 ft under the sea level)
Evaluate the expression shown below and write your answer as a fraction in
simplest form.
-3/8+(-9/10)
Answers
Answer:
-1 11/40
Step-by-step explanation:
-51/40 this is simplest form.
Step-by-step explanation:
is it true that all whole numbers are rational numbers ? why or why not
Answers
all whole numbers are rational numbers
because we can write 21 as 21/1 in rational form.
.
We can write any whole number (a) into the form of
[tex]\frac{a}{b}[/tex]where b = 1,
so all whole numbers can be written in form of rational numbers.
0.25(60) + 0.10x = 0.15(60 + x)
Answers
Answer: X = 120
Step-by-step explanation:
lol:
V = (−∞,∞)
X = 120
What is the slope of this line? :(
Answers
Answer:
y=1/4x+1
Step-by-step explanation:
Answer:
m=1/4
Step-by-step explanation:
Got it correct
Evaluate h(x) at x = 6, x = 8, and x= 12. h(x)=1.31^×
Answers
Answer : h(6) = 5.054
h(8) = 8.673
h(12) = 25.542
Given that h(x) = 1.31^x
[tex]\begin{gathered} h(x)=1.31^x \\ \text{ find the value of h(6) when x = 6} \\ h(6)=1.31^6 \\ h(6)\text{ = 5.05}4 \\ \text{when x = 8} \\ h(8)=1.31^8 \\ h(8)\text{ = 8.67}3 \\ \text{when x = 12} \\ h(12)=1.31^{12} \\ h(12)\text{ = 25.54}2 \end{gathered}[/tex]Therefore,
h(6) = 5.054
h(8) = 8.673
h(12) = 25.542
4 ft 12 ft The pitch of the roof is
Answers
As shown : in the figure
The pitch of the roof is the angle between the roof and the horizontal line
As shown we have a right angle triangle
The opposite side to the angle = 4 ft
And the adjacent side to the angle = 12 ft
According to the given sides, we will calculate the angle using tan function
So, let the angle = x
So,
[tex]\begin{gathered} \tan x=\frac{opposite}{adjacent} \\ \\ \tan x=\frac{4}{12}=\frac{1}{3} \\ \\ x=\tan ^{-1}\frac{1}{3}\approx18.435^o \end{gathered}[/tex]So, the pitch angle of the roof = 18.435
instead of writing the angle , just we will write the slope = rise/run
So, the pitch of the roof = 1/3
if sound travels at 335 miles per second through air and a plane is 2680 miles away how long will the sound take to reach the people
Answers
It will take 8 seconds for the sound to reach the people
Here, we want to calculate time
Mathematically;
[tex]\begin{gathered} \text{time = }\frac{dis\tan ce}{\text{speed}} \\ \end{gathered}[/tex]With respect to this question, distance is 2680 miles while speed is 335 miles per second
Substituting these values, we have;
[tex]\text{time = }\frac{2680}{335}\text{ = 8}[/tex]point).
Questions
1. (1) How many observations are collected? (2) How many variables are collected? (3) write
I
down quantitative variables (4) write down qualitative variables
2. Describe the data visually
2.1.(1) Make a frequency tables and histogram for the “Hour” variable (bin limit = 1), and (2)
describe the shapes of the histogram
2.2.(1) Make a frequency tables and histogram for the “Type” variable, and (2) prepare a 2-D
pie chart and write down the title of chart
2.3.(1) Make a frequency tables and histogram for the “Weekday” variable, and (2) prepare a 2-
D pie chart and write down the title of chart
2.4.(1) Make a frequency tables and histogram for the “Location” variable, and (2) prepare a 2-D
pie chart and write down the title of chart
2.5.(1) Make a scatter plot of the data for the “Time” and “Hour variables, placing “Hour" on the
X-axis and "Time" on the Y-axis. Add titles and modify the default colors, fonts, etc., to make
the scatter plot easy to understand. (2) Describe the relationship (if any) between X and Y.
Weak? Strong? Negative? Positive? Linear? Nonlinear?
2.6.(1) Make a dot plot of the “Hour" variable for the “Deposit Type" variable. (2) Make a dot
plot of the "Hour" variable for the "Withdraw Type” variable. (3) Compare the shapes of both
charts
Answers
1). 68 observations
1.2) 8 variables
1.3) Quantitative Variables: Type, Time, Date, DayCode, Hour, and Amount
1.4) Qualitative Variables: Location, Weekday
Question 1) Let's examine that table to find out the number of collected observations. Counting each row, we have 68 observations. Each one informing the type, time, date, day code, weekday, Location, Hour, and Amount
1.2) We have then 8 variables namely (type, time, date, day code, weekday, Location, Hour, and Amount)
1.3) The Quantitative Variables are the ones whose entries are numerical, so examining then we can state that:
Type, Time, Date, DayCode, Hour, and Amount each and every one of them receives a numerical entry.
1.4) Qualitative or Categoricals variables are the ones whose entry is not a numerical one. So we can enlist the following ones as Qualitative:
Location
Weekday
Hence the answers are:
1). 68 observations
1.2) 8 variables
1.3) Quantitative Variables: Type, Time, Date, DayCode, Hour, and Amount
1.4) Qualitative Variables: Location, Weekday
question: determine whether the function is one-to-one. If it is sketch the graph of its inverse.i already found out it is a one-to-one, i just don't know how to graph its inverse
Answers
The inverse function of f(x) = y is f(y) = x
This means, switch the coordinates of the points of the graph
If we choose a point on the given graph like (5, 3) it will be (3, 5) in the inverse function
Also, point (-5, -3) it will be (-3, -5) in the inverse function
You can plot them with point (0, 0) and draw the curve
Let me try to show it
It will be like that
after a translation 8 units left
Answers
The given transformation is 8 units left.
The pre-image vertices are A(1,-4), B(1,-6), C(5,-6), and D(5,-4).
Using the transformation, we have:
[tex]\begin{gathered} A^{\prime}(1-8,-4)=A^{\prime}(-7,-4) \\ B^{\prime}(1-8,-6)=B^{\prime}(-7,-6) \\ C^{\prime}(5-8,-6)=C^{\prime}(-3,-6) \\ D^{\prime}(5-8,-4)=D^{\prime}(-3,-4) \end{gathered}[/tex]The image below shows the graph of the image
The Lyon Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United States. For 186 restaurants located in Boston, the average price of a dinner, including one drink and tip, was 48.60 Dollars. You are leaving on a business trip to Boston and will eat dinner 23 of these restaurants, randomly selected. Your company will reimburse you for a maximum of 50 dollars per dinner. Business associates familiar with these restaurants have told you that the meal cost at one-third of these restaurants will exceed 50 dollars.
a. What is the probability that none of the meals will exceed the cost covered by your company?
b. What is the probability that at most 12 of the meals will exceed the cost covered by your company? What is the probability that between 4 and 8 of the meals will exceed the cost covered by your company?
c. Calculate the expected number of restaurants that will exceed the cost covered by your company.
d. Calculate the probability of the first question by using the binomial distribution approximation. Therefore, in this case we will consider the possibility of repetition in the randomly selected restaurants. Define p=r/N as the success probability.N is the size of the population. r is the number of elements considered as successes in the population.
e. Calculate the probability of the second question by using the binomial disribution approximation.
f. Calculate the probability of the third question by using the binomial disribution approximation.
g. Calculate the expected number of the fourth question by using the binomial disribution aproximation
Answers
Using the binomial distribution, the probabilities are given as follows:
a. None: 0%.
b.
At most 12: 0.9814 = 98.14%.Between 4 and 8: 0.6249 = 62.49%.c. The expected number of restaurants that will exceed the cost covered by your company is of 7.67.
Using the normal approximation, the probabilities are:
a. None: 0.0008 = 0.08%.
b.
At most 12: 98.38 = 98.38%.Between 4 and 8: 0.6121 = 61.21%.The difference in these probabilities is due to the small sample size.
Binomial distributionThe formula for the probability of x successes is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In which the parameters are given by:
n is the number of trials of the experiment.p is the probability of a success on a single trial of the experiment.Considering that you will eat dinner at 23 restaurants, and at around one-third of them the meal cost will exceed 50 dollars, the values of these parameters are given as follows:
n = 23, p = 1/3 = 0.3333.
The probability that none will exceed is P(X = 0), hence:
P(X = 0) = (1 - 0.3333)^23 = 0% (rounded).
The probability of at most 12 is:
P(X <= 12) = P(X = 0) + P(X = 1) + ... + P(X = 12).
Using a binomial distribution calculator with the given parameters, the probability is:
P(X <= 12) = 0.9814 = 98.14%.
The probability that between 4 and 8 dinners are paid is:
P(4 <= X <= 8) = P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)
Using a calculator, or the mass function P(X = x) and adding each probability, the desired probability is:
P(4 <= X <= 8) = 0.0493 + 0.0937 + 0.1405 + 0.1707 + 0.1707 = 0.6249 = 62.49%.
Normal approximationThe first step for the normal approximation is finding the mean and the standard deviation, as follows:
Mean = expected number: [tex]\mu = np = 23 \times 0.3333 = 7.67[/tex]Standard deviation: [tex]\sigma = \sqrt{np(1-p) = \sqrt{23 \times 0.3333 \times 0.6667} = 2.26[/tex]The probability of none, using continuity correction, is P(X < 0.5), which is the p-value of Z when X = 0.5, hence:
(the p-value of Z is found using the z-score table).
[tex]Z = \frac{X - \mu}{\sigma}[/tex] (z-score formula)
Z = (0.5 - 7.67)/2.26
Z = -3.17
Z = -3.17 has a p-value of 0.0008.
Hence the probability is 0.0008 = 0.08%.
The probability of at most 12 is P(X <= 12.5), using continuity correction, which is the p-value of Z when X = 12.5, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (12.5 - 7.67)/2.26
Z = 2.14
Z = 2.14 has a p-value of 0.9838.
Hence the probability is of 98.38 = 98.38%.
The probability of between 4 and 8 dinners being paid is P(3.5 <= X <= 8.5), which is the p-value of Z when X = 8.5 subtracted by the p-value of Z when X = 3.5, hence:
X = 8.5:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (8.5 - 7.67)/2.26
Z = 0.37
Z = 0.37 has a p-value of 0.6443.
X = 3.5:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
Z = (3.5 - 7.67)/2.26
Z = -1.85
Z = -1.85 has a p-value of 0.0322.
Hence the probability is:
0.6443 - 0.0322 = 0.6121 = 61.21%.
More can be learned about the binomial distribution at https://brainly.com/question/24756209
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Triangle BCA is similar to Triangle STR . What is the value of x?
Answers
Sin the triangles are similar the ratio 4 to 6 should hold for any side, this means that:
[tex]\frac{4}{6}=\frac{x}{9}[/tex]Solving for x we have:
[tex]\begin{gathered} \frac{4}{6}=\frac{x}{9} \\ x=9(\frac{4}{6}) \\ x=\frac{36}{6} \\ x=6 \end{gathered}[/tex]Therefore. x=6.
find the volume and total surface area of a right circular cone whose base diameter is 10 cm and whose altitude is 20 cm.
Answers
SOLUTION
Given the question in the question tab, the following are the solution steps to calculate the required measurements.
Step 1: write the given parameters
[tex]\begin{gathered} \text{diameter}=10\operatorname{cm},\text{altitude}=\text{height}=20\operatorname{cm} \\ r=\frac{d}{2}=\frac{10}{2}=5\operatorname{cm} \end{gathered}[/tex]Step 2: Calculate the volume of the right circular cone
[tex]\begin{gathered} V=\frac{\pi r^2h}{3} \\ V=\frac{\pi\times5\times5\times20}{3} \\ V=\frac{500\pi}{3}=523.5987756 \\ V\approx523.5988\operatorname{cm}^3 \end{gathered}[/tex]Step 3: Calculate the total surface area of the right circular cone
[tex]\begin{gathered} \text{TSA}=\pi r(r+\sqrt[]{h^2+r^2)} \\ \text{TSA}=\pi(5)(5+\sqrt[]{20^2+5^2)} \\ \text{TSA}=5\pi(5+\sqrt[]{400+25)} \\ \text{TSA}=5\pi(5+\sqrt[]{425})=5\pi(5+20.61552813) \\ \text{TSA}=5\pi(25.615528134) \\ \text{TSA}=402.3677749 \\ \text{TSA}\approx402.3678cm^2 \end{gathered}[/tex]Hence, the volume and the total surface area of the given right circular cone are approximately 523.5988cm³ and 402.3678cm² respectively
Below, the two-way table is given for aclass of students.Freshmen Sophomore Juniors Seniors TotalMale 462. .Female 33246TotalIf a student is selected at random, find theprobability the student is a junior. Roundto the nearest whole percent.
Answers
The final answer is: 27%
We are asked to find the probability that a student chosen at random is a junior. This requires that we know the total number of students in each level from Freshmen to Seniors.
Totals:
Freshmen = 4 + 3 = 7
Sophomore = 6 + 4 = 10
Juniors = 2 + 6 = 8
Seniors = 2 + 3 = 5
Thus we can calculate the total number of students considered:
7 + 10 + 8 + 5 = 30 students in total.
Now we can calculate the probability as:
[tex]\begin{gathered} P(\text{choosing juniors) = }\frac{Number\text{ of Juniors}}{\text{Total Number of Students}} \\ \end{gathered}[/tex]The number of Juniors was calculated earlier as: Juniors = 8
We have the total number of students as 30
Therefore, we can solve:
[tex]P(\text{choosing juniors)=}\frac{8}{30}=\frac{4}{15}[/tex]But we were asked to round to the nearest whole percent, which means we are required to put the fraction into percentage.
The way we do this is to multiply the fraction by 100%
[tex]\begin{gathered} \frac{4}{15}\times100=26.6667. \\ \\ \therefore P(\text{choosing juniors)=27\% (to the nearest whole percent)} \end{gathered}[/tex]Therefore the final answer is: 27%
A company charges $7 dor a t-shirt and ships any order for $22 a school principal ordered a number of t-shirts for the school store the total cost of the order was 1,520 how many t-shirts did the principal buy
Answers
the equation is
[tex]7x+22=1520[/tex]then solve for x
[tex]\begin{gathered} 7x+22-22=1520-22 \\ 7x=1498 \\ \frac{7x}{7}=\frac{1498}{7} \\ x=214 \end{gathered}[/tex]answer: the principal bought 214 t-shirts
If 200 is added to a positive integer I, the result is a square number. If 276 is added to to the same integer I, another square number is obtained. Find I.
Answers
Solution:
[tex]\begin{gathered} Let\text{ } \\ 200\text{ + I= x}^2----------\left(1\right) \\ 276+I\text{ =y}^2----------\left(11\right) \\ Subtract\text{ equation \lparen1\rparen from equation \lparen11\rparen} \\ 276+1-\left(200_+I\right?=y^2-x^2 \\ 76=\left(y-x\right?\left(y+x\right? \end{gathered}[/tex]Now y+x and y-x differ in 2x.
One of them is even, because their product is even, so the other must be even too.
76=2*2*19 and 19 is prime.
We can assume x,y>=0,
Thus, y+x=2.19, and y-x=2
from here y=20, x=18
Therefore,
[tex]\begin{gathered} 200+1=18^2 \\ 200+I=324 \\ I=324-200 \\ I=124 \end{gathered}[/tex]The answer is I = 124
Based on a recent study, the pH level of the arterial cord (one vessel in the umbilical cord) is normally distributed with mean 7.38 and standard deviation of 0.14. Find the percentageof preterm infants who have the following arterial cord pH levels.a. pH levels between 7.00 and 7.50.b. pH levels over 7.46A.The percentage of arterial cord pH levels that are between 7.00 and 7.50 is ____%.(Round to two decimal places as needed.)B.The percentage of arterial cord pH levels that are over 7.46 is ___%.(Round to two decimal places as needed.)
Answers
We have the pH level as a random normal variable with mean 7.38 and standard deviation of 0.14.
A) We have to calculate the percentage of infants that are expected to have pH levels between 7.00 and 7.50.
We can approximate this as the probability of selecting a random infant and it has a pH level within this interval.
Then, to calculate the percentage we will use the z-scores for each boundary of the interval:
[tex]z_1=\frac{X_1-\mu}{\sigma}=\frac{7-7.38}{0.14}=\frac{-0.38}{0.14}\approx-2.7143[/tex][tex]z_2=\frac{X_2-\mu}{\sigma}=\frac{7.5-7.38}{0.14}=\frac{0.12}{0.14}\approx0.8571[/tex]Then, we can use the standard normal distribution to look for the probabilities for each z-score and calculate the probability as:
[tex]\begin{gathered} P(7.00Given that the probability is 0.80099, we can express the percentage as:[tex]P=0.80099\cdot100\%=80.01\%[/tex]B) We now have to calculate the percentage that is above 7.46.
We start by calculating the z-score as:
[tex]z=\frac{X-\mu}{\sigma}=\frac{7.46-7.38}{0.14}=\frac{0.08}{0.14}\approx0.571428[/tex]Then, we can calculate the probability as:
[tex]P(X>7.46)=P(z>0.571428)\approx0.28385[/tex]This correspond to a percentage of 28.39%.
Answer:
A) 80.01%
B) 28.39%
JCPenney sells jeans for $49.50 that cost $38.00. What is the percent markup on cost? Check the cost. (Round your answer to the nearest hundredth percent.)
Answers
The percent mark up on the cost is 30.26%.
How to find the percent mark-up on cost?JCPenney sells jeans for $49.50 that cost $38.00.
The percent mark up can be calculated as follows:
Mark up percentage is calculated by dividing the gross profit of a unit by the cost of that unit.
In other words, Mark-up percentage is the difference between a product's selling price and cost as a percentage of the cost.
Hence,
selling price = $49.50
cost price = $38.00
mark up = 49.50 - 38 = 11.5
Therefore,
percent mark up = 11.5 / 38 × 100
percent mark up = 1150 / 38
percent mark up = 30.2631578947
Therefore,
percent mark up = 30.26%
learn more on percent mark up here: brainly.com/question/12284542
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Write these numbers from least to greatest: 0, -6.1, 4, 10/2
Answers
Answer:
10/2, 4, 0, -6.1
Step-by-step explanation:
It is the only answer that makes sense.
pls mark brainliest
Answer: -6.1, 0, 4 , 10/2
Step-by-step explanation:
-6.1 is the only negative number, so it is the least. Zero comes next. 10/2 is 5, so 4 comes before it. Therefore 4 is the 3rd installment in these ordered numbers.
A convenience store manager notices that sales of soft drinks are higher on hotter days, so he assembles the data in the table. (a) Make a scatter plot of the data. (b) Find and graph a linear regression equation that models the data. (c) Use the model to predict soft-drink sales if the temperature is 95°F.
Answers
ANSWER and EXPLANATION
a) First we have to make a scatter plot. We do this by plotting the calues of High Temperature on the x axis and Number of cans sold on the y axis:
b) We want to find and graph the linear regression equation that models the data.
The linear regression equation will be in the form:
y = a + bx
[tex]\begin{gathered} \text{where} \\ a\text{= }\frac{(\sum ^{}_{}y)(\sum ^{}_{}x^2)\text{ - (}\sum ^{}_{}x)(\sum ^{}_{}xy)}{n(\sum ^{}_{}x^2)\text{ }-\text{ (}\sum ^{}_{}x)^2} \\ \text{and b = }\frac{n(\sum ^{}_{}xy)\text{ - (}\sum ^{}_{}x)(\sum ^{}_{}y)}{n(\sum ^{}_{}x^2)\text{ }-\text{ (}\sum ^{}_{}x)^2} \end{gathered}[/tex]We have from the question that:
x = High Temperature
y = Number of cans added
So, we have to find xy and x^2. We will form a new table:
Now, we will find a and b:
[tex]\begin{gathered} a\text{ = }\frac{(4120)(39090)\text{ - (}554)(297220)}{8(39090)\text{ }-554^2} \\ a\text{ = }\frac{\text{ 161050800 - 164659880}}{312720\text{ - 306916}} \\ a\text{ = }\frac{-3609080}{5804} \\ a\text{ }\cong\text{-62}2 \end{gathered}[/tex][tex]\begin{gathered} b\text{ = }\frac{8(297220)\text{ - (554})(4120)}{5804} \\ b\text{ = }\frac{2377760\text{ - 2282480}}{5804} \\ b\text{ = }\frac{95280}{5804} \\ b\text{ }\cong\text{ 16} \end{gathered}[/tex]Therefore, the linear regression equation is:
y = -622 + 16x
Now, let us graph it using values of x (High Temperature):
That is the Linear Regression Graph.
c) To predict soft drink sales if the temperature is 95 degrees Farenheit, we will put the x value as 95 and find y. That is:
y = -622 + 16(95)
y = 898
The model predicts that 898 cans of soft drinks will be sold when the High Temperature is 95 degrees Farenheit.
10 ptsQuestion 3Find the measure of each interior angle. Round to the nearest hundredth.4x(6x - 90)(3x + 31)(7x+19)X=(4x)" =(6x - 90)(7x + 19)° =(3x + 31)º =
Answers
Alexandre, this is the solution:
Let's recall that the interior angles of a rhombus add up to 360 degrees.
Upon saying that, we have:
4x + 3x + 31 + 6x - 90 + 7x + 19 = 360
20x - 40 = 360
Adding 40 at both sides:
20x - 40 + 40 = 360 + 40
20x = 400
Dividing by 20 at both sides:
20x/20 = 400/20
x = 20
Now, we can calculate each of the angles and prove they add up to 360 degrees, as follows:
• 4x = 4 * 20 =, 80
,• 3x + 31 = 3 * 20 + 31 = 60 + 31 =, 91
,• 7x + 19 = 7 * 20 + 19 = 140 + 19 = ,159
,• 6x - 90 = 6 * 20 - 90 = 120 - 90 = ,30
80 + 91 + 159 + 30 = 360
The annual rainfall in a town has a mean of 54.11 inches and a standard deviation of 12.59 inches. Last year there was rainfall of 48 inches. How many standard deviations away from the mean is that? Round your answer to two decimal places.
Answers
SOLUTION
Mean=54.11, standard deviation = 12.59
X=48
Using the z formula
[tex]z=\frac{x-\mu}{\sigma}[/tex]Substituting values gives
[tex]z=\frac{48-54.11}{12.59}[/tex]Solve for z
[tex]z=-0.4853[/tex]This shows that the result shows that the value x=48 is 0.4853 standard deviation to the left of the mean.