Determine the average speed of the monorail, in miles per hour, over each segment of the route. Round each speed to the nearest tenth of a mile per hour

Answer:

No, but you can graph them by converting to mx+b form

Step-by-step explanation:

The procedure for solving simultaneous linear equations now called Gaussian elimination appears in the ancient Chinese mathematical text Chapter Eight: Rectangular Arrays of The Nine Chapters on the Mathematical Art. Its use is illustrated in eighteen problems, with two to five equations.[4]

Systems of linear equations arose in Europe with the introduction in 1637 by René Descartes of coordinates in geometry. In fact, in this new geometry, now called Cartesian geometry, lines and planes are represented by linear equations, and computing their intersections amounts to solving systems of linear equations.

The first systematic methods for solving linear systems used determinants, first considered by Leibniz in 1693. In 1750, Gabriel Cramer used them for giving explicit solutions of linear systems, now called Cramer's rule. Later, Gauss further described the method of elimination, which was initially listed as an advancement in geodesy.[5]

In 1844 Hermann Grassmann published his "Theory of Extension" which included foundational new topics of what is today called linear algebra. In 1848, James Joseph Sylvester introduced the term matrix, which is Latin for womb.

Linear algebra grew with ideas noted in the complex plane. For instance, two numbers w and z in {\displaystyle \mathbb {C} }\mathbb {C}  have a difference w – z, and the line segments {\displaystyle {\overline {wz}}}{\displaystyle {\overline {wz}}} and {\displaystyle {\overline {0(w-z)}}}{\displaystyle {\overline {0(w-z)}}} are of the same length and direction. The segments are equipollent. The four-dimensional system {\displaystyle \mathbb {H} }\mathbb {H}  of quaternions was started in 1843. The term vector was introduced as v = x i + y j + z k representing a point in space. The quaternion difference p – q also produces a segment equipollent to {\displaystyle {\overline {pq}}.}{\displaystyle {\overline {pq}}.} Other hypercomplex number systems also used the idea of a linear space with a basis.

Arthur Cayley introduced matrix multiplication and the inverse matrix in 1856, making possible the general linear group. The mechanism of group representation became available for describing complex and hypercomplex numbers. Crucially, Cayley used a single letter to denote a matrix, thus treating a matrix as an aggregate object. He also realized the connection between matrices and determinants, and wrote "There would be many things to say about this theory of matrices which should, it seems to me, precede the theory of determinants".[5]

Benjamin Peirce published his Linear Associative Algebra (1872), and his son Charles Sanders Peirce extended the work later.[6]

The telegraph required an explanatory system, and the 1873 publication of A Treatise on Electricity and Magnetism instituted a field theory of forces and required differential geometry for expression. Linear algebra is flat differential geometry and serves in tangent spaces to manifolds. Electromagnetic symmetries of spacetime are expressed by the Lorentz transformations, and much of the history of linear algebra is the history of Lorentz transformations.

The first modern and more precise definition of a vector space was introduced by Peano in 1888;[5] by 1900, a theory of linear transformations of finite-dimensional vector spaces had emerged. Linear algebra took its modern form in the first half of the twentieth century, when many ideas and methods of previous centuries were generalized as abstract algebra. The development of computers led to increased research in efficient algorithms for Gaussian elimination and matrix decompositions, and linear algebra became an essential tool for modelling and simulations.[5]

Vector spaces

Main article: Vector space

Until the 19th century, linear algebra was introduced through systems of linear equations and matrices. In modern mathematics, the presentation through vector spaces is generally preferred, since it is more synthetic, more general (not limited to the finite-dimensional case), and conceptually simpler, although more abstract.

A vector space over a field F (often the field of the real numbers) is a set V equipped with two binary operations satisfying the following axioms. Elements of V are called vectors, and elements of F are called scalars. The first operation, vector addition, takes any two vectors v and w and outputs a third vector v + w. The second operation, scalar multiplication, takes any scalar a and any vector v and outputs a new vector av. The axioms that addition and scalar multiplication must satisfy are the following. (In the list below, u, v and w are arbitrary elements of V, and a and b are arbitrary scalars in the field F.)[7]

Answer:

$960

Step-by-step explanation:

2,400 divided by 2.5 = 960

y divided by x = 950 (x) 2,400 (y)

Answer:

km that is k×m means k is multiplied by m

Answer: 2(x + 10)

Step-by-step explanation: you have to add all of the perimeter sides together so you will have to times the length by 2 so your equation would be (8 × 2 = 16). Then the width by 2 ( 2 × (x+2) = 2x + 4) now you add them together

16 + 2x + 4

2x + 20

Now you have to take out the highest common factor which is 2

So it will be 2(x + 10)

Answer:

Continuous

Step-by-step explanation:

Answer:

9,000

5,025

Step-by-step explanation:

Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:

.16666667

Step-by-step explanation:

(x)3=0.5

divide both sides by 3

x    =.16666667

Answer:

19. is 18

31. is 10y-x

Step-by-step explanation:

thats only what i know sorry

Answer:

-0.83

Step-by-step explanation:

Answer:

In my thinking the answer is 9.

Answer:

6.5 rounded from 6.53...

to see if this is correct we can:

13.5+9.5+6.5*3 = 42.5

but since we rounded it we can say its 6.5

Answer:

6.55 meters each day

Step-by-step explanation:

You know that in the end the fence must be 42.6 meters long.

On Monday & Tuesday, he installed 22.95 meters of fence. (We know this because 13.45 + 9.5 = 22.95).

So, how much is left? You find that by subtracting 22.95 from 42.6.

42.6-22.95 = 19.65 meters

There are 3 days left of fencing, and these days he will install equal lengths, so you can divide 19.65 meters by 3 days.

19.65 / 3 = 6.55 meters of fence per day

estimated sum-114, actual sum-112.97

Step-by-step explanation:

76.6-77

25.5-26

10.87-11

77+26+11=114

76.6+25.5+10.87=112.97

Answer:

D

Step-by-step explanation:

The 3 angles in a triangle sum to 180°

Sum the 3 given angles and equate to 180

2x + 3 + 7x - 5 + 3x + 14 = 180 , collect like terms

12x + 12 = 180 ( subtract 12 from both sides )

12x = 168 ( divide both sides by 12 )

x = 14

Then

∠ F = 7x - 5 = 7(14) - 5 = 98 - 5 = 93° → D

Answer:

15.25 hours

Step-by-step explanation:

her pay per hour is $27.2

414.80÷27.2=15.25

Answer:

=  2

=  − 5

Step-by-step explanation:

Answer:

(4x+5)°+(6x-10)°=145°

4x+6x+5-10=145°

10x-5=145°

10x=145+5

10x=150°

x=15

(6x-10)°=(6×15-10)°

=80°

The value of ∠XMN = 80.

An angle is a figure in plane geometry that is created by two rays or lines that have a shared endpoint.

The value of total ∠LMN = 145.

∠LMN = ∠LMX +∠XMN

145 = (4x + 5) + (6x - 10)

145 = 4x + 5 + 6x - 10

145 = 10x -5

10x = 150

x = 15

Substitute the value of x in ∠XMN =  (6x - 10)

∠XMN =  6×15 - 10

            = 90 - 10

∠XMN = 80

Therefore, the value of the angle  ∠XMN = 80.

To know more about the angle theorems, here

https://brainly.com/question/27962469

#SPJ2

Answer: -6x + 18

Step-by-step explanation: multiply each expression in the brackets by -3

so, -3 x 2x = -6x and -3 x -6 will give you +18 or just 18

for a final answer of -6x + 18

Answer:

Step-by-step explanation:

1)

We know that if [tex]x^2=9[/tex], then [tex]x=\pm \sqrt{9}[/tex], so [tex]\boxed{x=3,-3}[/tex]

2)

We know that if [tex]x^3=8[/tex], then [tex]x=\sqrt[3]{8}[/tex], so [tex]\boxed{x=2}[/tex]

3)

[tex]x^3=\frac{1}{8}[/tex] means that [tex]x=\sqrt[3]{\frac{1}{8}}=\frac{\sqrt[3]{1}}{\sqrt[3]{8}}=\frac{1}{2}[/tex].

So, [tex]\boxed{x=\frac{1}{2}}[/tex].

4)

[tex]x^3=27[/tex] means that [tex]x=\sqrt[3]{27}=\sqrt[3]{3^3}=3[/tex].

So, [tex]\boxed{x=3}[/tex].

5)

[tex]x^2=25[/tex] means that [tex]x=\pm \sqrt{25}=\pm \sqrt{5^2}=\pm 5[/tex].

So, [tex]x=5,-5[/tex].

6)

We know that the side length of the square will be [tex]\sqrt{\frac{9}{16}}=\frac{\sqrt{9}}{\sqrt{16}}=\boxed{\frac{3}{4}}[/tex].

7)

[tex]6x^2=54[/tex] means that [tex]x^2=9[/tex], which means that [tex]\boxed{x=3,-3}[/tex].

8)

[tex]2x^2+25=75[/tex] means that [tex]2x^2=50[/tex], which means that [tex]x^2=25[/tex], which means that [tex]\boxed{x=5,-5}[/tex]

Answer:

the right answer is x = 9/2

Answer:

[tex] \frac{2 \sqrt{3y} \times |x| }{3y} [/tex]

Step-by-step explanation:

[tex] \sqrt{ \frac{ {4x}^{2} }{3y} } [/tex]

[tex] \frac{2 \times |x| }{ \sqrt{3y} } \\ \frac{2 \times |x|}{ \sqrt{3y} } \times \frac{ \sqrt{3y} }{ \sqrt{3y} } \\ \frac{2 \times |x| \times \sqrt{3y} }{ \sqrt{3y} \sqrt{3y} } [/tex]

[tex] \boxed{Answer:{\boxed{\green{= \frac{2 \sqrt{3y} \times |x| }{3y}}}}} [/tex]

Answer:

 y = -1/2x -3

Step-by-step explanation:

The line perpendicular to one with a slope of 2 will have a slope that is the negative reciprocal of 2, that is, -1/2. The given point is the y-intercept of the required line, so we can write its equation directly in slope-intercept form:

y = mx + b

where m is the slope (-1/2), and b is the y-intercept (-3). Your line is ...

 y = -1/2x -3

_ _

| - 17 |

PQ = | - 3 |

| - 37 |

|_ 49 _|

Answer:

-5, -9

Step-by-step explanation:

This point is located in the fourth quadrant. When rotated at 270 degrees, it'll end up in the third quadrant. The rules for this quadrant is that both the x and y value will be negative.

Answer: I think is -9(5,)

Step-by-step explanation:

Answer:

[tex]t = \frac{-D+F}{Dr}[/tex]

Step-by-step explanation:

Step 1: Flip the equation.

Step 2: Subtract D from both sides.

Step 3: Divide both sides by Dr.