Answer:
[tex]0.078\text{ g/l}[/tex]Explanation:
Here, we want to calculate the density of the gas at STP
We use a modification of the general gas law as follows
Mathematically:
[tex]\frac{P_1}{D_1\times T_1}\text{ = }\frac{P_2}{D_2\times T_2}[/tex]where:
P1 is the initial pressure which is 0.95 atm
D1 is the initial density which is 0.066 g/l
T1 is the initial temperature in Kelvin (we add the temperature in Celsius with 273 K : 32 + 273 = 305 K)
P2 is the pressure at STP which is 1 atm
D2 is the density that we want to calculate
T2 is the temperature at STP which is 273 K
Substituting the values, we have it that:
[tex]\begin{gathered} \frac{0.95}{0.066\times305}\text{ = }\frac{1}{D_2\times273} \\ \\ D_2\text{ = }\frac{0.066\times305}{0.95\times273}\text{ = 0.078 g/l} \end{gathered}[/tex]dry cleaners use tetrachloroethylene (C2CL4) to dissolve oil and grease because C2CL4 is
Answer: Tetrachloroethylene is an nonpolar molecule.
an avocado can be a simple model of the structure of a cell.
which cell structure is represented by the avocado's skin.
The body of avocado fruit can be compared with the cell structure. The skin of the avocado is relatable with the cell membrane. Thus option B is correct.
What is cell?Cell is the basic unit of life. Cells connect together to forms tissues and tissues forms organs and a group organs forms an organ system. These different organ systems buildup the whole body.
Cell contains the core called nucleus. Inside the nucleus genetic material DNA, ribosomes, Golgi apparatus, lysosomes etc are located. The function of cell membrane is to protect the cell from damages as the skin do for our body.
In plants unlike animals, their cell is protected by a cell wall apart from cell membrane and various other differences are there in the cell structure of plant cells.
The fluid filled portion of cell is called cytoplasm. The inner content of the avocado fruit is comparable with the cytoplasm and its seed can be considered as the model for nucleus.
Therefore, the avocado's skin represents the cell membrane. Hence, option B is correct.
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How many mols of Cl₂ are needed to make 0.6 mols of NaCl according to the
following reaction?
2Na + Cl₂ --> 2NaCl
Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 0.950 kg of water decreased from 103 °C to 60.5 °C.
Property Value Units
Melting point 0 °C
Boiling point 100.0 °C
ΔHfus 6.01 kJ/mol
ΔHvap 40.67 kJ/mol
cp (s) 37.1 J/mol · °C
cp (l) 75.3 J/mol · °C
cp (g) 33.6 J/mol · °C
The energy change when the temperature of 0.950 kg of water decreased from 103 °C to 60.5 °C is 2308.87 kJ.
What is the heat energy change when the temperature of 0.950 kg of water decreased from 103 °C to 60.5 °C?The heat energy change when the temperature of 0.950 kg of water decreased from 103 °C to 60.5 °C is determined from the formulas below:
Heat change 1 = Heat capacity as gas * moles * temperature change
Heat change 2 = Heat of vaporization, ΔHvap * moles
Heat change 3 = Heat capacity as liquid, Cp (l) * moles * temperature change
moles of water = 950 kg * 1000 g/kg * 1 mol/ 18g = 52.78 mole
Heat change 1 = 33.6 * 52.78 * (103 - 100) = 5320.224 J
Heat change 2 = 40.67 * 1000 * 52.78 = 2146562.6 J
Heat change 3 = 75.3 * 52.78 * (100 - 60.5) = 156986.193 J
Total heat change = 5320.224 J + 2146562.6 J + 156986.193 J
Total heat change = 2308869.017 J = 2308.87 kJ
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How many groups are attached to a center atom with trigonal planar geometry? 3 groups 1 group 5 groups 4 groups
Answer:
The number of groups attached to a center atom with trigonal planar geometry is 3 groups.
What kind of intermolecular forces act between a chloramine (NH₂CI) molecule and an oxide (0²-) anion?Note: If there is more than one type of intermolecular force that acts, be sure to list them all, with a comma between thename of each force.
Answer
Hydrogen bonding, dipole-dipole interaction, and dispersion forces.
Explanation
The chloramine (NH₂CI) molecule has N-H bonds, so there will be hydrogen bonding. Also, NH₂Cl is a polar molecule, so there will be dipole-dipole interaction. And as with molecules like O²⁻, there will be dispersion forces.
Therefore, the kind of intermolecular forces that act between a chloramine (NH₂CI) molecule and an oxide (O²⁻) anion are hydrogen bonding, dipole-dipole interaction, and dispersion forces.
how do i calculate the molar mass of 5 and 65. K2Cr2O76. C12H22O11
To calculate the molar mass of a compound, we need to find at the periodic table the atomic mass of each element that belongs to the compound and then we multiply for the quantity of atoms of it.
So, for:
5. K2Cr2O7:
K = 39 g/mol
Cr = 52 g/mol
O = 16 g/mol
(2x39) + (2x52) + (7x16) = 78 + 104 + 112 = 294 g/mol
Molar mass of K2Cr2O7 = 294 g/mol
6. C12H22O11
C = 12 g/mol
H = 1 g/mol
O = 16 g/mol
(12x12) + (22x1) + (11x16) = 144 + 22 + 176 = 342 g/mol
Molar mass of C12H22O11 = 342 g/mol
A new alloy is designed for use in a car radiator. If the 17.6 kg radiator required 8.69 × 105 J of heat to warm from 22.1°C to 155.8°C, what is the specific heat of the new alloy?
A new alloy is designed for use in a car radiator. If the 17.6 kg radiator required 8.69 × 105 J of heat to warm from 22.1°C to 155.8°C, the specific heat of the new alloy is 369.2 J / kg °C.
Specific heat formula is given as :
Q = mcΔT
given that :
mass , m = 17.6 kg
Q = 8.69 × 10⁵ J
ΔT , change in temperature = 22.1 °C - 155.8 °C = 133.7 °C
c = specific heat = ?
Substituting the values in the formula we get:
Q = mcΔT
c = Q / mΔT
c = 8.69 × 10⁵ J / 17.6 kg × 133.7 °C
c = 8.69 × 10⁵ J / 2353.12 kg °C
c = 369.2 J / kg °C
Thus, A new alloy is designed for use in a car radiator. If the 17.6 kg radiator required 8.69 × 10⁵ J of heat to warm from 22.1°C to 155.8°C, the specific heat of the new alloy is 369.2 J / kg °C.
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A -13.68 gram of sample of iron is heated in the presence of excess fluorine. A metal Fluoride is formed with a mass of 27.64g. Determine the empirical formula of the metal fluoride.
Explanation:
A 13.68 g sample of iron is reacted in presence of excess fluorine and an iron fluoride with a mass of 27.64 g is formed.
We have to find the empirical formula of our compound. This compound has two elements: Fe and F. We can express it like:
metal fluoride = FeₐFₓ
Where a is the subscript of Fe and x is the subscript for F.
First we have to find the mass of F present in the compound. We know that our compound has a total mass of 27.64 g and the mass of Fe present is 13.68 g. Since it only has two elements we can find the mass of F.
mass of sample = mass of Fe + mass of F
mass of F = mass of sample - mass of Fe
mass of F = 27.64 g - 13.68 g
mass of F = 13.96 g
So we found that our sample has 13.96 g of F and 13.68 g of Fe. Now we can determine the number of moles of each element that are present in the sample by using their molar masses.
molar mass of Fe = 55.85 g/mol
molar mass of F = 19.00 g/mol
moles of Fe = 13.68 g * 1 mol/(55.85 g)
moles of Fe = 0.245 moles
moles of F = 13.96 g * 1 mol/(19 g/mol)
moles of F = 0.735 moles
By definition the empirical formula is "simplest whole number ratio of atoms present in a compound". So if we want to find the ratio between them we have to divide both of them by the smallest number.
a = subscript of Fe = 0.245/0.245 = 1
x = subscript of F = 0.735/0.245 = 3
So the empirical formula of our compound is:
empirical formula = FeₐFₓ
empirical formula = FeF₃
Answer: empirical formula = FeF₃
2. 5.4 grams of carbon dioxide gas is confined to a 20.0 L container at atemperature of 32.5°C. What pressure does the gas exert? (15 kPa)
To calculate this, we will need to assume the gas behaves as an ideal gas.
So, we can use the Ideal Gas Law:
[tex]PV=nRT[/tex]Where P is the pressure, V is the volume, n is the number of moles, is the absolut temperature and R is the gas law constant.
Since we have carbon dioxide, CO₂, we need to calculate its molar mass to convert the mass to number of moles:
[tex]\begin{gathered} M_{CO_2}=(1\cdot M_C+2\cdot M_O) \\ M_{CO_2}=(1\cdot12.0107+2\cdot15.9994)g\/mol \\ M_{CO_2}=44.0095g\/mol \end{gathered}[/tex]So, the number of moles is:
[tex]\begin{gathered} M_{CO_2}=\frac{m}{n} \\ n=\frac{m}{M_{CO_{2}}}=\frac{5.4g}{44.0095g\/mol}=0.1227\ldots mol\approx0.12mol \end{gathered}[/tex]Also, we need to convert the temperature to absolute temperature, so we can convert it to K by adding 273.15 to the degree celcius temperature:
[tex]T=32.5\degree C=(32.5+273.15)K=305.65K[/tex]Now, we need to use the constant R that has the unit we want. We have K for temperature, mol for number of moles and L for volume. Is we want the pressure in kPa, we need to use the R constant with units L*kPa/(K*mol), which have the value:
[tex]R\approx8.31446\frac{L\cdot kPa}{K\cdot mol}[/tex]So, solving the equation for P and substituting the values, we have:
[tex]\begin{gathered} PV=nRT \\ P=\frac{nRT}{V} \\ P=\frac{0.12mol\cdot8.31446L\cdot kPa\cdot K^{-1}mol^{-1}\cdot305.65K}{20.0L} \\ P=\frac{0.12\cdot8.31446\cdot305.65}{20.0}kPa \\ P=15.247\ldots kPa\approx15kPa \end{gathered}[/tex]So, the pressure is approximately 15 kPa.
The combustion of liquid ethanol (C2H, OH)produces carbon dioxide and water. After 5.8 mLof ethanol (density = 0.789 g/mL) was allowed toburn in the presence of 12.5 g of oxygen gas, 3.10mL of water (density = 1.00 g/mL) was collected.
Answer
Explanation
Given data:
Virginia has 11 people in the House and 2 in the Senate. How many electoral votes does it have? ________________ Where is this addressed?
The total number of electoral votes does Virginia have is 13. This addressed in congressional apportionment.
When people cast their vote, means they actually voting for the group of people called electors. Senator and representatives are equal to the number of voters in each state . According to the question , Virginia has 11 people in the house and 2 senate means 11 + 2 = 13 . the total number of electoral votes are 13. These votes are assigned by united states electoral college. In the constitution the congressional apportionment is addressed.
Thus, Virginia has 11 people in the House and 2 in the Senate. The total number of electoral votes does Virginia have is 13. This addressed in congressional apportionment.
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How many grams of solute would you use to prepare the following solutions?241.0 mL of 1.11 M NaOHExpress your answer with the appropriate units.
10.7 grams
Explanations:The formula for calculating the molarity of a solution is given as:
[tex]\begin{gathered} molarity=\frac{moles}{volume} \\ moles=molarity\times volume \end{gathered}[/tex]Given the following parameters
molarity of NaOH = 1.11M
volume of solution = 241.0mL = 0.241L
Find the moles of NaOH
[tex]\begin{gathered} moles\text{ of Na}OH=\frac{1.11mol}{L}\times0.241L \\ moles\text{ of Na}OH=0.2675moles \end{gathered}[/tex]Determine the mass of solute (NaOH)
[tex]\begin{gathered} Mass\text{ of NaOH}=mole\times molar\text{ mass} \\ Mass\text{ of NaOH}=0.2675\times40 \\ Mass\text{ of NaOH}=10.7grams \end{gathered}[/tex]Hence the grams of solute that would be used to prepare the solution is 10.7grams
Volume of syringes reading read as 4cc when the weight (pressure) was 600g. Determine the pressure used (weight) when the volume is 2.5 cc?
Answer:
[tex]960\text{ g}[/tex]Explanation:
Here, we want to calculate the pressure used at the new volume
It is expected that at a higher pressure, the volume will decrease
Thus, the weight and the pressure are inversely proportional
Mathematically:
[tex]P_1V_1\text{ = P}_2V_2[/tex]The above is according to Boyle's law which states that volume and pressure are inversely proportional
where:
V1 is the initial volume which is 4 cc
P1 is the initial weight which is 600 g
V2 is the final volume which is 2.5 cc
P2 is the final pressure which is unknown
Substituting the values:
[tex]P_2\text{ = }\frac{600\times4}{2.5}\text{ = 960 g}[/tex]3) Water is a polar solvent; gasoline is a non-polar solvent. Which compounds are
more likely to dissolve in water? Check all that apply.
CCI4
NaCI
CH4
Oil
According to given statement NaCI compounds are more likely to dissolve in water.
What is polar solvent with example?Polar solvents, which do have "positive" and "negative" charges at different points throughout their structures, can dissolve other polar compounds. Acetone, methanol, dimethylformamide (DMF), dimethylsulfoxide (DMSO), isopropanol, and ethanol are some other polar solvents. A few of these solvents is water.
Why water is a polar solvent?Due to the uneven distribution of its electron density, water is a polar molecule. This demonstrates that water is indeed a polar molecule because hydrogen and oxygen have different electronegativities. The fact that water can dissolve more chemicals compared to any other liquid makes it known as the "universal solvent."
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If 21.5 g of LiCl are dissolved 450.0 g of water at 20.0 °C in an insulated container, a temperature change is observed. The ∆H of solution of LiCl is -37.0 kJ/mol. Assuming that the specific heat of the solution is 4.184 J/(g°C), and that no heat is gained or lost by the container, what will be the final temperature of the solution?
The final temperature of the solution will be 29.5 °C.
What is the heat released when 21.5 g of LiCl is dissolved completely in water?The heat released when 21.5 g of LiCl is dissolved completely in water is determined from the enthalpy change, ∆H of the solution of LiCl as follows;
Moles of LiCl in 21.5 g = mass/ molar mass
molar mas of LiCl = 42.5 g/mol
Moles of LiCl in 21.5 g = 21.5/42.5
Moles of LiCl in 21.5 g = 0.506 moles
Heat released = 0.506 * -37.0 kJ/mol
Heat released = 18.722 kJ or 18722 J
Heat released = heat gained by solution
Temperature change of the solution = heat gained / mass * specific heat capacitymass of solution = 450 + 21.5
mass of solution = 471.5 g
Temperature change of the solution = 18722 / (471.5 * 4.184)
Temperature change of the solution = 9.5 °C
Final temperature of the solution = 20 °C + 9.5 °C
Final temperature of the solution =29.5 °C
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The empirical formula for a compound that contains 6.34 grams carbon and 1.06 grams hydrogen is
Answer:
[tex]CH_2[/tex]Explanation:
Here, we want to get an empirical formula
We start by dividing each of the masses by the corresponding atomic masses
The atomic mass of carbon is 12 amu
The atomic mass of hydrogen is 1 amu
We start the division as follows:
[tex]\begin{gathered} C\text{ = }\frac{6.34}{12}\text{ = 0.5283333} \\ \\ H\text{ = }\frac{1.06}{1}\text{ = 1.06} \end{gathered}[/tex]Now, we divide the results by the smaller of the two:
[tex]\begin{gathered} C\text{ = }\frac{0.528333}{0.529333}\text{ = 1} \\ \\ H\text{ = }\frac{1.06}{0.528333}\text{ = 2} \end{gathered}[/tex]Thus, we have the empirical formula as:
[tex]CH_2[/tex]Patricia wants to examine the morphology of a hair sample. What is the BEST way for her to accomplish this task?
A.
Send the sample away to a lab for DNA testing.
B.
Observe the sample under a high-powered microscope.
C.
Add a solution to the hair to see if it reacts.
D.
Use a Hemastix strip to perform A-B-O testing.
The best way for her to accomplish the task of evaluating a hair strip is DNA testing. Hence, option A is correct.
What is DNA testing?The DNA testing in forensic laboratories include extract the DNA strands from the sample and strictly evaluate it some reagents and color indicators.
Hair analysis involves examining the DNA of cells linked to the hair's root as well as the hair's structure. It can be used to determine a person's family relationship. It is possible to use forensic hair analysis to identify a person who may have been at a crime scene. Hair samples are examined under a microscope and evaluated using particular chemicals.
Additionally, metal poisoning from lead or mercury can be detected through hair analysis. However, this form of testing often does not involve hair analysis alone.
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How many joules of heat are needed to raise the temperature of 100 g of iron from 23°C to 33°C, if the specific heat of iron is 0.45 J/g°C
Joules of heat are needed to raise the temperature of 100 g of iron from 23°C to 33°C, if the specific heat of iron is 0.45 J/g°C is 450 J.
Given that :
The specific heat capacity expression is given as :
Q = m cΔT
Q = heat energy
m = mass = 100 g
c = specific heat = 0.45 J/g °C
ΔT = change in temperature = 33 °C - 23 °C = 10 °C
substituting the values in the formula:
Q = m cΔT
Q = 100 g × 0.45 J/g °C × 10 °C
Q = 450 J
Thus, Joules of heat are needed to raise the temperature of 100 g of iron from 23°C to 33°C, if the specific heat of iron is 0.45 J/g°C is 450 J.
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JWhat did Rutherford’s model of the atom include that Thomson’s model did not have?
a nucleus
energy levels
electron clouds
smaller particles
Answer:
Rutherford's model of the atom included the nucleus, something lacking in Thomson's model. Rutherford's inclusion of the nucleus came about after his discovery of the nucleus of the atom in 1911. He was testing J.J. Thomson's Plum Pudding model by directing a beam of alpha particles toward a thin sheet of gold foil.
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An experiment begins
with 87.5g of
potassium and 13.2g of
chlorine. What is the
experiment mass of
the product?
The experiment mass of the product is 28.1g
What is mass ?
Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia, or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.
The kilogramme is the primary mass unit in the SI (kg). Although weight is frequently measured using a spring scale rather than a balancing scale and compared directly with known masses, mass is not the same as weight in physics.
2K + Cl2 =====> 2KCl
70g Cl2 produces 2(39+35.5) = 149 g KCl
13.2g Cl2 produces 28.1g KCl
the experiment mass of the product is 28.1g
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Which state of matter is being described below?It cannot be squashed easily, will not spread out & is high densityA. GasB. SolidC. LiquidD. Plasma
There are 3 main states of matter: gas, solid, and liquid.
The solid is characterized by its rigid structure, its high density (it means that's there's a lot of mass per unit of volume). Also, it doesn't take the container's shape as a liquid does.
Then, the description corresponds to the solid state (option B).
A 0.016773-m^3 tank contains 1kg of refrigerant-134a at 110C. Determine the pressure of the refrigerant using (a) the ideal-gas equation, (b) the generalized compressibility chart, and (c) the refrigerant tables.
Answers:(a)1.861MPa,(b)1.583MPa,(c)1.6MPa
The pressure of the refrigerant using the ideal-gas equation is 1.861 MPa, the generalized compressibility chart is 1.583 MPa and the refrigerant tables is 1.6 MPa.
What is ideal gas equation?Ideal gas equation is defined as the state equation for a fictitious perfect gas. Although it has significant drawbacks, it is a decent approximation of the behavior of many gases under various conditions.
Ideal gas equation is expressed as
PV = nRT
By using Ideal gas equation
P x 0.016773 = 1 x 81.49 x 483
P = 1.861 MPa
By using generalized compressibility chart
For r134a
Temperature = 374.2 K
Pressure = 4.06 MPa
vR = V / R x Tc / Pc
= 0.016773 / 81.49 x ( 374.2 / 4.06 x 10⁶ )
= 2.2332
Tr = T/Tc = 383 / 374.2 = 1.024
Therefore from the chart Z = 0.85
So, P = Z mRT / V
P = 0.85 x 1 x 81.49 x 383 / 0.016773
= 1.582 MPa
By using refrigerant tables
T = 110 C and v = 0.0167763
So, P = 1.6 MPa
Thus, the pressure of the refrigerant using the ideal-gas equation is 1.861 MPa, the generalized compressibility chart is 1.583 MPa and the refrigerant tables is 1.6 MPa.
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At a pressure of 1.00atm the solubility of nitrogen in water is 23.5mg gas/100g water. Indicate whether each of the following changes would increase or decrease the solubility of nitrogen in water
Solubility of a substance changes as the pressure changes. If the pressure is high, solubility increases. When pressure is low, solubility decreases.
At 1 atm the solubility of Nitrogen in water is 23.5 mg gas/110g water.
The solution is submerged 40 m under water. Solubility increase.
The solution is carried to the top of a mountain. Solubility decrease.
The solution is placed in a chamber where the pressure is 0.50 atm. Solubility decrease.
The solution is brought into outer space. Solubility decrease.
The solution is canned at a pressure of 2.04 atm. Solubility increase.
Ionic compound formulas must be ______ to the smallest whole number ratio
Explanation:
As an example, Let's writte some ionic compounds:
how many moles of electrons are needed to produce 53.5 mol of Zn(s)
The moles of electrons are needed to produce 53.5 mole of Zn is 107 moles.
What are electrons?Electrons are defined as a subatomic particle having a negative charge that makes up the nucleus of an atom together with protons and neutrons.
The electron has an intrinsic angular momentum of a half-integer number and has a mass that is around 1/1836th that of the proton. The quantum state of any two electrons cannot be identical.
The chemical reaction for solid zinc is
Zn²⁺ + 2e⁻ = Zn (s)
When one mole of zinc ions receive two moles of electrons, one mole of zinc is created.
Electrons equal two moles to form one mole of solid zinc.
The electrons needed to create the 53.5 mole of zinc will provide 2 53.5 = 107 mol.
Thus, the moles of electrons are needed to produce 53.5 mole of Zn is 107 moles.
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Which of the following describes a physical property?Corrosiveness of sodiumToxcity of cadmiumWater when heated forms steamFlammability of hydrogen
Physical properties are the ones that describe the behavior of the substances when exposed to different physical changes.
In this case, the one that describes a physical change is water when heated forms steams. In this case water changes its state of matter but it is still the same substance, there is not chemical change, just physical.
The correct answer is Water when heated forms steams.
ectQuestion 13What is being reduced in the following reaction ?C2H4(g) + 302(g) → 2CO2(g) + 2H2O(g)C2H4H20No reduction or oxidation is occurringCO2
Step 1
The reaction is written and balanced as:
C2H4(g) + 302(g) → 2CO2(g) + 2H2O(g)
Step 2
Oxidation states are analyzed
For O2)
On the left, its oxidation state is 0 (O2)
On the right, it is -2 (H2O)
Step 3
The half-reaction is written as:
6 O + 12 e- => 6 O2-
Therefore, O2 is being reduced
Answer: O2
4. Collaborate with a partner, make a brochure that highlights an example of a
technology that you have seen in which density is important.
The common use of density in ships and submarines is to predict whether or not a thing will float. Objects that have densities lower than those of water will sink if their densities are lower than water's.
What does density mean ?A product's density is a measure of how heavy it is relation to its size. If added to water, an object will float if its density is less than that of the water, while it will sink if its higher density. The density of a material is a distinguishing quality that is independent of the substance's volume.
Why is density important in chemistry?Because density is an intense property, it remains constant regardless of how much of a substance is present. Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion.
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How many atoms are in 275 grams of iron (III) hydroxide. Include units and name of atom/molecule.
To calculate the number of atoms of any compound it is necessary to use the Avogadro constant. This is a constant of proportion between the amount of matter and the number of entities that are linked to that amount. These entities can be atoms, molecules, ions, electrons, protons, neutrons. The value of the Avogrado constant is 6.022 x 10^23 mol^-1.
So to calculate the number of atoms in 275 grams of iron (III) hydroxide:
- First you need to transform grams into moles
- transform moles into atoms/molecule using Avogrado constant.
- To transform 275 grams of Fe(OH)₃ you need to use the molecular mass of Fe(OH)₃ and the following equation: mole = mass/molar mass
Molecular mass of Fe(OH)₃:
Fe - 55.85
O - 16
H - 1
(1x55.85) + (3x16) + (3x1) = 106.86 g/mol
Replace the value in the equation:
mole = 250/106.86
mole = 2.34 mole of Fe(OH)₃
- Now, let's solve the number of molecules of Fe(OH)₃ into 2.34 mole of Fe(OH)₃:
6.022 x 10^23 molecule --- 1 mol
x molecule ---- 2.34 mole
x = 1.41 x 10^24 molecules of Fe(OH)₃
Answer: There are 1.41 x 10^24 molecules of Fe(OH)₃