Answer:
784.4kg
Explanation:
Given parameters:
Mass of Mg = 200kg
Unknown:
Mass of MgCl₂ = ?
Solution:
The reaction equation is given as:
Mg + Cl₂ → MgCl₂
Find the number of moles of the given specie;
Number of moles of Mg = [tex]\frac{mass}{molar mass}[/tex] = [tex]\frac{200000}{24.3}[/tex] = 8230.5mole
So;
1 mole of Mg will produce 1 mole of MgCl₂
8230.5mole of Mg will produce 8230.5mole of MgCl₂
Mass of MgCl₂ = number of moles x molar mass
Molar mass of MgCl₂ = 24.3 + 2(35.5) = 95.3g/mol
Mass of MgCl₂ = 8230.5mole x 95.3g/mol = 784.4kg
Please help outttt:(
Explanation:
1)
2Fe+3Cl2 →2FeCl3
2)
CH4+2O2 → CO2 +2H2O
3)
SnO2+2H2 →2H2O +Sn
4)
2KOH + H2SO4 → K2SO4+2H2O
How many electrons does H have with a -1 charge
Answer:The electron has a negative charge and the proton has a positive charge, and these charges work against each other to make the electromagnetic force that holds the entire atom together.
Explanation:
This is the answer
How many moles are 21.67 L of NH4CI?
Type your answer...
Answer:
0.967mole
Explanation:
Given parameters:
Volume of NH₄Cl = 21.67L
Unknown:
Number of moles = ?
Solution:
We assume that the volume was taken at standard temperature and pressure,
Then;
Number of moles = [tex]\frac{volume }{22.4L}[/tex]
Number of moles = [tex]\frac{21.67}{22.4}[/tex] = 0.967mole
How many grams of KClO3 will dissolve in 300g of water at 50°C?
Answer:
50 g
Explanation:
Please brainiest
whats the unit for mass
Answer:
The unit for mass is the kilogram (Kg).
Explanation:
Hope this helped!! <3 good luckk!!
3. If 12.5 grams of copper are reacted with excess chlorine gas, then 25.4 grams of
copper (II) chloride are produced. Calculate the theoretical yield and the percent
yield. Cu + Cl2 → CuCl2
Answer:
Percent yield = 99.6%
Theoretical yield = 25.5 g
Explanation:
Given data:
Mass of copper = 12.5 g
Mass of copper(II) chloride produced = 25.4 g
Theoretical yield = ?
Percent yield = ?
Solution:
Chemical equation:
Cu + Cl₂ → CuCl₂
Number of moles of copper:
Number of moles = mass/molar mass
Number of moles = 12.5 g / 63.5 g/mol
Number of moles = 0.19 mol
Now we will compare the moles of copper and copper chloride.
Cu : CuCl₂
1 : 1
0.19 : 0.19
Mass of CuCl₂: Theoretical yield
Mass = number of moles × molar mass
Mass = 0.19 mol × 134.45 g/mol
Mass = 25.5 g
Percent yield:
Percent yield = (actual yield / theoretical yield )×100
Percent yield = ( 25.4 g/ 25.5 g) ×100
Percent yield = 99.6%