These two pentagons are similar.
If two pentagons are similar, then their sides are proportional. To find PT, we'll need to set up a proportion.
AE / PT = AB / PQ
---There are many ways to set up this proportion, it just depends on what side lengths you have and ensuring that they match up on both shapes.
6 / x = 5 / 12.5
5x = 75
x = 15
Length of PT = 15 cm
Option C
Hope this helps!
Given the function h of x equals 2 times the cube root of x minus 10 end root plus 4, what is the x-intercept of the function?
–10
–4
2
8
Step-by-step explanation:
if I understand correctly, then we have
h(x) = 2 × cubic root(x - 10) + 4
the x-intercept is the x value where y or h(x) = 0.
0 = 2 × cubic root(x - 10) + 4
0 = cubic root(x - 10) + 2
-2 = cubic root(x - 10)
-8 = x - 10
x = 2
The intercept is the point where a line or curve crosses the axis. The x-intercept of the function is (2,0)
Intercept of a functionThe intercept is the point where a line or curve crosses the axis. Given the function below:
h(x) = 2(∛x-10) + 4
For the x-intercept, it is the point where h(x) = 0.
Substitute
2(∛x-10) + 4 = 0
2(∛x-10) = -4
(∛x-10) = -2
Take the cube of both sides
x-10 = (-2)^3
x -10 = -8
x = -8 + 10
x = 2
Hence the x-intercept of the function is (2,0)
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The equation 2x² + 2y2 – 8x - 12y + 16 = 0 defines a circle.
which of these shows a correct step for determining the center and radius of this circle? choose all that are correct.
(2x2 – 8x + 16) + (2y2 – 12y + 36) = -16 + 36
(x - 4)2 + (y - 9)2 = 5
(x2 - 4x + 4) + (y2 – 6y + 9) = -8 +13
ox? + y2 - 4x - 6y = -16
(x - 2)2 + (y - 3)2 = 5
Answer:
C, E
Step-by-step explanation:
Here, we want to change the equation of a circle from general form to standard form. This is done by making the leading coefficients 1, completing the squares, and then rewriting the equation in standard form.
The leading coefficients of the given equation are 2, so we first want to divide by 2. This gives ...
x² +y² -4x -6y +8 = 0
Subtracting 8 puts us in better position to complete the squares.
x² +y² -4x -6y = -8
Now, we can add the squares of half the coefficients of the linear terms.
(x² -4x +4) +(y² -6x +9) = -8 +13 . . . . . . matches C
And we can simplify this to the standard form equation:
(x -2)² +(y -3)² = 5 . . . . . matches E
What operation can you use on both sides of the equation 100=100 +y to solve the equation for y? Solve the equation for y.
The equation 100 = 100 + y is an algebraic equation
The operation is subtraction property of equality, and the value of y is 0
How to solve the equation?The equation is given as:
100 = 100 + y
To solve for y, we apply the following operation
Operation: subtraction property of equality
So, we have:
100 - 100 = 100 - 100 + y
Evaluate the differences
0 = y
Rewrite as:
y = 0
Hence, the operation is subtraction property of equality, and the value of y is 0
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I hate these types of problems
I was never taught this stuff
A cyclist travels a distance of 837 1/2 feet in 25 seconds. The cyclist travels at a constant rate. What is the unit rate, in feet per second, at which the cyclist travels?
PLEASE
Answer:
[tex]\boxed{33.5 \ \text{feet/second}}[/tex]
Step-by-step explanation:
To find the unit rate, we need to find out how much distance does the cyclist travel in 1 second. For that, we need to use the unitary method. A unitary method is a method that determines the unit rate of an object.
Note: Since the cyclist travels at a constant rate, unitary method can be used.
[tex]\rightarrow 837 \dfrac{1}{2} \ \text{feet in 25 seconds}[/tex]
[tex]\rightarrow 837.5 \ \text{feet} = 25 \ \text{seconds}[/tex]
Divide both sides by 25:
[tex]\rightarrow \dfrac{837.5}{25} \ \text{feet} = \dfrac{25}{25} \ \text{seconds}[/tex]
[tex]\rightarrow 33.5 \ \text{feet} = 1 \ \text{seconds}[/tex]
[tex]\rightarrow \boxed{33.5 \ \text{feet/second}}[/tex]
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Kindly solve this question
Answer:
x=-1/7
Step-by-step explanation:
[tex]\frac{3x-1}{3} -\frac{2x}{x-1} =x[/tex]
[tex]\frac{(3x-1)(x-1)}{3x-3} -\frac{2x(3)}{3x-3} =x[/tex]
[tex]\frac{3x^2-4x+1}{3x-3} -\frac{6x}{3x-3} =x[/tex]
[tex]\frac{3x^2-10x+1}{3x-3} =x[/tex]
[tex]\frac{3x^2-10x+1}{3x-3} =\frac{x(3x-3)}{3x-3}[/tex]
[tex]\frac{3x^2-10x+1}{3x-3} =\frac{3x^2-3x}{3x-3}[/tex]
[tex]3x^2-10x+1=3x^2-3x[/tex]
[tex]-10x+1=-3x[/tex]
[tex]-7x=1[/tex]
[tex]x=-1/7[/tex]
Please help! I don't know what answer b is, but i know a, thank you.
They are corresponding angles
Step-by-step explanation:
We know that x=75⁰ because
[tex]180 - 105 = 75[/tex]
75⁰ is angle EFB
Since we know this, and because we know that AD//EH,
We can conclude that x=75⁰(AD is parallel to EH and angle CBA or x and angle EFB are corresponding angles)
Evaluate the triple integral. X dv, where e is bounded by the paraboloid x = 4y2 4z2 and the plane x = 4. E
The triple integral that is bounded by a paraboloid x = 4y2 4z2 given as 16.762
Parabloid, x = 4y² + 4z²
plane x = 4
x = 4y² + 4z²
x = 4
4 = 4y² + 4z²
4 = 4 (y² + z² )
1 = y² + z²
from polar coordinates
y = r cos θ
z = r sin θ
r² = y² + z²
The limits of the integral0 ≤ θ ≤ 2π
4r² ≤ x ≤ 4
0 ≤ r ≤ 1
[tex]\int\limits\int\limits\int\limits {x} \, dV = \int\limits^1_0\int\limits^a_b\int\limits^c_d {x} \, dx ( rdrdz)[/tex]
where
a = 4
b = 4r²
c = 2r
d = 0
The first integral using limits c and d gives:
[tex]2pi\int\limits^1_0\int\limits^a_b {xr} \, dx[/tex]
The second integral using limits a and b
[tex]pi\int\limits^1_0 {16 } } \, rdr - pi\int\limits^1_0 {16r^{5} \, dx[/tex]
[tex]16pi\int\limits^1_0 { } } \, rdr - 16pi\int\limits^1_0 {r^{5} \, dx[/tex]
[tex]16pi\int\limits^1_0 { } } \, [r-r^{5}]dr[/tex]
The third integral using limits 1 and 0 gives: 16.762
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The triple integral that is bounded by a paraboloid x = 4y2 4z2 given as 16.762
What is integration?Integration is defined as adding small parts to form a new significant part.
Parabloid, x = 4y² + 4z²
plane x = 4
x = 4y² + 4z²
x = 4
4 = 4y² + 4z²
4 = 4 (y² + z² )
1 = y² + z²
from polar coordinates
y = r cos θ
z = r sin θ
r² = y² + z²
The limits of the integral
0 ≤ θ ≤ 2π
4r² ≤ x ≤ 4
0 ≤ r ≤ 1
[tex]\int\int\intxdV = \int_0_1\int_b_a\int_d_cxdx(rdrdz)[/tex]
where
a = 4
b = 4r²
c = 2r
d = 0
The first integral using limits c and d gives:
[tex]2\pi\int_0^1\int_b^axydx[/tex]
The second integral using limits a and b
[tex]\pi \int_0^116rdr-\pi\int_0^116r^5dx[/tex]
[tex]16\pi \int_0^1rdr-16\pi\int_0^1 r^5dx[/tex]
[tex]16\pi\int_0^1[r-r^5]dr[/tex]
The third integral using limits 1 and 0 gives: 16.762
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please help asap
For each relation, decide whether or not it is a function.
Answer:
Step-by-step explanation:
Refer to the definition of a function. I'll just give you a layman's definition to be concise.
For something to be a function, there needs to be exactly 1 output for every input. You cannot have a case where you input 1 value, and get 2 or more values as an output.
In math we call all the possible input values the domain, and we call all the possible output values the range.
Let's take a look at each situation on your worksheet.
1. Is a function. This is because only one arrow stems from each input value. There are cases where the different input values give the same output, sure, but each input returns 1 discrete thing, not an array of things.
(Think of it this way, if i had a machine that could answer any question I had with yes, no or maybe. I wouldn't want the machine to give me "yes and maybe" or "yes and no" as the result when I ask it a question. That doesn't make sense and I would think the machine is broken. What could happen, is that I ask the machine different questions, and for those different questions, it gave me the same answer, like "yes" and "yes" respectively. in that case, it would be acceptable, because it isn't contradicting itself for any individual question.)
2. Not a function. There are 2 different output values for b.
(Refer back to my machine analogy. The "machine" in this question is contradicting itself. I gave the machine one input, and the machine is telling me, "it's this and actually it's this other thing too")
3. Is a function for the same reasons as 1.
4. Isn't a function.
(It's basically telling you, the machine reads -6 as -4, but it also reads -6 as 0, and also 2. And it also tells you the machine reads -4 as -3, but it also reads it as 8. Again, the machine should only read 1 input in 1 way and not contradict itself. )
These two figures have the same perimeter. Solve for x and find the perimeter.
(Please say the actual number and not a link please!)
Answer:
x=4, perimeter is 30.
Step-by-step explanation:
Let's calcualte the perimeter of the two figures. I'm assuming the pentagon is regular else the problem lacks information.
[tex]5(x+2) = 3x+(2x-1)+(x+7)\\5x+10=6x+6\\4=x[/tex]
At this point the easiest to compute is the pentagon, one side is 6, the whole perimeter is 30.
find the median of first 10 prime numbers
Y is the midpoint of XZ and W is the midpoint of VX.
If VZ=s+52 and WY=7s, what is the value of s?
Answer:
4
Step-by-step explanation:
By the triangle midsegment theorem, 2(WY)=VZ.
So, 2(7s)=s+52, meaning s=4.
What is the diameter of a hemisphere with the volume of 74466
[tex]\textit{volume of a hemisphere}\\\\ V=\cfrac{1}{2}\cdot \cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=74466 \end{cases}\implies 74466=\cfrac{1}{2}\cdot \cfrac{4\pi r^3}{3} \\\\\\ 74466=\cfrac{2\pi r^3}{3}\implies 223398=2\pi r^3\implies \cfrac{22398}{2\pi }=r^3\implies \cfrac{111699}{\pi }=r^3 \\\\\\ \sqrt[3]{\cfrac{111699}{\pi }}=r~\hfill \stackrel{\textit{diameter = 2r}}{2\sqrt[3]{\cfrac{111699}{\pi }}\implies \sqrt[3]{\cfrac{893592}{\pi }}}~~ \boxed{\approx~~65.77}[/tex]
The trapezoid below is made up of a square and a triangle. The total area of the trapezoid is 57.5 square meters. The area of the triangle is 32.5 square meters. What is the length of a side of the square?
Answer:
5 m
Step-by-step explanation:
The length of the side of a square is the root of the area of the square. The area of this square is the difference between the trapezoid area and the triangle area.
__
square area = trapezoid area - triangle area
square area = 57.5 m² -32.5 m² = 25 m²
Then the side length is ...
side length = √(square area) = √(25 m²)
side length = 5 m
The length of a side of the square is 5 m.
[tex] \sf \large \: find \: \frac{dy}{dx} \: if \: x=a ( \Theta + sin \Theta ) , y= a (1- Cos \Theta ) \: at \: \Theta = \frac{π}{2} \\ \\ \\ \\ \\ [/tex]
Kindly Don't Spàm!
Thanks!!!!
Given :
[tex] \: \: \: [/tex]
[tex] \rm \large \: x = a ( \Theta + Sin \Theta )[/tex][tex] \: \: \: [/tex]
[tex] \rm \large y = a ( 1 - cos \: \Theta )[/tex][tex] \: \: [/tex]
Now , x = a ( θ + sin θ )
[tex] \: \: [/tex]
Diff w.r.t " θ "
[tex] \: \: \: [/tex]
[tex] \rm \large\frac{dx}{dθ } = a \: \frac{d}{dθ} (θ + \sin\theta )[/tex][tex] \: \: [/tex]
[tex] \boxed{ \rm \large\underline{ \frac{dx}{d \theta} = a(1 + \cos \theta ) }}[/tex][tex] \: \: [/tex]
Now y = a ( 1-cosθ)
[tex] \: \: [/tex]
Diff w.r.t " θ " we get .
[tex] \: \: [/tex]
[tex] \rm \large \frac{dy}{d \theta} = a \frac{d}{d \theta} (1 - cos \theta) [/tex][tex] \: \: \: [/tex]
[tex] \boxed{ \rm \large \underline{ \frac{dy}{d \theta} = a \sin \theta}}[/tex][tex] \: \: \: [/tex]
From eqn ( 1 ) & ( 2 )
[tex] \: \: [/tex]
[tex] \rm \large \frac{dy}{dx} = \frac{ \frac{dy}{d \theta} }{\frac{dx}{d \theta}} [/tex][tex] \: \: \: [/tex]
[tex] \: \: \: \rm \large = \frac{ \cancel{a} \: sin \theta}{ \cancel a \: (1 + cos \theta)} [/tex][tex] \: \: [/tex]
[tex] \rm \large \: = \frac{sin \theta}{1 + \cos \theta } [/tex][tex] \: \: \: [/tex]
[tex] \rm \large \: \frac{2 \sin( \frac{\theta }{2} ) cos\frac{\theta }{2} }{2 \: cos ^{2} \frac{\theta }{2}} \: \: ......(sin \: a \: = 2 \: sin \frac{a}{2} \: cos \frac{a}{2} 1 + \: cos \: a \: = 2cos ^{2} \frac{a}{2} )[/tex][tex] \: \: [/tex]
[tex] \rm \large \: \frac{dy}{dx} = \frac{sin \frac{ \theta}{2} }{cos \frac{ \theta}{2} } [/tex][tex] \: \: [/tex]
[tex] \rm \large \: \frac{dy}{dx} = tan \frac{ \theta}{2} [/tex][tex] \: \: [/tex]
[tex] \rm \large \: ( \frac{dy}{dx} ) = tan \frac{ \frac{ \theta}{2} }{2} [/tex][tex] \: \: [/tex]
[tex] \rm \large \: = tan( \frac{ \theta}{4} )[/tex][tex] \: \: [/tex]
[tex] \boxed{ \rm \large \underline{ ( \frac{dy}{dx} ) = \frac{\pi}{2} = 1}}[/tex][tex] \: \: [/tex]
Hope Helps!:)
What quadrilaterals can you draw that have two sides with length 8 cm and two sides with length
5 cm?
Which of these quadrilaterals can have two sides with length
8 cm and two sides with length 5 cm?
Select all that apply.
OA. Trapezoid
OB. Square
OC. Parallelogram
OD. Rectangle
E. Kite
Answer:
C. parallelogram
D. rectangle
E. kite
Step-by-step explanation:
Cannot be the square because all sides are the same. A trapezoid can have two sides the same, but not two pairs of equal sides. The remaining shapes can have two pairs of equal length sides. see image.
If 12 workers can dig a tunnel in 100 days, how long will it take 20 workers to dig the tunnel
Answer:
60 days.
Step-by-step explanation:
This is a proportion question. You compare two ratios. Unfortunately it is an inverse ratio.
12 = k/100 Multiply both sides by 100
1200 = k
20 = k/x Multiply both sides by x
20x = k
20x = 1200 Divide by 20
20x/20 = 1200/20
x = 60 days.
An inverse proportion works by making a constant k. The constant k makes the days shorter when the number of people increases. You should expect that. More people , less time.
Maryan harvested a total of 22.69 t of rice and sold it in 100 kg bags. how many full bags did she sell
Answer:
1t = 1000kg
22.69 x 1000= 22690 kg
22690 kg ÷ 100 = 226.9
I would usually round it to 227 but I would say 226, since they are asking how many full bags she sold.
NO LINKS PLEASE
I NEED THEM TODAY
NO LINKS!!!
Answer:
13. True, False, True
14. False, True, True
15. All true
Find the equation of the line shown.
Answer:
(0,6) to (4,10) it might be the answer..........
The equation of the line passing through the points (0, 6) and (4, 10) is y = x + 6.
Here, we have,
To find the equation of the line passing through the points (0, 6) and (4, 10), we can use the slope-intercept form of a linear equation, which is given by:
y = mx + b,
where m is the slope of the line, and b is the y-intercept.
First, let's calculate the slope (m) using the formula:
m = (y₂ - y₁) / (x₂ - x₁),
where (x₁, y₁) = (0, 6) and (x₂, y₂) = (4, 10).
m = (10 - 6) / (4 - 0) = 4 / 4 = 1.
Now that we have the slope (m = 1), we can substitute it into the slope-intercept form along with one of the given points to find the y-intercept (b).
Using the point (0, 6), we have:
6 = 1(0) + b,
b = 6.
Therefore, the y-intercept (b) is 6.
Now we can write the equation of the line using the slope-intercept form:
y = mx + b,
y = 1x + 6,
y = x + 6.
Hence, the equation of the line passing through the points (0, 6) and (4, 10) is y = x + 6.
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4x+y=2 solve for y algebra 2
Answer:
Step-by-step explanation:
4x + y = 2
y = -4x + 2
Anyone know the answer to all of them added together
Answer:
13x + 14
Step-by-step explanation:
5x + 6 + 3x = 8x + 6.
8x + 6 + x + 1 + x + 1 + 2= 10x + 10
10x + 10 + (2²)(i think) = 10x + 14
10x + 14 + 3x = 13x + 14
final answer
Answer:
[tex]13x+14[/tex]
Step-by-step explanation:
First take all the sides and add:
[tex]5x+6+3x+3x+2+2+2+x+1+x+1[/tex]
Then Combine Like terms:
[tex]5x+3x+3x+x+x+6+2+2+2+1+1[/tex]
There is your answer:
[tex]13x+14[/tex]
(If I misunderstood the handwriting, please tell me, and I will fix my mistakes)
can you help me with this
Answer:
the anwer is b
I did the math
The value of stock changes from $22 on Monday to $30 on Tuesday. Calculate the percent increase.
22 + 22 x r = 30
22 x r = 30 - 22
r = 8 : 22
r = +36,36%
r = increase rate
Factor: 35b + 15c -10
Answer:
5(7b+3c-2)
Step-by-step explanation:
Common factor of 5
35b/5= 7b
15c/5= 3c
-10/5= -2
Take the common factor and multiply it by the quotients
5(7b+3c-2)
Miranda's heart beats 3 times every 2 secounds. At that rate, how many times does her heart beat in 1 minute?
PLEASE I NEED HELP WITH THIS!! BRAINLIEST FOR THE FASTEST ANSWER
Answer:
B - 2093 in cubed
Step-by-step explanation:
Use the formula 4/3 * pi * r^3 to find the volume of one basketball, using 5 as the radius. Next, multiply this number by 4 to find the volume of 4 basketballs. The answer should be option B.
Hopefully this helps- let me know if you have any questions!
Answer:V≈268.08
Step-by-step explanation:Volume of a sphere: V = (4/3)πr. times 4 equals V≈268.08. i think this is it!! i hope it works loe you have an amazing day:) -marina mae
Solve for b
SOLVE ASAP!!
Answer:
Step-by-step explanation:
<A and <B are alternate interior angles. That means they are in the interior of the parallel lines and they are on opposite sides of the transversal.
When that happens <A = <B
8x + 78 = 2x + 114 Subtract 2x from both sides.
8x - 2x + 78 = 2x - 2x + 114 Combine
6x + 78 = 114 Subtract 78 from both sides
6x + 78 - 78 = 114 - 78
6x = 36 Divide by 6
6x/6 = 36/6
x = 6
I think you are asked for B
<B = 2x + 114
<B = 2*6 + 114
<B = 12 + 114
<B = 126
Donald said that the median is 2. What did he do wrong?
8,13,2,4,48
Answer:
He did not put the numbers in order.
Explanation:
The numbers need to be in order from smallest to largest before you find the median.