copper melting is a reversible or irreversible.

Answers

Answer 1

Answer:

Its a physical change so its reversible

Explanation:

hope it helps


Related Questions

Explain ocean currents and how density differences between HOT/COLD and SALT/FRESH affect them.

-for science

Answers

Density differences caused by temperature and salinity variations are fundamental drivers of ocean currents of seawater . Warm currents transport heat from the equator to higher latitudes, while cold currents transport cold water from higher latitudes to lower latitudes.

When seawater is heated, it expands and becomes less dense, causing it to rise. Conversely, when seawater cools, it contracts and becomes denser, causing it to sink. These density differences due to temperature variations create vertical movements in the ocean known as thermohaline circulation or convection currents. On the other hand, regions with high freshwater input from rivers or heavy precipitation have lower salinity, resulting in lower density. This lighter water tends to float on the denser seawater beneath it, leading to the formation of surface currents that transport water from areas of low salinity to areas of higher salinity. These ocean currents play a vital role in shaping global climate patterns and maintaining the balance of heat and nutrients in the ocean ecosystem.

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Sulfur oxides and nitrogen oxides are pollutants that are produced when fossil fuels are burned. Sulfur oxides and nitrogen oxides react with water in the atmosphere, which leads to the production of sulfuric acid and nitric acid, and thus acid rain. Rainwater is naturally acidic and has a pH of approximately 5.6, but acid rain has a lower pH, sometimes below 4. Which of the following correctly compares the concentration of H+ in acid rain with a pH of 4.6 and the concentration of H* in rain that is naturally acidic and has a pH of 5.6?

A
The H* concentration in the acid rain is a factor of (5.6) times higher than the H* concentration in the rain that is naturally acidic.
B
The H* concentration in the acid rain is 2 times higher than the H* concentration in the rain that is naturally acidic

C
The HI* concentration in the acid rain is 4.6 times higher than the HI* concentration in the rain that is naturally acidic.
D
The H* concentration in the acid rain is 10 times higher than the HI concentration in the rain that is naturally acidic.

Answers

The hydrogen ion concentration in the acid rain is 10 times higher than the HI concentration in the rain which is naturally acidic. Option D.

pH and acid rain

The pH scale is logarithmic, which means that a change of one pH unit represents a ten-fold change in hydrogen ion concentration.

Rainwater that is naturally acidic and has a pH of 5.6 has a hydrogen ion concentration of [tex]10^{5.6[/tex] moles per liter.

Acid rain with a pH of 4.6 has a hydrogen ion concentration of [tex]10^{4.6[/tex] moles per liter.

Therefore, the ratio of H+ concentration in acid rain to that in naturally acidic rain can be calculated as:

[H+] in acid rain / [H+] in naturally acidic rain = 10^(-4.6) / 10^(-5.6) = 10^(1) = 10

This means that the concentration of hydrogen ion in acid rain with a pH of 4.6 is 10 times higher than the concentration of H+ in rain that is naturally acidic and has a pH of 5.6.

In other words, the hydrogen ion concentration in the acid rain is 10 times higher than the hydrogen ion concentration in the rain which is naturally acidic.

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The single strand of nucleic acid shown is representative of

A). RNA
B). DNA
C). both RNA and DNA
D). protein

Answers

RNA.. it has single strand

Sputnik is the Russian name for __________.

Answers

Satellite would be the answer

How do the varying characteristics of Earth's atmospheric layers affect the types of wavelengths that are reflected back into space, absorbed or allowed to pass to Earth's surface?

Answers

The specific characteristics of the layers that make up the Earth's atmosphere affect the types of wavelengths that are reflected. Troposphere, stratosphere, and mesosphere are the three layers.

The stratosphere, which contains the ozone layer, is the next layer. The sun's dangerous UV light is absorbed by ozone, keeping it from reaching the surface of the Earth. Visible light and some infrared radiation can travel through this layer.

The mesosphere is located above the stratosphere, where the majority of meteoroids burn up as they enter the atmosphere of the Earth.

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Please help me ASAP!!!

Answers

240.1g is the mass of sodium propanoate. Mass was widely considered to be tied to the amount of matter within a physical body.

A body's mass is an inherent quality. Prior to the discoveries of the atom or particle physics, it was discovered that, despite having the same quantity of matter in theory, various atoms and elementary particles had varied masses. There are several conceptions of mass in contemporary physics that are theoretically different but practically equivalent. The resistance of the body to acceleration (alterations of velocity) in the presence of a net force may be measured experimentally as mass.

pH =Pka + log [salt]/[acid]

4.87=4.87+ log [salt]/[1]

4.87=4.87+ log [salt]/[1]

[salt] = 10 mol dm⁻³

mole = molarity ×volume

mole = 10×0.25

          =2.5

mass = 2.5×96.07

        = 240.1g

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URGENT! What is the classification of benzyl benzoate? (Besides organic compound)

Answers

Answer:

Benzyl benzoate is a type of aromatic ester compound. It can also be classified as a benzyl compound, a benzoate ester, and a fragrant substance. In addition, it is commonly used as a solvent, a fixative, and a fragrance in various industries such as cosmetics, pharmaceuticals, and food.

Explanation:

A student pours 50 g of hot water at 72 °C into a Styrofoam cup with 50 g of water at 25
°C. After a few minutes the water temperature is 43 °C. How much heat did the cup itself
absorb? (Hint Q for hot water = Q of cold water and Q for the cup. You do not need to
know the mass of the cup).

PLEASE HELP ASAPP

Answers

The amount of heat energy absorbed by the cup, given that 50 g of hot water at 72 °C was poured into the styrofoam cup with 50 g of water at 25 °C is 2301.2 J

How do i determine the heat absorbed by the cup?

First, we shall obtain the heat absorbed by the cold water. Details below:

Mass of  cold water (M) = 50 gInitial temperature of cold water (T₁) = 25 °CFinal temperature of cold water (T₂) = 43 °CChange in temperature (ΔT) = 43 - 25 = 18 °C Specific heat capacity of water (C) = 4.184 J/gºC Heat absorbed by cold water (Q) =?

Q = MCΔT

Q = 50 × 4.184 × 18

Q = 3765.6 J

Next, we shall obtain the heat release by the hot water

Mass of hot water (M) = 50 gInitial temperature of hot water (T₁) = 72 °CFinal temperature of hot water (T₂) = 43 °CChange in temperature (ΔT) = 43 - 72 = -29 °C Specific heat capacity of water (C) = 4.184 J/gºC Heat release by hot water (Q) =?

Q = MCΔT

Q = 50 × 4.184 × -29

Q = -6066.8 J

Note: The negative shows that heat is released.

Finally, we shall obtain the heat absorbed by the cup. Details below:

Heat absorbed by cold water = 3765.6 JHeat release by hot water = 6066.8Heat absorbed by cup = ?

Heat absorbed by cup = Heat release by hot water - heat absorbed by cold water

Heat absorbed by cup = 6066.8 - 3765.6

Heat absorbed by cup = 2301.2 J

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Post Test: Energy and Changes in Matter
Select the correct answer.
A student places a 12-gram cube of ice inside a container. After six hours, the student returns to observe the contents of the container. Which sentence
suggests that the container is an open system?
O A. The container contains 12 grams of liquid water and no ice.
O B.
The container contains 12 grams of ice and no liquid water.
OC. The container contains 8 grams of liquid water and no ice.
OD. The container contains 8 grams of ice and 4 grams of liquid water.
OE.
The container contains 8 grams of liquid water and 4 grams of water vapor.
Reset
R
mant
S
Submit Test
Next
>

Answers

The sentence that suggests that the container is an open system is option C: "The container contains 8 grams of liquid water and no ice."

In an open system, matter can freely enter or leave the system. In this case, if the container contains only liquid water and no ice, it indicates that some of the ice has melted and the resulting liquid water has escaped from the container. This suggests that matter (in the form of liquid water) has left the system, indicating an open system.

Option A suggests that the container contains 12 grams of liquid water and no ice, which implies that all of the ice has melted and the liquid water remains inside the container. This does not necessarily indicate an open system as the liquid water could still be contained within a closed system.

Option B suggests that the container contains 12 grams of ice and no liquid water, indicating that none of the ice has melted. This does not provide information about the system being open or closed.

Option D suggests that the container contains 8 grams of ice and 4 grams of liquid water, indicating that some of the ice has melted but the liquid water remains inside the container. This does not necessarily indicate an open system as the liquid water could still be contained within a closed system.

Option E suggests that the container contains 8 grams of liquid water and 4 grams of water vapor. This indicates a phase change from liquid to vapor, but it does not provide information about whether the system is open or closed.

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A car tire is inflated to 82.0 kPa in a repair shop where the temperature is 26.0 C
what is the temperature of the air inside the tire is the pressure increases to 87.3 kPa, when the car is taken outside

Answers

To determine the temperature of the air inside the tire when the pressure increases to 87.3 kPa, we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

Assuming the volume of the tire remains constant, we can rearrange the equation as follows:

P₁/T₁ = P₂/T₂

Where:

P₁ = initial pressure (82.0 kPa)

T₁ = initial temperature (26.0 °C + 273.15 K) [converting Celsius to Kelvin]

P₂ = final pressure (87.3 kPa)

T₂ = final temperature (unknown)

Substituting the values into the equation:

82.0 kPa / (26.0 °C + 273.15 K) = 87.3 kPa / T₂

Now, let's solve for T₂:

T₂ = (87.3 kPa * (26.0 °C + 273.15 K)) / 82.0 kPa

Calculating the expression:

T₂ ≈ 299.19 K

To convert this temperature back to Celsius:

T₂ ≈ 299.19 K - 273.15 ≈ 26.04 °C

Therefore, the temperature of the air inside the tire, when the pressure increases to 87.3 kPa, is approximately 26.04 °C.

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Write the equation that relates the rate expressions for this reaction in terms of the disappearances of Cl2 and F2 and the formation of ClF3

Answers

The equations indicate that the rate of disappearance of Cl2 is half the rate of formation of ClF3, and the rate of disappearance of F2 is three times the rate of formation of ClF3.

The rate equation for the reaction between Cl2 and F2 to form ClF3 can be written in terms of the disappearance of Cl2 and F2 and the formation of ClF3. Let's denote the rate of disappearance of Cl2 as r1, the rate of disappearance of F2 as r2, and the rate of formation of ClF3 as r3.

Based on the stoichiometry of the reaction, we can write the balanced equation as:

Cl2 + 3F2 → 2ClF3

The rate expressions can be expressed as:

r1 = -d[Cl2]/dt

r2 = -d[F2]/dt

r3 = d[ClF3]/dt

The relationship between the rate expressions can be described by the reaction stoichiometry:

r1 = (1/2) r3

r2 = (3/2) r3

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Explain how you would write the expression for the following reaction:

2 X (g) + 3 Y (s) <---> Z (g) + 2 W (g)

Answers

The equilibrium expression of the reaction is;

[tex]K = [Z] [W]^2/[X]^2 [Y]^3[/tex]

What is the equilibrium expression?

The equilibrium condition for a chemical reaction is represented mathematically by the equilibrium expression. It relates the reactant and product concentrations (or pressures) at equilibrium.

The law of mass action serves as the basis for the equilibrium expression.

From the reaction;

2 X (g) + 3 Y (s) <---> Z (g) + 2 W (g), the equilibrium expression would be;

[tex]K = [Z] [W]^2/[X]^2 [Y]^3[/tex] as derived from the reaction equation shown.

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A balloon is filled to a volume of 2.20L at a temperature of 25.0*C. The balloon is then heated to a temperature of 51*C. Find the new volume of the balloon

Answers

The new volume of the balloon after heating it to a temperature of 51 °C is approximately 2.39 L.

What is the final volume of the balloon?

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]

Given that:

Initial temperature of gas T₁ = 25°C = (25.0 + 273.15) = KInitial volume of gas V₁ = 2.2 LFinal temperature T₂ =  51 °C = ( 51 + 273.15 ) = 324.15 KFinal volume V₂ = ?

Substituting the given values and solve for V₂:

[tex]V_1T_2 = V_2T_1\\\\V_2 = \frac{V_1T_2}{T_1} \\\\V_2 = \frac{2.2\ *\ 324.15}{298.15 }\\ \\V_2 = 2.39 \ L[/tex]

Therefore, the final volume is 2.39 litres.

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To which homologous series does CH₂CH₂ CH₂CH₂ belong?​

Answers

The homologous series that CH₂CH₂ CH₂CH₂ belongs to is alkene.

What is homologous series?

Homologous series is any series of aliphatic organic compounds whose members differ only in the addition of a CH₂ group.

The members of the homologous series are as follows;

AlkaneAlkeneAlkyne

Alkene is an unsaturated, aliphatic hydrocarbon with one or more carbon–carbon double bonds.

According to this question, the above given compound is butene (a member of alkene) because it has four carbon atoms and 8 hydrogen atoms.

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PLEASE HELP THIS IS DUE IN 10 MORE MINUTES I WILL GIVE YOU 50 POINTS ANSWER THE QUESTIONS BELOW AND THE QUESTION IN THE IMAGE!

1. Light always travels in a straight line until something gets in its way.
True or False

2. Waves carry energy. The amount of energy they carry is related to their frequency and their amplitude.
True or False

3.The higher the frequency of a wave, the more energy, and the higher the amplitude of a wave, the more energy.
True or False

Answers

1. It is true that light always travels in a straight line

2. It is true that the amount of energy they carry is related to their frequency and their amplitude.

3. It is true that the higher the frequency of a wave, the more energy, and the higher the amplitude of a wave, the more energy.

What is a wave?

A wave is an oscillation or disturbance that moves through a medium or space and transmits energy from one point to another without actually moving any physical objects.

Water waves, sound waves, light waves, and electromagnetic waves are just a few examples of the many varied shapes and settings in which waves can occur.

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2. Given the following sets of values, calculate the unknown quantity.
P=200kPa V= 0.602 L n = ? (g of CO₂) T = 311 K
ignore (g of CO2) in the question just find
the number of molecule

Answers

The approximate number of molecules in the given set of values is 2.823 × 10²² molecules of CO₂.To calculate the number of molecules (n) of CO₂, we can use the ideal gas law equation:PV = nRT

Where:

P = Pressure (in kPa)

V = Volume (in liters)

n = Number of moles

R = Ideal gas constant (8.314 J/(mol·K))

T = Temperature (in Kelvin),First, let's convert the pressure from kPa to atm (atmospheres) since the ideal gas constant is usually expressed in atm:

1 atm = 101.325 kPa

So, 200 kPa is approximately 1.973 atm.

Now, rearranging the ideal gas law equation to solve for n:

n = (PV) / (RT)

n = (1.973 atm * 0.602 L) / (0.0821 L·atm/(mol·K) * 311 K)

n ≈ 0.0469 mol

Since 1 mole of any substance contains Avogadro's number (6.022 × 10²³) of molecules, the number of molecules (N) can be calculated by multiplying the number of moles by Avogadro's number:

N = n * Avogadro's number

N = 0.0469 mol * (6.022 × 10²³ molecules/mol)

=N ≈ 2.823 × 10²² molecules

Therefore, the approximate number of molecules in the given set of values is 2.823 × 10²² molecules of CO₂.

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Which of the following are not empirical formulas?

I. NO2

II. C6H6O2

III. C6H14N2O6

IV. PCl3

Answers

II (C6H6O2) and III (C6H14N2O6) are not empirical formulas.

What are empirical formulas?

The empirical formula of a chemical compound are known to be the simplest whole number ratio of atoms present in a compound.

The empirical formula for C6H6O2 is CH3O and the emperical formula for C6H14N2O6 isC3H7NO3.

NO2 is the empirical formula for nitrogen dioxide. And PCl3 is the empirical formula for phosphorus trichloride.

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Space shuttles are made out of three main parts: rocket boosters, a fuel tank, and a(n) ___________.

Answers

Answer:

Orbiter

Explanation:

Space shuttles are made out of three main parts: rocket boosters, a fuel tank, and orbiter (the part that resembles an airplane

In which type of chemical reaction do two or more substances combine to form one substance?
Osynthesis
Odecomposition
single replacement
Odouble replacement

Answers

The type of chemical reaction where two or more substances combine to form one substance is known as a synthesis reaction.

In a synthesis reaction, multiple reactants react with each other to produce a single product.

Synthesis reactions are characterized by the formation of new chemical bonds and the creation of a more complex compound from simpler substances. This reaction type is commonly observed in various chemical processes and natural phenomena.

The general equation for a synthesis reaction is:

A + B → AB

In this equation, A and B represent the reactants, while AB represents the product. The reactants can be elements, compounds, or a combination of both. When they combine, their atoms or molecules rearrange and bond together to form the product.

Synthesis reactions are essential for the formation of many substances. For example, the combination of hydrogen and oxygen through a synthesis reaction produces water:

2H₂ + O₂ → 2H₂O

Another example is the synthesis of sodium chloride (table salt) from sodium and chlorine:

2Na + Cl₂ → 2NaCl

Synthesis reactions are also prevalent in organic chemistry, where complex molecules are formed by combining simpler organic compounds.

Overall, synthesis reactions play a fundamental role in chemistry, contributing to the formation of new substances and the understanding of chemical processes.

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When 345 g of water at 35.0 °C and 295 g of water at 63.0 °C are added together *
in a calorimeter, the temperature of the mixture becomes 46.9 °C. If the specific
heat capacity of water is 4.18 J/g °C, how many joules of energy are absorbed by
the calorimeter?

A. 1592 J

B 2690 J

C. 3000 J

D. 3458 J

Answers

The amount of energy absorbed by the calorimeter is 5597.92 J. Option A.

Energy transfer

Using the formula:

Q = mcΔT

Where Q is the heat absorbed by the calorimeter, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Total mass of water = 345 g + 295 g = 640 g

Average temperature of the 2 water samples  = (35.0 °C + 63.0 °C)/2 = 49.0 °C

ΔT = 46.9 °C - 49.0 °C = -2.1 °C

Now, let's calculate the heat absorbed by the calorimeter:

Q = (640 g)(4.18 J/g °C)(-2.1 °C)

Q = -5597.92 J

Note that we have a negative value for Q because the calorimeter is absorbing heat from the water mixture.

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A calorimeter consists of metal parts with a heat capacity of 925.0 J/K and 1100 grams of oil with specific heat 2.814J/g K. What is the heat capacity, in joules per degree, of the entire assembly?

Answers

The heat capacity of the entire assembly is 4019.4 joules per degree Kelvin.

To calculate the heat capacity of the entire assembly, we need to consider the heat capacities of the metal parts and the oil separately, and then sum them up.

The heat capacity of the metal parts is given as 925.0 J/K. This means that for every 1 degree Kelvin (or Celsius) increase in temperature, the metal parts can absorb or release 925.0 joules of heat.

The oil has a specific heat of 2.814 J/g K. This means that for every 1 gram of oil and 1 degree Kelvin increase in temperature, it can absorb or release 2.814 joules of heat.

Given that there are 1100 grams of oil in the calorimeter, we can calculate the heat capacity of the oil as follows:

Heat capacity of oil = specific heat of oil × mass of oil

= 2.814 J/g K × 1100 g

= 3095.4 J/K

To find the heat capacity of the entire assembly, we sum the heat capacities of the metal parts and the oil:

Heat capacity of entire assembly = heat capacity of metal parts + heat capacity of oil

= 925.0 J/K + 3095.4 J/K

= 4019.4 J/K

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What is the mass, in grams, of a COCl2 sample that contains
1.55×1025 Cl atoms?

Answers

Answer:1.55x

Explanation: just do it

305.79 of 0₂ burned with C₂H6 How many
moles of CO2

Answers

Answer:

The amount of CO₂ produced can be calculated using the mole ratio of CO₂ to C₂H6:

2 mol CO₂ / 1 mol C₂H6 = x mol CO₂ / 1.01 mol C₂H6

x = 2 mol CO₂ / 1 mol C₂H6 × 1.01 mol C₂H6 = 2.02 mol CO₂

Therefore, 2.02 moles of CO₂ were produced.

1. What type of organic compounds are the reactants in an esterification reaction?

Answers

Esterification is the process that turned salicylic acid and acetic acid into acetylsalicylic acid.

Thus,  The process of creating esters from carboxylic acids is known as esterification. When a carbon is linked to two oxygen atoms, an ester results from one of the oxygens being double-bonded to the carbon while the other oxygen is linked to another carbon.

The letter "R" stands for a carbon chain in the following generic formula for an ester.

Esterification occurs when a carboxylic acid reacts with an alcohol. This reaction can only occur in the presence of an acid catalyst and heat. It takes a lot of energy to remove the -OH from the carboxylic acid, so a catalyst and heat are needed to produce the necessary energy.

Thus, Esterification is the process that turned salicylic acid and acetic acid into acetylsalicylic acid.

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How many sigma bonds found in 1 chloro, 1,3 penta-diene

Answers

There are 6 sigma bonds in 1-chloro-1,3-pentadiene.

In 1-chloro-1,3-pentadiene, let's break down the structure to count the number of sigma bonds

The compound 1-chloro-1,3-pentadiene has the following structure:

Cl

H2C=C=CH-CH2-CH3

To count the sigma bonds, we examine each carbon atom and its attached atoms or groups.

Starting from the left side:

The first carbon (C1) is bonded to one hydrogen (H) atom and two other carbon atoms (C2 and C3) by sigma bonds.

The second carbon (C2) forms a double bond with the third carbon (C3), so they share one sigma bond and one pi bond.

The third carbon (C3) is also bonded to the second carbon (C2) and the fourth carbon (C4) by sigma bonds.

The fourth carbon (C4) is bonded to the third carbon (C3) and the fifth carbon (C5) by sigma bonds.

The fifth carbon (C5) is bonded to one hydrogen (H) atom and one methyl (CH3) group by sigma bonds.

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The following set of reactions show
burning hydrogen and the reverse
process, electrolysis of water. What is
the missing change in enthalpy? Only
put in the numerical value. (The bond
energy of H-H is 432 kJ/mol was used
in the first equation. Other bond
energies are on this form, IF you need
it.)
_2_H₂ + _1_0₂_2_H₂O
_2_H₂O →_2_H₂ +_1_O₂
ΔΗrxn=-498 kJ/mol
ΔΗrxn= ??? kJ/mol

Answers

The missing value for ΔHrxn is -2226 kJ/mol as the enthalpy change that is missing is equal to -498 kJ/mol - 1728 kJ/mol.

Thus, two moles of hydrogen join with one mole of oxygen in the first reaction to create two moles of water. H-H has a 432 kJ/mol bond energy. The energy needed to break these bonds is 4 432 kJ/mol, or 1728 kJ/mol, because there are four moles of H-H bonds broken and two moles of hydrogen.

However, one mole of O=O bonds and four moles of O-H bonds are created, and their combined bond energies are unknown, determined by using the formula ΔHrxn = (energy released in bond creation) - (energy needed in bond breaking). ΔHrxn = -498 kJ/mol, hence the enthalpy change that is missing is equal to -498 kJ/mol - 1728 kJ/mol = -2226 kJ/mol.

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Krypton-79 has a half life of 35 hours. How many half lives have passed after 70 hours?

a.1
b.2
c.3
d.4

Answers

Answer: b.2

Explanation:

3 is the answer because it’s obvious


Urgent help please
Question 9 (1 point)
What is the pressure of a sample of Xenon gas that originally occupied 4.0L at a
pressure of 4.3atm, if the volume is increased to 9.OL?
Your Answer:
Answer
units

Answers

Answer:

9.7atm

Explanation:

Ideal gas laws let us find different characteristics of gas through its changes.

Boyle's Law

Boyle's law describes the relationship between pressure and volume. This law states that volume and pressure are inversely proportional. This means that as volume increases, pressure decreases. In equation form, Boyle's law is:

P₁V₁ = P₂V₂

In the question, the new volume is greater than the original. This means that the new pressure must be less than the original pressure.

Solving for P₁

In order to find the original pressure, we can plug in the information we know.

P₁ * 4.0L = 4.3atm * 9.0L

Now, divide both sides by 4.0L.

P₁ ≈ 9.675atm

This pressure is greater than 4.3atm, which follows the prediction we made earlier. So, this is a reasonable answer. Since this question involves measured values, we should round according to significant figure rules. This means that the original pressure is 9.7atm.

The temperature of a 150.0 g sample of aluminum rises from 25°C to 40°C after it has been
placed on a hot plate. Calculate how much heat was transferred, and state whether it was
gained or lost based on the sign of your answer.
Q=
Gained or Lost:

PLEASE HELP!!!!

Answers

Answer:

Q = 2.0 x 10³ J

Explanation:

Using the change in temperature, we can find the heat transfer.

Heat Transfer

An increase in temperature is caused by absorbing energy. This means that the aluminum must have absorbed energy in order to rise in temperature. Since energy is being absorbed, the Q-value should be positive.

The equation for heat transfer is:

Q = mcΔT

In this equation, Q is energy, m is mass, c is the specific heat, and ΔT is the change in temperature. Specific heat is a constant that every substance has that describes how much energy is needed to heat up the substance. These values can be found in a data table.

Solving for Q

To find Q, we can plug in the known values and solve. The question states that there are 150.0g of Al. The specific heat of Al is 0.897 J/g*C. Also, since 40-25 = 15, the change in temperature is +15°C.

Q = 150.0 * 0.897 * 15Q ≈ 2018.25 J

Since this question is based on measured values, we need to round according to significant figures. Our answer should have 2 sig figs. This means the answer rounds down to 2000J; however, this only has 1 sig fig. So, we need to use scientific notation to write our answer.

Given that Q is positive, the aluminum gains 2.0 x 10³ J of energy.

The question is below in the file

Answers

Answer:

A

Explanation:

just do it

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