Consider the incomplete paragraph proof.

Given: P is a point on the perpendicular bisector, l, of MN.
Prove: PM = PN

Line l is a perpendicular bisector of line segment M N. It intersects line segment M N at point Q. Line l also contains point P.

Because of the unique line postulate, we can draw unique line segment PM. Using the definition of reflection, PM can be reflected over line l. By the definition of reflection, point P is the image of itself and point N is the image of ________. Because reflections preserve length, PM = PN.

point M
point Q
segment PM
segment QM

The inequality that models this situation is 150x + 350 y ≤ 250000 and x + y < 1200

An inequality is an expression that shows the non equal comparison of two or more numbers and variables.

Let x represent the number of wheat acres and y represent the number of corn acres, hence:

150x + 350 y ≤ 250000     (1)

Also:

x + y < 1200     (2)

The inequality that models this situation is 150x + 350 y ≤ 250000 and x + y < 1200

Find out more on inequality at: https://brainly.com/question/24372553

Answer:

Answer: C. 45 minutes before 7:00

Hope this helps! :)

Brainliest please.

Answer:

Step-by-step explanation:

Answer:

14%

Step-by-step explanation:

lets whip out that EPIC CALCULATOR! alright so i hope that you have your calculator with you, whether it is a physical one or a digital one on your computer.

try this:

enter 14, then the division sign ( could be a ÷ or an / ) and then 100.

what do we get?

0.14

ok, now lets multiply this by 100 to get the PERCENT instead of the DECIMAL, and we get
14%

EPIC!

Multiply the probability of each by each other:

Probability of red = 1/4

Probability of blue = 1/4

Probability of green = 2/4 = 1/2

probability of red then blue then green = 1/4 x 1/4 x 1/2 = 1/32

answer: 1/32

Equation 1: x=32

Equation 2: y=28

Answer:

x  = 32

x = 28

Step-by-step explanation: hope this helps

Hey there!

Combine Like Terms and see if the expressions are equivalent or not.

6x-4-x

6x-x-4

5x-4

Is 5x-4 equivalent to 7x-4? No.

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

Answer:

Given;  7x – 4 and 6x – 4 – x

To Find; how you can tell if the expressions 7x – 4 and 6x – 4 – x are equivalent

Solution; This question can be easily solved by letting some value of x and putting in both the equation to check whether both are equal or not

Let x=1

7x-4=3 and 5x-4=1

Since both are not equal Hence the given equations are not equalnation:

the answer is ISABELLA YOUR BOYFRINDS HERE

Answer:

Ok, to find MAD, you have to add up all of the decimals in the set, and then divide by how much decimals there are in the set.

Adding them all up...

The final result of the adding is 56.7

Now, we have to divide by how much decimals.

We now have. 56.7 / 6

Do the division.

56.7 / 6 ===> 9.45

No need to round, the final answer is 9.4

Answer:

64 cm³

Step-by-step explanation:

The volume of a cube is an edge cubed. Since all the sides/edges are the side, you do 4 * 4 * 4 which gets 64

Answer:

Yes you want to do it again soon

Answer:

x+y=4

Step-by-step explanation:

hello :

note :  by identity  you have   x²-y² = (x-y)(x+y)

in this exercice : 2x²-2y² = 2(x²-y²) = 2 (x-y)(x+y)

means :   2 (x-y)(x+y) = 40

but x-y = 5

so : 2(5)(x+y) =40

x+y=40/10

x+y=4

draw a market and place the point (4 ; 1)

then you go on your right : 4 units

and go down : 3 units

you place a second point

and now you can graph the line

The square miles that was burned if one square mile is 640 acres is 840.625 square miles.

Division is the process of grouping a number into equal parts using another number. The sign used to denote division is ÷. Division is one of the basic mathematical operations.

Square miles that was burned = 538,000 / 640 = 840.625 square miles

To learn more about division, please check: https://brainly.com/question/13281206

There are 840.625 square miles did the fire burn.

Division is the process of sharing a collection of items into equal parts and is one of the basic arithmetic operations in maths.

The wallow fire of 2011 burned 538,000 acres in eastern Arizona.

The area of square miles did the fire burned is;

[tex]\rm Area =\dfrac{538,000}{640}\\\\Area =840.625 \ square \ miles[/tex]

Hence, there are 840.625 square miles did the fire burn.

To learn more about division here:

brainly.com/question/13281206

#SPJ4

Answer:

Step-by-step explanation:

Notation for Cereal Set Roster

The roster form is one of the simplest ways to represent the set. The elements of a set are represented in a row and separated by a comma in roster form. For example, the first five positive even numbers are denoted as A = 2, 4, 6, 8, 10.

A = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100 is an example of roster notation: A = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100.

Hope that helps you understand :)

Answer:

As Per Provided Information

A cylinder has a volume of 320 pi cubic inches and a height of 5 inches.

We have been asked to determine the radius of the cylinder .

Using Formulae

[tex] \purple{\boxed {\bf\: Volume_{(Cylinder)} = \pi {r}^{2}h}}[/tex]

Substituting the value and let's solve for radius .

[tex] \sf \qquad \longrightarrow \: 320 \pi \: = \pi \: \times r {}^{2} \: \times 5 \\ \\ \\ \sf \qquad \longrightarrow \:320 \cancel{\pi} = \cancel{ \pi} \times r {}^{2} \: \times 5 \\ \\ \\ \sf \qquad \longrightarrow \:320 = r {}^{2} \: \times 5 \\ \\ \\ \sf \qquad \longrightarrow \:r {}^{2} \: = \cfrac{320}{5} \\ \\ \\ \sf \qquad \longrightarrow \: {r}^{2} = \cancel\cfrac{320}{5} \\ \\ \\ \sf \qquad \longrightarrow \: {r}^{2} = 64 \\ \\ \\ \sf \qquad \longrightarrow \:r \: = \sqrt{64} \\ \\ \\ \sf \qquad \longrightarrow \:r \: = 8 \: inch[/tex]

Therefore,

Step-by-step explanation:

[tex]volume = \pi {r}^{2}h[/tex]

[tex]695 = 3.14 \times {r}^{2} \times 11.5[/tex]

[tex] {r}^{2} = 19.2[/tex]

[tex]r = \sqrt{19.2} = 4.3[/tex]

Answer:

  17.34 years

Step-by-step explanation:

The equation you wrote in the first part of the problem can be solved for the value of t that makes the population be 5000.

  [tex]P(t)=\dfrac{10000}{1+11.5e^{-0.1408614477t}}[/tex]

Setting this equal to 5000 and multiplying by the denominator, we have ...

  [tex]5000=\dfrac{10000}{1+11.5e^{-0.1408614477t}}\\\\5000+57500e^{-0.1408614477t}=10000\\\\e^{-0.1408614477t}=\dfrac{5000}{57500}\qquad\text{subtract 5000, divide by 57500}\\\\-0.1408614477t = \ln{\dfrac{1}{11.5}}=-\ln(11.5)\qquad\text{take logs}\\\\t=\dfrac{\ln(11.5)}{0.1408614477}\approx17.3386[/tex]

For the population to reach 5000, it will take about 17.34 years.

_____

Additional comment

The value -0.14086... is the natural log of the ratio 1818/2093. This means the "exact answer" is ln(11.5)/(ln(2093) -ln(1818)), an irrational number.

A graphing calculator can answer the question easily.

The answer for this equation funtion would be The first one because it is the correct answer.

Answer:

Step-by-step explanation:

Answer: High quality services cause customers to return for additional meals.

Step-by-step explanation:  The 90% crosses out the first option. Because it's 90% we don't know if all the customers reported their service. The last one just to me wouldn't make sense.

Answer:

(a)

Step-by-step explanation:

the equation of a circle centred at the origin is

x² + y² = r² ( r is the radius )

x² + y² = 20 ← is in this form , then

centre = (0, 0 ) and r = [tex]\sqrt{20}[/tex] = [tex]\sqrt{4(5)}[/tex] = [tex]\sqrt{4}[/tex] × [tex]\sqrt{5}[/tex] = 2[tex]\sqrt{5}[/tex]

[tex]tan(\theta )=\sqrt{3}\implies tan(\theta )=\cfrac{\sqrt{3}}{1}\implies tan(\theta )=\cfrac{\sqrt{3}}{1}\cdot \cfrac{2}{2} \implies tan(\theta )=\cfrac{\sqrt{3}}{2}\cdot \cfrac{2}{1} \\\\\\ tan(\theta )=\cfrac{~~\stackrel{sin(\theta )}{\frac{\sqrt{3}}{2}} ~~}{\underset{cos(\theta )}{\frac{1}{2}}}\implies \theta =tan^{-1}\left( \cfrac{~~\frac{\sqrt{3}}{2} ~~}{\frac{1}{2}} \right)\implies \theta = \begin{cases} \stackrel{I~Quadrant}{60^o}\\\\ \stackrel{III~Quadrant}{240^o} \end{cases}[/tex]

Check the picture below.

I'll do the first two questions of each activity to get you started. The remaining unanswered questions will follow similar steps compared to the other questions in the same activity group.

=======================================================

Activity 5, Problem 1

To find the mean, we first add up the values

4+8+2+8+5+9 = 36

Then we divide over n = 6 because there are 6 values in this data set.

36/n = 36/6 = 6

=======================================================

Activity 5, Problem 2

Follow the same idea as the previous problem.

Add the values:  9+8+8+13+12 = 50

Divide by the number of values: 50/n = 50/5 = 10

=======================================================

Activity 6, Problem 1

The median is the middle-most number. Think of a median of a highway or freeway.

In order to find the median, we first need to sort the data values from smallest to largest.

The original set {7,3,9,9,2,5,8} sorts to {2, 3, 5, 7, 8, 9, 9}

If we erased the first and last items, we get this smaller subset

{3, 5, 7, 8, 9}

repeat again to get

{5,7,8}

At this point its clear the middle most value is 7

But if you wanted, you could cross the first and last values from the list to end up with {7}

=======================================================

Activity 6, Problem 2

We could do the same trick as the previous problem, but I'll use a slightly different route this time.

We'll need to sort {10,8,4,11,9} into {4, 8, 9, 10, 11}

There are n = 5 items in that set. The middle slot would be at slot n/2 = 5/2 = 2.5 = 3

The value 9 is in slot 3 of the sorted items.

=======================================================

Activity 7, Problem 1

The mode is the most frequent value of a set. It repeats the most often.

The set {5,6,7,3,5,4} sorts to {3,4,5,5,6,7}

The value "5" shows up the most. It shows up twice when everything else shows up exactly once only.

=======================================================

Activity 7, Problem 2

Using the same idea in the previous problem, the set {7,4,11,9,7,3} has the mode 7 because it shows up the most of any other value.

Here's the sorted set: {3,4,7,7,9,11}

Sorting is optional with finding the mode in contrast to being mandatory when it comes to finding the median.

[tex] \qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Here we go ~

To find Highest common factor (HCF) we have to check what primes are common between them along with their exponent. And multiply them ~

here, we get [ 2³ and 3 as common ]

[tex]\qquad \sf  \dashrightarrow \:HCF = {2}^{3} \times 3 [/tex]

[tex]\qquad \sf  \dashrightarrow \:HCF = {8}^{} \times 3 [/tex]

[tex]\qquad \sf  \dashrightarrow \:HCF = 24[/tex]

So, HCF of the given numbers is 24

Answer:

For question 2: 15/4.

For question 3: 10/8.

Step-by-step explanation: To multiply fractions, you multiply the numerators and then the denominators.  We should first transform any whole numbers into fractions.  The first step is done below:

For question 2: 5 to 5/1.

For question 3: 2 to 2/1.

Now, we can multiply the numerators and denominators to answer the following:

For question 2: 5/1 x 3/4.  The numerators are 5 and 3, so multiply those to get 15.  The denominators are 1 and 4, so multiply those to get 4.  Your answer is 15/4.

For question 3: 2/1 x 5/8.  The numerators are 2 and 5, so multiply those to get 10.  The denominators are 1 and 8, so multiply those to get 8.  Your answer is 10/8.

Let me know if this is right! :)

Answer:

r≈12mi

Step-by-step explanation:

mark brainiest and Im 100% correct

Answer: C) His creative imagination

Step-by-step explanation:

J.R.R. Tolkien's creative imagination most helped him to become a successful writer

[tex]\qquad\qquad\huge\underline{{\sf Answer}}☂[/tex]

Let's find the Area of sector ~

[tex]\qquad \sf  \dashrightarrow \: \dfrac{ \theta}{360} \times \pi{r}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{ 270}{360} \times \pi{6}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{ 3}{4} \times {36}^{} \pi[/tex]

[tex]\qquad \sf  \dashrightarrow \:3 \times 9 \pi[/tex]

[tex]\qquad \sf  \dashrightarrow \:27\pi \: \: ft {}^{2} [/tex]