Consider the following equation of a parabola.y? + 4y = 8r + 4Step 1 of 3: Find the focus of the parabola.

Consider The Following Equation Of A Parabola.y? + 4y = 8r + 4Step 1 Of 3: Find The Focus Of The Parabola.

Answers

Answer 1

Given the equation:

[tex]y^2+4y=8x+4[/tex]

Let's find the focus of the parabola.

To find the focus of the parabola, let's first rewrite the equation in vertex form:

[tex]y=a(x-h)^2+k[/tex]

We have:

[tex]undefined[/tex]


Related Questions

Tyrone's car can travel about 30 miles for each gallon
of gas.
Using d for distance traveled in miles and g for
gallons of gas, write two different equations relating d
and g.

Answers

The equation can be written as d=30g

What is an equation?

An equation can be compared to a scale on which objects are weighed. When the two pans are filled with the same amount of anything (like grain), the scale will balance and the weights will be considered equal. To maintain the scale in balance, if any grain is taken out of one of the balance's pans, an equal amount must be taken out of the other pan. More broadly, if the identical operation is carried out on both sides of an equation, the equation remains in balance. Equations are used to describe geometric shapes in Cartesian geometry. The goal has changed since the equations under consideration, such as implicit equations or parametric equations, contain an unlimited number of solutions.

Tyrone's car can travel about 30 miles for each gallon

So, the equation can be written as d=30g, where d is distance travelled and g is gallons of gas used.

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How much will it cost to buy a low fence to put all the way around the bed? The fencing material costs $0.59 per foot and can only be bought in whole numbers of feet.

Answers

To find the cost we first need to know how many feet of fence we need. To do this we add all the lengths of the sides:

[tex]6+6+8.5=20.5[/tex]

Now, since we can only buy whole numbers of feet we need to buy 21 feets of fence, then the total cost is:

[tex]21\cdot0.59=12.39[/tex]

Therefore the cost will be $12.39

Find the slope of the line that passes through (54, -61) and (8, -56).

Answers

Answer:

The slope m of the line that passes through the two given points is;

[tex]m=-\frac{5}{46}[/tex]

Explanation:

We want to calculate the slope of the line that passes through the given point;

[tex](54,-61)\text{ and }(8,-56)[/tex]

Recall that the slope formula can be written as;

[tex]m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}[/tex]

substituting the given points;

[tex]\begin{gathered} (x_1,y_1)=(54,-61) \\ (x_2,y_2)=(8,-56) \end{gathered}[/tex]

We have;

[tex]\begin{gathered} m=\frac{-56-(-61)}{8-54}=\frac{5}{-46} \\ m=-\frac{5}{46} \end{gathered}[/tex]

Therefore, the slope m of the line that passes through the two given points is;

[tex]m=-\frac{5}{46}[/tex]

Solve the quadratic equation by using the quadratic formula. If the solutions are not real, enter NA. 3x2−5x+1=0 Enter the exact answers.

Answers

The given quadratic equation is,

[tex]3x^2-5x+1=0[/tex]

let us use the formula,

[tex]\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

where,

[tex]\begin{gathered} a=3 \\ b=-5 \\ c=1 \end{gathered}[/tex]

subistute the values in the formula,

[tex]\begin{gathered} =\frac{-(-5)\pm\sqrt[]{(-5)^2-4\times3\times1}}{2\times3} \\ =\frac{5\pm\sqrt[]{25-12}}{6} \\ =\frac{5\pm\sqrt[]{13}}{6} \\ x=\frac{5+\sqrt[]{13}}{6},x=\frac{5-\sqrt[]{13}}{6} \end{gathered}[/tex]

The roots of the quadratic equation are ,

[tex]x=\frac{5+\sqrt[]{13}}{6},x=\frac{5-\sqrt[]{13}}{6}[/tex]

what is the slope of any line is perpendicular to the equation y=1/2x-7

Answers

Answer:

The slope = -2

Explanations:

The given equation is:

[tex]y\text{ = }\frac{1}{2}x\text{ - 7}[/tex]

This is of the form y = mx + c

where the slope, m = 1/2

The equation perpendicular to the equation y = mx + c is:

[tex]y-y_1=\frac{-1}{m}(x-x_1)[/tex][tex]\begin{gathered} \text{The slope = }\frac{-1}{m} \\ \text{The slope = }\frac{-1}{\frac{1}{2}}=\text{ -2} \end{gathered}[/tex]

The slope = -2

Determine whether the graph represents a function.

Answers

A, the relation is not a function

in order for something to be a function, x (the input) can't repeat itself more than once

Find the area of the figure.A. 57 square yardsB. 66 square yardsC. 180 square yards D. 234 square yards

Answers

We would section the figure into two shapes as shown below

We can see a trapezium and a rectangle. We would find the area of each figure and add them.

For the trapezium,

Area = 1/2 * (a + b)h

a nd b are the opposite sides of the trapezium while h represents the height.

Thus,

a = 20, b = 24 and h = 9es of the trapezium while h represents the height.

Thu sid

What is the domain of the function graphed below?
x<7
x_<7
-2_< X_<3
all real numbers

Answers

The given function is defined everywhere except at x = 7 and a higher value than 7 thus x < 7 will be the domain of the function so option (A) is correct.

What is the range and domain of a function?

A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.

The domain is for the independent variable while the range is for the dependent variable.

As per the given graph of the function,

The value of the function at x = -1 is -2.

In another place, the graph is not breaking before x = 7.

So, at x > 7 the function is not defined.

The domain of the function will be (-∞ ,7).

Hence "The given function is defined everywhere except at x = 7 and a higher value than 7 thus x < 7 will be the domain of the function".

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The given question is incomplete, the complete question follows with the graph below;

7. 4×= 3yy=-4x + 39. y+2=0x+ 2 = 011.x-5y=45x + y = 4Determine if the graphs will show parallel or perpendicular lines, or neither.

Answers

Given:

[tex]\begin{gathered} 4x=3y \\ y=-4x+3 \end{gathered}[/tex]

Sol:.

If the both line are perpendicular then multipilcation of slope is -1 then:

[tex]\begin{gathered} y=mx+c \\ m=\text{slope} \\ \end{gathered}[/tex][tex]\begin{gathered} 3y=4x \\ y=\frac{4}{3}x \\ m_1=\frac{4}{3} \end{gathered}[/tex][tex]\begin{gathered} y=-4x+3 \\ m_2=-4 \end{gathered}[/tex][tex]\begin{gathered} =m_1m_2 \\ =\frac{4}{3}\times-4 \\ m_1m_2\ne-1 \\ \text{That mean its not perpendicular } \end{gathered}[/tex]

For parallel line slope are same then its not a parallel line

So line neither perpendicular or parallel.

Geo help please The price of an item has been reduced by 5% the original price was $60 what is the price of the item now

Answers

To answer this question, we can proceed as follows:

1. The original price of the item was $60.

2. If the price of this item has been reduced by 5%, we need to find the 5% of the original price as follows:

[tex]5\%=\frac{5}{100}\Rightarrow5\%(\$60)\Rightarrow\frac{5}{100}\cdot\$60=\frac{\$300}{100}=\$3[/tex]

3. Therefore, the price of the item now is:

[tex]P_{\text{item}}=\$60-\$3=\$57[/tex]

In summary, the price of the item now is $57.

[From the question, we have that the words "reduced by" imply a subtraction.]

if a certain number is added to the numerator and denominator of 9/13 the result is 9/11. find the number

Answers

We have the following:

When they tell us a certain number, we will assume a value x.

This number is added to the numerator and denominator of the fractional number 9/13 and gives us the result 9/11.

it is as follows

[tex]\frac{x+9}{x+13}=\frac{9}{11}[/tex]

solving for x:

[tex]\begin{gathered} \frac{x+9}{x+13}=\frac{9}{11} \\ 11\cdot(x+9)=9\cdot(x+13) \\ 11x+99=9x+117 \\ 11x-9x=117-99 \\ 2x=18 \\ x=\frac{18}{2}=9 \end{gathered}[/tex]

Therefore, the certain number is 9

16 - 2t = 5t +9 Can you help me solve this?

Answers

1=t

add 2t to the second side, so that it is going to be 16=7t+9

now, subtract 9 from the right side: 16-9=7t

7t=7

t=1

write a linear equation to: slope=2 and goes through point (4, 11)

Answers

When you have to write a linear equation and you have the slope (m) and a point (4, 11) you:

1. Use the standard form of a linear equation:

[tex]y=mx+b[/tex]

You know the value of:

m= 2

y= 11

x= 4

You make a substitution:

[tex]11=(2)(4)+b[/tex]

You can find then the value of b:

[tex]11=8+b[/tex][tex]b=11-8=3[/tex]

Then you have now the data to form the final linear equation:

[tex]y=2x+3[/tex]

Use percents to find price of each set of items.(1) You purchase one pair of jeans, 2 hoodies and 3 t-shirts. what is the Total cost with no Sale? You purchase the same items but now you receive a 40% off coupon, How much is your total including the discount?

Answers

We can multiply the number of items by the price of each item to find the total cost:

[tex]\begin{gathered} C=C_{jeans}+C_{hoodies}+C_{shirts}=1\cdot25+2\cdot30+3\cdot8 \\ C=25+60+24 \\ C=109 \end{gathered}[/tex]

The total cost is $109.

If we have a 40% discount, we have to substract it from the total cost.

The discount is equal to 40% of the total cost, so we can calculate the discount as:

[tex]D=\frac{40}{100}\cdot C=0.4\cdot109=43.60[/tex]

Then, we will pay a total cost with discount of:

[tex]C^{\prime}=C-D=109-43.60=65.40[/tex]

The total including the discount is $65.40.

NOTE: we could also have calculated it as 109*(1-0.4)=109*0.6=65.40.

I am not good at word problems this is a project so need extra help

Answers

M = $6,400

C = $3,600

CD interest = $180

Money market interest = $256

Here, we want to start by completing the chart

We proceed as follows;

Let us take it line by line

a) The rate for the CD account is 5%

Writing this as decimal is 5/100 = 0.05

b) The time for the CD account is 1 year

Next line;

a) Principal invested in money market is $M

b) The time is also 1 year

Next line;

The interest earned on investment is the sum of both

That will be;

0.05c + 0.04m

So, let us write the equations to solve simultaneously;

[tex]\begin{gathered} c\text{ + m = 10,000} \\ 0.05c\text{ + 0.04m = 436} \\ \text{second equation multiplied through by 100;} \\ 5c\text{ + 4m = 43,600} \\ \text{From i;} \\ c\text{ = 10,000-m} \\ \text{put this into the multiplied equation} \\ 5(10,000-m)\text{ + 4m = 43600} \\ 50,000\text{ - 5m + 4m = 43600} \\ m\text{ = 50,000-43600} \\ m\text{ = 6400} \\ c\text{ = 10,000-6400} \\ c\text{ = 3,600} \end{gathered}[/tex]

So, let us fill the last parts;

a) $3,600 + $6,400 = Total $10,000 invested

b) CD interest is 0.05 c = 0.05 (3,600) = $180

Money market interest = 0.04M = 0.04 (6,400) =$256

$180 + $256 = $436 total interest

The number of cities in a region over time is represented by the function

Answers

For this question, in order to find T(x), we need to multiply the two given functions.

[tex]T(x)=(C\cdot P)(x)[/tex][tex]T(x)=C(x)\cdot P(x)[/tex][tex]=(2.9)(1.05)^x\cdot(1.05)^{3x+5}[/tex][tex]=(2.9)(1.05)^{x+3x+5}[/tex][tex]T(x)=2.9(1.05)^{4x+5}[/tex]

Therefore, the answer must be option A.

5 In nahiangle Bcm. Ireos B = / 13 which function also cauals

Answers

Given data:

The given measurement of angle C is 90 degrees.

The given value of cos(B) =5/13.

The sum of all angles of triangle is,

[tex]\begin{gathered} \angle A+\angle B+\angle C=180^{\circ} \\ \angle A+\angle B+90^{\circ}=180^{\circ} \\ \angle A+\angle B=90^{\circ} \\ \angle B=90^{\circ}-\angle A \end{gathered}[/tex]

Substitute the above value in the given expression.

[tex]\begin{gathered} \cos (90^{\circ}-A)=\frac{5}{13} \\ \sin A=\frac{5}{13} \end{gathered}[/tex]

Thus, the correct answer is sin(A), so the third option is correct.

Please help me i have been struggling for two days

Answers

we have the equation

[tex]\log _5(x+1)-\log _2(x-2)=1[/tex]

using a graphing tool

see the attached figure

The solution is x=2.90

Of the twenty-two students in a classroom, ten are transfer students, seven are nursing students, four are AAS students and one student is undecided.If three students are chose randomly, without replacement, find the probability that all three students are nursing students.

Answers

Given that:

• There are a total number of 22 students in the classroom.

,

• 10 of them are transfer students.

,

• 7 are nursing students.

,

• 4 are AAS students.

,

• 1 student is undecided.

,

• Three students are chosen randomly.

Since you need to find the probability that all three students that are chosen randomly are nursing students, you need to set up that this is:

[tex]P(A)[/tex]

Where Event A is that one of the students is a nursing student.

Therefore, the probability that three of the chosen students are nursing students can be set up as:

[tex]\begin{gathered} P=P(A)\cdot P(A)\cdot P(A)=P(A)^3 \\ \\ P=P(A)^3 \end{gathered}[/tex]

Knowing that the total number of students is 22 and 7 of them are nursing students, you know that:

[tex]P(A)=\frac{7}{22}[/tex]

Therefore:

[tex]P=(\frac{7}{22})^3[/tex][tex]P=0.0322[/tex]

Hence, the answer is:

[tex]P=0.0322[/tex]

Differentiate. f(x) = (x3 - 3)2/3 2x f'(x) 3 x 8 х f'(x) 3 | 23-8 2x2 f'(x) 3 S x2 f'(x) 3 8

Answers

1) Let's calculate the derivative of f(x) = (x³-8) ^(2/3)

Let's start applying the power rule :

[tex]undefined[/tex]

Eliminate the y in the following system of equations. What is the result when you add the two equations? [tex]x + y = 8 \\ 5x - 3y = 24[/tex]A: 6x = 32B: 8x = 32 C: x = 0D: 8x = 48

Answers

EXPLANATION

x + y = 8 ----------------------------------------(1)

5x - 3y = 24 ------------------------------------------(2)

If we are to eliminate y in the equations, we first need to multiply through equation (1) by 3.

3x + 3y = 24 ----------------------------------------(3)

Add equation (2) and equation (3).

If we add equation(1) and equation(3) together, -3y will cancel-out 3y.

(5x + 3x) = (24 + 24)

8x = 48

Therefore, the correct option is D. 8x = 48

Kindly help with these questions.

Answers

the answer to the first question is the third one
because the constant relationship between the x and y coordinates makes the point go through the origin and makes a straight line.
The answer of the second question is k
X is the x coordinate
Y is the y coordinate
so, K is the constant of proportionality.

Right Triangle ABC is pictured below.Which equation gives the correct value for BC?Option 1: sin(32) = BC/8.2Option 2: cos(32) = BC/10.6Option 3: tan(58) = 8.2/BCOption 4: sin(58) = BC/10.6

Answers

Given the image, we are asked which equation gives the correct value for BC?

Explanation

From the image;

[tex]\begin{gathered} A+B+C=180 \\ 32+B+90=180 \\ B=180-90-32 \\ B=58^0 \end{gathered}[/tex]

Therefore,

[tex]tan58^0=\frac{opposite}{Adjacent}=\frac{8.2}{BC}[/tex]

Answer: Option three

roblems in Construction Mathematics me Frandy Ive the following problems. Show your work. Write your answers in the spaces provided. 1. A triangular frame has sides that measure 15-7, 20'-4 and 26-2". What is the total length of the three sides?

Answers

A triangular frame has sides that measure 15-7, 20'-4 and 26-2". What is the total length of the three sides?

Remember that

1 ft =12 inches

Convert all the measure to inches

so

15' 7 "=15(12)+7=187 in

20' 4"=20(12)+4=244 in

26' 2"=26(12)+2=314 in

The top of the hill rises 243 feet above checkpoint 2, which is -162. What is the altitude of the top of the hill?

Answers

The altitude of the top of the hill or the difference in elevation point is 406 feet.

Difference in Elevation Point

The vertical distance between two points is called the difference in elevation. The process of measuring differences in elevation is called levelling , and is a basic operation in topographical surveys.

To determine the difference in elevation between two points, determine the elevation at each point and then calculate the difference.

Point A = 243 feetPoint B = -162 feet

The difference in elevation between the two points is

Point A - Point B = 243 - (-162) = 243 + 162 = 406

The difference in the elevation point is 406 feet.

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You want to purchase an automobile for 28,711. The dealer offers you 0% financing for 60 months or a 3,972 rebate. You obtain 5.7% financing for 60 months at the local bank. Which option should you choose

Answers

Answer:

option 1

Step-by-step explanation:

the dealer one ok.......

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 7 m/s. The balls height h (in meters) after t seconds is given by the following. h=1+7t-5t^2Find all values of t for which the balls height is 2 meters.Round the answer(s) to the nearest hundredth

Answers

Solution

To find the values of t for which the ball's height is 2 meters

we set h = 2

=> 2 = 1 + 7t - 5t^2

=>5t^2 - 7t + 1 = 0

Using the quadratic formula,

[tex]\begin{gathered} t=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ \\ \Rightarrow t=\frac{7\pm\sqrt{\left(-7\right)^2-4\left(5\right)\left(1\right)}}{2\cdot5} \\ \\ \Rightarrow t=1.24s\text{ or }0.16s \end{gathered}[/tex]

Therefore, t = 1.23s or 0.16s

Segment EF is rotated 90° clockwise around the origin and then translated by (-6, y + 7).
The resulting segment E" F" has coordinates E" (-4, 5), F"(-1,-2).
What are the coordinates of the segment EF?

does anyone know this??

Answers

Answer:

E = 2,2     F = 5,-9

Step-by-step explanation:

First, you have to add (6, -7) to both coordinates (that being (-4,5)(-1,-2)

This results in E = 2,-2    and F = -5,-9

Next, you need to rotate both coordinates 90 counterclockwise, resulting in: E being (2,-2) and F being (5,-9)

Hope this helped!

I need help answering this question, if you can thank you very much.

Answers

Answer: We have to factor out the polynomial which is:

[tex]x^2+6x-16[/tex]

The factorization is as follows:

[tex]\begin{gathered} \text{ Method:} \\ \\ (x+a)(x+b)=x^2+(a+b)x+ab \\ \\ \\ ----------------------- \\ \text{ Solution:} \\ \\ x^2+6x-16 \\ \\ \text{ The unknowns }\rightarrow\begin{cases}ab={-16} \\ a+b={6}\end{cases} \\ \\ \\ \text{ The possible values are:} \\ \\ \\ a=8 \\ b=-2 \\ \\ \\ \text{ Because:} \\ \\ \\ (8)\times(-2)=-16 \\ (8)+(-2)=6 \\ \\ \\ \text{ Therefore the factored form is:} \\ \\ \\ (x+8)(x-2)=x^2+6x-16 \end{gathered}[/tex]

The one-to-one function f is defined below.

Answers

The inverse function of the relation is f-1(x) = 5x/(7x -6), while the domain and the range are x < 6/7 or x > 6/7 and f(x) < 5/7 or f(x) > 5/7, respectively

How to determine the inverse function?

The definition of the function is given as

f(x) = 6x/7x - 5

Rewrite the function as

y = 6x/7x - 5

Next, we swap or switch the variables x and y

So, we have the following equation

x = 6y/7y - 5

Cross multiply in the above equation

This gives

x(7y - 5) = 6y

Open the brackets

7xy - 5x = 6y

Collect the like terms

7xy -6y = 5x

Factor out y

y(7x -6) = 5x

So, we have

y = 5x/(7x -6)

Express as inverse function

f-1(x) = 5x/(7x -6)

Using a graphing calculator, we have

Domain: x < 6/7 or x > 6/7

Range: f(x) < 5/7 or f(x) > 5/7

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