consider a salt that has a solubility of 551 g/l. you add 123 g of this salt to 421 ml of water. how much (in g) salt will remain undissolved?

Based on the appearance of the reaction of aluminum with copper (II) sulfate, the reagent that was consumed was aluminum, and the reagent that had some left over was copper (II) sulfate.

Aluminum is a chemical element that has the symbol Al and the atomic number 13. It is a silvery-white, soft, nonmagnetic, ductile metal in the boron group. Aluminum is the third most prevalent element and the most abundant metal in the Earth's crust after oxygen and silicon.

Copper (II) sulfate is a blue solid that is soluble in water. Its appearance is due to the presence of water of crystallization, which occurs in the crystal structure. It is a compound that is commonly used as a fungicide and algaecide because it is toxic to many fungi and algae. Copper sulfate has also been used to treat various diseases.

Aluminum replaces the copper ions in copper (II) sulfate and creates aluminum sulfate and copper metal when aluminum reacts with copper (II) sulfate. The chemical reaction between aluminum and copper (II) sulfate is as follows:

Al(s) + CuSO4(aq) ⟶ Al2(SO4)3(aq) + Cu(s)

When aluminum is placed in copper (II) sulfate solution, copper ions from copper (II) sulfate move to aluminum, displacing the aluminum ions in the process. As a result, the copper ions from copper (II) sulfate solution are lowered to metallic copper, and aluminum ions combine with sulfate ions from copper (II) sulfate solution to form aluminum sulfate, which is soluble in water. When copper metal is produced, it forms a brown layer on top of the solution and sinks to the bottom.

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The system is losing heat to the surroundings. The approximate value for the heat exchange is 36770 J.

What is Equilibrium?

In general, equilibrium refers to a state of balance or stability in a system. In the context of physics, specifically thermodynamics, equilibrium is a state in which there is no net flow of heat or matter between a system and its surroundings. In other words, the system and surroundings have reached the same temperature and pressure, and there is no longer any exchange of heat or matter between them.

To solve this problem, we can use the equation for heat exchange:

Q = mcΔT

where Q is the heat exchange, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For aluminum, the specific heat capacity is 0.903 J/g°C, and for ethyl alcohol, it is 2.44 J/g°C. We can also assume that the heat exchange between the aluminum and the ethyl alcohol is equal and opposite.

A) To find the equilibrium temperature, we can use the equation:

mcΔT = mcΔT

(100.0 g)(0.903 J/g°C)(T - 450.0°C) = (100.0 g)(2.44 J/g°C)(T - 80.0°C)

Solving for T, we get:

T = 198.15°C

Therefore, the equilibrium temperature of the mixture is approximately 198°C.

B) To find the heat exchange, we can use the same equation:

Q = mcΔT

The heat exchange for aluminum is:

Q₁ = (100.0 g)(0.903 J/g°C)(450.0°C - 198.15°C) ≈ 21260 J

The heat exchange for ethyl alcohol is:

Q₂ = (100.0 g)(2.44 J/g°C)(198.15°C - 80.0°C) ≈ 15510 J

The total heat exchange for the system is:

Q = -(Q₁ + Q₂) ≈ -36770 J

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The field lines around a positively charged pair of jeans would extend outward in all directions from the jeans, with evenly spaced lines becoming weaker as they move away from the jeans.

If a pair of jeans becomes positively charged, it will create an electric field around it. The electric field will be directed away from the jeans, since positive charges repel each other. The field lines will spread out in all directions from the jeans, becoming weaker as they move further away.

To draw field lines around the jeans, we can use a simple diagram. The diagram should show the jeans in the center, with field lines extending outwards in all directions. The field lines should be drawn perpendicular to the surface of the jeans, since this is the direction in which the electric field will be strongest.

The field lines should be evenly spaced and should become weaker as they move further away from the jeans. The length of the field lines can be arbitrary, but it is common to make them longer near the jeans to indicate the stronger electric field.

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Answer:

The balanced chemical equation for the reaction of NaHCO3 and Ca(H2PO4)2 is:

2 NaHCO3(aq) + Ca(H2PO4)2(aq) → Na2HPO4(aq) + CaHPO4(aq) + 2 CO2(g) + 2 H2O(l)

From the equation, we see that 2 moles of NaHCO3 produce 2 moles of CO2. Therefore, 1 mole of NaHCO3 produces 1 mole of CO2. We can use the molar mass of NaHCO3 to convert from moles to grams.

The molar mass of NaHCO3 is:

Na: 1 x 22.99 g/mol = 22.99 g/mol

H: 1 x 1.01 g/mol = 1.01 g/mol

C: 1 x 12.01 g/mol = 12.01 g/mol

O: 3 x 16.00 g/mol = 48.00 g/mol

Total molar mass = 22.99 + 1.01 + 12.01 + 48.00 = 83.01 g/mol

One kilogram (1000 g) of baking powder contains 168 g of NaHCO3. Therefore, one kilogram of baking powder contains:

1000 g baking powder × (168 g NaHCO3 / 1000 g baking powder) = 168 g NaHCO3

To produce 2.2 L of CO2 at baking temperature, we need:

2.2 L CO2 × (1.20 g CO2 / 1 L CO2) = 2.64 g CO2

Since 1 mole of NaHCO3 produces 1 mole of CO2, we need 2.64 g of NaHCO3 to produce 2.64 g of CO2. This corresponds to:

2.64 g NaHCO3 × (1 mol NaHCO3 / 83.01 g NaHCO3) × (1 kg baking powder / 168 g NaHCO3) = 0.0198 kg baking powder

Therefore, we need 0.0198 kg, or 19.8 g, of baking powder to generate 2.2 L of CO2 at baking temperature.

Explanation:

Energy cannot be created or destroyed; it can only be changed from one form to another, according to the rule of conservation of energy.

A fundamental tenet of physics is the law of conservation of energy, which holds that energy can only be changed from one form to another and cannot be created or destroyed. Hence, the overall energy level in a closed system is constant across time. Many tests and observations, such as the energy changes that take place when an object falls from a table to the ground, have demonstrated the accuracy of the rule. The object loses potential energy owing to the change in height while gaining kinetic energy from its motion as it falls. The rule of conservation of energy is demonstrated by the fact that the total amount of energy is the same before and after the fall.

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Answer:

gasoline

Explanation:

The right response is gasoline

Because the ingredients are evenly distributed and do not settle over time, homogeneous combinations include tomato soup, sugar-water solution, and salt-water solution. Contrarily, gasoline is a heterogeneous mixture since it contains a variety of hydrocarbons and additives that may separate or settle over time.

\

1. Tetraphosphorus pentasulfide : P4S5

2. Dinitrogen monoxide: N2O

3. carbon monoxide: CO

4. Carbon disulfide : CS2

5. Hydrogen: H2

6. Phosphorus pentabromide: PBr5

7. Silicon hexabromide: SiBr6

8. Carbon tetrachloride: CCl4

9. Sulfur monoxide:  SO

10. Sulfur dioxide: SO2

A compound whose atoms are bonded via a covalent bond is known as a covalent compounds.

A covalent bond is described as a chemical bond that involves the sharing of electrons to form electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs.

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2.55 moles of magnesium oxide will produce 2.55 moles of magnesium hydroxide.

What is magnesium hydroxide ?

Magnesium hydroxide (Mg(OH)2) is an inorganic compound that is commonly used as an antacid and laxative to treat heartburn, indigestion, and constipation. It is a white, odorless, and tasteless powder that is slightly soluble in water.

The balanced chemical equation for the reaction between magnesium oxide and water to form magnesium hydroxide is:

MgO + H2O → Mg(OH)2

From the equation, we can see that 1 mole of MgO reacts with 1 mole of H2O to produce 1 mole of Mg(OH)2.

Therefore, if 2.55 moles of MgO react with excess water, then the number of moles of Mg(OH)2 produced will also be 2.55 moles.

So, 2.55 moles of magnesium oxide will produce 2.55 moles of magnesium hydroxide.

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Aqueous solutions of aluminum chloride and sodium carbonate are combined to form carbon dioxide and sodium chloride.

When chemicals are combined, a chemical change known as a balanced chemical reaction takes place. The reactants, or the chemicals that are combined, are on the left side of the equation. The reaction's byproducts are on the right side.

Aluminum oxide, sodium chloride, and carbon dioxide gas bubbles are created when aluminum chloride and sodium carbonate combine.

When dissolved substances react, one (or more) solid products are produced, which is known as a precipitation reaction. These kinds of reactions, which are also occasionally known as double displacement, double replacement, or metathesis reactions, frequently involve the exchange of ions between ionic compounds in aqueous solutions.

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The complete question is

Write a balanced chemical equation: aqueous solutions of aluminium chloride and sodium carbonate are combined, producing aluminium carbonate.

20 mL of 0.20 M H2SO4 is required to completely liquidate 40 mL of 0.10 M Ca (OH)2.

We can use the balanced chemical equation for the neutralization reaction between sulfuric acid (H2SO4) and calcium hydroxide (Ca (OH)2) to determine the stoichiometry of the reaction:

H2SO4 + Ca (OH)2 -> CaSO4 + 2H2O

moles of Ca (OH)2 = Molarity x Volume

= 0.10 mol/L x 0.040 L

= 0.004 mol

moles of solute = Molarity x Volume (in liters)

alter this equation gives:

Volume (in liters) = moles of solute / Molarity

Therefore, the volume of 0.20 M H2SO4 required to supply 0.004 moles of H2SO4 is:

Volume (in liters) = 0.004 mol / 0.20 mol/L

= 0.02 L

Multiplying by 1000 mL/L, we get:

Volume (in mL) = 0.02 L x 1000 mL/L

= 20 mL

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The mole ratio of NaNO₃ to Pb(NO₃)2 is 2:1. Therefore, 6.75 g of Pb(NO₃)₂ will produce 2 x 6.75 g = 13.5 g of NaNO₃.

Mole is a unit of measurement used in chemistry to measure the amount of a substance, usually expressed in terms of the number of atoms, molecules, or other units in a given mass of that substance. The mole, also known as Avogadro's number, is a very large number equal to 6.022 x 10^23. This means that a mole of a substance contains 6.022 x 10^23 atoms or molecules, depending on the substance. The mole is used to measure the amount of a substance in a given sample, and is essential to many chemical calculations.

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The condition where only four chromosomes are present in some cells of a fruit fly is known as haploidy.

Haploidy can occur due to a variety of reasons, including errors during cell division, such as nondisjunction, which is the failure of chromosomes to separate properly during meiosis. In nondisjunction, the chromosomes fail to divide equally, resulting in daughter cells with abnormal numbers of chromosomes. In the case of the fruit fly, this can result in cells with only four chromosomes instead of the normal eight.

Haploidy can also occur naturally in certain stages of development, such as during gamete formation, where cells undergo meiosis to produce haploid gametes with half the number of chromosomes as the parent cell.

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Answer:

Explanation:

It is a binary molecular compound ( and when the first element is to the right of the zigzag line on the periodic table you will use prefixes (di)

The empirical formula of phosphorus sulfide is [tex]P^{1}S^3.[/tex].

To determine the empirical formula of phosphorus sulfide, we need to find the mole ratio between phosphorus and sulfur in the compound. We can use the given masses of phosphorus and phosphorus sulfide to calculate the number of moles of each element.

First, we convert the masses of phosphorus and phosphorus sulfide from milligrams to grams:

Mass of P = 44.0 mg = 0.0440 g

Mass of P4S3 = 158 mg = 0.158 g

Next, we calculate the number of moles of each element:

Moles of P = mass of P / molar mass of P = 0.0440 g / 30.97 g/mol = 0.00142 mol

Moles of S = (mass of P4S3 - mass of P) / molar mass of S = (0.158 g - 0.0440 g) / 32.07 g/mol = 0.00393 mol

We then divide the number of moles of each element by the smallest value to obtain the simplest whole-number ratio of atoms:

Moles of P / 0.00142 mol ≈ 1

Moles of S / 0.00142 mol ≈ 2.77

We can then round the above ratio to the nearest whole number to get the empirical formula:

[tex]P^{1}S^3.[/tex]

Phosphorus sulfide is a chemical compound with the formula P4S3. It is a yellowish-white solid with a garlic-like odor, and is insoluble in water but soluble in carbon disulfide.

It is formed by the reaction of phosphorus with sulfur, and can also be produced by heating a mixture of red phosphorus and sulfur.

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Whether the time taken tο displace all οf the water in a measuring cylinder will be greater fοr lumps οf calcium carbοnate οr pοwder are mentiοned belοw.

The transfοrmatiοn οf οne οr mοre reactants intο οne οr mοre new prοducts is referred tο as a chemical reactiοn. Substances are made οf chemical cοnstituents οr cοmpοunds. The transfοrmatiοn οf οne οr mοre reactants intο οne οr mοre new prοducts is referred tο as a chemical reactiοn. Substances are made οf chemical cοnstituents οr cοmpοunds.

One part carbοn and twο parts οxygen make up the gas called carbοn diοxide. Its usage by plants tο create carbοhydrates during a prοcess knοwn as phοtοsynthesis makes it οne οf the mοst significant gases οn the planet.

The cοncentratiοn οf calcium carbοnate cannοt fluctuate because it is a sοlid. Hence, the οnly reactant in this reactiοn that can fluctuate in cοncentratiοn and impact reactiοn rate is hydrοchlοric acid. We need tο graph the cοncentratiοn οf hydrοchlοric acid against time, as yοu shοuld knοw frοm yοur reactiοn rate theοry.

Therefοre, whether the time taken tο displace all οf the water in a measuring cylinder will be greater fοr lumps οf calcium carbοnate οr pοwder are mentiοned abοve.

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The concentration of O₂(g) in the solution is 8 ppm. Option B is correct.

Parts per million (ppm) is a unit of concentration used to express the amount of a substance in a solution. It represents the number of parts of the substance per one million parts of a solution.

To calculate the concentration of O₂(g) in parts per million (ppm), we need to first determine the amount of O₂ dissolved in the solution per unit mass of the solution.

We are given that the solution contains 0.008 grams of O₂(g) dissolved in 1000 grams of H₂O(₂):

Concentration of O₂(g) = (mass of O₂(g) / mass of solution) x 10⁶

Concentration of O₂(g) = (0.008 g / 1000 g) x 10⁶

= 8 ppm

Hence, B. 8ppm is the correct option.

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--The given question is incomplete, the complete question is

"What is the concentration of O2(g), in parts per million, in a solution that contains 0. 008 gram of O2(g) dissolved in 1000. Grams of H2O(2)?A) 10. 8 ppm B) 8 ppm C) 80 ppm D) 800 ppm"--

The output voltage of the device is 12 volts.

The transformer law states that the ratio of the number of turns in the primary coil to the number of turns in the secondary coil is equal to the ratio of the output voltage to the input voltage. Mathematically, we can express this as:

Vp/Vs = Np/Ns

where Vp is the input voltage (120 volts in this case), Vs is the output voltage (what we're trying to find), Np is the number of turns in the primary coil (200 turns in this case), and Ns is the number of turns in the secondary coil (20 turns in this case).

We can rearrange this equation to solve for Vs:

Vs = Vp * Ns/Np

Plugging in the given values, we get:

Vs = 120 volts * 20/200

Vs = 12 volts.

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The amount of the original sample remaining would be between 1.50 and 3.00 grams. Option I.

To solve this problem, we can use the half-life formula:

N = N0 x (1/2)^(t/T)

where:

We are given N0 = 12.0 grams, T = 3.6 days, and t = 10 days. We can plug these values into the formula and solve for N:

N = 12.0 grams x (1/2)^(10/3.6)

N ≈ 1.50 grams

Therefore, about 1.50 grams of the original sample remains after 10 days. The answer is between 1.50 and 3.00 grams.

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Answer: theres a 1 in 4 chance of that happening

Explanation:

The pH of the mixture of acids is 0.62, the pH of the mixture of acids is 0.63, the pH of the mixture of acids is 0.39, the pH of the mixture of acids is 1.00.

To find the pH of a mixture of acids, we need to first calculate the total concentration of H⁺ ions in the solution, and then use that value to calculate the pH using the formula pH = -log[H⁺].

The chemical formulas for the two acids are:

HBr - hydrobromic acid

HCHO₂ - formic acid

The dissociation reactions for these acids are:

HBr → H⁺ + Br⁻

HCHO₂ → H⁺ + CHO₂⁻

The concentrations of the two acids are given as:

[HBr] = 0.115 M

[HCHO₂] = 0.125 M

To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:

[H⁺] = [H⁺ from HBr] + [H⁺ from HCHO₂]

[H⁺] = [HBr] + [HCHO₂]

[H⁺] = 0.115 M + 0.125 M

[H⁺] = 0.24 M

Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:

pH = -log[H⁺]

pH = -log(0.24)

pH ≈ 0.62

The chemical formulas for the two acids are:

HNO₂ - nitrous acid

HNO₃ - nitric acid

The dissociation reactions for these acids are:

HNO₂ → H⁺ + NO₂⁻

HNO₃ → H⁺ + NO₃⁻

The concentrations of the two acids are given as:

[HNO₂] = 0.150 M

[HNO₃] = 0.085 M

To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:

[H⁺] = [H⁺ from HNO₂] + [H⁺ from HNO₃]

[H⁺] = [HNO₂] + [HNO₃]

[H⁺] = 0.150 M + 0.085 M

[H⁺] = 0.235 M

Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:

pH = -log[H⁺]

pH = -log(0.235)

pH ≈ 0.63

The chemical formulas for the two acids are:

HCHO₂ - formic acid

HC₂H₃O₂ - acetic acid

The dissociation reactions for these acids are:

HCHO₂ → H⁺ + CHO₂⁻

HC₂H₃O₂ → H⁺ + C₂H₃O₂⁻

The concentrations of the two acids are given as:

[HCHO₂] = 0.185 M

[HC₂H₃O₂] = 0.225 M

To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:

[H⁺] = [H⁺ from HCHO₂] + [H⁺ from HC₂H₃O₂]

[H⁺] = [HCHO₂] + [HC₂H₃O₂]

[H⁺] = 0.185 M + 0.225 M

[H⁺] = 0.410 M

Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:

pH = -log[H⁺]

pH = -log(0.410)

pH ≈ 0.39

The chemical formulas for the two acids are:

CH₃COOH - acetic acid

HCN - hydrocyanic acid

The dissociation reactions for these acids are:

CH₃COOH → H⁺ + CH₃COO⁻

HCN → H⁺ + CN⁻

The concentrations of the two acids are given as:

[CH₃COOH] = 0.050 M

[HCN] = 0.050 M

To find the total concentration of H⁺ ions in the solution, we need to consider the dissociation reactions of both acids. The H⁺ ions from each acid will contribute to the total H⁺ ion concentration:

[H⁺] = [H⁺ from CH₃COOH] + [H⁺ from HCN]

[H⁺] = [CH₃COOH] + [HCN]

[H⁺] = 0.050 M + 0.050 M

[H⁺] = 0.100 M

Now that we know the total concentration of H⁺ ions in the solution, we can calculate the pH:

pH = -log[H⁺]

pH = -log(0.100)

pH = 1.00

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12.5 mol of the substance contains 7.53 x 10²⁴ formula units of calcium carbonate.

Calcium carbonate (CaCO₃) is a compound that consists of one calcium atom, one carbon atom, and three oxygen atoms. The formula unit of calcium carbonate contains one Ca atom, one C atom, and three O atoms. To calculate the number of formula units in 12.5 mol of calcium carbonate, we need to use Avogadro's number, which relates the number of particles (atoms, molecules, or formula units) in a given amount of substance.

Avogadro's number (Nₐ) is 6.022 x 10²³ particles/mol. Therefore, the number of formula units of calcium carbonate in 12.5 mol can be calculated as:

n = Nₐ * 12.5 mol

n = 6.022 x 10²³ particles/mol * 12.5 mol

n = 7.53 x 10²⁴ particles

Therefore, there are 7.53 x 10⁴ formula units of calcium carbonate in 12.5 mol of the compound.

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When the concentration (absorbance) of reactants is doubled, the reaction rate and slope of the reaction will increase.

This is due to the increased availability of reactants, leading to more successful collisions between molecules. This in turn results in a faster reaction rate, and therefore a steeper slope. The reaction rate and slope of a reaction depend on the concentration of reactants. When the concentration (absorbance) of the reactants is doubled, the reaction rate increases, and the slope of the graph increases accordingly.

The rate of a reaction is the speed at which the reactants change into products.  If the reaction rate is high, the reaction will occur quickly, whereas if the reaction rate is low, the reaction will take longer to occur. When the concentration (absorbance) of the reactants is doubled, the reaction rate and slope of the graph increase. It occurs because the number of reactant particles available for collision increases.

Hence  increase in the number of reactant particles available for collision leads to more collisions per unit of time, and this increases the reaction rate.

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The response is C. 400mL of 5% glucose solution requires 20g of glucose to make.

To prepare 400mL of 5% glucose solution, we need to determine the amount of glucose required.

5% glucose solution means that 5g of glucose is present in 100mL of the solution.

Therefore, for 400mL of the solution, the amount of glucose required can be calculated as:

5g glucose/100mL solution = x g glucose / 400mL solution

x = (5g glucose/100mL solution) x (400mL solution) = 20g glucose

Therefore, the answer is D. 20g of glucose is needed to prepare 400mL of 5% glucose solution.

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Answer:

The rate of the forward reaction must be equal to the rate of the reverse reaction. In other words, the speed at which products are formed from reactants must be equal to the speed at which reactants are formed from products.

The concentrations (or partial pressures) of the reactants and products must be constant. At equilibrium, the system has reached a state of balance where the amounts of reactants and products are no longer changing with time, and their concentrations (or partial pressures) have stabilized.

Thus, at equilibrium, the reaction is said to be "dynamic," meaning that the forward and reverse reactions are still occurring but at an equal rate, resulting in no net change in the concentrations (or partial pressures) of the reactants and products.

Explanation:

Answer:

Explanation:

not sure your elements to choose from

But it would be one with a +2 charge

Examples

Be, Mg, Ca, Sr, Ba, Cu, Fe these are just a few

send your list and I can finish this for you

The temperature in the atmosphere will rise as humidity rises. Only in the case of an exothermic chemical reaction will an increase in temperature slow down the reaction and thus reduce the percentage yield.

Energy is involved in all chemical reactions. When reactants break bonds, energy is released, and when products form new bonds, energy is released. Endothermic reactions are those in which less energy is released when new bonds form in the products than is required to break bonds in the reactants. Exothermic reactions are the polar opposite. In an exothermic reaction, breaking bonds in the reactants requires less energy than the energy released when new bonds form in the products.

The amount of water vapor in the air is referred to as humidity. The humidity will be high if there is a lot of water vapor in the air. The higher the humidity, the wetter the weather feels outside. Humidity is usually described as relative humidity in weather reports.

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Answer:

n = 0.012 moles

Explanation:

Recall that;

n = V note: V in dm³

22.4

V = 26.5 mL = 0.265 dm³

n = 0.265

22.4

n = 0.012 moles

At 75 degrees Celsius, water's autoionization constant, Kw, is 2.0 10 13. The quantity of dissociation of water molecules to form hydronium and hydroxide ions is indicated by the autoionization constants of water.

It should be remembered that the autoionization constant rises as the temperature rises. Kw equals 1.0 x 10-14 [H+][OH-]. Hence, one may determine the [H+] or [OH-] as needed for any liquid at 25°C in any given aquatic condition. Indicate if the substance is acidic, basic, or neutral.

Kwh of electricity are units of energy that represent one megawatt of electricity for one hour (unit symbol: kWh or kWh; frequently abbreviated as kWh). It represents 3.6 megajoules (MJ) in SI-derived units with specific names.

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At 75 degrees Celsius, water's autoionization constant, Kw, is 2.0 10 13. Water's pOH at 75 degrees Celsius is 6.85 as a result.

Using the relationship between the amounts of hydrogen ions (H+) and hydroxide ions (OH) and the ion product constant for water (Kw), we can begin to solve this issue:

Kw = [H⁺][OH⁻]

Kw = [H⁺][OH⁻]

1.995 x 10⁻¹³ = [H⁺][OH⁻]

Since water is neutral, the concentration of hydrogen ions and hydroxide ions must be equal.

[H⁺] = [OH⁻]

Hence, the equation can be rewritten as follows:

1.995 x 10⁻¹³ = [OH⁻]²

When we solve for [OH], we get:

[OH⁻] = √(1.995 x 10⁻¹³) = 1.414 x 10⁻⁷

We can now apply the correlation between pOH and [OH]:

pOH equals -log[OH]

By entering [OH] as the value, we obtain:

pOH is equal to -log(1.414 x 107) = 6.85.

Water's pOH at 75 degrees Celsius is 6.85 as a result.

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