Answer: (x=1 y=30) (x=2 y=27) (x=3 y=24) (x=4 y=21) (x=5 y=18) (x=6 y=15) (x=7 y=12) (x=8 y=9) (x=9 y=6) (x=10 y=3) etc its going down by 3 so 30-3=27 27-3=24 24-3=21 etc
hope i helped
Explanation:
A vector has an x-component of length 3 and a y-component of length 4 what is the angle of the vector
The angle of a vector with x and y component of 3 and 4 respectively is 53.13°
What is a vector?
Vectors are quantities that have both magnitude and direction
To calculate the angle of the vector, we use the formula below.
Formula:
∅ = tan⁻¹(y/x)........... Equation 1Where:
∅ = Angle of the vectorx = x-component = 3y = y-component = 4Substitute these values into equation 1
∅ = tan⁻¹(4/3)∅ = tan⁻¹(1.33)∅ = 53.13°Hence, the angle of the vector is 53.13°.
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gravitational potential energy is converted to kinetic __ energy when the object begins to move
Gravitational potential energy is converted to kinetic (Motion) energy when the object begins to move.
What is the gravitational potential energy movement about?The energy gained from this change in position is stored within the body as gravitational potential energy if a ball is raised from the ground to a height above the earth. The gravitational potential energy is then converted into kinetic energy when the ball hits the earth.
Therefore, the way an object falls, its gravitational potential energy is said to be transformed or altered into the kinetic energy of motion.
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Please help, I have no idea what story I can make out of these..
Make up a short story that uses these three constellations: Orion, Taurus, and Canis Major
Thank you!
Constellation is a group of stars that appears to form a pattern or picture. Some of the constellations include Orion, Taurus, Canis Major etc.
Orion is located on the celestial equator and it can be seen throughout the world. This constellation is named after the hunter, in Greek mythology. It is one of the most obvious and recognizable constellations in the sky. Orion is most visible in the evening sky from January to April, during winter season in the Northern Hemisphere, and summer season in the Southern Hemisphere. In the tropics, the constellation moves at the zenith. Orion is bordered by Taurus to the northwest, and by other constellations in other directions.
Taurus is one of the constellations of the 12 zodiac signs. It is a large and prominent constellation in the Northern Hemisphere during winter. It is one of the oldest constellations. The International Astronomical Union gave a three-letter abbreviation for the constellation, as "Tau". During late November-early December, Taurus occupies a furthest point from the Sun and is visible the entire night. By late March, it sets at sunset and completely disappears behind the Sun's glare from May to July.
Canis Major is a constellation in the southern celestial hemisphere. It is a Latin name, which means 'greater dog' in contrast to 'Canis Minor' meaning 'lesser dog'. These both figures are commonly represented as following the constellation of Orion, the hunter, through the sky. Canis Major contains Sirius, the brightest star in the night sky, known as the "dog star". It is bright because of its proximity to the Solar System.
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Which of the following are the freezing and boiling points of water on the Centigrade scale?Select one:a. 32° and 100°b. 0° and 100°c. 32° and 212°d. 0° and 212°
Answer:
b
Explanation:
For C scale , water freezes at 0 and boils at 100 C
three solid, uniform, cylindrical flywheels, each of mass 65.0 kg and radius 1.47 m rotate independently around a common axis. two of the flywheels rotate in one direction at the other rotates in the opposite direction at 3.42 rad/s. calculate the magnitude of the net angular momentum of the system.
Three solid, uniform, cylindrical flywheels with a radius of 1.47 m and a mass of 65.0 kg each rotate. The system's net angular momentum is 297.77 298 kg m2 / s in size.
I is the moment of inertia.
W = angular momentum L = angular velocity
I = 1/2 MR^2
I = 1/2 (65)(1.47^2)
I = 70.23
Moment of Inertia times Angular Velocity equals L.
In the same direction, two of the fly wheels turn.
L = 2I(W1) - I(W2) (W2)
L = 2*70.23(3.83) - 70.23(3.42) (3.42)
L = 297.77 ≈ 298 kg m^2 / s
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a driver who does not wear a seat belt continues to move forward with a speed of 18.0 m/sm/s (due to inertia) until something solid like the steering wheel is encountered. the driver then comes to rest in a much shorter distance - perhaps only a few centimeters. find the net force acting on a 65.0 kgkg driver who is decelerated from 18.0 m/sm/s to rest in 5.00 cmcm .
The net force acting on: 2.113 x 10⁵ N.
First, we need to calculate the deceleration of the driver by using 3rd equation of motion: 2as = Vf² - Vi²
where,
a = deceleration = ?
s = distance = 5 cm = 0.05 m
Vf = Final Velocity = 0 m/s
Vi = Initial Velocity = 18 m/s
Therefore,
2a(0.05 m) = (0 m/s)² - (18 m/s)²
a = (- 324 m²/s²)/0.1 m
a = - 3240 m/s²
where the negative sign represents a deceleration
From Newton's Second Law of Motion:
F = ma
F = (65 kg)(-3240 m/s²)
F = - 2.106 x 10⁵ N
So, the closest answer is:
F = 2.113 x 10⁵ N
What is force ?
In physics, a force is an effect that can change the motion of an object. A force can cause an object with mass to change speed, ie. accelerate A force can also be intuitively described as a push or a pull. A force has both magnitude and direction, so it is a vector quantity.
When a body tends to change or change its state under the influence of an external cause, it is called a force. A body can also change its shape, size and direction when a force is applied. For example, kicking a ball, pulling and pushing a door.
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A person of weight 600n at the bottom of a mountain climbs to the top. the gravitational field strength changes from 10.00n/kg at the bottom to 9.97n/kg at the top.his mass is unchanged as he climbs. what are his mass and his weight at the top of the mountain
At the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.
What is Mass?Weight is the force of gravity acting on an item, whereas mass is the amount of matter that makes up the object. Weight varies from place to place yet mass is constant everywhere you are in the cosmos. Kilograms are used to measure mass.Let the mass on earth be m.
Given, W= 600N, g= 9.97 N/kg(top of mountain)As we know:
The formula for Weight = mass x acceleration due to gravity at place W=m*gNow, calculate as follows:
m = W/g= 600*9.97mass = 60.18 kgW= m*g= 60.18 * 9.97= 600NWeight = 600NTherefore, at the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.
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Which Combination of graphs best describes free-fall motion? [Neglect air resistance.]
The combination of the graphs that shows a free fall are A and C.
What is the description of free fall?We know that motion has to do with the change of position with time. When an object is falling freely, the velocity of the object would remain constant because the velocity or the speed does not change.
Recall that when we throw objects down from a height, the objects would fall at the same rate irrespective of the masses of the objects. This can be understood to mean that the acceleration that acts on the objects is the same and does not change.
However, the distance that is covered by the object does change with tome and this can be seen from the graph as we have in the question. We can now see that the graph that has a flat speed time graph and a straight distance time graph can describe on object that is undergoing free fall.
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The amount of thermal energy inside a protostar increases with time, even though the protostar is losing radiative energy from its surface. How can we tell how much radiative energy the protostar is losing and how much thermal energy remains in the star? which type of energy can we measure and which type do we infer from the law of conservation of energy?.
The amount of thermal energy inside a protostar increases with time, We will degree radiative power without delay and infer thermal energy from models: type will we infer from the law of conservation of energy
A protostar is a very younger big name that is nonetheless accumulating mass from its parent molecular cloud. The protostellar phase is the earliest one within the system of stellar evolution. for a low-mass superstar, it lasts about 500,000 years.
A protostar is formed as gravity starts offevolved to pull the gases collectively into a ball. This technique is referred to as accretion. As gravity pulls the gasses toward the center of the ball, gravitational strength begins to warmness them, inflicting the gasses to emit radiation. in the beginning, the radiation simply escapes into space.
Protostar is an early degree in the evolution of a celebrity that generally grows to the factor of beginning nuclear fusion and becoming a star through gathering mass. it's miles made from a contracting cloud of bloodless and dark interstellar medium (often hydrogen gas).
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two satellites orbit the earth in stable orbits. satellite a is three times the mass of satellite b. satellite a orbits with a speed vvv at a distance rrr from the center of the earth. satellite b travels at a speed that is greater than vvv . at what distance from the center of the earth does the satellite b orbit?
Satellite B's radius will be less than Satellite A's radius.
m = Satellite Mass
v = Satellite Velocity
r = Orbital radius of the satellite
Relating the gravitational and centripetal forces
mv^2/ r= GmM/r^2
v^2/r=GM/r^2
v^2=GM/r
v = sqrtGM/r
As can be shown, the mass of the satellite has no bearing on the relationship between velocity and radius.
This implies that the radius must shrink for v to increase
Here, vb>va
Therefore, satellite b's radius will be smaller than satellite a's radius.
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a tank is 10 m long, 4 m wide, 4 m high, and contains kerosene with density 820 kg/m3 to a depth of 3.5 m. (use 9.8 m/s2 for the acceleration due to gravity.) (a) find the hydrostatic pressure on the bottom of the tank.
The hydrostatic pressure on the bottom of the tank is 197.083 kN.
Given,
Length of tank = 10 m
Width of tank = 8 m
height of tank = 4 m
density of kerosene = 820 kg/m³
depth of oil = 3.5 m
A. Hydrostatic pressure at the underside of the tank:
P = ρ g h
P = 820 x 9.81 x 3.5
P = 28154.7 Pa
B. Hydrostatic force at the underside of the tank:
F = P A
⇒A = 10 x 8 = 80 meter²
⇒F = 28154.7 x 80
= 2252.38 kN
C. Hydrostatic force at one edge:
Given,
Width = 8 m
depth = z
A = 4 y
dA = 4 dy
P = ρgh
P = ρgz = ρg(y-0.5)
F = P dA
F = ρg(y-0.5)(4dA)
F = 24.5 ρg
Hydrostatic force at one end = 24.5 x 820 x 9.81 = 197.083 kN.
The pressure exerted by a liquid thanks to gravity at any point in equilibrium. Hydrostatic pressure is proportional to the depth measured from the surface because the weight of the liquid increases when a downward force is applied. Hydrostatic pressure is the force produced by still or still water. this is often the constant force that water pressure exerts on underground walls.
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the sweet spot on a baseball bat is 55 cm from the axis of rotation during the swing of the bat. if the sweet spot on the bat moves 36 m/s, what is the angular velocity of the bat (in rad/s)?
The Angular velocity is 54.55 rad/s
What is angular velocity?
The rate at which an angle between two bodies changes is known as angular velocity. Something changes when an object rotates or revolves around an axis. This displacement is depicted in the image by the angle formed by a line on just one body and a line on the other. Technical terms like degrees, 360-degree revolutions, as well as revolutions per minute have been frequently used to describe angles or angular displacements (rpm). Angles and angular velocities are typically expressed in radians as well as radians per second, respectively, in mathematics and physics.
These conversion factors link these measurements together:
A radian equals 1/180 (or 0.0175) of a degree, and a radian per second = 1/30 (or 0.105) of a radian.
Angular velocity W= U/r
Given V= 30m/s ; r=0.55mW=3/0.55 = 54.55 rad/s
Hence the answer is 54.55 rad/s
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A constant force is used to punch a box along the floor a distance of 3 meters by applying 300j what is the magnitude of force?
The magnitude of the force is equal to 100 newtons.
How do you prove that?It's easy! You just need to divide the work by the displacement:
300 = F · 3
300 = 3F
300/3 = 3F/3
100 = F
F = 100
Here, F is the magnitude of force. The standard unit for force is newton (N). Recall that in physics, work is mathematically defined as W = F · x where W is work, F is force, and x is displacement. The standard unit for work is joule (J) and the standard unit for displacement is meter (m).
You are given that the work applied is equal to 300 joules and the displacement is equal to 3 meters. The force used to punch a box along the floor would then be 100 newtons.
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What are three sources of errors in a center of gravity lab experiment
The centre of gravity, in physics, is an imaginary point in a body of matter where for convenience in certain calculations,
What are three sources of errors in a center of gravity?Sources of errors for the center of gravity of an irregularly shaped object: -environmental error: when the wind blows it may remove the irregularly shaped object from equilibrium. add: density variations, shape variations say, thickness], inability to measure precisely, inability to compute precisely. For example, as a result of a number of the center of gravity measurements, we may have the best estimate of the true value for the acceleration due to gravity, the center of gravity is the point between which the force of gravity move on a thing or system. In most mechanics problems the gravitational pasture is assumed to be constant. The center of gravity is then in entirely the same position as the center of mass.
So we can conclude that It is important to know the center of gravity because it predicts the behavior of a moving body when acted on by gravity.
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hii i am satyam from India and i m having doubt in this question according to me answer should be 20 % but in answer key it's 21 % how??
The formula relating kinetic energy and momentum of a particle is expressed as
KE = p^2/2m
let the actual momentum be p. Since the error measurement is 10%, the measurement of the momentum would be
p + 0.1p = 1.1p
Percentage error in the measurement of the kinetic energy is obtained by the formula,
% error = (KEf - KEi)/KEi x 100
where
KEf is the final kinetic energy measured error
KEi is the initial kinetic energy measured without error
Thus,
% error = [(1.1p)^2/2m - p^2/2m)]/p^2/2m x 100
% error = p^2/2m(1.1^2 - 1)/(p^2/2m) x 100
% error = 100(1.1^2 - 1)
% error = 21%
what is the name of the theory that describes the history and fate of the universe?? what is the name of the theory that describes the history and fate of the universe?? the nebular theory. the big bang theory. the theory of everything. the general theory of relativity.
The name of the theory that describes the history and fate of the universe is the big bang theory.
The most influential theory of the origin of the universe at present is the so-called Big Bang theory. According to this theory, the universe was formed when a very hot dense fireball exploded, blowing matter outward. The consensus among scientists, astronomers, and cosmologists is the universe as we know it.
It was created in a massive explosion that determined not only most of the matter but also the physical laws that govern our ever-expanding universe about it. This is known as the Big Bang Theory. The most widely held theory of the origin of the universe is called the Big Bang theory. This argues that the universe began as a near-single point with near-infinite temperature and density. Since then the universe has continued to expand.
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an archer shoots an arrow toward a 300-g target that is sliding in her direction at a speed of 2.15 m/s on a smooth, slippery surface. the 22.5-g arrow is shot with a speed of 42.0 m/s and passes through the target, which is stopped by the impact. what is the speed of the arrow after passing through the target?
24.46 m/s is the speed of the arrow after passing through the target.
p=mv
Conservation of momentum: m1v1=m2v2
The target has a mometum of -(.3kg)(2.15m/s)
the arrow has a mometum of (.0225kg)(42.0m/s)
After impact the mometum of the target is 0 Ns since its velocity is zero.
After impact the velocity of the arrow can be determined with conservation of momentum calculations.
Δp(arrow)=-Δp(target)
m(arrow)v(arrow)i+m(target)v(target)i=m(arrow)v(arrow)f+m(target)v(target)f
(.0225kg)(42.0m/s)-(.3kg)(2.15m/s)=(.0225kg)vf(arrow)
the final velocity of the arrow should be equal to((.0225kg*42.0m/s)-(.3kg*2.15m/s))/.0225kg
v(arrow) final = 24.46 m/s
What is momentum?Momentum is a quantity used to describe the state of motion of an object with non-zero mass. Therefore momentum can be applied to any moving object. If
m is the mass of a body and v is the velocity of that body, the impulse momentum can be expressed as p=m.v
Since velocity is considered a vector, momentum is also considered a vector. This means that the impulse has a significant magnitude and direction—an impulse indicated by a vector or arrow. For example, if a ball of a certain mass moves with a certain speed, it has momentum. When the ball hits the wall, it stops and thus carries its momentum over the wall. Therefore momentum is always conserved.To learn more about momentum, refer;
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the chemical makeup of a star's surface is obtained by ... a. examining rocks recovered from the moon. b. examining rocks here on earth. c. examining material collecting on solar panels here on earth.
option c is the correct answer
What is Spectroscopy ?
It is a common method used by astronomers to determine the composition of stars, planets, and other objects. Today, this process uses instruments with gratings that distribute the light from the object by wavelength. This spread of light is called the spectrum.
The science of spectroscopy is very difficult. From the spectral lines, astronomers can not only determine the element, but also the temperature and density of this element within the star. The spectral lines also tell us about each of the star's magnetic fields. The width of the line tells us how fast the matter is moving.
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A car is driving with a constant velocity around a circular track. The track’s radius is 156.1 m, and the car returns to its starting position in 49.3 s. What is the car’s centripetal acceleration?
A car is driving with a constant velocity around a circular track. The track’s radius is 156.1 m, and the car returns to its starting position in
49.3 s the car’s centripetal acceleration is 0.327 m/sec².
What is acceleration?Rate of change of velocity with respect to time is called acceleration.
when the magnitude of velocity is constant and direction is changing
than the acceleration is centripetal acceleration.
Given that is question radius of track is 156.1 m and car returns to its starting position in 49.3 s.
Velocity of car = Circumference of Circle / total time
= 352.308/ 49.30
v = 7.14 m/sec
Centripetal acceleration = v²/r
= 51.06/156.1
= 0.327 m/sec²
The car’s centripetal acceleration is 0.327 m/sec².
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It took 89.5 degrees to stop the wheel from 47.8 rpm. What is the angular acceleration?
Given:
The angular displacement, θ=89.5°
Initial angular velocity, ω₀=47.8 rpm
Final angular velocity, ω=0 rad/s
To find:
The angular acceleration of the wheel.
Explanation:
The angular velocity can be converted to rad/s as,
[tex]\begin{gathered} \omega_0=\frac{47.8\times2\pi}{60} \\ =5\text{ rad/s} \end{gathered}[/tex]The angle is converted into the radians as,
[tex]\begin{gathered} \theta=\frac{89.5\times\pi}{180} \\ =1.56\text{ rad} \end{gathered}[/tex]From the equation of motion,
[tex]\omega^2-\omega^2=2\alpha\theta[/tex]Where α is the angular acceleration of the wheel.
On substituting the known values,
[tex]\begin{gathered} 0^2-5^2=2\times\alpha\times1.56 \\ \implies\alpha=\frac{-5^2}{2\times1.56} \\ =-8.01\text{ rad/s}^2 \end{gathered}[/tex]Final answer:
Thus the angular acceleration of the wheel is -8.01 rad/s²
A 10 kg box is pulled across a level floor, where the coefficient of kinetic friction is 0. 35. What horizontal force is required for an acceleration of 2. 0 m/s2?
The horizontal force required for an acceleration of 2.0 m/s² is equal to 54.3 N.
What is the force of kinetic friction?The force of kinetic friction is a type of frictions that acts on a moving object on a surface. In order to calculate the force of kinetic friction, we use the formula F = μN where F is the force of kinetic friction, μ is the coefficient of the kinetic friction, and N is the normal force. However, we need to take into account the force along the x-axis. Therefore, the formula ∑F = μN + ma will help us find the horizontal force.
Let ∑F represent the net force, N represent the normal force, m represent the mass of the box, g represent the acceleration of gravity, µ represent the kinetic friction, and a represent an acceleration of 2 m/s².
∑F = µN + ma
∑F = µmg + ma
∑F = m (µg + a)
∑F = 10 kg (0.35 × 9.8 m/s² + 2 m/s²)
∑F = 10 kg (3.43 m/s² + 2 m/s²)
∑F = 10 kg (5.43 m/s²)
∑F = 54.3 kg × m/s²
∑F = 54.3 N
The net force is equal to 54.3 N. That is the horizontal force required!
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compare and contrast the energy of moving water and the energy of water that is stored.
I need to get it done
The main difference between the energy of moving water and the energy of stored water is that the energy of moving water has kinetic energy whereas the energy of water that is stored has potential energy.
What are kinetic and potential energy?Potential energy is defined as the stored energy in any object due to its position while on the other hand, while Kinetic energy is defined as the energy an object has due to its motion. The energy stored in the water molecules which is used for the movement of these molecules is called water potential. Stored water has potential energy but the kinetic energy is present only in the moving molecules of water.
So we can conclude that moving water has kinetic energy while on the other hand, the energy of water that is stored has potential energy.
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assuming that the air friction is responsible for up to 15% momentum or energy loss, discuss how your results have (roughly) confirmed or contradicted the conservation law for elastic collisions if there is no air friction. do different mass configurations show the same physics of conservation (or non-conservation)? why or why not? g
Due to air friction different mass configurations show the same physics of non-conservation.
Momentum in an easy way is an amount of motion. right here quantity is measurable because if an item is transferring and has mass, then it has momentum. If an item no longer passes then it has no momentum. but, in normal lifestyles, it has significance but many humans did not understand it.
Momentum may be described as "mass in motion. All items have mass; so if an item is transferring, then it has momentum - it has its mass in motion. the quantity of momentum that an item has relies upon two variables.
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A 6-kg bowling ball rolling at 5 m/s strikes a stationary 4-kg bowling ball. If Ball #1 is moving forward at 2 m/s after the collision, what is the speed and direction of Ball #2?
The speed of ball #2 after the collision will be 4.5 m/s.
Given,
The mass of ball 1 = 6kg
The mass of ball 2 = 4 kg
Initial speed of ball 1 = 5 m/s
Final speed of ball 1 = 2 m/s
Initial speed of ball 2 = 0 m/s
Let us suppose the final speed of ball 2 is x m/s.
We know that, from the conservation of momentum theorem:
m1.v1(initial) + m2.v2(initial) = m1.v1(final) + m2.v2(final)
6.5 + 4.0 = 6.2 + 4.x
30 + 0 = 12 + 4x
=>4x = 18
=> x = 4.5 m/s
Thus the speed of 2nd ball after the collision will be 4.5 m/s.
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now assume that the crate is sliding along the floor with constant velocity. what is the magnitude fp of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity?
The magnitude[tex]F_{P}[/tex] of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity is 437.5N.
How friction force can be calculated?The Normal Force (in a horizontal plane, it is comparable to the mass by gravity) and the Kinetic Coefficient of Friction must be multiplied in order to obtain the Friction Force, which must be used in order to solve this problem.
Given that the sentence does not specify the value of the coefficient of friction, I will ascribe a value of 0.5 between the crate and the ground. If a different value has been specified for this coefficient, the below equation will simply need to be changed to reflect it.
[tex]F_{P}[/tex] = µK N
µK = Friction coefficient
Normal Force is N.
Replacing,
[tex]F_{P}[/tex] = 0.5 × 875
[tex]F_{P}[/tex] = 437.5N.
Consequently, the crate is subject to a friction force of 437.5N.
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Complete question is "Suppose you have to move a heavy crate of weight 875 {\rm N} by sliding it along a horizontal concrete floor. You push the crate to the right with a horizontal force of magnitude 300 {\rm N}, but friction prevents the crate from sliding. Now assume that the crate is sliding along the floor with constant velocity. What is the magnitude F_p of the force you need to exert on the crate to make it continue to slide along the floor with constant velocity?"
this si a 2 part question84) A shock absorber is designed to quickly damp out the oscillations that a car would otherwise make because it is suspended on springs. (a) Find the period of oscillation of a 1610-kg car that is suspended by springs that make an effective force constant of 5.75×104 N/m. (b) Find the damping constant b that will reduce the amplitude of oscillations of this car by a factor of 5.00 within a time equal to half the period of oscillation.
Given data
*The given mass of the car is m = 1610 kg
*The given effective force constant is k = 5.75 × 10^4 N/m
(a)
The formula for the period of oscillation of a 1610 kg car is given as
[tex]T=2\pi\sqrt[]{\frac{m}{k}}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} T=2\times3.14\times\sqrt[]{\frac{1610}{5.75\times10^4}} \\ =1.05\text{ s} \end{gathered}[/tex]Hence, the time period of oscillation of a 1610 kg car is T = 1.05 s
(b)
As from the given data, the amplitude of the oscillation of the car decreases by a factor of 5.00. Then, the expression for the amplitude of the oscillation, and the damping constant (b) is calculated as
[tex]A=A_0e^{-\frac{bt}{2m}}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \frac{A_0}{5.0}=A_0e^{-\frac{bt}{2m}} \\ bt=2m\ln (5.0)_{} \\ b(\frac{T}{2})=2m\ln (5.0) \\ b=\frac{4m\ln (5.0)}{T} \\ =\frac{4\times1610\times\ln (5.0)}{1.05} \\ =9871.2\text{ kg/s} \end{gathered}[/tex]Hence, the damping constant is b = 9871.2 kg/s
Jack and Jill takes 14 minutes to walk 340 m [West], then 129 m [South]. Calculate
a. their total displacement
b. their average speed
c. their average velocity
Answer:
a. their total displacement = 364 meters
b. their average speed = 33.5 meters/minute
c. their average velocity = 26 meters/minute SW
Explanation:
See attached worksheet
Consider a 3-atom molecule a-b-a for which b has a total of only two valence electrons. If you assume that b is a group ii metal, what is the bond angle for a-b-a? please answer in degrees to the nearest whole number.
The bond angle of the molecule to the nearest degree is 120 degrees.
What is the VSEPR theory?According to the valence shell electron pair repulsion theory (VSEPR). We know that the bond angle that an atom has with its neighbors which also call the dihedral angle of the compound is affected by the number of atoms that surround the central atom in the molecule.
Let us recall that when we have two atoms that surround the central atom then we are going to have a three atom compound which has a trigonal planar geometry and has a bond angle of 120 degrees.
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. is a major factor in dictating how much energy the vehicle can absorb to protect the occupants. a. frictional energy b. angle of attack c. speed d. all of the above
The correct answer is option c, speed.
Speed is the rate at which someone or something moves or operate. It is measured by the velocity and time.
Velocity is the total distance in total time taken.
Speed tells the amount of energy absorbed by the vehicle. The energy is used in the movement of the vehicle and it also helps the vehicle to move accordingly.
Speed is the major factor that helps to protect the occupants.
It is speed only that we can adjust a according to the situation. This also keeps the vehicle in control. It is the main factor in any vehicle that causes the vehicle to move and also it helps to keep it in control as well. Other controls are the supporting factors that helps to keep the speed in control.
Be it the weather, the climate, roads or traffic, it is speed that helps to keep the occupants safe.
Therefore, Speed is a major factor in dictating how much energy the vehicle can absorb to protect the occupants
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a square loop of wire with initial side length 20 cm is placed in a magnetic field of strength 0.5 t. the field is parallel to the axis of the loop. somebody carefully grabs the edges of the loop and begins pulling them apart such that the area of the loop increases at a rate of 20 cm2/s. what is the magnitude of the induced emf in the loop?
The magnitude of the induced emf in the loop is 1mV.
The formula to be used is:
E = B (dA/dt)
B = magnetic of magnetic field parallel to the axis of loop = 0.5 T
dA/dt = rate of change of area of the loop = 20 cm²/s = 20 x 10⁻⁴ m²
θ = Angle of the magnetic field with the area vector = 0
E = emf induced in the loop
Now, plugging in the values we get:
E = B (dA/dt)
E = (0.5) (20 x 10⁻⁴ )
E = 10 x [tex]10^{-4}[/tex] volts
E = 1 mV
Therefore, the magnitude of the induced emf in the loop is 1mV.
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