Choose SSS, SAS, or neither to comparethese two triangles.A) SSSB) SASC) neither

Choose SSS, SAS, Or Neither To Comparethese Two Triangles.A) SSSB) SASC) Neither

Answers

Answer 1

Answer:

C. Neither

Explanation:

The SSS Congruence Rule states that if the three sides of a triangle are equal to the three sides of another triangle, then the two triangles are congruent.

The SAS Congruence Rule states that if the two sides and the included angle of one triangle are equal to the two sides and the included angle of another triangle, then the two triangles are congruent.

Notice that in the given triangles, there are two congruent sides and a non-included angle, since this does not satisfy any of the rules stated above, SSS Congruence rule or SAS Congruence rule, we'll choose "neither" as the correct answer.


Related Questions

Tank A contains a mixture of 10 gallons of water and 5 gallons of pure alcohol tank b has 12 gallons of what and 3 gallons of alcohol how many gallons should be taken from each tank and combiend in order to obtain 8 gallons of a solution countaning 25% alcohol

Answers

The volume from tanks A and B are taken as 3 and 5 gallons respectively.

Here,
Let the volume taken from tank A and tank B be x and y.
According to the question,
x + y = 8 - - - - - (1)
And
Composition of the alcohol in Tank A = 1/3
Composition of the alcohol in tank B =  1 /5
x / 3 + y / 5 = 8 / 4
5x + 3y = 30
From equation 1
5(y8 - y) + 3y = 30
-5y + 40  + 3y = 30
-2y = -10
y = 5
Now, put y in equation 1
x = 8 - 5
x = 3

Thus, the Volume from tanks A and B are taken as 3 and 5 gallons respectively.

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discriminant for 2n^2+8n+1=-7

Answers

The given equation is

[tex]\begin{gathered} 2n^2+8n+1=-7 \\ 2n^2+8n+1+7=0 \\ 2n^2+8n+8=0 \end{gathered}[/tex]

Where a = 2, b = 8, and c = 8.

The discriminant formula is

[tex]D=b^2-4ac[/tex]

Let's replace the values

[tex]D=(8)^2-4(2)(8)=64-64=0[/tex]The equation has one real solution.

What is the solution to the equation below?A.x = -1B.x = 0C.x = -5D.x = 3

Answers

Explanation

We must solve the following equation for x:

[tex]x+3=\sqrt{3-x}[/tex]

We can square both sides of the equation so we can get rid of the radical:

[tex]\begin{gathered} (x+3)^2=(\sqrt{3-x})^2 \\ (x+3)^2=3-x \end{gathered}[/tex]

We expand the squared binomial on the left:

[tex]\begin{gathered} (x+3)^2=x^2+6x+9=3-x \\ x^2+6x+9=3-x \end{gathered}[/tex]

Then we substract (3-x) from both sides:

[tex]\begin{gathered} x^2+6x+9-(3-x)=x-3-(3-x) \\ x^2+6x+9+x-3=0 \\ x^2+7x+6=0 \end{gathered}[/tex]

Then we have to find the solutions to this last equation. Remember that the solutions to an equation of the form ax²+bx+c have the form:

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In our case a=1, b=7 and c=6 so we get:

[tex]\begin{gathered} x=\frac{-7\pm\sqrt{7^2-4\cdot1\cdot6}}{2\cdot1}=\frac{-7\pm\sqrt{49-24}}{2}=\frac{-7\pm\sqrt{25}}{2}=\frac{-7\pm5}{2} \\ x=\frac{-7+5}{2}=-1\text{ and }x=\frac{-7-5}{2}=-6 \end{gathered}[/tex]

So we have two potential solutions x=-1 and x=-6. However we should note something important, in the original equation we have the term:

[tex]\sqrt{3-x}[/tex]

Remember that the result of the square root is always positive. Then the term in the left of the expression has to be positive or 0. Then we impose a restriction in the value of x:

[tex]x+3\ge0\rightarrow x\ge-3[/tex]

From the two possible solutions only x=-1 is greater than or equal to -3 so this is the correct one.

Answer

Then the answer is option A.

how to find a volume of a cylinder that has a radius of 10 and a base of 4 Khan academy

Answers

Question:

Find a volume of a cylinder:

Solution:

Remember that the volume of the cylinder with radius r and height h is given by the following formula:

[tex]V\text{ = }\pi r^2h[/tex]

then, replacing the data of the problem into the previous equation, we get:

[tex]V\text{ = }\pi(4^2)(10)\text{ = 3.14 (16)(10) = 502.4}[/tex]

thus, we can conclude that the correct answer is:

[tex]V\text{ = 502.4}[/tex]

(−1/2x+7/10)−(−3/4x−1/5)

Answers

The expression (−1/2x + 7/10) − (−3/4x − 1/5) has a value of  1/4x + 9/10 when simplified

How to evaluate the expression?

From the question, the expression is given as

(−1/2x+7/10)−(−3/4x−1/5)

Rewrite the expression properly to  make it legible

So, we have

(−1/2x + 7/10) − (−3/4x − 1/5)

Expression the above parameter as an equation

This is represented as

(−1/2x + 7/10) − (−3/4x − 1/5) = (−1/2x + 7/10) − (−3/4x − 1/5)

Open the brackets

So, we have the following equation

(−1/2x + 7/10) − (−3/4x − 1/5) = −1/2x + 7/10 + 3/4x + 1/5

Collect the like terms in the equation

(−1/2x + 7/10) − (−3/4x − 1/5) = 3/4x − 1/2x + 7/10  + 1/5

Evaluate

(−1/2x + 7/10) − (−3/4x − 1/5) = 1/4x + 9/10

The expression cannot be further simplified

Hence, the solution to the expression (−1/2x + 7/10) − (−3/4x − 1/5) is 1/4x + 9/10

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Short steps pleaseFind the mean and variance of the binomial experiment in which n 5 and p 0.7. a. Mean b. Variance

Answers

Given

n= 5

p = 0.7

Find:

a. mean

b. variance

sol:

Mean d

[tex]\begin{gathered} mean\text{ =n}\times\text{p} \\ \\ \text{ = 5}\times\text{0.7} \\ \\ \text{ =3.5} \end{gathered}[/tex][tex]\begin{gathered} variance=np(1-p) \\ \\ =\text{ }5\times0.7(1-0.7) \\ \\ =3.5(0.3) \\ \\ =1.05 \\ \\ \end{gathered}[/tex]

can you solve for x and y y=4x-11=x+13

Answers

Answer:

x = 8, y = 21

Explanations:

The given equation is:

y = 4x - 11 = x + 13

This can be splitted into two equations as:

y = 4x - 11..........(1)

y = x + 13..........(2)

Substitute equation (1) into equation (2)

4x - 11 = x + 13

4x - x = 13 + 11

3x = 24

x = 24/3

x = 8

Substitute the value of x into equation (1)

y = 4x - 11

y = 4(8) - 11

y = 32 - 11

y = 21

x = 8, y = 21

A number cube is rolled once, {1,2,3,4,5,6)Determine the likelihood of each situation,Column AColumn B1.rolling an even numbera. unlikely2.rolling a 7b. impossible3.rolling a number greater than 0Ccertain4.rolling a number that is greater than 2d. likely5.rolling a 2 or 3e equally likely

Answers

The likelihood of the following situations:

1. rolling an even number is likely.

2. rolling a 7 is impossible.

3. rolling a number greater than 0 is certain.

4. rolling a number that is greater than 2 is likely.

5. rolling a 2 or 3 is equally likely

what is the approximation of 3√200

Answers

Given the expression:

[tex]\text{ }\sqrt[3]{200}[/tex]

Let's simplify the expression and convert its decimal form to get its approximation.

We get,

[tex]\text{ }\sqrt[3]{200}\text{ = }\sqrt[3]{8\text{ x 25}}[/tex][tex]\text{ =2 }\sqrt[3]{25}[/tex]

In decimal form:

[tex]\text{ 2 }\sqrt[3]{25}\text{ = 2 x 2.92401773821 = 5.84803547643 }\approx\text{ 5.8}[/tex]

Therefore, the approximate equivalent of 3√200 is 5.8.

Andrea invites 12 cousins 6 aunts 4 brothers 2 sisters what fraction of her party guests are cousins?

Answers

To determine the fraction of cousins, you have to divide the number of cousins she invited by the total number of guests.

She invited 12 cousins, 6 aunts, 4 brothers, and 2 sisters, a total of 24 guests.

Then:

[tex]\frac{nº\text{cousins}}{\text{total guests}}=\frac{12}{24}[/tex]

Both, 12 and 24 are divisible by 12, to simplify the fraction, divide the numerator and denominator by 12

[tex]\frac{12\div12}{24\div12}=\frac{1}{2}[/tex]

The fraction

8 Madison has two plants. She waters the spider plant every 4 days and the cactus every 6 daysShe water bo November 30. What is the next day that she will water both plants?

Answers

Two plants

Spider plant 4 days

Cactus plant 6 days

Then find when

4X = 6Y

find m.c.m (minimum common multiple) of 4 and 6

m.c.m (4,6) = 12

SO therefore, if both plants were watered November 30, then

add 12 days to Nov 30

12 days after Nov 30 = December 12

Given f(x)=3x+2 find f(-4)

Answers

Step-by-step explanation:

i think it will satisfied you

please mark me as brainlist

What would -5/6 be when turned into a decimal?

Answers

Answer:

answer is -0.8333

round about -0.834

Step-by-step explanation: I hope this helps.

Answer:

if an above ground graden is the shape of triangular pyramid measuring.the base is a right triangle with adjacent lengths measuring 5feet and 8feet. the height of the pyramid is 1.5feet. the organic soil cost $1.20 per cubic foot. how much will it cost to fill the graden fully

Answers

Solution

The volume for a triangular pyramid is given by:

[tex]V=\frac{1}{3}Bh[/tex]

And the Base is given by:

[tex]B=\frac{1}{2}(5)(8)[/tex]

And since h= 1.5 ft we have this:

[tex]V=\frac{1}{6}(5\cdot8)\cdot1.5ft^3=10ft^3[/tex]

And then we can find the total cost like this:

[tex]C=10ft^3\cdot\frac{1.2\text{ dollars}}{1ft^3}=12dollars[/tex]

Then the final answer would be 12$

ind the value of x. Round to the nearest tenth. The diagram is not drawn to scale.

Answers

ANSWER

x = 10.2

EXPLANATION

In this problem, we are given a right triangle: one of its non-right interior angles measures 22°. We know that the length of the hypotenuse is 11 units long and we have to find the length of the side adjacent to the given angle, x.

With the given information, we can use the cosine of the angle to find the missing value,

[tex]\cos\theta=\frac{adjacent\text{ }leg}{hypotenuse}[/tex]

In this problem,

[tex]\cos22\degree=\frac{x}{11}[/tex]

Solving for x,

[tex]x=11\cdot\cos22\degree\approx10.2[/tex]

Hence, the value of x is 10.2, rounded to the nearest tenth.

2,000 deposit,compound interest,compounded anually,at 6% for 2 years. What is the total balance(A=Principal+Interest)?

Answers

Given a principal P, compounded anually at r% for t years. Then the

4) The half-life of a medication is the amount of time for half of the drug to be eliminated from the body. The half-life of Advil or ibuprofen is represented by the equation 2 ) 5 . 0 ( t M R = , where R is the amount of Advil remaining in the body, M is the initial dosage, and t is time in hours.

Answers

Based on the half-life, 35.36 mg will remain at 6:00P PM in the body

The amount of the medication that will remain at 6:00P PM?

The details that complete the question are added as an attachment


From the question, we have

Initial dosage = 200 mg

This means that

M = 200

Also, we have

Initial time =1 : 00 pm

This means that the number of hours, is

n = 6pm - 1pm

n = 5

Recall that the function is given as

R = M(0.5)ⁿ/²

So, we have the following equation

R = 200 x (0.5)⁵/²

Evaluate the quotient of the exponents

So, we have the following equation

R = 200 x (0.5)².⁵

Evaluate the products

R = 35.36 mg

Using the above computation as a guide, we have the remaining amount to be 35.36 mg

Hence, the amount of the medication that will remain at 6:00P PM is 35.36 mg

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I need help with my math homework question please. Plus it has a second part of the question

Answers

The given quadratic equation is

y = - x^2 + 25

a) The leading coeffiecient is the coefficient of the term with the highest exponent. Thus, the leading coefficient is the coefficient of x^2.

Leading coefficient = - 1

Since the leading coefficient is negative, the graph would open downwards. Thus, the correct option is

Down

b) The standard form of a quadratic equation is

y = ax^2 + bx + c

By comparing both equations,

a = - 1

b = 0

c = 25

The formula for calculating the x coordinate of the vertex of the graph is

x = - b/2a

By substituting the given values,

x = - 0/2 * - 1 = 0

We would calculate the y coordinate of the vertex by substituting x = 0 into the original equation. We have

y = - 0^2 + 25

y = 25

The coordinate of the vertex is (0, 25)

c) To find the x intercepts, we would equate the original equation to zero and solve for x. We have

- x^2 + 25 = 0

x^2 = 25

Taking the square root of both sides,

x = square root of 25

x = ± 5

Thus, the x intercepts are

(5, - 5)

d) The y intercept is the value of y when x = 0

Substituting x = 0 into the orignal equation,

y = - 0^2 + 25

y = 25

y intercept = (0, 25)

e) We would find another point on the graph. Let us substitute x = 6 into the equation. We have

y = - (6)^2 + 25 = - 36 + 25

y = - 11

We would plot (6, - 11) and (0, 25) on the graph. The graph is shown below

In the figure below, ZYZA and _YZX are right angles and _XYZ and ZAYZ arecongruent. Which of the following can be concluded about the distance frompoint A from point Z using Thales's method?O A. The distance between points A and Z is the same as the distancebetween points X and Z.B. The distance between points A and Z is the same as the distancebetween points A and Y.O C. The distance between points A and Z is the same as the distancebetween points Yand Z.D. The distance between points A and Z is the same as the distancebetween points X and Y.

Answers

Let's begin by identifying key information given to us:

[tex]\begin{gathered} \angle YZA=90^{\circ} \\ \angle YZX=90^{\circ} \\ \angle XYZ\cong\angle AYZ \end{gathered}[/tex]

Thale's method shows that angles in a triangle opposite two sides of equal length are equal

[tex]undefined[/tex]

As such, the answer is A (The distance between points A and Z is the same as the distance between X and Z)

Look at the photograph and if you need anything let me know

Answers

Observe that the triangles have one pair of congruent angles, and two pair of congruent sides. This means we can demonstrate the congruence using SAS postulate, that is, Side-Angle-Side.

Therefore, the answer is the first option.

I only need help for letter b, the question is on the picture

Answers

Part B

Remember that

z =(x - μ)/(σ/√n)

where

n=21

we have

μ=1,700

σ=200

For X=1,500

Find out the value of Z1

Z1=(1,500-1,700)/(200/√21)

Z1=-4.5826

For X=1,900

Z2=(1,900-1,700)//(200/√21)

Z2=4.5826

Using a z-score table value

P(1,500therefore

The answer is 21 out of 21

Describe a situation that can be represented by the expression –15 + 8.

Answers

Answer:

-7

Step-by-step explanation:

Tiger Woods was 15 under par after the third round of a golf tournament, but was 8 over par for the fourth round. So, his score for the entire tournament was -15 + 8 = -7 (That is, 7 under par).

can anyone help me?
solve using system of linear equations using elimination

x – y - 3z = 4
2x + 3y – 3z = -2
x + 3y – 2z = -4

Answers

The values of the variables are x = 2, y = -2 and z =0

How to solve the system of equations?

From the question, the system of equations is given as

x – y - 3z = 4

2x + 3y – 3z = -2

x + 3y – 2z = -4

Subtract the second equation from the third

This action will eliminate (y)

So, we have

x + 3y – 2z = -4 - (2x + 3y – 3z = -2)

Evaluate

-x + z = -2

Make x the subject

x = z + 2

Substitute x = z + 2 in x – y - 3z = 4 and x + 3y – 2z = -4

z + 2 – y - 3z = 4

z + 2 + 3y – 2z = -4

Evaluate

-2z - y = 2

-z + 3y = -6

Double -z + 3y = -6

-2z + 6y = -12

Subtract -2z + 6y = -12 from -2z - y = 2 to eliminate z

7y = -14

Divide

y = -2

Substitute y = -2 in -z + 3y = -6

-z + 3(-2) = -6

Evaluate

-z - 6 = -6

Evaluate

z = 0

Recall that x – y - 3z = 4

So, we have

x + 2 - 3(0) = 4

Evaluate

x = 2

Hence, the solution is x = 2, y = -2 and z =0

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Two cyclists, 108 miles apart, start riding toward each other at the same time. One cycles 2 times asfast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist?

Answers

Initial distance: 108 miles

We know that they start riding toward each other, and one of them is 2 times as fast as the other. Then, if the speed of the slowest is v, the speed of the faster cyclist is 2v. The combined speed is:

[tex]v_T=v+2v=3v[/tex]

The speed and the distance are related by the equation:

[tex]V=\frac{D}{t}[/tex]

They meet 4 hours later, thus:

[tex]\begin{gathered} D=108 \\ t=4 \end{gathered}[/tex]

Finally, using the previous equation:

[tex]\begin{gathered} 3v=\frac{108}{4} \\ \Rightarrow v=9\text{ mi/h} \end{gathered}[/tex]

The speed of the faster cyclist (2v) is 18 mi/h.

Out of 3500 students at a college 1760 are enrolled in a computer class. What is the per cent of students taking the computer class?

Answers

Using percentages we can conclude that 50.2% of students are taking a computer class.

What is the percentage?A value or ratio that may be stated as a fraction of 100 is referred to as a percentage in mathematics. If we need to calculate a percentage of a number, we should divide it by its entirety and then multiply it by 100. By dividing the value by the entire value and multiplying the result by 100, one may determine the percentage. The percentage calculation formula is (value/total value)100%.

So, the percentage of students taking computer classes:

The total number of students is 3500.The number of students enrolled in a computer class is 1760.

Now, calculate as follows:

1760/3500 × 1000.502 × 10050.2

Therefore, using percentages we can conclude that 50.2% of students are taking a computer class.

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Determine the shape when the following points are graphed one a coordinate plane. A(-3, 1), B(2, 1), C(2, 4), D(-3, 4)

Answers

The given points are A(-3, 1), B(2, 1), C(2, 4), D(-3, 4).

The image below shows the figure formed by these points.

As you can observe, the shape formed by the given points is a rectangle with dimensions 5 times 3.

Therefore, the answer is "rectangle".

You need a quarter of a pumpkin
to make a pie. How many pies
can you make with three and a
half pumpkins?

Answers

14 pies with 3.5 pumpkins.

Answer: 14

Step-by-step explanation:

1/4 of a pumpkin is required to make a pie. The easiest way to complete this is to convert 3.5 pumpkins into the same fraction.

1 pumpkin = 4/4

3.5 pumpkins = 14/4

If only 1/4 of a pumpkin is required to make a pie and we have 14/4 then we can make 14 pumpkin pies.

Use a graph to predict the value of jewelry in 7 years.

Answers

Solution:

Given that the initial cost price of the jewelry is $2,200.

The rate at which it decreases each year is 12%.

Thus, the exponential decay function is;

[tex]\begin{gathered} y(t)=2200(1-0.12)^t \\ \\ \text{ Where }t\text{ is the time in years.} \end{gathered}[/tex]

The graph of the function is;

From the graph;

CORRECT OPTION:

[tex]\approx899.09[/tex]

If lines L=4x and M=x are perpendicular, what is the value of x?

Answers

Those angles are complementary, therefore, we can conclude:

[tex]\begin{gathered} 4x+x=90 \\ add_{\text{ }}like_{\text{ }}terms: \\ 5x=90 \\ Solve_{\text{ }}for_{\text{ }}x: \\ x=\frac{90}{5} \\ x=18 \end{gathered}[/tex]

Answer:

x = 18

Need answer if you could show work would be nice

Answers

In the  Polynomial  function  f(x)= [tex]2x^{3} -11x^{2} -12x+36 =0 then[/tex]

So all the zeros of f(x) algebraically

[tex]\mathrm{f}(\mathrm{x}) \ are\ \mathrm{x}=-2, \mathrm{x}=\frac{3}{2}, \mathrm{x}=6$[/tex].

Step: 1

Given[tex]$f(x)=2 x^3-11 x^2-12 x+36$and $f(6)=0 \Rightarrow(x-6)$ is factor of $f(x)$now $f(x)=2 x^3-11 x^2-12 x+36$$$[/tex]

[tex]\begin{aligned}&\Rightarrow \mathrm{f}(\mathrm{x})=\left(2 \mathrm{x}^2-12 \mathrm{x}^2\right)+\left(\mathrm{x}^2-\right. \\&\Rightarrow \mathrm{f}(\mathrm{x})=2 \mathrm{x}^2(\mathrm{x}-6)+(\mathrm{x}-6)^2 \\&\Rightarrow \mathrm{f}(\mathrm{x})=(\mathrm{x}-6)\left(2 \mathrm{x}^2+\mathrm{x}-6\right)\end{aligned}$$[/tex]

Step: 2

Now consider [tex]$2 x^2+x-6=2 x^2+4 x-3 x-6$$$\begin{aligned}&\Rightarrow 2 x(x+2)-3(x+2) \\&\Rightarrow 2 x^2+x-6=(2 x-3)(x+2)\end{aligned}$$[/tex]

[tex]$5 \circ f(x)=(x-6)\left(2 x^2+x-6\right)$$$\Rightarrow \mathrm{f}(\mathrm{x})=(x-6)(2 \mathrm{x}-3)(\mathrm{x}+2)$$[/tex]

Step: 3

so for finding zeros of

[tex]$f(x) \rightarrow f(x)=0$$$\Rightarrow(x-6)(2 x-3)(x+2)=0$$$$\Rightarrow(x-6)=0 ;(2 x-3)=0 ;(x+2)=0$$[/tex]

[tex]$$\Rightarrow x=6, x=\frac{3}{2} ; x=-2$$[/tex]

Explanation: Please refer to solution in this step.

Answer:

So required zeros of

[tex]\mathrm{f}(\mathrm{x}) \ are\ \mathrm{x}=-2, \mathrm{x}=\frac{3}{2}, \mathrm{x}=6$[/tex]

What is polynomial function?

A polynomial consists of two words, poly and nominal. "Poly" means many and "nomial" means  term, and so when  combined, polynomials can be said to be "algebraic expressions with many terms." Let's go ahead and start by defining polynomial functions and their types.

The polynomial function in standard form is:

f(x) =  [tex]a_{n}x^{n} +a_{n-1} x^{n-1} +.....a_{2} x^{2} +a_{1} x+a0[/tex]

This algebraic expression is called a polynomial function of the variable x. The name of a polynomial is determined by the number of terms it contains.

The three most common polynomials we usually encounter are

monomial binomial trinomial

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