The shape of a quadratic function is a parabola.
The domain of a quadratic function is the set of all real numbers.
The range of the quadratic function is the set of all y values at or above the vertex for a parabola open upwards.
In the given parabola, y=0 is the y coordinate of the vertex of the parabola.
Therefore, the range is R=[0, ∞).
The domain is (-∞, ∞).
Choose Yes or No to tell whether the expressions are equivalent. 4(5c + 3) and 9c + 7 10f – 10 and 2(8f - 5) 12g + 21 and 3(4g + 7)6(4j – 6) and 24 - 36j
Answer:
Explanation:
Part 1:4(5c + 3) and 9c + 7
[tex]4\mleft(5c+3\mright)=20c+12\neq9c+7[/tex]The answer is NO.
Part 2: 10f – 10 and 2(8f - 5)
[tex]2\mleft(8f-5\mright)=16f-10\neq10f-10[/tex]The answer is NO.
Part 3: 12g + 21 and 3(4g + 7)
Part 4: 6(4) – 6) and 24 - 36
Find the average rate of change of the following equation on the given interval. y=3x+1 on [45,48]
Given:
The equation is given as,
[tex]y=3x+1[/tex]The interval is given as,
[tex]\lbrack a,b\rbrack=\lbrack45,48\rbrack[/tex]The objective is to find the average rate of change.
Explanation:
The general formula to find the average rate of change is,
[tex]A=\frac{f(b)-f(a)}{b-a}\text{ . . . . (1)}[/tex]On plugging the function in the equation (1),
[tex]A=\frac{(3(48)+1)-(3(45)+1)}{48-45}[/tex]On further solving the above equation,
[tex]\begin{gathered} A=\frac{145-136}{3} \\ =\frac{9}{3} \\ =3 \end{gathered}[/tex]Hence, the average rate of change is 3.
In December, 64 teams qualify for a basketball tournament. After each round, half of the teams are eliminated.
Which exponential function can be used to find the number of teams left after a rounds, where is a whole number?
O f(x) = (64)
O f(x) =
(x)64
O f(x) = 64 (¹)
○ f(x) = x(¹)
The exponential function is f(x) = 64·(1/2)ˣ which can be used to find the number of teams left after a round.
What is an exponential function?An exponential function is defined as a function whose value is a constant raised to the power of an argument is called an exponential function.
Given that 64 teams qualify for a basketball tournament. After each round, half of the teams are eliminated.
Because it is an exponential function, f(x) will reach 0 as x increases, allowing us to construct the following table of values:
x f(x)
0 64
1 32
2 16
3 8
4 4
5 2
6 1
At that point, 64 teams are in the tournament, and the total number of teams (from this point forward)
Therefore, half of the teams are eliminated after each round and the exponential function is:
f(x) = 64·(1/2)ˣ
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When did the 6.5% Pay cut is applied to your original monthly salary by how many dollars will your monthly pay decrease
We are given that a cut of 6.5% is applied to a salary of $5050. To determine the amount that this amount will decrease we need to determine the product of the monthly salary by the percentage divided by 100, like this:
[tex]5050\times\frac{6.5}{100}[/tex]Solving the operations:
[tex]328.25[/tex]Therefore, the salary will decrease by $328.25.
you are given the point Q(-2,-5). A identify a point (x,y) that along with point Q defines a line with a positive slope.
Answer:
[tex] \sqrt{29} [/tex]
Which is an x-intercept of the continuous function in thetable?O (-1,0)O (0, -6)O (-6, 0)O (0, -1)
The x-intercept happens when:
[tex]f(x)=0[/tex]Therefore, the x-intercepts for that functions are:
[tex]\begin{gathered} x=-1 \\ x=2 \\ x=3 \end{gathered}[/tex]Answ
[tex] - x \div 4 \geqslant 2[/tex]That's the Math problem
Describe and justify the methods you used to solve the quadratic equations in parts A and B.
We know that give any pair of real numbers A and B, the following statement will be true:
[tex]A\cdot B=0[/tex]if, and only if
[tex]\begin{gathered} A=0 \\ or \\ B=0 \end{gathered}[/tex]Now, if we factor a quadratic equation into two factors A and B, and use the fact we've just mentioned, we can then equal each factor to zero, solve for x and get the solutions to said quadratic equation.
May I please get help with this. I have tried multiple times but still could not get the correct answer or at least answer to them
SOLUTION:
Step 1:
In this question, we have the following:
Step 2:
The details of the solution are as follows:
Parallelogram:
a) Two pairs of parallel sides: Yes
b) Only one pair of parallel sides: NO
c) Four right angles: NO
d) All sides congruentnt: NO
Rectangles:
a) Two pairs of parallel sides: Yes
b) Only one pair of parallel sides: NO
c) Four right angles: Yes
d) All sides congruentnt: NO
Trapezoid:
a) Two pairs of parallel sides: NO
b) Only one pair of parallel sides: NO
c) Four right angles: NO
d) All sides congruentnt: NO
Three students that share a townhouse find that their electric bill for October is $2.65 less than the September bill. The total of both bills is $174.65, and eachbill is split evenly among the roommates. How much did each owe in September?
SOLUTION
Let the electric bill for September be x.
October's bill is $2.65 less than the September bill
This means that October's bill = x - 2.65
September + october bill = $174.65
That means that x + x - 2.65 = 174.65
Now let's find x which is september's bill
[tex]\begin{gathered} x+x-2.65=174.65 \\ 2x-2.65=174.65 \\ 2x=174.65+2.65 \\ 2x=177.3 \\ x=\frac{177.3}{2} \\ \\ x=88.65 \end{gathered}[/tex]So September's bill is $88.65, now each student pays
[tex]\begin{gathered} \frac{88.65}{3} \\ \\ =\text{ 29.55} \end{gathered}[/tex]So each student owe $29.55 for the month of September
z2=46Use a calculator.Z≈(Round to the nearest tenth as needed. Use a comma to separate answers as needed.)
The given expression is
[tex]z^2=46[/tex]We can look for a number in which square power is 46 or close to 46.
Notice that, 6 times 6 is 36, and 7 times 7 is 49. This means The number is between 6 and 7.
[tex]z\approx6,-6[/tex]Now, we use a calculator to find the exact solution.
[tex]z=\sqrt[]{46}\approx\pm6.78[/tex]As you can see, the approximated solutions are 6.78 and -6.78.Mr. Bensoua buys 3 bags of Flaming Hot Cheetos for every 4 bags of Takis. He buys a total of 14 bags of chips. If the Flamin Hot Cheetos cost $2 per bag and the Takis cost $2.50 per bag, how much did Mr. Bensoua spend on all of the chips
Statement Problem: Mr. Bensoua buys 3 bags of Flaming Hot Cheetos for every 4 bags of Takis. He buys a total of 14 bags of chips. If the Flamin Hot Cheetos cost $2 per bag and the Takis cost $2.50 per bag, how much did Mr. Bensoua spend on all of the chips?
Solution:
When Mr. Bensoua buys 4 bags of Takis, he buys 3 bags of Flaming Hot Cheetos.
When he buys another 4 bags of Takis, he buys 3 bags of Flaming Hot Cheetos.
At the end, he buys 8 bags of Takis and 6 bags of Flaming Hot Cheetos and that makes it a total of 14 bags of chips.
The cost of Takis per bag is $2.50, the cost of 8 bags of Takis is;
[tex]\text{2}.50\times8=20[/tex]The cost of Flaming Hot Cheetos per bag is $2., the cost of 6 bags of Takis is;
[tex]2\times6=12[/tex]Hence, the total amount Mr. Bensoua spends is;
[tex]20+12=32[/tex]CORRECT ANSWER: $32
Lauren was going to by her mom her favorite perfume for Christmas at a price of $31.95. She waited until it got too close to Christmas and the price went up to $41.49. What was the percent of increase in the price?
The percent of increase in the cost of the perfume is 29.86%
What is percentage and how can it be calculated?
A percentage is a figure or ratio that can be stated as a fraction of 100 in mathematics. If we need to determine a percentage of a number, multiply it by 100 and divide it by the total. So, a part per hundred is what the percentage refers to. Percent signifies for every 100. The sign "%" is used to denote it. No dimension exists for percentages. Thus, it is referred to as a dimensionless number.
Mathematically,
Percent of increase = [(Final value - Initial value)/(Initial value)]×100
Given, the final value of the perfume at purchase = $41.49
Also, the initial value of the perfume as assessed = $31.95
Therefore using the formula established in the literature above,
Percentage increase = [(41.49 - 31.95)/31.95]×100 = 29.86%
Thus, the percent of increase in the cost of the perfume is 29.86%
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Red Tickets: 50 tickets for $37.50A sign at the fair advertises ticket prices for the carnival games,Blue Tickets: 20 tickets for $16.00Yellow Tickets: 5 tickets for $5.00Find the price per ticket for each:Red ticketBlue Ticket:Yellow Ticket:How much would 40 red tickets costs?123456 7 10
The price per ticket can be calculated as follows;
[tex]\begin{gathered} \operatorname{Re}d=\frac{\text{Price}}{No\text{ of tickets}} \\ \operatorname{Re}d=\frac{37.50}{50} \\ \operatorname{Re}d=0.75 \\ \text{Blue}=\frac{16}{20} \\ \text{Blue}=0.8 \\ \text{Yellow}=\frac{5}{5} \\ \text{Yellow}=1.00 \end{gathered}[/tex]The price per ticket for each is given as;
Red tickets = $0.75
Blue tickets = $0.80
Yellow tickets = $1.00
Therefore, 40 red tickets would cost
40 Red = 0.75 x 40
40 Red tickets = $30.00
This is a graph of the motion of a small boat traveling at a constant speed. Total Distance Traveled 12 10 8 Distance (Kilometers) 6 0 2 4 6 8 1012 Time (Hours) How far will the boat travel in 15 hours? O A. 25 km O B. 30 km O C. 15 km O D. 10 km
The speed of the boat is given by the gradient of the line.
Given two points (x1,y1) and (x2,y2) on a graph, the gradient of the line that passes through the two points is given by
[tex]\text{ gradient = }\frac{y_2-y_1}{x_2-x_1}[/tex]In this case,
the line passes through the points (0,0) and (2,2).
We can set (x1,x2) = (0,0) and (y1,y2) = (2,2)
Therefore,
[tex]\begin{gathered} \text{ gradient = }\frac{2-0}{2-0}=\frac{2}{2}=1 \\ \text{therefore} \\ \text{the speed = 1km/h} \end{gathered}[/tex]Given that a body travels with speed, s, and in time, t, the distance travelled, d, is given by
[tex]d=st[/tex]In this case,
s = 1km/h, and t = 15hours
Therefore,
[tex]d=1\times15=15\operatorname{km}[/tex]Therefore, the boat travelled a distance of 15km
Find the slope of the line that passes
through these two points.
Point 1 Point 2
(3,5)
(4,2)
X1 У1
X2 Y2
m =
3
=
y2-91
X2-X1
[?]
Enter
Answer:
-3
Step-by-step explanation:
The slope of a line is the steepness of the line and is given by the formula below:
[tex]\boxed{\text{Slope} = \frac{y_1 - y_2}{x_1 - x_2} }[/tex], where [tex](x_1,y_1)[/tex] is the 1st coordinate while [tex](x_2,y_2)[/tex] is the 2nd coordinate
The two coordinates given are: (3, 5) and (4, 2)
Slope of line
[tex] = \frac{5 - 2}{3 - 4} [/tex]
[tex] = \frac{3}{ - 1} [/tex]
= -3
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Solve for a: a = 10.
a = , ,
Answer:
a=10 and a=-10
Step-by-step explanation: its absolute value
3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x plus y plus z equals negative 1A N D5 x plus 2 y minus z equals negative 91. If the system has a single solution, write the solution as an ordered triple, (x, y, z).2. If the system has infinite solutions, write the solutions IN TERMS OF z.The solution should look something like left parenthesis 3 minus 3 z comma space minus 1 plus 7 z comma space z right parenthesis but not like left parenthesis negative 6 plus 3 y comma space y comma space 2 minus 5 y right parenthesis or not like left parenthesis x comma space 3 plus 5 x comma space minus 1 plus 4 x right parenthesis. None of these are the solution, they are just examples of what the answer could look like and not look like.3. Be sure to show all appropriate work. Extraneous work may be counted against you. Your handwritten work should include the steps used to find the solution. You should label your steps with how you combined your equations, like 2E1+E3. Solutions with no work will receive no credit.
Given the system of equation
[tex]\begin{gathered} -2x+y-2z=-8\ldots\ldots\ldots\text{.}(1) \\ 7x+y+z=-1\ldots\ldots\ldots\text{..}(2) \\ 5x+2y-z=-9\ldots\ldots\ldots\text{.}(3) \end{gathered}[/tex]step 1: Make z the subject of the formula in equations (2)
[tex]z=-1-7x-y\ldots\ldots\ldots(2)[/tex]step 2: Substitute the value of z obtained into equation (1)
10
step 3: Substitute the value of z obtained in step 1 into equation (3)
[tex]\begin{gathered} 5x+2y-(-1-7x-y)=-9 \\ 5x+2y+1+7x+y=-9 \\ 12x+3y=-10\ldots\ldots\ldots\text{.}(5) \end{gathered}[/tex]step 4: Solve equations (4) and (5) simultaneously,
[tex]\begin{gathered} 12x+3y=-10\ldots\ldots\ldots\text{.}(4) \\ 12x+3y=-10\ldots\ldots\ldots\text{.}(5) \\ \text{subtract equation (5) from (4)} \\ (12x-12x)+(3y-3y)=-10-(-8) \\ 0\text{ + 0 = }-10+10 \\ 0=0 \end{gathered}[/tex]Therefore, the system has infinite solutions
The solution in terms of z is
[tex]\begin{gathered} x=-\frac{1}{3}z+\frac{7}{9} \\ y=\frac{4}{3}z-\frac{58}{9} \\ z=z \end{gathered}[/tex]yesenia knits 21 centimeters of a scarf every week. what Is yesenia's unit rate (cm per day)for her knitting?After 18 days of knitting, how many centimeters long will the scarf be?write an equation and solve.
Answer:
3cm per day
54cm long
Explanation
Let x be yesenia's unit rate
If yesenia knits 21 centimeters of a scarf every week, then;
21 cm = 1 week (7 days)
To determine the amount for her knitting in a day, we can write;
x = 1 day
Divide both expressions
21/x = 7/1
Cross multiply
7 * x = 21
7x = 21
x = 21/7
x = 3
hence yesenia's unit rate is 3cm per day
- Recall that;
21 cm = 1 week (7 days)
Let y be the length of the scaf sfter 18 days, To get the length of the scarf, we can write;
y = 18days
Divide both resulting expressions;
21/y = 7/18
7y = 21 * 18
y = 3 * 18
y = 54cm
Hence the scarf will be 54cm longy
Recall that two angles are complementary if the sum of their measures is 90°.
Find the measures of two complementary angles if one angle is 18° more than two times
the other angle.
The smaller angle measures
...
Complementary angles - The smaller angle is 24 degrees in size.
what are complementary angles?
Angles that add up to a precise 90 degree angle are said to be complementary. For instance, 30 degrees and 60 degrees are complementary angles.
Let x equal the first angle's measurement for the sake of explanation.
Let y be the size of the first angle's complement.
One angle, which we'll refer to as y, is 18 more than twice as large as another, x.
y = 18 + 2x
Complementary angles add up to 90 degrees.
x + 18 + 2x = 90
By substituting for y,
we get x + 18 + 2 x = 90.
Putting like phrases together and taking 18 off on both sides...
3x + 18 = 90
- 18 -18
3x = 72
By dividing both sides by 3, you get
3x/3 = 72/3
24 degrees is the angle between the two that is smaller. and the other angle would be,
y= 18+2x
=18+2(24)= 66 degrees.
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Unit 2: homework 9 shingle proofs
??????????????????????????
y = (5/7)x - 13
The slope of this line is (5/7)
I a line has a slope m, then a line perpendicular would have a slope -1/m
In this case m= 5/7
So the perpendicular would be: -1/m = -7/5
Answer: -7/5
In decimal numbers: -1.4
Answer:
Is there a real question?
I can't seem to find it...
Step-by-step explanation:
Can you help me, please? I have to find the restrictions on x .Thank you.
If angle A is greater than angle C, then side BC is greater than side AB.
[tex]\begin{gathered} BC>AB \\ 8-x>4x+48 \end{gathered}[/tex]Then, we solve for x
[tex]\begin{gathered} -4x-x>48-8 \\ -5x>40 \\ x<-\frac{40}{5} \\ x<-8 \end{gathered}[/tex]Hence, the restriction of x is that its value must be less than -8.Solve the quadratic equation using any algebraic method. Show all work that leads to your answer.
6x² + 23x + 20 = 0
Answer:
x = - [tex]\frac{5}{2}[/tex] , x = - [tex]\frac{4}{3}[/tex]
Step-by-step explanation:
6x² + 23x + 20 = 0 ( factorise the left side )
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 6 × 20 = 120 and sum = 23
the factors are + 8 and + 15
use these factors to split the x- term
6x² + 8x + 15x + 20 = 0 ( factor the first/second and third/fourth terms )
2x(3x + 4) + 5(3x + 4) = 0 ← factor out (3x + 4) from each term
(3x + 4)(2x + 5) = 0
equate each factor to zero and solve for x
2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = - [tex]\frac{5}{2}[/tex]
3x + 4 = 0 ⇒ 3x = - 4 ⇒ x = - [tex]\frac{4}{3}[/tex]
what is x^4 − 14x2 + 45 as factored
Answer: B=3
Step-by-step explanation:
Please help me I don’t know how to do this
We have a point (4,-9) it moves to (9,-14)
(4+x = 9, -9+y= -14)
x = 9-4
x = 5
y = -14 +9
y = -5
We are moving to the right 5 and down 5
We want to move the point (-9,-8) exactly the same way
(-9+5, -8-5)
(-4, -13)
(-4, -13)
A figure is made up of three triangles. Each triangle has a baseof 4.5 feet and a height of 4.5 feet. What is the total area of thefigure?
Area of Compound Figures
A figure is made up of 3 triangles with a base b=4.5 feet and a height h=4.5 feet
The area of a triangle of base b and height h is:
[tex]A=\frac{b\cdot h}{2}[/tex]Substituting the given values:
[tex]A=\frac{4.5ft\cdot4.5ft}{2}=10.125ft^2[/tex]The total area is 3 times the above area, thus:
[tex]A_t=3\cdot10.125ft^2=30.375ft^2[/tex]Answer: a.
7. Martha baked 332 muffins. She packed them in boxes of twelve muffins and sold each full box for S6How much money did she make?
• Given that Martha baked 332 muffins,
,• 332 / 12 = 27.67 boxes
,• If she sold each box for $ 6 ; it will be
27*6 = $162
0.67 * 6 = 4.02
Total 162+4.02 = 166.02≈ $166
• She will make $166, ,
What is the explicit formula for the sequence?3,1,-1, -3, -5,...a,= -2n +5a, = 17-5an= 2n-5an= -2n + 3
We need the formula that gives us the values of the sequence
where n is the value of the position
using the formula
[tex]a_n=-2n+5[/tex][tex]\begin{gathered} a_1=-2(1)+5=3 \\ a_2=-2(2)+5=1 \\ a_3=-2(3)+5=-1 \\ a_4=-2(4)+5=-3 \\ a_5=-2(5)+5=-5 \end{gathered}[/tex]as we can see the formula is the correct formula because we obtain the values of the sequence
What is the complement of P(A) if P(A) = 0.52P(A) =
Given
P(A) = 0.52
Find
complement of P(A)
Explanation
As we know sum of probabilities is equal to one,
so ,
[tex]\begin{gathered} P(A)+P^{\prime}(A)=1 \\ P^{\prime}(A)=1-0.52 \\ P^{\prime}(A)=0.48 \end{gathered}[/tex]Final Answer
Therefore, the complement of P(A) = 0.48