can someone help me with this pls?

Answer:

The mode of this list of numbers would still be [tex]7[/tex] (the mode did not change) after "[tex]5[/tex]" was added to the list.

Step-by-step explanation:

The mode of a list of elements is the member that appears the most frequently.

The original list of numbers in this question [tex][5,\, 7,\, 7,\, 7,\, 1,\, 2,\, 9,\, 8][/tex] included the following members:

[tex]\begin{array}{c|c} \text{Member} & \text{Number of appearances} \\ \hline\hline 1 & 1 \\\hline 2 & 1 \\\hline 5 & 1\\\hline 7 & 3 \\\hline 8 & 1 \\\hline 9 & 1 \\\end{array}[/tex]

[tex]\begin{array}{c|c} \text{Member} & \text{Number of appearances} \\ \cline{1-2}\\[-1em]\cline{1-2} 1 & 1 \\\cline{1-2} 2 & 1 \\\cline{1-2} 5 & 1\\\cline{1-2} 7 & 3 \\\cline{1-2} 8 & 1 \\\cline{1-2} 9 & 1 \\\end{array}[/tex].

The member "[tex]7[/tex]" appeared more often than any other member of this list. Thus, the mode of the original list was "[tex]7\![/tex]".

Adding "[tex]5[/tex]" to the original list would give the list [tex][5,\, 7,\, 7,\, 7,\, 1,\, 2,\, 9,\, 8,\, 5][/tex]. Members of this list are:

[tex]\begin{array}{c|c} \text{Member} & \text{Number of appearances} \\ \hline\hline 1 & 1 \\\hline 2 & 1 \\\hline 5 & 2\\\hline 7 & 3 \\\hline 8 & 1 \\\hline 9 & 1 \\\end{array}[/tex]

[tex]\begin{array}{c|c} \text{Member} & \text{Number of appearances} \\ \cline{1-2}\\[-1em]\cline{1-2} 1 & 1 \\\cline{1-2} 2 & 1 \\\cline{1-2} 5 & 2\\\cline{1-2} 7 & 3 \\\cline{1-2} 8 & 1 \\\cline{1-2} 9 & 1 \\\end{array}[/tex].

The member "[tex]7[/tex]" still appeared more often than any other member of this list. Thus, the mode of the new list would also be "[tex]7\![/tex]".

Answer:

Events A and B are independent of each other, so P⁡(B∣A)=P⁡(B)=0.95726.

Explanation -

I got this answer from Plato.

Answer:

C. tanS = 5/12, tanT = 12/5

Step-by-step explanation:

Tangent has NOTHING to do with hypotenuse, do we can easily eliminate answer choices involving 13, the hypotenuse. For angle S, the opposite side measures 5 and the adjacent side measures 12. For angle T, the opposite side measures 12 and the adjacent side measures 5. See this below algebraically

tanθ = opp/adj

tanS = 5/12

tanT = 12/5

I hope this helps!

Using the z-distribution, it is found that the margin of error for a 95% confidence interval is of $0.04.

The confidence interval is:

[tex]\overline{x} \pm z\frac{\sigma}{\sqrt{n}}[/tex]

In which:

The margin of error is given by:

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In this problem, the values of the parameters are:

[tex]z = 1.96, \sigma = 0.48, n = 576[/tex].

Hence, the margin of error, in dollars, is given by:

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]M = 1.96\frac{0.48}{\sqrt{576}}[/tex]

M = 0.04.

More can be learned about the z-distribution at https://brainly.com/question/25890103

Using the z-distribution, as we are working with a proportion, it is found that you should sample 577 households.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

The margin of error is given by:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In this problem, we have a 95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.

In this problem, the estimate is of [tex]\pi = 0.6[/tex], and we want a margin of error of M = 0.05, hence we solve for n to find the sample size.

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.05 = 1.96\sqrt{\frac{0.6(0.4)}{n}}[/tex]

[tex]0.05\sqrt{n} = 1.96\sqrt{0.6(0.4)}[/tex]

[tex]\sqrt{n} = \frac{1.96\sqrt{0.6(0.4)}}{0.05}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.6(0.4)}}{0.05}\right)^2[/tex]

[tex]n = 576.24[/tex]

Rounding up, you should sample 577 households.

More can be learned about the z-distribution at https://brainly.com/question/25890103

Answer:

Step-by-step explanation:

First establish the pattern. Notice the sequence of numbers below. These are the ones making up the pattern. You can go as far as 47 - 31 which gives 16 which is 4^2.

18 -17 = 1 = 1^2

22 - 18 = 4 = 2^2

31 - 22 = 9 = 3^2

47 - 31 = 16 = 4^2

=================

Call the number comming x.  47 taken from x must give 5^2 which is 25

x - 47 = 5^2

x - 47 = 25                        Add 47 to both sides

x  -47 + 47 = 25 + 47

x  = 72

=================

72 -47 = 25 which is 5^2.

Answer: The next number is 72

Answer:

Slope = -3

Y-intercept = (0,-4)

Equation = -3x-4

Step-by-step explanation:

Slope is [tex]\frac{rise}{run}[/tex] or [tex]\frac{Y2-Y1}{X2-X1}[/tex]. Apply this from the data in the table, for example:

[tex]\frac{5-8}{-3-(-4)} = \frac{rise}{run}\\ \frac{-3}{1} = \frac{rise}{run}\\\\-3= \frac{rise}{run}[/tex]

Y-intercept is located where x=0. If we look at the table, we will find that when x=0, y=-4. If we turn it into a (x,y) point format, we will get (0,4).

The function can be found using the Y-intercept and the slope. Since at x=0, y=-4, we know that the function must have a -4 in it, therefore: [tex]y = x-4[/tex]. Our function decreases by 3 for every positive x and increases by 3 for every negative x, therefore [tex]y = -3x-4[/tex].

Answer:

128

6

12

48

Step-by-step explanation:

The required length of the rectangle is 12/5 feet and the width is 9/5 feet.

The equation model is defined as the model of the given situation in the form of an equation using variables and constants.

Here,
Let's denote the length of the rectangle as L and the width as W.

From the problem statement, we know that:

3L = 4W (equation 1)

We also know that the perimeter P is given by:

P = 2L + 2W = 8 2/5 feet

Multiplying both sides by 5 to get rid of the fraction, we get:

10L + 10W = 42

Dividing by 2, we get:

5L + 5W = 21 (equation 2)

Now we can use equations 1 and 2 to solve for L and W.

First, we can substitute equation 1 into equation 2 to get an equation in terms of W:

5L + 15L/4 = 21

Multiplying both sides by 4, we get:

20L + 15L = 84

35L = 84

L = 84/35 = 12/5 feet

Now we can substitute the value of L into equation 1 to get the value of W:

3L = 4W

3(12/5) = 4W

W = 9/5 feet

Therefore, the length of the rectangle is 12/5 feet and the width is 9/5 feet.

Learn more about models here:
https://brainly.com/question/22591166
#SPJ7

Answer:

A=1/2(b*h)

A=(3x2*4xy)

A=1/2(12x3y)

A=6x3y

so the answer is option (d)

Answer:

The answer is $1.85

Step-by-step explanation:

Now, we know that the cost of 5 chocolate bars are $5.75.

For 1 chocolate bar

5.75 ÷ 5 = $1.15

Here, we get the price of 1 chocolate bar

So, the cost of 2 chocolate bars and 3 packets of sweets are $7.85.

2 × chocolate bar = 2 × (1.15) = $2.3

Now, we want to find only the cost of one packet of sweets.

So,

7.85 – 2.3 = $5.55

3 packets of sweets cost $5.55

For 1 packets of sweets

5.55 ÷ 3 = $1.85

Thus, The cost of one packet of sweets = $1.85

Answer:

O = 15

Step-by-step explanation:

.mean ' is the average

(12 + 16 + O + 14 + 8) / 5 = 13

50 + O = 65

O = 15

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve ~

[tex]\qquad \tt \dashrightarrow \:x - \dfrac{1}{2} \geqslant 43 [/tex]

[tex]\qquad \tt \dashrightarrow \:x \geqslant43 + \dfrac{1}{2} [/tex]

[tex]\qquad \tt \dashrightarrow \:x \geqslant \dfrac{86 + 1}{2} [/tex]

[tex]\qquad \tt \dashrightarrow \:x \geqslant \dfrac{87}{2} [/tex]

hope this helps Belinda aunty ~

Answer: 3/4 is 75%

Step-by-step explanation: Since his fav number is 36 the half of 36 is 18 bc 18 + 18 is 36

Answer:

13

Step-by-step explanation:

[tex]\text{determinant of A} =\begin{vmatrix}4&-7\\ 3&-2\end{vmatrix}[/tex]

[tex]\text{determinant of A} =\left( 4\times \left( -2\right) \right) -\left( 3\times \left( -7\right) \right)[/tex]

[tex]\text{determinant of A} =-8+21=13[/tex]

Answer:

282 ft

Step-by-step explanation:

Area of 2 triangles = 6+6

= 12 ft

Area of 3 rectangles = 90+90+90

= 270 ft

therefore

the surface area = 12 + 270

= 282 ft

I think that I am right

Thursday

Explanation:

Two days after Sunday is Tuesday

Tuesday would be the day before yesterday (Wednesday)

So today is Thursday

Answer:

The Day before the day before yesterday was two days after the day before my birthday. Today is Thursday. The following steps can be used in order to determine the day on birthday: Step 1 - Remember today is Thursday according to the given data. Step 2 - Now, the Day before the day before yesterday is Monday. Step 3 - The two days before Monday is Saturday. Step 4 - And the day of the birthday is after Saturday that is Sunday

Step-by-step explanation:

Answer:

10,000 is the total amount of.money that was distributed

[tex]x = 4\\y = 3[/tex]

Question is [tex]5x^3 + 4y^3[/tex]

We know what [tex]x[/tex] and [tex]y[/tex] are.

[tex]5x^3 + 4y^3 = 5 \times 4^3 + 4 \times 3^3\\= 5 \times 64 + 4 \times 27\\= 320 + 108\\= 428[/tex]

Answer:

4 5/6 quarts or 4.83 quarts

Step-by-step explanation:

5 1/2 quart pot has an equal value to 11/2 quart pot

it is filled with 2/3 quarts of water

Therefore, the quarts of water the pot can hold is;

11/2 - 2/3

LCM = 6

11/2 - 2/3 ÷ 6

33 - 4 ÷ 6

29/6

:. 29/6 quarts(4 5/6 quarts or 4.83 quarts) of water is the amount needed to fill the 5 1/2 quart pot

Answer:

S

ThenSn=n(a1+an)2Sn=n(a1 + an)2 , where nn is the number of terms, a1a1 is the first term and anan is the last term. The sum of the first nn terms of an arithmetic sequence is called an arithmetic series .

Step-by-step explanation:

Answer:

A = $1,742.75

A = P + I

Where

P is the principal (1,500.00)

I is the interest (242.75)

Steps:

First, convert R as a percent to r as a decimal

r = R/100

r = 1.5/100

r = 0.015 rate per year,

Then solve the equation for A

[tex]A = Pe^{rt}\\A = 1,500.00(2.71828)^{(0.015)(10)}\\A = $1,742.75[/tex]

Summary:

The total amount with compound interest on a principal of $1,500.00 at a rate of 1.5% per year compounded continuously over 10 years is $1,742.75.

Answer:

1. 4/5+2/3=?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(4/5, 2/3) = 15

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(45×33)+(23×55)=?

Complete the multiplication and the equation becomes

12/15+10/15=?

The two fractions now have like denominators so you can add the numerators.

Then: 12+10/15=22/15

This fraction cannot be reduced. The fraction

22/15 is the same as 22÷15

Convert to a mixed number using long division for 22 ÷ 15 = 1R7, so

22/15=17/15

Therefore: 4/5+2/3=17/15

Solution by Formulas Apply the fractions formula for addition, to 4/5+2/3 and solve

(4×3)+(2×5)/5×3

=12+10/15

=22/15 Convert to a mixed number using long division for 22 ÷ 15 = 1R7, so 22/15=17/15 Therefore:4/5+2/3=1  7/15

Step-by-step explanation:

Answer:

See below.

Step-by-step explanation:

1.

2.

3.

4.

Answer:

this would be 2

Step-by-step explanation:

Step-by-step explanation:

3(2x - 5) = 4(x+3)

Distribute. Multiply 3 by 2x so the product keeps the variable, multiply 3 by 5 and keep the subtraction symbol. Multiply 4 by x so it would be 4x, multiply 4 by 3

(6x-5=4x+12) Answer

Answer:

2827.43 cm^2

Step-by-step explanation:

Hope this helped! <3 Have a great day :) Brainliest please?

Answer:

Below in bold.

Step-by-step explanation:

Supplementary angles add up to 180 dgrees, so we have the equation:

3x + 19 + 7x - 9 = 180

10x + 10 = 180

10x = 180 - 10

10x = 170

x = 17.

So m <ABC = 3(17) + 19 = 70 degrees

and m < DBC = 7(17) - 9 = 110 degrees.

Answer:

3x + 19+7x-9=180

10x+10=180

10x=180-10

10x=170

x =17

B

is the answer. Good luck!!

✰ Given Information :-

⠀

A cylinder with following dimensions :

⠀

✰ To Find :-

⠀

⠀

✰ Formula Used :-

⠀

[tex] \qquad \star \: \underline{ \boxed{ \purple{\sf Volume_{Cylinder} = \pi {r}^{2} h}}} \: \star[/tex]

⠀

Where,

⠀

✰ Solution :-

⠀

Putting the values in the formula, we get,

⠀

[tex] \sf \longrightarrow Volume=3.14 \times {(3)}^{2} \times 5 \\ \\ \\ \sf \longrightarrow Volume=3.14 \times 45 \: cm \: \: \: \: \: \\ \\ \\ \sf \longrightarrow \underline{ \boxed{ \green{ \frak{Volume= {141 .3 \: cm}^{3} }}}} \: \star \: \: \: \: \: \\ [/tex]

⠀

Thus, the volume of the cylinder is 141.3 cm³.

⠀

[tex] \underline{ \rule{230pt}{2pt}} \\ \\ [/tex]

Step-by-step explanation:

As it is given that, a cylinder has radius 3 inches and height 5 inches and we are to find the volume of the cylinder, also a extra information is given that is a cone has the same radius and height.

[tex] \: [/tex]

We know,

[tex]{ \longrightarrow\qquad{\frak {\pmb{Volume_{(cylinder) } = \pi {r}^{2}h }}}} \\ \\[/tex]

Where,

[tex] \: [/tex]

Now, we will substitute the given values in the formula :

[tex] \: [/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{Volume_{(cylinder) } = 3.14 \times ( {3})^{2} \times 5 }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{Volume_{(cylinder) } = 3.14 \times 9 \times 5 }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{Volume_{(cylinder) } = 3.14 \times 45 }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{\frak {\pmb{Volume_{(cylinder) } = 141.3 }}}} \\ \\[/tex]

Note :