Resistance is a material's tendency to resist the flow of charge (current). Resistance is the measure of the opposition to motion of free electrons(current) due to their continuous collisions with the atom of the lattice. An electric current flows when electrons move through a conductor, such as a metal wire. The moving electrons can collide with the atoms in the metal. This makes it more difficult for the current to flow, and causes resistance. The unit of Resistance is "OHM". Ohm is denoted by the greek letter "Ω".
_____________________________________Question 2:[tex]\Huge\text{Ohm's Law}[/tex]If a current 'I' is caused to flow in a conductor by a battery of potential difference 'V', it is found that the current is directly proportional to potential difference provided there is no change in the conductor itself. That means more will be I if we increase V. So
[tex]{\Longrightarrow}\qquad \qquad \qquad I {\propto} V\\\\{\Longrightarrow}\qquad \qquad \qquad I = KV[/tex]
Where K is Conductance. Conductance is the ability of a conductor to allow the current to pass through it. Resistance(R) is the reciprocal(opposite) of conductance(K) thus K is inversely proportional to R,
[tex]{\Longrightarrow}\qquad \qquad \qquad I = \frac{1}{R}V \\\\{\Longrightarrow}\qquad \qquad \qquad V = IR[/tex]
This is known as OHM's Law, and V = IR is the equation linking the R, V and I.
_____________________________________Question 3:[tex]\Huge\text{Circuit Diagram:}[/tex]
Circuit Diagram no 1 attached is of this question. In the circuit diagram, V is voltmeter to find the potential difference, A is the ammeter to find the current, R is the resistance i.e. the conductor wire, The switch and the battery.
Suppose the wire of length 100 cm is connected to a battery, the Voltmeter observes the potential difference and ammeter reads the current of the wire. We will use the R, V and I i.e. V = IR equation to find out the resistance of that wire and Record the resistance. Then attach another small wire of suppose 90 cm to the battery, and similarly Find out its resistance too. After recording the resistance 3 or 4 times, you will observe that When you decrease the length of the wire,
The Resistance decreasesThe Current increases The Potential Difference decreases_____________________________________Question 4:[tex]\Huge\text{Resistance:}[/tex]The resistance of a conductor depends upon the following factors.
Length(L), Longer the length of conductor, Greater the resistance.[tex]{\Longrightarrow}\qquad \qquad \qquad R\quad {\propto}\quad L[/tex]
Cross-Sectional Area(A), thicker the Wire, lesser the Resistance.[tex]{\Longrightarrow}\qquad \qquad \qquad R\quad {\propto}\quad \frac{1}{A}[/tex]
Material of the Conductor, The Resistance also changes because of the material of the wire. If we use copper it will have different resistance than the steel wire.The relation between only length of the wire and resistance is [tex]R\quad {\propto} \quad L[/tex] . The relation of R, L and A is given by, ρ
[tex]{\Longrightarrow}\qquad \qquad \qquad R\quad {\propto}\quad \frac{L}{A}\\\\{\Longrightarrow}\qquad \qquad \qquad R\quad =\ \frac{\ {\rho}\ L\ }{A}[/tex]
Where ρ is known as resistivity depends upon the nature of the material of the wire. The meter of resistivity is Ω x m(Ohm x meter).
_____________________________________Question 5:[tex]\Huge\text{I-V Characteristic:}[/tex]
I-V curves of an electrical device or component, are a set of graphical curves which are used to define its operation within an electrical circuit. I-V characteristic curves show the relationship between the current flowing through an electronic device and the applied voltage across its terminals. The circuit diagram to find I-V characteristic must have a resistor which is a device or component connected to a battery which is providing the potential difference V. When a resistor is connected to a battery, current I is observed due to drift velocity. To find the current and potential difference(voltage) the circuit must have the Ammeter and voltmeter. Recorded current and voltage must be used to plot the graph to check the I-V characteristic. The picture attached is the circuit diagram.
_____________________________________Question 6:We calculate the resistance at constant temperature by ohm's law. The Ohms law is applied at constant temperature because the resistance of any material varies with the change in temperature. It shows a linear relationship between the applied voltage and the resulting current, resistance being a constant. So we could use V = IR because resistance is constant at constant temperature.
_____________________________________Best Regards,'Borz'
How much force is needed to accelerate 250 kg at a rate of 6 m/s/s?
Answer:
[tex]1500 \: \mathrm{N}[/tex]
Explanation:
The equation [tex]F=ma[/tex] represents the force needed.
Plugging in [tex]m=250[/tex] and [tex]a=6\: \mathrm{m/s^2}[/tex], we find that the force needed to accelerate a 250 kg object at a rate of [tex]6 \: \mathrm{m/s^2}[/tex] to be [tex]\fbox{$1500 \: \mathrm{N}$}[/tex].
ANSWER QUICK 30 POINTS
What force controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters? Thoroughly explain your answer, making sure to include an example and describe how this force keeps planets in orbit. Make sure to write at least 3-5 sentences and proper conventions (spelling, grammar, punctuation, etc.) to respond. Put all answers in your own words
Answer:
Gravity controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters. The Universal Law of Gravitation depends on two things. First it depends on mass of each object and the second factor is the distance between two objects. If the mass of one object is Larger, the gravitational pull towards it will be larger and the smaller distance, the larger the gravitational pull will be between the objects. Therefore the Larger planets have more moon and the inner planets have less.
Explanation:
Which two life functions of animals help maintain the water cycle by recycling water back into the environment?
Answer:
Respiration and excretion
Explanation:
Respiration. When animals breathe, their lungs release water vapour to the atmosphere.
Animals excrete water by respiration and by passing urine.
I need help please I will give points
Answer:
-5 N of force
Explanation:
Hope it helps!
2. Arrange the following types of electromagnetic waves in order by wavelength, from longest to
shortest: Gamma rays, visible light, infrared radiation, ultraviolet radiation, microwaves, radio
waves, X-rays
Answer:
Radiowaves > microwaves> Infrared radiation > visible light > Ultraviolet radiation > x -rays > gamma rays
Explanation:
To solve this problem, we use the electromagnetic spectrum as a reference. On the electromagnetic spectrum, the lesser the wavelength, the higher the frequency and more energetic a wave is.
Therefore;
Radiowaves > microwaves> Infrared radiation > visible light > Ultraviolet radiation > x -rays > gamma rays
So, radiowaves have the longest wavelength and gamma rays have the shortest.
Answer:
Radio, microwave, infrared radiation, visible light, ultraviolet radiation, x-rays and gamma rays.
Explanation:
These electromagnetic waves are arranged from longest to shortest wavelengths.
Have an amazing day!
An object is subject to a 84 Nm torque about a point when a
21 N of force is applied to a second point along the object's
length. How far apart are the two points
Answer:
d = 4[m]
Explanation:
Torque in physics is defined as the product of force by distance. This way you can use the following equation to calculate the torque.
[tex]T=F*d[/tex]
where:
T = torque [N*m]
F = force [N]
d = distance [m]
Now replacing in the equation above.
[tex]84=21*d\\\\d= 4[m][/tex]
Will mark brainliest Why are acoustic panels are used in concert halls
Answer:
what person above said is correct
Explanation:
The walls of the concert halls are used to control the acoustic. ... Rough surfaces can also be used to disperse sound in all directions – this might be used in concert halls to get rid of echoes that would distract from performances.
An acoustic panel is a sound-absorbing panel used to mitigate noise and reduce the reverberation and echo in a space. For both types, we can talk about different principles of good acoustics: absorption, diffusion, and attenuation. These are all linked to the acoustic performance of the panels.
brainliest?a train has an initial velocity of 44m/s and an accelaration of _4m/s calculate its velocity
Answer:
It's 4m/s
Explanation:
V = u _ at, at u = 44m/s
44 + [-4]10
4m/s
Hi!! Does anyone know this answer? :D
Answer:
Im not fully corrrect but I would say C
Explanation:
If the mass of an object increases, then its kinetic energy will ____________ because __________________________
Answer:
when mass will increase then kinetic energy will also increase because both have positive relationship
Explanation:
when volume increase then molecule come closer then more movement will occurs and kinetic energy increase
explain how balanced and unbalanced forces effect an objects motion differently
Answer:
Balanced Forces will not change the object's motion.
Unbalanced Forces will change the object's motion.
Explanation:
PLEASE HELP ASAP!!!!!
Carrie pulls a 41.5 kg bin across the floor of her garage using a rope that is attached to the bin. She pulls with a force of 138 N, at an angle of 28.0° above horizontal. The coefficient of kinetic friction between the floor and the box is 0.290 . What is the acceleration of the box?
Answer: 0.81N
Explanation: Fwx = .165x 9.81 Silicon 30 = 0.81N
Question 17 of 25
A sound wave from a brass bell passes through the air with a
wavelength of 3.5 m. When the sound wave originated in the
brass bell, its wavelength was 47 m. If the sound wave has a
constant frequency of 100 Hz, what was its speed as it
traveled through the brass bell? (The equation for wave speed
is v= f*1.)
A. 3,500 m/s
B. 4,700 m/s
C. 350 m/s
D. 470 m/s
Answer:
The speed of the wave as it travelled through the brass bell is;
B. 4,700 m/s
Explanation:
The given parameters are;
The wavelength of the sound wave produced from the brass bell, [tex]\lambda _{(air)}[/tex] = 3.5 m
The wavelength of the wave in the brass bell, [tex]\lambda _{(brass \ bell)}[/tex] = 47 m
The frequency of the wave in the brass bell, f = 100 Hz
The given equation for wave speed, v = f × λ
Therefore, the speed of the wave as it travelled through the brass bell, [tex]v _{(brass \ bell)}[/tex], is given as follows;
[tex]v _{(brass \ bell)}[/tex] = f × [tex]\lambda _{(brass \ bell)}[/tex] = 100 Hz × 47 m = 4,700 m/s
The speed of the wave as it travelled through the brass bell = [tex]v _{(brass \ bell)}[/tex] = 4,700 m/s
Answer:
B.) 4700 m/s
Explanation:
On Earth, a spring stretches by 5.0 cm when a mass of 3.0 kg is suspended from one end.
The gravitational field strength on the Moon is
1/6 of that on Earth.
Which mass, on the Moon, would stretch the spring by the same extension?
Reasons too :(
igcse physics
Answer:
Mass = 18.0 kg
Explanation:
From Hooke's law,
F = ke
where: F is the force, k is the spring constant and e is the extension.
But, F = mg
So that,
mg = ke
On the Earth, let the gravitational force be 10 m/[tex]s^{2}[/tex].
3.0 x 10 = k x 5.0
30 = 5k
⇒ k = [tex]\frac{30}{5}[/tex] ................ 1
On the Moon, the gravitational force is [tex]\frac{1}{6}[/tex] of that on the Earth.
m x [tex]\frac{10}{6}[/tex] = k x 5.0
[tex]\frac{10m}{6}[/tex] = 5k
⇒ k = [tex]\frac{10m}{30}[/tex] ............. 2
Equating 1 and 2, we have;
[tex]\frac{30}{5}[/tex] = [tex]\frac{10m}{30}[/tex]
m = [tex]\frac{900}{50}[/tex]
= 18.0
m = 18.0 kg
The mass required to produce the same extension on the Moon is 18 kg.
Answer:
18 kg
Explanation:
weight (N) = mass (kg) × gravitational acceleration (m/s²)force (N) = k (spring constant) × extension (m)On Earth, acceleration of gravity is 10 m/s²
weight = 3.0 (kg) × 10 (m/s²)weight = 30 (N)Since weight is a force, the force is 30 N. The value of spring constant is unknown
30 (N) = k × 5 (m)k = 6 (m/N)Spring constant is 6. Now let's find the mass on the Moon
mass (kg) × gravitational acceleration (m/s²) = k (spring constant) × extension (m)Gravitational acceleration of the moon is 1/6 of that on Earth. Earth's g = 10, so Moon's g = 10/6
m × 10/6 = 6 × 5m = 30/(10/6)m = 18The mass is 18 kg
A sample of gas in a syringe releases heat to its surroundings while the
plunger is pulled out. What are the correct signs of heat and work for this
change?
A. +Q+W
B. --W
O C. +Q, -W
D. -Q. +W
Answer: b
Explanation:
When heat is released by the system i.e. system loses heat. So, we take it as negative -Q
When the work is done on the system then it is considered as negative work on the system i.e. -W
In this case, the plunger is pulled out, and work is done on the system. So, we take work as negative work -W
Correct option is b
The answer is D.
-Q +W
Two spheres have a gravitational force between
them of 45 N. If the distance between the masses
is increased to 4.0 times its original distance, what
is the new force?
Answer:
The new force is 2.8125 N
Explanation:
Newton’s Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2
Suppose two spheres have a gravitational force between them of F = 45 N. Now increase the distance to r'=4r. The new force F' is:
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{(4r)^{2}}}[/tex]
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{16r^{2}}}[/tex]
[tex]\displaystyle F'=\frac{1}{16}\ G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Substituting the original value of the force:
[tex]\displaystyle F'=\frac{1}{16}\ 45 N[/tex]
F' = 2.8125 N
The new force is 2.8125 N
please answerrr asapp tyty Laura goes for cycle from her house to the post office 4km away how long did it take for Laura to reach the post office
Answer:
See the answer below
Explanation:
The time Laura took to reach the post office would depend on the speed of cycling.
We know that;
speed = [tex]\frac{distance}{time}[/tex]
hence,
time = [tex]\frac{distance}{speed}[/tex]
Since the distance from Laura's house to the post office is 4 km, the equation becomes;
time = [tex]\frac{4}{speed}[/tex]
Just ensure that the speed is in km per hour, minute, or seconds in order to obtain the time in hours, minutes, or seconds respectively.
At the height of 800 meters, a skydiver falls from an airplane flying horizontally at 40 m/sec. What is the horizontal distance of the skydivers travel before they "hit" the ground?
Answer:
The horizontal distance traveled by the skydiver is 510.8 m.
Explanation:
Given;
height of fall, h = 800 m
initial velocity of the airplane, u = 40 m/s
The time to fall to the ground is calculated as;
[tex]t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2 \times 800}{9.81} }\\\\t = 12.77 \ s[/tex]
The horizontal distance or range of the motion is calculated as;
R = ut
R = 40 m/s x 12.77 s
R = 510.8 m
Therefore, the horizontal distance traveled by the skydiver is 510.8 m.
Please help me this is worth allot
If the boy travelled 2 meters to the right and 4 meters to the left what is the total distance that he travelled?
4 m
-4 m
6 m
2 m
Answer:
6m
Explanation:
2+4=6
.A water tank has dimensions
of 6m x 4m x 4m. Find the pressure exerted by
water at the base of dam when it is half
filled. ( Density of water - 1000 kg/ m2,
acceleration
due to to gravity is 9.8m/s2
Answer:
9800Nm⁻²
Explanation:
Given parameters:
Dimensions of the water tank = 6m x 4m x 4m
Density of water = 1000kgm⁻³
Gravity = 9.8m/s²
Unknown:
Pressure exerted by the water at the base of the dam = ?
Solution:
The pressure exerted by the water is given as:
Pressure = density of water x acceleration due to gravity x height of water
The height of the water here is half = 1m
Pressure = 1000 x 9.8 x 1 = 9800Nm⁻²
A pickle sits 8.0 cm from the center of a circular, rotating platter. The platter rotates such
that the pickle's tangential speed is 4.8 cm/s. What is the pickle's centripetal
acceleration?
(A) 0.36 cm/s
(B) 0.60 cm/s2
(C) 1.2 cm/s2
(D) 2.9 cm/s2
(E) 5.8 cm/s2
can be answered using momentum.
momentum = p
p1= mass1 * velocity1
p1 = p2
therefore
p1 = 6kg * 4m/s
p1 = 24kgm/s
p2=m2 * v2
24 kgm/s = 7kg * v2
v2 = 24 kgm/s / 7kg
v2= 3.42 m/s
Brian Berg of lowa built a house of cards 4.88 m tall. Suppose Berg throws a ball from ground level
with a velocity of 9.98 m/s straight up. What is the velocity of the ball as it first passes the top of
the card house?
Answer:
Vf = final velocity = 1.96 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}^{2}=v_{o}^{2}-2*g*x[/tex]
where:
Vf = final velocity [m/s]
Vo = initial velocity = 9.98 [m/s]
g = gravity acceleration = 9.81 [m/s²]
x = vertical distance [m]
[tex]v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s][/tex]
Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.
1. A kangaroo hops 84 m to the east in 7 seconds.
o What is the kangaroo's speed? 12 m/s
o What is the kangaroo's velocity?
Explanation:
Given parameters:
Distance hopped = 84m
Displacement = 84m due east
Time = 7s
Unknown:
Speed of kangaroo = ?
Velocity of kangaroo = ?
Solution:
To solve this problem,
Speed = [tex]\frac{distance}{time }[/tex] = [tex]\frac{84}{7}[/tex] = 12m/s
Velocity = [tex]\frac{displacement}{time}[/tex] = [tex]\frac{84}{7}[/tex] = 12m/s due east
Nina's measurements, shown in the table here, BEST represent a wave with
A)
decreasing frequency.
B)
increasing frequency.
C)
increasing amplitude.
D)
decreasing amplitude.
Nina's data in this table most accurately depict a wave with decreasing frequency. Option A is right.
What is frequency?A recurring event's frequency is measured by how many times it occurs in a unit of time.
To emphasize distinctions with spatial and angular frequencies, respectively, it is also sometimes referred to as ordinary frequency or temporal frequency.
If the duration, or time interval, required to complete one cycle or vibration is half a second, the frequency is 2 per second; if it is one hundredth of an hour, the frequency is 100 per hour.
The frequency and period, or time interval, are often reciprocally equal, therefore frequency = 1/period = 1 in most circumstances.
The Moon rotates about Earth about a little bit more than 12 times a year. In a violin A string vibrates at a frequency of 440 cycles per second.
Thus, the correct option is A.
For more details regarding frequency, visit:
https://brainly.com/question/5102661
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If an object undergoes a change in velocity, then it also undergoes a change in:
Answer:
acceleration
Explanation:
If the velocity is not constant, then there must be a beginning and ending of its velocity. If that is so and there is also a change in time (which there must be) then there is a change in acceleration.
The formula for that is a = (vf - vi)/t
Answer:
probably acceleration
Explanation:
acceleration is the change in velocity
which unit would be most
suitable for its scale?
Answer:
down below
Explanation:
for a scale, kg is used, as well as grams
for force, newtons is used
Please help I’ll give you brain
Answer:
Explanation:
distance (km)
a) As near as I can tell from the graph, the distance travelled was 4km
b) I would answer 40 minutes, but don't be surprised if your instructor says 30 minutes.
c) The average speed is 4 km/40 minutes = 0.1 km/minute
What is the volume of a liquid in a 50 mL cup?
A. 50mL
B. 10mL
C. There is not enough information to answer this question.
Answer:
there is not enough information
5
Select the correct answer.
Which statement best explains the relationship between electric force and the charges on two interacting objects?
СА.
Electrical force is directly proportional to the product of the charges on the two objects.
B.
Electrical force is inversely proportional to the product of the charges on the two objects.
Electrical force is inversely proportional to the product of the squares of the charges on the two objects.
D. Electrical force is directly proportional to the product of the squares of the charges on the two objects.
Answer:
Electrical force is directly proportional to the product of the charges on the two objects.
Explanation:
The electric force between two charges is given by :
[tex]F=\dfrac{kq_1q_2}{d^2}[/tex]
Where
k is electrostatic constant
q₁ and q₂ are charges
d is the distance between charges
It can be very clear that the electric force is directly proportional to the product of charges and inversely proportional to the square of the distance between them.
Hence, the correct option is (a) "Electrical force is directly proportional to the product of the charges on the two objects".