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Since g(x) = x² - 6x - 16, a statement which is true include the following: C. The zeros are -2 and 8, because the factors of g are (x+2) and (x-

8).

In Mathematics and Geometry, the general form of a quadratic function can be modeled and represented by using the following quadratic equation;

y = ax² + bx + c

Where:

Next, we would solve the quadratic function by using the factorization method as follows;

g(x) = x² - 6x - 16

0 = x² - 6x - 16

0 = x² - 8x + 2x - 16

0 = x(x - 8) + 2(x - 8)

(x - 8)(x + 2)

x = 8 or x = -2.

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Answer:

To evenly space the letters of "EAGLES" across a 63 inch wide banner with no margins, you would need to divide the remaining space between each letter of the word equally. With five letters total and each letter being 8 inches wide, the total width occupied by the letters is 40 inches. Therefore, the remaining space is 23 inches (63-40=23). To find out how many inches should exist between each pair of letter, you would divide the remaining space by the number of gaps between the letters, which is 4 (one less than the total number of letters in the word).

23 inches ÷ 4 gaps = 5.75 inches between each pair of letters.

Step-by-step explanation:

Answer:

16.5

Step-by-Step Explanation:

16.5 would be the average because it is right between 16 and 17. hope that helps :)

Answer:

0 ≤ < 2

Step-by-step explanation:

Answer:1.02 5.27 are correct

Step-by-step explanation:We can solve this quadratic equation in cos(θ) by using the substitution u = cos(θ):

3u^2 + 6u - 4 = 0

Now we can use the quadratic formula to solve for u:

u = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 3, b = 6, and c = -4. Substituting these values, we get:

u = (-6 ± sqrt(6^2 - 4(3)(-4))) / 2(3)

u = (-6 ± sqrt(84)) / 6

u = (-3 ± sqrt(21)) / 3

Therefore, either:

Answer:

--------------------------

To find the slope use the slope formula:

Substitute the coordinates into slope formula to get the slope:

The matching choice is B.

Answer:

-m = x is the answer hope it helps

Answer: 504 different ways.

Step-by-step explanation:

      This situation uses a permutation. We will use the given formula and simplify to solve. n is equal to the number of contestants and r is 3 since we are selecting and first-, second-, and third-place winner.

Given:

      [tex]\displaystyle P = \frac{n!}{(n-r)!}[/tex]

Substitute values:

      [tex]\displaystyle P = \frac{9!}{(9-3)!}[/tex]

Subtract:

      [tex]\displaystyle P = \frac{9!}{6!}[/tex]

Multiply:

      [tex]\displaystyle P = \frac{9*8*7*6*5*4*3*2*1}{6*5*4*3*2*1}[/tex]

Simplify using the knowledge that something divided by itself is 1:

      P = 9 * 8 * 7

Multiply:

      P = 504

      We can also think of it as 9 different people could win 1st, 8 different people could win 2nd, and 7 different people could win 3rd. 9 * 8 * 7 = 504. However, the steps above show why this works with the formula as well.

Answer:

Step-by-step explanation:

ask ur teacher

0.034141137 o sobre 17/500

Differentiating y = x^3 ln 2x/e^x Sin x is: y' = x^2 [(3 ln 2x/e^x Sin x + 3/x) - 2 ln 2x/e^x Sin x cos x + cos x].

Differentiate y can be find using the product and chain rule.

Using the chain rule

v'(x) = [1/(2x/e^x)] * (2e^x - e^x*2x) / (2x/e^x)^2

v'(x) = [e^x(2-e^x)] / (2x)^2

Using the product rule

y' = 3x^2 ln(2x/e^x) sin(x) + x^3 [e^x(2-e^x)] / (2x)^2 sin(x) + x^3 ln(2x/e^x) cos(x)

Simplifying

y' = 3x^2 ln(2x/e^x) sin(x) + (x/2) [2-e^x] sin(x) + x^3 ln(2x/e^x) cos(x)

So,

derivative of y is:

y' = 3x^2 ln(2x/e^x) sin(x) + (x/2) [2-e^x] sin(x) + x^3 ln(2x/e^x) cos(x)

Therefore the differentiate of y is 3x^2 ln(2x/e^x) sin(x) + (x/2) [2-e^x] sin(x) + x^3 ln(2x/e^x) cos(x).

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Answer:

68

Step-by-step explanation:

the median is the term in the middle (53) the upper quartile is the median of the terms above the median. Since there are an even number of terms, you need to average them (58+78)/2

Answer:

been wondering that my self

Step-by-step explanation:

that's why they asked

Answer:

5cm

Step-by-step explanation:

To find the radius of the base of the cone, we need to use the formula for the volume of a cone, which is V=31​πr2h

, where V is the volume, r is the radius, and h is the height1

We are given the volume and the height, so we can plug them into the formula and solve for r:

200π=31​πr2(24)

Simplify and isolate r:

r2=8π200π​

r2=25

r=25​

r=5

Therefore, the radius of the base of the cone is 5 cm.

Answer:

Step-by-step explanation:

To distribute the expression 18+(d+3)(d-3)(4), you can use the distributive property of multiplication, which states that a(b+c) = ab + ac.

Here's how you can apply the distributive property to the expression:

First, simplify the expression inside the parentheses by using the difference of squares formula: (d+3)(d-3) = d^2 - 3d + 3d -9

(d+3)(d-3) = d^2 - 9

So now the expression becomes:

18 + (d^2 - 9)(4)

Next, use the distributive property to multiply 4 by each term inside the parentheses:

18 + 4d^2 - 36

Simplify by combining like terms:

4d^2 - 18

So the final result is 4d^2 - 18

Answer:

If you called at 11:45 pm and were on the phone for 1 hour 24 minutes, the call would have ended at 1:09 am.

Rounding to the closest hundredth, the final result is 12.16 mL, which is the amount of the drug that should be administered.

The patient's weight must first be converted from pounds to kilograms.

1 lb = 0.453592 kg

Therefore, 134 lb = 60.78 kg

The dose must then be determined depending on the patient's weight:

60.78 kg times 5 mg/kg equals 303.9 mg.

Now that we know the medication's concentration, we need to determine how much to deliver.

25 mg/mL x 125 mg/5 mL

The dosage for 303.9 mg is as follows:

303.9 mg x 25 mg/mL = 12.16 mL

The final result, rounded to the closest hundredth, is 12.16 mL.

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The number of rooms of the same size it willl vaccum in 3 hours is 10

From the question, we have the following parameters that can be used in our computation:

Unit rate = 3/10 hour per room

Time = 3 hours

using the above as a guide, we have the following:

Number of rooms = Time/Unit rate

Substitute the known values in the above equation, so, we have the following representation

Number of rooms = 3/(3/10)

Evaluate the quotient

Number of rooms = 10

Hence, the number of rooms is 10

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The value of angle 1 given the value of angle 4 as 47° will be 133°

Parallel lines are two lines on a two-dimensional plane that, no matter how far they are extended, never collide. They always keep the same gap between them.

Parallel lines have the same slope, which means they have the same angle of inclination or steepness. In other words, they rise and fall at the same pace along their length.

The value will be:

= 180° - 47°

= 133°

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Answer:

a. The given equation is (y - 3)^2 -10 = 71. To determine the number and type of solutions, we need to use the discriminant, which is given by b^2 - 4ac, where a, b, and c are the coefficients of the quadratic equation in standard form (ax^2 + bx + c = 0). In this case, the equation can be rewritten as (y - 3)^2 = 81, which is in the form of (y - k)^2 = r^2, where k = 3 and r = 9. Therefore, the equation can be written as (y - k)^2 - r^2 = 0, which is a quadratic equation with a = 1, b = -6, and c = -72. The discriminant is then b^2 - 4ac = (-6)^2 - 4(1)(-72) = 300. Since the discriminant is positive, there are two real solutions.

b. To solve the equation (y - 3)^2 -10 = 71, we first add 10 to both sides to get (y - 3)^2 = 81. Then, we take the square root of both sides to get y - 3 = ±9. Adding 3 to both sides, we get y = 3 ± 9, which gives us two solutions: y = 12 and y = -6.

Therefore, the equation (y - 3)^2 -10 = 71 has two real solutions, which are y = 12 and y = -6.

Step-by-step explanation:

Answer:  type: real   number of solutions:2   y=12,-6

Step-by-step explanation:

see images for explanations

Answer:

Step-by-step explanation:

a. Using the formula p(t) = 1 - e^(-kt), where k = 0.28:

Probability of mastering the dance's steps in 1 trial: p(1) = 1 - e^(-0.28*1) ≈ 0.243

Probability of mastering the dance's steps in 2 trials: p(2) = 1 - e^(-0.28*2) ≈ 0.446

Probability of mastering the dance's steps in 5 trials: p(5) = 1 - e^(-0.28*5) ≈ 0.846

Probability of mastering the dance's steps in 11 trials: p(11) = 1 - e^(-0.28*11) ≈ 0.981

Probability of mastering the dance's steps in 16 trials: p(16) = 1 - e^(-0.28*16) ≈ 0.997

Probability of mastering the dance's steps in 20 trials: p(20) = 1 - e^(-0.28*20) ≈ 0.999

b. The rate of change, p'(t), can be found by taking the derivative of the function p(t):

p'(t) = k * e^(-kt)

c. Here's a graph of the function p(t):

I apologize for the technical issue, but the graph doesnt load, so here's a description of the graph:

The graph of p(t) should be an increasing curve that starts at 0 and approaches 1 asymptotically. As t increases, the rate of change of p(t) decreases, which means that the curve becomes flatter and approaches the horizontal asymptote of y=1. The curve is concave down, meaning that its rate of change is decreasing. At t=0, the rate of change is k, which is the steepest point of the curve.

_______________________

graph of p(t) = 1 - e^(-0.28*t)

The x-axis represents the number of learning trials, and the y-axis represents the probability of mastering the dance's steps. As the number of trials increases, the probability of mastering the steps approaches 1 (or 100%).

The value of variable 'v' in the expression ( v - 2 ) / (2v² + 10v ) + 1 / ( 2v + 10 ) = 1 / 2 is equal to -4.

The expression is equal to,

( v - 2 ) / (2v² + 10v ) + 1 / ( 2v + 10 ) = 1 / 2

Simplify the expression we have,

⇒ ( v - 2 ) / 2v ( v + 5 ) + 1 / 2( v+ 5 ) = 1 / 2

Take the least common multiple of the denominator we have,

⇒ [( v - 2 ) + 2 ] / 2v( v+ 5 ) = 1 / 2

⇒ v  / 2v( v+ 5 ) = 1 / 2

Multiply both the sides of the expression by 2 we get,

⇒ 1 / 2( v+ 5 ) = 1 / 2

⇒ 1 /( v + 5 ) = 1

Cross multiply the expression we get,

⇒ v + 5 = 1

Subtract 5 from the both the sides of the equation we get,

⇒ v = -4

Therefore , the value of v in the given expression is equal to -4.

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Answer:

The normalization property of the distribution law states that the sum of probabilities of all possible outcomes must equal 1. In this case, we have:

P(X=k) = c/2^k, for k = 0, 1, 2, ...

To find the value of the constant c, we need to use the normalization property:

∑ P(X=k) = ∑ c/2^k = c/2^0 + c/2^1 + c/2^2 + ... = 1

To simplify this expression, we can use the formula for the sum of an infinite geometric series:

∑ a*r^n = a/(1-r), where a is the first term, r is the common ratio, and n goes from 0 to infinity.

In this case, a = c, r = 1/2, and n goes from 0 to infinity. So we have:

∑ P(X=k) = ∑ c/2^k = c/2^0 + c/2^1 + c/2^2 + ... = c/(1-1/2) = 2c

Setting this expression equal to 1, we get:

2c = 1

c = 1/2

Therefore, the value of the constant c is 1/2.

Step-by-step explanation:

The solid that is produced rotating the triangle about the line m is given as follows:

A cylinder with height of 2 units.

The cylinder has a circular base, hence we must start there, then we consider that;

Rotating the line, the features of the cylinder generated are given as follows:

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Note that where the above conditions are given, m∠FCA is also = 158°. This is due to the principle of alternate angles.

A pair of angles that are created by a transversal intersecting two parallel lines, known as alternate angles, have key properties which contribute to their importance in geometry.

They take place on opposite sides of the transversal and have equal magnitudes.

These concepts aid in understanding vertical angles and parallel lines within geometrical systems.

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Answer: ur correct answer is 158

Step-by-step explanation: not doing this to tke points!!

Answer:

6.7 = π(r^2)(33.5/12)

r = .874

75/(2 × .874) = 42.9 = 42 barrels

6.7 = (3.14)(r^2)(33.5/12)

r = .874

75/(2 × .874) = 42.9 = 42 barrels

The price at the point of equilibrium is 105

From the question, we have the following parameters that can be used in our computation:

The supply/demand graph

The price at the point of equilibrium is the price where the lines/curves of the supply and the demand functions intersect

Using the above and the graph as a guide, we have the following:

Price = 105 when demand = supply

Hence, the price at the point of equilibrium is 105

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Question

Using the above supply/demand graph, what is the price at the point of equilibrium? a. 105 b. 100 c. 95 d. 80

The expression for the area under the graph of f(x) = √x as a limit of Riemann sums is A = lim [n -> ∞ ] Ax [f(x₁) + f(x₂) + ... + f(xₙ)]

For a continuous function f(x), the area A of the region S that lies under the graph of the function can be expressed as the limit of the sum of the areas of approximating rectangles. Each rectangle has a width of Ax, where A is the interval over which we want to find the area and x is a point within that interval. The height of each rectangle is f(x).

Using this definition, we can find an expression for the area under the graph of f(x) = √x, where 1 ≤ x ≤ 13. We start by dividing the interval [1, 13] into n subintervals, each of width Ax = (13-1)/n = 12/n. We can label the endpoints of the subintervals as x₁, x₂, ..., xₙ+1, where x₁ = 1 and xₙ+1 = 13.

Next, we approximate the area under the curve using n rectangles. The height of the ith rectangle is f(xi), where xi is any point in the ith subinterval. The width of each rectangle is Ax, so the area of the ith rectangle is f(xi) Ax. The total area of the rectangles is then the sum of the areas of each rectangle:

f(x₁) Ax + f(x₂) Ax + ... + f(xₙ) Ax

We can simplify this expression by factoring out the common factor of Ax:

Ax [f(x₁) + f(x₂) + ... + f(xₙ)]

Taking the limit as n approaches infinity, we obtain:

A = lim [n -> ∞] Ax [f(x₁) + f(x₂) + ... + f(xₙ)]

To evaluate the limit, we need to find a formula for the sum of f(xi) for i = 1 to n.

This is a sum of square roots, which can be approximated using numerical methods or evaluated exactly using calculus techniques such as the definite integral.

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Answer:

[tex]\displaystyle \lim_{n \to \infty}\sum^n_{i=1}\left(\dfrac{12}{n}\right)\sqrt[7]{1+\dfrac{12i}{n}}[/tex]

Step-by-step explanation:

The Riemann sum is a method by which we can approximate the area under a curve using a series of rectangles.

The area under the curve of f(x) on the interval [a, b] is represented by:

[tex]\boxed{\begin{minipage}{6cm}$\displaystyle \int^b_af(x)\; \text{d}x=\lim_{n \to \infty}\sum^n_{i=1}f(x_i) \cdot \Delta x$\\\\\\where $\Delta x=\dfrac{b-a}{n}$ and $x_i=a+\Delta x \cdot i&\\\end{minipage}}[/tex]

Δx is the width of each rectangle.

[tex]f(x_i)[/tex] is the height of each rectangle.

[tex]x_i[/tex] is the right endpoint of each rectangle.

Therefore:

[tex]\begin{aligned}\displaystyle \int^b_af(x)\; \text{d}x&=\lim_{n \to \infty}\sum^n_{i=1}f(x_i) \cdot \Delta x\\\\&=\lim_{n \to \infty}\sum^n_{i=1}f\left(a+\left(\dfrac{b-a}{n}\right)i\right) \cdot \left(\dfrac{b-a}{n}\right)\end{aligned}[/tex]

The given interval is [1, 13]. Therefore, a = 1 and b = 13:

[tex]\implies \Delta x=\dfrac{13-1}{n}=\dfrac{12}{n}[/tex]

As f(x) = ⁷√x then:

[tex]\implies f(x_i)=f(a+i \Delta x)=\sqrt[7]{a+\Delta x \cdot i}=\sqrt[7]{1+\dfrac{12i}{n}}[/tex]

Substituting into the summation formula:

[tex]\begin{aligned}\displaystyle \int^{13}_1 \sqrt[7]{x}\; \text{d}x&=\lim_{n \to \infty}\sum^n_{i=1}\sqrt[7]{1+\left(\dfrac{13-1}{n}\right)i} \cdot \left(\dfrac{13-1}{n}\right)\\\\&=\lim_{n \to \infty}\sum^n_{i=1}\left(\dfrac{12}{n}\right)\sqrt[7]{1+\dfrac{12i}{n}}\\\\\end{aligned}[/tex]

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The measures of the three intercepted arcs from least to greatest are;

AC < BC < AB

We have,

We are given that

Angle ACB = 63 degrees

Arc BC is 118 degrees.

Now, from the Triangle angle sum theorem, we know that the sum of all interior angles of any triangle is always equal to 180 degrees.

Thus, the sum of the interior angles of the inscribed triangle given to us id also 180 degrees.

Now, since Angle ACB = 63 degrees

Then Arc AB = 63 * 2 = 126

Arc AC = 360 - (Arc BC + Arc AB)

We are given BC = 118 degrees

Thus;

Arc AC = 360 - (118 + 126)

Arc AC = 116°

Thus, the least arc angle is Arc AC while the greatest is Arc AB

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complete question:

Triangle ABC is inscribed in a circle centered at point O.

The figure shows triangle ABC is inscribed in a circle centered at point O and has an angle ACB is 63 degrees and arc BC is 118 degrees.

Order the measures of the three intercepted arcs from least to greatest.