The temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is 10,684.4 K.
Conservation of energyThe temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is determined by applying principle of conservation of energy as shown below;
E = K + U
E = K - GmM/R
0 = K - GmM/R
K = mgR
When the minimum escape energy is 15 times average kinetic energy;
15K = mgR
[tex]15 \times \frac{3}{2} kT = mgR[/tex]
where;
m is mass of oxygen per atom = (0.032 kg)/(6.02 x 10²³) = 5.316 x 10⁻²⁶ kg/atomg is acceleration due gravity = 9.8 m/s²R is radius of Earth = 6.371 x 10⁶ m.k is Boltzmanns’ constant = 1.38066 x 10⁻²³ J/K.[tex]T = \frac{2mgR}{15 \times 3k} \\\\T = \frac{(2)(5.316 \times 10^{-26})(9.8)(6.371 \times 10^6)}{45(1.38066 \times 10^{-23})} \\\\T = 10,684.4 \ K[/tex]
Thus, the temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is 10,684.4 K.
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Can you hear the vibrations a tuning fork puts off when hit?
no
Explanation:
no not an vibration signal
The vertebral region is _________ to the scapular region.
Answer:
The answer is medial!
Explanation:
The vertebral region is medial to the scapula.
Hope This Helps!
-Justin:)
What is current of 12 ohm? help me pleasee
Answer:
2.5A
Explanation:
We know the relation :
V = IR
V = voltage (potential difference)I = currentR = resistanceBy using the formula,
I = V/RI = 30/12I = 10/4I = 2.5AAnswer :-
Current of Device = 2.5 Ampere .Explanation :-
As per the provided information in the given question, we have been given that the Potential Difference is 30 Volt . The Resistance is given as 12 Ohm . And, we have been asked to calculate the Current of the Device.
For calculating the Current , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed { \sf{ \: Current \: = \: \dfrac{Potential \: Difference}{Resistance} \: }} [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \sf { Current \: = \: \dfrac{Potential \: Difference}{Resistance} } [/tex]
[tex] \longmapsto \: \: \: \sf { Current \: = \: \dfrac{30}{12} } [/tex]
[tex] \longmapsto \: \: \: \textbf {\textsf {Current \: = \: 2.5 }} [/tex]
Hence :-
Current = 2.5 Ampere .[tex]\underline {\rule {180pt} {4pt}} [/tex]
What is the new period if the pendulum is taken to a planet that has 4 times the mass and 4 times the radius of earth
The new period of the pendulum when it is taken to the new planet is double of its period on Earth.
Period of a pendulumThe period of a pendulum is given by the following formula;
[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]
where;
g is acceleration due to gravity of the pendulumL is length of the pendulumAcceleration due to gravity of the new planetThe acceleration due to gravity of the new planet is calculated as follows;
[tex]g_E = \frac{GM_E}{R_E^2} = 9.81 \ m/s^2 \\\\g(new \ planet) = \frac{G(4M_E)}{(4R_E)^2} = \frac{4GM_E}{16R_E^2} = \frac{GM_E}{4R_E^2} = \frac{9.81}{4} = 2.45 \ m/s^2[/tex]
New period of the pendulum[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\T =\frac{2\pi \sqrt{l} }{\sqrt{g} } \\\\T_1\sqrt{g_1} = T_2\sqrt{g_2} \\\\T_E\sqrt{g_E} = T\sqrt{g} \\\\T = \frac{T_E\sqrt{g_E}}{\sqrt{g} } \\\\T = \frac{T_E \times \sqrt{9.81} }{\sqrt{2.45} } \\\\T = 2T_E[/tex]
Thus, the new period of the pendulum when it is taken to the new planet is double of its period on Earth.
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When an object standing on the floor is tipped, the height of its center of gravity (cg) may or may not change. Classify each case as stable, unstable, or neutral
The three types of equilibrium in an object are; stable, unstable, or neutral equilibrium.
What is equilibrium?The term equilibrium refers to a situation in which all the forces acting on an object are balanced such that the object does not move. The question is incomplete as the images are missing.
There are three types of equilibrium:
Stable equilibrium: In a stable equilibrium, the object returns to rest in its original place when displlaced.Unstable equilibrium: In this type of equilibrium, the body moves further away from its original position when displaced.Neutral equilibrium: In this type of equilibrium, the object comes to rest in a new position when displaced.Learn more equilibrium of forces: https://brainly.com/question/12262457
When an object standing on the floor is tipped, the height of its center of gravity (cg) for each case as stable, unstable, or neutral may increase, decreased and remain same respectively.
What is the equilibrium state of a standing object?Equilibrium is the location of the body, in which the body be static or in motion and does not change it with respect to time.
The equilibrium of an object can be classified in the 3 following types.
Stable Equilibrium- Stable equilibrium is the condition, in which the object gains its position back after displacing it.Unstable Equilibrium-Unstable equilibrium is the condition, in which the object does not gain its position back after displacing it.Neutral Equilibrium-Natural equilibrium is the condition, in which the object displace from its position and there is no force acting on it.When an object standing on the floor is tipped, the height of its center of gravity (cg) may or may not change.
The stability of object demands in the center of gravity. Lower the value of CG, results in more stable object. For each case,
Stable-Center of gravity is increased when tipped.Unstable-Center of gravity is decreased when tipped.Natural-Center of gravity is remained at same level when tipped.Thus, when an object standing on the floor is tipped, the height of its center of gravity (cg) for each case as stable, unstable, or neutral may increase, decreased and remain same respectively.
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The term group polarization refers to the tendency for.
Polarization refers to the tendency for acquiring specific orientation by the oscillation.
What is polarization?Polarization is a property that specifies the geometrical orientation of the oscillations. In a transverse wave, the direction of the oscillation is perpendicular as compared to other that have parallel.
So we can conclude that Polarization refers to the tendency for acquiring specific orientation by the oscillation.
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What do tripped circuit breakers and blown fuses indicate.
Answer:
When a circuit breaker regularly trips or a fuse repeatedly blows, it is a sign that you are making excessive demands on the circuit and need to move some appliances and devices to other circuits. Or, it may indicate that your house has too few circuits and is in need of a service upgrade.
2 eggs cook in a frying pan, which is sitting over a gas burner. Is thermal energy being transferred from the metal pan to the eggs by radiation in this image? Why or why not?
Answer:
No, the eggs are in direct contact with the metal pan, which is in direct contact with the gas flame, so this is conduction, not radiation
Reasons:
-Thermal energy is being transferred by conduction.
-Radiation transfers thermal energy by electromagnetic waves.
-Radiation does not transfer thermal energy by direct contact.
Radiation heat transfer is a process where heatwaves are emitted that may be absorbed, reflected, or transmitted through a colder "body". Sun heats the earth by electromagnetic waves. The sun does not come in physical contact with the Earth to transfer heat. (In my opinion, the Earth touching the sun would not be on my to-do list.)
Explanation:
Have a great rest of your day
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Which of the following was correctly predicted by Einstein's theory of gravity?
(A) the origin of mass
(B) law of refraction
(C) the measure of G
(D) light deflected around large objects because of their gravity
Answer:
(D) light deflected around large objects because of their gravity
I hope this helps you
:)
A 80kg astronaut is training in human centrifuge to prepare for a launch. The astronaut uses the centrifuge to practice having a 3.16g force (3.16 times his own weight) on his back. The radius is 12m.
Attached is a picture of the question.
The answers on the model of the human centrifuge ready for the launch to each question of the statement are listed below:
a) A force of 2479.210 newtons is acting on the astronaut's back.
b) A net centripetal force of 2479.210 newtons is acting on the astronaut.
c) The centripetal acceleration of the astronaut is 30.990 meters per square second.
d) The astronaut has a linear speed of approximately 19.284 meters per second.
e) The angular speed of the astronaut is 1.607 radians per second (15.346 revolutions per minute).
How to apply Newton's laws to analyze a process in a human centrifuge trainingThe human centrifuge experiments a centripetal acceleration when it reaches a peak angular speed. In this question we must apply Newton's laws of motion and concepts of centripete and centrifugal forces to answer the questions. Now we proceed to answer the questions:
How much force is acting on the astronaut's back?By the third Newton's law the astronaut experiments a rection force (F), in newtons, which has the same magnitude to centrifugal force but opposed to that force. The magnitude of the force acting on the back of the astronaut is equal to:
[tex]F = 3.16\cdot (80\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 2479.210\,N[/tex]
A force of 2479.210 newtons is acting on the astronaut's back. [tex]\blacksquare[/tex]
What is the net centripetal force on the astronaut?By the second and third Newton's laws we know that the net centripetal force on the astronaut is equal to the magnitude of the force found in the previous question. Thus, a net centripetal force of 2479.210 newtons is acting on the astronaut. [tex]\blacksquare[/tex]
What is the astronaut's centripetal acceleration?The centripetal acceleration of the astronaut (a), in meters per square second, is found by dividing the result of the previous question by the mass of the astronaut (m), in kilograms:
[tex]a = \frac{F}{m}[/tex] (1)
If we know that F = 2479.210 newtons and m = 80 kilograms, then the centripetal acceleration of the astronaut is:
[tex]a = \frac{2479.210\,N}{80\,kg}[/tex]
[tex]a = 30.990\,\frac{m}{s^{2}}[/tex]
The centripetal acceleration of the astronaut is 30.990 meters per square second. [tex]\blacksquare[/tex]
What is the astronaut's linear speed?By definition of uniform circular motion, we have the following formula for the linear velocity of the astronaut (v):
[tex]v = \sqrt{a\cdot r}[/tex] (1)
Where r is the radius of the human centrifuge, in meters.
If we know that [tex]a = 30.990\,\frac{m}{s^{2}}[/tex] and [tex]r = 12\,m[/tex], then linear velocity of the astronaut is:
[tex]v = \sqrt{\left(30.990\,\frac{m}{s^{2}} \right)\cdot (12\,m)}[/tex]
v ≈ 19.284 m/s
The astronaut has a linear speed of approximately 19.284 meters per second. [tex]\blacksquare[/tex]
What is the astronaut's angular speed?The angular speed of the astronaut (ω), in radians per second, is found by the following kinematic relationship:
[tex]\omega = \frac{v}{R}[/tex] (1)
If we know that v ≈ 19.284 m/s and R = 12 m, then the angular speed is:
[tex]\omega = \frac{19.284\,\frac{m}{s} }{12\,m}[/tex]
ω = 1.607 rad/s (15.346 rev/m)
The angular speed of the astronaut is 1.607 radians per second (15.346 revolutions per minute). [tex]\blacksquare[/tex]
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How does a white dwarf compare to our sun as it exists now?.
Answer:
answer down below
Explanation:
it has similar mass but the white dwarf is much denser
Hello people ~
Sound cannot travel through
(a) air
(b) water
(c) air
(d) vacuum
Answer:
Vaccum
Explanation:
Sound travels through the particles of different matter In vaccum there is no air so no matter and so no particles .So sound can't travel through vaccum.You can test it .
Take a speaker and keep it inside a bottle ,close it .You won't hear any soundA round tube weighs 30 lbs. If the tube is stood on end it pushes down on the floor with a pressure of
2 lbs/in?. How many square inches is the end of the tube?
Answer:
15in2
Explanation:
The diagram shows part of a radio antenna.The plastic tube protects the radio antenna from bad weather.Dust particles carried by the wind rub against the plastic tube.After some time, the dust particles cause the tube to become positively charged.State the property of plastic that allows it to become electrostatically charged.
Have a good day!! :>
When using a different calorimeter, and mixing 50 ml of hot water at 65 degrees c with 60 ml of water in the calorimete
The specific heat capacity of the calorimeter used in mixing the water is determined as 21.87 J/g⁰C.
Conseervation of energyThe heat capacity of the calirometer is determined by applying the principle of conservation of energy.
Heat lost by the hot water = Heat gained by the calirometer
[tex]Q _w = Q_c\\\\M_w C_w\Delta \theta _w = M_c C_c\Delta \theta _c[/tex]
where;
M is massmass = density x volume = ρV
Density of water = 1 g/ml
Mass of hot water = 1 x (50) = 50 g
Mass of water in calorimeter = 1 x (60) = 60 g
Equilibrium temperature[tex]\Delta T_c = 5.5\\\\T - 25 = 5.5\\\\T = 30.5 \ ^0C[/tex]
Specific heat capacity of the calirometer[tex]50 \times 4.184 \times (65 - 30.5) = 60 \times C_c \times (30.5 - 25)\\\\7217.4 = 330C_c\\\\C_c = \frac{7217.4}{330} \\\\C_c = 21.87 \ J/g^0C[/tex]
Thus, the specific heat capacity of the calorimeter used in mixing the water is determined as 21.87 J/g⁰C.
The complete question is below
When using a different calorimeter, and mixing 50 ml of hot water at
65 degrees C with 60 ml of water in the calorimeter at 25 degrees C, the temperature of the calorimeter increased by 5.5 degrees C.
a. Calculate the heat capacity of this calorimeter?
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1. A 30-kg child is spinning horizontally in a ride with a
centripetal acceleration of 10 m/s/s. How many newtons
of centripetal force are acting on her?
Answer:
300newtons of centripetal force
Explanation:
Force is mathematically expressed as mass×acceleration due to gravity
Mass of child equals 30kg
Acceleration due to gravity equals 10m/s²
Force is unknown so we restate formula & fix in the quantities
∴Force equals mass×acceleration due to gravity
(representing force by f,mass by m & acceleration...gravity by g)not always necessary
So f equals m×g(fix in values)
f equals 30kg×10m/s²
f equals 300newtons
∴The centripetal force acting on her is 300newtons
angular velocity of a rotating wheel increases 2 rev/s every minute. The angular acceleration of this wheel is:
The angular acceleration of the rotating wheel at the given rate of change of angular velocity is 0.21 rad/s².
Angular acceleration of the wheel
The angular acceleration of an object is the rate of change of anguar velocity of the object with time.
[tex]\alpha = \frac{\Delta \omega }{\Delta t}[/tex]
where;
Δω is the change in the angular velocityΔt is the change in timeChange in angular velocity of the wheel is calculated as follows;
[tex]\Delta \omega = 2 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} = 4\pi \ rad/s = 12.57 \ rad/s[/tex]
Change in time, Δt = 1 min = 60 s
The angular acceleration of the rotating wheel is calculated as follows;
α = (12.57) / (60)
α = 0.21 rad/s²
Thus, the angular acceleration of the rotating wheel at the given rate of change of angular velocity is 0.21 rad/s².
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Use F = 1/T as your basis:
7. What is the period of 60.0Hz electrical power?
The answer is 16.7 ms but please show your work.
[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{T}[/tex]
[tex]\\ \rm\rightarrowtail T=\dfrac{1}{\nu}[/tex]
[tex]\\ \rm\rightarrowtail T=\dfrac{1}{60}[/tex]
[tex]\\ \rm\rightarrowtail T=1.67\times 10^{-4}s[/tex]
[tex]\\ \rm\rightarrowtail T=16.7\times 10^{-3}s[/tex]
[tex]\\ \rm\rightarrowtail T=16.7ms[/tex]
The free-body diagram below represents all the forces acting on an object. What is the net force acting on this object?
300 N right
100 N down
0 N up
200 N right
Answer:
200 N Right
Explanation:
The 50 up and 50 down balance or 'cancel' each other
then you only have the 200 N to the right
What does the text mean when it says “naming an elements is like creating history
Answer: When you name an element, it's usually because the element is newly discovered. So by naming an element you are creating something that will last throughout history.
Explanation:
What is the 3rd largest planet in the solar system?
Answer:
Uranus
Explanation:
Your welcome
A planet is a celestial body. The third-largest planet in the solar system is Uranus.
What is a planet?A celestial body is differentiated from the fixed stars by its apparent mobility (including the moon and sun), especially in relation to its claimed impact on people and events.
A planet is a celestial body. The third-largest planet in the solar system is Uranus.
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(please answer) It is better to jump on a smooth, flat surface than on thick carpeting.
Question 5 options:
True
False
I believe the answer to your question would be True
What is current of 12 ohm? help me pleasee
Answer:
the current of 12 ohm is 2Amps
Why doesn't mercury have an atmosphere?
Answer:
The main reasons are two. Mercury's atmosphere is hard to hold onto because it is small and does not have much gravity. As Mercury is close to the Sun, any atmosphere is blasted away by material being blown off the Sun.
Hope this helps friend!
Who developed the principle of whenever 2 objects come into contact with one another, materials are exchanged between them?.
Answer:
Edmond Locard
Explanation:
Hope this helps :)
16. By how much leeway (both percentage and mass) would you have in the selection of the mass of the object in the previous problem if you did not wish the new period to be greater than 2.01 s or less than 1.99 s?
Please show all of your work.
Here is the solution for previous question
[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{m}{k}}[/tex]
[tex]\\ \rm\rightarrowtail T\propto \sqrt{m}[/tex]
Hence
[tex]\\ \rm\rightarrowtail \dfrac{T_1}{T_2}=\sqrt{\dfrac{m1}{m2}}[/tex]
[tex]\\ \rm\rightarrowtail \dfrac{1.5}{2}=\sqrt{\dfrac{0.5}{m2}}[/tex]
[tex]\\ \rm\rightarrowtail 0.75^2=\dfrac{0.5}{m2}[/tex]
[tex]\\ \rm\rightarrowtail m_2=\dfrac{0.5}{0.75^2}[/tex]
[tex]\\ \rm\rightarrowtail m_2=0.888888888\dots[/tex]
So
from this
So it's infinite in terms of 8 so must be greter than one 8
We rounded it up for 3 decimals
0.889kgSo
Error range=[1.99,2.01]
∆Error=2.01-1.99=0.02Very mere one
Now find percentage
[tex]\\ \rm\rightarrowtail \dfrac{0.02}{2}(100)=0.01(100)=1\%[/tex]
Mass should be lied in
0.01(0.889)=0.00889 kgBut for increase mass
it would be
0.00889-0.00500=0.00389kgeasy one here pls help thanks so much
A man pushes a 8 kg object. A distance of 5. 0 m upward along a frictionless slope that makes an angle of 30° with the horizontal. His force is parallel to the slope. If the speed of the object decreases at a rate of 1. 5 m/s, then the work done by the man is:
Answer:
is 200 J
Explanation:
hope this is the right answer
The earliest stage of a star’s life before it begins to undergo fusion is known as:
Answer:
A protostar is the earliest stage of a star's life. A star is born when the gas and dust from a nebula become so hot that nuclear fusion starts.
The origin of star is called nebula. The earliest stage of a star’s life before it begins to undergo fusion is known as a protostar.
What is the earlier stage of star ?Every star begins from nebula. A nebula is a huge gas and dust cloud. Some of the gas and dust in a nebula can be drawn together by gravity. The cloud's contraction is then described as a protostar. The first stage of a star's life is called a protostar.
As the gas and dust from a nebula heat up to a point where nuclear fusion begins, a star is created. A star is referred to as a main sequence star once it has "switched on". A main sequence star turns into a red giant or a red super giant when its hydrogen fuel runs exhausted.
An exploding red super massive star is possible. It is referred to be a supernova. After the star explodes, some of the ingredients from the star are left behind. Hence, the earlier stage of a star before fusion starts is called a protostar.
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A garbage can of mass 12 kg standing on horizontal ground is pushed by a horizontal force of 40N. If the coefficient of static friction is 0. 32 and the coefficient of dynamic or
kinetic friction is 0. 24 between the can and ground, the acceleration of the garbage can is
____ m/s2
The acceleration of the garbage can is 2.55 m/s².
What is acceleration?Acceleration is the rate of change of velocity with respect to time.
To calculate the acceleration of the can, we use the formula below
Formula:
ma = F-mg(η-μ)............ Equation 1Where:
F = Horizontal forcem = mass of the cang = acceleration due to gravitya = acceleration of the canμ = Coefficient of static frictionη = Coefficient of kinetic frictionMake a the subject of the equation
a = [F-mg(η-μ)]/m.................. Equation 2From the question,
Given:
F = 40 Nm = 12 kgg = 9.8 m/s²μ = 0.32η = 0.24Substitute these values into equation 2
a = [40-12×9.8(0.32-0.24)]/12a = (40-9.408)/12a = 30.592/12a = 2.55 m/s²Hence, the acceleration of the garbage can is 2.55 m/s².
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how do the properties of waves correspond with observations of waves?
Answer:
no sabo por q no mi entender