Answer:
3.39 x 10²³ particles
6.02 x 10²²particles
Explanation:
The problem here entails we find the number of particles in the given substances.
From the mole concept;
1 mole of a substance contains 6.02 x 10²³ particles
a. 18g of O₂;
We first find the number of moles of this substance first;
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of O₂ = 2(16) = 32g/mol
Number of moles = [tex]\frac{18}{32}[/tex] = 0.56mole
So;
1 mole of a substance contains 6.02 x 10²³ particles
0.56 mole of O₂ will contain 0.56 x 6.02 x 10²³ particles
= 3.39 x 10²³ particles
b. 0.1mole of calcium atom:
1 mole of a substance contains 6.02 x 10²³ particles
0.1 mole of the substance will contain 0.1 x 6.02 x 10²³ particles
= 6.02 x 10²²particles
How many moles are 21.67 L of NH4CI?
Type your answer...
Answer:
0.967mole
Explanation:
Given parameters:
Volume of NH₄Cl = 21.67L
Unknown:
Number of moles = ?
Solution:
We assume that the volume was taken at standard temperature and pressure,
Then;
Number of moles = [tex]\frac{volume }{22.4L}[/tex]
Number of moles = [tex]\frac{21.67}{22.4}[/tex] = 0.967mole
How many grams of KClO3 will dissolve in 300g of water at 50°C?
Answer:
50 g
Explanation:
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