The question requires us to calculate the number of moles of each element (magnesium, chlorine and oxygen) in 8.30 moles of the compound magnesium perchlorate (Mg(ClO4)2).
From the molecular formula of magnesium perchlorate we can take the following information:
- in 1 mol of Mg(ClO4)2, there is only 1 mol of Mg;
- in 1 mol of Mg(ClO4)2, there are 2 moles of Cl;
- in 1 mol of Mg(ClO4)2, there are 8 moles of O.
With the information above, and knowing that the amount of Mg(ClO4)2 given by the question was 8.30 moles, we can calculate the amount, in moles, of each element:
1 mol Mg(ClO4)2 --------------- 1 mol Mg
8.30 mol Mg(ClO4)2 ---------- x = 8.30 mol Mg
1 mol Mg(ClO4)2 --------------- 2 mol Cl
8.30 mol Mg(ClO4)2 ---------- y = 2 x 8.30 mol Cl = 16.6 mol Cl
1 mol Mg(ClO4)2 --------------- 8 mol O
8.30 mol Mg(ClO4)2 ---------- z = 8 x 8.30 mol O = 66.4 mol O
Therefore, there are 8.30, 16.6 and 66.4 moles of Mg, Cl and O in 8.30 moles of magnesium perssufate.
Definition: This is a type of element or substance that is not a metal.Example: oxygen, nitrogen, hydrogen
This elements or substances that are not a metal are called non-metals.
I think that the answer is Non-metal
Why is CuSO4 the correct formula for copper (ii) sulfate and not CuSO3?
The correct formula of copper (II) sulfate is CuSO₄ because Copper ion (Cu²⁺) has +2 charge and sulfate ion SO₄²⁻ has -2 charge, while CuSO₃ is copper(II) sulfite.
What is copper sulfate?The CuSO₄ molecule contains an ionic bond between the copper cation (Cu²⁺) and the sulfate anion (SO₄²⁻).
The copper sulfate in its pentahydrate form is given by the chemical formula CuSO₄.5H₂O. This form of copper sulfate is characterized by its bright blue color but the anhydrous form of this salt is a white powder.
The oxidation state of the copper atom in a CuSO₄ molecule is +2. The molar mass of the pentahydrate and anhydrous forms of copper sulfate are 249.685 grams/mole and 159.609 grams/mole respectively.
Anhydrous CuSO₄ has a powdery appearance and a grey-white, while the pentahydrate has a bright blue color.
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A lawyer is presenting a hair sample with its corresponding nuclear DNA that was found at the crime scene. How will this MOST likely affect the criminal case?
A.
The evidence will have a low probability of providing accurate matching results.
B.
The evidence will need to be looked at under a microscope to be admitted.
C.
The evidence will not be admissible in a court case.
D.
The evidence will provide a nearly exact match to the suspect’s hair.
A sample will likely affect a criminal case because this evidence will provide a nearly exact match to the suspect’s hair (Option D).
What is DNA testing?DNA testing refers to the techniques used to obtain DNA from samples that can be used to identify an individual in a police case. A sample of hair may be used for DNA testing because it contains cells and therefore also contains DNA.
Therefore, with this data, we can see that DNA testing allow us to identify individuals for which we need to obtain a sample with cells.
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Part II Dilution Problems: 17. 350.0 mL of water was added to a 2.3 L solution of NaCl. If the final concentration of the solution was 0.967 M, what was the original concentration of the solution?
ANSWER
The original concentration of the solution is 0.147 mol
EXPLANATION
Given that;
The volume of water is 350.0mL
The volume of NaCl solution is 2.3L
The final concentration of the solution is 0.967M
To find the original concentration of the solution, follow the steps below
Step1: Write the dilution formula
[tex]\text{ M1V1}=M2V2[/tex]Where
• M1 is the original concentration of the solution
,• V1 is the original volume of the of the solution
,• M2 is the final concentration of the solution
,• V2 is the final volume of the solution
Step 2: Convert the volume of water to L
Recall, that 1mL is equivalent to 0.001L
[tex]\begin{gathered} \text{ The volume can be converted below as} \\ \text{ 1mL }\rightarrow\text{ 0.001L} \\ \text{ 350mL }\rightarrow\text{ vL} \\ \text{ Cross multiply} \\ \text{ vL}\times\text{ 1mL }=\text{ 350mL}\times0.001L \\ \text{ Isolate v} \\ \text{ v }=\text{ }\frac{350\cancel{mL}\times\text{ 0.001L}}{1\cancel{mL}} \\ \text{ v }=\text{ 350}\times\text{ 0.001} \\ \text{ v }=\text{ 0.35L} \end{gathered}[/tex]Step 3; Find the original concentration of the solution by substituting by the given data into the formula in step 1
[tex]\begin{gathered} \text{ M1}\times2.3\text{ }=\text{ 0.35}\times\text{ 0.967} \\ \text{ 2.3M1 }=\text{ 0.33845} \\ \text{ Divide both sides by 2.3} \\ \text{ }\frac{2.3M1}{2.3}\text{ }=\text{ }\frac{0.33845}{2.3} \\ \text{ M1}=\text{ 0.147 mol} \end{gathered}[/tex]Hence, the original concentration of the solution is 0.147 mol
The total number of calcium atoms in the expression 3 cal 2 shown in the equation 3CaCl 2 +2Na 3 PO 4 Ca(PO 4 ) 2 +6 NaCl is:
Let's write the balanced chemical equation:
[tex]3CaCl_2+2Na_3PO_4\to Ca_3(PO_4)_2+6NaCl.[/tex]You can see that in the reactants and in the products we have the same number of atoms for each element. This is due to the matter of conservation law.
The total number of calcium atoms that are reacting and produced in the reaction is 3.
Balance the equation: __MgCl2 + __Cr2O3 --> __MgO + __CrCl3
We start by counting the number of atoms of each element on each side of the reaction.
Now we balance the reaction by trial and error, starting with chlorine. We have 2 chlorine atoms in the reactants and 3 clear atoms in the products, so to balance we cross the coefficients placing 3 on the reactant side and two on the product side in the respective molecules:
[tex]3Mg_{}Cl_2+Cr_2O_3\rightarrow MgO+2CrCl_3[/tex]Now we continue with the oxygens, we have 3 oxygens on the reactant side and 1 on the products, so we put the coefficient 3 on the products side in front of the respective molecule:
[tex]3Mg_{}Cl_2+Cr_2O_3\rightarrow3MgO+2CrCl_3[/tex]We now have the balanced equation. We have 3 Mg atoms, 6 Cl atoms, 2 Cr atoms, and 3 O atoms on each side of the reaction.
7. A given sample of gas is held in a container with the volume of 6.02 L with a temperature of 59.5℃ at a pressure of 1.20 atm. What is the final pressure when the sample of gas is administered to a new volume of 10.0 L at 20.2℃?
The final pressure of the sample gas based on the new volume and temperature would be 0.245 atm.
Combined gas lawThe combined gas law is expressed as:
[tex]\frac{p_1v_1}{t_1}[/tex] = [tex]\frac{p_2v_2}{t_2}[/tex]
Where
[tex]p_1[/tex]= initial pressure[tex]v_1[/tex]= initial volume[tex]t_1[/tex]= initial temperature[tex]p_2[/tex]= final pressure[tex]v_2[/tex]= final volume[tex]t_2[/tex]= final temperatureIn this case, we were given all the variables except the final pressure, [tex]p_2[/tex]:
[tex]p_1[/tex]= 1.20 atm[tex]v_1[/tex]= 6.02 L[tex]t_1[/tex]= 59.5℃[tex]v_2[/tex]= 10.0 L[tex]t_2[/tex]= 20.2℃Making p2 the subject of the formula in the combined gas equation, we have:
[tex]p_2[/tex]= [tex]p_1v_1t_2/t_1v_2[/tex]
Next, let's substitute the given variables:
[tex]p_2[/tex]= 1.2 x 6.02 x 20.2/59.5 x 10.0
= 145.9248/595
= 0.245 atm
In other words, the final pressure when the sample of gas is administered to a new volume of 10.0 L at 20.2℃ is 0.245 atm'
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In the reaction, 2NaOH + H2SO4 —> Na2SO4 + H2O, 40.0 g NaOH reacts with 60.0 g H2SO4. Which is the limiting reactant
Step 1
The reaction must be written, completed, and balanced:
2 NaOH + H2SO4 => Na2SO4 + H2O
-----------
Step 2
Information provided:
Mass of NaOH = 40.0 g
Mass of H2SO4 = 60.0 g
--
Information needed:
The molar masses:
NaOH) 40.0 g/mol approx.
H2SO4) 98.0 g/mol approx.
-----------
Step 3
The limiting reactant?
By stoichiometry:
1 mole NaOH = 40.0 g
1 mole H2SO4 = 98.0 g
2 NaOH + H2SO4 => Na2SO4 + H2O
2 x 40.0 g NaOH ----------- 98.0 g H2SO4
40.0 g NaOH ----------- X
X = 40.0 g NaOH x 98.0 g H2SO4/2 x 40.0 g NaOH = 49.0 g H2SO4
For 40.0 g of NaOH, 49.0 g of H2SO4 is needed but is provided 60.0 g of H2SO4. Therefore, the excess is the H2SO4, and the limiting reactant is the NaOH.
Answer: the limiting reactant is NaOH
Chemistry Electromagnetic Radiation HW Help. Pls real answers
The frequency of the green light from a traffic signal is 5.76 * 10¹⁴ Hz
The frequency of the light is 1.85 * 10¹⁶ Hz
The frequency of the light is 4.84 * 10¹⁴ Hz
The energy of the photons is 1.172 * 10⁻³ J
The energy of the photons is 4.34 * 10⁻² J
What is the frequency of light wave given the wavelength?The frequency of light can be found given the wavelength from the formula below:
frequency = velocity / wavelength8. The frequency of the green light from a traffic signal is calculated below:
velocity of light = 3.0 * 10⁸ m/s
wavelength = 5.2 x 10⁻⁷ m
Frequency = 3.0 * 10⁸ / 5.2 x 10⁻⁷
frequency = 5.76 * 10¹⁴ Hz
9. The frequency of the light is calculated below:
velocity of light = 3.0 * 10⁸ m/s
wavelength = 16.23 x 10⁻⁹ m
Frequency = 3.0 * 10⁸ / 16.23 x 10⁻⁹
frequency = 1.85 * 10¹⁶ Hz
10. The frequency of the light is calculated below:
velocity of light = 3.0 * 10⁸ m/s
wavelength = 6.2 x 10⁻⁷ m
Frequency = 3.0 * 10⁸ / 6.2 x 10⁻⁷
frequency = 4.84 * 10¹⁴ Hz
11. The energy of one of the photons will be calculated as follows:
E = hf
E = hc/λ
Energy of the photons = 2.3 x 10¹¹ x hc/λ
h = 6.626 * 10⁻³⁴Js
λ = 3.9 x 10⁻¹² m
c = 3.0 * 10⁸ m/s
E = 2.3 x 10¹¹ x 6.626 * 10⁻³⁴ * 3.0 * 10⁸ / 3.9 x 10⁻¹²
E = 1.172 * 10⁻³ J
12. The energy of one of the photons will be calculated as follows:
E = hf
E = hc/λ
Energy of the photons = 9.4 x 10¹⁶ x hc/λ
h = 6.626 * 10⁻³⁴Js
λ = 4.3 x 10⁻⁷ m
c = 3.0 * 10⁸ m/s
E = 9.4 x 10¹⁶ x 6.626 * 10⁻³⁴ * 3.0 * 10⁸ / 4.3 x 10⁻⁷
E = 4.34 * 10⁻² J
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Which temperature is unattainable?
a)_1k
b)_1°C
c)_1°F
d)All of these
Answer:
A is the correct answer.
Explanation:
It is possible to reach 1°C and 1°F because they are both units of temperature. But 1k is not a unit of temperature.
Monica works in a crime lab. Her supervisor tells her that she needs to better understand Locard’s Exchange Principle. How will she MOST accurately demonstrate her understanding of this concept?
A.
She will always test for the presence of blood at crime scenes.
B.
She will use both fingerprints and bullet matching to solve crimes.
C.
She will keep evidence separated so it doesn’t get contaminated.
D.
She will exchange information openly with other crime investigators.
She will keep evidence separated so it doesn’t get contaminated demonstrates the understanding of Locard’s Exchange Principle and is denoted as option C.
What is Locard’s Exchange Principle?This principle states that an individual who commits a crime will bring something into the crime scene and leave with something from it. This also explains that they can be used as evidence during investigation by the appropriate authorities.
Since we are aware that new substances are always brought into and carried away from the crime scene then it is best to keep the evidence separated so it doesn’t get contaminated.
This ensures that the results gotten from the analysis and investigation are accurate and is therefore the reason why option C was chosen as the correct choice.
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Write formulas or names as appropriate for each of the following hydrates. 1. Magnesium sulfate heptahydrate 6. CoSO4•H2O 2. Copper(I) sulfate pentahydrate 7. Na2CrO4•4H2O 3. Potassium phosphate decahydrate 8. CuF2•2H2O 4. Calcium chloride hexahydrate 9. Sr(NO3)2•6H2O 5. Iron(III) nitrate nonahydrate 10. ZnSO4•7H2O
Answer:
Explanation:
Here, we want to give the names or formulas of the given hydrates
1) Magnesium sulfate heptahydrate
The first thing we have to do here is write the formula for magnesium sulfate.
Hepta means 7, which is pointing to the fact that there are 7 water molecules
We can have this as:
[tex]\text{MgSO}_4\cdot7H_2O[/tex]6) Here, we can see that the element involved is cobalt with an oxideation number of 2. We also have just one water of crystallization
So, we have the name of the compound as:
[tex]\text{Cobalt (II) Sulphate hydrate}[/tex]Co-60 is used medically for radiation therapy as implants and as an external source of radiation exposure. The half-life of
Co-60 is 5, 272 years. How much of a 2.000 mg sample will remain after 21, 088 years? You must show your work to receive
credit.
. Show the equation needed
b. Show a picture of you solving for the unknown.
c. Show the final answer
Co-60 is used medically for radiation therapy as implants and as an external source of radiation exposure the half-life of Co-60 is 5, 272 years 2.000 mg sample will remain after 21, 088 years is 0.0625 gm left
Radiation therapy is the cancer treatment that uses high doses of radiation to kill cancer cell and shrink tumor
Here given data is Co-60 is 5, 272 years and we have to find the number of half lives in 21, 088 years = ?
21, 088/5, 272 = 4 half lives
(1/2)⁵ = 1/32 nd of the original will be left
1/32×2.000mg = 0.0625 gm left
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What is the maximum number of electrons that can occupy the n = 2 shell?
Explanation:
If n = 2 we have this posibility:
This shell contains 2 subshells: s and p
Subshell 2s can only contain 2 electrons
Subshell 2p can only contain 6 electrons
Answer: In total, we can have 8 electrons in n = 2
1. 60.0 mL of 0.322 M lithium chloride, LICI (aq) are combined with 20.0 mL of 0.530 M Tin (II) nitrate,
Sn(NO₂)2 (aq), 0.632 g of precipitate are recovered.
a. Write a balanced chemical equation for the reaction.
b. Write a balanced net-ionic equation for the reaction.
c. Calculate the moles of precipitate that are actually produced in the reaction.
d. Calculate the moles of precipitate that should be produced if the reaction went to completion.
e. Calculate the percent yield of the reaction.
Answer:
60.0 mL of 0.322 M potassium iodide are combined with 20.0 mL of 0.530 M lead (II) nitrate.
How many grams of lead (II) iodide will precipitate? (you must write your own reaction)
Explanation:
What is the mass of 9.50 moles of magnesium chloride, MgCl2 ?'
Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will form, enter its empirical formula in the last column.
1) A precipitate called [tex]Fe(OH)_{2}[/tex]
2) A precipitate is formed called [tex]Mg(CH_{3} COO)_{2}[/tex]
What is a precipitate?The term precipitate is used to describe the product that is formed when there is a reaction between two aqueous phase reactants that leads to the formation of a solid product from the reaction as we can see from the image that is attached.
we now have to look at the reactions as we can see them in the mage that is attached. We must note that we can only say that a precipitate has been formed if the product is solid after we have mixed the aqueous phase reactants.
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A student wants to produce a 1.8 M solution and has 0.9 moles of solute available. What is the maximum volume (in mL) of solution that can be produced?Given:Find:Equation used:Answer:
Answer:
[tex]500\text{ mL}[/tex]Explanation:
Here, we want to get the maximum volume of solution that can be produced
Given:
Molarity = 1.8 M
Number of Moles = 0.9 moles
Find:
Volume
Equation Used:
Number of moles = molarity * volume
Answer:
[tex]\begin{gathered} 0.9\text{ = 1.8 }\times\text{ V} \\ V\text{ = }\frac{0.9}{1.8} \\ V=0.5dm^3 \end{gathered}[/tex]To convert this to mL, we multiply the volume by 1000 since 1 L = 1000 mL
Thus, we have it that:
[tex]0.5\text{ }\times1000\text{ = 500 mL}[/tex]A photon has a frequency of 3.16 * 10^7 Hz. Calculate its energy
If the photon has a frequency of 3.16 × 10 ⁷ Hz, then the energy of the the photon as per Planck's law would be 1.978× 10⁻²⁶ Joules
What is Wavelength?It can be understood in terms of the distance between any two similar successive points across any wave.
C = λν
As given in the problem we have to calculate the energy of the light if the frequency of light is 3.16 × 10 ⁷ Hz
The energy of the photon = h ν
= 6.26 × 10⁻³⁴ × 3.16 × 10 ⁷
= 1.978× 10⁻²⁶ Joules
Thus, If the photon has a frequency of 3.16 × 10 ⁷ Hz, then the energy of the the photon as per Planck's law would be 1.978× 10⁻²⁶ Joules.
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If a student did an experiment were they mixed 25 mL of HCl (0.5M) and 7.4g of sodium bicarbonate together How many moles of carbon dioxide would be generated at STP? Show your balanced equation aswell.
The first thing will be to finish the reaction that happens in the experiment to the reactional HCl and sodium bicarbonate (NaHCO3). The balanced reaction is the following:
[tex]NaH_{}CO_3+HCl\rightarrow NaCl+H_2O+CO_{2(g)}[/tex]Now, we must determine which is the limiting reactant. To do this we are going to convert all the data they give us to moles.
For HCl we are given the molarity, so the moles will be:
[tex]\begin{gathered} \text{Molarity}=\text{ }\frac{\text{Moles of solute}}{L\text{ of solution}} \\ \text{Moles of solute= Molarity}\times L\text{ of solution} \\ \text{Moles of solute=}0.5M\times(25mL\times\frac{1L}{1000mL}) \\ \text{Moles of solute=}0.0125\text{ mol HCl} \end{gathered}[/tex]Now the moles of sodium bicarbonate are found using its molar mass:
[tex]\begin{gathered} \text{Moles }NaHCO3=\text{Given g }NaHCO3\times\frac{1molNaHCO3}{Molar\text{ mass, g}NaHCO3} \\ \text{Moles }NaHCO3=7.4g\times\frac{1moNaHCO3}{84.007gNaHCO3} \\ \text{Moles }NaHCO3=0.0880\text{mol }NaHCO3 \end{gathered}[/tex]By stoichiometry, we have that one mole of NaHCO3 reacts with one mole of HCl. We have more moles of NaHCO3 than HCl. Therefore, HCl will be the limiting reactant.
So the reaction will occur according to the number of moles of HCl. Now the ratio between HCl and CO2 gas formed is 1 to 1. For one mole of HCl that reacts, 1 mole of CO2 will be formed.
so, the number
If39.50 ml of a vegetable juice contains 45% of the recommendeddaily allowance of vitamin C (equal to 60 mg). How many milliliters ofthe vegetable juice will provide 100% of the recommended dailyallowance?
87.77 ml will provide the recommended daily allowance of vitamin C.
- To calculate the milliliters of vegetable juice that will provide 100% of the recommended daily allowance of vitamin C, we can use a mathematical Rule of Three:
[tex]\frac{100.39.50}{45}=87.77[/tex]So, 87.77 ml will provide the recommended daily allowance of vitamin C.
How many grams of MgO are produced when 40.0 grams of O2 react completely with Mg? I picked B but I’m not sure if I’m correct
Step 1
The reaction provided:
2 Mg (s) + O2 (g) => 2 MgO (s) (completed and balanced)
-----------
Step 2
Information provided:
40.0 g of O2 which react completely
---
Information needed:
The molar masses of:
O2) 32.0 g/mol
MgO) 40.3 g/mol
-----------
Step 3
By stoichiometry,
2 Mg (s) + O2 (g) => 2 MgO (s)
32.0 g O2 ------- 2 x 40.3 g MgO
40.0 g O2 ------- X
X = 40.0 g O2 x 2 x 40.3 g MgO/32.0 g O2
X = 101 g MgO
Answer: C 101 g
7) What is the volume of the liquid in graduated cylinder A before the rockwas added?AYour answer8060BE10080★8 points
To read the measuring cylinder we first count the number of smaller divisions between the marked interval. In this case it is 10 intervals. The marked intervals are 60 and 80, therefore between these values we have 20. We will now divide the 20 by the 10 intervalswhich is equal to 2. Now each interval has a numerical value of 2. We read from the bottom of the meniscus. The meniscus is ttouching the 5th line and so we say 5 x 2=10, we add this to 60.
Answer: 60+10= 70,
Consider the reaction between sodium metal and chlorine gas to form sodium chloride (table salt):2 Na(s) + Cl2 (g) > 2 NaCI(s)If 12.5 g of sodium react with sufficient chlorine, how many grams of sodium chloride should form?1. 12.1 grams2. 1.18 x 10^2 grams3. 15.9 grams4. 3.18 x 10^1 grams5. 51.0 grams
Answer:
[tex]4\text{ : 3.18 }\times\text{ 10}^1\text{ grams}[/tex]Explanation:
Here, we want to calculate the mass of sodium chloride formed
Firstly, we need to get the number of moles of sodium that reacted
To get this, we divide the mass of sodium by its atomic mass
We have that as:
[tex]\frac{12.5}{23}\text{ = 0.5435 mole}[/tex]Now, let us get the number of moles of chlorine
From the equation of reaction, 1 mole of sodium produced 1 mole of sodium chloride
Thus, 0.5435 mole of sodium will also produce 0.5435 mole of sodium chloride
To get the mass of sodium chloride formed, we multiply the above number of moles by the molar mass of sodium chloride
The molar mass of sodium chloride is 58.44 g/mol
Thus, the mass of sodium chloride formed will be:
[tex]58.44\text{ }\times\text{ 0.5435 = 31.8 g}[/tex]**NEED USEFUL ANSWER ASAP**
How do the masses of the hottest main sequence stars compare to the masses of the coolest main sequence stars?
Answer:
the more hotter the star, the more brightly it burns
Explanation:
someone just deleted my answer ugh sorry....ill write it again
so, te main sequence is a sequence in mass (and not a sequence in time).
The most massive stars are located at the the top left (since they are the brightest and hottest/bluest). The lowest mass stars are are located at the bottom left ( since they dimmer and cooler/redder).
Following the main sequence from the top left to the bottom right is thus a sequence from high to low mass.
Of the elements calcium, Ca, beryllium, Be, barium, Ba, and strontium, Sr, arrange in order of decreasing atomic radii. Explain your answer using the terms electron and energy level.
Order these elements Ca, Be, Ba, and Sr:
If we take a look at the periodic table trends we will see that the atomic radii increases from left to right and from top to bottom.
So let's look for our elements:
Be: atomic number 4
Ba: atomic number 56
Ca: atomic number 20
Sr: atomic number 38
They are all Alkaline Earth Metals, they are in the same group.
So we said that the atomic radii increases from top to bottom. If we have to arrange them in order of decreasing atomic radii, we have to put first the largest one. The Barium is the one that is in a lower position, then Sr, then Ca and finally Be.
So the order of our problem is Ba, Sr, Ca and Be.
Which is the explanation?
As we move down in the periodic table the number of electrons increases. They all have 2 electrons in the outer shell. But let's look at the electronic configuration of two of them:
Ca:
Ba:
Determine the number of atoms of O in 7.23 moles of Ca(NO3)2.
Answer: 43.38 number of atoms
Explanation: If you look at this formula, then this one molecule contains six oxygen atoms. That means number of moles of oxygen atoms. That is six times the number of moles and of calcium nitrate, That is six, multiply 7.23, which comes out to be 43.38 moles of oxygen atom.
What is the correct name-formula pair for calcium (II) oxide?
The chemical formula of calcium (II) oxide is CaO, wherein the valency of both oxygen and calcium is two.
What is chemical formula?Chemical formula is a way of representing the number of atoms present in a compound or molecule.It is written with the help of symbols of elements. It also makes use of brackets and subscripts.
Subscripts are used to denote number of atoms of each element and brackets indicate presence of group of atoms. Chemical formula does not contain words. Chemical formula in the simplest form is called empirical formula.
It is not the same as structural formula and does not have any information regarding structure.It does not provide any information regarding structure of molecule as obtained in structural formula.
There are four types of chemical formula:
1)empirical formula
2) structural formula
3)condensed formula
4)molecular formula
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How to balance ____CaCl2 —-> ____Ca+ ____ Cl
In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient. In the reaction from the question we can properly balance by adding the following stoichiometric coefficients
For this question we have:
CaCl2 -> Ca + 2 Cl
Which of the following set of quantum numbers are NOT possible? (You can pick more than one)
a. 1, 0, 0, +1/2
b. 4, 0, 0, +1/2
c. 3, 3, -3, -1/2
d. 2, 1, 1, -1/2
e. 2, 1, 2, +1/2
The set of quantum numbers (3, 3, -3, -1/2), and (2, 1, 2, +1/2) are not possible. Therefore, options c and e are correct.
What are the quantum numbers?The set of numbers that can describe the position and energy of the electron. We have four quantum numbers principal, azimuthal, magnetic, and spin quantum numbers.
Principal quantum numbers (n) tell about the principal electron shell of the atom and the most probable distance between the electrons and the nucleus. The azimuthal quantum number (l) tells about the shape of an orbital in which an electron is present. It has values equal to l = n - 1.
The magnetic quantum number tells about the total number of orbitals in a subshell and the orientation of these orbitals. The value of m lies in between -l to +l. The value of the spin quantum number describes the direction of spin of an electron and it has only two values +½ and -½.
In option c, the principle (n) and azimuthal (l) quantum number has the same value but when n = 3 the possible values of l are 2, 1, 0. In option d, the magnetic quantum number has the value of 2 while l has 1 which is not possible because when l= 1 the values of m can be +1, 0, and -1.
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