The no. of quarters will be 4 and no. of dimes will be 6.
It is given that Total value of jar of quarters and dimes = $8.80
We have to found the no. of quarters and no. of dimes.
What is algebra ?
Algebra is the branch that deals with various symbols and the arithmetic operations such as addition , subtraction , division , etc.
As per the question ;
Total value of jar of quarters and dimes = $8.80
Also ;
Number of quarters is 8 less than twice the number of dimes.
Let's assume the number of dimes be x.
So ;
The no. of quarters = 2x - 8
and
Total value will be equal to ;
2x - 8 + x = 8.80
3x = 16.80
x = 16.80 ÷ 3
or
No. of dimes = x = 5.6 ≈ 6
And no. of quarters will be ;
= 2 × 6 - 8
= 12 - 8
= 4
Thus , the no. of quarters will be 4 and no. of dimes will be 6.
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the perimeter of a rectangle is 92. the length is (2x+3) and the width is (x+7) . find x
Answer:
x= 12
Step-by-step explanation:
The perimeter of a rectangle is the sum of the lengths of all its sides.
Formula
Perimeter of rectangle= 2(width) +2(length)
Substitute the given information into the formula:
92= 2(2x +3) +2(x +7)
Expand:
92= 4x +6 +2x +14
92= 6x +20
Subtract 20 from both sides:
6x= 92 -20
6x= 72
Divide both sides by 2:
x= 72 ÷6
x= 12
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3
- 3
19 ÷ +525
(Simplify your answer.)
Answer:
Step-by-step explanation:
Answer:
36
Step-by-step explanation:
Find the sum..
74 − (−12)
Answer:
86
Step-by-step explanation:
Adding integers:
74 − (−12)
We are subtracting a negative, which is like adding
74 + (12)
86
A school club consists of 26 male students and 11 female students. If 4 students are selected to represent the club in the student government, what is the probability 2 will be male and 2 will be female?
The probability of selecting two male students is 0.47
The probability of selecting two female students is 0.08
Given,
Number of male students in a school club = 26
Number of female students in a school club = 11
Total number of students in the club = 26 + 11 = 37
Number of students selected to represent the club in the student government = 4
We have to find the probability of selecting 2 male and 2 female students:
Then,
The probability of selecting two male students = (26 / 37) × (25 / 37) = 0.47
The probability of selecting two female students = (11 / 37) × (10 / 37) = 0.08
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please help..I am.so.confused
Answer:
67
Step-by-step explanation:
Answer:
there asking you what the veritable represent
What is the value of x in the equation 1/5x - 2/3y =30, when y = 15
Answer:
x = 200
Step-by-step explanation:
1/5x - 2/3y = 30 when y = 15
2/3 * 15 = 10
1/5x - 10 = 30
1/5x = 40
x = 200
Answer:
x = 200
Step-by-step explanation:
=> [tex]\frac{1}{5}x-\frac{2}{3}y=30[/tex]
=> Put the value of y into the equation
=> [tex]\frac{1}{5}x-\frac{2}{3}*15=30[/tex]
=> Simplify
=> [tex]\frac{1}{5}x-10=30[/tex]
=> Shift the 10 to the right side
=> [tex]\frac{1}{5}x=40[/tex]
=> Solve For x
=> [tex]x = 200[/tex]
- If The Answer Helped You Please Mark As Brainliest
1,402 x 71 is 71 less than 1,402x 71) -40 yes or no
No , 1,402 x 71 is 71 is not less than (1,402x 71) -40 .
An arithmetic} expression in mathematics is AN expression that is formed from variables and constants, in conjunction with pure mathematics operations (addition, subtraction, etc.). Expressions area unit created from terms.We have given two numbers 1,402 x 71 and (1,402x 71) -40.
As we can see that in second expression we have subtracted 40 from 1,402 x 71 .So , It is obvious that value of second expression will differ by first expression by 40 .
Hence , 1,402 x 71 is 40 more than (1,402x 71) -40 .
So , it is not possible to have 1,402 x 71 is 71 less than (1,402x 71) -40
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In the adjoining figure, AB//CD. Show that, AC//BD.
Learn
for
A
70°
C
50%
B
60%D
T
As shown in the next figure, AB/CD results in AC/BD.
The definition of alternating interior angleWhen a transversal connects two coplanar lines, alternate interior angles are created. They are located on the transverse sides of the parallel lines, but on the inner side of the parallel lines.
based on the given value;
we are aware of this;
The adjacent figure displays
AB//CD.
∠BCD=∠ABC=50
(By alternating interior angle are equal)
∠ACB=70
∠ACD=∠BCD+∠ACB
=50+70
=120
∠CDB=60
∠ACD+∠CDB=180
Hence; AC//BD
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Work out the missing number in this sum:
6.802 6 + 0.8+___
Answer: The answer might be 0.002
Step-by-step explanation: Looking at the number made it look like it.
and pls brainliest if I am right
{x|-1
Enter the solution in interval notation
PLEASE SHOW YOUR WORK!!!!!!
Craig’s job pays him $18.75 per hour, plus overtime at
the usual rate. Last month, Craig worked the following
hours per week:
• Week 1 = 37 hours
• Week 2 = 47 hours
• Week 3 = 42 hours
• Week 4 = 39 hours
The monthly payment to Craig is $ 3093.75
Given,
The payment got by Craig for his job = $ 18.75 per hour
Weekly working hours of Claig:
Week 1 = 37 hours
Week 2 = 47 hours
Week 3 = 42 hours
Week 4 = 39 hours
We have to find the total monthly payment of Craig:
That is,
Week 1 + Week 2 + Week 3 + Week 4
For getting the weekly salary, we have to multiply hourly payment with hours worked:
So,
Week 1 = 37 × 18.75 = 693.75
Week 2 = 47 × 18.75 = 881.25
Week 3 = 42 × 18.75 = 787.5
Week 4 = 39 × 18.75 = 731.25
Now calculate the total monthly payment:
That is,
693.75 + 881.25 + 787.5 + 731.25 = 3093.75
Therefore,
The monthly payment to Craig is $ 3093.75
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A zoologist needs to dive into the shark exhibit to supervise its cleaning. The depth of the water in the exhibit is 40 feet, and the divers can safely descend at a rate of 2 feet per minute. Which number expresses how deep below the water the divers are after 15 minutes? − 30 feet − 15 feet − 40 feet − 2 feet
Answer:
30 feet
Step-by-step explanation:
1 minute = 2 feet
15 minute = ? Feet
15 x 2 = 30
? = 30 feet
Caitlin started with 18 stuffed animals and gave away x stuffed animals. Allie started with 30 stuffed animals and gave away three times as many stuffed animals as Caitlin did. How many stuffed animals did Caitlin give away, given they had the same number of stuffed animals left?
1. 2 stuff animals
2. 6 stuff animals
3. 12 stuff animals
4. 16 stuff animals
Answer: 6 stuff animals
Step-by-step explanation: Caitlin give away 6 and Allie give away 6 x 3 = 18 and she had 12 left so that leaves both of them with 12
Hope that helped!
Public school per-student expenditures increased approximately linearly from $4.6 thousand in 1990 to $10.8 thousand in 2013. Predict the per-student expenditure in 2024.
In 2024 public school per-student expenditures will be about $thousand.
(Round the final answer to two decimal places as needed. Round all intermediate values to two decimal places as needed.
per-student expenditures will be about $ 9.16.
Public school per-student expenditures in 1990 is $4.60
per-student expenditures in 2013 is $10.8
in 23 years per student expenditure has increase of 10.8-4.60 = $6.2
in 1 years per student expenditure has increase of $6.2/23.
in 34 years per student expenditure has increase of ($6.2/23)34 =$9.16
per-student expenditures will be about $ 9.16.
the act of spending (as money, time, or power) 2 : something this is spent hold a file of your costs. expenditure.
What are examples of costs?
Expenditure – this is the whole purchase fee of a great or service. for instance, a agency buys a $10 million piece of device that it estimates to have a useful life of five years. this will be labeled as a $10 million capital expenditure.
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In a class of 99 students, one student is 1% of the class (when rounded to the nearest whole percent) and, 99 of the students represent 100%. What positive integer between 1 and 100 cannot be represented as a whole percent?
The positive integer between 1 and 100 that cannot be represented as a whole percent are 8, 15, 36 and many more.
How to find the positive integer that cannot be represented as a whole percent?The class has 99 students.
One student of the class is 1% of the class when rounded to the nearest whole percent. The actual percentage of one student is 1 / 99 × 100 = 100 / 99 = 1.0101010101%
99 of the students represents 100% of the students.
99 / 99 × 100 = 9900 / 99 = 100%
Therefore, the positive integer between 1 and 100 that cannot be represented as a whole percent is as follows:
36, 15, 8 and many more.
8 / 99 ×100 = 800 / 99 = 8.08080808081%
15 / 99 × 100 = 1500 / 99 = 15.1515151515 %
36 / 99 × 100 = 3600 / 99 = 36.3636363636 %
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write a problem based on the information given c = regular cost of one airline ticket 0.2c = amount of 20% promotional discount 3(c - 0.2c) = 330
The question for this information:
The cost of buying 3 airline tickets at a promotional discount of 20% is 330 dollars. Find the regular cost of 1 ticket.
Discounts and allowances are price reductions from a product's or service's base price.
Discount is calculated by subtracting the sell price of an article from its Marked price.
The given conditions in the question are
C=regular cost of a ticketamount of promotional discount=20%=0.2cAnd the expression 3(c - 0.2c) = 330So from the above information we can see that if the price of a ticket is c dollars then the discounted price of 1 ticket will be (c - 0.2c).
Total price of 3 tickets =3(c - 0.2c)
but the total price is 330 dollars
Therefore:
3(c - 0.2c) =330
or, 2.4c=330
or, c=330÷2.4
or, c=137.5 dollars
Hence the regular price of each ticket is 137.50 dollars.
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What is a solution to this equation?
(1 − 3x)¾ − 1 = x
Answer:
x= -1/3
Step-by-step explanation:
3/4-9/4x-1=x
-1/4-9/4x=x
-1-9x=4x
-9x=4x+1
-9x-4x=1
-13x=1
x= -1/13
hope this helps
Round to the nearest one-hundred dollars: $3,245.31
A $3,245.30
B $3,300.00
C $3,200.00
D $3,000
Answer:
C
Step-by-step explanation:
Our choices would be 3,300 for 3,200. Those would be the answer rounded to the nearest 100 up and down. 3245.31 is between those numbers. Which number would it be closer to? 3200.
Give the rate in miles per hour round to the nearest tenth Rachel jogs 20 feet in three seconds
Answer: The Rate of jogging is 4.6 miles per hour.
Step-by-step explanation: i really hope this helps (:
The coordinates of the endpoints of GH are G(2,7) and H(11,16). Point I is on GH and divides it such that GI:HI is 4:5. What are the coordinates of I?
The coordinates of I ( x, y) = ( 6, 11 )
What is coordinate in math?
A pair of numbers that use the horizontal and vertical separations from the two reference axes to define a point's location on a coordinate plane. typically expressed by the x-value and y-value pair (x,y).
The coordinates of the G = (2,7)
The coordinates of the H = (11,16)
Point I is on GH and divides it such that GI:HI is 4:5.
the coordinates of I ( x, y)
[tex]x = \frac{m_{1}x_{2} + m_{2} x_{1} }{m_{1} + m_{2} }[/tex]
[tex]x = \frac{4 * 11 + 5 * 2}{ 4 + 5}[/tex]
x = 6
[tex]y = \frac{m_{1}y_{2}+ m_{2}y_{1} }{m_{1} + m_{2} }[/tex]
[tex]y = \frac{4 * 16 + 5 * 7}{9}[/tex]
y = 11
the coordinates of I ( x, y) = ( 6, 11 )
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PLEASE HELP
8√18 x 3√8 =
Answer:
hope this helps
Step-by-step explanation:
Can anybody help me with this
Answer: is C y=-2x-2
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A cannonball is fired in the air at an angle of 45∘. How far does it travel before it is
1,700 feet above ground? (Assume the cannonball travels in a straight line. Ignore the force of gravity and wind resistance. Give your answer to the nearest foot.)
It travels 2404 feet before it is 1,700 feet above ground;
The given question can be represented in the form of equation;
y = tan(45°)x + c;
Since it is launched from ground; c = 0;
thus; y = x is the equation of motion of cannonball;
According to question; y = 1700 feet
x = 1700 feet;
The distance travelled by cannonball will be
√(x² + y² = √(1700² + 1700²) (∵ it is a right angled triangle;
using Pythagoras theorem)
= 2404.16 feet
≅ 2404 feet
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At a carnival, Jenny bought 7 packs of 13 tickets each. She has used 39 of the tickets so far. How many tickets does she have left?
Answer:
52 tickets
Step-by-step explanation:
7 x 13 = 91
91 - 39 = 52
How to find A and B?
Answer:more work pls
Step-by-step explanation:
3 consecutive numbers have a sum of 120. Write an equation to
determine what numbers these are, and find them.
I need help with 19 please. I will give Brainly and bunch of extra points. Thank you .
4. Philips is given an interest free loan to buy a LCD television. He needs to repay the loan by monthly instalments. He repays RM35 for the first month, RM38 for the second month and the repayment increase by RM3 each month until the loan is fully settled.
(a) Show that the monthly instalment earned form an arithmetic series and state its common difference. [2 marks]
(b) If the final monthly instalment if RM212, calculate the number of months it takes Philips to settle the loan. [4 marks]
(c) Determine the sum of the loan taken. [4 marks]
The monthly instalment amounts forms an (a) Arithmetic Progression with common difference 3. (b) Phillips takes 60 months to settle the loan. (c) The sum of the loan is $7410 .
A series of numbers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms.
The n-th term of an arithmetic progression is given by:
aₙ = a + ( n - 1 ) d
Where a is the first term and d is the common difference .
(a) Amount of money repaid in the first month = $35
Amount of money repaid in the second month = $38
Amount of money repaid in the third month = $ (38+3) = $ 41
Therefore 41 -38 = 3 and 38 - 35 = 3 . So we see that each monthly instalment is increasing by 3 and the difference between each installment is 3
Therefore the numbers are in an arithmetic progression whose common difference is 3 .
(b) Given the final monthly installment is $ 212
Let us consider that after this is the installment for the n-th month.
∴ aₙ =212 , a= 35 and d=3
Putting the values in the equation of the n-th term of an AP we get:
aₙ = a + ( n - 1 ) d
or, 212 = 35 +(n-1)3
or, 212 - 35 + 3 = 3n
or, n = 60 months
Therefore Phillips takes 60 months to settle the loan.
(c) The formula for the sum of all terms of an AP is given by:
S = (n / 2 ) ( a + aₙ )
or, S = (60/2) × (35+212)
or, S = 30 × 247
or, S = 7410
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What is the range of function represented by this graph?
Which of the sets can be placed in a one-to-one correspondence?
a. {1,2,3,4,5) and {m,n,o,a,r}
b. {a,b,c,...,f} and {4,8,12,...,20}
c. {t It is a letter in the word jar) and {1,2,3,4}
PERFORMANS
O No
OYes
a. Can the sets {1,2,3,4,5) and (m,n,o,a,r} be placed in a one-to-one correspondence?
MUSICIA
FILOLETN
TRIOTO PRESE
INNOINS FORE
The set which can be placed in a one to one correspondence is:
a. {1,2,3,4,5) and {m,n,o,a,r}
b. Yes.
A rule or method that matches every element of set A with exactly one element of set B and every element of set B with exactly one element of A is known as a one-to-one correspondence.
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